An 800-N box is pushed up an inclined plane. The plane is 4.0 m long and 2.0 m high. If it requires 3200 J of work to get the box to the top of the plane, what was the magnitude of the average friction force on the box? Group of answer choices 400 N 0 N Non-zero, but less than 400 N Greater than 400 N

Answers

Answer 1

The magnitude of the average friction force on the box is 400 N

What is energy conservation?

It is the principle by which the total energy remains constant in a system that is not subject to external influence.

It states that energy can neither be created nor be destroyed, It may be transformed from one form to another.

Here,

length of the plane, d = 4 m

height of the plane, h = 2 m

work done total, w = 3200 J

kinetic energy on top, KE = 0

Potential energy on top,

PE = weight x height

PE = 800 *2

PE = 1600 J

Now,

Total work done = KE + PE + W (friction)

W (friction) = 3200 - 1600

W (friction)  = 1600 J

W (friction) = F (friction) x d

F (friction) = 1600 / 4

F (friction) = 400 N

Hence,

The magnitude of the average friction force on the box is 400 N

option A is correct

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Related Questions

Find the work done by a person weighing 133 lb walking exactly one revolution(s) up a circular, spiral staircase of radius 5 ft if the person rises 13 ft after one revolution.

Answers

The work done by a person will be  2341.28 J

Work done is negative of change in potential energy, that is  W=−(∆U). It means that Work done against a force (or work done on a system) increases its potential energy. And Work done by a force (or work done by the system) decreases its potential energy

mass = 60.33kg

height = 3.96 m

work done = change in potential energy

                  = m*g*h

                  = 60.33* 9.8 * 3.96 = 2341.28 J

The work done by a person will be  2341.28 J

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The period of a satellite, the time it takes for a complete revolution, depends on the satellite's: _________

Answers

The period of a satellite, the time it takes for a complete revolution, depends on the satellite's mass of planet and the distance of satellite form center of the planet .

According to the question

The period of a satellite, the time it takes for a complete revolution, depends on the satellite's:

1. The mass of the planet being orbited

2. The distance of the satellite from the center of the planet.

Hence, The period of a satellite, the time it takes for a complete revolution, depends on the satellite's mass of planet and the distance of satellite form center of the planet .

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A copper penny has a mass of 3.0 g. A total of 4.0 × 1012 electrons are transferred from one neutral penny to another. If the electrostatic force of attraction between the pennies is equal to the weight of a penny, what is the separation between them?

Answers

Answer:

F = K Q1 Q2 / R^2 = m g

Q1 = - Q2 = (4E12 * 1.60E-19) = 6.4E-7   coulombs

Q^2 = 4.10E-13

R^2 = 9.0E9 * 4.1E-13 / (.003 * 9.80) = 36.9E-4 / 2.94E-2

R^2 = .126

R = .35 m

F = K Q1 Q2 / R^2 = m g, Q1 = - Q2 = (4E12 * 1.60E-19) = 6.4E-7   coulombs Q^2 = 4.10E-13, R^2 = 9.0E9 * 4.1E-13 / (.003 * 9.80) = 36.9E-4 / 2.94E-2 R^2 = .126 and R = .35 m.

What is Electrostatic force?

Due to their electric charges, particles can be attracted to or repelled by electrostatic forces. This force is also known as the Coulomb force or Coulomb contact, and it was first described in 1785 by French physicist Charles-Augustin de Coulomb.

Over a distance of 10-16 meters, or roughly one-tenth the diameter of an atomic nucleus, the electrostatic force is present. While opposite charges attract one another, like charges repel one another.

For instance, two positively charged protons, two negatively charged electrons, or two anions all repel one another. Cation and anions, as well as protons and electrons, are all attracted to one another.

Therefore, F = K Q1 Q2 / R^2 = m g, Q1 = - Q2 = (4E12 * 1.60E-19) = 6.4E-7   coulombs Q^2 = 4.10E-13, R^2 = 9.0E9 * 4.1E-13 / (.003 * 9.80) = 36.9E-4 / 2.94E-2 R^2 = .126 and R = .35 m.

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The crystal in a digital watch oscillates at a rate of 215 Hz. If the maximum displacement of one crystal face (measured from one extreme of its motion to the other) is 50 nm, what is the maximum speed of the face?

Answers

The maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.

Maximum speed of the face

v = fλ

where;

f is frequency of the waveλ is the wavelength

Angular speed of the wave

ω = 2πf

v(max) = ωA

v(max) = 2πfA

where;

A is amplitude of the wave

v(max)  = 2π(215)(50 x 10⁻⁹ m)

v(max) = 6.75 x 10⁻⁵ m/s

Thus, the maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.

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A substance has life of 40 years. In how many years will the substance disintegrate to 1/8 of its initial size

Answers

Answer:

5 years

Explanation:

[tex]\frac{1}{8}(40)\\\\= 5[/tex]

Voltage-gated calcium ion channels that function in neurotransmission are primarily found on the:_________

Answers

Voltage-gated calcium ion channels that function in neurotransmission are primarily found on the: excitable cells

A neurotransmitter is the body’s chemical messenger. They are molecules that transmit signals from neurons to muscles, or between different neurons. The transmission of signals between two neurons occurs in the synaptic cleft.

The electrical signals that travel along the axon are briefly converted into chemical signals through neurotransmitters.

Voltage-gated calcium (Ca2+) channels are key transducers of membrane potential changes into intracellular Ca2+ transients that initiate many physiological events. There are ten members of the voltage-gated Ca2+ channel family in mammals, and they serve distinct roles in cellular signal transduction.

They are found in excitable cells, not only in motor neurons but also in other types of excitable cells .

Voltage-gated calcium channels are important mediators of depolarization-evoked release of neurotransmitters. To ensure efficient coupling of calcium influx to rapid vesicle release, calcium channels must be localized within the active zones of presynaptic nerve terminals

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Arrange these objects according to size, largest to smallest. Group of answer choices traditional dwarf elliptical, ultra-compact dwarfs, globular clusters ultra-compact dwarfs, traditional dwarf galaxies, globular clusters globular clusters, traditional dwarf elliptical, ultra-compact dwarfs globular clusters, ultra-compact dwarfs, traditional dwarf elliptical

Answers

Among the given objects, the largest one is dwarf elliptical, then ultra-compact dwarf and then globular clusters. Thus, option a is correct.

To find the correct answer, we need to know about the galaxies.

Are galaxies bigger than globular clusters?Globular clusters are spherical groups of stars that are primarily located in the spiral galaxy' stellar halo. There are 150 or so globular clusters in our Milky Way galaxy, some of which house our galaxy's oldest stars.Globular clusters are much smaller than galaxies.a system of gas and dust, as well as millions or billions of stars, kept together by gravitational attraction is called galaxy.Ultracompact dwarfs are more extended and have higher surface brightness than typical dwarf nuclei.Dwarf elliptical galaxies are elliptical galaxies that are smaller than ordinary elliptical galaxies. They are quite common in galaxy groups and clusters and are usually companions to other galaxies.

Thus, we can conclude that, option a is correct.

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Why might the measurements of ""true distances"" be different for different groups even though they are measuring the same distance?

Answers

While measuring , there are a lot of errors which can happen due to which ""true distances"" be different for different groups even though they are measuring the same distance.

While measuring , there are a lot of errors which can happen , to find the most correct value in order to make the result precise and accurate number of measurements needed to be done in order to reduce the error

As nothing can be measured with full precision and accuracy, different measurements for different groups even though they are measuring the same distance.

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Does your experimental density of the unknown liquid agree with the true value? if no, give reasons for the discrepancy. Do not include operator errors

Answers

The reasons  for the discrepancy in the experimental density of the unknown liquid agree with the true value can be instrument not having same levels , Temperature Effects , Kind of scales used and  Shape of objects used for measure .

According to the question

Discrepancy:

The state or quality of being discrepant or in disagreement, as by displaying an unexpected or unacceptable difference; inconsistency.

Density:

Density is mass per unit volume, so when measuring density, you find the mass of the object and divide it by its measured volume.

All measurements include some uncertainty, however, and certain kinds of errors can increase the uncertainty in your calculation.

The reason of discrepancy in the experimental density of the unknown liquid agree with the true value can be:

1. Use of instrument not having same levels

2. Temperature Effects as Density varies with temperature .

3. Kind of scales used for measures

4. Shape of objects used for measure .

Hence, the reasons  for the discrepancy is instrument not having same levels , Temperature Effects , Kind of scales used and  Shape of objects used for measure .

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describe how you would connect a voltmeter to measure the potential difference across a resistor and an ammeter to measure the current through a resistor

Answers

A voltmeter needs to be connected in parallel to the two sites in order to measure the potential difference between them.

What is a voltmeter?The electrical potential difference between two locations in an electric circuit is measured using a voltmeter.The potential difference between two ends of a current-carrying conductor is measured using a voltmeter.On a scale that is typically measured in volts, millivolts (0.001 volts), or kilovolts, a voltmeter primarily monitors the voltage of direct or alternating electric current (1,000 volts).Numerous voltmeters are digital and display readings as numbers.How is a voltmeter connected?A galvanometer with high resistance is a voltmeter.Any portion of an electrical circuit can be measured.Due to its high resistance, it is linked in parallel so that it does not impact the circuit's overall net resistance and does not draw any current by itself.A device's voltage is measured by a voltmeter connected in parallel, and its current is measured by an ammeter connected in series.

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An astronaut in training is seated at the end of a horizontal arm 8 meters long. How many revolutions per second must the arm make for the astronaut to experience a horizontal acceleration of 4.0g

Answers

Answer:

a = v^2 / R        where a is the centripetal acceleration and R the radius

v = 2 π R N / t        where (N / t) is the revolutions / sec giving distance / time

a = 4 g         horizontal acceleration

4 g = (2 π R N / t)^2 / R = 4 π^2 * R * (N / t)^2

(N / t)^2 = g / (π^2 * R)

N / t = 1 /  π * (g / R)^1/2 = .318 * (9.80 m / s^2 / 8 m)^1/2  = .352 / sec

5. a new type of hoverboard has been designed to levitate over a copper surface. the
developers had a skateboard icon test out the hoverboard on a copper halfpipe.
what type of field is responsible for levitating the hoverboard and rider as it
traverses the half pipe?
a-magnetic field
b-gravitational field
c-electric field
d-tesla field

Answers

The magnetic field is responsible for levitating the hoverboard and rider as it traverses the half pipe.

What is a magnetic field?The magnetic field is defined as the field the magnetic materials generate or when an electric charge moves in a field region that generates the magnetic field.The surface is made up of from the copper and copper is conductor of electricity.When an electrical charge moves, it generates a magnetic field. As with electrical current running via a wire, the spinning and orbiting of an atom's nucleus produces a magnetic field.Thus, the magnetic field is responsible for levitating the hoverboard and rider as it traverses the half pipe.What is the characteristics of Magnetic fields?Magnetic field lines never cross one another.They begin (from the north pole) and end (to the south pole) perpendicular to the surface of the magnet. Magnetic field lines also run through the magnet.The magnetic field is denser at the poles and less dense as we move away from them.A single magnetic pole does not exist. Magnetic poles are always found in pairs of opposing poles.

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Which would require the greater energy; slowing down of the orbital speed of the Earth so it crashes into the sun, or speeding up the orbital speed of the Earth so it escapes the sun

Answers

Answer: Speeding up the orbital speed of earth so it escapes the sun require the greater energy.

Explanation: To find the answer, we need to know more about the Orbital and escape velocities.

What is Orbital and Escape velocity?Orbital velocity can be defined as the minimum velocity required to put the satellite in its orbit around the earth.The expression for orbital velocity near to the surface of earth will be,

                   [tex]V_o=\sqrt{gR}[/tex]

Escape velocity can be defined as the minimum velocity with which a body must be projected from the surface of earth, so that it escapes from the gravitational field of earth.The expression for orbital velocity will be,

                    [tex]V_e=\sqrt{2gR}[/tex]

If we want to get into the sun, we want to slow down almost completely, so that your speed relative to the sun became almost zero.We need about twice the raw speed to go to the sun than to leave the sun.

Thus, we can conclude that, the speeding up the orbital speed of earth so it escapes the sun require the greater energy.

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As we adjust to low light, our ______ becomes nonfunctional and it may take ______ for rhodopsin to become regenerated sufficiently so that you can see well in low-light conditions.

Answers

As we adjust to low light, our cone becomes nonfunctional and it may take 20-30 min for rhodopsin to become regenerated sufficiently so that you can see well in low-light conditions.

Rhodopsin:

The most prevalent protein in the retinal rod cells is rhodopsin, a G-protein coupled receptor. It consists of two components: an opsin molecule connected to an 11-cis-retinal chromophore, which serves as the main photoreceptor molecule of vision. When a photon of light excites 11-cis retinal, rhodopsin is linked to it. This isomerizes into an all-trans conformation.

Rhodopsin is crucial to our ability to see in low light because it enables the rods in our eyes to receive photons and detect light. As rhodopsin absorbs a photon, it separates into a retinal and an opsin molecule before slowly and at a constant rate recombining back into rhodopsin. But because this happens gradually, it takes some time for our eyes to get used to the dark. For humans, acclimating to the dark takes roughly 20 to 30 minutes.

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A car goes around a curve at a constant speed. what is the direction of the net force on the car?

Answers

Answer:

The direction of the net force is at a tangent to the circle.

If a 100 ω resistor is placed across a 0. 10 μf charged capacitor which is initially charged to 3 v. How long does it take it to discharge to 2v to 1v?

Answers

1. The time taken to discharge to 2 V is 2×10⁻⁹ s

2. The time taken to discharge to 1 V is 5×10⁻¹⁰ s

Energy stored in a capacitor

The energy stored in a capacitor is given by

E = ½CV²

But

E = Pt

Thus,

Pt = ½CV²

Where

E is the energy C is the capacitorV is the voltageP is the power t is the time

With the formula (Pt = ½CV²), we can determine the time in each case. Detail below:

1. How to determine the time required to discharge to 2 V

Data obtained from the question include:

Power (P) = 100 wCapacitor (C) = 0.10 μF = 1×10⁻⁷ FVoltage (V) = 2 VTime (t) = ?

Pt = ½CV²

100 × t = ½ × 1×10⁻⁷ × 2²

Divide both sides by 100

t = (½ × 1×10⁻⁷ × 2²) / 100

t = 2×10 s

Thus, the time required to discharge to 2 V is 2×10⁻⁹ s

2. How to determine the time required to discharge to 1 V

Data obtained from the question include:

Power (P) = 100 wCapacitor (C) = 0.10 μF = 1×10⁻⁷ FVoltage (V) = 1 VTime (t) = ?

Pt = ½CV²

100 × t = ½ × 1×10⁻⁷ × 1²

Divide both sides by 100

t = (½ × 1×10⁻⁷ × 1²) / 100

t = 5×10⁻¹⁰ s

Thus, the time required to discharge to 1 V is 5×10⁻¹⁰ s

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What does the word apparent mean in apparent visual magnitude

Answers

The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.

What is visual magnitude?

The brightness of a celestial body is determined by eye estimation with or without optical aid or by other instrumentation equivalent to the eye in spectral sensitivity.

Apparent magnitude:

Apparent magnitude is a measure of how bright the star appears when viewed from Earth.It is a measure of the brightness of a star or other astronomical object observed from Earth. An object's apparent magnitude depends on its intrinsic luminosity and its distance from Earth.

Hence,

The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.

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A graph with vertical axis Energy Unit and horizontal axis Amplitude Unit. A line goes in straight segments from 1 16 to 2 9 to 4 1.
Tara prepared a report to show how the amplitude of waves affects the energy of waves. Is her graphical representation correct? Why or why not?

Answers

The graphical representation of Tara is correct because of energy of the wave depends on the amplitude of the wave.

Energy of a wave

The energy of a wave due to the motion of a spring is calculated as follows;

E = ¹/₂KA²

where;

k is the force constant of the springA is the amplitude of the wave

Thus, the graphical representation of Tara is correct because of energy of the wave depends on the amplitude of the wave.

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Answer:  No, it is not correct because as the amplitude of a wave increases, the energy it carries also increases. This graph shows that as the amplitude increases, the energy decreases.  

Explanation:

A 1.75 kg box is pushed with a 8.35 N force across ground where k = 0.267. What is the net force on the box?

Answers

The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

To find the answer, we have to know more about the basic forces acting on a body.

How to find the net force on the box?Let us draw the free body diagram of the given box with the data's given in the question.From the diagram, we get,

                                 [tex]N=mg\\F_t=ma\\F_t=F-f[/tex]

where, N is the normal reaction, mg is the weight of the box, [tex]F_t[/tex] is the net force, f is the kinetic friction.

We have the expression for kinetic friction as,

                      [tex]f=kN=kmg=0.267*1.75*9.8= 4.58N[/tex]

Thus, the net force will be,

                        [tex]F_t= 8.35-4.58=3.77N[/tex]

Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

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The net force acting on the box is 3.77 N.

We need to learn more about the fundamental forces affecting a body in order to locate the solution.

How can I determine the box's net force?Let's use the information provided in the question to draw the free body diagram of the given box.The diagram gives us,

                             [tex]N=mg\\F_n=F-f[/tex]

where N stands for the normal reaction, mg for the box's weight, is the net force, and f for kinetic friction.

The kinetic friction expression is as follows:

                            [tex]f=kN=kmg=4.58N[/tex]

the net force will be as follows:

                                     [tex]F_n=3.77N[/tex]

Thus, it is clear that the box with a mass of 1.75 kg will experience a net force of 3.77 N when it is pushed across a surface with a coefficient of friction of 0.264.

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If the platinum-based engine is run continuously at 300 k for 1 hour with 0.50 atm of h2 and 0.50 atm of o2 injected for each reaction, approximately what mass of water will be produced?

Answers

About 4.5 mol of water will be created when the platinum-based engine is run continuously at 300 K for an hour with 0.5 atm of H2 and 0.5 atm of O2 injected for each reaction.

For fuel cell engines' electrodes, platinum is a requirement. It acts as an electrocatalyst to speed up the electrochemical reactions needed to induce H2 to release electrons and form H2 ions when it is placed on porous electrodes.

Platinum is particularly well suited as a fuel cell catalyst because it makes it possible for the hydrogen and oxygen reactions to occur at an ideal rate and because it is stable enough to withstand both the intense electrical current density and the complex chemical environment found inside a fuel cell. This allows platinum to function effectively over an extended period of time.

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A 1.5 kg ballistic cart, moving at 2.8 m/s, ejects a 25 g ball vertically with an initial velocity of 6.5 m/s. What is the magnitude of the initial velocity of the ball relative to the ground?
a. 2.8 m/s
b. 9.3m/s
c. 7.1 m/s
d. 6.5 m/s

Answers

The magnitude of the initial velocity of the ball relative to the ground is 9.3 m/s.

What is relative velocity?

Relative velocity is the velocity of an object relative to another moving in the same plane. On frame of reference is used when measuring relative velocity.

The velocity of the ball relative to the ground  is the sum of the velocity of the ballistic cart and the velocity in which the ball is ejected.

The velocity of the ball relative to the ground = 6.5 m/s + 2.8 m/s = 9.3 m/s

In conclusion, relative velocity measures the velocity of an object from a reference point.

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How does the distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n?

Answers

The distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n because:

Option C: The energy difference between adjacent orbit radii decreases with increasing values of the principal quantum number.

What determines the distance of the electrons from the nucleus?

In an atom, an electron is known to be attracted to a given nucleus by the use of "electromagnetic force".

Note that  similar to a baseball, the faster the electron is said to go, the farther away from the nucleus it is known to be seen. Therefore, the electrons in an atom are known to be in a state where they are moving a lot and very fast, so they are said to be far away from their nucleus.

Note also that energy difference between what we call consecutive levels tends to often decreases as well as increases.

Therefore, The distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n because:

Option C: The energy difference between adjacent orbit radii decreases with increasing values of the principal quantum number.

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See full question below

Consider the hydrogen atom. How does the distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n?

The distance difference between adjacent orbit radii varies with increasing values of the principal quantum number.

The distance difference between adjacent orbit radii increases with increasing values of the principal quantum number.

The distance difference between adjacent orbit radii remains constant with increasing values of the principal quantum number.

The distance difference between adjacent orbit radii decreases with increasing values of the principal quantum number.

Determine the lamp wattage required to obtain an illumination level of 50 f-c over a 100 ft2 area if a fixture is used with a CU of 0.75 and 80% of the available light reaches the work surface, the rest being absorbed by walls and other items in the space. Assume a luminous efficacy of 70 lumens/watt.

Answers

Lamp Wattage is utilized with a CU of 0.75 and 80 percent of the available light reaches the work surface, the remaining 20 percent is absorbed by walls and other objects in the space, resulting in an illumination level of 50 f-c over a 100 ft2 area

The term "lumen" refers to the emission of "luminous flux," which is a measurement of the total amount of visible light emitted by a source in a certain amount of time. The illumination level over a 100 ft2 area will be 50 f-c Lamp Wattage with a CU of 0.75 used, with 80 percent of the available light reaching the work surface and the remaining 20 percent being absorbed by walls and other objects in the room.
Total Lamp Wattage = Number of Lamps X Wattage of Each Lamp.
The fixtures' total wattage is 2 x 32, or 64 watts.
Lumen per Fixtures equals Lumen Efficiency (Lumen per Watt) times the Watt of each Fixture
85x 64 = 5440 lumens per fixture.

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If the ocular lens magnifies a specimen 10x, and the objective lens used magnifies the specimen 35x. What is the total magnification being used to observe the specimen?

Answers

Answer:

350x^2

Explanation:

I'm assuming you're saying you're using them together, like stacking them on top of each other, so if that's the case then this is a simple multiplication problem, which can be written as 10x(35x). Solve it and you get 350x^2.

What is accurate about the planet’s climate system?

Answers

The accurate about the planet’s climate system is the wind

because heating near the equator blows the wind to drive the convection cells in the atmosphere, and the friction created by the rotation of the spherical planet in the atmosphere causes the wind to appear to bend left or right across the surface of the planet. ..

The climate system is a highly complex global system consisting of five major components: the atmosphere, the ocean, the cryosphere (cryosphere), the land surface, the biosphere, and the interactions between them.

Solar energy drives the climate by heating the surface of the earth unevenly. Ice also reflects incoming sunlight, further cooling the poles. Temperature differences move the ocean and atmosphere as they work together to disperse heat throughout the globe.

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2. Find rectangular coordinates for the point (6, 240°).

Answers

Answer:

(-3, -3√3)

Explanation:

To convert from polar coordinate to rectangular coordinate, first you have to know these two equations:

[tex]\displaystyle{x=r\cos \theta}\\\displaystyle{y=r\sin \theta}[/tex]

We know that (x,y) is in rectangular coordinate form while (r,θ) is in polar coordinate form.

Therefore, substitute r = 6 and θ = 240° in both equations:

[tex]\displaystyle{x=6\cos 240^{\circ}}\\\displaystyle{y=6\sin 240^{\circ}}[/tex]

After evaluating, you'll get:

[tex]\displaystyle{x=-3}\\\displaystye{y=-3\sqrt{3}}[/tex]

Therefore, substitute x and y in rectangular coordinate form - hence, the answer is (-3, -3√3)

A pulley system is used to lift a 4500 n weight using a 900 n force. if the mass moves 1.0m while the pulley is pulled 6.0m, what is the efficiency of the machine?

Answers

The efficiency of the machine is determined as 83.3 %.

Mechanical advantage of the pulley

M.A = load/Effort

M.A = 4500/900 = 5

Velocity ratio of the pulley

V.R = distance moved by effort/distance moved by load

V.R = 6/1 = 6

Efficiency of the pulley

E = M.A/V.R x 100%

E = (5/6) x 100%

E = 83.3 %

Thus, the efficiency of the machine is determined as 83.3 %.

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Describe the usefulness of frictional force when a soccer player runs with soccer boots

Answers

Frictional force provided by the teeth of the boots which are in contact with the grass in the soccer pitch enables the soccer player to start running and prevents him from slipping and falling.

What is friction?

Friction is the opposition to the relative motion of one object over another at their surface of contact.

Friction is a type of contact force as it requires between the two objects for its effect to be felt.

Friction has both advantages and disadvantages.

On of the advantages of friction is in the ability to walk or run. Friction between the ground and the foot or the boots of a person walking or running enables the person from slipping.

For example, when a soccer player runs with soccer boots, friction enables the runner to start running and prevents him from slipping and falling. The friction is provided by the teeth of the boots which are in contact with the grass in the soccer pitch.

In conclusion, friction enables a soccer player to start running and also prevents him from falling.

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The radial velocity method preferentially detects: Choose one: A. all of the above described planets equally well. B. small planets far from the central star. C. small planets close to the central star. D. large planets close to the central star. E. large planets far from the central star.

Answers

The radial velocity method preferentially detects large planets close to the central star

what is the Radial velocity:

The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.

This is due to the fact that low mass stars are more affected by the gravitational tug of planets.

When a planet orbits around a star, the star wobbles a little.

From this, we can determine the mass of the planet and its distance from the star.

hence we can say that,

option D is correct.

The radial velocity method preferentially detects large planets close to the central star

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a 1200 kg car rolling on a horizontal surfact has a speed of 25 m/s when it strikes a horizontal coiled spring and is brought ot rest in a distance of 2.5m. what is the spring constant of this spring

Answers

The required spring constant:

The spring constant of the spring is [tex]12\times 10^4 \text{ N/m}[/tex].

Calculation:

The mass of the car is m=1200 kg, the speed of the car is v=25 m/s, and after colliding the spring is brought to rest at a distance of x=2.5m. Let the spring constant of the spring is, k.

From the conservation of energy,

Total initial kinetic energy= Total final potential energy of the spring

Therefore,

[tex]\frac{1}{2}mv^2=\frac{1}{2}kx^2[/tex]

Now, substituting the values of the mass of the car, speed of the car, and displacement, we get:

[tex]$$\begin{aligned}1200\times(25)^2&=k\times (2.5)^2\\\Rightarrow k&=\frac{1200\times(25)^2}{(2.5)^2}\\&=12\times 10^4 \text{ N/m}\end{aligned}$$[/tex]

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