Accumulation Functions and FTC 1: Problem 6 (8 points) The curve C is the graph of y = Som t2 -3t+6 dt. Determine x-interval(s) on which the curve is concave downward. C is concave downward on: ___

The matrix A will be singular when its determinant is equal to zero. To determine the value(s) of λ for which A is singular, we need to calculate the determinant of A and find the values of λ that make the determinant zero.

The determinant of a matrix can be found by applying the rule of expansion along a row or column. In this case, we can use the first column to calculate the determinant:

det(A) = 1 * (1 * 4 - λ * 0) - 0 - (5 * (1 * 0 - λ * λ))

= 1 * (4 - 0) - 0 - (5 * (0 - λ^2))

= 4 - 5λ^2.

To make the determinant equal to zero, we solve the equation 4 - 5λ^2 = 0. Rearranging the equation, we have 5λ^2 = 4. Dividing both sides by 5, we get λ^2 = 4/5.

Taking the square root of both sides, we find λ = ±(2√5)/5. Therefore, the value(s) of λ for which the matrix A will be singular are λ = ±(2√5)/5.

In conclusion, the answer is f. none of the above, as none of the given options match the correct value(s) of λ for which the matrix A is singular

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True, Wn is bipartite for n ≥ 3 because we need to partition its vertices into two disjoint sets, such that no two vertices in the same set are adjacent.

To show that Wn is bipartite, we need to partition its vertices into two disjoint sets, such that no two vertices in the same set are adjacent.

Step 1: Consider a wheel Wn, where n is the number of vertices, and n ≥ 3.

Step 2: The wheel Wn is formed by adding an additional vertex, called the hub, to a cycle Cn.

Step 3: Divide the vertices into two sets:
- Set A: The hub vertex and every other vertex of the cycle Cn.
- Set B: The remaining vertices of the cycle Cn.

Step 4: Observe that no two vertices in Set A are adjacent, as the hub is only connected to the vertices in the cycle, and the vertices from the cycle in Set A are separated by vertices from Set B. Similarly, no two vertices in Set B are adjacent since they are separated by vertices from Set A in the cycle.

Step 5: Since the vertices can be divided into two sets with no adjacent vertices within each set, we can conclude that Wn is bipartite for n ≥ 3.

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Answer: Part A: Square Part B: 4.5 Part C: The reason why the shape of the cross-section is because if split a rectangle in half you get two squares.  

Step-by-step explanation:

Answer:  x=12.8

Step-by-step explanation:

Solution by Cross Multiplication

The equation:

5

8  =  

8

x

The cross product is:

5 * x  =  8 * 8

Solving for x:

x =

8 * 8

5

x = 12.8

Answer:

To solve the proportion 5/8 = 8/x, we can use cross-multiplication, which involves multiplying the numerator of one fraction by the denominator of the other fraction, and vice versa.

So, we have:

5/8 = 8/x

Cross-multiplying, we get:

5x = 8 * 8

Simplifying the right-hand side, we get:

5x = 64

Dividing both sides by 5, we get:

x = 64/5

So the solution to the proportion is:

x = 12.8

Therefore, 8 is proportional to 12.8 in the same way that 5 is proportional to 8.

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The negative binomial, geometric, and Poisson distributions do not have a specified maximum value of X.

In the negative binomial distribution, X represents the number of trials needed to achieve a fixed number of successes. The number of trials can vary indefinitely, so there is no maximum value for X.

Similarly, in the geometric distribution, X represents the number of trials needed to achieve the first success. Since the number of trials can continue indefinitely until the first success occurs, there is no predetermined maximum value for X.

The Poisson distribution models the number of events occurring in a fixed interval of time or space. The number of events can be arbitrarily large, and thus there is no specific maximum value for X.

On the other hand, the binomial and hypergeometric distributions have a fixed number of trials or population size, respectively, which defines the maximum value of X. In these distributions, X represents the number of successes within the specified constraints.

Therefore, the negative binomial, geometric, and Poisson distributions do not have a specified maximum value of X, making them distinct from the binomial and hypergeometric distributions.

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According to the information, Charles de Vendeville earned 148.4 points to place first.

In the underwater swimming event, the score was calculated based on the time underwater and the distance traveled. Each second underwater earned one point, and each meter traveled earned two points.

Charles de Vendeville stayed underwater for 68.4 seconds and traveled 60.2 meters. To calculate his score, we need to multiply the time underwater by one and the distance traveled by two, and then sum the two values:

So, Charles de Vendeville earned 188.8 points.

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Since the limit is less than 1, by the ratio test, the series converges absolutely.

To determine the convergence or divergence of the series, the ratio test is applied. The ratio test involves taking the limit of the absolute value of the ratio of the (k+1)-th term and the k-th term as k approaches infinity. If this limit is less than 1, then the series converges. If the limit is greater than 1 or does not exist, then the series diverges.

In this case, the ratio test is applied to the series ∑(k=1 to infinity) ke^(-5k). After applying the ratio test and simplifying, the limit is found to be 0, which is less than 1. Therefore, the series converges. This means that the sum of the series exists and is a finite value.

Applying the ratio test:

lim k→∞ (k+1)e−5(k+1) / ke−5k

= lim k→∞ (k+1) / e5 * k

As k approaches infinity, the denominator (e5k) grows much faster than the numerator (k+1), so the limit is 0.

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The smallest positive integer value of x for which[tex]f(x) = 2^x + 2[/tex] exceeds [tex]g(x) = 12x + 8[/tex]  is x = 4.

To find the smallest positive integer value of x for which the value of[tex]f(x) = 2^x + 2[/tex] exceeds the value of g(x) = 12x + 8, we need to compare the two functions and determine when the inequality is satisfied.

Setting up the inequality, we have:

[tex]2^x + 2 > 12x + 8[/tex]

First, let's simplify the inequality by subtracting 8 from both sides:

[tex]2^x - 6 > 12x[/tex]

Now, we can try to solve this inequality by considering different values of x.

However, it is challenging to find an exact solution by hand due to the exponential nature of [tex]2^x.[/tex]

Therefore, let's graph the two functions,[tex]f(x) = 2^x + 2[/tex] and g(x) = 12x + 8, to visually determine the point of intersection.

Upon graphing the functions, we observe that the graphs intersect at some point.

We can see that the value of f(x) starts to exceed g(x) as x increases.

To find the smallest positive integer value of x for which f(x) exceeds g(x), we need to analyze the graph and determine the first integer value after the intersection point where f(x) is greater than g(x).

Examining the graph, we find that the smallest positive integer value of x for which f(x) exceeds g(x) is x = 4.

Therefore, the answer is x = 4.

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The given indefinite integrals can be evaluated as

a) ∫6etdt = 6et + c

b) ∫2rdr = r^2 + c

c) ∫10x^2 0dx = (10/3)x^3 + c

In calculus, an indefinite integral represents a family of functions that differ from each other only by a constant. It is also known as an antiderivative because it is the opposite operation of differentiation.

The indefinite integral of a function f(x) is denoted as ∫f(x)dx, where dx represents the variable of integration. The result of integrating a function is called an antiderivative or a primitive of the function.

For part a), the indefinite integral of 6e^t is simply 6e^t + C, where C is the constant of integration.

For part b), the indefinite integral of 2r is r^2 + C, where C is the constant of integration.

For part c), the indefinite integral of 10x^2 is (10/3)x^3 + C, where C is the constant of integration.

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A line segment with an endpoint at (1, 6) and a length of 1.2 units can be drawn by extending the segment from the endpoint in the positive x-direction.

To draw the line segment, we start with the endpoint at (1, 6) on the coordinate plane. We then extend the segment from this point by moving 1.2 units in the positive x-direction.

To determine the endpoint of the line segment, we add the length of the segment, which is 1.2 units, to the x-coordinate of the starting point. Since the starting point has an x-coordinate of 1, adding 1.2 units results in an x-coordinate of 2.2. Therefore, the endpoint of the line segment is (2.2, 6), as the y-coordinate remains the same.

Using a ruler or a straightedge, we can now draw a line connecting the starting point (1, 6) to the endpoint (2.2, 6). This line segment will have a length of 1.2 units and will extend in the positive x-direction from the starting point.

Overall, by extending the line segment 1.2 units from the starting point (1, 6) in the positive x-direction, we can accurately represent a line segment with the desired endpoint and length.

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3x-0.03=0.75 where x is the price from 20 years ago.

A group must consist of 73 people to guarantee that at least 7 were born in the same month of the year.

To guarantee that at least 7 people were born in the same month of the year, we can use the Pigeonhole Principle. The Pigeonhole Principle states that if n items are placed into m containers, with n > m, then at least one container must contain more than one item.

In this case, the "items" are people, and the "containers" are the months of the year. Since there are 12 months in a year, there are 12 containers. To guarantee that at least 7 people were born in the same month, we need to find the smallest number of people (n) that satisfies the Pigeonhole Principle.

First, let's consider placing 6 people in each of the 12 months. This would result in 72 people (6 x 12).

However, this scenario still doesn't guarantee that any of the months would have 7 people.

To ensure that at least one month has 7 people, we need to add 1 more person to the group, making the total 73 people (72 + 1).

Now, even in the worst-case distribution scenario, at least one month would have 7 people, satisfying the Pigeonhole Principle. Therefore, a group must consist of 73 people to guarantee that at least 7 were born in the same month of the year.

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A statement that correctly describes the graph of g(x) if g(x) = f(x - 11) include the following: A. It is the graph of f(x) translated 11 units to the right.

In Mathematics and Geometry, the translation of a graph to the right simply means adding a digit to the numerical value on the x-coordinate of the pre-image:

g(x) = f(x - N)

Conversely, the translation of a graph upward simply means adding a digit to the numerical value on the y-coordinate (y-axis) of the pre-image.

g(x) = f(x) + N

In conclusion, we can logically deduce that the parent function f(x) = x was translated 11 units to the right in order to produce the graph of g(x).

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To prove that the order of u(n) is even when n > 2, we can use Corollary 2 of Lagrange's theorem (Theorem 7.1). Corollary 2 states that if G is a group and a is an element of G of finite order, then the order of a divides the order of G.

Let's consider the group G = U(n), the multiplicative group of integers modulo n, and let a = u(n), an element of G. We want to show that the order of a is even when n > 2.

By definition, the order of an element a in a group is the smallest positive integer k such that a^k = e, where e is the identity element of the group.

Since a = u(n), we have a^n ≡ 1 (mod n) by Euler's theorem. This implies that a^n - 1 is divisible by n.

Now, let's consider the order of a. Assume the order of a is odd, i.e., k is an odd positive integer such that a^k = e. This implies that a^(2k) = (a^k)^2 = e^2 = e.

Since k is odd, 2k is even. Therefore, we have found a positive integer (2k) such that a^(2k) = e, contradicting the assumption that k is the smallest positive integer satisfying a^k = e. Thus, the order of a cannot be odd.

By Corollary 2 of Lagrange's theorem, the order of a divides the order of G. Since n > 2, the order of G is even (it contains the identity element and at least one non-identity element). Therefore, the order of a (u(n)) must also be even.

Hence, we have proven that the order of u(n) is even when n > 2 using Corollary 2 of Lagrange's theorem.

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Thus, the original series converges by the Integral Test.

To determine if the series converges or diverges using the Integral Test, we will evaluate the corresponding improper integral:
∫(1 to infinity) xe^(-3x) dx

To solve this integral, we use integration by parts, where u = x and dv = e^(-3x) dx. Then, du = dx and v = -1/3 e^(-3x).
Using the integration by parts formula, we get:
∫(1 to infinity) xe^(-3x) dx = -1/3 x e^(-3x) | (1 to infinity) - ∫(1 to infinity) (-1/3 e^(-3x) dx)

Now we evaluate the remaining integral:
∫(1 to infinity) (-1/3 e^(-3x) dx) = (-1/3) ∫(1 to infinity) e^(-3x) dx = (-1/9) [e^(-3x)] (1 to infinity)

Evaluating the limits, we have:
-1/3 [(-1/3)e^(-3)(infinity) - (-1/3)e^(-3)(1)] - (-1/9)[0 - e^(-3)]

Which simplifies to:
(-1/3)(-1/3)e^(-3) - (-1/9)e^(-3) = (1/9)e^(-3)

Since the integral converges, the original series also converges by the Integral Test.

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The most logical order for the steps in correlation analysis is as follows:

1. Make scatter diagram.

2. Calculate a correlation coefficient.

3. Draw a least squares fit line.

The first step in correlation analysis is to create a scatter diagram, which involves plotting the paired data points on a graph. This helps visualize the relationship between the variables and provides an initial understanding of the data distribution.

Once the scatter diagram is created, the next step is to calculate a correlation coefficient. This numerical value quantifies the strength and direction of the relationship between the variables. It indicates the degree of linear association between the variables and ranges from -1 to 1, with positive values indicating a positive correlation, negative values indicating a negative correlation, and values close to zero indicating a weak or no correlation.

Finally, after obtaining the correlation coefficient, one can draw a least squares fit line. This line represents the best linear approximation of the relationship between the variables. It is obtained by minimizing the sum of the squared differences between the observed data points and the predicted values on the line. The least squares fit line provides a visual representation of the trend or pattern observed in the data and can help in making predictions or drawing conclusions about the relationship between the variables.

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the final answer is: 1/3. We can use the hypergeometric distribution to solve this problem.

Let X be the number of funds that grew by at least 10% out of Sam's three selected funds. Then X follows a hypergeometric distribution with parameters N = 10 (total number of funds), K = 5 (number of funds that grew by at least 10%), and n = 3 (number of funds Sam selected).

The probability of two of Sam's three funds growing by at least 10% is:

P(X = 2) = (5 choose 2) * (5 choose 1) / (10 choose 3)
         = 10 * 5 / 120
         = 1/3

Therefore, the probability of experiencing  neither of the side effects is:

P(neither side effect) = 1 - P(at least one side effect)
                      = 1 - (0.23 + 0.52 - 0.12)
                      = 0.37

So the final answer is: 1/3.

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Answer:

its like choosing one of 52 which is a 0,0213 chance

Step-by-step explanation:

The given statements

(a) [1+1] we can then conclude that all the means are different from one another is false

(b) [1] the standardized variability between groups is higher than the standardized variability within groups is true

(c) [1+1]the pairwise analysis will identify at least one pair of means that are significantly since there are four groups is true

(d) [1+1] the appropriate α to be used in pairwise comparisons is 0.05 / 4 = 0.0125 since there are four groups is true.

(a) False. Rejecting the null hypothesis that the means of four groups are all the same using ANOVA at a 5% significance level does not necessarily mean that all the means are different from one another. It only indicates that there is at least one group that is significantly different from the others, but it does not provide information about which groups are different.

(b) True. If the null hypothesis is rejected, it means that there is a significant difference between at least one group mean and the overall mean. This implies that the standardized variability between groups is higher than the standardized variability within groups.

(c) True. If the null hypothesis is rejected, it means that there is a significant difference between at least one group mean and the overall mean. Therefore, pairwise analysis will identify at least one pair of means that are significant since there are four groups.

(d) True. When conducting pairwise comparisons, the appropriate α level to be used should be adjusted to account for multiple comparisons. In this case, since there are four groups, the appropriate α level would be 0.05/4 = 0.0125 to control for the family-wise error rate.

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The shortest distance from the chord and the center of the circle is given by the relation D = 4.6 cm

Given data ,

A circle of diameter 15 cm contains a chord of length 11.8 cm.

The shortest distance between the chord and the center of the circle is given by the formula:

Distance = √(r² - (d/2)²)

where r is the radius of the circle and d is the length of the chord.

On simplifying , we get

D = √(7.5² - (11.8/2)²)

Distance = √(56.25 - 34.81)

Distance = √21.44

Distance ≈ 4.6 cm

Hence , the distance is 4.6 cm

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In all cases, pumping the string w results in a string that is not in L, which contradicts the pumping lemma. And we can conclude that L is not a context-free language.

To prove that a language is not context-free, we can use the pumping lemma for context-free languages.

Assume that the language L = {w : w is a palindrome containing the same number of 0's and 1's} is context-free. Then, by the pumping lemma for context-free languages, there exists a constant p such that any string w in L with length |w| ≥ p can be written as w = uvxyz, where:

Let's choose the string w = [tex]0^p1^p0^p[/tex]. This string is in L because it is a palindrome and contains the same number of 0's and 1's. By the pumping lemma, we can write w = uvxyz, where |vxy| ≤ p and |vy| > 0.

There are three cases:

Therefore, in all cases, pumping the string w results in a string that is not in L, which contradicts the pumping lemma. Hence, we can conclude that L is not a context-free language.

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The value of c is 25 in the perfect square trinomial x^2 + 10x + c.

The value of c in the perfect square trinomial x^2 + 10x + c can be determined by examining the entries in the table. The missing values in the table represent the terms that complete the perfect square trinomial, allowing us to find the value of c.

In the given table, the first column is labeled "x squared" and contains entries x, x, x, x, x. The second column is labeled "x" and is left blank. The third, fourth, fifth, and sixth columns are all labeled "x" and are also left blank.

To find the value of c in the perfect square trinomial x^2 + 10x + c, we need to consider the entries in the table. The expression x^2 represents the first column of the table, which has entries x, x, x, x, x. The expression 10x represents the sum of the entries in the second, third, fourth, fifth, and sixth columns. Since these columns are blank in the table, the sum is 0.

Therefore, to complete the perfect square trinomial, the value of c would be the square of half the coefficient of x, which is (10/2)^2 = 25.

Hence, the value of c is 25 in the perfect square trinomial x^2 + 10x + c.

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The effective annual growth rate of the quantity with a half-life of 14 years is 4.9%.

To find the effective annual growth rate of a nominal exponential growth/decay, we can use the formula:

Effective annual growth rate = (1 + r)^n - 1

where r is the nominal annual growth rate (expressed as a decimal) and n is the number of compounding periods per year.

In this case, the quantity has a half-life of 14 years, which means that it decreases by a factor of 2 every 14 years. We can use the formula for exponential decay:

N(t) = N0 * e^(-kt)

where N0 is the initial quantity, t is the time elapsed, and k is the decay constant. Since the half-life is 14 years, we know that:

1/2 = e^(-k*14)

Taking the natural logarithm of both sides, we get:

ln(1/2) = -k*14

Solving for k, we get:

k = ln(2)/14

Now we can use the formula for the nominal annual growth rate:

r = e^(k) - 1

Substituting the value of k, we get:

r = e^(ln(2)/14) - 1

r = 0.0489

This means that the quantity is decreasing at a nominal annual growth rate of 4.89%. To find the effective annual growth rate, we need to know how often the quantity is being compounded. If we assume that it is compounded once a year (i.e. annual compounding), then the effective annual growth rate is:

Effective annual growth rate = (1 + 0.0489)^1 - 1

Effective annual growth rate = 0.0489 or 4.9% (rounded to one decimal place)

Therefore, the effective annual growth rate of the quantity with a half-life of 14 years is 4.9%.

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Answer:

Solution is in attached photo.

Step-by-step explanation:

Do take note for this question, since we let X be the distance between the start point and the falls, 2X will be the total distance travelled for the round trip.

There are 24 different ways we can draw two red, three green, and two purple balls if the balls are considered distinct.

To determine the number of ways we can draw the balls, we can use the concept of permutations. Since the balls are considered distinct, the order in which they are drawn matters.

First, let's consider the red balls. We need to choose 2 out of the available 2 red balls, so the number of ways to choose them is 2P2 = 2! = 2.

Next, let's consider the green balls. We need to choose 3 out of the available 3 green balls, so the number of ways to choose them is 3P3 = 3! = 6.

Finally, let's consider the purple balls. We need to choose 2 out of the available 2 purple balls, so the number of ways to choose them is 2P2 = 2! = 2.

To find the total number of ways we can draw the balls, we multiply the number of ways for each color: 2 * 6 * 2 = 24.

Therefore, there are 24 different ways we can draw two red, three green, and two purple balls if the balls are considered distinct.

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a) The exponential growth function that represents this growth is:

P(t) = 320[tex]e^{(0.0304t)[/tex]

b) We can estimate that the population in 2020 was approximately 397.3 million.

c) It will take approximately 22.8 years for the population to double.

a) The exponential growth function that represents this growth is:

P(t) = P₀[tex]e^{(rt)[/tex]

where P₀ is the initial population, r is the continuous growth rate, and t is the time elapsed.

We know that the population in 2002 was 320 million, so P₀ = 320. We also know that the population in 2012 was 330 million, so:

330 = 320[tex]e^{(10r)[/tex]

Solving for r:

[tex]e^{(10r)[/tex] = 1.03125

10r = ln(1.03125)

r ≈ 0.0304

Therefore, the exponential growth function that represents this growth is:

P(t) = 320[tex]e^{(0.0304t)[/tex]

b) To estimate the population in 2020, we need to find the value of P(18), since 2020 - 2002 = 18. So:

P(18) = 320[tex]e^{(0.0304*18)[/tex] ≈ 397.3 million

c) To find how long it will take to double the original population, we need to solve for t in the equation:

2P₀ = P₀[tex]e^{(rt)[/tex]

Dividing both sides by P₀:

2 = [tex]e^{(rt)[/tex]

Taking the natural logarithm of both sides:

ln(2) = rt

Solving for t:

t = ln(2)/r

Substituting the value of r that we found earlier:

t ≈ 22.8 years

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The rate of filling the silos is 106 ft³/ min.

a) Let's assume that both silos A and B have the same volume, represented as V cubic feet.

So, Volume of cylinder A

= πr²h

= 29587.69 ft³

and, Volume of cone A

= 1/3 π (12)² x 6

= 904.7786 ft³

Now, Volume of cylinder B

= πr²h

= 31667.25 ft³

and, Volume of cone B

= 1/3 π (12)² x 6

= 1206.371 ft³

Thus, the rate of filling

= (6363.610079)/ 10 x 60

= 106.0601 ft³ / min

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The monthly finance charge rate is 0.021, or 2.1%.

To find the monthly finance charge rate, we divide the finance charge by the previous balance and express it as a decimal.

Given that Mr. Dan Dapper received a statement with a finance charge of $2.10 on a previous balance of $100, we can calculate the monthly finance charge rate as follows:

Step 1: Divide the finance charge by the previous balance:

Finance Charge / Previous Balance = $2.10 / $100

Step 2: Perform the division:

$2.10 / $100 = 0.021

Step 3: Convert the result to a decimal:

0.021

Therefore, the monthly finance charge rate is 0.021, which is equivalent to 2.1% when expressed as a percentage.

Therefore, the monthly finance charge rate for Mr. Dan Dapper's clothing store is 2.1%. This rate indicates the percentage of the previous balance that will be charged as a finance fee on a monthly basis.

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The triple integral is equal to ∫∫∫ f(x, y, z) dV using spherical coordinates is equal to 64π/21 .

Use spherical coordinates to evaluate this triple integral over the given region.

The region p < 2 is a sphere centered at the origin with radius 2.

In spherical coordinates, this region can be described by,

0 ≤ ρ ≤ 2

0 ≤ θ ≤ 2π

0 ≤ φ ≤ π

The volume element in spherical coordinates is ρ² sin φ dρ dφ dθ.

The triple integral can be written as,

∫∫∫ f(x, y, z) dV

= [tex]\int_{0}^{2}\int_{0}^{\pi}\int_{0}^{2\pi }[/tex] (ρ² sin φ)(ρ⁴ sin²φ cos²θ sin²θ) dρ dφ dθ

= [tex]\int_{0}^{2}\int_{0}^{\pi}\int_{0}^{2\pi }[/tex]  (ρ⁶ sin³φ cos²θ sin⁵ θ) dρ dφ dθ

= [tex]\int_{0}^{2}[/tex](ρ⁶/7) [tex]\int_{0}^{\pi }[/tex] (sin³ φ) [tex]\int_{0}^{2\pi }[/tex] (cos² θ sin⁵θ) dθ dφ dρ

The innermost integral evaluates to π/8.

The second integral can be evaluated using the substitution u = cos φ, du = -sin φ dφ, which gives,

[tex]\int_{0}^{\pi }[/tex](sin³ φ) dφ

= -[tex]\int_{1}^{-1}[/tex](1-u²) du

= 4/3

The outer integral evaluates to (2⁷)/7.

Triple integral is equal to

∫∫∫ f(x, y, z) dV

= (2⁷/7) (4/3) (π/8)

= (32/7)π/6

= 64π/21

Therefore, the triple integral is equal to ∫∫∫ f(x, y, z) dV = 64π/21 .

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By integrating the joint PDF over the specified region.

To compute the probability P(X ≤ 1.25, Y ≥ 0.75) using the given joint PDF, we need to integrate the joint PDF over the specified region.

The region of interest is defined as 1 ≤ x ≤ 1.25 and 0.75 ≤ y ≤ 10.

The joint PDF, FXY(x, y), is given by FXY(x, y) = (x - cy) for 1 ≤ x ≤ 2 and 0 ≤ y ≤ 10, and 0 otherwise.

To compute the probability, we integrate the joint PDF over the specified region:

P(X ≤ 1.25, Y ≥ 0.75) = ∫∫[FXY(x, y)]dydx

Breaking down the integral into two parts:

∫[∫[FXY(x, y)]dy]dx

First, integrate the inner integral with respect to y:

∫[FXY(x, y)]dy = ∫[(x - cy)]dy = xy - (cy[tex]^2[/tex])/2

Next, integrate the outer integral with respect to x over the given range:

∫[xy - (cy[tex]^2[/tex])/2]dx = ∫[(xy - (cy)[tex]^2[/tex]/2)]dx

Evaluate the integral over the range 1 ≤ x ≤ 1.25:

= [∫[(xy - (cy[tex]^2[/tex])/2)]dx] evaluated from 1 to 1.25

Substitute the limits of integration into the expression:

= [(1.25y - (cy[tex]^2[/tex])/2) - (y - (cy[tex]^2[/tex])/2)]

Simplifying the expression:

= 1.25y - (cy[tex]^2[/tex])/2 - y + (cy[tex]^2[/tex])/2

= 0.25y

Finally, evaluate the integral with respect to y over the range 0.75 ≤ y ≤ 10:

∫[0.25y]dy = (0.25/2)y[tex]^2[/tex] evaluated from 0.75 to 10

Substitute the limits of integration into the expression:

= (0.25/2)(10^2 - (0.75)^2)

= (0.25/2)(100 - 0.5625)

= (0.25/2)(99.4375)

= 12.4296875

Therefore, P(X ≤ 1.25, Y ≥ 0.75) is approximately equal to 12.4296875.

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