A ring-shaped region is shown below.
Its inner diameter is 14 ft. The width of the ring is 4 ft.
4 ft
14 ft
Find the area of the shaded region.
Use 3.14 for PI. Do not round your answer.
Answers
The area of the ring-shaped shaded region is found to be 650.46 square feet.
The area of the bigger ring minus the area of the smaller ring will give us the area of the shaded region. The radius of the outer circle is,
r = (14 + 4/2) ft = 16 ft
The area of the outer circle is,
A_outer = πr²
= 3.14 x 16²
= 804.32 ft²
The radius of the inner circle is,
r = 14/2 ft
r = 7 ft
The area of the inner circle is,
A_inner = πr²
= 3.14 x 7²
= 153.86 ft²
Therefore, the area of the shaded region is,
A_shaded = A_outer - A_inner
= 804.32 - 153.86
= 650.46 ft²
So the area of the shaded region is 650.46 square feet.
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Complete question - A ring-shaped region is shown below. Its inner diameter is 14 ft. The width of the ring is 4 ft. Find the area of the shaded region. Use 3.14 for PI. Do not round your answer.
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When a rocket is launched, it climbs 50 feet for every 13 feet it travels horizontally. Estimate the rocket's distance (Find the missing side of triangle).
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Answer:
(1, - 1 )
Step-by-step explanation:
Given the 2 equations
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Answers
1-0.63=0.37
0.37(100)=37
So the final answer is 37% decrease.
Answer:
decay function
percent rate of decrease is 37%
Step-by-step explanation:
I assume the x is the exponent.
[tex] y = 47(0.63)^x [/tex]
The number raised to the exponent x is 0.63 which is between 0 and 1. That means that as x increases, (0.63)^x decreases. That means it is an exponential decay function.
Each unit more in x results in 0.63 being multiplied by the number.
Since 1 - 0.63 = 0.37, the percent rate of decrease is 37%.
Answer:
decay function
percent rate of decrease is 37%
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Answer:
3x² + 8x + 5
Step-by-step explanation:
Subtract the sum of the 2 given sides from the perimeter, that is
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= 9x² + x + 6 - 6x² + 7x - 1 ← collect like terms
= 9x² + 8x + 5
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Answer:
y=-4/7x+4
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Answer:
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Find the values of the variables in the parallelogram. The diagram is not to scale.
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Step-by-step explanation:
option B is the correct answer of this question.
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plz mark my answer as brainlist plzzzz vote me also .
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Answer:
B
Step-by-step explanation:
x is 29 because the inverse opposite of angles are the same.
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Answer:
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Step-by-step explanation:
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Answer:
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Answer:
If you are doing subtraction with fractions you need to make a common denominator and subtract the numerators from each other
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x(x+5)=387
Hint: Use the quadratic formula
Answers
Answer:
x= −5−11√13/2, −5+11√13/2Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.
Exact Form:
x= −5−11√13/2, −5+11√13/2
Decimal Form:
x=17.33053201…,
−22.33053201…
Step-by-step explanation:
x(x+5)=387
Simplify
x(x+5).
x^2+5x=387
Subtract 387 from both sides of the equation.
x^2+5x−387=0
Use the quadratic formula to find the solutions.
−b±√b^2−4(ac)/2a
Substitute the values a=1, b=5, and c= −387 into the quadratic formula and solve for x.−5±√5^2−4⋅(1⋅−387)/2⋅1
Simplify.
x=−5±11√13/2
The final answer is the combination of both solutions.
x=−5−11√13/2, −5+11√13/2
The result can be shown in multiple forms.
Exact Form:
x=−5−11√13/2,−5+11√13/2
Decimal Form:
x=17.33053201…,
−22.33053201…
Hope it is helpful....Answer:
[tex]\displaystyle x=\frac{-5+11\sqrt{13}}{2}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityAlgebra I
Standard Form: ax² + bx + c = 0Quadratic Formula: [tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]Step-by-step explanation:
Step 1: Define
x(x + 5) = 387
Step 2: Identify Variables
Rewrite
[Distributive Property] Distribute x: x² + 5x = 387[Subtraction Property of Equality] Subtract 387 on both sides: x² + 5x - 387 = 0Part: a = 1, b = 5, c = -387Step 3: Solve for x
Substitute in variables [Quadratic Formula]: [tex]\displaystyle x=\frac{-5\pm\sqrt{5^2-4(1)(-387)}}{2(1)}[/tex][√Radical] Evaluate exponents: [tex]\displaystyle x=\frac{-5\pm\sqrt{25-4(1)(-387)}}{2(1)}[/tex][√Radical] Multiply: [tex]\displaystyle x=\frac{-5\pm\sqrt{25+1548}}{2(1)}[/tex][√Radical] Add: [tex]\displaystyle x=\frac{-5\pm\sqrt{1573}}{2(1)}[/tex][Fraction - Denominator] Multiply: [tex]\displaystyle x=\frac{-5\pm\sqrt{1573}}{2}[/tex][Fraction - √Radical] Simplify: [tex]\displaystyle x=\frac{-5\pm 11\sqrt{13}}{2}[/tex]5y=2x+5 Y=-x +6
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Answer:
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