An object of height 8.50 cm is placed 20.0 cm to the left of a converging lens with a focal length of 12.0 cm. Determine the image location in cm, the magnification, and the image height in cm.

Answers

Answer 1

The image distance is 33.3 cm while the image height is 14.2 cm.

What is a converging lens?

A converging lens will always have a positive focal length hence, we have to find the object distance as follows;

1/f = 1/v + 1/u

1/12 = 1/v + 1/20

1/v = 1/12 - 1/20

1/v = 0.08 - 0.05

v =33.3 cm

Now;

Magnification =  33.3 cm/20.0 cm =1.67

M = Image height/Object height

1.67 =  Image height/8.50 cm

Image height = 1.67  * 8.50 cm

Image height = 14.2 cm

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Related Questions

A mole of a monatomic ideal gas at point 1 (101 kPa, 5 L) is expanded adiabatically until the volume is doubled at point 2. Then it is cooled isochorically until the pressure is 20 kPa at point 3. The gas is now compressed isothermally until its volume is back to 5 L (point 4). Finally, the gas is heated isochorically to return to point 1.
a. Draw the four processes and label the points in the pV plane.
b. Calculate the work done going from 1 to 2.
c. Calculate the pressure and temperature at point 2.
d. Calculate the temperature at point 3.
e. Calculate the temperature and pressure and point 4.
f. Calculate the work done going from from 3 to 4.
g. Calculate the heat flow into the gas going from 3 to 4. g

Answers

Answer:

(a). Check attachment.

(b). 280.305 J.

(c). 31.81 kpa; 38.26K.

(d). 24.05K.

(e). 24.05k; 40kpa.

(f). -138.6J.

Explanation:

(a). Kindly check the attached picture for the diagram showing the four process.

1 - 2 = adiabatic expansion process.

2 - 3 = Isochoric process.

3 - 4 = isothermal process.

4 - 1 = isochoric process.

(b). Recall that the process from 1 to is an adiabatic expansion process.

NB: b = 5/3 for a monoatomic gas.

Then, the workdone = (1/ 1 - 1.66) [ (p1 × v1^b)/ v2^b × v2 - (p1 × v1)].

= ( 1/ 1 - 5/3) [ (101 × 5^5/3) × 10^1 -5/3] - 101 × 5.

Thus, the workdone = 280.305 J.

(c). P2 = P1 × V1^b/ V2^b = 101 × 5^5/3/ 10^5/3 = 31.81 kpa.

T2 = P2 × V2/ R × 1 = 31.81 × 10/ 8.324 = 38.36k.

(d). The process 2 - 3 is an Isochoric process, then;

T3 = T2/P2 × P3 = 38.26/ 31.82 × 20 = 24.05K.

(e). The process 3 - 4 Is an isothermal process. Then, the temperature at 4 will be the same temperature at 3. Tus, we have the temperature; point 3 = point 4 = 24.05k.

The pressure can be determine as below;

P4 = P3 × V3/ V4 = 20 × 10/ 5 = 200/ 5 = 40 kpa.

(f) workdone = xRT ln( v4/v3) = 1 × 8.314 × 24.05 × ln (5/10) = - 138.6 J

please answer correctly

Answers

Answer:

616000 J.

Explanation:

Bi. Determination of the work done.

Force (F) = 220 N

Distance (s) = 2800 m

Workdone (Wd) =?

Workdone is simply defined as the product of force and the distance moved in the direction of the force. Mathematically, is can be expressed as:

Workdone = Force × distance

Wd = F × s

With the above formula, we can obtain the Workdone as follow:

Force (F) = 220 N

Distance (s) = 2800 m

Workdone (Wd) =?

Wd = F × s

Wd = 220 × 2800

Wd = 616000 J.

A 4.0-g bead carries a charge of 20 μC. The bead is accelerated from rest through a potential difference V, and afterward the bead is moving at 3.0 m/s. What is the magnitude of the potential difference V? *
1 point
900 V
400 V
200 V
400 kV

Answers

Answer:

The magnitude of the potential difference is 900 V.

Explanation:

Given;

mass of the bead, m = 4.0 g = 0.004 kg

charge of the bead, Q = 20 μC = 20 x 10⁻⁶ C

final velocity of the bead, v = 3 m/s

What is the magnitude of the potential difference V?

Apply the principle of conservation of energy;

The electric potential energy at the beginning is equal to kinetic energy of the bead  at the end of the journey.

qV = ¹/₂mv²

[tex]V = \frac{mv^2}{2q} \\\\V = \frac{0.004 \ \times \ (3)^2}{2(20 \times 10^{-6})}\\\\V = 900 \ V[/tex]

Therefore, the magnitude of the potential difference is 900 V.

The magnitude of the potential difference (V) is equal to 900 Volts.

Given the following data:

Mass of bead = 4.0 g to kg = 0.004 kgCharge of bead = 20 μC = [tex]20 \times 10^{-6} \;C[/tex]Final velocity of bead = 3 m/s

To determine the magnitude of the potential difference (V):

How to calculate the potential difference (V).

We would apply the law of conservation of energy, which states that the electric potential energy possessed by the bead at the beginning is equal to the kinetic energy possessed by the bead at the end of the journey:

[tex]qV = \frac{1}{2} mv^2\\\\V = \frac{\frac{1}{2} mv^2}{q} \\\\V = \frac{\frac{1}{2} \times 0.004 \times 3.0^2}{20 \times 10^{-6}} \\\\V = \frac{ 0.002 \times 9}{20 \times 10^{-6}}[/tex]

V = 900 V.

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For a given substance, the molecules
move fastest when the substance is

Answers

Heat makes the molecules move faster

Answer:GAS

Explanation:

A crate rests on a flatbed truck which is initially traveling at 13.6 m/s on a level road. The driver applies the brakes and the truck is brought to a halt in a distance of 38.1 m. If the deceleration of the truck is constant, what is the minimum coefficient of friction between the crate and the truck that is required to keep the crate from sliding

Answers

Answer:

0.248

Explanation:

Initial speed u = 13.6

Final speed v = 0

Distance s = 38.1

We have umg = ma

We make u subject of the formula

u = a/g

V² = u² + 2as

a = v²-u²/2s

We substitute the values into the above

a = 0-(13.6)²/2*38.1

a = 184.96/76.2

a = 2.427m/sec

Remember that

u = a/g

u = 2.427/9.8

= 0.2476

This is approximately 0.248

This is the minimum coefficient of friction required to keep the crate from sliding.

PROBLEM 5 (Problem 4-145 in 7th edition) Consider a well-insulated horizontal rigid cylinder that is divided into two compartments by a piston that is free to move but does not allow either gas to leak into the other side. Initially, one side of the piston contains 1 m3 of N2 gas at 500 kPa and 120oC while the other side contains 1 m3 of He gas at 500 kPa and 40oC. Assume the piston is made of 8 kg of copper initially at the average temperature of the two gases on both sides. Now thermal equilibrium is established in the cylinder as a result of heat transfer through the piston. Using constant specific heats at room temperature, determine the final equilibrium temperature in the cylinder. What would your answer be if the piston were not free to move

Answers

Answer:

The answer is "[tex]\bold{83.8^{\circ} \ C}[/tex]".

Explanation:

Formula for calculating the mass in He:

[tex]\to m = \frac{PV}{RT}\\[/tex]

        [tex]= \frac{500 \times 1}{ 2.0769 \times (40 + 273)}\\\\ = \frac{500 }{ 2.0769 \times 313}\\\\ = \frac{500 }{ 650.0697}\\\\= 0.76914 \ Kg[/tex]

Formula for calculating the mass in [tex]N_2[/tex]:

[tex]\to m = \frac{PV}{RT}\\[/tex]

        [tex]= \frac{500 \times 1}{ 0.2968 \times (120+ 273)}\\\\ = \frac{500 }{ 0.2968 \times 393}\\\\ = \frac{500 }{ 116.6424}\\\\= 4.2866\ Kg[/tex]

by using the temperature balancing the equation:

[tex]T' = \frac{mcT (He) + mcT ( N_2 )}{ mc (He) + mc ( N_2)}[/tex]

    [tex]= \frac{0.76914 \times 3.1156 \times 313 + 4.2866 \times 0.743 \times393}{ 0.76914 \times 3.1156 + 4.2866 \times 0.743} \\\\ = 357 \ \ K \approx 83.8^{\circ} \ C[/tex]

Which statement is true of a glass lens that diverges light in air?
A.
It is thick near the center and thin at the edges.
B.
It is thin near the center and thick at the edges.
C.
It is uniformly thick.
D. It is uniformly thin.

Answers

C it is uniformly thick

Answer: it is thin near the center and thick at the edges

Explanation: took the test on Plato :)

[RM.03H]Which of these is the most likely impact of extensive mining of uranium to produce energy?

land becomes unfit for food production
rainfall decreases because of harmful gases
greenhouse gases are absorbed by the mineral
radiations are better absorbed by the atmosphere

Answers

Answer:

land becomes unfit for food production


what is a vector quantity?

Answers

Answer:

A quantity that has magnitude and direction. It's usually represented by an arrow whose direction is the same direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude

Vector Quantity

A physical Quantity, which has magnitude, direction and units But must follow the traingle law of vector addition

Example:- Force, velocity acceleration displacement etc.

Plzz answer this question correctly

Answers

Answer:

by reducing friction.....

Two strings with linear densities of 5 g/m are stretched over pulleys, adjusted to have vibrating lengths of 0.50 m, and attached to hanging blocks. The block attached to string 1 has a mass of 20 kg and the block attached to string 2 has a mass of M. Listeners hear a beat frequency of 2 Hz when string 1 is excited at its fundamental frequency and string 2 is excited at its third harmonic. What is one possible value for mass M

Answers

Answer:

2.18 kg

Explanation:

The frequency of a wave in a stretched string f = n/2L√(T/μ) where n = harmonic number, L = length of string, T = tension = mg where m = mass of object on string and g = acceleration due to gravity = 9.8 m/s² and μ = linear density of string.

For string 1, its fundamental frequency f  is when n = 1. So,

f = 1/2L√(T/μ) =  1/2L√(mg/μ)

Now for string 1, L = 0.50 m, m = 20 kg and μ = 5 g/m = 0.005 kg/m

substituting the values of the variables into f, we have

f = 1/2L√(mg/μ)

f = 1/2 × 0.50 m√(20 kg × 9.8 m/s²/0.005 kg/m)

f = 1/1 m√(196 kgm/s²/0.005 kg/m)

f = 1/1 m√(39200 m²/s²)

f = 1/1 m × 197.99 m/s

f = 197.99 /s

f = 197.99 Hz

f ≅ 198 Hz

For string 2, at its third harmonic frequency f'  is when n = 3. So,

f' = 3/2L√(T/μ) =  3/2L√(mg/μ)

Now for string 2, L = 0.50 m, m = M kg and μ = 5 g/m = 0.005 kg/m

substituting the values of the variables into f, we have

f' = 3/2L√(Mg/μ)

f' = 3/2 × 0.50 m√(M × 9.8 m/s²/0.005 kg/m)

f' = 3/1 m√(M1960 m²/s²kg)

f' = 3/1 m√M√(1960 m²/s²kg)

f' = 3/1 m √M × 44.27 m/s√kg

f' = 132.81√M/s√kg

f' = 132.81√M Hz/√kg

Since the frequency of the beat heard is 2 Hz,

f - f' = 2 Hz

So, 198 Hz - 132.81√M Hz/√kg = 2 Hz

132.81√M Hz/√kg = 198 Hz - 2 Hz

132.81√M Hz/√kg = 196 Hz

√M Hz/√kg = 196 Hz/138.81 Hz

√M/√kg = 1.476

squaring both sides,

[√M/√kg] = (1.476)²

M/kg = 2.178

M = 2.178 kg

M ≅ 2.18 kg

an object of 5kg is attached to a rope of length 4m is Rotating horizontally at 8m/s horizontally 20m above the ground if the rope is suddenly cut what is the horizontal distance travelled by the object? Please guys help

Answers

Answer:

16 meters

Explanation:

When the rope is suddenly cut the object moving tangent at the circle. In that moment the gravity act in the object making it falls.

First we need to find how much time de object take to reach at the ground.

VERTICALLY EQUATION:[tex]h(t)=h-v*t-\frac{g}{2} t^{2} \\[/tex]

g=acceleration of gravity=10m/s²

v= vertical velocity =0m/s

h=vertical altitude =20m

We will find t such that h(t)=0

[tex]0=20-5t^{2} \\\\5t^{2} =20\\\\t^{2} =4\\\\t=2s[/tex]

HORIZONTALLY EQUATION:*horizontally we do not have acceleration[tex]D(t)=v*t[/tex]

v=horizontal velocity

D(t=2) is the horizontal distancetravelled by the object:

[tex]D(2)=8*2\\\\D(2)=16m[/tex]

Please help I’m almost done with exam

Which phrase is the best description of what a telescope does?
O A. Causes objects to grow larger
B. Transports equipment to space
C. Converts solar energy to electricity
D. Detects electromagnethwaves

Answers

Answer:

D

Explanation:

Telescopes detect electromagnetic waves from space and it travels back to the telescope lens in order for you to see.

Answer:

D

Explanation:

Ap ex science exam lol

An object initially traveling in a straight line with
a speed of 5.0 meters per second is accelerated
at 2.0 meters per second squared for 4.0 seconds.
The total distance traveled by the object in the
4.0 seconds is

Answers

Answer:

We conclude that the total distance traveled by the object in the 4 seconds is 36 m.

Explanation:

Given

Initial velocity u = 5.0 m/sAcceleration a = 2.0 m/s²Time t = 4 s

To determine

The total distance traveled by the object in the  4.0 seconds is

Important Tip:

We can determine the total distance traveled by the object in the  4.0 seconds by using the equation of motion such as

[tex]s=ut+\frac{1}{2}at^2[/tex]

where

s = distanceu = initial velocitya = accelerationt = time

substituting u = 5.0, a = 2, and t = 4 in the formula

[tex]s=ut+\frac{1}{2}at^2[/tex]

[tex]s=\left(5\right)\left(4\right)+\frac{1}{2}\left(2\right)\left(4\right)^2[/tex]

[tex]s=20+16[/tex]

[tex]s=36[/tex] m

Therefore, we conclude that the total distance traveled by the object in the 4 seconds is 36 m.

The total distance traveled by the object is 36 meters.

Given the following data:

Initial velocity = 5.0 m/s Acceleration = 2.0 [tex]m/s^2[/tex] Time = 4.0 seconds.

To find the total distance traveled by the object, we we  would use the second equation of motion.

Mathematically, the second equation of motion is given by the formula;

[tex]S = ut + \frac{1}{2}at^2[/tex]

Where:

S is the total distance traveled.

u is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting the values into the formula, we have;

[tex]S = 5(4) + \frac{1}{2}(2)(4^2)\\\\S = 20 + 1(16)[/tex]

Total distance, S = 36 meters.

Therefore, the total distance traveled by the object is 36 meters.

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Even though Alice visits the wishing well frequently and always tosses in a coin for good luck, none of her wishes have come true. As a result, she decides to change her strategy and make a more emphatic statement by throwing the coin downward into the well. If the water is 5.43 m below the point of release and she hears the splash 0.85 seconds later, determine the initial speed at which she threw the coin. (Take the speed of sound to be 343 m/s.)

Answers

Answer:

Explanation:

Total time taken = 0.85 s .

Time taken by sound to travel 5.43 m + time taken by coin to fall by 5.43 m = .85

5.43 / 343 + time taken by coin to fall by 5.43 m = .85

time taken by coin to fall by 5.43 m = .85 - 5.43/343 = .834 s

Let the initial velocity of throw of coin = u

displacement of coin s  = 5.43 m

time take to fall t =  .834 s

s = ut + 1/2 gt²

5.43 = u x .834 + .5 x 9.8 x .834²

5.43 = u x .834 + 3.41

u x .834 = 2.02

u = 2.42 m /s .

a car acceleration from rest to 90km/h in 10 seconds. what is its acceleration in meter per second square?​

Answers

Answer:

2.5 m/s^2

Explanation:

First, convert 90 km/hr into m/s:

90/3.6 = 25 m/s

vf = final velocity = 25 m/s

vi = initial velocity = 0 m/s

t = time = 10 seconds

a = acceleration, unknown

Then, find a using the following equation:

(vf - vi)/t = a

(25 m/s)/10 s = 2.5 m/s^2

a = 2.5 m/s^2

Hope this helps!! :)

If a satellite is orbiting the Earth in elliptical motion, then it will move _______________ (slowest, fastest) when its closest to the Earth. While moving towards the Earth (along the path from D to A) there is a component of force in the __________________ (same, opposite) direction as the motion; this causes the satellite to ___________________ (slow down, speed up). While moving away from the Earth (along the path from A to D) there is a component of force in the _________________ (same, opposite) direction as the motion; this causes the satellite to ___________________ (slow

Answers

Answer:fastest,same,slow down,opposite,slow

Explanation:

A satellite move fastest when its closest to the Earth. The other correct options are same direction, speed up, opposite direction and slow.

Velocity of a satellite around the planet.

If a satellite is orbiting the Earth in elliptical motion, then it will move fastest when its closest to the Earth (based on Kepler's, law).

While moving towards the Earth (along the path from D to A) there is a component of force in the  same direction as the motion; this causes the satellite to speed up.

While moving away from the Earth (along the path from A to D) there is a component of force in the opposite direction as the motion; this causes the satellite to slow.

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A flat screen tv uses 120 watts. How much energy is used up if it is left on for 15 min?
A.) 4j
B.) 15j
C.) 0.67j
D.) 108,000j

Answers

Answer:

d

Explanation:

how does the strength of the forces that hold the basic particles of a substance together relate to the temperature at which the substance changes state​

Answers

The kinetic energy keeps the molecules apart and moving around, and is a function of the temperature of the substance. ... Increasing the pressure on a substance forces the molecules closer together, which increases the strength of intermolecular forces.

A block of mass m1 = 19.5 kg slides along a horizontal surface (with friction, μk = 0.35) a distance d = 2.6 m before striking a second block of mass m2 = 8.25 kg. The first block has an initial velocity of v = 6.5 m/s.
(a) Assuming that block one stops after it collides with block two, what is block two's velocity after impact in m/s?
(b) How far does block two travel, d2 in meters, before coming to rest after the collision?

Answers

Answer:

19.5 m/s

87.8 m

Explanation:

The acceleration of block one is:

∑F = ma

-m₁gμ = m₁a

a = -gμ

a = -(9.8 m/s²) (0.22)

a = -2.16 m/s²

The velocity of block one just before the collision is:

v² = v₀² + 2aΔx

v² = (8.25 m/s)² + 2 (-2.16 m/s²) (2.3 m)

v = 7.63 m/s

Momentum is conserved, so the velocity of block two just after the collision is:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m₁u₁ = m₂v₂

(18.5 kg) (7.63 m/s) = (7.25 kg) v

v = 19.5 m/s

The acceleration of block two is also -2.16 m/s², so the distance is:

v² = v₀² + 2aΔx

(0 m/s)² = (19.5 m/s)² + 2 (-2.16 m/s²) Δx

Δx = 87.8 m

Explanation:

By using conservation of linear momentum and also by equating work done to kinetic energy,  [tex]V_{2}[/tex]  = 15.36 m/s and [tex]d_{2}[/tex] = 4.32 meters

Parameters given are :

[tex]m_{1}[/tex] = 19.5 kg

friction, μk = 0.35

distance d = 2.6 m

mass [tex]m_{2}[/tex] = 8.25 kg.

initial velocity of [tex]U_{1}[/tex] = 6.5 m/s.

a.) Since we assumed that the block one stops after it collides with block two, the final velocity for block one will be zero. That is, [tex]V_{1}[/tex] = 0 so its final momentum = 0

Let us also assume that block two was initially at rest. Therefore, it initial velocity and its momentum will be equal to zero.

The formula to use will be :

[tex]m_{1}U_{1} = m_{2}V_{2}[/tex]

Substitute all the parameters into the formula above

19.5 x 6.5 = 8.25[tex]V_{2}[/tex]

Make [tex]V_{2}[/tex] the subject of formula

[tex]V_{2}[/tex] = 126.75/8.25

[tex]V_{2}[/tex] = 15.36 m/s

b.) Let us first calculate the work done in by block one.

The K.E = [tex]1/2mU^{2}[/tex]

substitute its mass and velocity into the formula

K.E = 1/2 x 19.5 x [tex]6.5^{2}[/tex]

K.E = 411.94 Joule

The work done = Kinetic energy

But the resultant Force F = force f - friction

where Frictional force = 0.35 x 19.5 x 9.8

Frictional force = 66.89N

Work done will be the product of resultant Force F and the distance travelled

(F - 66.89) x 2.6 = 411.94

F - 66.89 = 411.94/2.6

F - 66.89 = 158.44

F = 225.3 N

The second block will experience the same force which is equal to 225.3N

Find the kinetic energy of the second block.

K.E =  [tex]1/2mV^{2}[/tex]

K.E = 0.5 x 8.25 x 15.36^2

K.E = 973.2

Using The work done = Kinetic energy

225.3[tex]d_{2}[/tex] = 973.2

[tex]d_{2}[/tex] = 973.2/225.3

[tex]d_{2}[/tex] = 4.32 meters

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what is the mathematical formula associated with newton's 2nd law of motion?​

Answers

Answer:

F= m x a

Explanation:

Force (f) = mass (m) x acceleration (a)

How do you classify flammable liquid to gas and solid?​

Answers

Answer:

A flammable liquid enjoys the attention of at least three different federal agencies: the DOT in matters of its transportation, OSHA as it might affect workplace safety, and the EPA concerning its cradle-to-grave management.A flammable liquid enjoys the attention of at least three different federal agencies: the DOT in matters of its transportation, OSHA as it might affect workplace safety, and the EPA concerning its cradle-to-grave management.Add to that a gaggle of state, regional, and local authorities; and we feel compelled to begin this blog entry with our favorite caveat: get expert advice before deciding what to do with that rusting drum of stale gasoline out back.

Explanation:

I hope it help you;)

Four-wheel drive trucks do not stop better on icy
roads than a car. Is what law of motion (Newton's laws)

Answers

It would be Newton’s second law of motion

Plzz help me with this

Answers

Answer: d

Explanation:

Blythe and Geoff compete in a 1.00-km race. Blythe's strategy is to run the first 600 m of the race at a constant speed of 4.10 m/s, and then accelerate to her maximum speed of 7.30 m/s, which takes her 1.00 min, and then finish the race at that speed. Geoff decides to accelerate to his maximum speed of 8.30 m/s at the start of the race and to maintain that speed throughout the rest of the race. It takes Geoff 3.00 min to reach his maximum speed. Assume all accelerations are constant.

Required:
a. Calculate the time of Blythe's run.
b. Calculate the time of Geoff s run.

Answers

Answer:

Explanation:

1.00 km = 1000 m .

Blythe's run : -------

Time taken to run 600 m speed

= distance / speed

T₁= 600 / 4.10 = 146.34 s

Next time T₂ = 1 min = 60 s

acceleration of Blythe

a = (7.30 - 4.10) / 60 = .053 m /s²

displacement during acceleration

= ut + 1/2 at²

= 4.10 x 60 + .5 x .053 x 60²

= 246 + 95.4

= 341.4 m

Rest of the distance to be covered = 1000 - ( 600 + 341.4 )

= 58.9 m

Time taken to cover this distance

T₃= 58.9 / 7.3 = 8.06 s

Total time = T₁ + T₂ + T₃ = 214.4 s

Geoff s run : ---------

initial acceleration during first 3 min

= (8.3 - 0 ) / (3 x 60 )

= .046 m /s²

displacement

s = ut + 1/2 a t²

= 0 + .5 x .046 x ( 3 x 60 )²

= 745.2 m

Rest of the distance of race

= 1000 - 745.2 = 254.8 m

This distance is covered at speed of 8.3 m/s

time taken to cover this distance

T₂ = 254.8 / 8.3

= 30.7 s

Total time taken to complete the race

= 180 + 30.7

= 210.7 s .

is a step in the scientific method. The step that follows this step involves forming

Answers

Answer: read this hope this helped

Explanation: A hypothesis is a possible explanation for a set of observations or an answer to a scientific question. ... The next step in the scientific method is to test the hypothesis by designing an experiment. This includes creating a list of materials and a procedure— a step-by-step explanation of how to conduct the experiment.

Which of the following hydrocarbons are SATURATED hydrocarbons?

I. alkanes II. alkenes III. alkynes IV. cycloalkanes

A. I and IV

B. II and III

C. I and III

D. II and IV

Answers

Answer:

i think c

Explanation:

Why are we seeing extremely old light from Canopus instead of light in real-time?

Answers

Answer:

Canopus is more than 300 light years away from earth. This means it takes the light we see more than 300 years to reach us.

How do you think that changing the mass of the pendulum bob will affect the period of the pendulum swing?​

Answers

(Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.)

A battery has an emf of ε = 15.0 V. THe terminal voltage of the battery is Vt = 11.6 V when it is delivering P = 20.0 W of power to an external load resistor R. (a) What is the value of R? (b) What is the internal resistance r of the battery?

Answers

AnswerHM???

Explanation:

I dONT KNOW

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T/F: it is not possible to use a discounted cash flow model to value a firm if it does not pay dividends. If tacos cost $0.50, about how many more tacos would customers buy than if they cost $3.00? the proportion of variation explained by the model is called the ____group of answer choices a. slope of the line b. sum of squares error c. coefficient of determination d. coefficient of correlation the equal areas law is kepler's 2nd law of planetary motion. it states that _____. At the market price of $1, a hotdog seller is willing and able to supply (or produce) 12 units of hotdogs. However, at that price, buyers are willing and able to buy 8 hotdogs. What is the quantity supplied in this case?Group of answer choicesO 10O 12O 20O 8 A 2.842 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 6.461 grams of CO2 and 2.645 grams of H2O are produced. In a separate experiment, the molecular weight is found to be 116.2 amu. Determine the empirical formula and the molecular formula of the organic compound. 7. Which compound do you believe will have an absorption maximum at a longer wavelength in a UV-VIS spectrum: ethylene, or 1,3-butadiene? Explain your answer using no more than 2 sentences give an indexed family of sets that is pairwise disjoint but the intersection over it is nonempty DISCUSS the specific training methods that will be used in your training preparation for April. Eg. Fartlek, endurance, weight etc. Use DETAILS!!!! Do not just list the training methods many research psychologists think of _________ as an information processor that woeks without awareness The main waterline for a neighborhood delivers water at a maximum flow rate of 0.020 m^3/s. If the speed of this water is 0.20 m/s, what is the pipe's radius? Express your answer to two significant figures and include the appropriate units. FILL IN THE BLANK.The ____ stage of the attack methodology is a systematic survey of the target organizations Internet addresses, conducted to identify the network services offered by the hosts in that range. Air is expanded from 2000 kPa and 500"C to 100 kPa and 50'C Assuming constant specific heats determine the change in the 'specific entropy of air: [Hint: Cp 1.040 kJlkg K & R = 0.287 kJkg K] a. deltaSair = 1.0478 kJ/kgK b. deltaSair = 0.478 kJ/kgK c. deltaSair = 0.0478 kJ/kgK d. deltaSair = -0.478 kJ/kgK e. deltaSair = -0.0478 kJ/kgK what type of director may have multiple titles within the world of theater How does a low credit score affect a person who applies for a loan?A. It makes banks more likely to give the person a large, long-termloan.B. It causes banks to charge the person higher interest rates on theloan.OC. It makes it easier for the person to get a loan with a poor debt-to-income ratio.D. It allows banks to give the person a loan without checking his orher tax records, .A solution of nitrous acid, HNO2, is found to have the following concentrations at equilibrium: [HNO2]=0.050M and [H3O+]=[NO2]=4.8103M What is the Ka of nitrous acid?4.61044.81039.61021.1104 Kelly draws a rectangle. How many square corners does Kelly's rectangle have?Choose the answer that makes the statement true. Kelly's rectangle has Choose. Square corners Market skimming prices are preferred in all of the following conditions except __________.A.an initial low price is set by the companiesB.competitors should not be able to enter the market easily and undercut the high priceC.the product's quality and image must support its higher priceD.enough buyers must want the product at that priceE.the costs of producing a smaller volume cannot be so high that they cancel the advantage of charging more fitb. to help maintain control of a meeting, the leader or administrative professional should choose the ________ seating arrangements Calculate the pH for each of the following cases in the titration of 35.0 mL of 0.220 M LiOH(aq), with 0.220 M HCl(aq). (a) before addition of any HCl (b) after addition of 13.5 mL of HCl (c) after addition of 25.5 mL of HCl (d) after the addition of 35.0 mL of HCl (e) after the addition of 40.5 mL of HCl (f) after the addition of 50.0 mL of HCl