A test with hypotheses H0:μ=100,Ha:μ>100, sample size 60, and assumed population standard deviation 8 will reject H0 when x¯>101.7. What is the power of this test against the alternative μ=102.5?
A. 0.5398
B. 0.4602
C. 0.2193
D. 0.7807

Answers

Answer 1

The probability is D. 0.7807. Therefore, the answer is D. 0.7807.

To calculate the power of the test, we need to determine the probability of rejecting the null hypothesis when the alternative hypothesis is true. In other words, we want to find P(reject H0 | Ha is true).

First, we need to calculate the critical value that corresponds to the level of significance of the test. Since the alternative hypothesis is one-tailed (Ha:μ>100), and the level of significance is not given, we'll assume a significance level of 0.05 (commonly used in hypothesis testing).

Using a standard normal distribution table or calculator, we find that the critical value for a one-tailed test at a 0.05 level of significance is 1.645.

Next, we need to calculate the standard error of the mean (SEM), which is equal to the population standard deviation divided by the square root of the sample size.

SEM = 8 / √60 = 1.0328

To find the test statistic (z-score) for the alternative hypothesis, we use the following formula:

z = (x¯ - μ) / SEM

z = (101.7 - 102.5) / 1.0328 = -0.775

The area to the right of this z-score under the standard normal distribution represents the probability of rejecting the null hypothesis when the alternative hypothesis is true.

Using a standard normal distribution table or calculator, we find this probability to be:

P(z > -0.775) = 0.7807

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Answer 2

The probability is D. 0.7807. Therefore, the answer is D. 0.7807.

How to calculate the value

Using a standard normal distribution table or calculator, we find that the critical value for a one-tailed test at a 0.05 level of significance is 1.645.

Next, we need to calculate the standard error of the mean (SEM), which is equal to the population standard deviation divided by the square root of the sample size.

= 8 / √60 = 1.0328

To find the test statistic (z-score) for the alternative hypothesis, we use the following formula:

z = (x - μ) / SEM

z = (101.7 - 102.5) / 1.0328 = -0.775

Using a standard normal distribution table or calculator, we find this probability to be:

P(z > -0.775) = 0.7807

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Step-by-step explanation:

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Step-by-step explanation:

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I’m so sorry I don’t know sorry for the inconvenience

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Step-by-step explanation:

only x+1 , x+3 COULD represent consecutive even integers

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Step-by-step explanation:

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a. What is the slope of the line containing the points?

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Answer:

Answer:

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Explanation:

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Answer:

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Step-by-step explanation:

The easiest way to do this is to convert all the fractions into minutes

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right  

Equality Properties

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Algebra I

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85 - 82 = .6h

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Step-by-step explanation:

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Answer:

1

Step-by-step explanation:

d=-4 , f = 3

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Answer:

1 is the answer

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Answer

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Step-by-step explanation:

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Answer:

C

Step-by-step explanation:

Remark

There are probably a couple of ways that you could do this. I'm going to pick the most obvious way.

Givens.

KN = 2.5

NO = 10

LM = 3

MP = x

Equation

NO/KN = PM / LM

Solution

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That looks like it should be the answer, and it almost is, but you are asked for LP.

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The bases of a trapezoid lie on the lines y=2X +7 and y= 2X -5. Write the equation that contains the midsegment of the trapezoid

Answers

Given:

The bases of a trapezoid lie on the lines

[tex]y=2x+7[/tex]

[tex]y=2x-5[/tex]

To find:

The equation that contains the midsegment of the trapezoid.

Solution:

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[tex]y=mx+b[/tex]

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[tex]m_1=2,b_1=7[/tex]

On comparing [tex]y=2x-5[/tex] with slope intercept form, we get

[tex]m_2=2,b_2=-5[/tex]

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[tex]m=m_1=m_2=2[/tex]

The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.

[tex]b=\dfrac{b_1+b_2}{2}[/tex]

[tex]b=\dfrac{7-5}{2}[/tex]

[tex]b=\dfrac{2}{2}[/tex]

[tex]b=1[/tex]

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[tex]y=2x+1[/tex]

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Answers

Answer:

Step-by-step explanation:

m:  y = -2x + 4

n:    y = x - 1

l:      y = 4

p:     x = -4

m: y=-2x+4

slope: 2

2/1=2

Its negative because the line is going down from left to right

y-intercept:

it crosses the y axis at (0,4)

n: y=x-1

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1/1=1

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it crosses the y axis at (0,-1)

l: y=4

slope: 0

A vertical line's slope is always 0

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it crosses the y axis at (0,4)

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To find the equation for a horizontal line, you need to find what x always is no matter what.

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