The number of boxes with 20kg = 15
The number of boxes with 25 kg = 35.
How to estimate the value of X and Y?
To estimate the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to estimate the result.
Total weight of all boxes = 1175kg
Total number of boxes = 50
X + Y = 50........................(1)
20X + 25Y = 1175 .............(2)
(1) [tex]\times[/tex] 20
20 (X + Y = 50)
20X + 20Y = 1000 .............(3)
Subtracting (3) from (2), we get
20X + 25Y = 1175 -
20X + 20Y = 1000
--------------------
5Y = 175
Y = 175/5
Y = 35
Substitute the value of y in (1), then we get
X + Y = 50
X + 35 = 50
X = 50 - 35
X = 15
The value of X = 15 and Y = 35
Number of boxes with 20kg = 15
Number of boxes with 25 kg = 35.
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You randomly select an integer from 0 to 9 (inclusively) and then randomly select and integer from 0 to 7 what is the probability of selecting a 2 both times
Reason:
Set A = {0,1,2,3,4,5,6,7,8,9}
Set B = {0,1,2,3,4,5,6,7}
The probability of getting a "2" from set A is 1/10 since there is one copy of "2" that we want out of ten values total.
The probability of getting a "2" from set B is 1/8 for similar reasoning. This time there are eight numbers in this set.
Multiply those fractions mentioned (1/10)*(1/8) = 1/80
This fraction converts to the exact decimal value of 0.0125, meaning there's exactly a 1.25% chance of getting "2" twice in a row.
I need answers please and thank you!
Arnez Company’s annual accounting period ends on December 31. The following information concerns the adjusting entries to be recorded as of that date. The Office Supplies account started the year with a $3,850 balance. During the year, the company purchased supplies for $15,901, which was added to the Office Supplies account. The inventory of supplies available at December 31 totaled $3,388. The Prepaid Insurance account had a $27,744 debit balance at December 31 before adjusting for the costs of any expired coverage for the year. An analysis of prepaid insurance shows that $20,004 of unexpired insurance coverage remains at year-end. The company has 15 employees, who earn a total of $1,800 in salaries each working day. They are paid each Monday for their work in the five-day workweek ending on the previous Friday. Assume that December 31 is a Tuesday, and all 15 employees worked the first two days of that week. Because New Year’s Day is a paid holiday, they will be paid salaries for five full days on Monday, January 6 of next year. The company purchased a building at the beginning of this year. It cost $725,000 and is expected to have a $45,000 salvage value at the end of its predicted 25-year life. Annual depreciation is $27,200. Since the company is not large enough to occupy the entire building it owns, it rented space to a tenant at $3,400 per month, starting on November 1. The rent was paid on time on November 1, and the amount received was credited to Rent Revenue. However, the tenant has not paid the December rent. The company has worked out an agreement with the tenant, who has promised to pay both December and January rent in full on January 31. On November 1, the company rented space to another tenant for $3,080 per month. The tenant paid five months' rent in advance on that date. The payment was recorded with a credit to the Unearned Revenue account. Assume no other adjusting entries are made during the year. Required: 1. Use the information to prepare adjusting entries as of December 31. 2. Prepare journal entries to record the first subsequent cash transaction in January of the next year for parts c and e.
1. The preparation of the adjusting entries as of December 31 for Arnez Company is as follows:
Adjusting Journal Entries:1. Debit Office Supplies Expenses $16,363
Credit Office Supplies $16.363
2. Debit Insurance Expenses $7,740
Credit Prepaid Insurance $7,740
3. Debit Salaries Expenses $54,000
Credit Salaries Payable $54,000
4. Debit Rent Receivable $3,400
Credit Rent Revenue $3,400
5. Debit Unearned Rent Revenue $6,160
Credit Rent Revenue $6,160
2. The preparation of the journal entries to record the first subsequent cash transactions in January of the next year for Arnez Company is as follows:
Journal Entries:Debit Salaries Payable $54,000
Credit Cash $54,000
Debit Cash $6,800
Credit Rent Receivable $3,400
Credit Rent Revenue $3,400
Adjusting Transaction Analysis:1. Office Supplies Expenses $16,363 Office Supplies $16.363 ($3,850 + $15,901 - $3,388)
2. Insurance Expenses $7,740 Prepaid Insurance $7,740 ($27,744 - $20,004)
3. Salaries Expenses $54,000 Salaries Payable $54,000 ($1,800 x 15 x 2)
4. Rent Receivable $3,400 Rent Revenue $3,400
5. Unearned Rent Revenue $6,160 Rent Revenue $6,160 ($3,080 x 2)
January Transactions:Salaries Payable $54,000 Cash $54,000
Cash $6,800 Rent Receivable $3,400 Rent Revenue $3,400
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Q19. When a resistor is placed across 230M supply (de) the
current is 12A. What is the value of resistor that must
De connected in parallel to increase the load current
to 16a
The value of the resistor that must be connected in parallel is 57.47 ohms
How to determine the resistor connected across the 230 V supplyVoltage (V) = 230 VCurrent (I) = 12 AResistor 1 (R₁) =?V = IR
230 = 12 × R₁
Divide both sides by 12
R₁ = 230 / 12
R₁ = 19.17 ohms
How to determine the total resistanceVoltage (V) = 230 VCurrent (I) = 16 ATotal resistance (Rₜ) =?V = IR
230 = 16 × Rₜ
Divide both sides by 12
Rₜ = 230 / 16
Rₜ = 14.375 ohms
How to determine the resistor connected in paralleResistor 1 (R₁) = 19.17 ohms Total resistance (Rₜ) = 14.375 ohmsResistor 2 (R₂) = ?1/Rₜ = 1/R₁ + 1/R₂
Collect like terms
1/R₂ = 1/Rₜ - 1/R₁
R₂ = (Rₜ × R₁) / (R₁ - Rₜ)
R₂ = (14.375 × 19.17) / (19.17 - 14.375)
R₂ = 57.47 ohms
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Determine whether the graph is bipartite.
The graph isn't bipartite because it isn't possible to assign either Blue or Red to each vertex, without having connected vertices with the same color.
What is the bipartite graph theorem?The bipartite graph theorem states that a graph is considered to be bipartite only if it's possible to assign either Blue or Red to all the vertex, such that no two (2) connected vertices would have the same color.
By critically observing the image after assigning the colors to each vertices (see attachment), we can logically deduce that the graph isn't bipartite because it isn't possible to assign either Blue or Red to all the vertex, without having connected vertices with the same color.
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If a cylinder has a volume of 300 m3 and a radius of 5 m, what is its height (in meters)? (Round your answer to two decimal places.)
also second question:
The diameter is 6 feet 6 inches. The height is 12 feet 3 inches. Determine the surface area (in square feet) and volume (in cubic feet) of the following. (Round your answers to one decimal place.)
The height of the cylinder is 3.82 m
2. The surface area is 316.5 ft²
The volume is 406.5 ft³
Calculating volume of a cylinderThe volume of a cylinder is given by the formula,
V = πr²h
Where V is the volume
r is the radius
and h is the height
From the given information,
V = 300 m³
r = 5 m
h = ?
Putting the parameters into the formula, we get
300 = π × 5² × h
300 = π × 25× h
∴ h = 300/25π
h = 3.82 m
Hence, the height of the cylinder is 3.82 m
2.
Diameter = 6 feet 6 inches = 6.5 feet
∴ Radius = 3.25 feet
Height = 12 feet 3 inches = 12.25 feet
Surface area of a cylinder is given by
Surface area = 2πr(r + h)
Where r is the radius
and h is the height
Surface area = 2π×3.25(3.25 + 12.25)
Surface area = 316.5 ft²
For the volume
V = πr²h
V = π × 3.25² × 12.25
V = 406.5 ft³
Hence, the volume is 406.5 ft³
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Which of the following is NOT a criterion for making a decision in a hypothesis test?
Choose the correct answer below.
OA. If P-values a, the decision is to reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.
OB. If the test statistic falls within the critical region, the decision is to reject the null hypothesis.
OC. If a confidence interval does not include a claimed value of a population parameter, the decision is to reject
the Inull hypothesis.
OD. If the P-value is less than 0.05, the decision is to reject the null hypothesis. Otherwise, we fail to reject the null
hypothesis.
If the p-value less than 0.05, the decision is to reject the Null hypothesis.
What is hypothesis testing?Hypothesis testing is statistical reasoning using information from a sample to draw conclusions about a population parameter or population probability distribution. The parameter or distribution is initially bestguessed. Because it is the underlying assumption, the null hypothesis is often referred to as H0.For instance, you might explore and find that a specific drug effectively manages headaches. But nobody will believe what you find if you can't do that experiment again.A hypothesis seeks to provide an answer to a question. We will be forced to think about the results an experiment should try to achieve by a formulated hypothesis.The independent variable is the first variable. Results with seriousness.The following should NOT be used as a decision-making standard in a hypothesis test.
If the p-value less than 0.05, the decision is to reject the Null hypothesis.
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Will give brainliest
Answer:
Step-by-step explanation:
will give brainiest wrrwrwvrwvr
Complete the left-hand column of the table below following the steps indicated in the right-hand column to show that "sin a sin b = 1/2[cos(a-b)-cos(a+b)]" is an identity. Use the definitions of sum and difference formulas for cosine.
The equations which completes the left-hand column of the table are;
[tex] \frac{1}{2} \cdot \left(cos(a - b) - cos(a + b) \right)[/tex]
cos(a - b) - cos(a + b) = (cos(a)•cos(b) + sin(a)•sin(b)) - (cos(a)•cos(b) - sin(a)•sin(b))sin(a)•sin(b) = (1/2)•(cos(a - b) - cos(a + b))Which equations and identities complete the left-hand column of the table?The given expression on the right is written as follows;
First row;
[tex] \frac{1}{2} \cdot \left(cos(a - b) - cos(a + b) \right)[/tex]
The definition of the sum and difference of cosine are;
cos(a - b) = cos(a)•cos(b) + sin(a)•sin(b)
cos(a + b) = cos(a)•cos(b) - sin(a)•sin(b)
Therefore;
Second row;
cos(a - b) - cos(a + b) = (cos(a)•cos(b) + sin(a)•sin(b)) - (cos(a)•cos(b) - sin(a)•sin(b))cos(a - b) - cos(a + b) = 2•sin(a)•sin(b)
Which gives;
[tex] sin(a) \cdot sin(b) = \frac{1}{2} \cdot \left(cos(a - b) - cos(a + b) \right)[/tex]
Third row;
sin(a)•sin(b) = (1/2)•(cos(a - b) - cos(a + b))Learn more about trigonometric functions here:
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the sum of the measures of three angles is 200. these measures are in the ration 3:5:12. Find the measure of the three angles.
Answer:
30, 50, and 120
Step-by-step explanation:
3/20 × 200 = 30
5/20 × 200 = 50
12/20 × 200 = 120
The measures of three angles that are in ratio 3:5:12 are 30 degrees,50 degrees and 120 degrees.
Given that:
The sum of the measures of three angles = 200.
Let the ratios be x.
The ratio of first angle be 3x
The ratio of second angle be 5x
The ratio of third angle be 12x
According to the question,
3x+ 5x+ 12x = 200
20x = 200
Divide both sides by x
x = 200/20
x = 10
The ratio of first angle be 3x = 3(10) = 30 degrees
The ratio of second angle be 5x = 5(10) = 50 degrees
The ratio of third angle be 12x = 12(10) = 120 degrees
The measures of three angles that are in ratio 3:5:12 are 30 degrees,50 degrees and 120 degrees.
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Solve for x in sin xtan x + tan x – 2sin x + cos x = 0 for 0 ≤ x ≤2π rads.
The value of x = 4.71, 0.41, or 5.89 radian value
Specification:
sinxtanx + tanx -2sinx + cosx = 0
tanx = sinx / cosx
sinx (sinx / cosx) + sinx / cosx -2sinx + cosx = Multiply 0
cosx to remove the fraction
sin ^ 2 (x) + sinx -2sinxcosx + cos ^ 2 (x) = 0
sin ^ 2 (x) + cos ^ Replace with 1. 2 (x) = 1
sinx -2sinxcosx + 1 = 0
sinx (1-2cosx) = -1
1-2cosx = -1 / sinx
-2cosx = -1 / sinx -1
2cosx = 1 / sinx + 1
cosx = 1 / 2sinx + 1/2
sqr (1-sin ^ 2 (x)) = 1 / 2sinx + 1/2
Squared on both sides
1-sin ^ 2 (x) = 1 / 4sin ^ 2 (x) + 1 / 2sinx + 1/4
4sin ^ 2 (x) Multiply
4sin ^ 2 (x) -4sin ^ 4 (x) = 1 + 2sinx + sin ^ 2 (X)
4sin ^ 4 (x) -3sin ^ 2 (x) + 2sinx +1 = 0
y = sinx
4y ^ 4 -3y ^ 2 + 2y + 1 = 0
sinx = y = -1 or -0.3478
x = 270, 180-22.61 or -22.61 degrees
x = 270, 157.39 or 337 .39 degrees
or
x = 3pi / 2, 0.13pi or 1.87pi radians
or
x = 4.71, 0.41 Or 5.89 radians
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Compute the exact value of the height h of the square-based straight pyramid, given that the base is a square with sides 34 feet long, and all other edges are 50 feet long.
Answer:
31√2 feet
Step-by-step explanation:
The height can be found using the Pythagorean theorem. The height of the pyramid will be the height of the right triangle whose sides are half the diagonal of the square base, the distance from the base to the peak, and the edge from the peak back to the corner of the base.
SetupLet h represent the height of the pyramid. The diagonal of the square base will be √2 times the side of the base. So, half the diagonal will be 17√2 ft. The Pythagorean theorem tells us ...
h² +(17√2)² = 50²
SolutionSubtracting the constant on the left gives ...
h² = 2500 -578 = 1992
h = √1992 = 31√2
The height of the square pyramid is exactly 31√2 feet.
__
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I need some help on this question
Using slopes, the table that could represent Relationship B is the second table.
What is the slope of a relationship?The slope of a relationship is given by the change in y divided by the change in x.
For relationship A, we have points (2,3) and (4,6), hence the slope is:
mA = (6 - 3)/(4 - 2) = 3/2 = 1.5.
Then, the slopes in the table are given as follows:
m = (8.4 - 6.3)/(4 - 3) = 2.1 > mA, hence the first table cannot be representation B.m = (4.5 - 2.25)/(6 - 3) = 0.75 < mA, hence the second table could represent Relationship B.m = (7.2 - 5.4)/(4 - 3) = 1.8 > mA, hence the third table cannot be representation B.m = (9.6 - 4.8)/(6 - 3) = 1.6 > mA, hence the fourth table cannot be representation B.More can be learned about slopes at https://brainly.com/question/24674549
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Which of the following has the least steep graph?
Robin can make 8 puppets with the material she already has. For each additional sheet of felt she buys, she can make 5 more puppets. What is an equation that shows how the total number of puppets she can make, y, depends on the number of sheets of felt she buys?
In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 4.8 minutes. It is assumed that this is a normally distributed variable. Find the probability that randomly selected individual would spent between 35 and 48 minutes on the treadmill.
Using the normal distribution, there is a 0.8155 = 81.55% probability that a randomly selected individual would spent between 35 and 48 minutes on the treadmill.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The mean and the standard deviation for this problem are given, respectively, by:
[tex]\mu = 42.5, \sigma = 4.8[/tex]
The probability that a randomly selected individual would spent between 35 and 48 minutes on the treadmill is the p-value of Z when X = 48 subtracted by the p-value of Z when X = 35, hence:
X = 48:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{48 - 42.5}{4.8}[/tex]
Z = 1.15
Z = 1.15 has a p-value of 0.8749.
X = 35:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{35 - 42.5}{4.8}[/tex]
Z = -1.56
Z = -1.56 has a p-value of 0.0594.
0.8749 - 0.0594 = 0.8155.
0.8155 = 81.55% probability that a randomly selected individual would spent between 35 and 48 minutes on the treadmill.
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ienes una cuerda que mide 90 cm. Hay que partir la cuerda en 2 segmentos (A y B). La cuerda B debe ser 5 veces más grande que la cuerda A. ¿Cuánto mide la cuerda B?
Basada en el concepto de relación, tenemos que la cuerda B tiene una longitud de 75 centímetros y la cuerda A es de 15 centímetros.
¿Cuánto mide cada segmento de cuerda?
En este problema debemos hallar dos segmentos de cuerda que cumple la siguiente relación, basada en el enunciado citado:
5 = (90 cm - x)/x (1)
5 · x = 90 cm - x
6 · x = 90 cm
x = 15 cm
Basada en el concepto de relación, tenemos que la cuerda B tiene una longitud de 75 centímetros y la cuerda A es de 15 centímetros.
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A ternary string of length n is a sequence of n digits in which only 0, 1, or 2 appear.
For example, (0,1,0,2) and (1,1,2,2) are ternary strings of length 4 and can be seen as: 0102 and 1122.
How many ternary strings of length 2n are there in which the zeros appear only in odd positions?
dunnodunnodunnodunnodunnodunnodunnodunnodunnodunnodunnodunnodunnodunno
dunno
-11r is greater than or less than -20
What is the missing exponent in the equation 3 TO THE SEVENTH POWER EQUALS 27
Answer: 3 to the 3rd power equals 27
Step-by-step explanation: Because a exponent is the number times itself 3x3 equals 9 that's already 2 then 9x3 equals 27 so anything above is to much
Country A has an exponential growth rate of 3.8% per year. The population is currently ,000, and the land area of Country A is 35,000,000,000 square yards. Assuming this growth rate continues and is exponential, after how long will there be one person for every square yard of land?
The number of years it would it take for there to be one person for every square yard is 93.6 years.
How many years would it take for there to be one person for every square yard?When there is one person for every square yard, it means that the population and land area are equal in value.
Number of years = (In FV / PV) / r
FV = future population PV = present population r = rate of growth(In 35 billion / 1 billion) / 0.038 = 93.6 years
Here is the complete question:
Country A has an exponential growth rate of 3.8% per year. The population is currently 1,000,000 ,000 and the land area of Country A is 35,000,000,000 square yards. Assuming this growth rate continues and is exponential, after how long will there be one person for every square yard of land?
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Ayayai inc. Has a customer loyalty program that rewards a customer with 1 customer loyalty point for every $10 of purchase. Each point is redeemable for $3 discount on any future purchases . On july 2, 2020 customers purchase pro for $370000 (with a cost of $210900 )and earn 37000 points redeemable for future purchases. Ayayai is expected 31500 points to be redeemed. Ayayai estimates a standalone selling price for $2.50 per point (or $92500 total ) on the basis of the likelihood of redemption . The points provide a material right to customers that they would not receive without entering into a contract. As a result. Ayayai concludes that the points are separate performance obligation. Determine the transaction price for the product and the customer loyalty points. Product purchases, loyalty points, total transaction price
The transaction price for Ayayai's product and the customer loyalty points are $92500 and 37000 points respectively.
How to determine the transaction price?Based on the information provided about Ayayai inc., the transaction price for their product and the customer loyalty points would be allocated as follows:
SSP PA TTP AA____
Product purchases $370,000 80% $370,000 $296,000
Loyalty points $92,500* 20% $370,000 $74,000__
$462,500 $370,000
*37,000 × 2.50 = $92,500
Note:
SSP means Standalone selling prices.PA means Percent allocated.TTP means Total transaction price.AA means Allocated amounts.Read more on transaction price here: https://brainly.com/question/15874481
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The function y=f(x is graphed below. What is the average rate of change of the function f(x)on the interval 0≤x≤5?
[tex]m = \frac{f(5) - f(0)}{5 - 0} [/tex]
[tex]m = \frac{ - 10 - 10}{5} = \frac{ - 20}{5} = - 4[/tex]
Step-by-step explanation:
the average rate of change is
(f(high interval end) - f(low interval end))/(high interval end - low interval end)
in our case here
(f(5) - f(0)) / (5 - 0)
(-10 - 10) / 5 = -20/5 = -4
Deondra has 57 m of fencing to build a three-sided fence around a rectangular plot of
land that sits on a riverbank. (The fourth side of the enclosure would be the river.)
The area of the land is 340 square meters. List each set of possible dimensions
(length and width) of the field.
(L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters. This can be obtained by forming quadratic equation for the data.
Calculate the set of possible dimensions (length and width) of the field:
Let length be L and width be W.
Given that,
three sided fence has a length of 57m,
⇒ 2W + L = 57 m ⇒ L = 57 - 2W
the area of the land is 340 square meters
length × width = 340 ⇒ L × W = 340
(57 - 2W)W = 340
57W - 2W² = 340
2W² - 57W + 340 = 0
Solve for W using quadratic formula,
a = 2, b = -57, c = 340
W = (-b±√b²-4ac)/2a
= (57±√3249-2720)/4
= (57±√529)/4
= (57±23)/4
W = 20 m and W = 8.5 m
For W=20, L=57-2(20) = 17
For W=8.5, L=57-2(8.5) = 40
Hence (L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters.
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Which graph represents the function f(x) =3(2)*?
I assume you meant [tex]f(x)=3(2)^x[/tex].
divide 7.39 divide 0.72 rounded quotient of the nearest hundredth
Answer:
10.26 I believe you wanted me to divide 7.39/0.72. If so, you get 10.2638 that rounds to 10.26
Step-by-step explanation:
Can u give me brainliest please
The value of the expression 7.39 ÷ 0.72 is 10.26 to the nearest hundredths.
We have,
Expression:
7.39 ÷ 0.72
Now,
The expression can be written as,
= 7.39 / 0.72 ______(1)
Simplify the numerator and denominator.
Numerator = 7.39 = 739/100 _____(2)
Denominator = 0.72 = 72/100 ______(3)
Now,
From (1), (2), and (3).
7.39 / 0.72
= (739/100) / (72/100)
= 739/100 x 100/72
100 is the common factor so it gets canceled.
= 739/72
= 10.2638888.....
Rounding to the nearest hundredths.
= 10.26
Thus.
The value of the expression 7.39 ÷ 0.72 is 10.26 to the nearest hundredths.
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slove each problem include a diagram. a. A 6m long wheelchair ramp makes an angle of 15 with the ground. How high abouve the ground does the top end of the ramp reach. b.two treees are 120m apart. From the point halfway between them, then angle of the elevation to the top of the trees is 36 and 52. how much taller is one tree than the other.
The wheelchair ramp must have a height of approximately 1.553 meters. One tree is approximately 310.309 meters taller than the other one.
How to determine measures with trigonometric functions
In this problem we have two cases in which geometric diagrams and trigonometric functions are utilized to determine side lengths. Based on all informations presented in the images attached below, we proceed to find the side lengths:
Case A
h = (6 m) · sin 15°
h ≈ 1.553 m
Case B
Δh = 60 m /cos 36° - 60 m /cos 52°
Δh ≈ 310.309 m
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a weather balloon is released and reaches a maximum altitude of 5000 meters.A week later, the balloon is recovered at 3750 metwrs. What was the change in altitude between the maximum height and the height at which the balloon was recovered
The change in altitude between the maximum height and the height at which the balloon was recovered is 1300 meters
How to determine the changeIt is important to note that the maximum height is the peak altitude the balloon reached
To find the difference, we use the formula
Change = Maximum height - recovery height
Maximum height = 5000 meters
Recovery height = 3700 meters
Substitute the values
Change = 5000 - 3700
Change = 1300 meters
Thus, the change in altitude between the maximum height and the height at which the balloon was recovered is 1300 meters
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articipation Activity #6
This is similar to Try It #11 in the OpenStax text.
A satellite is rotating around Earth at 0.2 radians per hour at an altitude of 252 km above Earth. If the radius of Earth is 6,378 kilometers, find the linear speed of the satellite in kilometers per hour.
Enter the exact answer.
The linear speed of the satellite is
Number
kilometers per hour.
The linear speed based on the information is 1326 km/h.
How to calculate the speed?The radius will be:
= 6378 + 252
= 6630 km
The angular speed is 0.2. The linear speed will be:
= 6630 × 0.2
= 1326 km/h.
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Se dispone de 800 000 para invertir. Una cuenta paga el 18% de interés anual, y otra paga el 21%. ¿Cuánto debe invertirse en cada cuenta para ganar 150 000 en intereses en un año?
Se debe depositar $ 600 000 en la cuenta con 18 % de interés anual y $ 200 000 en la cuenta con 21 % de interés anual para recibir $ 150 000 en intereses.
¿Cuánto se debe invertir en cada cuenta para alcanzar las ganancias deseadas en un período dado?
En este problema tenemos un depósito repartido en dos cuentas, que adquiere ganancias de manera continua en el tiempo. En consecuencia, tenemos por interés compuesto la siguiente ecuación a resolver:
x · (18/100) + (800 000 - x) · (21/100) = 150 000
168 000 - (3/100) · x = 150 000
(3/100) · x = 18 000
x = 600 000
Se debe depositar $ 600 000 en la cuenta con 18 % de interés anual y $ 200 000 en la cuenta con 21 % de interés anual para recibir $ 150 000 en intereses.
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