A sample is found to contain 66.5% NaHCO3 by mass. What is the mass of NaHCO3 in 4.25g of the sample?

Answers

Answer 1

Answer:

2.83 grams NaHCO₃ in the 4.25g Sample.

Explanation:

Given 4.25g Sample is 66.5% NaHCO₃

=> mass of NaHCO₃ = 0.665(4.25g) =2.83grams NaHCO₃.

Answer 2

The mass of NaHCO₃ in 4.25 g of the sample is 2.83 g

From the question given above, the following data were obtained:

Mass of sample = 4.25 g

Percentage by mass of NaHCO₃ = 66.5%

Mass of NaHCO₃ =?

[tex]Percentage = \frac{mass of substance}{total mass} X 100[/tex]

66.5% = [tex]\frac{Mass of NaHCO_{3} }{4.25}\\\\[/tex]

Cross multiply

Mass of NaHCO₃ = 66.5% × 4.25

Mass of NaHCO₃ = 0.665 × 4.25

Mass of NaHCO₃ = 2.83 g

Therefore, the mass of NaHCO₃ in 4.25 g of the sample is 2.83 g

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Related Questions

1s22s22p63523p645230104p5
Which element is this?
answer : bromine

Answers

Answer:

indeed it 1s22s22p63523p645230104p5 is bromine

how does temperature affect solubility​

Answers

Answer:

The increase in kinetic energy that comes with higher temperatures allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions.

Explanation:

Solubility is affected by temperature due to heatness.

What is the slope of the line on the graph?

Answers

Answer:

6

Explanation:

slope= [tex]\frac{rise}{run}[/tex]

slope=[tex]\frac{6}{1}[/tex]

slope=6

Answer:

its one half

Explanation:

i learned this last week

squence the steps in constructing and interpreting an electron dot diagram

Answers

43 EXPLAINION The cardiac system comes in various different shapes and sizes

What are the basis of making symbols of an element?​

Answers

Each element is given its own chemical symbol, like H for hydrogen or O for oxygen. Chemical symbols are usually one or two letters long. Every chemical symbol starts with a capital letter, with the second letter written in lower case. For example, Mg is the correct symbol for magnesium, but mg, mG and MG are wrong...

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Mg + AgNO3 MgNO3 + Ag

How many grams of magnesium are needed to produce 5.0 moles of silver

Answers

Answer:

539.35 g

Explanation:

molar mass of Mg = moles of Ag * molar mass of Ag

x = 5 * 107.87

x = 539.35 g

write the property of graphite? any two​

Answers

Answer:

Allotrope of carbon.

High melting point.

Explanation:

Answer:

Density lower than that of diamond.

It has soft, slippery feel.

what is the mass percent of a solution prepared from 50.0g nacl and 150.0g of water

Answers

Answer:

Explanation:

In this problem, we have 50.0 g of solute and 150.0 g of water. The total mass of the solution will thus be 50.0 g + 150.0 g = 200.0 g. The mass percent will be 50.0g/200.0 g (x100%) = 25.0 %.

Mass percent of a solution can be defined as grams of solute per 100 grams of solution.  In this problem, we have 50.0 g of solute and 150.0 g of water.  The total mass of the solution will thus be 50.0 g + 150.0 g = 200.0 g.  The mass percent will be 50.0g/200.0 g (x100%) = 25.0 %.  You can also look at it another way.  Since you have 50 g solute in 200 g solution, you will have 25 g solute in 100 g solution.  By the definition provided above, this is a 25% by mass solution.

What would happen to the density of a mass of air that is heated?

Would that mass of air rise above and float on top of cooler air above it or would it sink down below cooler air below it? (Assume that the majority of the masses do not mix.)

Answers

Answer: As air is heated its density decreases because its mass remains constant but its volume increases. As air is cooled, its density increases because its mass remains constant but its volume decreases. ... The decrease in density as air is heated causes it to rise above cooler, more dense air. Hope this helped.

How do you know what’s inside of an atom

Answers

Answer:

microscope

Explanation:

Determine the subunit composition of a protein from the following information:

a. Molecular mass by gel filtration: 200 kD
b. Molecular mass by SDS-PAGE: 100 kD
c. Molecular mass by SDS-PAGE with 2-mercaptoethanol: 40 kD and 60 kD

Answers

Answer:

Explanation:

The protein comprises of two 60-kD polypeptides and two 40-kD polypeptides. Each one of the 40-kD chains has a disulfide-bond which is directly bonded to a 60-kD chain.

The 100-kD units attach noncovalently to produce a protein with a molecular mass of 200 kD. The interaction among the different subunits in the protein is not affected by the Gel filtration chromatography.

Hence, the protein seems to be 200 kD in size. When SDS-PAGE takes place samples are being subjected to heat and therefore undergoing denaturation conditions. The aftermath effect of this causes disorganization in the 100 kD units.

However, the reducing agent (BME) main task is the reduction of disulfide bonds in a protein.

It implies that BME is responsible for the reduction between the R1-S-S-R2 bond between 40 kD and 60 kD to R1-SH and R2-SH, resulting in seperate proteins.

lead 2 nitrate and potassium iodide net ionic equation​

Answers

Answer:

Pb2+(aq) + l+(aq) ------------pbl2(s) net ionic equation

Explanation:

Pb(NO3)2(aq) + kI(aq)------------PbI2(s) + kNo3(aq)

Pb2+ (aq)No3-(aq) + k+(aq) l-(aq) ______PbI2(s) + k+(aq) + NO32+(aq)

Pb2+(aq) + I-(aq). ------------Pbl2(s)

the # molecules in 52.1 grams of NH4OH

Answers

Answer:

Explanation:

Hey there!

From question;

The molecular mass of NH₄OH is 35.

Avogadro number = 6.023*10²³ molecules.

Then,

From mole concept,

Molecular mass =  Avogadro number

So, 35 grams contains  6.023*10²³ molecules.

1 gram contains [tex]\frac{ 6.023*10^{23} }{35}[/tex] molecules.

52.1 grams contains [tex]\frac{6.023*10^{23} }{35} *52.1[/tex] molecules.

Therefore, 52.1 grams contains 8.96*10²³ molecules.

Hope it helps!

Write the name for each of the following chemical formulas.
d. P3N5 (for doping semiconductors)

Answers

Answer:

Triphorphorus Pentanitride

Explanation:

since there are three phosphorus use the prefix tri-, since there are five nitrogen use the prefix penta. tri=3, penta=5. then add a suffix -ide to the end of nitrogen. that will give you triphosphorus pentanitride.

What is the density at 27 °C of 28.0 milliliters of a liquid that has a mass of 4.05 grams?

Answers

Answer:

The answer is 0.14 g/mL

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

mass = 4.05 g

volume = 28 mL

We have

[tex]density = \frac{4.05}{28} \\ = 0.1446428571...[/tex]

We have the final answer as

0.14 g/mL

Hope this helps you

SOMEONE PLEASE HELP I WILL Mark u BRAINLIST

Answers

Answer:

answer 7.4 atm

Explanation:

i did this and got it correct

How many grams are in 2.3 moles of Aluminum

Answers

Answer:

62.1 gram

Explanation:

Al molar mass = 27 g/mol

mass = molar mass × no of moles

= 27 × 2.3 = 62.1 gram

Pure gold has a density of 19.32g/cm^3. You find a gold ring with a mass of 6g and a volume of 0.31cm^3.is this ring pure gold?

Answers

Answer:

Yes, this ring is pure gold because when we divide the mass by the volume we get our density for the ring, which comes out to about 19.32.

Explanation:

How many O atoms are there in 1.51×10^23 molecules of trifluoroacetic acid, C2HF3O2?

Answers

Answer:

9.033 × 10²³ molec C₂HF₃O₂ x (2 O atoms / 1 molec C₂HF₃O₂) = 1.8066 x 10²⁴ O atoms

There are 3.01 × 10^23 atoms of oxygen in 1.51×10^23 molecules of trifluoroacetic acid, C2HF3O2.

The formula of trifluoroacetic acid is C2HF3O2

Number of moles of the trifluoroacetic acid(C2HF3O2)is given using the approach;

1 mole of the compound contains 6.02 × 10^23 molecules

x moles of the compound contains 1.51 × 10^23 molecules

x = 1.51 × 10^23 molecules × 1 mole /6.02 × 10^23 molecules

x = 0.25 moles of  trifluoroacetic acid.

Now;

Number of O atoms in the sample = 0.25 × 2 × NA

Where; NA = Avogadro's number

Number of O atoms in the sample = 0.25 × 2 × 6.02 × 10^23 atoms

= 3.01 × 10^23 atoms

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HELP PLZ!!! A sample contains only the compound CaCl2 and water. When it is dried, its weight decreases from 5.00g to 4.24g. What is the mass percentage of water in the original sample? Round to three significant figures.

Answers

Answer:is 15.2%

Explanation:

Got it wrong and this the correct answer it told me

The percentage of water in the original sample is 15.2 %.

From the information provided in the question;

Weight of the wet sample = 5.00g

Weight of the dried sample = 4.24g

Loss in mass =  5.00g - 4.24g = 0.76 g

percentage of water in the original sample = Difference in mass between wet and dry sample/ mass of wet sample × 100/1

Hence, when we substitute values;

percentage of water in the original sample =  0.76 g/5.00g × 100/1

percentage of water in the original sample = 15.2 %

So, the percentage of water in the original sample is 15.2 %.

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Number of electrons for all of these even the ones with a number by them ? Will give brain-list!!!!

Answers

Explanation:

s=2

p=6

d=10

f=14

I hope this was helpful

How do you determine the chemical reactivity for nonmetals by using the periodic table?

Answers

elements increase in reactivity as they go down in groups and up in periods!!

At 600. K how many moles of gas are in a 1.00 L cylinder at atmospheric pressure?

Answers

Answer:

0.02moles

Explanation:

To answer this question, the general gas law equation is used. The General gas law is:

Pv = nRT

Where; P = standard atmospheric pressure (1 atm)

V = volume (L)

n = number of moles

R = Gas law constant

T = Temperature

For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?

Therefore; Pv = nRT

n = PV/RT

n = 1 × 1/ 0.0821 × 600

n = 1/49.26

n = 0.0203moles

Hence, there are 0.02 moles of gas.

The number of mole of the gas present in the cylinder is 0.02 mole

From the question given above, the following data were:

Temperature (T) = 600 K

Volume (V) = 1 L

Pressure (P) = 1 atm

Number of mole (n) =?

The number of mole of the gas present in the cylinder can be obtained by using the ideal gas equation (PV = nRT) as illustrated below:

Temperature (T) = 600 K

Volume (V) = 1 L

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

PV = nRT

1 × 1 = n × 0.0821 × 600

1 = n × 49.26

Divide both side by 49.26

[tex]n = \frac{1}{49.26}\\\\[/tex]

n = 0.02 mole

Thus, 0.02 mole of the gas is present in the cylinder.

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The formula for the nitrate ion: NO3 NO2 NO3+​

Answers

Answer:

NO3-

Explanation:

edge2020

no3-Edg 2020

Explanation

Brainliest

Help please I need help fast.

Answers

Answer:

d) It incorrectly describes the two processes

Hope it helps you

And please mark it as the brainliest answer

A 2.74-g sample of a substance suspected of being pure gold is warmed to 72.1 oC and submerged into 15.2 g of water initially at 24.7 oC. The final temperature of the mixture is 26.3 oC. What is the heat capacity of the substance? Could the substance be pure gold?

(The specific heat capacity of water is 4.184 J/g oC)

J/g oC (Round to three significant digits)

Look up the specific heat capacity of gold.

Could the unknown substance be pure gold? Write yes or no in the following box:

Answers

1. The specific heat capacity of the sample of gold obtained is 0.81 J/gºC

2. The substance is not pure gold

1. How to determine the specific heat capacity of gold From the question given above, the following data were obtained:Mass of gold (M₉) = 2.74 gTemperature of gold (T₉) = 72.1 °CMass of water (Mᵥᵥ) = 15.2 g Temperature of water (Tᵥᵥ) = 24.7 °C Equilibrium temperature (Tₑ) = 26.3 °C Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC Specific heat capacity of gold (C₉) =?

The specific heat capacity of the sample of gold can be obtained as follow:

Heat loss = Heat gain

M₉C₉(M₉ –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)

2.74 × C₉(72.1 – 26.3) = 15.2 × 4.184 (26.3 – 24.7)

C₉ × 125.492 = 101.75488

Divide both side by 125.492

C₉ = 101.75488 / 125.492

C₉ = 0.81 J/gºC

2. How to determine if the substance is pure Specific heat capacity of gold calculated = 0.81 J/gºC Specific heat capacity of pure gold = 0.13 J/gºC

From the above we can conclude that the substance is not pure gold since the calculated and standard value of the specific heat capacity of the gold sample is not the same

Learn more about heat transfer:

https://brainly.com/question/6363778

What do scientists do to determine if their results support their hypothesis?

Answers

Answer:

They experiment, and study

Explanation:

Repeat your experiments several times to make sure that the first results weren't just an accident.

This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar):
CH. CO,H
An analytical chemist has determined by measurements that there are 4.2 moles of carbon in a sample of acetic acid. How many moles of hydrogen are in the
sample?
Be sure your answer has the correct number of significant digits.

Answers

Answer:

2.408 moles of hydrogen are in the sample.

Explanation:

Molecular formula of acetic acid =CH3COOH

Ratio of carbon to hydrogen :2/4:1/2

Measured  number of moles of carbon atoms = 1.204

Let the moles of hydrogen be = x

Number of carbon atoms in 1.204 mol = 1.204mol*Avogadro number

Number of hydrogen atoms in x mol = x*Avogadro number

As we know that ratio of carbon to hydrogen atoms is 1:2.

1/2=1.204mol* avogadro/ x* avogadro

x = 2.408 moles

2.408 moles of hydrogen are in the sample.

What's meant by chemistry

Answers

Answer: Chemistry is the properties, composition, and structure of elements and compounds, how they can change, and the energy that is released or absorbed when they change.

Explanation:

Answer:

The scientific study of the structure of substances and what happens to them in different conditions or when mixed with each other is known as Chemistry.

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Explain what happens to the imidazole side chain of histidine in a buffer of pH 4.0 and at pH 10.2.

Answers

Histidine, an essential amino acid, has as a positively charged imidazole functional group. The imidazole makes it a common participant in enzyme catalyzed reactions. The unprotonated imidazole is nucleophilic and can serve as a general base, while the protonated form can serve as a general acid.

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