The electric field strength at point (x,y) = ( 25 mm ,0cm) is =16321.0769 N/C
The electric field strength at point (x,y) = (0cm, 25 mm) is =35321.58999 N/
What is meant by electric strength?An insulating substance can withstand a certain voltage at its electric strength before losing its ability to insulate. The thickness of the insulating material, as well as the test technique and conditions, will all affect the value for the electric strength.To avoid flash over before breakdown, samples with a thickness of 2mm or more are often examined in oil. Once the breakdown voltage and sample thickness have been determined, the dielectric strength may be estimated. Dielectric strengths for the majority of polymers range from 10 to 30 kV/mm, which is a respectable value.A material's capacity to withstand large voltage swings without experiencing current breakdown is measured by its dielectric strength.To learn more about electric strength refer to:
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The electric field strength at point (x,y) = ( 20 mm ,0cm) is =16321.0769 N/C
The electric field strength at point (x,y) = (0cm, 20 mm) is =35321.58999 N/C
What distinguishes an electric field from an electric field of strength?A vector is a quantity with both a magnitude and a direction, like the electric field. The vector's magnitude corresponds to the electric field intensity.
What do you mean by electric field?Each point in space has an electric field associated with it when there is charge present in any form. E, often known as electric field strength, electric field intensity, or just the electric field, is a mathematical constant that expresses the strength and direction of an electric field.
Given:
Charge = 5.0 nC
x = 25 mm, y = 0 cm
The electric field at any given point of the dipole is given as:
E= (KP) ÷ (r^2 + a^2)^3/2
Where:
K = 9x10^9 Nm^2/c^2 (coloumb constant)
P = (0.003) (5x10^-9c) which is the movement of the dipole
(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.
r= the point, in the question above is 20mm = 0.02m
Now, the electric field (E),
E = (KP) ÷ (r^2 + a^2)^3/2
= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2
= 0.135 ÷ (8.271513x10^-6)
=16321.0769 N/C
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A 15,000 kg rocket traveling at +230 m/s turns on its engines. Over a 6. 0 s period it burns 1,000 kg of fuel. An observer on the ground measures the velocity of the expelled gases to be −1,200 m/s
First, we need to calculate force of the rocket.
What is Velocity?
Velocity is a vector quantity that describes the rate and direction of a body's motion. It is represented by an arrow pointing in the direction of motion and having a length equal to the rate of motion. Velocity is a fundamental concept in classical mechanics and is defined as the rate of change of position with respect to time.
Calculate the force of the rocket:
F = ma = (15,000 kg)(230 m/s) = 3,450,000 kg m/s2
Calculate the force of the exhaust gases:
F = ma = (1,000 kg)(-1,200 m/s) = -1,200,000 kg m/s2
Calculate the net force on the rocket:
Net Force = F_rocket + F_exhaust = 3,450,000 kg m/s2 + (-1,200,000 kg m/s2) = 2,250,000 kg m/s2
Calculate the acceleration of the rocket:
a = F/m = (2,250,000 kg m/s2)/(15,000 kg) = 150 m/s2
Calculate the change in velocity of the rocket:
Δv = a × t = (150 m/s2)(6.0 s) = 900 m/s.
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Select the correct answer. if a running system has a total change in the heat of 315 joules, and it is running at a temperature of 350 k, what is the entropy?
a. 1.54 joules/kelvin
b. 0.847 joules/kelvin
c. 1.22 joules/kelvin
d. 0.900 joules/kelvin e. 0.762 joules/kelvin
If a running system has a total change in the heat of 315 joules, and it is running at a temperature of 350 k, the entropy will be e. 0.762 joules/kelvin.
Entropy is essential for understanding the behavior of many physical systems, such as in thermodynamics, statistical mechanics, and thermochemistry.
Entropy can be used to analyze the efficiency of a system, as well as its stability and predictability.
This can be calculated by using the formula S = ΔQ/T, where S is entropy, ΔQ is the total change in heat and T is temperature. In this case ΔQ = 315 Joules and T = 350K.
Plugging these values into the equation gives us S = 315/350, which equals 0.762 joules/kelvin. Hence, option e is correct.
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A car moves at 45 kilometers per hour.
Which option describes if the given value is speed or velocity?
speed, because there is a mention of time speed, because there is a mention of time
velocity, because there is a mention of time velocity, because there is a mention of time
velocity, because there is no specific directionvelocity, because there is no specific direction
speed, because there is no specific direction
Since this car moves at 45 kilometers per hour, an option which describes if the given value is speed or velocity include the following: D. speed, because there is no specific direction.
What is speed?In Science, speed can be defined as the distance covered by a physical object per unit of time. This ultimately implies that, speed is a scalar quantity because it has magnitude but no direction.
What is velocity?In Science, velocity can be defined as the distance covered by an object per unit of time in a specific direction. This ultimately implies that, velocity is a vector quantity because it has both magnitude and direction.
In this context, we can reasonably infer and logically deduce that a car that moves at 45 kilometers per hour describes speed rather than velocity, because there is no specific direction mentioned.
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Since no direction is specified, the correct answer is the last option which is speed, because there is no specific direction
Difference Between Speed and VelocitySpeed is a scalar quantity. That is, it has only magnitude but no direction. While velocity is a vector quantity. That is, it has both magnitude and direction.
If a car moves at 45 kilometers per hour, only the car magnitude is given but no direction.
The option that describes if the given value is speed or velocity is speed, because there is no specific direction
Therefore, the correct option is speed, because there is no specific direction.
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If you cool down a container of gas, there will be _______ collisions with the side of the container, resulting in ______ pressure.
A container of gas might lose pressure by cooling down because there are fewer collisions with the container's side.
What transpires when a container of gas is cooled?When the gas in the supplied sealed jar is chilled, the molecules travel more slowly. This occurs because when the temperature drops, gaseous particles get closer to one another (on cooling). Upon cooling, there are also fewer accidents.
How does a gas's compression affect the frequency of collisions inside a container?The container's capacity has shrunk, which reduces the distance the gas molecules must travel before colliding. As a result, there will be more collisions per second, increasing the pressure.
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A student is pushing on a heavy door, trying to slide it open. Their friend stands behind them and helps push. How have the forces changed
There will be an increase in the net force.It appears that an object is moving faster, slower, or in a different direction.
What actually constitutes force?There are several instances of forces in daily life, including:heft and powerthe force a bat applies to a ball.the pressure that a hair brush applies to hair when brushing it.the pressure your foot applies to the pedal when you're riding a bike.
What occurs when a force shifts?An object can change its size or shape, begin moving, stop moving, accelerate, or decelerate as a result of a pressure applied on it.
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Suppose a 51-N sled is resting on packed snow. The coefficient of kinetic friction is 0.13. If a person weighing 680 N sits on the sled, what force is needed to pull the sled across the snow at constant speed
95 N much force is needed to pull the sledge at a constant speed.
Explain force.A force in physics is an effect that has the power to alter what an object moves. Every object with mass might travel faster or at a different rate as a result of a force. A push or a pull made natural sense when describing force. Since forces are vector quantities, they own both size and direction.
The sled is being subjected to the following horizontal forces:
F = applied force.
Fr = friction force.
And the following vertical forces:
N = normal force.
W =combined weight of the person and the sled
The second law of Newton states:
F = m * a
where the object's mass is "m" and its acceleration is "a"
So, in the horizontal direction:
F - Fr = m *a
Determining the force, F, required to keep the sled moving at a constant pace (acceleration = 0). Then,
F - Fr = 0
F = Fr
The applied force must have a magnitude equal to or greater than the friction force.
The friction force is calculated as follows:
Fr = μ · N
Where μ is coefficient and N represent the normal force, respectively.
Let's use Newton's second law with in vertical direction to determine the normal force:
F = N - W
= m · a
Keep in mind that the sledge is not accelerated vertically so that a = 0:
N - W = 0
N = W
The mass is the total of a weight of a person plus the mass of the sled, and the force is equivalent to the weight:
W = 51 N + 680 N = 731 N
Then:
N = 731 N
Fr = 0.13 · 731 N
Fr = N
Then
F = 95.03 N
As a result, 95 N of force is necessary to pull a sled at a steady pace.
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A skier is pushed from the top of a hill so that he starts moving down the hillside from a height of 100 m with
an initial speed of 0.434 m/s. After traveling 80.4 m, he reaches the bottom of the valley. Due to inertia, he
then continues 70.4 m up another hillside (y = 40 m) and crashes into a snow bank that compressess like a
spring (k = 50 N/m). What is the skiers speed as he crashes into the snow bank? How far does the snow
compress? Assume that you can neglect friction.
Speed as the skier crashes into the snow bank: 0.434 m/s
Distance the snow compresses: 1.544 m
The speed of the skier as he crashes into the snow bank is the initial speed since there is no acceleration due to the lack of friction. The distance the snow compresses is calculated using the following equation:
compression = (mass x velocity2) / (2 x spring constant)
Therefore, compression = (75 kg x 0.4342) / (2 x 50 N/m) = 1.544 m
We can best understand how a diver is able to control his rate of rotation while in the air (and thus enter the water in a vertical position) by observing that while in the air
A) his linear momentum is constant.
B) his potential energy is constant.
C) his kinetic energy is constant.
D) his angular momentum is constant.
E) his total energy is constant.
A diver can regulate his rate of rotation and reach the water in a vertical position because his angular momentum stays constant while he is in the air. This information makes it easier for us to comprehend how this is possible.
As a result, Option D is accurate.
The rotating counterpart of linear momentum in physics is called angular momentum. Given that the total angular momentum is conserved, or remains constant in a closed system, it is an important physical quantity. By dividing the rotational inertia of an item by the angular velocity, one may get its angular momentum. The angular velocity of an item is used to calculate its rotational speed. An object's rotational inertia is what makes turning it challenging. On an ice rink or in an office, someone spinning
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the effect of a stress raiser is more significant for which of the following types of materials?
a Ductile
b.Gaseous
c Volatile
d. Brittle
Option A is the correct Answer. The effect of a stress raiser is more significant for Ductile materials.
Ductility is the ability of a material to be drawn or plastically deformed without fracture. The ductility of steels varies depending on the types and levels of alloying elements present.
Examples: aluminum, copper, and magnesium alloys.
Uses of Ductile materials:
Ductility is mostly used in metalworking, as materials that crack, break or shatter under stress cannot be manipulated using metal-forming processes such as hammering, rolling, drawing, or extruding.High degrees of ductility occur due to metallic bonds, which are found predominantly in metals; this leads to the common perception that metals are ductile in general.The ductility of steel varies depending on the alloying constituents. Increasing the levels of carbon decreases ductility.To know more about Ductile materials:
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A baseball has a momentum of 6.0kg*(m)/(s) south and a mass of 0.15kg. What is the baseball's velocity?
A baseball weighs 0.15kg and has a south momentum of 6.0kg m/s. The speed of the baseball was (v) = 40 m/s south.
It's a physical magnitude that measures the product of the mass by the velocity of a particle. Its units in the International System is kg. m/s and the formula is
p = mv
where
m is the mass of the object
v is its velocity
In this problem, we know:
p = 6.0 kg m/s is the momentum of the baseball
m = 0.15 kg is its mass
Therefore, we can re-arrange the equation to find the baseball's velocity:
v = p/m
v = 6.0/0.15
v = 40 m/s south
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2. A 1.0 kg roller coaster is at the top of a 25m hill, and has a velocity of 8 m/s.
a. Determine the velocity of the roller coaster when it is halfway down the hill, at height of 12.5 m. (Ignore Friction)
b. What is the velocity of the roller coaster at the bottom of the hill assuming a force due to friction of 3.0 N, and the length of the hill is 45.0 m.
SHOW ALL WORK!
The car's acceleration can be calculated as: a = v2/R = (18.0 m/s) 2/(12.0 m) = 27.0 m/s2. The conventional method can be used to determine net force: 13500 N is equal to Fnet = m•a = (500 kg)•(27.0 m/s2).
What happens to a roller coaster's speed as it climbs a hill?It may slow down or decelerate when traveling uphill or straight ahead. Roller coasters accelerate as they travel down hills due to the force of gravity dragging them downward.
How do roller coasters use math?Calculus and other fundamental mathematical concepts are used to calculate the maximum speed, the angles of ascent and descent, and the height necessary for the automobile to climb the next hill. The roller coaster's safety is further ensured by these calculations.
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1) compare the isochron map to the topographic map of the seafloor in the previous investigation. which seafloor features are associated with young crust what can you infer from this?
2) how does the age of the seafloor change as you move away from these features?
what can you conclude from this evidence?
From this evidence, you can conclude that the seafloor is not a static feature and is constantly being renewed through the movement of tectonic plates and the creation of new crust at mid-ocean ridges. The age of the seafloor can be used to help understand the history and dynamics of the Earth's crust and how it has evolved over time.
HOPE IT HELPS!Roller Coaster Physics Gizmo
With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the bottom of this hill from its starting height. To do this start by setting the kinetic and potential energy equations equal to one another. K= U
1/2mv^2 = mhm
a. Use algebra to solver for the speed. V=
b. With the no friction, does the final speed depend on the mass of the car?
c. With no friction, does the final speed depend on the steepness of the hill?
d. What is the final speed of the car if the height of the hill is 55 cm (. 55m)?
A) Using algebra, the required speed V=(2gh)1/2
B) With the no friction, the final speed does not depend on the mass of the car.
C) With no friction, the final speed does depend on the steepness of the hill.
D) The final speed of the car if the height of the hill is 55 cm is 3.569 m/s.
Given that there is no friction considered. Thus, the total energy of the system can be considered as conserved.
Thus, sum of kinetic and potential energy will be constant.
K = U
mu 2 = mgh ......................................(1)
m = mass of object
v = speed of object
g = acceleration due to gravity = 9.8 m/s2
h = height of object with respect to a reference position
Thus for an object at a height from ground, will have its potential energy converted to kinetic energy during it's descent.
(A) from (1)
mv2 = 2mgh
Thus, v2 = 2gh
v = (2gh)1/2
this, is the velocity of an object from conservation of energy.
(B) with no friction, the enrgy is taken to be conserved. from the answer of (A), we know,
v = (2gh)1/2.
clearly this equation doesn't depend on mass.
thus, final speed doesn't depend on the mass.
(C) Given height of hill , h = 65cm = 0.65 m
from (1), v = (2gh)1/2.
the potential energy of car at the hill top = mgh
this potential energy gets entirely converted to kinetic energy at the bottom of hill due to conservation of energy. Thus
v = (2 x 9.8 x 0.65)1/2
= 3.569 m/s
Thus, the final velocity of the car is 3.569 m/s
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A 1000-kg car is moving at 30 m/s around a horizontal unbanked curve whose diameter is 0. 20 km. What is the magnitude of the friction force required to keep the car from sliding?
The friction force required to keep the car from sliding is 9000N.
Calculation-mass of car, m = 1000 kg
speed , v = 30 m/s
diameter , d = 0.2 km
r = 100 m
for the car to keep from sliding frictional force is required, ff = m*v^2/r
ff = 1000 * 30^2 /100
ff = 9000 N
the friction force required is 9000 N
What kind of force does an automobile exert on a straightaway?Simply put, an unbanked curve (or turn) is a curve that is flat on the ground (parallel to the horizontal). A force of friction applies to the car as it drives along one of these curves, keeping it rotating in a circular course.
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Suppose a radio message is sent home by astronauts in a spaceship approaching Mars at a distance of from Earth. How long (in minutes) will it take for the message to travel from the spaceship to Earth
A radio message is sent home by astronauts in a spaceship approaching Mars at a distance of from Earth.
A contact from Mars travels [between 3 and 22] minutes at light speed to reach Earth. Relativity contributes to the fact that the distance between Earth and Mars is 1.26 seconds longer.
A Mars year is roughly equivalent to two Earth years because of Mars' nearly two-fold longer orbital period than the Earth's. Earth and Mars are 57.6 million kilometers (35.8 million miles) from one another, while 401 million kilometers separate them at their farthest point (249 million mi).
The sole means of contact between Earth and Mars are radio and messenger. A courier will undoubtedly require a lot of time. We can determine how long it will take a radio message to travel between the two planets since radio waves travel at the speed of light (299,792 km/s; 186,282 mi/s). When the two planets are at their closest, the one-way voyage takes the fewest amount of time—3.2 minutes.
The time required for a one-way trip is 22.3 minutes when they are the furthest apart. A round-trip message will take between 6.4 and 44.6 minutes to send and receive. Of course, receiving an answer will take the same amount of time in each situation.
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What is the work applied to a 1000kg car when it is pushed 1000m up along a 10- degree incline at a constant velocity. Assume the coefficient of friction between the car and the ramp is 0.30.
The required work applied to a 1000 kg car when it is pushed 1000 m up along a 10- degree incline at a constant velocity is calculated to be 4.6 × 10⁶ J.
Given that,
Mass m = 1000 kg
Displacement d = Δx = 1000 m
Angle of inclination θ = 10°
Coefficient of friction μ = 0.3
The equation for work done is known to be,
W = F × d
We must divide the force of gravity into its component parts and examine the side acting in the x-direction in order to calculate the force of gravity in that direction.
F gx direction = F g sinθ = mg sinθ
The force of friction is directly related to μ times the normal force. The normal force in this situation is equivalent to the y component of the force of gravity.
F gy direction = F g cosθ = mg cosθ
We know force of friction, Ff = μ FN
FN = F gy direction
Ff = μ mg cosθ
We know that our force applied must balance both of these forces,
F applied = mg sinθ + μ mg cosθ
As, W = F × d = (mg sinθ + μ mg cosθ) d = ( 1000× 9.8 sin10° + 0.3 × 1000× 9.8 cos10°) 1000 = (9800 sin10° + 2940 cos10°) 1000 = (0.17 × 9800 + 0.985 × 2940) 1000 = (1666 + 2895.9) 1000 = 4561.9 × 10³ J = 4.6 × 10⁶ J
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A car is traveling for 1638 km for a time period of 6.5 hours. What is the average speed of the car?
Answer:
252 km/hr
70 m/s
Explanation:
s = d/t
answer in km/hr:
s = 1638 km / 6.5 hr = 252 km/hr
if you need the answer in m/s:
s = ((1638 km)(1000 m/km)) / ( (6.5 hr)(60 min/hr)(60 s/min))
= 70 m/s
A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its equilibrium position, what is its instantaneous velocity?
A.Instantaneous velocity cannot be determined without additional information
B.At equilibrium, its instantaneous velocity is less than its maximum but not zero.
C.At equilibrium, its instantaneous velocity is at maximum
D.At equilibrium, its instantaneous velocity is zero.
At the instant when a mass is at its equilibrium position when undergoing simple harmonic motion, its instantaneous velocity is its maximum.
Therefore the answer is C. At equilibrium, its instantaneous velocity is at maximum
The simple harmonic motion is periodic motion that oscillates around an equilibrium position. At the equilibrium position, the net force on the mass is zero. Therefore, the mass is not accelerating, so its instantaneous acceleration is zero.
The motion is periodic, meaning it repeats itself at regular intervals of time. In the case of a mass on the end of a spring, the spring exerts a force on the mass that acts to bring it back to its equilibrium position. When the mass is at the equilibrium position, the spring force is zero, and the mass is not accelerating. Therefore, the acceleration is maximum at it ends and decreases to zero at equilibrium position.
The instantaneous velocity is zero at the end as it changes direction of motion, though the acceleration is decreasing from end position to equilibrium, velocity is increasing. The instant after equilibrium position, the acceleration is in opposite direction decreasing the velocity till it is zero at the end position.
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Why does torque increase with distance?
Torque increases with distance because torque is defined as the force acting on an object multiplied by the distance from the axis of rotation. The farther the force is applied from the axis of rotation, the greater the torque will be.
To understand this, imagine a lever with a weight on the end of it. If the weight is placed closer to the pivot point of the lever, it will take less force to lift the weight than if the weight is placed farther away from the pivot point. This is because the farther the weight is from the pivot point, the greater the torque will be. The same is true for any object that is being rotated around an axis - the farther the force is applied from the axis of rotation, the greater the torque will be.
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You weigh 600 N.
What would you weigh if the Earth were
seven times as massive as it is and its radius
were three times its present value?
Answer in units of N.
Your weight would be 85.7N if the Earth were seven times as massive as it is and had a radius three times that of today since the gravitational pull is reduced by seven times with an increase in radius.
Gravitation is a fundamental interaction in physics that produces attraction between all objects with mass or energy. Of the four fundamental interactions, gravity is by far the weakest, being about ten times less than the strong interaction. A body's mass is a fundamental characteristic. Before the discovery of the atom and the field of particle physics, it was generally thought to be tied to the amount of matter in a physical body. x = 600N/7, x = 85.7N
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If there exists a d such that ad = 0, d > 0, and cd > 0, then is the optimal objective value unbounded?
With an unbounded optimal solution, the feasible region essentially reaches infinity and even the optimal solution is not constrained by the constraints. Resolution.
This seems to be quite uncommon in real life. One or even more constraints may miss; verify the phrasing of the constraints.
The feasible zone effectively extends into infinity as well as the optimal solution is unbound, meaning the restrictions do not place any upper bounds on it. This is incredibly uncommon in real life. If there are any lacking constraints, kindly verify the formulation of both constraints.
Unbounded functions are those that are neither above nor below bounded by such a finite limit. For instance, because it ranges from to, x is an unbounded function. The unbounded function tax would be defined for any real x with the exception of x(2n+1)2.
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What are two way in which early psychological research was biased? What’s an example of bias in psychology?
Psychological research gives us information about the research that psychologists conduct for systematic study and for analysis of the experiences and behaviors of individuals or groups.
Give the two methods on which early psychological research was based.
There are two ways in which psychological research is based and that is the research being androcentric and ethnocentric. Examples of this include the theory of personality and the attachment of the theory.
There are many more biases is well in psychological research which are Citation bias, Language bias, and Outcome reporting bias. The citation bias includes whether the research receives citations or not. Language bias includes when research is published in one language over another. The outcome reporting bias includes that when only some outcomes are reported from a study.
So we can conclude that there are two ways in which early psychological research was biased and that are; when research is androcentric and ethnocentric.
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1. A 10 kg rubber block sliding on a concrete floor (μ=0. 65) 2. A 248 kg object moving at 19 m/s comes to stop over a distance of 38 m. What is the coefficient of kinetic friction between the surfaces? HURRY 50pts and dont take the points just answer the question
The coefficient of kinetic friction between the surfaces is 0.48.
What is kinetic friction?Friction is simply defined as the force that prevents a sliding object from moving. Kinetic friction is a natural phenomenon that disrupts the motion of two or more objects. The force acts in the opposite direction of the motion of the object.
When we stop a car, we use brakes, which is where friction comes into play. When walking, friction is to thank once more. But when we have to stop in the middle of a puddle, things become more difficult because friction is less and cannot help as much.
Solve for a using K3: [tex]$v^2=v_0^2+2 a d$\\[/tex]
[tex]& 19^2=0_0^2+2 a 38 \\& a_x=-4.75 \mathrm{~m} / \mathrm{s}^2[/tex]
[tex]\begin{aligned}& \text F_{\text {net }}=-f_k=m a_x, \text { and } \\& -f_k=\mu_k F_n=\mu_k m g, \text { so we can say } \\& -m a_x=\mu_k \cdot m g \\& \mu_k=\frac{m a_x}{m g}=\frac{-a_x}{g} \\& \mu_k=\frac{-(-4.75)^m / s^2}{9.8}=0.48\end{aligned}$$[/tex]
Thus, The coefficient of kinetic friction between the surfaces is 0.48.
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You bought a can of apricot jam. The contents marked as: net weight: 500g and volume: 400ml is the statement correct?why? and what is the mass of the jam you bought? calculate the density of jam in g/cm
The statement is not correct the mass of the jam is 500g and the density of the jam is 0.125gm/cm³
How to calculate the density?The statement is not correct because mass and volume cannot be used together to describe the contents of a can. Mass is a measure of how much matter is in an object and volume is a measure of the amount of space taken up by an object. So, in this case, the can of apricot jam should just be marked with the net weight in grams.The mass of the jam you bought is 500g.To calculate the density of the jam, we need to divide the mass by the volume. The density of the jam is 500g/400ml = 1.25g/ml. To put this in g/cm3, we need to divide the density by 1000, which gives us 1.25g/ml = 0.125g/cm3.To learn more about density refer to:
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To report the position of an object, first choose a reference point. Then, describe the of the object with respect to the reference point. Next, measure the from the reference point to the object.
We will understand the given concept through an example
The rat serves as your point of reference if you mentioned that the rabbit was to the left of it. You are expressing its position when you specify the distance and direction. The present separation and direction of an object from a reference point is its position.
When something moves with relation to a reference frame, like when a passenger gets off an airline or a lecturer gets up to leave, the object's position changes.the right in relation to a whiteboard. Displacement describes this shift in location.Every location helps you to achieve various location positions.Your position is defined by how you describe your place. The separation in the first illustration is one meter. The reference point helps to locate each and every point.To know more about reference point here
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A cannonball is fired with a velocity of 10 m/s upward from horizontal and 30 m/s to the west. What is the angle and direction of the cannonball
The angle and the direction of the cannonball is calculated to be about 18.435° of west.
Expressed as the ratio between two sides of a right triangle or an angle measure along with a given side, trigonometry can find unknown angle measures and lengths.
Given that,
Velocity of cannonball upward = 10 m/s
Velocity of cannonball to the west = 30 m/s
One of the side lengths reflects the velocity going north (or upward from the horizontal) at 10 m/s. Another side length depicts the speed moving west.
Angle can be calculated by applying trigonometric relation.
tan θ = northward velocity of the cannonball/westward velocity of the cannonball = 10/30
tan⁻¹(tan θ) = tan⁻¹(10/30)
θ = 18.4349°
As, the cannonball was measured from the horizontal, the angle and the direction of the cannonball is about 18.435° of west.
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11. A weightless bar AB is pivoted at its centre and weight of 10N and 30N are attached on side A at 4m and 2m from the pivot respectively. These weights are balanced by a weight of 25N on the other side B. How far is the 25N weight from the pivot?
Answer:
-3.2m
Explanation:
To find the distance of the 25N weight from the pivot, we can use the concept of moments. The moment of a force is the product of the force and the perpendicular distance from the pivot to the line of action of the force.
The total moment about the pivot due to the weights on side A is:
Moment_A = (10N * 4m) + (30N * 2m) = 80Nm
The moment of the 25N weight on side B must be equal and opposite to the total moment of the weights on side A, so we can set up the following equation:
Moment_B = -80Nm
We can solve for the distance of the 25N weight from the pivot by rearranging the equation to solve for x:
x = Moment_B / 25N = -80Nm / 25N = -3.2m
So the distance of the 25N weight from the pivot is -3.2m. This means that the weight is 3.2m to the left of the pivot, since the pivot is taken as the origin for the purpose of calculating moments.
What pressure, in pascals, can you create by exerting a force of 480 N with your tooth on an area of 0.95 mm2
According to the given statement The pressure exerted by the tooth is 506,315.78 Pa.
What is pressure?Pressure is a measure of the force exerted on a surface per unit area. It is a scalar quantity and is measured in units of force per unit area, such as pascals (Pa), pounds per square inch (psi), or atmospheres (atm).
It can be calculated using the formula:
Pressure (Pa) = Force (N) / Area (m²)
Given that the force exerted is 480 N and the area of contact with the tooth is 0.95 mm^2, we can use the formula to find the pressure exerted:
Pressure (Pa) = 480 N / (0.95 x 10⁻³ m²)
To convert mm² to m², we divide by 10⁶
Pressure (Pa) = 480 N / (0.95 x 10⁻³ m²) = 506,315.78 Pa
Hence, the pressure exerted by the tooth is approximately 506,315.78 Pa.
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Why are dynamic flexibility tests not used as often as?
Dynamic flexibility tests are not used as often as static flexibility tests because dynamic flexibility tests involve more subjective measurements.
Static flexibility tests are more common in comparison to dynamic tests because static flexibility tests are easier to replicate. It is difficult to standardize motion-based tests such as dynamic flexibility tests between various subjects, while static flexibility tests are simple and easy to standardize it is because the metrics are fixed and not open to interpretation.
Since, dynamic flexibility tests are hard to perform because they measure the amount of stress on a muscle that is in motion. And it is difficult to assess this among multiple people and to get an accurate picture. That is why these tests are not used as often as static flexibility tests.
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Complete question
Why are dynamic flexibility tests not used as often as static flexibility tests?
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If you are going the same speed, the greater the vehicle _______ the greater the force of impact. florida
If you are going the same speed, the greater the vehicle, the greater the force of impact on the reacting body and greater the inertia of it and greater is its velocity.
Velocity of any body is the speed by which it is travelling along with the direction it has given. velocity is a vector quantity because it has both magnitude and direction. velocity has both magnitude and direction so it different from speed but its magnitude is same as that of speed and we can calculate both as their magnitude are equal. velocity is the measure of the speed of the moving body by which it is moving in the place from one place to another. velocity and speed are the same but they are different in the essence in the form of their type. speed is scalar and velocity is vector. by this primary information we can consider that primarily that if you are going the same speed, the greater the vehicle, the greater the force of impact on the reacting body and greater the inertia of it and greater is its velocity.
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