The new temperature (in °C) of the gas, given the data is –148.20 °C
Data obtained from the question Initial temperature (T₁) = 149.05 °C = 149.05 + 273 = 422.05 KInitial pressure (P₁) = 349.84 KPa Volume = constant New pressure (P₂) = 103.45 KPaNew temperature (T₂) =? How to determine the new temperatureThe new temperature of the gas can be obtained by using the combined gas equation as illustrated below:
P₁V₁ / T₁ = P₂V₂ / T₂
Since the volume is constant, we have:
P₁ / T₁ = P₂ / T₂
349.84 / 422.05 = 103.45 / T₂
Cross multiply
349.84 × T₂ = 103.45 × 422.05
Divide both side by 349.84
T₂ = (103.45 × 422.05) / 349.84
T₂ = 124.80 K
Subtract 273 from 124.80 K to express in degree celsius
T₂ = 124.80 – 273
T₂ = –148.20 °C
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What component of NADH is a vitamin, and how does this part of the cofactor function in oxidation-reduction reactions
The Part of Nicotinamide Adenine Dinucleotide NADH that is a vitamin is niacin, a type of B vitamin.
This cofactor acts as a hydrogen acceptor in oxidation-reduction reactions.
What Is NADH?NADH is the reduced form of the NAD+, which means that it gains the electron lost by NAD+. NADH is a very important coenzyme central to metabolism.
NADH is a dinucloetide because it consists of two nucleotides joined through their phosphate groups.
One nucleotide contains an adenine nucleobase and the other nicotinamide.
What Is a Cofactor?
A cofactor is a non-protein chemical compound or metallic ion that is required for an enzyme's role as a catalyst in a chemical reaction. A cofactor binds to an enzyme to bring about its catalytic reaction.
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Which of the following results in an increase in the entropy? (4 points)
Freezing water
Cooling a solid
Condensing water vapor
Dissolving sugar in water
Dissolving sugar in water results in an increase in the entropy.
Hence, Option (D) is correct answer.
What is Entropy ?Measurement of randomness of a system is called entropy. It is an extensive property. It is a state function. Unit of entropy is JK⁻¹ mol⁻¹.
Now lets check all options one by one
Option (A): Freezing water
Freezing water decreases the entropy because here second law of thermodynamics does not violate.
So it is incorrect option
Option (B): Cooling water
Cooling water does not increases entropy because entropy increases when solid melts to give liquid.
So it is incorrect option
Option (C): Condensing water vapour
In Condensing water vapour the temperature of liquid phase decreases and thus kinetic energy decreases. The randomness will decrease and hence entropy will also decrease.
So it is incorrect option.
Option (D): Dissolving sugar in solute
In dissolving sugar in solute the solid dissociates to ions and the randomness will increase and hence entropy will also increase.
So it is correct option
Thus from the above conclusion we can say that Dissolving sugar in water results in an increase in the entropy.
Hence, Option (D) is correct answer.
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A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively. What is the partial pressure in torr of the carbon dioxide in the mixture
A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively. 27.1 torr is the partial pressure of the carbon dioxide in the mixture.
What is Dalton's Law of Partial Pressure ?Dalton's Law of partial pressure states that the total pressure exerted by non reacting gaseous mixture at a constant temperature and given volume is equal to the sum of partial pressure of all gases.
It is expressed as:
[tex]P_{A} = X_{A} P_{T}[/tex]
where,
[tex]P_{A}[/tex] = Partial pressure of gas A
[tex]X_{A}[/tex] = Mole fraction of gas A
[tex]P_{T}[/tex] = Total pressure
Mole Fraction of Nitrogen
= [tex]\frac{930}{930 + 850}[/tex]
= 0.52
Mole Fraction of Oxygen
= [tex]\frac{850}{850 + 930}[/tex]
= 0.47
Now,
Mole fraction of nitrogen + Mole fraction of oxygen + Mole fraction of carbon dioxide = 1
⇒ 0.52 + 0.47 + Mole fraction of carbon dioxide = 1
⇒ 0.99 + Mole fraction of carbon dioxide = 1
⇒ Mole fraction of carbon dioxide = 1 - 0.99
⇒ Mole fraction of carbon dioxide = 0.01
Now put the value in above expression we get
[tex]P_{A} = X_{A} P_{T}[/tex]
= 0.01 × 2710
= 27.1 torr
Thus from the above conclusion we can say that A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively. 27.1 torr is the partial pressure of the carbon dioxide in the mixture.
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a plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. what is its water potential? show your work if it is placed in a solution with a water potential of -1.0 what will happen to this plant cell
A plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. Its water potential is -2 bar. The cell will gain water or swell.
What is Water Potential ?Water Potential is the potential energy of water in a system per unit volume relative to pure water , when both pressure and temperature are kept same. Water potential is never positive. It is expressed in kPa (Kilopascals). The symbol of water potential is ψ.
How to find the Water Potential ?To find the water potential use this formula
[tex]\Psi = \Psi_{s} + \Psi_{p}[/tex]
where,
ψ = Water Potential
[tex]\Psi_{s}[/tex] = Solute Potential
[tex]\Psi_{p}[/tex] = Pressure potential
Now put the value in above expression we get
[tex]\Psi = \Psi_{s} + \Psi_{p}[/tex]
= -2.0 + 0.0
= - 2 bar
Thus from the above conclusion we can say that A plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. Its water potential is -2 bar. The cell will gain water or swell.
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How many molecules of H₂O are
equivalent to 97.2 g H₂O?
(H = 1.008 g/mol, O = 16.00 g/mol)
[?]
[?]x10 molecules
Enter your answer with the correct number of
significant figures and be sure the prefix is a number
between 1 and 10!
dro's Number = 6.02 x 1023 molecules/mole
Answer:
3.25 x 10²⁴ molecules H₂O
Explanation:
To find the number of H₂O molecules, you need to (1) convert grams to moles (via molar mass) and then (2) convert moles to molecules (via Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.
Atomic Mass (H): 1.008 g/mol
Atomic Mass (O): 16.00 g/mol
Molar Mass (H₂O): 2(1.008 g/mol) + 16.00 g/mol
Molar Mass (H₂O): 18.016 g/mol
Avogadro's Number:
6.02 x 10²³ molecules = 1 mole
97.2 g H₂O 1 mole 6.02 x 10²³ molecules
------------------ x ------------------- x ------------------------------------ =
18.016 g 1 mole
= 3.25 x 10²⁴ molecules H₂O
PLEASE HELP!
You are preparing standard acid and base solutions for the laboratory, using potassium hydrogen phthalate (KHC₈H₄O₄, abbreviated KHP) as the primary standard. KHP (molar mass = 204.22 g/mol) has one acidic hydrogen. You prepared solutions of both NaOH and HCl. It took 22.65 mL of the NaOH solution to titrate (react exactly with) 1.55 g KHP. It then took 25.35 mL of HCl solution to titrate 25.00 mL of the NaOH solution. What is the molarity of the HCl solution?
Other than reducing greenhouse gas emissions, why would an entity switch to an alternative energy solution
Answer:
renewable energy sources such as solar and wind DONT emit carbon dioxide and other greenhouse gases that contribute to global warming
Explanation:
Which diagram is the correct electron dot diagram for magnesium?
A.
A symbol of magnesium M g has four dots representing four free electrons.
B.
A symbol of magnesium M g has three dots representing three free electrons.
C.
A symbol of magnesium M g has one dot representing one free electron.
D.
A symbol of magnesium M g has two dots representing two free electrons.
Answer:
D.) A symbol of magnesium Mg has two dots representing two free electrons.
Explanation:
Magnesium is located in the second group (column) of the periodic table. Elements located here have 2 valence electrons in their outermost shell. Thus, the electron dot diagram of magnesium has 2 dots symbolizing the 2 valence electrons.
50.) a 26 m tall statue of buddha in tibet is covered with 279 kg of gold. if the gold
was applied to a thickness of 0.0015 mm, what surface area (in square units) was
covered? [gold's density is 19,320 kg/m?]
The surface area of the statute covered with the gold is 9,627.32 m².
What is Volume?
Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.
Volume of the statute covered with gold
The volume of the statute covered with gold is calculated as follows;
Volume = mass/density
Volume = (279 kg) / (19,320 kg/m³)
Volume = 0.0144 m³
Surface area of the statute covered with goldThe surface area of a solid object is a measure of the total area that the surface of the object occupies.
V = S.A x h
where;
S.A is surface areah is thicknessS.A = V/h
S.A = (0.0144) / (0.0015 x 10⁻³)
S.A = 9,627.32 m²
Thus, the surface area of the statute covered with the gold is 9,627.32 m².
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Calculate the molar mass of powdered fruit drink mix, made from sucrose (c12h22o11). appreciate it.
molar mass of sucrose is 342 g/mol.
Concept:
It is the substance's molecular mass. M is the abbreviation for it, and g/mol is the standard unit for measuring molar mass.
Given:
Sucrose (C12H22O11)
Find:
Calculate the molar mass of the powdered fruit drink mix, made from sucrose (C12H22O11).
Solution:
The molar mass of carbon = 12 g/mol
The molar mass of hydrogen = 1 g/mol
The molar mass of oxygen = 16 g/mol
Thus, the molar mass of sucrose can be calculated as:
C12H22O11 12 C + 22 H + 11 O
= 12 12 g/mol + 22 * 1 g/mol + 11 * 16 g/mol
= 144 g/mol + 22 g/mol + 176 g/mol = 342 g/mol
Therefore, the molar mass of sucrose is 342 g/mol.
Hence, the molar mass of the powdered fruit drink mix, made from sucrose
Hence, the molar mass of the powdered fruit drink mix, made from sucrose(C12H22O11) is 342 g/mol.
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If sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose. A solution of sucrose at room temperature does not readily decompose to form a solution of simple sugars because
The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose because the activation energy of the reaction is high.
Hence, Option (B) is correct answer.
What is Activation Energy ?The minimum amount of energy that must be provided by a reacting molecules to get converted into the product is called Activation energy.
It is expressed as:
[tex]k = Ae^{\frac{-E_a}{RT}}[/tex]
where,
k = rate constant
A = pre-exponential factor
Eₐ = activation energy
R = universal gas constant
T = absolute temperature in K
Thus from the above conclusion we can say that The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose because the activation energy of the reaction is high.
Hence, Option (B) is correct answer.
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Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose. Why?
A. The change in free energy of the reaction is positive.
B. The activation energy of the reaction is high.
C. The change in free energy of the reaction is negative.
D. This is a hydrolysis reaction, so it requires an input of energy.
E. The free energy of the products is higher than the free energy of the reactants.
Which models of the atom from task 1 are not supported by rutherfords experimental evidence?
Model not supported is:
Thomson's atomic model of the atom from task 1 are not supported by Rutherford's experimental evidence.
Experiments given by Thomson, Rutherford & Dalton:
The cathode ray tube experiments of J.J. Thomson demonstrated that all atoms contain minute, electron-like subatomic particles that are negatively charged.The plum pudding model of the atom was put up by Thomson and featured negatively charged electrons embedded within a positively charged "soup."The majority of an atom is empty space, with a small, dense, positively-charged nucleus, as demonstrated by Rutherford's gold foil experiment.Rutherford postulated the nuclear model of the atom in light of these findings.Atoms, in Dalton's opinion, are the tiniest pieces of matter that can never be further divided. This belief persisted up until the time it was learned that the atom was made up of subatomic particles.Dalton and Thomson's concepts are in conflict with the experimental findings of Rutherford. Dalton's model is unsupported by evidence because it does not include electrons, protons, or neutrons.
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Calculate the pH of a buffer solution prepared by mixing 75.0 mL of 1.00 M lactic acid and 25.0 mL of 0.50 M sodium lactate.
From the calculations, the pH of the buffer is 3.1.
What is the pH of the buffer solution?The Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;
pH = pKa + log[(salt/acid]
Amount of the salt = 25/1000 * 0.50 M = 0.0125 moles
Amount of the acid = 75/1000 * 1.00 M = 0.075 moles
Total volume = ( 25 + 75)/1000 = 0.1 L
Molarity of salt = 0.0125 moles/0.1 L = 0.125 M
Molarity of the acid = 0.075 moles/0.1 L = 0.75 M
Given that the pKa of lactic acid is 3.86
pH = 3.86 + log( 0.125/0.75)
pH = 3.1
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how many moles are in 2.00g of H2O
n = m/M = 2/18 = 1/9 ~0,1 mol
Answer:
.111 mole (using 3 significant digits)
Explanation:
Mole weight of H2O = 2 x 1.008 + 15.999 = 18.015 gm/mole
2 gm / 18.015 gm/mole = .111 mole
A cabbage p h indicator color key. entries are 0 to 2, bright red; 3 to 4, pink; 5 to 6, purple; 7, dark violet; 8 to 9, blue; 10 to 11, bright green; 12 to 13, lighter green. why would you use a solution, such as a cabbage ph indicator, to measure the ph of household items? to see if food went bad to test the safety of water to make sure conditions are safe to use up old cabbage
We use a solution, such as a cabbage ph indicator, to measure the ph of household items :
to see if food went badto test the safety of waterto make sure conditions are safeCabbage ph indicator:Anthocyanin, a water-soluble pigment found in red cabbage, can change color when combined with an acid or a basic. The color changes to red in situations with a pH under 7, and to bluish-green in alkaline (basic) environments with a pH above 7. Cabbage isn't known to cause acid reflux, but plenty of other common foods are.
Anthocyanin turns pink when it interacts with the hydronium ions in an acid, and blue or green when it interacts with the hydroxide ions in a base. Because it may inform us if a substance is acidic or basic by changing color, cabbage juice is referred to as a pH indicator.
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What is the molar solubility of AgCl in a 0.050 M NaCl solution? The Ksp of AgCl is 1.6 x 10-10. (Assume that the contribution of [Cl-] from AgCl is negligible relative to the [Cl-] from NaCl)
The molar solubility of AgCl:
The molar solubility of AgCl in a 0.050 M NaCl solution is 8 x [tex]10^{-8}[/tex] M [tex]Ag^{+}[/tex]
What is solubility?
The solubility is the quantity of reagent required to saturate the solution or bring about the dissociation reaction's equilibrium.
Reaction:
The dissociation reaction of AgCl in water is:
[tex]AgCl[/tex] ⇄ [tex]Ag^{+} + Cl^{-}[/tex]
Each mole of AgCl that dissolves in this reaction yields 1 mole of both [tex]Ag^{+}[/tex] and [tex]Cl^{-}[/tex]. The concentration of either the Ag or Cl ions would then be equal to the solubility.
Solubility= [[tex]Ag^{+}[/tex]] = [[tex]Cl^{-}[/tex]]
Calculation:
in 0.050 M NaCl, the [[tex]Cl^{-}[/tex]] = 1 x [tex]10^{-2}[/tex]
ksp = [[tex]Ag^{+}[/tex]] x [[tex]Cl^{-}[/tex]]
1.6 x [tex]10^{-10}[/tex] = [[tex]Ag{+}[/tex]] x ( 5 x [tex]10^{-2}[/tex])
[[tex]Ag^{+}[/tex]] = 5 x [tex]10^{+2}[/tex] x 1.6 x [tex]10^{-10}[/tex]
[[tex]Ag^{+}[/tex]] = 5 x 1.6 x [tex]10^{-10+2}[/tex]
[[tex]Ag^{+}[/tex]] = 8 x [tex]10^{-8}[/tex] M
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Which molecule will undergo only london dispersion forces when interacting with other molecules of the same kind?.
Molecules undergo London dispersion forces:
[tex]C_{4}H_{10}[/tex] is the molecule will undergo only London dispersion forces when interacting with other molecules of the same kind.
What are London dispersion forces?
A sort of force that interacts between atoms and molecules that is often electrically symmetric is referred to as a London dispersion force.When viewed from the nucleus, their electron distribution is frequently symmetrical. This dispersion force, which is also known as a transient attractive force, is frequently observed when the locations of the electrons in two nearby atoms cause the atoms to temporarily form dipoles.The bond is polar when there are significant variations between the elements' electronegativities; it is nonpolar when there are similarities. When the molecule's dipole moment is equal to O, it is nonpolar; when it differs from O, it is polar.The force at these molecules is known as the London dispersion force. In nonpolar molecules, the forces are weak, and partial charges must be induced so that they can bond. In polar molecules, partial charges caused by polarity result in a stronger link known as a dipole-dipole. The dipole-dipole is significantly stronger and known as a hydrogen bond if it is connected to a large electronegative atom (F, O, or N). Ionic force is the name for the attraction force at ionic substances.The intermolecular force in the letter an is the London dispersion force because the compound is nonpolar;Reason for incorrect options:
b: the compound is ionic because Na is a metal and the other part is covalent,
c: two compounds are possible: one is nonpolar and exhibits London dispersion force; the other is polar and exhibits dipole-dipole force; and
d: both compounds exhibit hydrogen bonds (H bonded to O, and H bonded to F).
NOTE: Your question is incomplete, but most probably your full question was, which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind? Which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind?
A. [tex]C_{4}H_{10}[/tex]
B. [tex]NaC_{2}H_{3}O_{2}[/tex]
C. [tex]CH_{2}C_{12}[/tex]
D. [tex]C_{2}H_{5}OH HF[/tex]
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The molecule CH₂O contains two single bonds and one double bond. True or false
Answer:
The answer to your question is True
Explanation:
CH2O is a polar molecule. It has three polar bonds that are arranged asymmetrically, thus allowing their dipole moments to add up and give the molecule an overall dipole moment. CH2O has a central carbon atom that forms two single bonds with the two hydrogen atoms and a double bond with the oxygen atom.
I hope this helps and have a good day!
The emission spectrum of sodium is shown below. What do the two bright
yellow vertical lines in the spectrum show about sodium atoms?
The two lines show that these are the only two lines that do not cause energy transition in the sodium atom. Option D
What are the two lines in the spectrum of sodium atom?The spectrum of the sodium atom appears as a doublet. This implies that there are two lines in the spectrum and they appear as bright yellow lines that are not spaced apart in the spectrum.
The two bright yellow vertical lines in the spectrum shows that these are the only two lines that do not cause energy transition in the sodium atom.
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Need this answered ASAP
The concentration of the final solution will be 0.2886 M.
Molar concentration50.6 g of NaCl is dissolved in 600 mL of water.
Mole of 50.6 g NaCl = 50.6/58.44 = 0.8658 mol
Molar concentration of the oiriginal solution = 0.8658/06 = 1.4431 M
25 mL of 1.4431 M of the solution is diluted up to the 125 mL mark.
m1 = 1.4431, v1 = 25 ml, v2 = 125 mL
m2 = m1v1/v2 = 1.4431 x 25/125 = 0.2886 M
The concentration of the final solution will be 0.2886 M
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What type of molecule is shown below?
S
H-C=C-CH2-CH3
O A. An alkene-alkyne
OB. An alkane-alkyne
OC. An alkyne
O D. An alkane
H - C ≡ C - CH₂ - CH₃ this is an alkyne molecule.
Hence, Option C is correct answer.
What is Alkane ?The saturated hydrocarbon which have only single bonds between the carbon atoms is called Alkanes.
What is Alkene ?The unsaturated hydrocarbon which have at least one carbon carbon double bond is called Alkene.
What is Alkynes ?The unsaturated hydrocarbon which have one or more than one carbon carbon triple bonds is called Alkynes.
H - C ≡ C - CH₂ - CH₃ in this molecule one triple bond is present so it is alkyne.
Thus from the above conclusion we can say that H - C ≡ C - CH₂ - CH₃ this is an alkyne molecule.
Hence, Option C is correct answer.
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Organic molecules (amino acids) needed to be concentrated to stimulate reactions to form proteins concentration mechanisms do not include:___.
Organic molecules (amino acids) needed to be concentrated to stimulate reactions to form protein concentration mechanisms that do not include Boiling.
Amino acids are natural compounds composed particularly of nitrogen, carbon, hydrogen, and oxygen. Your body desires 20 awesome amino acids to grow and function. amino acid, any of a group of organic molecules that consist of a basic amino group (―NH2), an acidic carboxyl group (―COOH).
fruits have an excessive content of amino acid that allows modify insulin degrees. fruits like bananas, apples, berries, and so forth., are rich resources of amino acids.
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With a good mask-to-face seal and an oxygen flow rate of 15 L/min, the nonrebreathing mask is capable of delivering up to ______% inspired oxygen.
With a good mask-to-face seal and an oxygen flow rate of 15 L/min, the nonrebreathing mask is capable of delivering up to 90% inspired oxygen.
What is fraction of inspired oxygen?FiO2 is the fraction of inspired oxygen which is explained as the concentration of oxygen inhaled by a person.
Non breather mask:It delivers a high concentration of oxygen. Hence the liter flow will be 8-15L/min with the percentage of oxygen between 60-90%.
The liter flow of nonbreathing mask must not be less than 8L/min.
From the above information we can conclude that the fraction of inspired oxygen for a nonbreathing mask is 90%
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A saturated solution of baso4 has a concentration of 0.5mol/l. a 55ml sample is taken by you. what is the mass of baso4 in the solution
Answer:
6.4 g BaSO₄
Explanation:
You have been given the molarity and the volume of the solution. To find the mass of the solution, you need to (1) find the moles BaSO₄ (via the molarity ratio) and then (2) convert moles BaSO₄ to grams BaSO₄ (via the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to reflect the sig figs of the given values.
Molarity (mol/L) = moles / volume (L)
(Step 1)
55 mL / 1,000 = 0.055 L
Molarity = moles / volume <----- Molarity ratio
0.5 (mol/L) = moles / 0.055 L <----- Insert values
0.0275 = moles <----- Multiply both sides by 0.055
(Step 2)
Molar Mass (BaSO₄): 137.33 g/mol + 32.065 g/mol + 4(15.998 g/mol)
Molar Mass (BaSO₄): 233.387 g/mol
0.0275 moles BaSO₄ 233.387 g
--------------------------------- x ------------------- = 6.4 g BaSO₄
1 mole
The density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 via a combustion reaction
The answer is 9.94 ml.
What is density?Density is a word we use to describe how much space an object or substance takes up (its volume) in relation to the amount of matter in that object or substance (its mass). Another way to put it is that density is the amount of mass per unit of volume. If an object is heavy and compact, it has a high density.Given,
The density of ethanol, C2H5OH = 0.789 g/mL
[tex]n (CO_{2} ) = \frac{m}{M} = \frac{15G}{44 g/mol} } = 0.341 mol;[/tex]
[tex]n ( C_{2} H_{2} OH) = \frac{n (CO_{2}) }{2} = \frac{0.341}{2} = 0.1705 mol;[/tex]
[tex]m (C_{2} H_{2} OH) = 0.1705 mol * 46 g/ mol[/tex] = 7.843 g
[tex]V (C_{2} H_{2} OH ) = \frac{7.843}{0.789} = 9.94 ml.[/tex]
Therefore, the answer is 9.94 ml
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The complete question is -
If the density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 according to the following chemical equation?
C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)
1. Determine the amount concentration of calcium ions and acetate ions in a 0.80 mol/L
solution of calcium acetate (work out formula first).
Since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.
What is concentration?The term concentration has to do with the amount of substance in solution. The concentration can be measured in several units. Generally, concentration is expressed in molarity, molality, mass concentration units or percentage.
Now we are asked to find the amount concentration of calcium ions and acetate ions in a 0.80 mol/L solution of calcium acetate. The formula of calcium acetate is Ca(CH3COO)2.
Thus;
Ca(CH3COO)2(aq) ----> Ca^2+(aq) + 2CH3COO^-(aq)
It then follows that since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.
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What is the molality of a solution prepared by dissolving 2.00 ml of bromine (d = 3.105 g/ml) in 125 ml of acetic acid, hc2h3o2 (d = 1.05 g/ml) (ans. 0.30 m)?
The molality of a solution is 0.304g
Calculation,
Given data,
Volume of bromine = 2 mldensity of bromine = 3.105 g/ml Volume of acetic acid = 125 mldensity of of acetic acid = 1.05 g/mlDensity of bromine = 3.105 g/ml = mass / volume = mass / 2 ml
Mass of bromine = 3.105 g/ml × 2 ml = 6.206 g
Density of acetic acid = 1.05 g/ml = mass / volume = mass / 125 ml
Mass of bromine = 1.05 g/ml × 125 ml = 127.5 g
Molality = mass of solute in gram/molar mass of solute × 1000/mass of solvent in gram
Molality = 6.206 g/159.88 g/mol × 1000/127.5 g = 0.304 g
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a student carried out a combustion reaction with methane (ch4) as the limiting reagent. a 12.0g quantity of methane was used, and the student collected 22.0g of carbon dioxide. what was the percent yield
The total percent yield:
After the combustion reaction with methane, the percent yield was 66.7%.
Combustion of Methane:
Methane produces a blue flame as it burns in the atmosphere.Methane burns in the presence of enough oxygen to produce carbon dioxide (CO₂) and water (H₂O). It creates a significant quantity of heat during combustion, making it an excellent fuel source.The other reactant, air's excess oxygen, is always present, making methane the limiting reactant. As a result, the amount of CH₄ burned will determine how much CO₂ and H₂O are produced.
The following chemical process produces carbon dioxide from methane:
CH₄ + 2O₂ ⇒ CO₂ + 2H₂O
Calculations:
1. Theoretical quantity of carbon dioxide:
All calculations will be based on the amount of methane because the problem specifies that it is the limiting reagent:
12.0g of CH₄ × (1 mol of CH₄/16g CH₄) × (1 mole of CO₂/1 mole of CH₄) × (44g CO₂/1 mole of CO₂)
= 33g of CO₂
2. Percent yield:
= Actual yield/Theoretical yield × 100
= 22.0g/33g × 100
= 66.7%
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If 5. 0 grams of kcl is dissolved in 500 ml of water, what is the concentration of the resulting solution?
If 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.
How to calculate concentration?The concentration of a solution can be calculated by using the following formula;
Molarity = no of moles ÷ volume
According to this question, 5.0 grams of KCl is dissolved in 500 ml of water. The concentration is calculated as follows:
no of moles of KCl = 5g ÷ 74.5g/mol = 0.067mol
Molarity = 0.067mol ÷ 0.5L = 0.134M
Therefore, if 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.
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what causes a wavy pattern of dark and light bands on the bottom of a pond? A P E X learning
A wavy pattern of dark and light bands on the bottom of a pond is caused by refraction of light waves through a rough surface; option D.
What is destructive interference?Destructive interference occur when two waves come in contact with each other and cancel each other out.
Reflection and refraction of light waves can result in destructive interference. An example of destructive interference due to refraction of light is a wavy pattern of dark and light bands on the bottom of a pond.
In conclusion, destructive interference occurs when waves cancel each other out.
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The answer to the question is D.