A train moves from rest to a speed of 22 m/s in 34.0 seconds. What is its acceleration?

The initial velocity of a car that accelerates to a speed of 55 m/s within the span of 8 seconds is 23m/s.

The initial velocity of a moving body can be calculated using the following formula:

a = v - u/t

Where;

According to this question, a car accelerates to a speed of 55 m/s within the span of 8 seconds. If its acceleration was 4 m/s², the initial velocity is calculated as follows:

4 = 55 - u/8

32 = 55 - u

u = 55 - 32

u = 23m/s

Therefore, the initial velocity of a car that accelerates to a speed of 55 m/s within the span of 8 seconds is 23m/s.

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if the distance between the objects is doubled the force is reduced by a factor of 4

Gravitational force is the force of attraction between objects in the universe.

f = G * m1 * m2 / r^2

f = gravitational force

G = gravitational constant

m1 = mass of object 1

m2 = mass of object 2

r = distance between the objects

From the formular, the gravitational force and the distance is an inverse relationship so increasing the distance by a factor results to reduction of the force by the square of the factor. hence doubling the distance which is distance mutiplied by 2 will lead to reduction of the force by 2^2 = 4

Therefore: The force decreases by a factor of 4.

hope it helps

Answer:

As the cars ascend the next hill, some kinetic energy is transformed back into potential energy. Then, when the cars descend this hill, potential energy is again changed to kinetic energy. This conversion between potential and kinetic energy continues throughout the ride.

Explanation:

hope it helps U

Answer:

Blue supergiants represent a slower burning phase in the death of a massive star. Due to core nuclear reactions being slightly slower, the star contracts and since very similar energy is coming from a much smaller area (photosphere) then the star's surface becomes much hotter.

Explanation:

I know this may not be the answer youre looking for, but hopefully this can help somehow!

When people are interested in changing their personalities, they are usually most interested in more neurotic less assertive.

Personality makes up an individual, they are the features or characteristics that forms an individual.

Each individual is made of distinctive character which makes one of different from other.

Therefore, when people are interested in changing their personalities, they are usually most interested in more neurotic less assertive

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Answer:

let alpha be y,

1/2=y(x-6)^(-b)

1/2=y(1/x-6)

1/2=y/x-6

x-6=2y

x-6/2=y

(1/2)x-(6/2)=y

y=(1/2)x-3

As it mentioned

So

power is 100W

Now

Current be I

[tex]\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{100}{120}=\dfrac{5}{6}=0.8A[/tex]

Answer:

1/R = 1/R1 + 1/R2 + 1/R3

1/1 + 1/2 + 1/4 = 1 + .5 + .25 = 1.75

1/1.75 = .572

multiplying this by 100 gives us

R = 57.2 ohms

The smallest resistor (100 ohms) will draw the most current

(One can also use R = R1 R2 R3 / (R1 R2 + R1 R3 + R2 R3)

Hi there!

We can use the following equation to solve for equivalent resistance:

[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}[/tex]

We can plug in the givens and solve.

[tex]\frac{1}{R_T} = \frac{1}{100} + \frac{1}{200} + \frac{1}{400} \\\\\frac{1}{R_T} = 0.175\\\\R_T = \frac{1}{0.175} = \boxed{57.143 \Omega}[/tex]

The resistor that would draw the most current is the 100 Ohm resistor because current chooses the path of LEAST RESISTANCE. This can also be proved mathematically with the following:

For resistors in parallel, the POTENTIAL DIFFERENCE (VOLTAGE) is the same.

Since I = V/R, a smaller 'R' means a larger 'I'. Thus, the smallest resistor would have the greatest current through it.

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Heat capacity of body 1 :

[tex]\qquad \sf  \dashrightarrow \:m_1s_1[/tex]

Heat capacity of body 2 :

[tex]\qquad \sf  \dashrightarrow \:m_2s_2[/tex]

it's given that, the the head capacities of both the objects are equal. I.e

[tex]\qquad \sf  \dashrightarrow \:m_1s_1 = m_2s_2[/tex]

[tex]\qquad \sf  \dashrightarrow \:m_1 = \dfrac{m_2s_2}{s_1} [/tex]

Now, consider specific heat of composite body be s'

According to given relation :

[tex]\qquad \sf  \dashrightarrow \:(m_1 + m_2) s' = m_1s_1 + m_2s_2[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_1s_1 + m_2s_2}{m_1 + m_2}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_2s_2+ m_2s_2}{ \frac{m_2s_2}{s_1} + m_2 }[/tex]

[ since, [tex] m_2s_2 = m_1s_1 [/tex] ]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2m_2s_2}{ m_2(\frac{s_2}{s_1} + 1)}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 \cancel{m_2}s_2}{ \cancel{m_2}(\frac{s_2}{s_1} + 1)}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 s_2}{ (\frac{s_2 + s_1}{s_1} )}[/tex]

[tex]\qquad \sf  \dashrightarrow \: s' = \dfrac{2s_1s_2}{s_1 + s_2} [/tex]

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Answer:                                                                                    

Explanation:

Answer: 20 m/s

Explanation:

Acceleration = change in velocity / time → 10 m/s^2 = final velocity - 0 (original velocity) / 2s → final velocity = 20 m/s

Muscles such as quadriceps, hamstrings, the calf muscles and the hip adductors get stronger by walking.

The quadriceps, hamstrings, the calf muscles and the hip adductors are the muscles which get stronger by doing walking because impact is produced on these muscles while walking. Walking is a good exercise which have many health benefits.

So we can conclude that muscles such as quadriceps, hamstrings, the calf muscles and the hip adductors get stronger by walking.

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Answer:

introversion is the correct answer

Explanation:

God bless! Have a great day!

Answer:

velocity

Explanation:

because the si unit of mass is kg, velocity is m/s, acceleration is m/S2 , moment is kgm2/s . so 5 is given as velocity.

Answer:

Fundamental quantities are quantities that were created to measure a object/substance which are the basis on which derived quantities are formed, where as derived quantities are created by extracting variables from the fundamental quantities.

From Newton’s Third Law, the Law of Conservation of Momentum for an elastic collision is derived as m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.

This law states that action and reaction are equal and opposite. That is the force applied to an object is equal to the reaction received by the object.

F₁₂ = -F₂₁

m₁a₁ = -m₂a₂

m₁v₁/t = -m₂v₂/t

m₁v₁ = -m₂v₂

m₁v₁ + m₂v₂ = 0

The sum of the initial momentum must be equal to sum of final momentum.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Thus, from Newton’s Third Law, the Law of Conservation of Momentum for an elastic collision is derived as m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.

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The resulting charge in sphere A from the two given different charges is determined as +2 μC.

The resulting charge of the two spheres is determined by suming the two individual charges together as shown below;

Resulting charge = +6 μC - 2 μC

Resulting charge = +4 μC

The resulting charge will be distributed uniformly between the two spheres and charge in sphere A and B will be equal.

Charge in sphere A = charge in sphere B = ¹/₂ x +4 μC = + 2 μC

Thus, the resulting charge in sphere A from the two given different charges is determined as +2 μC.

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Answer:

R1 + R2 = R = 12 for resistors in series - so R1 = R2 if they are identical

2 R1 = 12         and R1 = R2 = 6 ohms

1 / R = 1 / R1 + 1 / R2     for resistors in parallel

R = R1 * R2 / (R1 + R2) = 6 * 6 / (6 + 6) = 3

The equivalent resistance would be 3 ohms if connected in parallel

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The volume that the gas will occupy based on the temperature given will be 0.80 liters.

From the information, it was stated that the figure shows a pV diagram for 4.00×10−3 mole of ideal H2 gas and that the temperature of the gas does not change during segment bc.

Therefore, the volume will be:

= (0.20) × (2.0/0.50)

= 0.20 × 4

= 0.80

In conclusion, the volume is 0.80 liters.

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Answer:

load

a generator, a light bulb (load) and a closed switch

Explanation:

as explained in the other question, the fan is using generated electric energy to create mechanical movement. as such it is a load on the grid or circuit or net.

and electric power can only flow, if there is a closed (uninterupted) circuit from the power source to a load and back.

any open switch is an interruption of the circuit.

a buzzer is a kind of switch. it closes the circuit (and puts a load on) only when somebody presses it.

by the way, a closed circuit without a load will "destroy" (short circuit) the power source or at least the wires (burn through).

For a tire on a car is rolling smoothly and It's center of mass is moving at 18 m/s, the speed of the top of the tire is mathematically given as

Vtop=36m/s

Generally, the equation for the relationship between the top and the core is mathematically given as

Vtop=2*(vcore)

Threrefore

Vtop=2*18

Vtop=36m/s

In conclusion, the speed of the top

Vtop=36m/s

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Answer:

oh what do you believe this one

Answer:

Your answer is attached above

Hope it helps

TC

have a great time

By using the right-hand rule for magnetic force to determine the charge on the moving particle, it's a negative charge.

It should be noted that the magnetic force simply means the attraction or repulsion that arises between electrically charged particles.

The right-hand rule for magnetic force states that to determine the direction of the magnetic force, one should point the right thumb in the direction of the velocity.

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Answer:

Particle q1 has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10–3 N, what is the strength of the magnetic field?

✔ 2.8

T

In the same magnetic field, particle q2 has a charge of 42.0 μC and a velocity of 1.21 × 103 m/s. What is the magnitude of the magnetic force exerted on particle 2?

✔ 0.12

N

Explanation:

Hope this helps

Answer:

Explanation:

The hot exhaust from a rocket travels in one direction, and the rocket travels in the opposite direction. This is an example of?

A. Equal and opposite forces.

B. Friction.

C. Balanced forces.

D. Inertia.

Answer:

1.2 is the correct answer due to the graph

Explanation:

math teacher

Answer:

2.4*10^-17 J

Explanation:

E = V/d = 300 V / 3*10^-3 m = 1.0*10^5 V/m

Voltage at midpoint = E*d = 1.0*10^5 V/m * 1.5*10^-3 m = 150 V

ΔV = 300 V - 150 V = 150 V

Charge of a proton = 1.6*10^-16 C

U = qΔV = (1.6*10^-16 C)(150V) = 2.4*10^-17 J

The electric field strength inside the capacitor is 100,000 V/m, the Potential difference at the midpoint is 150V, and the potential energy of a proton at the midpoint of the capacitor is  2.403 x 10⁻¹⁷J.

A capacitor is an electronic device that stores electrical energy in an electric field between two conducting plates separated by a dielectric material. When a voltage difference is applied across the plates, a charge is stored on each plate, creating an electric field between the plates. The capacitor can then release this stored electrical energy when needed.

The energy stored in a capacitor is given by the formula:

U = [tex]\frac{1}{2}[/tex]CV²

Where

U =the energy stored in the capacitor,

C = the capacitance of the capacitor,

V =the voltage difference across the plates.

Capacitance is a measure of the ability of a capacitor to store charge and is given by the formula:

C = εA/d

Where C = the capacitance,

ε = the permittivity of the dielectric material between the plates,

A = the area of the plates,

d =the distance between the plates.

Here in the question

To calculate the electric field strength inside the capacitor, we can use the formula:

E = V/d

Where E = the electric field strength,

V =the voltage difference between the plates,

d =the distance between the plates.

In this case, the distance between the plates is d=3mm =0.003m,

the voltage difference is between 0V to 300V.

Now, the electric field strength inside the capacitor is:

E = V/d = 300V/0.003m = 100,000 V/m

To calculate the potential energy of a proton at the midpoint of the capacitor, we can use the formula:

U = qV

Where U = the potential energy,

q =the charge of the particle,

V =the voltage difference between the plates.

In this case, we need to know the charge of the proton.

The charge of a proton = +1.602 x 10⁻¹⁹ C.

At the midpoint of the capacitor, the proton will experience a potential difference of 150V (half of the 300V voltage difference).

Now, the potential energy of the proton at the midpoint of the capacitor is:

U = qV = (1.602 x 10⁻¹⁹ C) x (150V) = 2.403 x 10⁻¹⁷J

Therefore, the electric field strength is 100,000 V/m and the potential energy of a proton at the midpoint of the capacitor is 2.403 x 10⁻¹⁷J.

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#SPJ2

Answer:

wood lighters gasoline hope it helps

Explanation: