Acquisition agreements sometimes include a provision requiring an increase in the cash price contingent upon investee's profits exceeding a specified level within a certain time period. Regarding the contingent consideration, acquisition accounting requires at acquisition date: Select one: A. Recognition of a liability at its fair value, but with no effect on the purchase price

The equation of the first circle is (x + 1)^2 + (y - 1)^2 = r^2 and the equation of the second circle is (x + 1)² + (y - 1)² = 16

The points are given as:

P(3, 0) and Q(0, 5)

The midpoint of PQ is

Midpoint = 0.5(3 + 0, 0 + 5)

Midpoint = (1.5, 2.5)

Calculate the slope of PQ

m = (y2 - y1)/(x2 - x1)

m = (5 - 0)/(0 - 3)

m = -5/3

A line perpendicular to PQ would have a slope (n) of

n = -1/m

This gives

n = -1/(-5/3)

n = 0.6

The equation is then calculated as:

y = n(x - x1) + y1

Where

(x1, y1) = (1.5, 2.5)

So, we have:

y = 0.6(x - 1.5) + 2.5

y = 0.6x - 0.9 + 2.5

Evaluate the sum

y = 0.6x + 1.6

Hence, the equation of the perpendicular bisector of PQ is y = 0.6x + 1.6

We have:

y = x + 2

Substitute y = x + 2 in y = 0.6x + 1.6

x + 2 = 0.6x + 1.6

Evaluate the like terms

0.4x = -0.4

Divide

x = -1

Substitute x = -1 in y = x + 2

y = -1 + 2

y = 1

Hence, the center of the circle is (-1, 1)

We have:

Center, (a, b) = (-1, 1)

Point, (x, y) = (0, 5) and (3, 0)

A circle equation is represented as:

(x - a)^2 + (y - b)^2 = r^2

Where r represents the radius.

Substitute (a, b) = (-1, 1) in (x - a)^2 + (y - b)^2 = r^2

(x + 1)^2 + (y - 1)^2 = r^2

Substitute (x, y) = (0, 5) in (x + 1)^2 + (y - 1)^2 = r^2

(0 + 1)^2 + (5 - 1)^2 = r^2

This gives

r^2 = 17

Substitute r^2 = 17 in (x + 1)^2 + (y - 1)^2 = r^2

(x + 1)^2 + (y - 1)^2 = r^2

Hence, the circle equation is (x + 1)^2 + (y - 1)^2 = r^2

The equation of the second circle is

2x² + y² + ax + by - 14 = 0

Rewrite as:

2x² + ax + y² + by = 14

For x and y, we use the following assumptions

2x² + ax = 0    and  y² + by = 0

Divide through by 2

x² + 0.5ax = 0    and  y² + by = 0

Take the coefficients of x and y

k = 0.5a                   k = b

Divide by 2

k/2 = 0.25a           k/2 = 0.5b

Square both sides

(k/2)² = 0.0625a²           (k/2)² = 0.25b²

Add the above to both sides of the equations

x² + 0.5ax +0.0625a² = 0.0625a²    and  y² + by + 0.25b² = 0.25b²

Express as perfect squares

(x + 0.25a)² = 0.0625a² and (y + 0.5b)² = 0.25b²

Add both equations

(x + 0.25a)² + (y + 0.5b)² = 0.0625a² + 0.25b²

So, we have:

2x² + ax + y² + by = 14 becomes

(x + 0.25a)² + (y + 0.5b)² = 0.0625a² + 0.25b²+ 14

Comparing the above equation and (x + 1)^2 + (y - 1)^2 = r^2, we have:

0.25a = 1 and 0.5b = -1

Solve for a

a = 4 and b = -2

This means that the value of a is 4 and b is -2

We have:

a = 4 and b = -2

Substitute these values in (x + 0.25a)² + (y + 0.5b)² = 0.0625a² + 0.25b²+ 14

This gives

(x + 0.25*4)² + (y - 0.5*2)² = 0.0625*4² + 0.25*(-2)²+ 14

(x + 1)² + (y - 1)² = 16

The equation of the first circle is

(x + 1)² + (y - 1)² = 17

The radii of the first and the second circles are

R = √17

r = √16

√17 is greater than √16

Since they have the same center, and the radius of the first circle exceeds the radius of the second circle, then the second circle lies inside the first circle.

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Step-by-step explanation:

the sum of all angles around a single point on one side of a line must be 180°.

because that line can be seen as the extension of the diameter of a circle, and the point would be the center of that circle. so, one side of the line represents a half-circle, which stands for 180°.

so we have

180 = 40 + 40 + (2x + 30) = 80 + 2x + 30 = 110 + 2x

70 = 2x

x = 35

The arc length of [tex]y=2\cos(3x)[/tex] on the interval [tex][a,b][/tex] is

[tex]\displaystyle \int_a^b \sqrt{1 + (y')^2} \, dx = \int_a^b \sqrt{1 + (-6\sin(3x))^2} \,dx = \boxed{\int_a^b \sqrt{1+36\sin^2(3x)} \, dx}[/tex]

Answer:

C, 24 units^2

Step-by-step explanation:

The formula for area of a parallelogram is base times height.

The height of the parallelogram is 4 units

The base of the parallelogram is 6 units

4 times 6 is 24

Hope this helps:)

Answer:

C. 24 units²

Step-by-step explanation:

To calculate the area of a parallelogram we use the following formula:

A = B*h (B: base, h: height)

The base of the parallelogram is 6 units and the height is 4 units

4*6 = 24 units but, the area is presented in square units so the answer is  24 units²

Answer:

there will be 17 integers!

List :

1

4

9

16

25

36

49

64

81

100

121

144

169

196

225

256

289

They're all squares, like for example, 1^2, 2^2, 3^2, etc

Answer:

cheapt

Step-by-step explanation:

The measure of the arc is given as π/2. See the explanation below.

An "arc" is a curve that connects two points in mathematics.

It can also be depicted as a section of a circle. It is essentially a portion of a circle's circumference. An arc is a kind of curve.

Note that the viewing angle is 45°.

Thus, the center angle is:
45 X 2 = 90°

Measure of the arc therefore is:
= (π/180°) x 90

= π/2

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a. See attachment for the labelled diagram

b. Using the sine ratio, distance from the hot air to pond A is 5,038.9 m, while distance from the hot air to pond B is 6,287.1 m.

c. Distance between the two ponds is 1,263.5 m.

Sine ratio, is: sin ∅ = opposite side/hypotenuse length

Tangent ratio is: tan ∅ = opposite side/adjacent length.

a. The diagram with the appropriate labels is shown in the image attached below.

b. Use the sine ratio to find the distance from the hot air to pond A (CA) and to pond B (CB):

CA = hypotenuse

∅ = 10°

Opposite = 875 m

sin 10 = 875/CA

CA = 875/sin 10

CA ≈ 5,038.9 m (distance from the hot air to pond A)

CB = hypotenuse

∅ = 8°

Opposite = 875 m

sin 8 = 875/CB

CB = 875/sin 8

CB ≈ 6,287.1 m (distance from the hot air to pond B)

c. Distance between the two ponds, BA = BD + DA.

Apply the tangent ratio to find BD and DA

tan 8 = 875/BD

BD = 875/tan 8

BD = 6,225.9 m

tan 10 = 875/DA

DA = 875/tan 10

DA = 4,962.4 m

Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.

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Hello,

[tex] \frac{ \frac{m - 4}{m + 4} }{m + 2} = \frac{ \frac{m - 4}{m + 4} }{ \frac{m + 2}{1} } = \frac{m - 4}{m + 4} \times \frac{1}{m + 2} = \frac{m - 4}{(m + 4)(m + 2)} [/tex]

Answer:

B. 54π units ²

Step-by-step explanation:

solution:

given,

Radius (r) = 3

(l) = 15

we know that,

T.S.A. of cone = πr( r + l )

= π × 3(3 + 15)

= π × 3 × 18

= π × 54

= 54π units ²

Answer:

Each Person:

-In tips: $2

-Food Bill: $7.50

Step-by-step explanation:

Let's find the tip amount for each person. $16 for the whole group. Each person will give in $2 for the tips, for a total of $16 in tips.

Now that tips are done, we must subtract the amount of tips from the food bill, to see how much each person pays. $76 - $16 = $60.

Divide 60 by 8 to get.. 60/8= 7.5.

With 7.5 as an answer, we can conclude that each person paid $7.50 for the food bill.

I see you need to select solutions, may I see them to help you out? The description is pretty vague..

The total amount in the investment account is $3031.00

The given parameters are

Principal, P = $2800

Rate, r = 5.5%

Time = 18 months i.e. 1.5 years

The amount is then calculated as:

A = P + PRT

This gives

A = 2800 + 2800 * 5.5% * 1.5

Evaluate

A = 3031

Hence, the total amount in the investment account is $3031.00

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Answer: 384 feet

Step-by-step explanation:

     We will simplify and solve -16t² + 160t when t is equal to 4.

-16t² + 160t

-16(4)² + 160(4)

384 feet

Answer:

Step-by-step explanation:

**Note: The polynomial in question is -16t² + 160t, as clarified in the discussion under the question.**

Since there is a polynomial to find the height given a certain time, the height is a function of time.

This function would be h(t) = -16t² + 160t, so plugging in 4 for t would give the height.

[tex]h(4) = -16(4)^2+160(4)[/tex]

[tex]-16(16)+160(4)[/tex] [Squaring 4]

[tex]-256 + 640[/tex] [Multiplying]

[tex]384[/tex] [Combining both terms]

Hence, the height of the firework after 4 seconds is 384 feet.

a. The mean, median and mode for this plot are 70.8, 70 and 60 respectively.

b. Mean best represents the data for this plot.

c. When there are outliers, the mean might be a deceptive center tendency measure.

Mean, Median, and Mode

Mean = Sum of prices / Total number of sunglasses

Mean = (20 + 20 + 50 + 50 + 50 + 60 + 60 + 60 + 60 + 60 + 60 + 70 + 70 + 70 + 80 + 80 + 80 + 80 + 90 + 90 + 90 + 90 + 100 + 100 + 130) / 25

Mean = 70.8

Median is equal to (n/2 + 1) when n is an odd number.

Here, the number of sunglasses is represented by n.

⇒ (25/2 + 1)th term is the median

Median = 13th term

Median = 70

Mode is the most frequent data from the plot.

⇒ Mode = 70

Mean Being the Best Central Measure

The mean is often the ideal measure of central tendency to use when your data distribution is continuous and symmetrical, such as when your data are normally distributed. So, mean here denotes the typical cost of the sunglasses.

Misleading Measure

When there are outliers, the data mean is significantly impacted. As a result, it may be inaccurate when examining the data's average price.

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Answer:

324[tex]\pi[/tex] units³

Step-by-step explanation:

Surface Area of Sphere = 4[tex]\pi[/tex]r²; where 'r' is the radius of the sphere.

4[tex]\pi[/tex]r² =

4[tex]\pi[/tex]9² =

4[tex]\pi[/tex]81 =

324[tex]\pi[/tex] units³

Answer:

324[tex]\pi[/tex] unit^2

Step-by-step explanation:

The formula for finding the surface area of a sphere is: [tex]A = 4\pi r^2[/tex]

--> A = Surface area of the sphere

--> r = Radius of the sphere

The image shows that the radius of the sphere is 9.

All we need to do is to replace r with 9.

--> A = 4[tex]\pi[/tex]9^2

--> A = 4[tex]\pi[/tex]81

--> A = 324[tex]\pi[/tex]

So that is your final answer! 324[tex]\pi[/tex] unit^2

--> It is unit^2 since it is an area, not a volume.

+ I'm leaving this as [tex]\pi[/tex], since the question is asking for the exact value, not the ones that are rounded up.

Answer: There are only 90 two-digit numbers. It shouldn’t take long to write them out and count them

Step-by-step explanation:

Answer:

45 numbers

Step-by-step explanation:

The 10-digit numbers are 10-99. We can manually write them out to start and see if we can find a pattern.

We can start 10-19: The numbers that have one odd digit and one even digit at 10, 12, 14, 16, 18 (since 1 is odd, we can only pick the numbers that have an even unit digit)

Next, we move on to 20-29: The numbers that follow the property are 21, 23, 25, 27, 29

Both of these examples have 5 numbers that follow the property. We can notice that all of the subsequent clusters (30-39, 40-49, 50-59, 60-69, 70-79, 80-89, 90-99) will also have 5 each. The numbers that start with an odd number will have the same unit digits as the 10-19 cluster, and the numbers that start with an even number will have the same unit digits as the 20-29 cluster. Observe:

30-39: 30, 32, 34, 36, 38

40-49: 41, 43, 45, 47, 49

50-59: 50, 52, 54, 56, 58

60-69: 61, 63, 65, 67, 69

70-79: 70, 72, 74, 76, 78

80-89: 81, 83, 85, 87, 89

90-99: 90, 92, 94, 96, 98

In all, there are 9 clusters of numbers, and each one has 5 numbers that follow the property. Therefore, the total is 9*5 or 45 numbers

Answer:

y = -3x + 4

Step-by-step explanation:

y = mx + c

y = gradient(x intercept) + y intercept

y = -3x + 4

Answer:1.166 reams of paper.

Step-by-step explanation:

Just use simple division and divide 7/6.

Each classroom will get  [tex]\dfrac{7}{6}[/tex]  paper when there are 6 fifth grade classrooms that share 7 packs of paper.

A fraction is defined as a part of a whole. The upper part of the fraction is called the numerator, and the lower part is called the denominator.

Given that:

Number of fifth grade classrooms = 6

Number of packs of paper = 7

The number of paper each classroom get in fractions can be obtained by dividing the number of packs of paper by the number of fifth grade classrooms.

Each classroom get = [tex]\dfrac{Number \ of \ packs \ of \ paper}{ \ Number \ of \ fifth \ grade \ classrooms}[/tex]

Each classroom get = [tex]\dfrac{7}{6}[/tex]

Each classroom will get  [tex]\dfrac{7}{6}[/tex]  paper.

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f(-a) is the remainder when f(x) is divided by (x+a). This can be obtained by remainder theorem for polynomials.

Given that f(x) is divided by (x+a) and leaves a reminder

Using the remainder theorem for polynomials we get,

f(x) = (x+a)·g(x) + r, where g(x) is the quotient and r is the remainder.

Put x = -a, then

f(-a) = (-a+a)·g(-a) + r

f(-a) = (0)·g(x) + r

f(-a) = r

f(-a) is the remainder.

Hence f(-a) is the remainder when f(x) is divided by (x+a).

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It looks like the boundaries of [tex]R[/tex] are the lines [tex]y=\dfrac23x [/tex] and [tex]y=3x[/tex], as well as the hyperbolas [tex]xy=\frac23[/tex] and [tex]xy=3[/tex]. Naturally, the domain of integration is the set

[tex]R = \left\{(x,y) ~:~ \dfrac{2x}3 \le y \le 3x \text{ and } \dfrac23 \le xy \le 3 \right\}[/tex]

By substituting [tex]x=\frac uv[/tex] and [tex]y=v[/tex], so [tex]xy=u[/tex], we have

[tex]\dfrac23 \le xy \le 3 \implies \dfrac23 \le u \le 3[/tex]

and

[tex]\dfrac{2x}3 \le y \le 3x \implies \dfrac{2u}{3v} \le v \le \dfrac{3u}v \implies \dfrac{2u}3 \le v^2 \le 3u \implies \sqrt{\dfrac{2u}3} \le v \le \sqrt{3u}[/tex]

so that

[tex]R = \left\{(u,v) ~:~ \dfrac23 \le u \le 3 \text{ and } \sqrt{\dfrac{2u}3 \le v \le \sqrt{3u}\right\}[/tex]

Compute the Jacobian for this transformation and its determinant.

[tex]J = \begin{bmatrix}x_u & x_v \\ y_u & y_v\end{bmatrix} = \begin{bmatrix}\dfrac1v & -\dfrac u{v^2} \\\\ 0 & 1 \end{bmatrix} \implies \det(J) = \dfrac1v[/tex]

Then the area element under this change of variables is

[tex]dA = dx\,dy = \dfrac{du\,dv}v[/tex]

and the integral transforms to

[tex]\displaystyle \iint_R 9xy \, dA = \int_{2/3}^3 \int_{\sqrt{2u/3}}^{\sqrt{3u}} \frac{dv\,du}v[/tex]

Now compute it.

[tex]\displaystyle \iint_R 9xy \, dA = \int_{2/3}^3 \ln|v|\bigg|_{v=\sqrt{2u/3}}^{v=\sqrt{3u}} \,du \\\\ ~~~~~~~~ = \int_{2/3}^3 \ln\left(\sqrt{3u}\right) - \ln\left(\sqrt{\frac{2u}3}\right) \, du \\\\ ~~~~~~~~ = \frac12 \int_{2/3}^3 \ln(3u) - \ln\left(\frac{2u}3\right) \, du \\\\ ~~~~~~~~ = \frac12 \int_{2/3}^3 \ln\left(\frac{3u}{\frac{2u}3}\right) \, du \\\\ ~~~~~~~~ = \frac12 \ln\left(\frac92\right) \int_{2/3}^3 du \\\\ ~~~~~~~~ = \frac12 \ln\left(\frac92\right) \left(3-\frac23\right) = \boxed{\frac76 \ln\left(\frac92\right)}[/tex]

We can identify that the missing reason in the proof is: Definition of Congruent angles.

We know that an angle measure of 90° of ∠ABC in the triangle means that it is a right angle triangle.

We also see that ∠ADB is also a right angle and is equal to 90°.

Now, since they have exactly the same measure, these angles are congruent. Then we can say that the angles are congruent and as such:

∠ABC ≅ ∠ABD

Thus, we can identify that the missing reason is: Definition of Congruent angles.

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Answer:

B

Step-by-step explanation:

See the attached image.

Answer:

(-2, -0.5)

Step-by-step explanation:

1. add the x-coordinates and then either divide by 2 or multiply by 1/2

2. add the y-coordinates and then either divide by 2 or multiply by 1/2

(-7+3)/2 = -2

(-10+9)/2 = -0.5

Have a blessed day!

Answer:

10

Step-by-step explanation:

It's just symmetry. You see that the geometrical construction above has been rotated, so its properties will remain the same.

Isabel is incorrect because the point of intersection between line B and parabola A that can be determined is the y-intercept of the equations, not the vertex.  This can be obtained using finding y intercept of both parabolas and vertex of parabola A.

Parabola A, (x + 3)² = y = x² + 6x + 9

Parabola B, y = mx + 9

x=0, y = 9

y coordinate of parabola A is (0,9)

⇒The vertex coordinate,

(-b/2a , -(b²-4ac)/4a) = (-3,0)          

x=0, y = 9  

y coordinate of parabola B is (0,9)    

Isabel claims one solution to the system of two equations must always be the vertex of parabola A which is wrong.  

Hence Isabel is incorrect because the point of intersection between line B and parabola A that can be determined is the y-intercept of the equations, not the vertex.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Parabola A can be represented using the equation (x + 3)2 = y, while line B can be represented using the equation y = mx + 9. Isabel claims one solution to the system of two equations must always be the vertex of parabola A. Which best describes the reasonableness of her claim?

Considering the sum of the internal angles of the triangle, the angle of elevation from point L to point J is of 37º.

The sum of the internal angles of a triangle is of 180º.

In this problem, the angles are:

90º, 53º, x

Hence:

90 + 53 + x = 180

x = 180 - 143

x = 37º

The angle of elevation from point L to point J is of 37º.

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Answer:

53*

Step-by-step explanation:

took on edge

[tex]\textbf{Heya !}[/tex]

use the slope-formula:-

[tex]\sf{\cfrac{y2-y1}{x2-x1}}[/tex]

put-in the values

[tex]\sf{\cfrac{-2-1}{1-(-3)}}[/tex]

[tex]\sf{\cfrac{-3}{1+3}}[/tex]

[tex]\sf{\cfrac{-3}{4}[/tex]

[tex]\sf{-\cfrac{3}{4}}[/tex]

`hope it's helpful to u ~

Answer:

line segment AC (hypotenuse)

Step-by-step explanation:

The Pythagorean Theorem states that the sum of squares of the base/height of the triangle will equal the hypotenuse squared which is what c is equal to. So the c would represent the hypotenuse which is the side from the points A to C in the diagram.

It means the probability of a random permutation of n numbers gets sorted after 1 pass of bubble sort is n!

According to the statement

we have to find the probability of random permutation of the N numbers.

So, according to the definition of A random permutation is a random ordering of a set of objects, that is, a permutation-valued random variable.

In this we order of select the objects randomly.

So, Let There are n−1 comparisons, so 2n−1 possible sequences of actions - swap or don't swap.

To find the permutations, start with 1,2,3,4,5 and undo a sequence.

For example, if let n=5, there are 24=16 out of 5!

which is 5! =120 that end after one round of bubble sort.

So, It means the probability of a random permutation of n numbers gets sorted after 1 pass of bubble sort is n!

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The thousand of miles across the United states from the east coast to the west coast.

In order to find the number of miles across the United states from the east coast to the west coast.

Hence, the thousand of miles across the United states from the east coast to the west coast.

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Outliers are sample values that lie very far away from the majority of the other sample values.

We know that, an outlier is an observation that lies an abnormal distance from other values in a random sample from a population.

It differs significantly from other observations in a sample values.

Outlier is a value that is distant from the majority of the values in a data set.

For a scatter plot, an outlier is the point or points that are farthest from the regression line.

For example in the record of marks 25, 29, 7, 32, 85, 33, 27, 28 both 7 and 85 are outliers.

Therefore, outliers are sample values that lie very far away from the majority of the other sample values.

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