A reaction that consumed 3. 50 mol of H2 produced 50. 0 g of H20. What


is the percent yield of the reaction? Round to the nearest tenths place

Answers

Answer 1

To determine the percent yield of the reaction. to compare the actual yield (the amount of product obtained experimentally) to the theoretical yield (the amount of product that would be obtained according to stoichiometry).

Given:

Moles of H2 consumed = 3.50 mol

Mass of H2O produced = 50.0 g

Step 1: Calculate the molar mass of H2O.

The molar mass of H2O is calculated by summing the atomic masses of hydrogen (H) and oxygen (O):

Molar mass of H2O = (2 × atomic mass of H) + atomic mass of O

Molar mass of H2O = (2 × 1.008 g/mol) + 16.00 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: Calculate the theoretical yield of H2O.

Theoretical yield of H2O = Moles of H2 × (Molar mass of H2O / Moles of H2O per mole of H2)

The balanced equation for the reaction is:

2 H2 + O2 → 2 H2O

From the equation, we can see that 2 moles of H2 produce 2 moles of H2O.

So, Moles of H2O per mole of H2 = 2

Theoretical yield of H2O = 3.50 mol × (18.02 g/mol / 2)

Theoretical yield of H2O = 31.535 g

Step 3: Calculate the percent yield.

Percent yield = (Actual yield / Theoretical yield) × 100

Percent yield = (50.0 g / 31.535 g) × 100

Percent yield ≈ 158.9%

Rounding to the nearest tenths place, the percent yield of the reaction is approximately 158.9%.

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Related Questions

The equilibrium constant for the reaction shown here is Kc=5.0×102. A reaction mixture at equilibrium contains [A]=1.0×10−3M. What is the concentration for the B mixture?


A(g)⇌B(g)


Here are the choices:

A. 1.0×10−3M

B. 5.0×102M

C. 1.0 M

D. 0.50 M

Answers

D. The concentration for the B mixture is 0.5 M.

concentration for the B mixture

kc = [B]/[A]

where;

kc is  equilibrium constantA is the concentration for the A mixtureB is the concentration for the B mixture

B = kc(A)

B = (5x 10²)(1 x 10⁻³)

B = 0.5 M

Thus, the concentration for the B mixture is 0.5 M.

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The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Calculate its empirical and molecular formulas.

Answers

The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

What is Empirical Formula ?

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C            83.87       12                     [tex]\frac{83.87}{12}[/tex] = 6.98                   [tex]\frac{6.98}{0.25}[/tex] = 3

H            11.99         1                       [tex]\frac{11.99}{1}[/tex] = 11.09                  [tex]\frac{11.09}{0.25}[/tex] = 4

O            4.14          16                      [tex]\frac{4.14}{16}[/tex] = 0.25                    [tex]\frac{0.25}{0.25}[/tex] = 1

Thus the empirical formula is C₃H₄O₁.

How to find the Molecular formula of compound ?

Molecular formula = Empirical formula × n

n = [tex]\frac{\text{Molecular weight}}{\text{Empirical formula weight}}[/tex]

  = [tex]\frac{386.64}{56}[/tex]

  = 7

Molecular formula = Empirical formula × n

                               = 7 (C₃H₄O₁)

Thus from the above conclusion we can say that The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

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How many moles of electrons are transferred when the two half-reactions shown below are combined to generate the spontaneous balanced chemical reaction with the lowest possible integer coefficients

Answers

6 moles of e-  are transferred when the two half-reactions shown below are combined to generate the spontaneous reaction with the lowest possible integer coefficients

A spontaneous reaction is one that favors the creation of products under the reaction's current conditions. A bonfire that is raging and exothermic is an illustration of a spontaneous reaction (there is a decrease in the energy of the system as energy is released to the surroundings as heat)

A redox reaction's oxidation or reduction reaction component is known as a half-reaction (or half-cell reaction). By taking into account the shift in oxidation states of the many chemicals participating in the redox reaction, a half-reaction is obtained. At each electrode, there are two chemical reactions taking on in the cell. Half-reactions are what we refer to as. An oxidation reaction that releases electrons occurs at the anode.

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There are millions of organic compounds but only thousands of inorganic compounds because:______

Answers

Answer:

There are millions of organic compounds but only thousands of inorganic compounds because:

a. organic compounds were formed by living things.

b. there is more carbon on Earth's surface than any other element.

c. atoms of elements other than carbon never combine with themselves.

d. carbon atoms can combine with up to four other atoms, including other carbon atoms.

Bonding gels and _____ are designed specifically to improve adhesion of light cured gels to the natural nail plate. glossing gels self-leveling gels gel primers building gels

Answers

Bonding gels and gel primers are designed specifically to improve adhesion of light cured gels to the natural nail plate and is therefore denoted as option C.

What is Adhesion?

This is defined as the tendency of particles or substance which have dissimilar origins to stick to one another. A common adhesive is referred to as glue, cement etc  and ensures there is enough resistance for their separation in case of the presence of any type of external force or stimuli acting on them.

Gel primer is referred to a vital used in makeup and serves as a form of foundation before they are applied on the skin of individuals so as to enable it stick and also look more presentable.

This is therefore the reason why gel primers was chosen as the most appropriate choice.

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The "barking dog" reaction is an exciting combustion reaction that generates a bright blue flame because sulfur is produced during the reaction (sulfur burns blue!). At the end of the reaction, a "woosh" sound is made which sounds like a dogs bark (hence the name of the reaction). Assume the reaction is carried out in a closed container. CS₂ + 4N₂0 CO₂ + SO₂ + S + 4N₂ Note: the equation is balanced How many moles of CO₂ can you generate if you were to carry out the reaction with 8.28 g CS₂?​

Answers

From the mole ratio CO₂ and CS₂ in the reaction, the moles of CO₂ produced is 0.109 moles.

What is the mole ratio of the reaction?

The mole ratio of the reaction is the ratio in which the reactants combine to form products.

The mole ratio of the reaction is obtained from the equation of the reaction.

The equation of the reaction is given below:

CS₂ + 4N₂0 → CO₂ + SO₂ + S + 4N₂

Mole ratio of CO₂ and CS₂ is 1 : 1

Moles of CS₂ reacting = mass/molar mass

Molar mass of CS₂ is 76 g/mol

Mass of CS₂ reacting is 8.28 g

Moles of CS₂ reacting = 8.28/76

Moles of CS₂ reacting = 0.109 moles

Based on the mole ratio of the reaction, moles of CO₂ produced is 0.109 moles.

In conclusion, the moles of CO₂ produced is determined from the mole ratio CO₂ and CS₂ in the reaction.

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Which statements describe some of the original ideas proposed about the universe during the big bang? Check all that apply.

Answers

The statements which describe some of the original ideas proposed about the universe during the big bang include:

The universe was opaque.  The universe was very dense and hot.  The universe expanded from a single point.  

What is Big bang theory?

This theory describes how the universe expanded from a single point to form the earth we are living in.

it states that the very dense and hot environment led to it thereby making it the most appropriate choice.

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The labels required by the Department of Transportation (DOT) must be placed on ________ when chemicals are being shipped. These labels may look similar to GHS pictograms and categorize hazardous chemicals into ________ different categories. The labels required by the Department of Transportation (DOT) must be placed on ________ when chemicals are being shipped. These labels may look similar to GHS pictograms and categorize hazardous chemicals into ________ different categories.

Answers

The labels required by the Department of Transportation (DOT) must be placed on outside containers when chemicals are being shipped.

These labels may look similar to GHS pictograms and categorize hazardous chemicals into nine different categories.

OSHA recently revised the Hazard Communication Standard, and as part of that modification, new standards for labeling dangerous chemicals were established.

As a result, workers will have better information available on the safe handling and use of hazardous chemicals, thereby allowing them to avoid injuries and illnesses related to exposures to hazardous chemicals.

These modifications will aid in ensuring higher standards and uniformity in the categorization and labeling of all substances.

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How many moles of helium are in a
45.0 liter tank at 293 K and 15.0 atm?

Answers

Answer:

28.1 moles   (three sig digits)

Explanation:

Using Ideal Gas Law

PV = n RT      looking for 'n'   R = .082057366  L-atm/K-mole

15.0 * 45.0  = n  * .082057366 * 293

n = 28.1 Moles

The number of moles of helium that are in a 45.0-liter tank at 293 K and 15.0 atm is  28.1 Moles.

What are moles?

Moles is the measuring unit that measures the quantity of a substance. Moles is a SI unit.

Helium is the lightest gas, which is used in the tires of an airplane if it is filled in the balloons, the balloon flies in the sky.

Given the volume is 45.0 liter

The pressure is 15.0 atm.

The temperature is 293 K

To calculate the moles, we will use the formula of an ideal gas:

PV = n RT      

R = .082057366 is the gas constant.

We have to calculate the n

Putting the values in the equation

15.0 x 45.0  = n  x .082057366 x 293

n = 28.1 Moles.

Thus, the moles of helium is n = 28.1 Moles.

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How many sulfur dioxide molecules are in 2.8 moles of sulfur dioxide?

Answers

Answer:

1,69 x10²⁴

Explanation:

Answered it in the comments! ^^

If the ph of a solution is 6.1 what is the concentration of h+ ions in the solution

Answers

Answer:

[tex]10^{-6} \frac{mol}{L}[/tex]

Explanation:

Comparing to the solution consisting a pH of 5 containing [tex]10^{-5}[/tex]  [tex]\frac{mol}{L}[/tex] of hydrogen ions, a solution having a pH of 6 consists of [tex]10^{-6} \frac{mol}{L}[/tex] of hydrogen ions. A solution having a pH of 7 too will have a pH of [tex]10^{-7} \frac{mol}{L}[/tex].

John has been feeling ill all day. He arrives home from work and takes his temperature. Unfortunately, the thermometer shows his temperature in Celsius, and he can’t get it to change. It reads 40 degrees Celsius. What is his temperature in Fahrenheit?

Answers

Answer:

[tex]40 \times 1.8 + 32 = 104[/tex]

Explanation:

The best way to change Celsius to Fahrenheit is to times it by 1.8 then plus 32

The correctly reported volume for a rectangular solid that is found to be
12.49 cm x 4.00 cm x 0.90 cm is
cm³?

Answers

Volume of a rectangle:
L x W x H

12.49 x 4 x 0.90 = 44.964

In a titration of a monoprotic weak acid with sodium hydroxide, the ph at the half-equivalence point is 4. 20. What is the experimental ka value of this acid?.

Answers

Ka value of monoprotic weak acid:

The experimental ka value of this acid is 6.3 × [tex]10^{-5}[/tex]  

Half-equivalence point:  

The pH of the solution will be equal to the pKa of the weak acid at the half-equivalence point.At the equivalence point, the strong base OH- will neutralize the weak acid in the case of a weak monoprotic acid, which I'll denote as HA.

   

HA + OH⁻  →  A⁻ + H₂OThe moles of OH are equivalent to the moles of the acid since the acid is monoprotic:

At half equivalence point, pH = pKₐ

The pKa is determined by the weak acid's Ka acid dissociation constant.

pKₐ = -log(Kₐ)

Kₐ = [tex]10^{-pKa}[/tex]

At the half equivalence point,

Kₐ = [tex]10^{-pH}[/tex]

Given,

pH = 4.20. By putting the value;

Kₐ = [tex]10^{-4.20}[/tex]

     = 6.3 × [tex]10^{-5}[/tex]  

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Help!!
Classify each diagram as an element a compound or mixture

Answers

Answer:

1. Mixture

2. Compound

3. Compound

4. Element

Explanation:

Number 1 shows two completely different types of compounds in the same space, so it is a mixture.

Numbers 2 and 3 are compounds because there aren't different types compounds as in Number 1, but the same compound repeated. 2 is a compound because while all of the circles are the same element, they are connected. O2 for example, oxygen, is a compound.

Number 4, finally, is all of the same substance, non-connected, so it shows an element.

Brainliest, please :) (Trying to become a genius so that I can continue helping more people)

PLEASE HURRY AND HELP
Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
Fe²+, CH₂CO₂, Pb4+, MnO-4

Answers

Answer:

Fe(CH₂CO₂)₂, Fe₂MnO, Pb(CH₂CO₂)₄, PbMnO

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) Fe(CH₂CO₂)₂

   ----> Fe²⁺ and 2 CH₂CO₂⁻

   ----> +2 + (-1) + (-1) = 0

2.) Fe₂MnO

   ----> 2 Fe²⁺ and 1 MnO⁴⁻
   ----> 2(+2) + (-4) = 0

3.) Pb(CH₂CO₂)₄
   ----> 1 Pb⁴⁺ and 4 CH₂CO₂⁻
   ----> +4 + (-1) + (-1) + (-1) + (-1) = 0

4.) PbMnO

   ----> 1 Pb⁴⁺ and 1 MnO⁴⁻

   ----> +4 + (-4) = 0

A coupled reaction is a pair of reactions occurring together in which the energy released by one reaction is used in bond formation in the second reaction. For example, glycolysis and pyruvate processing form a coupled reaction. Explain how coupling reactions allows a cell to capture the free energy of glucose oxidation rath

Answers

A coupled reaction is a pair of reactions occurring together in which the energy released by one reaction is used in bond formation in the second reaction. For example, glycolysis and pyruvate processing form a coupled reaction.

Chemical reactions that involve a common intermediate and the transfer of energy from one side to the other are referred to as coupled reactions. An illustration is the endergonic process of ATP synthesis, which is connected to proton gradient dissipation.

High-energy phosphate bonds are broken during the hydrolysis of an ATP molecule, which releases a lot of energy into the exergonic form. The coupled reaction is crucial in the transformation of this energy into an endergonic state. Coupled reactions are those that occur when two separate reactions are driven by the free energy released during the first reaction.  




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Which image best represents a solution of distilled water at pH = 7?

Answers

Answer:

nuetral

Explanation:

water has neutral

Determine the limiting reagent in the following equation for the production of salt and determine the amount of NaCl produced and the mass of excess reagent. (I - 10 marks)

100g 100g
NaHCO3 + HCl —> NaCl + H2O + CO2

Answers

Answer:

Limiting Reagent: NaHCO₃

Amount of NaCl: 69.6 g NaCl

Mass of Excess Reagent: 56.6 g HCl

Explanation:

To find the mass of NaCl, you need to (1) convert mass reactant to moles reactant (via molar mass), then (2) convert moles reactant to moles NaCl (via mole-to-mole ratio from equation coefficients), and then (3) convert moles NaCl to mass NaCl (via molar mass).

Molar Mass (NaHCO₃):

22.990 g/mol + 1.008 g/mol + 12.011 g/mol + 3(15.998 g/mol)

Molar Mass (NaHCO₃): 84.003 g/mol

Molar Mass (HCl): 1.008 g/mol + 35.453 g/mol

Molar Mass (HCl): 36.461 g/mol

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

100 g NaHCO₃            1 mole                  1 mole NaCl             58.443 g
------------------------  x  ------------------  x  ---------------------------  x  ----------------  =
                                   84.003 g            1 mole NaHCO₃            1 mole

=  69.6 g NaCl

100 g HCl            1 mole               1 mole NaCl          58.443 g
----------------  x  ------------------  x  -----------------------  x  ----------------  =
                           36.461 g             1 mole HCl              1 mole

=  160 g NaCl

Since NaHCO₃ results in the smaller amount of product, it is the limiting reagent. In other words, it is used up before the HCl has the chance to completely react. Therefore, the actual amount of NaCl produced is 69.6 grams.

To find the mass of the excess reagent, you need to calculate the amount of HCl actually used in the reaction. Then, you need to subtract that value from the total amount of HCl.

69.6 g NaCl             1 mole                1 mole HCl             36.461 g
---------------------  x  ------------------  x  -----------------------  x  ----------------  =
                                58.443 g            1 mole NaCl             1 mole

=  43.4 g HCl

Amount Given - Amount Reacted = Mass Excess

100 g HCl - 43.4 g HCl = 56.6 g HCl

Positron emission tomography (pet) imaging relies upon the emission of __________ from radioactive isotopes such as carbon-11.

Answers

Answer:

positron

Explanation:

PET scanning works by injecting a radioactive material, called a tracer, into the body. The tracer emits a positron inside the body, and the positron collides with electrons in the body, thereby annihilating and releasing two gamma rays that travel in opposite directions.

A liquid solvent is added to a flask containing an insoluble solid. the total volume of the solid and liquid together is 81.0 ml. the liquid solvent has a mass of 40.5 g and a density of 0.865 g/ml. determine the mass of the solid given its density is 2.25 g/ml.

Answers

The mass of solid is 76.905 g.

Given that,

Total volume of solid and liquid = 81.0 mL

Mass of liquid = 40.5 g

Density of liquid = 0.865 g/mL

Density of solid = 2..25 g/mL

We need to calculate the volume of liquid

Using formula of density

[tex]Density = Mass/volume(V_{l} } )\\\\volume(V_{l} )=Mass/Density[/tex]

Put the value into the formula

[tex]V_{l} = 40.5/0.865\\\\V_{l} = 46.82 mL[/tex]

We need to calculate the volume of solid

Volume of solid = Total volume of solid and liquid- volume of liquid

[tex]V_{s} =81.0-46.82\\\\V_{s} =34.18 mL[/tex]

We need to calculate the mass of solid

[tex]P_{s}=M_{s} /V_{s} \\\\M_{s} =P_{s}V_{s}[/tex]

Using formula of density

Put the value into the formula

[tex]M_{s}=2.25 X 34.18\\\\M_{s}=76.905 g[/tex]

Hence, The mass of solid is 76.905 g.

What is density?

A substance's density (more accurately, its volumetric mass density; sometimes known as specific mass) is its mass per unit volume. The most common symbol for density is (the lower case Greek letter rho).

There are three types of Density:

linear densitybulk densityarea density

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Why is the practice of using a spatula to scoop powder from a bottle discouraged?

Answers

Answer:

it's both impossible and inefficient

Explanation:

think about it, if your spatula can even fit in the bottle will it take out a measured amount of powder? if the spatula has holes in it the powder will fall out and you will have to restart the experiment

The population that experienced the highest radioactivity from chernobyl in norway were:______

Answers

The population that experienced the highest radioactivity from chernobyl in norway were "a small community of reindeer herders called the Saami".

Typically, the term "population" denotes the total quantity of people living in a particular area, be it a city or town, region, country, continent, or even the entire world.

The native reindeer herders of Scandinavia could be known as the Sámi. These breathtaking images capture a herd during its yearly journey through summer pastures as well as wintering areas.

Therefore, the population that experienced the highest radioactivity from chernobyl in norway were "a small community of reindeer herders called the Saami".

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If the same test, given at different points in time to the same test takers, yields different scores, then the method typically used to assess this source of error is_________.

Answers

If the same test, given at different points in time to the same test takers, yields different scores, then the method typically used to assess this source of error is alternate form.

What is alternate forms test?

An alternate form or parallel form test is a test which is conducted at different time on the same set of test takers in order to test the reliability of the results obtained.

In conclusion, alternate or parallel form tests is a test of reliability.

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The element with the lowest melting point is: Select one: a. B b. Al c. Ga d. Tl e. All of these have the same melting point.

Answers

The element with the lowest melting point is Ga.
Hence, Option (C) is correct answer.

What is Melting point ?

Melting point is usually defined as the temperature at which solid changes to liquid.

What is the order of melting point of  B, Al, Ga, Tl ?

The melting point order of B, Al, Ga, Tl is B > Al> Tl > Ga due to structural changes, melting point increases from Ga to Tl. Hence Ga has the lowest melting point among all these.

Thus from the above conclusion we can say that The element with the lowest melting point is Ga.
Hence, Option (C) is correct answer.

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The isotope 226Ra has a half-life for radioactive decay of 1600 Y. How long will it take the amount of 226 Ra in a sample of 226RaCl2 to decrease by 25%

Answers

the correct answer is 226Ra is half and long as radioactive decay

Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equation to determine the mass of NaCl that reacted with F2 at 280. K and 1.50 atm.

F2 + 2NaCl → Cl2 + 2NaF

Part 2. Explain how you would determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP.​

Answers

The mass of NaCl that reacted with 12 lit of F2 at 280 K and 1.50 atm= 0.027 gm.

the mass of sodium chloride that can react with the same volume of fluorine gas at STP = 0.01 gm.

Given,

F2 + 2NaCl → Cl2 + 2NaF

PART-1:

So, from the given reaction we can say that 2 moles of NaCl is required for 1 mole of F2.

By using combined gas law,

[tex]\frac{P1V1}{n1T1} =\frac{P2V2}{n2T2}[/tex]

here , P1 =P2

and moles of NaCl is twice as pf F2

∴n2=2n1

and also T1 = T2

by simplifying the reaction we get..

[tex]\frac{V1}{n1} = \frac{V2}{2n1}[/tex]

V2= 2 × V1

∴V2 = 2 ×12

      = 24 Lit.

from ideal gas law ,

we can find the moles of NaCl,

PV= nRT

n=[tex]\frac{PV}{RT}[/tex]

n= 1.5 × 24 ÷( 0.082 × 280)

∴ n= 1.57

mole = mass / molecular mass

so, molecular mass of NaCl = 58.5

∴ mass of NaCl used = 1.57/58.5

                                 = 0.027 gm

PART -2:

At, STP

T= 273 K

P = 1atm

V= 12 lit

n= ?

using ideal gas law we can determine the number of moles

PV= nRT

n = 1 ×12 ÷(0.082 × 273)

n= 0. 54

∴ mass of NaCl = 0.54 / 58.5

                         = 0.01 g

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Answer: for part 1: our equation is F2 + 2NaCI -> CI2 + 2NaF. We can solve this by using the gas law(s). The ideal gas law is PV = nRT. P = pressure V = volume n = amount of substance R = ideal gas constant and T = temperature. We know that 2 moles of NaCI is crucial for 1 mole of F2. P1=P2 and T1=T2. we multiply the 12 liters by 2. which is 24 liters. We know NaCI consists 58.44/58.5g per mole. if we divide that by n of (nRT) we find the mass. we mutiply 24 by 1.5. which is 36 the divide by 0.082 which was multiplied by 280. and u get 1.567 or 1.57. we divide that by the g of NaCI. u get 0.027.

for part 2: we STP stands for Standard Temperature and Pressure. we can also use the ideal gas law. PV = nRT. Using this knowledge we can determine the mass. T is 273k and p is 1 atm. v is 12. we multiply 0.082 and 273. 22.386. we divid that by 12. we get 0.54. then we divide the 0.54 by the g again. which is 0.01g.

Explanation:

Calculate the molecular weight of Na2sio3

Answers

Answer:

Answer:122 g/ mol

Answer:122 g/ molExplanation:

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compound

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ molhence , summation of the molar masses

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ molhence , summation of the molar masses46+28+48 = 122g/mol

The molecular weight of [tex]\rm Na_2SiO_3[/tex] (sodium silicate) is approximately 122.07 g/mol.

To calculate the molecular weight of [tex]\rm Na_2SiO_3[/tex] (sodium silicate), we need to add the atomic weights of each individual element in the compound.

The atomic weights are as follows:

- Sodium (Na) = 22.99 g/mol

- Silicon (Si) = 28.09 g/mol

- Oxygen (O) = 16.00 g/mol

Now, multiply the atomic weights by the number of atoms in the compound:

- Sodium (Na) = 2 atoms * 22.99 g/mol = 45.98 g/mol

- Silicon (Si) = 1 atom * 28.09 g/mol = 28.09 g/mol

- Oxygen (O) = 3 atoms * 16.00 g/mol = 48.00 g/mol

Finally, add up all the atomic weights:

[tex]\rm \[Molecular \, weight \, of \, Na2SiO3 = 45.98 g/mol + 28.09 g/mol + 48.00 g/mol \\= 122.07 g/mol\][/tex]

So, the molecular weight of [tex]\rm Na_2SiO_3[/tex] (sodium silicate) is approximately 122.07 g/mol.

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Give the coordination number and the charge of the central metal ion in each coordination compound: For the charges, enter your answers with the correct sign. e.g. if you think the answer is 1, enter the positive sign followed by the number 1. Na2[Zn(OH)4] coordination number

Answers

The coordination number shows the number of ligands attached to the central metal.

What is complex in coordination compound?A coordination complex is the product of a Lewis acid-base reaction in which neutral molecules or anions (called ligands) bond to a central metal atom (or ion) by coordinate covalent bonds. Ligands are Lewis bases - they contain at least one pair of electrons to donate to a metal atom/ion.A complex is a coordination compound which contains a central metal atom or ion. The coordination number refers to the number of ligands in the complex. The coordination number usually influences the geometry of the complex compound.

The coordination number and the charge on the central metal in each of the complexes are shown below;

Na2[Zn(OH)4] - The coordination number of the complex is 4 and the charge on the central metal ion is +2.

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By now you should realize that having an octet of electrons on a central atom is critical for a molecule to be stable. Would you expect NO and NO2 to be stable molecules

Answers

NO is a stable compound

The octet rule describes an atom's propensity to favor eight electrons in its valence shell. Atoms with fewer than eight electrons are more likely to interact with one another and create a more stable compound.

The majority of other odd-electron molecules, including NO, are highly chemically reactive and stable compounds. The second breach of the octet rule is the presence of molecules lacking electrons. Less than eight electrons are positioned around each atom in these stable compounds.

The overall molecular orbital arrangement of NO will be as follows, nitrogen has 7 electrons and oxygen has 8 electrons, according to the molecular orbital theory.

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