A store has clearance items that have been marked down by 30% They are having a sale, advertising an additional 40% off clearance items. What percent of the original price do you end up paying?

Give your answer accurate to at least one decimal place.

The Distance from the point P(2, 1, 4) to the plane is approximately -0.9487.

The equation of a plane can be found using the normal vector and a point on the plane.

First, we can find the normal vector of the plane by finding the cross product of two vectors connecting the points on the plane.

The vector from point Q to R is (0, 2, 0) - (1, 0, 0) = (-1, 2, 0)

The vector from point Q to S is (0, 0, 3) - (1, 0, 0) = (-1, 0, 3)

The normal vector is the cross product of these two vectors:

n = cross(-1, 2, 0), (-1, 0, 3)) = (3, 3, -2)

Next, we can find the equation of the plane using the normal vector and a point on the plane, say Q(1, 0, 0):

ax + by + cz = d

3x + 3y - 2z = d

3x + 3y - 2z = 3(1) + 3(0) - 2(0) = 3

Finally, we can find the distance from the point P(2, 1, 4) to the plane by finding the perpendicular distance between the point and the plane. This can be done using the formula:

[tex]d = (Ax + By + Cz + D)/\sqrt{ {A^2 + B^2 + C^2}[/tex]

[tex]d = (3x + 3y - 2z + 3)/\sqrt{ (3^2 + 3^2 + (-2)^2)[/tex]

[tex]d = (3(2) + 3(1) - 2(4) + 3)/\sqrt{ (3^2 + 3^2 + (-2)^2)[/tex]

[tex]d = (-3)/\sqrt{(18)[/tex]

d = -3/3.162 = -0.9487

So the distance from the point P(2, 1, 4) to the plane is approximately -0.9487.

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Accumulated depreciation account is used to calculate an asset's net book value, which is the value of an asset carried on the balance sheet.

The accumulated depreciation account is a contra asset account on a company's balance sheet. It represents a credit balance. It appears as a reduction from the gross amount of fixed assets reported. Accumulated depreciation specifies the total amount of an asset's wear to date in the asset's useful life.

One of the uses of accumulated depreciation account is that is used to calculate an asset's net book value, which is the value of an asset carried on the balance sheet.

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The amount grace invested $3420 at 7% and the rest of her savings, $5580, at 9%.

Simple interest is a method of calculating the interest charge. Simple interest can be calculated as the product of principal amount, rate and time period.

Simple Interest = (Principal × Rate × Time) / 100

We are given that;

Amount grace invested= 9000 at 9%

Rate for rest of it= 9%

Annual income=741.6

Now,

Let's call the amount Grace invested at 7% "x".

Then the amount she invested at 9% would be "9000 - x", since she invested the rest at the higher rate.

We know that her annual income from the investments was $741.60.

The amount of money she made from the 7% investment would be 0.07x (7% expressed as a decimal multiplied by the amount invested), and the amount of money she made from the 9% investment would be 0.09(9000 - x) (9% expressed as a decimal multiplied by the amount invested).

So we can set up the equation:

0.07x + 0.09(9000 - x) = 741.60

Simplifying and solving for x:

0.07x + 810 - 0.09x = 741.60

-0.02x = -68.4

x = 3420

Therefore, by the given interest rate answer will be $5580, at 9%.

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This question is about to determine the conditional statement,  proposition and either that is true or false.

The explanation of each part in this question is given below:

a) The given proposition can be written as the conjunction of two conditional statements as follows:

If a = 2 (mod 8), then [tex](a^2 + 4a) = 4 (mod 8)[/tex].

If [tex](a^2 + 4a) = 4 (mod 8)[/tex], then a = 2 (mod 8).

b) To prove the first conditional statement, assume a = 2 (mod 8). Then, there exists an integer k such that a = 8k + 2. Substituting this value of a into [tex](a^2 + 4a)[/tex], we get:

[tex]a^2 + 4a = (8k + 2)^2 + 4(8k + 2) = 64k^2 + 36k + 8[/tex]

Reducing this expression modulo 8, we get:

a^2 + 4a ≡ 64k^2 + 36k + 8 ≡ 0 + 4k + 0 ≡ 4 (mod 8)

Therefore, we have shown that if a = 2 (mod 8), then (a^2 + 4a) = 4 (mod 8).

To prove the second conditional statement, assume (a^2 + 4a) = 4 (mod 8). Then, there exists an integer k such that (a^2 + 4a) = 8k + 4. Substituting this value of (a^2 + 4a) into the equation a^2 + 4a - 8k = 0, we can use the quadratic formula to solve for a:

a = (-4 ± √(16 + 32k))/2 = -2 ± √(4 + 8k)

Since a is an integer, it follows that √(4 + 8k) must be an integer as well. This implies that 4 + 8k is a perfect square. The only perfect squares that are congruent to 4 (mod 8) are those of the form 8m + 4 for some integer m. Therefore, we have:

4 + 8k = 8m + 4

k = m

Substituting k = m back into the expression for a, we get:

a = -2 + √(4 + 8k) = -2 + √(8m + 4) = -2 + 2√(2m + 1)

Since a is an integer, it follows that √(2m + 1) must be an integer as well. This implies that 2m + 1 is a perfect square. The only perfect squares that are congruent to 1 (mod 8) are those of the form 8n + 1 for some integer n. Therefore, we have:

2m + 1 = 8n + 1

m = 4n

Substituting m = 4n back into the expression for a, we get:

a = -2 + 2√(2m + 1) = -2 + 2√(8n + 1) = 2(√(2n + 1) - 1)

Therefore, we have shown that if (a^2 + 4a) = 4 (mod 8), then a = 2 (mod 8).

Since both conditional statements have been proven, the given proposition is true.

(c) The given proposition is true, as shown in the proofs of the two conditional statements in part (b).

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The integral that would give the volume V generated by rotating the region bounded by the given curves about the y-axis is V = ∫[from x=0 to x=6] π[(13 - x²/3)² - 13²]dx

To find the volume of a rotational solid, we can use the method of disks/washers, which involves slicing the solid into thin disks or washers, calculating the volume of each slice, and then adding them up using integration.

To use the method of disks/washers, we need to first determine the radius of each disk or washer. Since we're rotating the region around a horizontal line, the radius will be the distance from each point on the curve to the line of rotation, which in this case is y = 16. To find this distance, we subtract 16 from the y-coordinate of each point on the curve.

The outer radius is the distance from the point on the curve y = x^2/3 + 3 to the line y = 16, which is

=>  r = 16 - (x²/3 + 3) = 13 - x²/3.

The inner radius is the distance from the point on the curve y = 3 to the line y = 16, which is

=> r = 16 - 3 = 13.

Next, we need to express the volume of each disk or washer in terms of these radii.  This gives us the following formula for the volume of each slice:

dV = π[(13 - x²/3)² - 13²]dx

Finally, we can find the total volume of the solid by integrating over the range of x values that define the region we're rotating:

V = ∫[from x=0 to x=6] π[(13 - x²/3)² - 13²]dx

Evaluating this integral will give us the volume of the solid created by rotating the region between y = x²/3 + 3  and y = 3 about the line y = 16.

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Complete Question:

Set up the integral that uses the method of disks/washers to find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified lines. y = x²/3 + 3 , y = 3 , x = 6 About the line y = 16.

Susan could save 10.4 minutes getting to class each morning if she were to ride the bike.

As per the data given:

The distance is given between the school and the apartment = 1.3 miles

Susan's walking speed = 3 miles/hr

Now we know that speed = distance ÷ time

Putting values in the above formulae, we get the time for walking situation

3 miles/hr = 1.3 ÷ time

Time = 1.3 ÷ 3 miles

Time = (13 ÷ 30 )hr

= (13 ÷ 30) × 60 minutes

= 13 × 2

= 26 minutes

The time taken when she is walking is 26 minutes.

Here we have to determine how many minutes could Susan save getting to class each morning if she were to ride the bike.

Now if she uses a bike, the speed is 5 miles/hr

Again applying same formulae speed = distance ÷ time

5 miles/hr= 1.3 ÷ time

Time= 1.3 ÷  5 miles

= (13 ÷ 50)hr

= (13 ÷ 50) × 60 minutes

= 15.6 minutes

Time taken by bike is 15.6 minutes

Total time saved = time taken when walking - time taken using the bike

= 26 - 15.6

= 10.4 minutes

Hence, Susan could save 10.4 minutes if she uses a bike.

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Answer:

Step-by-step explanation:

14.0

Answer:

[tex]x=11.5[/tex]

The third option listed

Step-by-step explanation:

We can use the sine function to evaluate [tex]x[/tex].

The definition of the sine function is

[tex]\sin \theta=\frac{O}{H}[/tex]

Note

[tex]\theta[/tex] is the angle

[tex]O[/tex] is the side opposite to the angle

[tex]H[/tex] is the hypotenuse

In this example we are given the hypotenuse and the angle.

Knowing these 2 values we can evaluate the opposite side ([tex]x[/tex]).

Lets solve for [tex]O[/tex].

[tex]\sin \theta=\frac{O}{H}[/tex]

Multiplying both sides by [tex]H[/tex] lets us isolate [tex]O[/tex] ([tex]x[/tex]).

[tex]O=H*\sin \theta[/tex]

Numerical Evaluation

We are given

[tex]\theta=35\textdegree\\H=20[/tex]

Inserting those values into our equation for [tex]O[/tex] ([tex]x[/tex]) yields

[tex]O=20*\sin 35[/tex]

[tex]O=11.4715287[/tex]

Rounding to the nearest tenth gives us

[tex]O=11.5[/tex]

[tex]x=11.5[/tex]

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Answer:

$381

Step-by-step explanation:

9% = 1 year

27% = 3 years

$300 = 100%

After 3 years, we have

100% + 27% = 127%

127% = 1.27

300 tines 1.27 = $381

So, after 3 years has $381

The statements about the given situation that are true about domain and range  are;

B: The maximum value in the range is $320.

D: The minimum value in the domain is 0.

The domain is defined by b, the number of bracelets sold.

The minimum value in the domain is 0, which represents no bracelets sold.

The maximum value in the domain is 260, which represents the largest number of bracelets the group can make, and the largest number they could sell.

The range is defined by f(b), the amount of profit on the bracelets.

To find the maximum value in the range, we find f(260), the profit on selling the maximum in the domain.

Substitute 260 for b in f(b) = 2b – 200 to get:

f(260) = 2(260) – 200

f(260) = 320

The maximum value in the range is $320.

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Complete question is;

The high school jazz band is selling homemade leather bracelets at a local craft fair to raise money for a trip. The group has a $200 budget to spend on supplies, which is enough to make 260 bracelets. The group is charging $2 per bracelet at the craft fair.

Which statements about this situation are true?

Select all the correct answers.

The maximum value in the range is $200.

The maximum value in the range is $320.

The maximum value in the domain is 200.

The minimum value in the domain is 0.

The three equations that can be used to solve for y, the length of the room, are:

1. y(y + 5) = 750

2. y^2 – 5y = 750

3. (y + 25)(y – 30) = 0

Explanation:

Let's assume that the length of the room is y and the width of the room is y - 5.

We know that the area of the room is the product of its length and width, so we can write an equation:

y(y - 5) = 750

Simplifying this equation, we get:

y^2 - 5y - 750 = 0

Now we can solve this quadratic equation using the quadratic formula or factoring method. By factoring, we can get equation 3. By using the quadratic formula, we can get equation 2. Equation 1 is just another form of equation 2. Therefore, options 1, 2, and 3 can be used to solve for y. Option 4 is not a valid equation as it doesn't represent the area of the room.

Invertible matrices P = [1 -2; 0 1] and Q = [1 0; 2 1] such that

A = PQ =  [1 2; 2 -3]  is non-invertible.

To find invertible matrices such that a given matrix is non-invertible, we can use the fact that if A is non-invertible, then the system of linear equations Ax = 0 has a non-trivial solution. This means that there exists a non-zero vector x such that Ax = 0.

Let's start with a non-invertible matrix A, for example:

A = [1 2; 2 4]

The determinant of A is 0, which means that A is non-invertible.

To find a non-zero vector x such that Ax = 0,

We can solve the system of linear equations:

x + 2y = 0

2x + 4y = 0

This system is equivalent to the single equation:

x + 2y = 0

If we choose y = 1, then x = -2, and we get the non-zero vector:

x = [-2; 1]

Now we can use x to construct invertible matrices P and Q such that

PQ = A, as follows:

P = [1 -2; 0 1]

Q = [1 0; 2 1]

The inverse of P is:

P^-1 = [1 2; 0 1]

And the inverse of Q is:

Q^-1 = [1 0; -2 1]

We can verify that P and Q are invertible and that PQ = A:

PQ = [1 -2; 0 1][1 0; 2 1]

PQ = [1 -2; 2 -4 + 1]

PQ = [1 2; 2 -3] = A

Therefore, we have found invertible matrices P and Q such that A = PQ is non-invertible.

Note:- that neither P nor Q is a diagonal matrix, and they are not scalar multiples of each other.

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The complete question may be:

Find non-invertible matrices A, B such that A+B is invertible. Choose

A, B, so that (1) neither is a diagonal matrix and (2) A, B are not scalar multiples of each other.

The expression representing the perimeter of the rectangle is given as follows:

P = 6x + 4.

The perimeter of the rectangle when x = 7 is given as follows:

46 feet.

The perimeter of a rectangle of length l and width w is given by the expression presented as follows:

P = 2(l + w).

The dimensions for this problem are given as follows:

Hence the expression for the perimeter of the rectangle is given as follows:

P = 2(x + 4 + 2x - 2)

P = 2(3x + 2)

P = 6x + 4.

When x = 7, the perimeter of the rectangle is given as follows:

P = 6(7) + 4

P = 46 feet.

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The limit of the difference quotient must not exist at any location z0 in the complex plane in order to demonstrate that f(z) = z is nowhere differentiable.

For f(z), the difference ratio is as follows:

[f(z Plus h) - f(z)] / h = [(z + h) - z] / h = h / h = 1

As h gets closer to 0, we take the maximum and obtain:

lim h0 [z + h - z] / = lim h 0 h / h = 1

This limit is constant at 1 and is unaffected by the number of z. The limit of the difference quotient must not exist at any location z0 in the complex plane in order to demonstrate that f(z) = z is nowhere differentiable. As a result, f(z) = z is never differentiable and the limit of the difference quotient is not present at any position z0 in the complex plane.

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Leah's argument is that the rounded up figures for Tuesday sales are greater than the sales for Monday. She supports it by summing up the sales figures.

Leah's reasoning is wrong because she rounded up $ 233 to $ 300 instead of to $ 200.

Leah's reasoning therefore does not make sense.

Leah attempts to round the Tuesday sales figures to the nearest 100. In doing so, she rounded $ 233 to $ 300 instead of $ 200 which was the closest.

If she had done so, the result would be :

= 200 + 400

= $ 600

This would then show that Monday's figures were higher than Tuesday.

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The value of x is 9.

The value of y is 5.

An equation contains one or more terms with variables connected by an equal sign.

Example:

2x + 4y = 9 is an equation.

2x = 8 is an equation.

We have,

4x - 2y = 26

This can be written as,

4x - 26 = 2y ______(1)

5x – 2y = 35

This can be written as,

5x - 35 = 2y _______(2)

From (1) and (2),

4x - 26 = 5x - 35

35 - 26 = 5x - 4x

9 = x

x = 9

And,

Substituting x = 9 in (1),

4x - 26 = 2y

4 x 9 - 26 = 2y

36 - 26 = 2y

2y = 10

y = 5

Thus,

The solution is (9, 5).

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Answer:

24.5in

Step-by-step explanation:

7 days in a week. 7 weeks. 7 x 7=49

49 x 0.5 + 24.5in

Answer:

8

Step-by-step explanation:

plug in the values of x and y into the equation

4(4) / (2)

16 / 2 = 8

Out of a population of 100,000, the number of people who read at least two newspapers is = 33,000.

Let's approach this problem using the inclusion-exclusion principle.

First, we can add up the proportions of people who read each paper to get:

P(I) + P(II) + P(III) = 10% + 30% + 5% = 45%

However, this includes the people who read two or more papers multiple times, so we need to subtract those out. We can calculate these as follows:

P(I&II) + P(I&III) + P(II&III) = 8% + 2% + 4% = 14%

2P(I&II&III) = 2%

Using the inclusion-exclusion principle, we can now find the proportion of people who read at least two papers:

P(at least 2 papers) = P(I) + P(II) + P(III) - (P(I&II) + P(I&III) + P(II&III)) + 2P(I&II&III)

Plugging in the values, we get:

P(at least 2 papers) = 45% - 14% + 2% = 33%

So, the number of people who read at least two newspapers is:

0.33 * 100,000 = 33,000

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Complete question is:

A certain town of population size 100,000 has three newspapers: I , II and III the proportions of townspeople that read these papers are:  

I= 10 percent

II= 30% percent

II=5 percent

I&II=8 percent

I&III=2 percent

II&III=4 percent

I&II&III=1 percent

How many people read at least two newspapers?

Box plot is a chart that shows data from a five-number summary including one of the measures of central tendency.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

A box plot, also known as a box and whisker plot, is a graphical representation of a set of numerical data that displays its distribution, central tendency, and variability.

The box plot consists of a rectangular box with whiskers that extend from the edges of the box.

The box represents the middle 50% of the data, and the vertical line inside the box represents the median (50th percentile) of the data.

The whiskers extend to the smallest and largest observations that are within 1.5 times the interquartile range (IQR) of the lower and upper quartiles, respectively.

Any observations that fall outside the whiskers are considered outliers and are plotted as individual points.

Box plots are useful for comparing the distribution of data between different groups of data.

Hence, Boxplot is a graphical representation of a set of numerical data that displays its distribution, central tendency, and variability.

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Answer:

False, No.

Step-by-step explanation:

No, it is not possible to create a regular tessellation with a regular heptagon. A regular tessellation, also known as a tiling, is a repeating pattern of identical regular polygonal shapes that cover a plane without any gaps or overlaps. The only regular polygonal shapes that can be used to form a regular tessellation are the equilateral triangle, square, and hexagon. These shapes have interior angles that are multiples of 60 degrees, which allows them to fit together seamlessly to form a repeating pattern. The interior angle of a regular heptagon is roughly 128.5714 degrees, which does not divide evenly into 360 degrees, so it cannot be used to form a regular tessellation.

Answer:

The United States form of government is a...

O Republic

can I please get the five points:)

Answer:

Republic

Step-by-step explanation:

Option B

I hope this helps :) if not let me know

The angle measure of x, y and z are 104, 76 and 104 degrees respectively

The given. figure is a parallelogram with 4 interior angles. In a parallelogram, the sum of its adjacent angle is 180 degrees and its opposite angles are equal.

<A = <C

x = 104 degrees

For the measure of y:

x + y = 180

104 + y = 180

y = 180 - 104

y = 76 degrees

Since the sum of angles on a straight line is 180 degrees, hence;

y + z = 180

76 + z = 180

z = 104 degrees

Hence the measure of x, y and z are 104, 76 and 104 degrees respectively

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Answer:

We can use the formula speed = distance / time to calculate the speed of the plane.

The total distance traveled by the plane is 3,000 + 600 = 3,600 miles.

The total time taken by the plane is 2 hours 30 minutes, which is equivalent to 2.5 hours.

Therefore, the speed of the plane is:

speed = distance / time

     = 3,600 / 2.5

     = 1,440 miles per hour

So the answer is (A) 1440mph

The required scaled copy of polygon B using a scale factor of 0.75 as shown.

Scale image is defined as a ratio that represents the relationship between the shape and size of a figure and the corresponding dimensions of the actual figure or object.

The polygon B is given as shown, which dimensions are below:

Length of polygon = 8 units

Height of polygon = 10 units

Here, the scale factor = 0.75

So, the dimensions of the scaled copy of polygon B are below:

Length of polygon B' = 8 × 0.75 = 6 units

Height of polygon B' = 10 × 0.75 = 7.5 units

Thus, the scaled copy of polygon B using a scale factor of 0.75 as shown.

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The distance between the ships is increasing at a rate of approximately 91.6 km/h at 4:00 PM.

From the question, we have the following parameters that can be used in our computation:

Distance, D = 150 km

Rates = 35 km/h and 30 km/h

Let t be the time elapsed from noon to 4:00 PM

So, we have

t = 4

The distance between the ships to their distances is represented as

d^2 = (D + rate 1 * t)^2 + (rate 2 * t)^2

So, we have

d^2 = (150 + 35t)^2 + (30t)^2

d^2 = (150)^2 + 10500t + 1225t^2 + 900t^2

Differentiate with respect to time (t)

2D d' = 10500 + 2450t + 1800t

So, we have

D d' = 5250 + 1225t + 900t

Substitute 4 for t

D d' = 13750

So, we have

d' = 13750/D

This gives

d' = 13750/150

d' = 91.6

So the distance between the ships is increasing at a rate of approximately 91.6 km/h at 4:00 PM.

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The values missing sides of the figures are calculated below.

The scale factor is the size by which the shape is enlarged or reduced. It is used to increase the size of shapes like circles, triangles, squares, rectangles, etc.

NUMBER 7

Scale factor is the ratio of two corresponding sides of similar figures. Since the scale factor from A to B = 3:5. We have:

A : B = 3:5

(x+11) : 30 = 3 : 5

(x+11) /30 = 3 / 5

x + 11 = (30*3)/5

x + 11 = 90/5

x + 11 = 18

x = 18 - 11

x = 7

NUMBER 8

(2x-12) : 12 = 1:3

(2x-12) /12 = 1/3

2x-12 = 12/3

2x-12 = 4

2x = 4 + 12

2x = 14

x = 14/2

x = 7

NUMBER 9

AB : FG = BC:GH

104/39 = 112/x

x = 42

NUMBER 9

TK:KL = KU:KM

14/91 = 12/x

x = 78

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Answer:8

Step-by-step explanation:

15/15=1

112/15=7.466...

you can't buy 7.466... cups, so you round up to 8.

hope I'm right ;)

Answer:

  y = -5

Step-by-step explanation:

You want to solve for y in 2y -3(2y -3) +2 = 31.

Parentheses can be eliminated using the distributive property.

  2y -6y +9 +2 = 31

Like terms can be combined.

  -4y +11 = 31

We can separate the constant and variable terms by subtracting 11 from both sides.

  -4y = 20

The value of y is now found by dividing by -4.

  y = 20/(-4) = -5

  y = -5

Answer:m=2/5

Step-by-step explanation:

m[tex]\neq[/tex]0

5/6=1/3m

15m=6

m=2/5, m[tex]\neq[/tex]0