A sample contains 2.2 g of the radioisotope niobium-91 and 15.4 g of its daughter isotope, zirconium-91.

If the half-life of niobium-91 is 680 years, how long will it take for the decay described in the previous question?

680 years
1,360 years
✓2,040 years (correct answer)
2,720 years

Answers

Answer 1

Time to decay : 2040 years

Further explanation  

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

The main particles are emitted by radioactive elements ,so that they generally decay, are alpha (α), beta (β) and gamma (γ) particles  

General formulas used in decay:  

[tex]\tt Nt=No.\dfrac{1}{2}^{\dfrac{T}{t\frac{1}{2} }[/tex]  

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

moles zirconium :

[tex]\tt \dfrac{15.4}{91}=0.169[/tex]

moles niobium :

[tex]\tt \dfrac{2.2}{91}=0.0242[/tex]

the half-life of niobium-91 is 680 years

Reaction

⁹¹₄₁Nb ⇒⁹¹₄₀Zr + ₁⁰e

Amount of Nb from reaction : 0.169

Amount of initial Nb = 0.0242 + 0.169 = 0.1932

Time to decay (T) :

[tex]\tt 0.0242=0.1932.\dfrac{1}{2}^{\dfrac{T}{680}}\\\\0.1252=\dfrac{1}{2}^{\dfrac{T}{680}}\\\\\dfrac{1}{2}^{3}=\dfrac{1}{2}^{\dfrac{T}{680}}\\\\T=680\times 3=2040[/tex]

Answer 2

Answer:

It’s CCCCCCCCCCCCCCC

Explanation:

I just took the instruction and yes its “C.”


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Answer:

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Answer:

As the coil moves through the magnetic field, created by the magnet, an electric current flows through it. The electric current flows out from the microphone to a computer or other recording device, and you can hear it. Aspeaker works in almost the same way, except that the process isreversed.

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Hope this helps :) all you need to do is use the C1V1=C2V2 formula

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who was the first person to create the periodic table

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Answers

When sodium acetate is dissolved in water, it is hydrolyzed into ions.

What happen when sodium acetate dissolved in water?

When a salt of weak acid or base is dissolved in water, this salt hydrolysis in it. Water ionises into hydroxide and hydrogen due to addition of sodium acetate. In water, sodium acetate splits into sodium and acetate ions.

So we can conclude that when sodium acetate is dissolved in water, it is hydrolyzed into ions.

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What is the Atomic weight Of Neon/ Ne in elements.

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Can some inherited traits be changed by an organism's environment?

Answers

Some inherited traits can be changed by an organism's environment because environment has a direct impact on organisms.

Can inherited traits be changed by environment?

Traits allow a plant, animal, or other organism to survive and reproduce in its environment which is known as adaptations. Natural selection occurs when there is some variation in the inherited traits of organisms within a species.

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Answers

Further explanation

Isotopes : the same atomic number, but different mass numbers  

Atomic mass is the average atomic mass of all its isotopes  

avg atomic mass = m1.%m1 + m2.%m2....mn.%mn

You did not include the mass of each isotope

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Answer:

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Explanation:

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i hope this helped

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Answers

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Answer:

Explanation:

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When the moon goes behind the earth to the shadow it becomes a solar eclipse.

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Answer:

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Answers

Answer:

The answer is "0.015 M ".

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[tex]M_1 = 1.25 \ M\\\\M_2 = M_2\\\\V_1 = 5.00 \ mL\\\\V_2 = 25.00 \ mL \\\\\bold{\text{Formula:}}\\\\\to M_1 \times V_1 = M_2\times V_2\\\\\to M_2 = \frac{ M_1 \times V_1}{V_2}\\\\=\frac{( 1.25 \times 5.00 )}{ 25.00}\\\\=\frac{( 6.25 )}{ 25.00}\\\\= 0.25 \ M \\\\[/tex]

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A rod of iron of uniform density has a thickness such that a one-inch-long segment of it weighs 3. 88 ounces. Given that there are 0. 035273 ounces in a gram and 2. 54 centimeters in an inch, how many grams would a 14. 79 cm length of the same iron rod weigh? a. 73. 30 g b. 274. 49 g c. 640. 51 g d. 1,626. 89 g.

Answers

The number of grams of iron present in 14.79 cm length of the same iron rod is 640.51 g.

What is ounces?

Ounces is a unit of mass which is used to define a very little amount of anything.

In the question, given that:

In one inch of iron rod whose weighs is 3.88 ounces = 2.54 cm long

In 1 g = 0.035273 ounces present

So we can calcuylate the number of grams in which 3.88 ounces present as:
x = (3.88 ounces) / (0.035273 ounces/g)

x = 110g

So, in 110g = 3.88 ounces present

And in 2.54 cm = 110g of iron present

In 14.79 cm, present grams of iron can be calculated as:

y = (14.79cm x 110g) / 2.54cm

y = 640.51 g

Hence option (c) is correct i.e. 640.51 g.

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The weight of the iron rod with 14.79 cm length with same density is given by: Option C; 640.51 g

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Suppose that a finite amount of substance is there having its properties as:

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Then, they are related as:

[tex]d = \dfrac{m}{v}[/tex]

We know that:

1 ounce = 28.3495 g approx

Now, from the facts given in the problem, we have:

The weight of first iron rod which is one inches long = 3.88 ounces

The new rod is 14.79 cm long. And 1 cm = 0.3937 inches approx, thus the new rod is: [tex]14.79 \times 0.3937 \approx 5.8228 \: \rm inches[/tex]

As for 1 inch long rod, there is  weight of 3.88 ounces, thus:

for 5.8228 inch rod, the weight of the rod would be [tex]5.8228 \times 3.88 \approx 22.5924 \: \rm ounces[/tex]

And since 1 ounce = 28.3495 g approx

Thus, weight of the new rod in grams would be [tex]22.5924\times 28.3495 \approx 640.485 \approx 640.51\: \rm g[/tex]

Thus, the weight of the iron rod with 14.79 cm length with same density is given by: Option C; 640.51 g

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Answer:

Construction

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Buildings
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