A student increases the temperature of a 200 cm balloon from 60°C to 120°C.
What will the new volume of the balloon be?
A)100cm^3
B)200cm^3
C)263cm^3
D)400cm^3

Answer:

298. 7 K.

Explanation:

Hello!

In this case, since equation we use to compute the heat in a cooling or heating process is:

[tex]Q=mC(T_f-T_i)[/tex]

Whereas we are given the heat, mass, specific heat and initial temperature. Thus, we infer that we need to solve for the final temperature just as shown below:

[tex]T_f=T_i+\frac{Q}{mC}\\\\T_f=1000 K+\frac{-270000J}{1000g*0.385\frac{J}{g*K} } \\\\T_f=298.7 K[/tex]

It is important to notice that the iron release heat as water absorbs it, that is why it is taken negative.

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Answer:

Kp = Kc (RT) ^(-2)

Explanation:

For the reaction;

N2 (g) + 3H2 ⇄ 2NH3(g)

We can write;

Kc = [NH3]^2/[N2] [H2]^3

But

Kp = pNH3^2/pN2 . PH2^3

To convert from Kc to Kp

Kp = Kc (RT) ^Δn

where Δn is the change in number of moles going from reactants

to products.

For this reaction;

Δn = 2- (3+1) = -2

Kp = Kc (RT) ^(-2)

Answer:

6.48%

Explanation:

Answer:

Convention

Explanation:

Answer:

Because the soup became warm and less dense, so it rose up.

Explanation:

Found on Course Hero is an American education technology website company based in Redwood City, California, which operates an online learning platform for students to access course-specific study resources contributed by a community of students and educators.

Answer:

[tex]7.84\ \text{moles}[/tex]

Explanation:

Number of atoms of carbon = [tex]4.72\times 10^{24}[/tex]

Avogadro's number = [tex]6.022\times 10^{23}\ \text{mol}^{-1}[/tex]

Here we have to divide the number of atoms by the Avogadro's number

[tex]\dfrac{4.72\times 10^{24}}{6.022\times 10^{23}}=7.83792\approx 7.84\ \text{moles}[/tex]

The moles of carbon are [tex]7.84\ \text{moles}[/tex].

Answer:C10H12

Explanation:

Given :empirical formula =C5H6

molar mass of carbon =12 g /mole approximately

molar mass of hydrogen =1.01g/mole approximately

molar mass of C5H6=(5*12)+(6*1.01)=66.06 g/moles

132.21/66.06=2 approximately

therefore ,the answer is  C10H12

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Answer:

it is option c. the mass is equal of both

The law of conservation of mass is the concept used here to find out the true statement. The correct option is C - The mass of the products is equal to the mass of the reactants.

The law which states that matter can neither be created nor destroyed in a chemical reaction is defined as the law of conservation of mass. This law was postulated by the scientist A. Lavoisier.

This law also states that the total mass of the products should be always equal to the total mass of the reactants. The reactants are the substances which are seen on the left part of the equation and the products are seen on the right part of the equation.

Here the mass of the compound Mercury (II) oxide is same as that of mercury and oxygen. Thus the given equation obeys the law of conservation of mass.

Thus the correct option is C.

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Answer: balanced

Explanation:

Answer:

Part 1

triple point; 0.72 atm, 115.8 K

Part 2

Option D, The sample is initially a gas.

Explanation:

Part 1

The triple point of krypton is  0.72 atm

and the melting point of Krypton is -157.4 °C or  115.8 K

Hence, option C is correct

Part 2

Option D

At 59.8 atm, Krypton is a gas. It changes its state from gas to liquid and solid when the temperature is extremely low. Here the temperature is same , hence only option D is correct

Answer: The Law of Conservation of Mass dates from Antoine Lavoisier's 1789 discovery that mass is neither created nor destroyed in chemical reactions. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.

Explanation:

Answer:

2.68 cm^3

Explanation:

Density= Mass/Volume

so...

8.96 g/cm^3 = 24.01 g/ V

and then u solve so it would be 2.68 cm ^3

((:

Answer:31 days

Explanation:

3500kcal/lb x 5lb =17500

1800-1230=570

17500/570=30.70

Round up =31

This question involves the concepts of energy, weight, and time.

It will take Charles "9.7 days" to lose 5.0 lb.

Since the loss of 1.0 lb weight requires expending 3500 kcal energy. Therefore, by using the unitary method,

1.0 lb loss = 3500 kcal

(5)(1.0) lb loss = (5)(3500 kcal)

5.0 lb loss = 17500 kcal ----- eqn(1)

Now, the time required to consume 1800 kcal is 1 day. Hence, by the unitary method,

1800 kcal = 1 day

1 kcal = [tex]\frac{1}{1800}\ day[/tex]

17500 kcal = [tex]\frac{17500}{1800}[/tex] day

17500 kcal = 9.7 days ------ eqn(2)

Comparing eqn (1) and eqn (2)

5.0 lb loss = 9.7 days

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Answer:

P₂O₄

Explanation:

From the question given above, the following data were obtained:

Empirical formula = PO₂

Molar mass of compound = 126 g/mol

Molecular formula =.?

The molecular formula of the compound can be obtained as illustrated below:

Molecular formula = [Empirical]ₙ

= molar mass

[PO₂] × n = 126

[31 + (16× 2)] × n = 126

[31 + 32] × n = 126

63 × n = 126

Divide both side by 63

n = 126 / 63

n = 2

Molecular formula = [PO₂]ₙ

Molecular formula = [PO₂]₂

Molecular formula = P₂O₄

Answer:

Hindi ko po alam pero subukan ko pong sagutan yan

Answer:

A. Ba

Explanation:

Atomic radius increases as you go down and decreases as you go right.

458 g H₂SO₄

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

4.67 mol H₂SO₄

Step 2: Identify Conversions

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

458.08 g H₂SO₄ ≈ 458 g H₂SO₄

Answer:

b. temperature difference

Answer:

[tex]d=4.75\times 10^{-9}\ \text{inches}[/tex]

Explanation:

Given that,

The distance between the centers of the two oxygen atoms in an oxygen molecule is [tex]1.21\times 10^{-8}\ cm[/tex].

We need to convert this distance in inches.

We know that,

1 cm = 0.393 inches

We can solve it as follows :

[tex]1.21\times 10^{-8}\ cm=0.393\times 1.21\times 10^{-8}\\\\=4.75\times 10^{-9}\ \text{inches}[/tex]

So, the distance between the centers of the two oxygen atoms is [tex]4.75\times 10^{-9}\ \text{inches}[/tex].

Answer:

1. I

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3.YOU

JUST KIDDING

REAL ANSWER

Therefore, to get a neutral compound requires two Br and one Ca - ie, CaBr2.

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3.0 × 10²³ molecules AgNO₃

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

85 g AgNO₃ (silver nitrate)

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃

Answer:

Formula for aluminum oxide Al₂O₃

Explanation:

Hope that helps

Answer:

Al2O3, ionic

Explanation:

Answer:

Dispersion forces

Dipole-Dipole interaction

Explanation:

The London dispersion force refers to the temporary attractive force that acts between the electrons in two adjacent atoms when the atoms develop temporary dipoles. Dispersion forces act between any two molecules even when other intermolecular forces are in operation as long as the molecules are in close proximity to each other.

Now, CO is polar and the HCN is also polar molecule. Hence, dipole - dipole interaction forces  are also in operation and acts between the two molecules in close proximity to each other.

Dispersion forces and Dipole-Dipole interaction are intermolecular forces which act between a hydrogen cyanide (HCN) molecule and a carbon monoxide molecule

The transitory attractive force that exists between the electrons in two nearby atoms when the atoms form transient dipoles is known as the London dispersion force. As long as the molecules are close to one another, dispersion forces can exist between any two molecules, even when other intermolecular forces are active.

The HCN molecule and CO are both polar molecules right now. As a result, dipole-dipole interaction forces act between the two molecules when they are close to one another.

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Answer:

Motion control systems are any system that control one or more of the following of a machine: its position, velocity, force, and/or pressure. They generally consist of the follow components: Motion controller: the central part that operates the system (I.e. the brain)

Answer:

1. Mn(s) + Ca(NO₃)₂(aq)  ----> No reaction

2. KOH(aq) +  Fe(s)   ----> No reaction

3. Pt(NO₃)₂(aq) + Cu(s)  ----> Reaction occurs

4. Cr(s) + H₂SO₄(aq)   ----> Reaction occurs

Explanation:

The activity series of metals is a series that arranges metals in order of reactivity from highest to lowest. It is used to determine which metal will displace another in a single displacement reactions, whereby a metal A, will replace or be replaced by another metal B in an aqueous solution depending on their relative positions in the activity series.

Considering the given reactions:

1. Mn(s) + Ca(NO₃)₂(aq)

2. KOH(aq) +  Fe(s)

3. Pt(NO₃)₂(aq) + Cu(s)

4. Cr(s) + H₂SO₄(aq)

Reaction 1 will not occur because manganese, Mn, is lower than calcium, Ca, in the activity series of metals and cannot displace it from aqueous solutions.

Reaction 2 will not occur since iron, Fe, is lower than potassium, K, in the activity series and cannot displace it from aqueous solutions.

Reaction 3 will occur since platinum, Pt, is lower than copper, Cu, in the activity series and thus can be displaced by copper from aqueous solutions.

Reaction 4 will  occur since chromium, Cr, is higher than hydrogen, H, in the activity series and thus, can displace it from aqueous solutions.

Answer:

Enzyme mutations can lead to serious or fatal human disorders and are the consequence of inherited abnormalities in the affected individual's DNA. The mutation may be at a specific position in an enzyme encoded by a mutated gene, just like a single abnormal amino acid residue.

Explanation:

Answer:

4.82 moles of Ag.

Explanation:

We'll begin by calculating the number of mole in 450.98 g of Cu(NO₃)₂. This can be obtained as follow:

Molar mass of Cu(NO₃)₂ = 63.5 + 2[14 + (16×3)]

= 63.5 + 2[14 + 48]

= 63.5 + 2[62]

= 63.5 + 124

= 187.5 g/mol

Mass of Cu(NO₃)₂ = 450.98 g

Mole of Cu(NO₃)₂ =?

Mole = mass /Molar mass

Mole of Cu(NO₃)₂ = 450.98 / 187.5

Mole of Cu(NO₃)₂ = 2.41 moles

Next, we shall determine the number of mole of Cu needed to produce 450.98 g (i.e 2.41 moles) of Cu(NO₃)₂. This can be obtained as follow:

Cu + 2AgNO₃ —> Cu(NO₃)₂ + 2Ag

From the balanced equation above,

1 mole of Cu reacted to produce 1 mole of Cu(NO₃)₂.

Therefore, 2.41 moles of Cu will also react to produce 2.41 moles of Cu(NO₃)₂.

Thus, 2.41 moles of Cu is needed for the reaction.

Finally, we shall determine the number of mole of Ag produced from the reaction. This can be obtained as follow:

From the balanced equation above,

1 mole of Cu reacted to produce 2 moles of Ag.

Therefore, 2.41 moles of Cu will react to produce = 2× 2.41 = 4.82 moles of Ag.

Thus, 4.82 moles of Ag were obtained from the reaction.