Find the angle θ made by the road. When rounding the curve at 15.0 m/s, the car has a radial acceleration of
a = (15.0 m/s)² / (75.0 m) = 3.00 m/s²
There are two forces acting on the car in this situation:
• the normal force of the road pushing upward on the car, perpendicular to the surface of the road, with magnitude n
• the car's weight, pointing directly downward; its magnitude is mg (where m is the mass of the car and g is the acceleration due to gravity), and hence its perpendicular and parallel components are, respectively, -mg cos(θ) and mg sin(θ)
By Newton's second law, the net forces in the perpendicular and parallel directions are
(perp.) ∑ F = n - mg cos(θ) = 0
(para.) ∑ F = mg sin(θ) = ma
==> sin(θ) = a/g ==> θ = arcsin(a/g) ≈ 17.8°
(Notice that in the paralell case, the positive direction points toward the center of the curve.)
When rounding the curve at 31.8 m/s, the car's radial acceleration changes to
a = (31.8 m/s)² / (75.0 m) ≈ 13.5 m/s²
and there is now static friction (mag. f = µn, where µ is the coefficient of static friction) acting on the car and keeping from sliding off the road, hence pointing toward the center of the curve and acting in the parallel direction. Newton's second law gives the same equations, with an additional term in the parallel case:
(perp.) ∑ F = n - mg cos(θ) = 0
(para.) ∑ F = mg sin(θ) + f = ma
The first equation gives
n = mg cos(θ)
and substituting into the second equation, we get
mg sin(θ) + µmg cos(θ) = ma
==> µ = (a - g sin(θ)) / (g cos(θ)) = a/g sec(θ) - tan(θ) ≈ 1.12
Answer:
Explanation:
You are in the chapter on Physics about uniform circular motion and gravity. This is a centripetal force problem in particular, and the equation for that is
[tex]F_c=\frac{mv^2}{r}[/tex] where
[tex]F_c[/tex] is the centripetal force needed to keep the car moving in its circular path,
m is the mass of the car,
v is the velocity with which the car is moving, and
r is the radius of the circle that the car is moving around.
For us, the centripetal force is supplied by the friction keeping the car on the road, altering the equation to become
[tex]f=\frac{mv^2}{r}[/tex] and friction is defined by
f = μ[tex]F_n[/tex] (the coefficient of friction multiplied by the weight of the car).
Going on and getting buried even deeper,
[tex]F_n=mg[/tex] which says that the weight of the car is equal to its mass times the pull of gravity. Putting all that together, finally, we have the equation we need to solve this problem:
μ·m·g = [tex]\frac{mv^2}{r}[/tex] and we solve this for μ:
μ = [tex]\frac{mv^2}{mgr}[/tex] and it just so happens that the mass of the car cancels out. (I'll tell you why the mass of the car doesn't matter at the end of this problem). Filling in and solving for the coefficient of friction:
μ = [tex]\frac{31.8^2}{(9.8)(75.0)}[/tex] to 2 significant figures is
μ = 1.4
The mass of the car doesn't affect whether or not the car can stay on the curve. Even though a car with a greater mass will have a greater frictional force, that doesn't mean that it's easier for that car to stay on the road; a larger mass only means that a larger centripetal force is needed to keep it moving in a circle. This makes the gain in friction become offset by the fact that a larger centripetal force is necessary. Thus,
On a flat curve, the mass of the object experiencing circular motion does not affect the velocity at which it can stay on the curve.
PLEASE HELP
this is about volleyball
A good training partner helps with
• Setting the weight
• Using proper technique
• Keeping track of repetitions
• All of the above
Answer:
• All Of The Above
Hope it helps uh
Mark me as brainliest
A puck is travelling at a speed of 28 m/s. If it has a mass of 200 g, what is its momentum?
Answer:
Explanation:
Momentum is equal to mass times velocity:
p = mv; therefore,
p = .200(28) and
p = 5.6 [tex]\frac{kg*m}{s}[/tex]
A college dorm room measures 14 ft wide by 13 ft long by 6 ft high. What is the air in it under normal conditions?
Complete question:
A college dormitory room measures 14 ft wide by 13 ft long by 6 ft high. Weight density of air is 0.07 lbs/ft3. What is the weight of air in it under normal conditions?
Answer:
the weight of the air is 76.44 lbs
Explanation:
Given;
dimension of the dormitory, = 14 ft by 13 ft by 6 ft
density of the air, = 0.07 lbs/ft³
The volume of the air in the dormitory room = 14 ft x 13 ft x 6 ft
= 1092 ft³
The weight of the air = density x volume
= 0.07 lbs/ft³ x 1092 ft³
= 76.44 lbs
Therefore, the weight of the air is 76.44 lbs
Two cups having different liquids at a temperature of 20°c and 68°c lose heat energy to the environment. To measure the temperature difference between the two cups of liquid, you would use a ____
Answer:
youd use a thermometer. this can be used to measure the temperature of a solid such as food, a LIQUID such as water, or a gas such as air.
Explanation:
8. A tortoise moves a distance of 100 metres in 15 minutes. What is the average speed of
tortoise in km/h ?
Behaviors in deer such as herding and male deer using antlers to compete for females increase the chances of successful reproduction.
True or False
Answer:
True
Explanation:
The reproductive success of any species is the capability to produce their offspring per breeding lifetime or event.
Most of the species have to attract their partners by their physical capability and build up so that the mother can choose her partner in order to breed the best kind of off spring.
In the context, in case of deer, the size of the their antlers as well as behavior in herding is considered as the best chances for a successful reproduction to compete among the males and find their breeding mate.
Thus the answer is TRUE.
Find the value of 60 joule in ergs.
Answer:
600000000 ergs
Explanation:
Formula - multiply the energy value by 1e+7
A radio has a 1.3 A current. If it has a resistance of 35 Ω, what is the potential difference?
Answer:
22
Explanation:
Answer:
45.5 v
Explanation:
I = 1.3 A
R = 35 Ω
V = I * R
V = 1.3 * 35 = 45.5 v
The dependent variable measured was the ______
a. fan speed
b. mass
c. acceleration
Answer:
a
Explanation:
Fan speed is the answer
A square wooden raft floats on a lake. The density of the water in the lake is 1000 kg/m². The sides of the raft are 2.0m long and the thickness of the raft is 0.20 m. The mass of the raft is 700 kg. How many barrels, each of mass 100 kg, could be placed on the raft before its surface sinks to the surface of the water?
Answer:
1
Explanation:
V=2*2*0.2=0.8m^3
d=m/v 1000*0.8=800kg
800=700+100(n) (n for barrels)
n=1
This question deals with the concept of buoyancy. This can be solved by calculating the buoyant force.
"1" barrels, each of mass 100 kg, could be placed on the raft before it sinks to the surface water.
First, we need to calculate the buoyant force on the raft due to water. This force is equal to the weight of the volume of water equal to the volume of the raft.
Buoyant Force = (Volume of Raft)(Density of Water)(g)
Buoyant Force = [(2 m)(2 m)(0.2 m)][1000 kg/m³](9.81 m/s²)
Buoyant Force = (0.8 m³)(1000 kg/m³)(9.81 m/s²)
Buoyant Force = 7848 N
For the raft to sink the weight of the raft combined with the weight of barrels must exceed the buoyant force. Now, we will calculate the weight of raft and barrels and equate it with the buoyant force.
[Mass of Raft + (No. of Barrels)(Mass of 1 Barrel)][g] = Buoyant Force
[700 kg + (No. of Barrels)(100 kg)][9.81 m/s²] = 7848 N
(No. of Barrels)(981 N) = 7848 N - 6867 N
[tex]No. of Barrels = \frac{981\ N}{981\ N}[/tex]
No. of Barrels = 1
The attached picture shows the concept of buoyancy.
Learn more about buoyancy here:
https://brainly.com/question/21990136?referrer=searchResults
What is the variable unit for acceleration,gravity and height
Answer:
HLW ITS JESS BREGOLI
YOUR ANSWER IS HERE
At different points on Earth's surface, the free fall acceleration ranges from 9.764 m/s2 to 9.834 m/s2[2] depending on altitude and latitude, with a conventional standard value of exactly 9.80665 m/s2 (approximately 32.17405 ft/s2). Locations of significant variation from this value are known as gravity anomalies.
Explanation:
HOPE IT MAY HELP YOU !!
En el proceso de diseño de ingeniería, ¿qué limitaciones deben tenerse en cuenta al utilizar un modelo / prototipo?
Answer:
Las limitaciones de un modelo o prototipo son;
1) Los parámetros ambientales (donde se opera el modelo, prototipo o producto) son diferentes y, por lo tanto, pueden producir relaciones y factores ambientales que serán diferentes de los factores ambientales y las relaciones del objeto real.
2) El análisis del problema puede ser inadecuado
3) La posibilidad de falta de satisfacción del cliente con un modelo, preferencia por la demostración real del producto.
4) Reproducción inexacta del entorno del producto durante la prueba del modelo
5) El factor de costo del modelo
6) Mayor complejidad introducida por el modelo / prototipo al análisis de la solución
Explanation:
El modelo o prototipo es la presentación del diseño articulado, construido para demostrar el producto real con el propósito de encontrar la existencia de errores en el diseño que serían corregidos, antes de que se realice la producción real
In this graph, calculate the speed of
segment A in m/s?
Answer:
The answer is Speed=2m/s
Explanation:
S=D/T
S=10m/5s
S=2m/s
A 1000 kg car accelerates from rest at a rate of 10 m/s² for 3 seconds. A) what is the final velocity of the car?
Answer:
Refer to the attachment!~
Please help!!!!! I will give brainliest. Describe four examples of acceleration you see during your day. Choose an object that is slowing down, one that is speeding up, one that is moving at a constant speed but changing direction, and one that is moving at a constant velocity with zero acceleration.
When the brake is applied to the car and comes to rest after some time is an example of an object that is slowing down.
What is acceleration?The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
1. When the brake is applied to the body and comes to rest after some time is an example of an object that is slowing down.
2. When a person accelerates the car and the velocity is increasing is an example of speeding up.
3. An object moves in a circular motion moving at a constant speed but changing direction,
4. Acceleration is the rate of change of velocity. If the change in the velocity is constant the acceleration is zero is an example of moving at a constant velocity with zero acceleration.
To learn more about acceleration, refer to the link;
https://brainly.com/question/2437624
#SPJ1
which forces are capable of affecting particles or objects from large distance
Answer:
only long-range force that affects all particles is the gravitational force.
Explanation:
In nature there are four fundamental forces: nuclear, weak, gravitational and electrical.
The last two are long-range, that is, the forces are zero for infinite distances, the current gravitational on all the particles and the electric one acts on the charged particles, without the chosen charge it is zero, the forces is also zero.
Consequently the only long-range force that affects all particles is the gravitational force.
Explain the energy transformations that occur when breaking in a hybrid
vehicle.
it occur kinetic energy
when breaking in a hybrid
vehicle.
hope it helps
Answer:
it occur kinetic energy when breaking in a hybrid
vehicle .
hope it is helpful to you ☺️
The
push switch is closed and the door unlocks. Explain in detail how this happens.
Answer:
The push switch is closed and the door unlocks. ... The switch completes the circuit and a current flows through the coil. The coil becomes an electromagnet and its iron core becomes magnetised. The iron bolt is attracted to the electromagnet.
Explanation:
Please Mark me brainliest
This type of mutation occurs when one or more base pairs are added to the gene sequence.
Answer:
Insertion
Explanation:
It causes a frameshift.
6. ¿Es importante conocer el sistema inglés? ¿Por qué?
Answer: Es importante conocer el sistema ingles porque luego podemos cmmunicar con otros que solo abalan ingles y les podes ayudar con espanol si solo abaln ingles
Explanation:
there is no gain in mechanical advantage in a single fixed pulley but they are used
Answer:
A single fixed pulley is used to lift load by changing the direction of the lifting force. Even though a single fixed pulley has no mechanical gain in that, the effort applied is greater than the load, it is preferred in use since you do not have to pull or push the pulley up and down.
Explanation:
The answer itself speaks
The waste product of photosynthesis is
Answer:
oxygen
Plants need to excrete excess carbon dioxide and oxygen. Carbon dioxide is a waste product of aerobic respiration in plant cells. Oxygen is a waste product of photosynthesis .
Explanation:
yw!
Please answer in your own words and I will mark brainlist, Compare all matters from the view of passing light through them (name 3 types and write if they pass the light or not.)
Answer:
Light passes through the gas
Light passes through the pure water
Light passes through some solids
Explanation:
In gasses, there are many spaces between the molecules. These spaces allow light to pass through them without any interruption.
In pure water, there are some spaces between particles. these particles allow some light rays to pass theough, some to move through the common boundary and reflec5 some of them.
in solids, some allow light to pass through as they are transparent or translucent
Solve this question please sqdancefan
Answer:
(D) 4×10⁻³
Explanation:
The difference is ...
0.2050 -0.2014 = 0.0036 = 3.6×10⁻³
The number 0.205 is expressed to a precision of 1×10⁻³, so the result of the subtraction operation cannot be considered to be more precise. It must be expressed as ...
4×10⁻³ . . . . matches choice D
_____
Additional comment
This is physics, not math. In the physical sciences, most numbers must be considered to be measurements. (A few are definitions.) Hence, the rules of significant figures and precision apply to the results of arithmetic operations. This problem is a good illustration of what happens when computing small differences of large numbers. We start with 3 significant figures in 0.205, and end up with 1 significant figure in 0.004.
inertia is a force whuch keeps stationary object at rest and moving objects in motion is it trur?
Answer:
True
Explanation:
Inertia is the resistance of any physical object to any change in its velocity. This includes changes to the object's speed, or direction of motion. An aspect of this property is the tendency of objects to keep moving in a straight line at a constant speed, when no forces act upon them
Answer:
True po sagot sabihin mo kong mali
Which one is best for health? A) Boiled Seeds B) roasted seeds c) wet swollen seeds d)Sprouted seeds
Answer:
d.) "Sprouted seeds"Explanation:
Sprouted seeds - are the best for health.
I hope it helps! Please mark my answer answer as bräinliest (if my answer is correct). Thank You!
a car starts from rest & acquire a velocity of 54km/h in 2 sec. Find-
a) the acceleration
b) distance traveled by car assume motion of car is uniform
c) if the mass of the car is 1000kg. what is the force acting on it?
Pls help me. I'm bad in this subject. kinda need it by today
Answer:
a. Acceleration, a = 7.5 m/s
b. Distance, S = 15 meters
c. Force = 7500 Newton
Explanation:
Given the following data;
Mass = 1000 kg
Initial velocity = 0 m/s (since it's starting from rest).
Final velocity = 54 km/h
Time = 2 secs
Conversion:
54 km/h to m/s = 54*1000/3600 = 15 m/s
a. To find the following acceleration;
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{initial speed - final speed}{time}[/tex]
Substituting into the formula, we have;
[tex] Acceleration = \frac{15 - 0}{2}[/tex]
[tex] Acceleration = \frac{15}{2}[/tex]
Acceleration, a = 7.5 m/s
b. To find the distance, we would use the second equation of motion.
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Where;
S represents the displacement or height measured in meters. u represents the initial velocity measured in meters per seconds. t represents the time measured in seconds. a represents acceleration measured in meters per seconds square.Substituting into the equation, we have;
[tex] S = 0*2 + \frac {1}{2}*(7.5)*2^{2}[/tex]
[tex] S = 0 + 3.75*4[/tex]
[tex] S = 15 [/tex]
Distance, S = 15 meters
c. To find the force, we would use the following formula;
[tex] Force = mass * acceleration [/tex]
[tex] Force = 1000 * 7.5 [/tex]
Force = 7500 Newton
Q3. (a) The student places 0.5 kg of potato into a pan of water.
During cooking, the temperature of the potato increases from 20 °C to 100°C
The specific heat capacity of the potato is 3400 J/kg °C
80
Calculate the change in thermal energy of the potato. Use the equation:
change in thermal energy = mass * specific heat capacity * temperature change
m = 0.5kg
C = 34001
TA= 20° - 100°
° = 80°C
OʻS x 3400 x 80 - 136000J
136000
Change in thermal energy =
(b) Why is the energy supplied by the cooker greater than that calculated in part (a)?
HELP
Write the equation which links gravitational potential energy,height and mass.
Answer:
PE = mgh
Explanation:
The equation of potential energy is mgh.
Scientists have developed a new type of solar cell with an efficiency of over 40 %.
The efficiency of the solar cell was confirmed independently by other scientists.
Suggest why it was important to confirm the efficiency independently.
Answer:
According to Carl Sagan's Baloney Detection Kit notes
"Whenever possible there must be independent confirmation of the facts"
Independent confirmation by other scientist is to ensure that the observation of the over 40% efficient solar panel is repeatable
It is also important to avoid accepting the given mandates at face value and accepting that the scientist considered all factors when taking the results or that the original developers has assigned others to check their findings before the introduction of the new type of solar cell
Explanation: