The given chemical equation represents a reversible reaction in which two molecules of sulfur trioxide (SO₃) react to form two molecules of sulfur dioxide (SO₂) and one molecule of oxygen gas (O₂).
What are the concentrations of SO₃, SO₂, and O₂at equilibrium?The problem states that a 1-liter flask contains 0.50 moles of SO₃, 0.20 moles of SO₂, and 0.30 moles of O₂. These three substances react with each other to reach equilibrium, which can be determined using the equilibrium constant (Kc).
At equilibrium, the concentration of oxygen gas (O₂) is given as 0.52 M. This information can be used to calculate the concentrations of sulfur trioxide (SO₃) and sulfur dioxide (SO₂) at equilibrium using the equilibrium constant (Kc) and the initial concentrations of the reactants.
Using the given equation for the equilibrium constant and the initial concentrations of the reactants, we can write:
Kc = [SO₂]²[O₂] / [SO₃]²
Substituting the given values, we get:
59 = [0.20 mol/L]² (0.52 mol/L) / [0.50 mol/L]²
Solving for SO₃], we get:
[SO₃] = [tex]\sqrt{[(0.20 mol/L)² (0.52 mol/L) / 59] }[/tex]= 0.10 mol/L
Similarly, solving for [SO₂], we get:
[SO₂] = 2 [SO₃] = 0.20 mol/L
Therefore, at equilibrium, the concentrations of SO₃, SO₂, and O₂are 0.10 M, 0.20 M, and 0.52 M, respectively. This means that the reaction has favored the production of SO₂and O₂ over the reactant SO₃ at equilibrium.
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Answer the following questions about the fermentation of glucose (C6H12O6, molar mass 180.2 g/mol) to ethanol (C2H6O) and CO2.
C6H12O6(s) → 2 C2H6O(l) + 2 CO2(g) ΔH = −16 kcal/mol
glucose ethanol
How many kilocalories of energy are released from 40.0 g of glucose?
kcal of energy released
Report answer to TWO significant figures.
Answer:
Explanation:
40/ 180.2 x (-16 / 1 mole glucose)=-3.6 KJ
Determine the pressure (in atm) of a 7.16-g sample of He gas at 692 K in a container with a volume of 55.9 L.
Answer:
1.82 atm
Explanation:
Ideal gas law
P=nRT/V
1) solve for n which is moles
7.16 / 4 = 1.79 mole He
2)
n=1.79
R=0.0821
T=692 K
V=55.9
P=1.79 X 0.0821 X 692 / 55.9 =1.82 atm
Part A Find the magnitude of the electric force, ignoring the sign, that the water molecule exerts on the chlorine ion. The dipole moment of the water molecule (H2O) is 6.17 x 10-30 C.m. Consider a water molecule located at the origin whose dipole moment p points in the positive x direction. A chlorine ion (C1_), of charge – 1.60 x 10-19 C, is located at x = 3.00 x 10–9 meters. Assume that this x value is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis can be used. ► View Available Hint(s) = Η ΑΣΦ J ? a 18 xa Хь vx x x х х |X| ] X.10n 6 x x N Submit Previous Answers
The magnitude of the electric force that the water molecule exerts on the chlorine ion is 1.08×10-58 N.
The first thing we need to know is that:
Electric force is given by;
[tex]F=kq1q2d2[/tex]
Where, k=Coulomb's constant=9×109, N⋅m2⋅C-2q1 and q2 are charges, d is distance between charges, thus this formula applies to point charges. However, in this question, we are not given point charges, but a dipole moment.
So we can use the equation:
[tex]F=E2p[/tex]
where, E is the electric field and, p is the dipole moment. Thus, to find the magnitude of the electric force that the water molecule exerts on the chlorine ion, we have to calculate the electric field of the dipole moment at the location of the chlorine ion, and then multiply the result by the magnitude of the dipole moment.
Part B:
Electric field of a dipole moment at any point on the axial line is given by;
[tex]E=2kp cosθr3[/tex]
where, k is Coulomb's constant,θ is the angle between the dipole moment and the axial line, and, r is the distance from the center of the dipole moment to the point where the electric field is measuredcosθ=1, because the angle between the dipole moment and the axial line is 0°.
Thus, we have;
[tex]E=2kp r3[/tex]
where, p is the magnitude of the dipole moment, r is the distance between the center of the dipole moment and the point where the electric field is measured.
Therefore, at the location of the chlorine ion, we have;
r=3.00×10-9m
Applying the formula for electric field
[tex]E=2kp r3E[/tex]
=2(9×109 N⋅m2⋅C-2)(6.17×10-30 C⋅m)(3.00×10-9m)3
=1.25×10-4 N/C
Thus, the magnitude of the electric force that the water molecule exerts on the chlorine ion is given by;
F=E2p
F=(1.25×10-4 N/C)2(6.17×10-30 C⋅m)
F=1.08×10-58 N
Therefore, the magnitude of the electric force that the water molecule exerts on the chlorine ion is 1.08×10-58 N.
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is the energy of the surroundings increases for any chemical reactoin supported by the first law of thermodynamics
Yes, the increase in surrounding energy for any chemical reaction is supported by the first law of thermodynamics, which means that the total energy in the universe is constant.
Thermodynamics is the branch of science concerned with the study of heat changes in various chemical processes. There are four basic laws of thermodynamics named zeroth law, first law, second law, and third law which represents all changes in reaction.
The first law of thermodynamics states that "energy cannot be created or destroyed in a chemical reaction, but can be converted from one form to another", and if a system loses energy in the process, it can gain some through the environment.
It simply changes from one form to another, so the total energy of the universe is conserved.
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Complete question:
Is the energy of the surroundings increases for any chemical reaction supported by the first law of thermodynamics?
FILL IN THE BLANK bone cells called _______ break down bone by secreting hydrochloric acid and enzymes that dissolve the matrix.
Bone cells called osteoclasts break down bone by secreting hydrochloric acid and enzymes that dissolve the matrix.
Bone cells called osteoclasts break down bone by secreting hydrochloric acid and enzymes that dissolve the matrix.
A type of bone cell called an osteoclast degrades bone tissue. This function is essential for the upkeep, restoration, and remodelling of the vertebral skeleton's bones. By secreting acid and a collagenase, the osteoclast breaks down and digests the composite of hydrated protein and mineral at the molecular level, a process known as bone resorption. The blood calcium level is likewise regulated by this process.
Osteoclasts are multinucleated cells that originate from white blood cells of the monocyte/macrophage family. They are the cells responsible for the breakdown of bone (osteolysis) during normal bone growth and maintenance processes. Osteoclasts are critical for bone remodeling and maintenance, as they resorb and dissolve mineralized bone tissue, releasing calcium and other ions into the bloodstream.
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Which of the following species is amphoteric? Answer HPO42- CO32- HF NH4 None of the above are amphoteric
Among the given species, the only one that is amphoteric is the carbonate ion, CO₃²⁻.
What are amphoteric species ?Amphoteric species are chemical species that can act as both an acid and a base. This means that they can donate or accept a proton (H⁺) depending on the conditions of the reaction. For example, water (H₂O) is an amphoteric molecule because it can act as an acid when it donates a proton to a strong base, such as hydroxide ion (OH⁻), to form the hydronium ion (H₃O⁻). Water can also act as a base when it accepts a proton from a strong acid, such as hydronium ion, to form the hydroxide ion.
Among the given species, the only one that is amphoteric is the carbonate ion, CO₃²⁻. This is because it can accept a proton (H⁺) to form bicarbonate ion (HCO₃⁻) in the presence of a strong acid, or it can donate a proton to a strong base to form the hydrogencarbonate ion (HCO₃⁻).
The others are not amphoteric species. HPO₄²⁻ is a conjugate base of a weak acid ( H₂PO₄⁻), which means it can only act as a base. HF is a weak acid and can act as an acid but not a base. NH₄⁺ is a weak acid and can act as an acid, but not a base.
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What is the bond angle of carbonothioyl dibromide
Also what is the molecular shape
Answer:
Carbonothioyl dibromide, also known as CBr2S, has a bond angle of approximately 109.5 degrees, which is the typical tetrahedral bond angle for molecules with sp3 hybridization.
The molecular shape of CBr2S is also tetrahedral, with the two bromine atoms and the sulfur atom arranged at the corners of a tetrahedron, and the carbon atom at the center.
How many oxygen atoms are I one molecule of serotonin
Answer:
There are no oxygen atoms in one molecule of serotonin. Serotonin (5-hydroxytryptamine) is a monoamine neurotransmitter that is composed of carbon, hydrogen, and nitrogen atoms. Its chemical formula is C10H12N2O.
Explanation:
Answer:1 atom
Explanation: it’s at the end of the molecule
consider the following reaction: compound 5.69 205.0 213.6 what is the standard free energy of the reaction at ?
The standard free energy of the reaction at 23.0 °C is -394.4 kJ/mol, which can be calculated using the Gibbs free energy equation and substituting the given values for standard enthalpy change, standard entropy change, and temperature in Kelvin.
To find the standard free energy of the reaction at 23.0 °C, we can use the Gibbs free energy equation:
ΔG° = ΔH° - TΔS°
where ΔH° is the standard enthalpy change, ΔS° is the standard entropy change, T is the temperature in Kelvin, and ΔG° is the standard free energy change.
First, we need to convert the temperature to Kelvin:
T = 23.0 + 273.15 = 296.15 K
Next, we can substitute the values given in the question:
ΔH° = -393.5 kJ/mol
ΔS° = (213.6 J/K/mol) - [(5.69 J/K/mol) + (205.0 J/K/mol)] = 2.91 J/K/mol
T = 296.15 K
ΔG° = (-393.5 kJ/mol) - (296.15 K)(2.91 J/K/mol)
ΔG° = -393.5 kJ/mol - 862.25 J/mol
ΔG° = -394.4 kJ/mol
Therefore, the standard free energy of the reaction at 23.0 °C is -394.4 kJ/mol.
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The titration of 45.0 ml of an unknown triprotic acid required 32.71 ml of 0.37 M KOH to
reach the endpoint. What is the molarity of the unknown acid?
The molarity of the unknown triprotic acid is 0.269M.
How to calculate molarity?Molarity is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.
The molarity of the unknown acid can be calculated using the following formula:
CaVa = CbVb
Where;
Ca and Va = acid concentration and volume respectivelyCb and Vb = base concentration and volume respectivelyAccording to this question, the titration of 45.0 ml of an unknown triprotic acid required 32.71 ml of 0.37 M KOH to reach the endpoint.
45 × Ca = 32.71 × 0.37
45Ca = 12.1027
Ca = 0.269M
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How many moles of HCl will be produced when 873 g of AlCl3 are reacted according to this chemical equation?
2AlCl3 + 3H2O --> Al2O3 + 6HCl
19.641 moles of HCl will be produced when 873 g of AlCl₃ are reacted according to this chemical equation.
What is the number of moles of HCl produced?To determine the number of moles of HCl produced, we need to first calculate the number of moles of AlCl₃ using its molar mass and the given mass:
Molar mass of AlCl₃ = 133.34 g/mol
Number of moles of AlCl₃ = 873 g / 133.34 g/mol = 6.547 moles
From the balanced chemical equation, we can see that 2 moles of AlCl₃ reacts to form 6 moles of HCl.
So, we can use this ratio to determine the number of moles of HCl produced:
Number of moles of HCl = (6.547 mol AlCl₃) x (6 mol HCl / 2 mol AlCl₃) = 19.641 moles
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300 ml of nitrogen react with 300 ml of hydrogen to form ammonia. N₂ + 3H₂ ---> 2NH3 What volume of ammonia will be formed, if the reaction gets over at the same temperature? a) 100 ml b) 200 ml c)300 ml d) 400 ml
Answer:
According to the balanced chemical equation for the reaction:
N₂ + 3H₂ → 2NH₃
1 volume of nitrogen (N₂) reacts with 3 volumes of hydrogen (H₂) to form 2 volumes of ammonia (NH₃) at the same temperature and pressure.
Therefore, if 300 ml of nitrogen (N₂) reacts with 300 ml of hydrogen (H₂), the limiting reactant will be hydrogen, since it is present in the smallest amount. To find the volume of ammonia (NH₃) formed, we can use the volume ratio from the balanced chemical equation:
1 volume of N₂ + 3 volumes of H₂ → 2 volumes of NH₃
Since we have 300 ml of H₂, which is equivalent to 3 volumes of H₂, the maximum volume of ammonia (NH₃) that can be formed is:
2 volumes of NH₃ = 300 ml of H₂ × (2 volumes of NH₃ / 3 volumes of H₂) = 200 ml
Therefore, the correct option is (b) 200 ml.