A spring with a force constant of 5.0×104 N/m is initially at its equilibrium length.
How much work must you do to stretch the spring 0.070 m?
How much work must you do to compress it 0.070 m?

Answer: I'm not very good at all. I need help with determine the velocity of an object just before it hits the ground, given the object's mass and the distance it falls. For example, a .060 kg (or 60 g) ball falls from a 12 meter building. Also, assume it is free falling (no air resistance) and the average time it takes to hit the ground it 1.16 seconds.

Explanation:

Answer:

Explanation:

initial velocity, u = 43 m/s

final velocity, v = 3.38 m/s

time, t = 70 sec

acceleration, a = v - u / t

3.38 - 43 / 70

= -39.62/ 70

= -0.56 m/s^2

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The force of attraction between the balloon and the rod is 9 x 10⁻³ N.

The force of attraction between the balloon and the rod is calculated by applying Coulomb's law as shown below;

[tex]F = \frac{kq_1 q_2}{r^2}[/tex]

where;

F = (9 x 10⁹) x (2.0 x 10⁻⁸)²/(0.02)²

F = 9 x 10⁻³ N

Thus, the force of attraction between the balloon and the rod is 9 x 10⁻³ N.

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[tex]\:\:\:\:\:\:\:\:\:\:\star [/tex]We can calculate the force between the balloon and the rod applying "Coulomb's Law". Which states-

[tex]\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{F_{(air)} = K\times \dfrac{ q_1 q_2}{r^2}} \\ [/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\star\:\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ [/tex]

Where-

As per question, we are given that -

Now that required values are given, so we can substitute the values into the formula and solve for Force -

[tex] \:\:\:\:\:\:\:\:\:\:\star\:\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= 9\times 10^9 \times \dfrac{-2\times 10^{-8}\times 2\times 10^{-8} }{(0.02)^2}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= -9\times 10^9 \times\dfrac{4\times10^{-16}}{4\times 10^{-4}}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= -9\times 10^9 \times\dfrac{\cancel{4}\times10^{-16}}{\cancel{4}\times 10^{-4}}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^9 \times 10^{-16} \times 10^{4}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^9 \times 10^{-16+4} \\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^9 \times 10^{-12} \\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^{9-12}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^{-3}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf \underline{Force_{(air)} = -9\times 10^{-3}\:N}\\ [/tex]

Answer:

B

Explanation:

Answer:

i think it's either B or C

Explanation:

This question involves the concept of artificial gravity.

The effective gravitational strength at outer rims is "0.9 g".

The effective gravitational strength at the outer rims can be given by the following formula:

[tex]v=\frac{1}{2\pi}\sqrt{\frac{a_c}{r}}\\\\a_c=4\pi^2v^2r[/tex]

where,

Therefore,

[tex]a_c = 4\pi^2(0.0167\ rev/s)^2(804.672\ m)\\a_c =8.82\ m/s^2\\\\In\ terms\ of\ g:\\\\a_c=(8.82\ m/s^2)(\frac{g}{9.81\ m/s^2})\\\\a_c = 0.9g[/tex]

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Explanation:

The mechanical energy can be expressed as kinetic and potential energy, given by the equation;

ME=KE+PE

but since the car isn't elevated off the ground nor is it subjected to the restoring force of a spring, we can then say PE=0

ME=KE

The equation of KE=0.5mv²

ME=0.5mv²

32 000=0.5(1600)v²

[tex]v {}^{2} = \frac{32 \: 000}{1600 \times 0.5} [/tex]

[tex]v {}^{2} = \frac{32 \: 000}{800} [/tex]

[tex] {v}^{2} = 40[/tex]

[tex]v = \sqrt{40} = 6.324[/tex]

v=6.324 m/s :)

Given parameters:

Volume of metal block = 0.035mL

Mass of block  = 765mg

Unknown:

Volume of metal block = ?

Solution:

Density is the mass per unit volume of a substance.

  Density  = [tex]\frac{mass}{volume}[/tex]

Mass is the amount of matter in a substance

Volume is space occupied by a substance

     Mass of the block in g;

                         765mg =    765 x 10⁻³ g

                                     = 0.765g

 Density = [tex]\frac{0.765}{0.035}[/tex]   = 21.86g/mL

The density of the metal block is 21.86g/mL

Answer:

neutrons protons electrons

Explanation:

after the Big Bang, the universe was filled with neutrons, protons, electrons, anti-electrons, photons and neutrinos.

Answer: When there is no change in chemical composition of a substance then it is known as physical change. When we say that mass is conserved during a physical change then it means that total mass of the substance or object will remain the same from beginning till the end

Answer:

Sample Response: When a physical change occurs, the mass of the substance is conserved. This means that the total mass of the substance remains the same from beginning to end. The physical properties of the substance, such as size and shape, may change, but the amount of matter in the substance does not change.

Explanation:

Answer:

Explanation:

Writing out the Newton's Law pf Cooling:

dT/dt = -k * (T - A),

where T is the temperature of the coffee, A is the room temperature, and k is a positive constant.

If the coffee cools from 100°C to 90°C in 1 minute at a room temperature of 25°C,

T = 100

A = 25

dT = 100 - 90 = 10

dt = 1

Putting the figures into the equation:

10/1 = -k * (100 - 25)

k = -10/75°C

After 4 minutes, dT/4 = 10/75 (100 - 25) = 10

dT = 40

Temperature after 4 minutes = 100 - 40 = 60°C

The temperature of a cup of coffee varies according to Newton's Law of Cooling, the temperature of the coffee after 4 minutes is approximately 67°C.

To tackle this problem, we can apply Newton's Law of Cooling's differential equation and solve it using variable separation.

dT/dt = -k(T - A)

At t = 0 (initial condition): T = 100°C

At t = 1 minute: T = 90°C

dT/dt = -k(T - A)

At t = 0: dT/dt = -k(100 - 25)

So,

-10 = -k(75)

k = 10/75

Separating variables and integrating, we have:

1/(T - A) dT = -k dt

∫(1/(T - A)) dT = ∫(-k) dt

ln|T - A| = -kt + C

ln|100 - 25| = 0 + C

ln|75| = C

So, the equation will be:

ln|T - A| = -kt + ln|75|

ln|(T - 25)/(75)| = -kt

Now,

ln|((T - 25)/(75))| = -(10/75)(4)

|((T - 25)/(75))| = [tex]e^{(-40/75)[/tex]

T - 25 = ± 75 *  [tex]e^{(-40/75)[/tex]

T = 25 ± 75 *  [tex]e^{(-40/75)[/tex]

T ≈ 25 ± 42.42

Therefore, the temperature of the coffee after 4 minutes is approximately:

T ≈ 25 + 42.42 = 67.42°C

Thus, the temperature of the coffee after 4 minutes is approximately 67°C.

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Answer:

D.

Explanation:

Budgeting time, avoiding stress, and prioritizing.

The change in the internal energy of the system is 110 kJ.

Internal energy is defined as the energy associated with the random, disorder motions of molecules.

calculate the change in internal energy, we apply the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The change in the internal energy of the system is 110 kJ.

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Answer:

110.0kJ

Explanation:

The following solution may contain one or more values that are different from the problem provided to you, however, the steps to solve the problem are the same.

.The internal energy (E) of a system can change as heat (q) flows into or out of the system, or work (w) is done on or by the system. The following equation represents the relationship.

ΔE=q+w

In this question, heat is absorbed by the system, so it has a positive sign. Work is done by the system, so it has a negative sign.

ΔE=(155.0 kJ)+(−45.0 kJ)=110.0 kJ

Answer:

ratio

Explanation:

Apex Verified

For a bumper car A (296 kg) moving +3.74 m/s, and a bumper car B (222 kg) moving +1.85 m/s, the velocity of car A after the collision is mathematically given as

V1=4.977m/s

Generally, the equation for the Velocity of car A  is mathematically given as

[tex]V1=\frac{m1-m2v1}{m1+m2}v1 +\frac{2m_2}{m1+m2}v2[/tex]

Therefore

[tex]V1=\frac{296-222}{296+222}*23.74+\frac{2*222}{296+222}*1.85[/tex]

V1=4.977m/s

In conclusion, The velocity of car A after the collision

V1=4.977m/s

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Answer:3.74

Explanation:

it was given same goes for bumper car b

Open star clusters tend to orbit within the disk. Globular star clusters contain hundreds of thousands of stars, and some – like Omega Centauri, shown above – contain millions of stars. Open star clusters tend to contain only hundreds of stars.

International system of measurements in helpful because all scientists can use them

International System of measurement abbreviated SI is the modern most widely accepted system of unit of measurement

Answer:

19.5

Explanation:

16,17,18,18,21,24,24,29

(fourth (18) and fifth(21)) ÷2=

(18+21)÷2=

39÷2=

19.5 is median

Answer:

use math.way

Explanation:

i solved it.

Explanation:

Crossing over is the swapping of genetic material that occurs in the germ line. During the formation of egg and sperm cells, also known as meiosis, paired chromosomes from each parent align so that similar DNA sequences from the paired chromosomes cross over one another.

Answer:

Explanation:

After cross-over, the chromosomes are randomly shuffled to the daughter cells as the cell divides. This process results in in gametes that with unique combinations of chromosomes and is called independent assortment.

Answer:

The earth rotates from West to east

Explanation:

The deflection will be toward the backside for bad cost and closer to the pinnacle of the spread page for the high-quality charge.

Charged particles are simply defined as particles with an electric charge on them. This may sometimes result in being an ion, as a molecule with excess or a reduced amount of electrons relative to protons.

Generally, the Magnetic area points internal the airplane so through fleming left hand rule is

F = q ( V x B). Ie

hence

qVB = qE

V= E/B then no deflection.

V > E/B then magnetic pressure is dominant over electric powered force.

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See the flash fictions are small nov.els with para.graphs where as ch*.t story is a storyline that just look like some c

c.h.*.t.s.

Both "text-talk novels" and "flash fiction" are forms of written literature, but they have distinct characteristics and purposes.

Text-Talk Novel:

A text-talk novel, also known as a "chat novel" or "text-message novel," is a narrative written in the style of text messages or chat conversations. These novels are typically composed of short, informal messages exchanged between characters, presented in a way that resembles conversations on messaging apps. Text-talk novels often use emojis, abbreviations, and informal language to create a sense of immediacy and relatability. They are designed to be read on mobile devices and appeal to readers who are used to communication through texting and social media platforms. Text-talk novels often cater to a younger audience and can cover various genres, from romance to mystery.

Flash Fiction:

Flash fiction, also known as "microfiction," "short-short stories," or "sudden fiction," refers to extremely short works of fiction characterized by their brevity. Flash fiction stories are typically no longer than 1,000 words, and often much shorter. Despite their limited length, flash fiction stories aim to convey a complete narrative, evoke emotions, and leave a lasting impact on the reader. Due to their concise nature, flash fiction stories often focus on a single idea, moment, or theme, and they require skillful crafting to create a meaningful story within a tight word count. Flash fiction can cover a wide range of genres and styles, and its brevity challenges writers to distill their storytelling abilities to essentials.

Hence, a "text-talk novel" is a novel written in the style of text messages or chat conversations, aiming to engage readers familiar with mobile communication. On the other hand, "flash fiction" refers to very short stories that convey complete narratives or ideas within a limited word count, challenging writers to create impactful stories in a condensed format.

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Answer:

2 m/s2

Explanation:

Newton's 2nd law:

F=ma

20 N= (10 kg)a

a= 2 m/s2

Answer:

a = 2.5 m/s^2

Explanation:

u = 0

v = 25

t = 10

(using first eq. of motion)

a = (v - u) /t

a = (25 - 0) /10

a = 25/10

a = 2.5 m/s^2

Answer:

perpendicular

Explanation:

The projectile motion of an object can be described by two independent vector components that are horizontal and vertical motion.

The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.

The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.

The projectile's motion is divided into two parts: horizontal and vertical motion.

Because perpendicular motion components are independent of one another, these two motion components may be treated individually.

Hence two independent vector components are horizontal and vertical motion.

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