a student that just received their driver's license decides to buy a new car. he remembers from physics class that heat engines have thermal efficiency that can be calculated. he asks the car dealer for a car that has a high thermal efficiency rating. the car dealer say he has a car that is 100% efficient. which law of thermodynamics best describes why the car cannot be 100% efficient?

Answers

Answer 1

Answer: the first law of thermodynamics

Explanation:

Answer 2

The second law of thermodynamics is the best description for the car to cannot be having 100% efficient engine.

What is the second law of thermodynamics?

Thermodynamics is the branch of science which deals with the study of heat. Heat is a form of energy which exists as a result of the change in the temperature between the two bodies or objects under study.

The second law of thermodynamics is a physical law, which is based up on the universal experience concerning with the heat and energy interconversions between bodies present in the system and surrounding. One simple statement of this law is that, the heat energy always moves from the hotter objects to the colder objects, unless the energy in some form is supplied to the object to reverse the direction of heat flow between the objects.

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Related Questions

6. A baseball player hits a 0.155-kilogram fastball traveling at -44.0 m/s into center field at a speed of 50.0

m/s. If the impact lasts for 0.00450 second, with what force does he hit the

baseball?

Answers

Answer:

3,237.78N

Explanation:

According to Newton's second law of motion

F = mass * acceleration

Since a = v-u/t

F = m(v-u)/t

Given

Mass m = 0.155kg

v = 50.0m/s

u = -44.0m/s

Time t = 0.00450secs

Substitute

F = 0.155(50-(-44))/0.00450

F = 0.155(50+44)/0.00450

F = 0.155(94)/0.00450

F = 14.57/0.00450

F = 3,237.78N

hence he hit the baseball with a force of 3,237.78N

what are the four intermittent reinforcement schedules in your own words?

Answers

The four resulting intermittent reinforcement schedules are: Fixed interval schedule (FI) Fixed ratio schedule (FR) Variable interval schedule (VI)

Using your knowledge on personal care products, how does sunscreen

lotion protect your skin from the damaging effect of ultraviolet rays?

Explain why of x-rays and gamma rays are commonly used in

radiotherapy.​

Answers

Answer:

Ultraviolet rays from sun are very harmful from skin and can cause sunburn and skin diseases especially ultraviolet B rays. A sunscreen  lotion act as a protection barrier on the skin that restrict the direct contact of UV rays with skin and filter the harmful rays to enter the skin.

Radiotherapy is a medical therapy use to treat cancer. Radiotherapy commonly uses x-rays and gamma rays because they are high-energy particles or waves that kills or destroys the cancer cells.

Sunscreen lotion is able to filter this damaging ultraviolet radiation and prevent it from damaging the skin.

The sun reaches us from outer space brings ultraviolet rays to us. Ultraviolet rays are known to have some damaging effects on the skin. One way to protect our skin from this damaging ultraviolet rays is to use sunscreen lotion which is able to filter this damaging ultraviolet radiation and prevent it from damaging the skin.

X-rays and gamma rays are used in radiotherapy because they are light energy rays which are able to penetrate and destroy malignant cells in the body.

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A car traveling 85 km/h is 250 m behind a truck
traveling 73 km/h.

Answers

Time needed = t = 20.83 s

Further explanation

Given

car speed = 85 km/h

truck speed = 73 km/h

Required

the time it takes for the car to reach the truck

Solution

When the car reaches the truck, the distance between them will be the same

x car - 250 m = x truck

General formula for distance (d) :

d = v.t

So the equation becomes :

85t-250 = 73t

12t=250

t = 20.83 s

A pendulum is placed on a distant planet. The length is one meter, and the measured period is 1.4 seconds, what is the acceleration of gravity on that planet?

Answers

Answer:

[tex]a=20.14\ m/s^2[/tex]

Explanation:

The time period of the simple pendulum is given by :

[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

l is the length of the pendulum

g is the acceleration due to gravity

We have,

T = 1.4 s, l = 1 m

So,

[tex]T^2=\dfrac{4\pi^2 l}{g}\\\\g= \dfrac{4\pi^2 l}{T^2}\\\\g= \dfrac{4\pi^2 \times 1}{(1.4)^2}\\\\g=20.14\ m/s^2[/tex]

So, the acceleration due to gravity of that planet is [tex]20.14\ m/s^2[/tex].

Is it possible for the earth to be sucked into a black hole? If so, what would happen?

Answers

Answer:

si es posible

Explanation:

ya no existiria la tierra

if possible

the earth would no longer exist.

Answer:

Yes,

Explanation:

We would all die immediatly, its like being stretched and crushed

A negatively-charged rod is brought close to (but does not touch) two neutral spheres that are in contact with each other but insulated from the ground. If the two spheres are then separated, what kind of charge will be on the spheres

Answers

Answer:

One sphere obtains a positive charge, while the other obtains a negative charge.

Explanation:

When the negatively-charged rod is brought close to the two neutral spheres in contact with each other, the electrons in both spheres are repelled away from the rod and thus those electrons move into the second sphere farther away from the rod.

The first sphere is now short of electrons.

When the spheres are separated, the first sphere which is short of electrons now carries a net positive charge, while the other sphere which has excess electrons now carries a net negative charge.

A stunt man jumps from a burning building and comes to
rest at ground level. Consider his impulse during landing if
he lands on a soft mat, on a concrete surface, or in a safety
net. Which of the following is true?
a. His impulse is greatest if he lands on a soft mat.
b. His impulse is greatest if he lands on a concrete
surface.
c. His impulse is greatest if he lands in a safety net.
d. The impulse is the same in all three cases.
e. There is zero impulse in all three cases because he
comes to rest.

Answers

Answer:

I think it's E it just sounds right to me tbh

Explanation:

How does energy keep the world going? How is energy conserved?​

Answers

Answer:

The most notable way that reducing energy helps the environment is by decreasing power plant emissions.

Answer:

Explanation:

The conservation of energy law states that energy cant be created or destroyed, only transferred. Since energy cant be created or destroyed, the amount of energy in the universe is completely constant.

Energy keeps the world "going" because we use it every single day in our life. Everything in the universe uses some sort of energy. We digest food for energy, we use electrical energy for electronics, we convert electrical energy into heat energy for heaters and such, we use solar panels to power our houses. There are countless examples of how energy keeps the world "going."

Which of the following statements is FALSE regarding the law of conservation of energy?


The total amount of energy remains constant.


Energy can neither be created nor be destroyed.


Energy can be transformed from one form to another.


The total amount of energy changes upon an energy transformation.

Answers

Answer:

D

Explanation:

because it doesn't agree with the law of definite proportion

and energy can niether be created nor destroyed but can be transformed from one form to another

The false statement will be, The total amount of energy changes upon an energy transformation.

What is conservation of energy?

The conservation of energy according to the first law of thermodynamics is that energy neither be created nor be destroyed, but can be transformed from one form to another form.

Now we can take many examples like if we are running a bicycle our efforts are converted to the rotation of the wheel and the rotation energy is converted to the linear energy of our motion.

But the necessary point is that from the second law of thermodynamics it states that the energy can not be completely converted to the other form but some part of it is losses in the environment.

Thus the false statement will be, The total amount of energy changes upon an energy transformation.

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Which statement about personal strength is TRUE?
1. It is inborn and cannot be developed with training or practice.
2. It is something you can acquire with hard work and lots of practice.
3. It is strictly a physical quality, like beauty, or physical ability, like the ability to swim fast.
4. It is such a natural part of a person that they may not even recognize it.

Answers

I think the answer would be 2 because strength can be learned and acquired with weights or other equipment

Hope this helps

Have a great day/night

Feel free to ask any questions

Predictions about the future based on the position of planets is an example of
- physics
- biology
- earth science
- pseudoscience

Answers

Answer:

astronomi

Explanation:

sciemce ya ya

9. What is the speed of a 25 kg object that has 2500 J of kinetic energy?

Answers

Answer:

We conclude that the speed of a 25 kg object that has 2500 J of kinetic energy is 14.14 m/s.

Explanation:

Given

Mass m = 25 kg Kinetic Energy (K.E) = 2500 J

To determine

The speed v = ?

We know that a body can possess energy due to its movement — Kinetic Energy.

The speed with which a body moves can be determined using the formula

[tex]K.E=\frac{1}{2}mv^2[/tex]

[tex]v=\sqrt{\frac{2\times \:K.E}{m}}\:\:\:[/tex]

substituting m = 25 and K.E = 2500 in the formula

[tex]v=\sqrt{\frac{2\times 2500}{25}}[/tex]

[tex]v=\sqrt{\frac{5000}{25}}[/tex]

[tex]v=\sqrt{200}[/tex]

[tex]v=14.14[/tex] m/s

Therefore, we conclude that the speed of a 25 kg object that has 2500 J of kinetic energy is 14.14 m/s.

An object is traveling at a velocity of 100 rn/s to the left for about 5 seconds. How far has the object traveled? (What is the distance?)

Answers

Answer:

500 rn

Explanation:

In a game of ice hockey, you use a hockey stick to hit a puck of mass 0.16 kg that slides on essentially frictionless ice. During the hit you exert a constant horizontal force on the puck that gives it an acceleration of 75 m/s2 for a fraction of a second. During the hit, what is the magnitude of the horizontal force that you exert on the puck

Answers

Answer:

12N

Explanation:

given- mass, acelation

Fnet=ma= .16kg*75m/s2

Fnet=12 N only force no friction given.

Cheetahs can accelerate to a speed of 20.0 m/s in 2.50 s and can continue to accelerate to reach a top speed of 30.0 m/s. Assume the acceleration is constant until the top speed is reached and is zero thereafter. Let the +x-direction point in the direction the cheetah runs. Express the cheetah’s top speed (vtop) in miles per hour (mi/h).
Starting from a crouched position, how much time (t-accel) does it take a cheetah to reach its top speed, and what distance (d) does it travel in that time?

Answers

Answer:

The cheetah’s initial velocity is 0 m/s. Let’s use the following equation to determine the acceleration.

Explanation:

Acceleration = (v/t) = (20/2.5) = 8m/sec^2.

1) Time to 29m/sec. = (v/a) = (29/8) = 3.625 secs. (3.6)

Distance covered to top speed = (v^2/2a) = 52.5625 metres (52.6).

2) Distance to run at top speed = (120 - 52.5625) = 67.4375 metres.

Time = (d/v) = (67.4375/29) = 2.325 secs.

Total time to warthog = (2.325 + 3.625) = 5.95 secs.

Cheetah's top speed will be "67.12 mi/h". A complete solution is provided below.

Given that:

Speed,

20.0 m/s

Time,

2.50 s

Acceleration to top speed,

30.0 m/s

Now,

Acceleration (a) of cheetah will be:

= [tex]\frac{20}{2.5}[/tex]

= [tex]8 \ m/s^2[/tex]

Top speed ([tex]V_{top}[/tex]) of cheetah

= [tex]\frac{30}{1609}\times 3600[/tex]

= [tex]67.12 \ mi/h[/tex]

→ The time required (t) to reach the top speed will be:

= [tex]\frac{30}{8}[/tex]

= [tex]3.75 \ sec[/tex]

and,

→ The distance travelled (d) by cheetah will be:

= [tex]\frac{1}{2}\times 8\times (3.75)^2[/tex]

= [tex]\frac{1}{2}\times 8\times 14.0625[/tex]

= [tex]56.25[/tex]

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A ball player catches a ball 3.10 s after throwing it vertically upward. a) with what speed did he throw it? b) what height did it reach?​

Answers

Answer:

speed=30.41, height=94.27

Explanation:

since the motion is vertical upward means the motion is against gravitational force and the initial velocity of the ball was zero.

Glucose is the main source of energy.
True or false

Answers

Answer:

True :p

Explanation:

Carbohydrates are foods that get converted into glucose.

For each scenario below, choose the best graph.
(a) Maria bikes from home to work.

Answers

A line graph that plots either speed or distance against time.

Really, the type of graph depends on what quantity you want the graph to show.

During their physics field trip to the amusement park, Leslie and Maria took a ride on the Whirligig. The Whirligig ride consists of long swings which spin in a circle at relatively high speeds. As part of their lab, Leslie and Maria estimate that the riders travel through a circle with a radius of 6.5 m and make one circle every 5.8 seconds. Determine the frequency, the period, the speed and acceleration of the riders on the Whirligig

Answers

Answer:

a) frequency = 0.1724 Hz

b) Period = 5.8 sec

c) speed = 7.04 m/s

d) acceleration = 7.62 m/s²

Explanation:

Given that;

radius = 6.5m

time period = 5.8 sec every circle

a)  the frequency

frequency is the number of rotation in unit time

frequency = 1 / time period = 1/5.8

frequency = 0.1724 Hz

b)  the period

period is time taken in one rotation

period = total time / rotation = 5.8 / 1

Period = 5.8 sec

c)  the speed

speed = distance/time = circumference/time period = 2πr / t = (2π×6.5) / 5.8

speed = 7.04 m/s

d) acceleration

To find the acceleration we take the linear velocity squared divided by the radius of the circle.

so

acceleration = v² / r = (7.04)² / 6.5 = 49.5616 / 6.5

acceleration = 7.62 m/s²

Someone help me with this PE question?

Answers

Answer:

Your abdominals

Explanation:

I think it is your core

Calculate the change in momentum of a ball has 35 kg mass and it changed its velocity from 3m/s to 6 m/s
please hellllpppppp

Answers

Answer:

105 kg.m/s

Explanation:

Formula for change in momentum is given as;

ΔP = m(v - u)

We are given;

Mass; m = 35 kg

Initial velocity; u = 3 m/s

Final velocity; v = 6 m/s

Thus;

ΔP = 35(6 - 3)

ΔP = 35 × 3

ΔP = 105 kg.m/s

What is a watt a unit of?

light


time


distance


power

Answers

Answer:

power...............m....

Answer:

The dimension of power is energy divided by time. In the International System of Units (SI), the unit of power is the watt (W), which is equal to one joule per second.

SI unit: watt (W)

In SI base units: kg⋅m2⋅s−3

Explanation:

At what speed, in m/s, would a moving clock lose 1.3ns in 1.0 day according to experimenters on the ground?

Answers

Answer:

v=0.14c

Explanation:

A cart was allowed to roll down a ramp from rest. It reached the bottom of the ramp with a speed of 25 cm/s. A student could conclude that the cart

Answers

Answer:

A student could conclude that the cart gained momentum as it rolled down.

Explanation:

If the cart was allowed to roll down the ramp from rest, it means that the initial velocity of the cart is zero (0). Also, if the final velocity of the cart became 25 cm/s, it means that the velocity of the cart increased from 0 to 25 cm/s.

Therefore, A student could conclude that the cart gained momentum as it rolled down.

Look at the equation. What detail is missing? 3 m/s2= (33 m/s - X)/30 S

Answers

Answer:

The starting velocity.

Explanation:

We must understand that this equation comes from the following equation of kinematics.

[tex]v_{f}=v_{o}+a*t[/tex]

where:

Vf = final velocity = 33 [m/s]

Vo = starting velocity [m/s]

a = acceleration = 3 [m/s²]

t = time = 30 [s]

So, these values can be assembly in the following way:

[tex]v_{f}=v_{o}+a*t\\a*t=v_{f}-v_{o}\\3=\frac{33-v_{o}}{30}[/tex]

if |v|= 11, |w|= 23, |v-w|= 30, find |v+w|​

Answers

Answer:

[tex]|v+w|=20[/tex]

Explanation:

We are given that

|v|=11

|w|=23

|v-w|=30

We have to find the value of |v+w|

|a-b|^2=(a+b)\cdot (a+b)=a^2+b^2-2|a||b|cos\theta

Using the formula

[tex](30)^2=(11)^2+(23)^2-2(11)(23)cos\theta[/tex]

[tex]900=121+529-506cos\theta[/tex]

[tex]900-121-529=-506cos\theta[/tex]

[tex]250=-506cos\theta[/tex]

[tex]cos\theta=-\frac{250}{506}[/tex]

[tex]|a+b|^2=|a|^2+|b|^2+2a\cdot bcos\theta[/tex]

Using the formula

[tex]|v+w|^2=(11)^2+(23)^2+2(11)(23)\times (-\frac{250}{506})[/tex]

[tex]|v+w|^2=400[/tex]

[tex]|v+w|^2=(20)^2[/tex]

[tex]|v+w|=20[/tex]

A taxi hurries with a constant speed of 60 miles per hour. How long will it take to travel a distance of 130 miles

Answers

Answer:

2.17 hrs

Explanation:

time = distance / velocity

We know that distance = 130 miles and velocity = 60 miles/h.

t = d / v

t = 130 miles / 60 miles/h

t = 2.17 hrs

It takes about 2.17 hours to travel a distance of 130 miles. Hope this helps, thank you !!

A particle with a charge of -4.3 μC and a mass of 4.4 x 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 80 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VA, then give the answer as a positive number. If VB is less than VA, then give the answer as a negative number.

Answers

Answer:

ΔV = - 3274 V

Explanation:

For this exercise we can use conservation of energy

starting point.

         Em₀ = U = q ΔV

final point

          Em_f = K = ½ m v²

energy is conserved

          Em₀ = Em_f

          q ΔV = ½ m v²

          ΔV = [tex]\frac{m \ v^2 }{q}[/tex]

let's calculate

          ΔV = [tex]\frac{4.4 \ 10^{-6} \ 80^2 }{ 2 \ 4.3 10^{-6} }[/tex]

          ΔV = 3274.4 1 V

since the charge q is negative, the potential at point B must be less than the potential at point A, so the answers

          ΔV = - 3274 V

The surface area of a postage

stamp is 0.00600 m^2, and the air

exerts 1.00 atm of pressure on it.

How much force does it exert on

the stamp?

(Hint: The standard unit for

pressure is Pa.)

(Unit = N)

Answers

Answer:

Force = 607.95 Newton

Explanation:

Given the following data;

Area = 0.00600 m^2

Pressure = 1 atm to Pascal = 101325 Pa

To find the force;

Pressure = Force/area

Force = pressure * area

Substituting into the equation, we have;

Force = 101325 * 0.00600

Force = 607.95 Newton.

Therefore, the amount of force exerted by the air on the stamp is 607.95 Newton.

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