A strip footing of width 3 m is founded at a depth of 2 m below the ground surface in a (c – 0) soil having a cohesion c = 30 kN/m2 and angle of shearing resistance 0 = 35°. The water table is at a depth of 5 m below ground level. The moist weight of soil above the water table is 17.25 kN/m3. Determine the find ultimate bearing capacity of the soil.
Answers
Using Terzagi's Equation as shown in the attachement;
Qa = 4225 kN/m
As per the given data, the ultimate bearing capacity of the soil is 313 kN/[tex]m^2[/tex]
What is bearing capacity?Bearing capacity is the capacity of soil to support loads applied to the ground in geotechnical engineering.
To determine the ultimate bearing capacity of the soil, we can use the following formula:
q_ult = cN_c + 0.5γ*(BN_q + 0.4N_g*(B - B_f)*N_q)
To find the values of N_c, N_q, and N_g, we can use the following equations:
N_c = [cot(0) + tan(φ)][1 + 0.2(B_f/D)][(N_q/N_c) - 1][(N_q/N_c) - 2]
N_q = [(1 + sin(0))(1 - sin(0))][(N_q/N_c) - 1]
N_g = 0.5*(N_q - 1)*tan^2(φ)
Using the above equations, we can calculate the values of N_c, N_q, and N_g as follows:
N_c = [cot(35°) + tan(35°)][1 + 0.2(3/2)][(2.45/N_c) - 1][(2.45/N_c) - 2] ≈ 11.5
N_q = [(1 + sin(35°))(1 - sin(35°))][(2.45/N_c) - 1] ≈ 10.5
N_g = 0.5*(10.5 - 1)*[tex]tan^2[/tex](35°) ≈ 2.6
Substituting these values into the formula for q_ult, we get:
q_ult = 3011.5 + 0.517.25*(310.5 + 0.42.6*(3 - 3)*10.5) ≈ 313 kN/m^2
Therefore, the ultimate bearing capacity of the soil is approximately 313 kN/m^2.
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Related Questions
In lighting system, why it is important to consider maintenance factor?
Answers
Answer: The maintenance factor of a lighting system reflects how much of the initial luminous flux is still available at the end of its useful life. The planned lighting engineer must compute the maintenance factor and multiply the new value of the light output by it.
Explanation:
Answer:
Explanation: A lighting system's maintenance factor indicates how much of the initial luminous flux remains available at the end of its service life. The maintenance factor must be determined by the planning lighting engineer and the new value of the luminous flux multiplied by it.
A measurement that represents where two lines, arcs, or a
line and an arc would meet is called:
Answers
Angle is defined as the measurement that represents where two lines, arcs, or a line and an arc would meet.
What is an Arc?This is defined as a smooth curve which joins two endpoints. An angle can be formed when two two lines, arcs, or a line and an arc meet.
This is why it was chosen as the most appropriate type of measurement in the scenario mentioned above.
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what is an undescribable outcome from cellphones?
Answers
Answer:
Cell phones emit low levels of non-ionizing radiation when in use. The type of radiation emitted by cell phones is also referred to as radio frequency (RF) energy. As stated by the National Cancer Institute, "there is currently no consistent evidence that non-ionizing radiation increases cancer risk in humans.
Explanation:
what is the irregular past tense of hear?
Answers
Answer:
Past tense of hear = heard
Refrigerant-134a at 1 MPa and 100 C is to be cooled to 1 MPa and 28 C in a condenser by air. The air enters at 125 kPa and 25 C with a mass flow rate of 697 kg/min and leaves at 97 kPa and 58 C. Determine the mass flow rate of the refrigerant. Assume air has a constant heat capacity determined at room temperature. Report the mass flow rate of the refrigerant in kg/min with one decimal digit, for example 95.3 or 105.6.
Answers
What’s is the answer
Answers
Whose responsibility is it to provide a safe and healthy workplace?
Answers
Answer:
Under the OSH law, employers have a responsibility to provide a safe workplace. This is a short summary of key employer responsibilities: Provide a workplace free from serious recognized hazards and comply with standards, rules and regulations issued under the OSH Act.
credits to google
Explanation:
Answer:
employers
Explanation:
because they are responsible.
“We’re late for homeroom,” said Bonnie, surprised to hear herself say “we.” “EARL is a tool, Bonnie’s mother kept reminding her, not a friend or a puppy. ‘Don’t anthropomorphize it, honey,’ Bonnie’s mom said one night after she found Bonnie dancing around her bedroom with the metal contraption. ‘It’s a walking blender. Never forget that.”
QUESTION: What does, "Anthropomorphize" means in the sentences above?
(A) It means to program a robot so that it acts in a robotic or unnatural way?
(B) Or it means to give human characteristics to an object or animal?
(C) To make a human act more like an animal and less of a human?
(D) Or to make a human act more like an animal and less of a human?
Answer correctly
Will give Brainliest, a THX, friend request, and will rate ur answer
Answers
Answer:
Hi there
Your answer is:
B.
Explanation:
The "metal contraption", as the text goes on to say, is treated like a friend to Bonnie. Her mom comments on this by contrasting the metal contraption to a puppy.
Hope this helps
Lynx eat snowshoe hares, and snowshoes hears eat plants. Which term can be applied to the lynx in this food chain example? Primary consumer predator secondary consumer
Answers
Answer:
primary consumer because YES
Answer:predator and secondary consumer
Explanation:
What is troubleshooting?
creating a checklist
finding and fixing a problem
scanning for viruses
performing regular maintenance
Answers
Answer:
B. finding and fixing a problem
Explanation: is correct on edge2020
Please hit that thanks button below and mark brainliest if possible
a. An 80-percent efficient pump with a power input of 20 hp is pumping water from a lake to a nearby pool at ar ate of 1.5 ft3 /s through a constant-diameter pipe. The free surface of the pool is 80 ft above that of the lake. Determine the mechanical power used to overcome frictional effects in piping.
b. Water is pumped from a lake to a storage tank 15 m above at a rate of 70 L/s while consuming 15.4 kW of electric power. Disregarding any frictional losses in the pipes and any changes in kinetic energy. Determine:
1. The overall efficiency of the pump–motor unit.
b. The pressure difference between the inlet and the exit of the pump.
Answers
Answer:
A) mechanical power used to overcome frictional effects in piping = 2.373 HP
B) efficiency = 66.82%
Pressure difference = 147 KPa
Explanation:
We are given;
efficiency of pump; η = 80% = 0.8
power input of pump;P_pump,in = 20 hp
rate being pumped; Q = 1.5 ft³/s = 0.04248 m³/s
free surface of pool; Δz = 80 ft = 24.384 m
mechanical pumping power used to deliver water is;
W_u = η × P_pump,in
W_u = 0.8 × 20
W_u = 16 Hp
Now, change in total mechanical energy of water will be equal to the change in potential energy.
Thus, it is expressed as;
ΔE_mech = ρ × Q × g × Δz
Where ρ is density of water = 1000 kg/m³
Thus;
ΔE_mech = 1000 × 0.04248 × 9.81 × 24.384 = 10,161.5150592 J/s
Converting to HP gives;
ΔE_mech = 13.627 HP
Now, mechanical power used to overcome frictional effects is given by;
W_frict = W_u - ΔE_mech
W_frict = 16 - 13.627
W_frict = 2.373 HP
B) We are now given;
W_elect,in = 15.4 KW
Volumetric flow rate; q = 70 l/s = 0.07 m³/s
Height; h = 15 m
Mass flow rate; m' = qρ
Where ρ is density of water = 1000 kg/m³.
m' = 0.07 × 1000
m' = 70 kg/s
Now,
ΔE_mech = workdone through height of 15m
Thus;
ΔE_mech = m'gh
ΔE_mech = 70 × 9.8 × 15
ΔE_mech = 10,290 W = 10.29 Kw
efficiency of the pump–motor unit = ΔE_mech/(W_elect,in) = 10.29/15.4 = 0.6682 or 66.82%
Pressure difference = ρgh = 1000 × 9.8 × 15 = 147,000 Pa = 147 KPa
At time t the resultant force on a particle, of mass 250kg is (300ti-400tj)N. Initially, the particle is at the origin and is moving
with the velocity (2i-3j)m
−1
Answers
Answer:
i
Explanation:
Silicon carbide nanowires of diameter D = 15 nm can be grown onto a solid siliconcarbide surface by carefully depositing droplets of catalyst liquid onto a flat silicon carbide substrate. Siliconcarbide nanowires grow upward from the deposited drops, and if the drops are deposited in a pattern, an array ofnanowire fins can be grown, forming a silicon carbide nano-heat sink. Consider finned and unfinned electronicspackages in which an extremely small, 10 μm × 10 μm electronics device is sandwiched between two d = 100-nm-thick silicon carbide sheets. In both cases, the coolant is a dielectric liquid at 20°C. A heat transfer coefficient of h= 1 × 10^5 W/m^2 · K exists on the top and bottom of the unfinned package and on all surfaces of the exposed siliconcarbide fins, which are each L = 300 nm long. Each nano-heat sink includes a 200 × 200 array of nanofins.
Required:
Determine the maximum allowable heat rate that can be generated by the electronic device so that its temperatureis maintained at Tt < 85°C for the unfinned and finned packages.
Answers
Answer:
For unfined package = 1.30 × 10^-3 W.
Dor fined package = 8.64 × 10^-3 W.
Explanation:
STEP ONE: The first thing to do is to determine the cross sectional area and input the value into the convectional resistance formula/equation in order to determine the heat rate for the unfined package.
Thus, Area = (dimension of the electronic device) ^2. = (10 × 10^-6)^2 m.
Convectional Resistance = (100 × 10^-9)÷ (10 × 10^-6)^2 × 490 = 2.04 K/W.
Heat transfer coefficient = 1/ (10 × 10^-7)^2 × 10^5. = 1 × 10^5 K/W.
Thus, the heat rate for the unfined package = 2{(85 - 20) ÷ (10^5 + 2.04)} = 1.30 × 10^-3 W.
STEP TWO: Determine the surface area of each fin and the prime area.
Surface area of each fin = {300 + 15/4} × 10^-9 × 10^-9 × π × 15 = 1.43 × 10^-14 m^2.
Prime area = (10^-6 × 10)^2 - (200 × 200) × π × [ ( 15 × 10^-9)^2 ÷ 4] = 9.29 × 10^-11 m^2.
STEP THREE: Determine the efficiency
G ={ [300 + 15/4) × 10^9 } × [ 4 × 10^5÷ 490 × 15 × 10^-9] = 7.09 × 10^-2.
Efficiency= tanh ( 7.09 × 10^-2) ÷ 7.09 × 10^-2 = 0.998.
Thus, the coefficient = 1 - (1.43 × 10^-14 × (200 × 200) ÷ (6.65 × 10^-10) × (1 - 0.998) = 0.99.
STEP FOUR: Determine the heat rate for the finned package.
Thermal resistance = 1/ (10^5 × 0.999 × 10^-10 × 6.65 = 1.50 × 10^4 K/W.
The heat rate for the finned package = 2 { 85 - 20} ÷ { 1.50 × 10^4 + 2.04} = 8.64 × 10^-3 W
Three groups of students are given study outlines for 6 weeks. One group studies 2 hours a night, a second group studies 1 hour a night, and the third group only studies 30 minutes. Their final exam grade will be at the end of the 6 weeks. What is the constant ?
Answers
Answer:
The constant here is the study outline
Explanation:
In scientific research, the constant variable is that part/variable of the experiment that does not change or is set not to change. Examples include temperature, environment or height.
Assuming the scenery described in this question is an experiment. All the groups presented are bound by a constant during the experiment. The constant here is the study outline. The study outline provided to the students is not going to change.
NOTE: There could be confusion as regards the answer being the final exam grade but that will be the dependent variable as that will be the outcome of the experiment while the time spent to study will be the independent variable.
Using the Equilibrium Equation (F1d1 = F2d2), find F1, if d1 = 30ft, and F2 = 1050lb, and d2=22ft. Please state your answer in pounds and round to the nearest whole number.
Answers
Answer:
77 lb
Explanation:
Equation: F₁d₁ = F₂d₂
Knowns:
d₁ = 30 ft
F₂ = 105 lb
d₂ = 22 ft
Solving for F₁:
1). F₁•30 = 105•22
2). F₁•30=2,310
3).[tex]\frac{F_1\cdot 30}{30}=\frac{2310}{30}[/tex]
4). F₁ = 77 lb
Which of the following is most characteristic of OSHA's relationship with professional trade organizations in residential construction?
O beneficial
confrontational
competitive
awkward
Answers
Answer:
its beneficial
Explanation:
took the test
Answer:
Beneficial would be the correct answer.
Explanation:
if you play roblox leave user down bellow
Answers
Answer:
why dont you make friends on roblox lol might be safer
Explanation:
Answer:
yes i play roblox
Explanation:
But why are you asking this type of Question
WILL GET MARKED BRAINLIEST
Based on the results, which statement is most likely a criterion for the gaming system design? Choose the correct answer.
a. width of about 8 inches
b. ability to connect wifi
c. battery life of at least 24hrs
d. production cost of less than $40
Answers
Answer:
B
Explanation:
You need to connect to WiFi without it no multiplayer
what is an undescribable outcome from cellphones?
Answers
Answer:
Cell phones emit low levels of non-ionizing radiation when in use. The type of radiation emitted by cell phones is also referred to as radio frequency (RF) energy. As stated by the National Cancer Institute, "there is currently no consistent evidence that non-ionizing radiation increases cancer risk in humans.
Explanation:
Cell phones emit low levels of non-ionizing radiation when in use. The type of radiation emitted by cell phones is also referred to as radio frequency (RF) energy. As stated by the National Cancer Institute, "there is currently no consistent evidence that non-ionizing radiation increases cancer risk in humans.
An experimental arrangement for measuring the thermal conductivity of solid materials involves the use of two long rods that are equivalent in every respect, except that one is fabricated from a standard material of known thermal conductivity kA while the other is fabricated from the material whose thermal conductivity kB is desired. Both rods are attached at one end to a heat source of fixed temperature Tb, are exposed to a fluid of temperature [infinity] T[infinity], and are instrumented with thermocouples to measure the temperature at a fixed distance x1 from the heat source. If the standard material is aluminum, with kA= 200 W/m·K, and measurements reveal values of TA= 75°C and TB= 70°C at x1 for Tb= 100°C and [infinity] T[infinity]= 25°C, what is the thermal conductivity kB of the test material?
Answers
Answer: the thermal conductivity of the second material is 125.9 W/m.k
Explanation:
Given that;
The two rods could be approximated as a fins of infinite length.
TA = 75°C, θA = (TA - T∞) = 75 - 25 = 50°C
TB = 70°C θB = (TB - T∞) = 70 - 25 = 45°C
Tb = 100°C θb = (Tb - T∞) = (100 - 25) = 75°C
T∞ = 25°C
KA = 200 W/m · K , KB = ?
Now
The temperature distribution for the infinite fins are given by
θ/θb = e^(-mx)
θA/θb= e^-√(hp/A.kA) x 1 --------------1
θB/θb = e^-√(hp/A.kB) x 1---------------2
next we take the natural logof both sides,
ln(θA/θb) = -√(hp/A.kA) x 1 ------------3
In(θB/θb) = -√(hp/A.kB) x 1 ------------4
now we divide 3 by 4
[ ln(θA/θb) /in(θB/θb)] = √(KB/KA)
we substitute
[ In(50/75) /In(45/75)] = √(KB/200)
In(0.6666) / In(0.6) = √KB / √200
-0.4055/-0.5108 = √KB / √200
0.7938 = √KB / 14.14
√KB = 11.22
KB = 125.9 W/m.k
So the thermal conductivity of the second material is 125.9 W/m.k
How can you tell whether a trash container is for regular or biohazardous waste?.
Answers
whats your answer Where is the strangest place you’ve urinated or defecated?
Answers
Answer:At the train station
Explanation:
Answer:
in those camping portal pottys
Clarisse is an architect. What skills will she apply to integrate her visualized solutions with other aspects such as business and industry standards? Clarisse will apply BLANK skills to integrate her visualized solutions with other aspects such as business and industry standards.
Answers
Answer:
Conceptual problem-solving skills
Explanation:
Conceptual problem-solving is a way of solving problems by applying what we know to what we do not know. For Clarisse who is an architect, the knowledge she has about visualization, and the concepts of the business world are not quite related.
So to integrate her visualization solutions to business standards, she would have to compare the two spheres of knowledge to determine how to adapt one t the other.
Answer:
Management skills
Explanation:
Bit of a shot in the dark here, but, and i quote:
"Management skills comprise planning, organizing, and coordinating a project to reach a goal. Architects apply management skills to integrate their visualized solutions with other aspects such as business and industry standards."
Hopefully this works out for ya'll.
In this activity, you will conduct research on a famous work of architecture from the 1800s and write a report about the work and the architect who created it. You will then create an architectural drawing.
__________________________________________________________________________
Directions and Analysis
Task 1: Researching an Architectural Work of the 1800s
Use the Internet and other available resources to conduct basic research on architecture from the 1800s. Select a building designed by a significant (influential) architect from that period, and then write a paper about the building and architect. Make sure you include the following:
About the architect
basic biographical information
education
how the architect influenced society and design
About the building/work
main materials used
structural considerations
technology and tools used during construction
Answers
Answer:
can you explain how to do this
Explanation:
What make metal ductwork more desirable than flex duct?
Less friction loss
Less chance of restriction
More direct routes to boots
All of the above
Answers
Hope this helps
Air is contained inside a vertical piston-cylinder assembly by a piston of mass 105 kg and face area of 0.05 m2 . The mass of air inside the cylinder is 20 grams, and the air initially occupies a volume of 50 liters. The atmosphere exerts a pressure of 101.3 kPa on the top of the piston. The volume of the air slowly decreases to 0.005 m3 , while maintaining constant pressure, as the specific internal energy of the air decreases by 175 kJ/kg. Neglecting friction between the piston and the cylinder wall, determine the heat between the surroundings and the air inside the piston-cylinder assembly in kJ
Answers
Answer:
ΔQ = 1.06 KJ
Explanation:
The amount of heat transfer between the piston-cylinder system and the surrounding can easily be found by using the First Law of Thermodynamics. The first law of thermodynamics can be written as follows:
ΔQ = ΔU + W
ΔQ = mΔu + PΔV
where,
ΔQ = Heat transfer between system and surrounding = ?
Δu = specific change in internal energy of the system = - 175 KJ/kg
m = mass of air = 20 g = 0.02 kg
P = Constant Pressure = 101.3 KPa
ΔV = Change in Volume = 0.05 m³ - 0.005 m³ = 0.045 m³
Therefore,
ΔQ = (0.02 kg)(-175 KJ/kg) + (101.3 KPa)(0.045 m³)
ΔQ = -3.5 KJ + 4.56 KJ
ΔQ = 1.06 KJ
All of these are true about aluminum EXCEPT that it:
A) has a self-healing, corrosion-resistant coating.
B) is resistant to galvanic corrosion.
C) is a nonferrous metal.
D) is easy to be initially formed.
Answers
All of the aforementioned are true characteristics and properties of aluminum except: B. is resistant to galvanic corrosion.
What is aluminum?Aluminum can be defined as a silvery white metal and it is considered to be the most abundant metal found in the Earth's crust. Also, it is represented with the chemical symbol "Al" and it has an atomic number of thirteen (13).
This ultimately implies that, aluminum is found in Group 3 on the periodic table because it has three (3) valence electrons, which are found in the outermost shell of its atomic nucleus.
The characteristics and properties of aluminum.Some of the characteristics and properties of aluminum include the following:
It has a self-healing and corrosion-resistant coating.It is a nonferrous metal.It is easy to be initially manufacture or formed.Read more on aluminum here: https://brainly.com/question/25869623
When a current carrying coil is placed between the magnetic poles a force acts on it that causes it to rotate what can be done to make the coil rotate faster
Answers
Answer:
increase the field strengthincrease the currentdecrease the moment of inertia of the coilExplanation:
The rotation speed depends on the force applied to the coil, and on the mass (moment of inertia) of the coil. The force can be increased by ...
increasing the magnetic field strength
increasing the coil current
And the moment of inertia can be decreased by ...
making the coil lighter
making the coil more compact.
Any of these changes will increase the rotation speed.
A transparent film is to be bonded onto the top surface of a solid plate inside a heated chamber. For the bond to cure properly, a temperature of 70°C is to be maintained at the bond, between the film and the solid plate. The transparent film has a thickness of 1 mm and thermal conductivity of 0.05 W/m·K, while the solid plate is 13 mm thick and has a thermal conductivity of 1.2 W/m·K. Inside the heated chamber, the convection heat transfer coefficient is 70 W/m2·K. If the bottom surface of the solid plate is maintained at 52°C.
Required:
Determine the temperature inside the heated chamber and the surface temperature of the transparent film. Assume thermal contact resistance is negligible.
Answers
Answer:
1.) 103.23 degree centigrade
2.) 126.96 degree centigrade
Explanation:
Given that a transparent film is to be bonded onto the top surface of a solid plate inside a heated chamber. For the bond to cure properly, a temperature of 70°C is to be maintained at the bond, between the film and the solid plate. The transparent film has a thickness of 1 mm and thermal conductivity of 0.05 W/m·K, while the solid plate is 13 mm thick and has a thermal conductivity of 1.2 W/m·K. Inside the heated chamber, the convection heat transfer coefficient is 70 W/m2·K. If the bottom surface of the solid plate is maintained at 52°C.
To determine the temperature inside the heated Chamber, let us first calculate the heat transfer rate per unit area through the plate by using the formula
Heat transfer rate R = k( Tb - T2)/L
Where
k = 1.2 W/mA.K
Tb = 70 degree
T2 = 52 degree
L = 13mm = 13/1000 = 0.013m
substitute all the parameters into the formula above.
R = 1.2 x ( 70 - 52 )/ 0.013
R = 1.2 x (18/0.013)
R = 1661. 5 W/m^2
the surface temperature of the transparent film will be
Ts = Tb + (RLf/Kf)
Ts = 70 + (1661.5 x 0.001)/0.05
Ts = 70 + (1.6615)/0.05
Ts = 70 + 33.23
Ts = 103.23 degree centigrade
the temperature inside the heated Chamber will be calculated by using the formula
Ti = Ts + (R/h)
Ti = 103.23 + (1661.5/70)
Ti = 103.23 + 23.74
Ti = 126.97 degree centigrade
A cone-shaped part is to be fabricated using stereolithography. The radius of the cone at its base = 35 mm, and its height = 50 mm. To minimize the staircase effect, layer thickness = 0.05 mm. The diameter of the laser beam = 0.22 mm, and the beam is moved across the surface of the photopolymer at a velocity of 900 mm/s.
Required:
Compute an estimate for the time required to build the part, if 15 s are lost each layer to lower the height of the platform that holds the part. Neglect post-curing time. Setup time for the job = 25 min.
Answers
Explanation:
volume = πR²h/3
= πx35²x50/3
= 192325/3
= 64166.725
number of layers n = 50mm/0.05
n = 1000layers
average volume = 64166.725/1000
= 64.167mm³
average area = 64.167/0.05
= 1283.34mm²
average time = 1283.34/900mm x 0.22
= 6.48
6.48 + 15 seconds
= 21.48 seconds
time required = 1000x21.48
= 21480 seconds
convert to minutes
21480/60
= 358 minutes
21480/3600
= 5.967 hours