A(n) _____ is a legal right of ownership of intellectual property.

end-user license

agreement

free and software license

proprietary software license

copyright

Answer:

#include <iomanip>

#include<iostream>

using namespace std;

int main(){

char name[100];

float classp, test, assgn, exam, prctscore,ave;

cout<<"Student Name: ";

cin.getline(name,100);

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; }

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){  cout<<"Test: "; cin>>test; }

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; }

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; }

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; }

ave = (int)(classp + test + assgn + exam + prctscore)/5;

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

return 0;}

Explanation:

The required parameters such as cin, cout, etc. implies that the program is to be written in C++ (not C).

So, I answered the program using C++.

Line by line explanation is as follows;

This declares name as character of maximum size of 100 characters

char name[100];

This declares the grading items as float

float classp, test, assgn, exam, prctscore,ave;

This prompts the user for student name

cout<<"Student Name: ";

This gets the student name using getline

cin.getline(name,100);

This prompts the user for class participation. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; }

This prompts the user for test. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){  cout<<"Test: "; cin>>test; }

This prompts the user for assignment. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; }

This prompts the user for examination. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; }

This prompts the user for practice score. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; }

This calculates the average of the grading items

ave = (int)(classp + test + assgn + exam + prctscore)/5;

This prints the calculated average

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

Answer:

Disadvantages of Napier's bone: It became tedious when the multiplication has to be done with big numbers. It was a much elaborate setup. It was made up of 200 rods placed in a special box.

Answer:

java” xargs grep -i "Hello World”

Answer:

Blind carbon copy (abbreviated Bcc)

Click on the menu item with a paperclip icon that says "Attach a file" or something similar (e.g., "Attach Files")

Click Reply and then select Forward

CC

reply

Hampton was shot and killed in his bed during a predawn raid at his Chicago apartment by a tactical unit of the Cook County State's Attorney's Office in conjunction with the Chicago Police Department and the FBI; during the raid, Panther Mark Clark was also killed and several others were seriously .

Explanation:

Answer:

C. You may become a target of users who wish to make inappropriate contact with you.

Explanation:

Answer:

xy-1

Explanation:

Given expression is :

[tex]x^2-y^2=1[/tex] ..(1)

We need to find the value of [tex]\dfrac{dy}{dx}[/tex].

Differentiating equation (1) wrt x.

[tex]\dfrac{d}{dx}(x^2-y^2)=1\\\\2x-2y\times \dfrac{dy}{dx}=0\\\\2y\times \dfrac{dy}{dx}=2x\\\\y\times \dfrac{dy}{dx}=x\\\\\dfrac{dy}{dx}=\dfrac{x}{y}[/tex]

or

[tex]\dfrac{dy}{dx}=xy^{-1}[/tex]

Hence, the correct option is (c) "xy-1".

The options given above are all correct about the visual aid that best matches each description given.

These are known to be any kind of thing or an instrument that is often used to portray an item or  one that helps people to know something or to remember something.

Conclusively, population clusters within a particular country can be depicted on a  map as well as the other options are also correct.

Learn more about visual aid from

https://brainly.com/question/3610367

Answer:

False

Explanation:

Account of expenses, losses, gains, and incomes is called the Nominal account. Profit and Loss Account contains all indirect expenses and indirect incomes of the firm. Therefore, Profit and Loss Account is a Nominal Account and not a real account.

:)

Answer:

See attachment 1 for code

See attachment 2 for the output of permuting letters of parba

See attachment 3 for the output of permuting letters of arbca

Explanation:

The program was implemented in C

The program uses a recursive function letterpermutation and a swap function to successfully implement the requirement of this question.

The letterpermutation function is defined here

void letterpermutation(char *mystring, int index1, int index2) {  

This lets the program writes to a file

  FILE *fptr;

This opens the file in an appending mode

  fptr = fopen("q3out.txt","a");

int i;

This checks for unique strings.

if (index1 == index2) {

If found, this appends the string to the text file

   fprintf(fptr,"%s\n",mystring); }

If otherwise

else{  

This iterates through the string

for (i = index1; i <= index2; i++)   {

The swap function is called to swap the characters of the string

 swap((mystring+index1), (mystring+i));  

This calls the function, recursively

letterpermutation(mystring, index1+1, index2);  

This further swaps the characters of the string

swap((mystring+index1), (mystring+i));  

} } }  

The swap function begins here and what it literally does is that it swaps characters of the input string to create a new string

void swap(char *ch1, char *ch2) {  

char temp;  

temp = *ch1;  *ch1 = *ch2;  *ch2 = temp; }

The main function begins here

int main() {  

This declares and initializes the string

char mystring[] = "ABCd"; // The string here can be changed

This calls the function to permute the string

letterpermutation(mystring, 0, strlen(mystring)-1);  

return 0; }

Answer:

There are at least five areas that are covered by computer applications, and five of those are business, government, military, manufacturing, and music. There are also other areas such as scientific and the role of technology in our society is growing annually.

Computers have now for several decades brought automation to the table in small, medium, and large businesses. There are word processing and spreadsheet applications for small businesses all the way up to enterprise-wide applications that cover every aspect of a large business such as accounting, inventory, shop floor, management, and feature real-time reporting capability that can give a snapshot glimpse of the financial position of a company at any point in time.

The government has a wide variety of computer applications. Government uses many of the same tools as small to large businesses in desktop type applications and many that are much more advanced that are used in the military.  Manufacturing applications involve computer-aided design and applications that are used to track production from the time a raw material is moved into the warehouse all the way to the production floor and back into the warehouse as a finished good.  

Military only applications include systems that use GPS in missiles to hone in on targets from miles away. There are all kinds of other applications some of which are secret in nature and the public does not become aware of these until a war is underway. Computer applications in music can help to transcribe and compose music as well as provide accompaniment for a musician to practice with.  

Expect the number of computer applications in all of these fields to become more common in the future. Expect many applications to take the place of people to save money in a cash-crunched economy where everyone is looking for more ways to save money and cut costs.

Explanation: