an amplifier is formed by cascading 2 amplifiers with the following transfers functions. what is the low-frequency gain, gain at the cut-off frequency and the value of the cut-off frequency?

First generation computers were also referred to as vacuum-tube computer and they can be defined as a type of computer system that were designed and developed to make use of vacuum tubes for their logic circuitry.

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Complete Question?

What are the features of first generation computers?

Answer:

The reference line helps you achieve the precise connection of Walls for clean intersections.

Explanation:

Reference Lines allow you to place lines on the plot at specific locations to mark important values. You could use these to mark control limits or to indicate a trend line for a set of data.

A high compression ratio may result in compressor failure.

A compressor refers to a mechanical device that is designed and developed to provide power to refrigerators, especially by increasing the pressure on air or other applicable gases.

According to heating, ventilation, and air conditioning (HVAC) information, a high compression ratio of 8: 1 or higher is most likely to result in compressor failure.

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Basic speed law requires individuals driving at speeds that are reasonable and prudent for conditions.

This is defined as the rate of change of the position of a body with respect to time and the unit is metre per second.

The basic speed law states that speeds which are reasonable and prudent should be adopted by drivers so as to avoid accidents and potential risks to other road users. Appropriate punishment are also meted out to defaulters in this type of scenario.

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The three ways that research can facilitate the work of building technicians is that:

Building technicians are known to be people who help with some tasks around construction projects and building works.

Note that building technician overseeing a scope of tasks such as monitoring build progress and as such The three ways that research can facilitate the work of building technicians is that:

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The capacitance is affected is that the capacitance increases because of the insertion of Teflon.

A `is known to be a form of a device that is said to be used to save some amount of charges in any electrical circuit.

Note that the capacitor functions on the principle that the capacitance of a conductor is said to increases if an earthed conductor is  taken close to it.

Hence, The capacitance is affected is that the capacitance increases because of the insertion of Teflon.

See full question below

A dielectric material, such as Teflon®, is placed between the plates of a parallel-plate capacitor without altering the structure of the capacitor. The charge on the capacitor is held fixed. How is the electric field between the plates of the capacitor affected?

The electric field is not altered, because the structure remains unchanged.

The electric field becomes zero after the insertion of the Teflon®.

The electric field decreases because of the insertion of the Teflon®.

The electric field becomes infinite because of the insertion of the Teflon®.

The electric field increases because of the insertion of the Teflon®.

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A Weave lane is a single lane used by drivers to enter and exit a freeway.

Weave lanes are known to be lanes that acts as an entrance and exits for a lot of cars in highways.

Hence, one can say that A Weave lane is a single lane used by drivers to enter and exit a freeway.

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Answer:

The wheel will go through 1146 revolutions in 5 minutes.

Explanation:

We can the formula:

[tex]\boxed{\omega = \frac{2 \pi}{T}}[/tex]

where

ω ⇒ angular speed (24 rad/s),

T ⇒ time period (? s),

and solve for T to find the time it takes for the wheel to complete one revolution.

⇒  [tex]24 = \frac{2 \pi}{T}[/tex]

⇒  [tex]T = \bf \frac{2 \pi}{24}[/tex]  s

This means it takes [tex]\bf \frac{2 \pi}{24}[/tex] seconds for the wheel to complete one revolution.

Now, using the unitary method,

In [tex]\frac{2 \pi}{24}[/tex] seconds          ⇒    1 revolution completed

In 1 second              ⇒    1 ÷ [tex]\frac{2 \pi}{24}[/tex]   =  [tex]\frac{24}{2 \pi}[/tex]  revolutions completed

In (5 × 60 = ) 300s  ⇒     [tex]\frac{24}{2 \pi}[/tex]   ×  300   = 1145.9

                                                            ≅ 1146 revolutions completed

Maximum absolute values of the shear = 28 KN

Maximum absolute values of bending moment = 5.7 KN.m

A) We can see the beam loaded in the first image attached.

For the shear diagram, let us calculate the shear from point load to point load.

From A to C, summing vertical to zero gives; ∑fy = 0: -20 - V = 0

V = -20 KN

From C to D, summing vertical to zero gives; ∑fy = 0: -20 + 48 - V = 0

V = 28 KN

From D to E, summing vertical to zero gives; ∑fy = 0: -20 + 48 - 20 - V = 0

V = 8 KN

From E to B, summing vertical to zero gives; ∑fy = 0: -20 + 48 - 20 - 20 - V = 0

V = -12 KN

For the bending moment diagram, let us calculate the bending moment from point load to point load.

At point A, the bending moment would be zero. Thus, M_A = 0 KN.m

At point C, taking moment about point C and equating to zero gives;

M_C = 0. Thus; 20(0.225) + M = 0

M = -4.5 KN.m

At point D, taking moment about point D and equating to zero gives;

M_D = 0. Thus; 20(0.525) - 48(0.3) + M = 0

M = 3.9 KN.m

At point E, taking moment about point E and equating to zero gives;

M_D = 0. Thus; 20(0.75) - 48(0.525) + 20(0.225) + M = 0

M = 5.7 KN.m

At point B, taking moment about point E and equating to zero gives;

M_E = 0. Thus; 20(1.05) - 48(0.825) + 20(0.525) + (20 * 0.3) + M = 0

M = 2.1 KN.m

2) From the attached diagrams, we can deduce that;

Maximum absolute values of the shear = 28 KN

Maximum absolute values of bending moment = 5.7 KN.m

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The thermal energy when the spark-ignition engine operates on an Otto cycle with a compression ratio of 9 and temperature limits of 30°C and 1000oC is 58%.

From the information given, we are told that spark-ignition engine operates on an Otto cycle with a compression ratio of 9 and temperature limits of 30°C and 1000oC.

The thermal energy will be:

= 1 - 1/(1.4 - 1)

= 0.58

= 58%

Also, the mass flux of air will be illustrated below:

T2 = 729.70k

W = 224.60kj

Therefore, the mass flux will be:

= 500/224.60

= 2.226kg/s

In conclusion, the the mass flux will be 2.226kg/s.

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The Answer is D. The technician should remove jewelry

Explanation: A technician has been given a PC that is not powering up. After brief troubleshooting, the technician comes to the conclusion the power supply needs to be replaced. Which of the following is the NEXT step in the process of performing the repair?

Answer:

Measuring elevations

Explanation:

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The higher level of acceleration should be used when accelerating on a short highway entry ramp.

Given data:

When accelerating on a short highway entry ramp, you should use a higher level of acceleration to safely merge with the traffic already on the highway. This is particularly important when the entry ramp is short, as you need to reach the speed of the highway traffic and find a suitable gap to merge into the flow.

Using a higher level of acceleration allows you to match the speed of the vehicles on the highway more quickly and efficiently, reducing the risk of causing disruptions or potential hazards. It's essential to accelerate smoothly and decisively to ensure a safe merge onto the highway. Always follow traffic rules and guidelines while merging onto highways to ensure the safety of yourself and others.

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The net radiation heat transfer between the two plates per unit surface area of the plates with shield and without shied are respectively; 2282.76 W/m² and 9766.75 W/m²

We are given;

Temperature 1; T₁

Temperature 2; T₂

Temperature 3; T₃

Emissivity 1; ε₁ = 0.3

Emissivity 2; ε₂ = 0.7

Emissivity 3; ε₃ = 0.2

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with shield is;

Q'₁₂ = σ(T₁⁴ - T₂⁴)]/[((1/ε₁) + (1/ε₂) - 1) + ((1/ε₃,₁) + (1/ε₃,₂) - 1)]

Q'₁₂ = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[((1/0.3) + (1/0.7) - 1) + ((1/0.15) + (1/0.15) - 1)]

Q'₁₂,shield = 2282.76 W/m²

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with no shield is;

Q'₁₂,no shield = σ(T₁⁴ - T₂⁴)]/((1/ε₁) + (1/ε₂) - 1))

Q'₁₂,no shield = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[(1/0.3) + (1/0.7) - 1)]

Q'₁₂,no shield = 9766.75 W/m²

Then the ratio of radiation heat transfer for the two cases becomes;

Q'₁₂,shield/Q'₁₂,no shield = 2282.76/9766.75 = 0.2337 or 4/17

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if two 1.5 ya alt batteries are connected to head to the tail the voltage is 3.0 volt it is the because the battery is insidious reduce a voltage equal to number of battery is multiplied by the voltage of individual

Volume load balancing method is supported in equal cost multipath (ECMP) load balancing when SD-WAN is enabled.

Load balancing means are regarded as a form of an algorithms or method that is used to rightly share an incoming server request or traffic in the midst or among servers that is from the server pool.

Note that Volume load balancing method is supported in equal cost multipath (ECMP) load balancing when SD-WAN is enabled as that is its role.

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The fence height, additional structures, and architectural design are generally categorized under covenants.

The primary private land-use control is known to be a form of a deed restrictions, that hinders what a person can do on the property as regards to the owner.

Note that in the case above, the fence height, additional structures, and architectural design are generally categorized under covenants.

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The equivalent cost per mile is mathematically given as

Equivalent kilometer =  0.61

Distance is a measure of the distance between two places. Depending on context, the term "distance" might refer to a precise measurement or an approximation based on other factors. |AB| can be used to represent the distance between two points.

Generally, the equation for Equivalent annual cost  is  mathematically given as

EAC= $ 25,000 ( A/P, 10% , 3 years ) + $ 900 + $ 0.22 * 22,000 - $ 8000 ( A/F , 10% , 3 years)

Therefore

EAC= $ 25,000 * 0.402115 + $ 5740 - $ 8000 * 0.302115

EAC= $ 13,375.955

In conclusion, the Equivalent cost per kilometer

Equivalent kilometer [tex]=\frac{ 13,375.955}{22,000}[/tex]

Equivalent kilometer =  0.61

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The Travel Speed at which the welding operation can be accomplished is given as 7.147mm/s. See the computation below.

The travel speed of the welding flame or gun across the workpiece is simply measured in millimeters per minute.

Travel speed, along with voltage and amperage, is one of three factors in arc welding that affect the amount of heat input.

We are given the following:

Melting temperature = 1650 K

k = (3.33 * 10⁻⁶) * (1,650)²

k = 9.066 J/mm^3

The formula for velocity here is given as:

V = f1 * f2 * Rh / (k*A)

V = 0.9 * 0.6 * 3000 / (9.066*25)

V = 7.147 mm/s

Hence, the Travel Speed at which the welding operation can be accomplished is given as 7.147mm/s.

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Answer:

Continued and/or excessive heat and centrifugal force on turbine engine rotor blades is likely to cause creep.

Explanation:

Creep is a technical term for permanent elongation that happens over time. Heat will result in the rotor blades' material becoming less dense which will allow the material to stretch since the force is centrifugal.

If your crew is the first to arrive on the scene of a major MCL, The major aspect of your scene size-up will be to Make a sweep to determine what needs must be met. Option D. This is further explained below.

Generally, If your team is the first to arrive at the scene of a significant MCL, the most important part of your scene size-up will be to do a sweep to identify the requirements that need to be satisfied. Choose option D.

In conclusion, A medial collateral ligament (MCL) injury occurs when the ligament on the inside of the knee is stretched, partially torn, or completely ruptured. Most knee injuries are caused by an excessive amount of valgus stress on the knee, which is one of the most prevalent.

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CQ

If your crew is the first to arrive on the scene of a major​ MCI, what will be a major aspect of your scene​ size-up?

A.

Make an initial scene report to the communications center.

B.

Control​ on-scene communication as help arrives.

C.

Prevent uncoordinated or undirected activity at the scene.

D.

Make a sweep to determine what needs must be met.

The strategies for dealing with the problem of self-occlusion in object data capture are:

Occlusion is known to often takes place if  two or more objects are seen too close and are seen to be merged or combine with one another.

Note that in the case above, The strategies for dealing with the problem of self-occlusion in object data capture are:

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The time at which the acceleration is zero is given as 4.66 seconds

First we have to solve for the velocity. To do this, we would have to take the derivative.

[tex]s = e^-0.5t (3 t - 2)[/tex]

Then velocity =

[tex]ds/dt = e^-0.5t (4 - 1.5 t)[/tex]

The acceleration can be gotten by finding the second derivative

[tex]a = dv/dt = e^-0.5t (.75 t - 3.5)[/tex]

To find t at acceleration = 0

We have

[tex]0 = e^-0.5t (.75t - 3.5)[/tex]

This gives t to be

t = 4.66 sec

The displacement of a particle which moves along the s-axis isgiven by

s = (-2+3t)e^(-0.5t), where s is in meters and t is inseconds. Plot the displacement, velocity and acceleration versustime for the first 20 seconds of motion. Determine the time atwhich the acceleration is zero.

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A broken yellow line on the pavement tells that the adjacent lane is traveling in the opposite direction and passing is permitted.

A broken white line on the pavement show that the adjacent lane is traveling in the same direction and passing is permitted.

Pavement markings are known to be tools that are used to pass infor or messages to roadway users.

Note  that they tell the part of the road that one need to use, give information about conditions ahead, and others

Note that A broken yellow line on the pavement tells that the adjacent lane is traveling in the opposite direction and passing is permitted.

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"1/2" is the right response to this question. Approximately half of the governor gear in vertical crankshaft engines that have a slinger or governor gear and the correct amount of oil in the crankcase is placed above the oiled surface. Draining the oil from the top oil fill tube, as well as the fuel tank and the engine, should be done when the governor gear is about halfway through its rotation.

This is further explained below.

Generally, Engine connecting rods are joined to the crankshaft through the crank mechanism, which is made up of many rotating parts, including the crankshaft, the crankpins, and the crankshaft gears.

In conclusion, "1/2" is the right answer. About half of the governor gear is visible above the oil surface in vertical crankshaft engines with a slinger or governor gear. In order to drain the oil from the top oil fill tube, both the fuel tank and the engine should be at about half of the governor gear after it is completed.

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The option that best describes electronic stability control are:

The electronic stability control is known to be that which helps to hinder loss of control in regards to curves and emergency steering maneuvers and it often stabilizes  the car if it begins to move off an intended path.

Hence, The option that best describes electronic stability control are:

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An expression for the voltage drop between inverter and PUC

[tex]V D \rightarrow \frac{I(\Omega / k f t) d}{2770}$[/tex]

This is further explained below.

Generally, the equation for Voltage drop is  mathematically given as

[tex]V=\frac{I R}{V}[/tex]

Therefore

[tex]\%$ Voltage drop $=\frac{I R}{V} * 100\\\\$\rightarrow \frac{100 I(\Omega / 15 f t) d}{1000 V_{p}}\\\\$V_{P}=277 \mathrm{~V}$[/tex]

[tex]V D=\frac{I(\Omega / \mathrm{kft}) d}{10 * 2770} \rightarrow \frac{I(\Omega / \mathrm{kft}) d}{2770} \mathrm{~V}\\\\$\% V D \rightarrow \frac{I(\Omega / k f t) d}{2770}$[/tex]

In conclusion, the expression for the voltage drop between inverter and PUC

[tex]V D \rightarrow \frac{I(\Omega / k f t) d}{2770}$[/tex]

CQ

An inverter has a balanced 3-phase, 277/480 V output and is installed a distance, d, ft from the point of utility connection. The DC/AC converter is shown below in the inverter. And the distance d is the physical separation between this DC/AC converter and the PCC.

Derive an expression for the voltage drop between inverter and PUC in terms of d using the basic equation %VD =100IR/V.

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Answer: The red color on the cylinder is indicative of the material's flammability.

Explanation:

The protection that  must be provided when installing a cable in a notched stud or joist are:

If a nonmetallic cables is said to pass through holes or slots in metal framing members, the cable that need to ]be protected is through bushings or grommets and it is used to cover all metal edges and rightly fastened in the opening before one can install the cable.

Hence, The protection that  must be provided when installing a cable in a notched stud or joist are:

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Answer:

passage of the English will of right