A student accidentally left a bottle of ammonia unclosed in the corner of a laboratory. After a few minutes the entire laboratory smelled of ammonia. Which process has occurred?
Diffusion
Distillation
Evaporation
Brownian motion

Answers

Answer 1
Diffusion I’d the spreading of something more widely.

The smell of ammonia diffused throughout the laboratory.

Answer : Diffusion

Related Questions

tell me the name please

Answers

Answer:

molecules

Explanation:

they are molecule

How does an indicator show the difference between an acid and an alkali?​

Answers

Answer: There are various indicators like litmus paper, phenolphthalein, universal indicator etc. that changes its colour to show the difference between acid and alkali.

Which of the following molecules is an
alcohol? There is only one correct answer.
CH3COOH
CH3OH
CH2NH2
C2H5CI

Answers

CH3OH IS MOLECULES OF ALCOHOL

the answer is CH3OH and i hope you get it correctly

Which of the following most likely happens when the volume of a gas increases?

-The number of collisions of gas particles remains same.

-The number of collisions of gas particles increases.

-The pressure of the gas remains same.

-The pressure of the gas decreases.

Answers

the pressure of the gas increases

Answer:

The number of collisions of gas particles increases.

Explanation:

Just took the test!!!

Detects radio waves from objects in space:

a) Radio Telescopes
b) Reflection Telescope
c) Compound telescope
d) Refraction telescope

Answers

Answer:

The correct answer is A

Explanation:

A radio telescope is used to detect, collect and focus radio waves from distant objects in the sky or space. While a compound telescope, by design, can both refract and reflect waves. A reflection telescope uses curved mirrors to reflect light to form an image. A refraction telescope forms an image using a lens as its objective.

From the above definitions, it can be deduced that option A is the correct answer.

how to determine the aspects for core and valence electrons in a periodic table. How comes in some elements like cobalt the 3d is on the valence side and arsenic the 3d is on the core side.​

Answers

Answer:

See explanation

Explanation:

The electron configuration of an atom in an element determines the property of the atom. The core electrons are found inside the atom while the valence electrons are found on the outermost shell of the atom.

For cobalt, the outermost shell electron configuration is; [Ar] 3d7 4s2. The 3d7 and 4s2 are found in the valence shell of cobalt.

For arsenic, the electronic configuration is [Ar] 3d¹⁰ 4s² 4p³. The valence electrons are 4s2, 4p3. The 3d electrons are found inside the arsenic atom.

The density of aluminum is 2.7 grams per cm'.
How many grams does 12 cm of aluminum
weigh?

Answers

Answer:

32.4grams

Explanation:

Density of a substance can be calculated as follows:

Density = mass ÷ volume

According to this question, the density of aluminum is 2.7g/cm³ while its volume is 12 cm³. The mass of aluminum is therefore,

2.7 = m/12

m = 12 × 2.7

m = 32.4grams.

The mass of aluminum is 32.4grams

số oxi hóa của các nguyên tố: Fe(OH)2; Fe(OH)3; FexOy; Zn(OH)2 là gì

Answers

Answer:

esfsef

Explanation:

esfsefseF

(1) The solubility of Salt AB2(S) IS 5mol/dm^3.
a. Obtain an expression for the solubility product of AB2(S),in terms of s.
b. Calculate the Ksp of AB2,given that solubility is 2.4x10^3mol/dm^3

Answers

Answer:

a. Ksp = 4s³

b. 5.53 × 10⁴ mol³/dm⁹

Explanation:

a. Obtain an expression for the solubility product of AB2(S),in terms of s.

AB₂ dissociates to give

AB₂ ⇄ A²⁺ + 2B⁻

Since 1 mole of AB₂ gives 1 mole of A and 2 moles of B, we have the mole ratio as

AB₂ ⇄ A²⁺ + 2B⁻

1 : 1 : 2

Since the solubility of AB₂ is s, then the solubility of A is s and that of B is 2s

So, we have

AB₂ ⇄ A²⁺ + 2B⁻

[s]        [s]    [2s]

So, the solubility product Ksp = [A²⁺][B⁻]²

= (s)(2s)²

= s(4s²)

= 4s³

b. Calculate the Ksp of AB₂, given that solubility is 2.4 × 10³ mol/dm³

Given that the solubility of AB is 2.4 × 10³ mol/dm³ and the solubility product Ksp = [A²⁺][B⁻]² = 4s³ where s = solubility of AB = 2.4 × 10³ mol/dm³

Substituting the value of s into the equation, we have

Ksp = 4s³

= 4(2.4 × 10³ mol/dm³)³

= 4(13.824 × 10³ mol³/dm⁹)

= 55.296 × 10³ mol³/dm⁹

= 5.5296 × 10⁴ mol³/dm⁹

≅ 5.53 × 10⁴ mol³/dm⁹

Ksp = 5.53 × 10⁴ mol³/dm⁹

The element copper has 29 protons. What is the atomic number of copper?

Answers

The atomic number of copper is 29.

Hope this helps and if it does, don't be afraid to rate my answer as well as maybe give it a "Thanks"? (Or even better a "Brainliest"). And if it’s not correct, I am sorry for wasting your time, and good luck finding the correct answer :)


Answer:

29

Explanation:

since protons are a constant and unique characteristic of an element it's considered as he atomic number of that element.

NaBr
ions in
an aqueous solution.
A
forms
B
does not form

Answers

Answer:

A

Explanation:

i had to answer this question a few weeks ago

Which substance is a basic oxide?​

Answers

The oxide that gives a base in water is known as a basic oxide. An amphoteric solution is a substance that can chemically react as either acid or base. However, it is also possible for an oxide to be neither acidic nor basic, but is a neutral oxide.

A brass metal bar is made up of copper and zinc. (Between 50% to 70% is copper.) A brass metal bar weighs 20.15 ounces. 35% of the bar is zinc. How many ounces of copper are in the bar?

Answers

Answer:

The correct answer would be - 13.0975 ounces.

Explanation:

We know that brass is made up of zinc and copper. The copper part of the brass is approximately around 50 to 70% and the remaining is the zinc part.

Given:

Zinc percentage in a brass = 35%

copper percentage would be - 65% (100 - 35 = 65)

Weight of the brass metal bar = 20.15 ounce

ounces of copper are in the bar = ?

Solution:

The weight of the copper in the brass metal in ounces-

= weight of brass* percentage of copper/100

= 20.15*65/100

= 13.0975 ounces of copper.

2nd method =

The weight of the zinc in the brass metal in ounces-

= weight of brass* percentage of zinc/100

= 20.15*35/100

= 7.0525

The weight of the copper = total weight - weight of zinc

= 13.0975 ounces of copper.

The values used in the scale of pH and pOH are derived from a system designed by ______.

Curie
Gordonsen
Dalton
Sorenson

Answers

the answer to this question Is sorenson

What determines the strength of a dipole dipole force?

Answers

Answer:

The more polar the molecules, the stronger the force. The more hydrogen in the molecule, the stronger the force.

Explanation:

I hope this helps and please ask if you need further help!

Which diagram shows how the covalent bonds most likely form in a phosphorous trichloride molecule?

Answers

The first answer is correct

The first diagram shows the covalent bonds most likely form in a phosphorous trichloride molecule. Hence, option A is correct.

What is a covalent bond?

Covalent bonds can be polar or nonpolar depending on the electronegativity difference between the atoms involved. In a nonpolar covalent bond, the electrons are shared equally between the atoms. In a polar covalent bond, the electrons are shared unequally.

Phosphorus trichloride (PCl₃) is a covalent compound that consists of one phosphorus atom and three chlorine atoms. The three chlorine atoms are located in a plane that is perpendicular to the phosphorus atom, forming an equilateral triangle with bond angles of 120°.

The molecule has a trigonal pyramidal shape, with the phosphorus atom at the apex and the three chlorine atoms at the base of the pyramid. The fourth hybridized orbital of phosphorus contains a lone pair of electrons that is located above the trigonal plane, giving the molecule a distorted tetrahedral geometry.

Thus, option A is correct.

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Which factor decide the reactivity of alkyl halide?

Answers

Answer:

The reactivity order reflects both the strength of the C-X bond and the stability of X(-) as a leaving group and leads to the general conclusion that alkyl iodides are the most reactive members of this functional class

304 cm x m and 67kg to gram please helpppp!!!!!!!!​

Answers

304cm = 3.04m

67kg= 67000g

Answer:

[tex]304cm = 3.04m \\ 67kg = 67000g[/tex]

Explanation:

[tex]100cm \: = 1m \\ 304cm = x \\ use \: \: cross \: multipication \\ 100x = 304 \\ \frac{100x}{100} = \frac{304}{100} \\ x = 3.04m[/tex]

-------------------------------------------------

[tex]1kg = 1000g \\ 67kg = x \\ \\ use \: cross \: \: multipication \\ 1x = 67 \times 1000 \\ x = 67000g[/tex]

Hope this helps

Have a nice day!

What is a molecule containing only carbon and hydrogen called?
O A. An inorganic molecule
O B. A hydrocarbon
O c. A metallic molecule
D. An ionic molecule
(answer is provided) :)

Answers

Answer:

A

Explanation:

did that on my test

A. It’s A bc the girl answered it before so I believe A

How many grams are in 562 dg?
56.2 g
56,200 g
5.620 g
5.62 g

Answers

Answer:

56.2

Explanation:

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Calculate the total amount of energy required in calories to convert 50.0 g of ice at 0.00 degrees Celsius to steam at 100. degrees Celsius.

Specific heat capacity of water is 1.00 cal/g OC

Hfusion = 80 cal/g OC and Hvap = 540 cal/g OC

Write the complete equation you will use.

Substitute the values in the equation in step 1.

Report the math answer with 3 sig figs and the correct unit.

Answers

Answer: The amount of heat absorbed is [tex]36.0\times 10^3Cal[/tex]

Explanation:

Few processes involved are:

(1): [tex]H_2O (s) (0^oC, 273K) \rightleftharpoons H_2O(l) (0^oC,273K)[/tex]

(2): [tex]H_2O (l) (0^oC, 273K) \rightleftharpoons H_2O(l) (100^oC,373K)[/tex]

(3): [tex]H_2O (l) (100^oC, 373K) \rightleftharpoons H_2O(g) (100^oC,373K)[/tex]

Calculating the heat absorbed for the process having same temperature:

[tex]q=m\times \Delta H_{(f , v)}[/tex] ......(i)

where,

q is the amount of heat absorbed, m is the mass of sample and is the enthalpy of fusion or vaporization

Calculating the heat released for the process having different temperature:

[tex]q=m\times C_{s,l}\times (T_2-T_1)[/tex] ......(ii)

where,

[tex]C_{s,l}[/tex] = specific heat of solid or liquid

[tex]T_2\text{ and }T_1[/tex] are final and initial temperatures respectively

For process 1:

We are given:

[tex]m=50.0g\\\Delta H_{fusion}=80Cal/g[/tex]

Putting values in equation (i), we get:

[tex]q_1=50.0g\times 80Cal/g\\\\q_1=4000Cal[/tex]

For process 2:

We are given:

[tex]m=50.0g\\C=1.00Cal/g^oC\\T_2=100^oC\\T_1=0^oC[/tex]

Putting values in equation (i), we get:

[tex]q_2=50g\times 1Cal/g^oC\times (100-0)\\\\q_2=5000Cal[/tex]

For process 3:

We are given:

[tex]m=50.0g\\\Delta H_{vap}=540Cal/g[/tex]

Putting values in equation (i), we get:

[tex]q_3=50.0g\times 540J/g\\\\q_3=27000Cal[/tex]

Calculating the total amount of heat released:

[tex]Q=q_1+q_2+q_3[/tex]

[tex]Q=[(4000)+(5000)+(27000)]Cal=36000Cal=36.0\times 10^3Cal[/tex]

Hence, the amount of heat absorbed is [tex]36.0\times 10^3Cal[/tex]

True or false one example of a chemical reaction is when H20 melts and changes state ice to liquid

Answers

Answer:

faulse

Explanation:

this is an example of a change in proporties

please i need help ……

Answers

Answer:

H2

Explanation:

(l) means liquid

(s) means solid

(g) means gaseous

I hope this helped [:

What is the y-intercept of the function f(x) = -x+ ?
2 름

Answers

The y intercept will be +2

The points on the y-intercepts are (0,y) whereas the point on the x-intercept are (x,0). Here the y-intercept of the function f(x) = -x + 2 is 2.

What is y-intercept?

When the line touches the y-axis, we can say that these are y-intercepts. The y-intercept can be found out when x = 0. This represents the point at which the graph crosses through the y-axis. The y-intercept can also be referred as y-value.

In order to find the intercepts of any function, we must find the coordinates of the point where the function intersects the x and y axis. This can also be done by equating the independent or dependent variable value as 0 and then finding out the other value.

Here the given function is:

f(x) = -x + 2

When we put x = 0, then

f(x) = -0 + 2 = 2

Thus the y-intercept is 2.

To know more about y-intercept, visit;

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the rate of diffusion of gas having molecules mass 4 times that ouch4 is 50 cc.the rate of diffusion of mithane is??​

Answers

Answer: The rate of diffusion of methane is 100 cc.

Explanation:

Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

[tex]\text{Rate}=\frac{1}{\sqrt{M}}[/tex]       .....(1)

where M is the molar mass of the gas

We are given:

[tex]Rate_{X}=50cc[/tex]

[tex]M_{X}=4\times M_{CH_4}[/tex]

Since the molar mass of methane = 16 g/mol

Using equation 1:

[tex]\frac{Rate_{CH_4}}{Rate_{X}}=\sqrt{\frac{M_X}{M_{CH_4}}}[/tex]

Putting values in above equation, we get:

[tex]\frac{Rate_{CH_4}}{50cc}=\sqrt{\frac{(4\times 16)}{16}}\\\\Rate_{CH_4}=50\times \sqrt{4}\\\\Rate_{CH_4}=50times 2=100cc[/tex]

Hence, the rate of diffusion of methane is 100 cc.

The absorption spectrum of sodium has a line at 589 nm. What is the energy of this line? (The speed of light in a vacuum is 3.00 x 10^8 m/s, and Planck's constant is 6.626 x 10^-34 Jos.)

A. 8.89 x 10^26 J
B. 5.09 x 10^14 J
C. 3.37 x 10^-19 J
D. 2.96 x 10^18 J

Answers

Answer:

C. 3.37 x 10^-19 J

Explanation:

At 40km up in the atmosphere the pressure is 3.8 kPa. I release a balloon with a volume of 30.0
liters from sea level. The balloon ascends up into to atmosphere 40 km. What will be the new
volume of the balloon, assuming no change in temperature?
Answer in liters

Answers

30 is the best for you to be able to get items on each other’s back to io

What is the colour of Copper sulphate solution​

Answers

Answer:

blue

Explanation:

Pu-238 (Plutonium, 238) decays by α emission to form an atom, which atom is this?

Answers

Answer:

Helium atom

Explanation:

For the RTGs flown by the United States, the radioisotope has been some chemical form of plutonium-238 (238Pu or Pu-238). Plutonium-238 decays primarily by the emission of an alpha particle (a helium atom without its electrons).

Summarize your findings in a short report of 150 words. Include your hypothesis, observations, data, calculations, and conclusion. The answers to the questions below should be included in your conclusion.

Why didn't the box slide off the table before you put enough coins in the bag?
What was the coefficient for the smooth surface? For the rough surface?
What was the difference between the two coefficients? What caused this difference?
What factors caused a margin for human error in this investigation?
Would the coefficient vary if you tied the string to a similar object of different masses, but on the same surface? Explain.
What did you learn from this investigation? Be thoughtful in your answer.

Answers

Answer:

Follow these steps.

1. Fill the matchbox with pebbles. Weigh the matchbox with the pebbles inside. Record that weight.

2. Tie the string to the box. Allow the string to hang over the edge of the table.

3. Tie the other end of the string to a corner of the plastic bag, leaving an opening to put in coins.

4. Add coins one by one until the box is pulled off the table.

5. Count and record the number of coins and the weight of the bag with the coins in it.

6. Lay the round sticks on the table about 1 inch apart and about 2 inches from the edge of the table.

7. Put the matchbox on the rollers farthest from the edge of the table.

8. Now add coins one by one to the bag until the box is pulled off the table.

9. Count and record the number of coins and the weight of the bag with the coins in it.

10. Repeat the experiment. Determine your margin of error if your results vary. For accuracy, repeat the experiment if desired.

11. Using the equation for the coefficient of friction in the text above, determine the coefficient of friction for the matchbox in each experiment. Include this data in your summary.

Explanation:

I think this is useful

please make me as breainlest

Answer:Follow these steps.

1. Fill the matchbox with pebbles. Weigh the matchbox with the pebbles inside. Record that weight.

2. Tie the string to the box. Allow the string to hang over the edge of the table.

3. Tie the other end of the string to a corner of the plastic bag, leaving an opening to put in coins.

4. Add coins one by one until the box is pulled off the table.

5. Count and record the number of coins and the weight of the bag with the coins in it.

6. Lay the round sticks on the table about 1 inch apart and about 2 inches from the edge of the table.

7. Put the matchbox on the rollers farthest from the edge of the table.

8. Now add coins one by one to the bag until the box is pulled off the table.

9. Count and record the number of coins and the weight of the bag with the coins in it.

10. Repeat the experiment. Determine your margin of error if your results vary. For accuracy, repeat the experiment if desired.

11. Using the equation for the coefficient of friction in the text above, determine the coefficient of friction for the matchbox in each experiment. Include this data in your summary.

Explanation:

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