Answer the following questions. Make sure to show all your work. 1. When is it best to solve a system of equations using graphing? 2. When is it best to solve a system of equations using substitution? 3. When it is best to solve a system of equations using elimination? When it is 4. Solve the following system of equations graphically. y=3x+4 y=-2x-5

The central angle formed between the ends of the ribbon is 98.6°.

The circumference will be:

= πd

= 3.14 × 15 = 47.1

Ribbon = 60 - 47.1 = 12.9

Length of arc = x/360 × πd

12.9 = x/360 × 3.14 × 15

x = 98.6°

The angle is 98.6°

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Answer:

c

Step-by-step explanation:

option a (x-4) translates the graph 4 units right, not down

option b (x)-4 translates the graph 4 units down, not left

option c (x)+4 translates the graph 4 units up, so it is correct

option d (x+4) translates the graph 4 units left, not right

if the number is outside of the parentheses, like (x)+4 or (x)-4, the graph undergoes a vertical translation, and it moves up/down, with + meaning up and - meaning down

if the number is inside of the parentheses, like (x+4) or (x-4), the graph undergoes a horizontal translation, and moves left/right, with - meaning right and + meaning left

The coordinates of the vertex that A maps to after Daniel's reflections are (3, 4) and the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)

From the given figure, the coordinate of the vertex A is represented as:

A = (-5, 2)

The coordinates of the vertex that A maps to after Daniel's reflections

The rule of reflection across the line x = -1 is

(x, y) ⇒ (-x - 2, y)

So, we have:

A' = (5 - 2, 2)

Evaluate the difference

A' = (3, 2)

The rule of reflection across the line y = 2 is

(x, y) ⇒ (x, -y + 4)

So, we have:

A'' = (3, -2 + 4)

Evaluate the difference

A'' = (3, 4)

Hence, the coordinates of the vertex that A maps to after Daniel's reflections are (3, 4)

The coordinates of the vertex that A maps to after Zachary's reflections

The rule of reflection across the line y = 2 is

(x, y) ⇒ (x, -y + 4)

So, we have:

A' = (-5, -2 + 4)

Evaluate the difference

A' = (-5, 2)

The rule of reflection across the line x = -1 is

(x, y) ⇒ (-x - 2, y)

So, we have:

A'' = (5 - 2, 2)

Evaluate the difference

A'' = (3, 2)

Hence, the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)

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The equivalent expression of the expression is 128x^5y^6/2x^7y^5

The expression is given as:

128x^5y^6/2x^7y^5

Divide 128 by 2

64x^5y^6/x^7y^5

Apply the law of indices

64y^(6-5)/x^(7-5)

Evaluate the differences

64y/x^2

Hence, the equivalent expression of the expression is 128x^5y^6/2x^7y^5

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Complete question

Select the correct answer. which expression is equivalent to 128x^5y^6/2x^7y^5 , if x > 0 and y > 0

Solving an inequality, we will see that there is less than $280 in the pile of money.

Let's say that the amount of money is defined by the variable.

First, we know that Jeri keeps $80, so now in the pile we have:

M - $80.

Now she gives one third of that, then the leftover is:

(2/3)*(M - $80) + $80

We know that this is more than:

M - $200

Then we have the inequality:

(2/3)*(M - $80) + $80 > M - $200

And we can solve this for M.

(2/3)*M  - (2/3)*$80 + $80 > M - $200

(1/3)*$80 + $200 > M - (2/3)*M

(1/3)*$80 + (1/3)*$200 > (1/3)*M

$280 > M

Then we conclude that there is less than $280 in the pile of money.

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The y-intercept of the linear function is y = 0.

A linear function is modeled by:

y = mx + b

In which:

The y-intercept is given by (0,a) = (0,-a). From this, we have that for it to be a function, a = -a, and the only value that respects this condition is a = 0, hence the y-intercept of the linear function is y = 0.

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Answer:

37

Step-by-step explanation:

6m+5n

plug in your given values

6(2) + 5(5)

12+25

=37

Answer:

37

Step-by-step explanation:

6m + 5n

6*2  +  5*5 = 12 + 25

= 37

A cone has a circular base. So, the answer to your question is B for circle.

Area covered with grass seed = 10.4[tex]m^{2}[/tex].

What is trapezoid geometry?

A quadrilateral with one set of parallel opposite sides is referred to as a trapezoid. It can have congruent sides (isosceles) and right angles (a right trapezoid), but neither is necessary.

Area of the trapezoid ={ (a+b)/2} +h

where a and b is base and h is height of the trapezoid geometry.

In the question,

a=6m , b=7m and h=4m.

According to the formula { (a+b)/2} +h.

Area covered with grass seed = {(6+7)/2} + 4

                                                    = 10.4[tex]m^{2}[/tex].

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Answer:

26

Step-by-step explanation:

GOT IT RIGHT`

Answer:

3 2/5

Step-by-step explanation:

Each slash/mark on the number line is 1/5, meaning that 6 marks away is 3 2/5.

To further explain how I know each mark is 1/5, each question had a denominator of 5, and if you count each mark from 2 1/5 (2 2/5, 2 3/5, 2 4/5, 3, etc) you will eventually land on 4 evenly.

The height of the frame is 15 feet.

From the information given, the following can be depicted:

b - 10/a = 2/5

2a = 5b - 50

2a - 5b = -50

Also, slope of AC:

= (b - 10(/(a - 5) = 2/5

2a - 50 = -5b + 50

2a + 5b = 100

Both equations will be solved

The height of the frame will be:

= 5 + 10

= 15 feet

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Answer:

[tex]4x^2+20x-2[/tex]

Step-by-step explanation:

To find (c.g)(x) we basically use the function d(x) as your variable, x, and plug it into c(x). So we replace every x in c(x) with the function d(x), [tex]x^{2} +5x[/tex]

c(g(x))=4(x^{2} +5x)-2

c(g(x))4[tex]x^2[/tex]+20x-2

Answer:

A.  63.8 in^2

Step-by-step explanation:

The surface area of a cylinder is given by:

A=2πrh+2πr^2

2πr^2 gives the area of the 2 ends, each with area πr^2.

2πrh gives the suface area of the outside of the cylinder.

r = 0.4 inches

h = 25 inches

Area = 63.8 in^2

Putting the other player's king in check is always a good move. true

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Answer:

See below.

Step-by-step explanation:

a. If h is the number of hours of labour required to print the cards, construct an equation for the cost of the cards, C.

C = $250 + ($40/hr)*h

b. You have budgeted $1000 for the printing job. How many hours of labour can you afford? Give your answer to the nearest minute.

$1000 = $250 + ($40/hr)*h

($40/hr)*h = $750

h = 18.75 hours

(18.75 hours)(60 min/hr) = 1125 minutes

c. The company estimates that it can print 1000 cards per hour of labour. How many cards will you get printed with your current budget?

(18.75 hr)*(1000 cards/hr) = 18,750 cards

d. An alternative to printing is photocopying. The company charges 15 cents per side for the first 10 000 cards and then 10 cents per side for the remaining cards. Which is the cheaper option for 18 750 single-sided cards and by how much?

Photocopy Cost for the first 1000 single-sided cards is:

(1000 cards)*($0.15) = $150

Photocopy Cost for the final 17,750 single-sided cards is:

(17,750)*($0.10) = $1,775

Totoal photocopy cost for 18,750 single-sided cards is $1,925.  [1775+150]

The cheapest option for 18,750 cards is printing:  $1,000

Printing is (1,925 - 1000) $925 cheaper than photocopying.

The equation which represent the interpretation of the scenario is 5 + 2x

Total laws mowed = Number of lawns Homer mowed + (Additional laws mowed each month × Number of months)

= 5 + (2 × x)

= 5 + 2x

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Systemic chemotherapy's impact on survival and recurrence in people with high-grade glioma has not been conclusively studied.

Patients undergoing systemic chemotherapy can get their chemotherapy drugs intravenously or orally. The medication may be injected into the body intravenously, or through an IV, or intramuscular, into a muscle (IM).

Some Key features of systemic chemotherapy are-

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Answer:

y = 9.84 mm

Step-by-step explanation:

Law of sine:

   [tex]\sf \boxed{\bf \dfrac{a}{Sin \ A}=\dfrac{b}{Sin \ B}= \dfrac{c}{Sin \ C}}[/tex]

    a = y

    A = 31°

   b  = 17 mm

    B = 117°

[tex]\sf \dfrac{y}{Sin \ 31^\circ}=\dfrac{17}{Sin \ 117^\circ}\\\\[/tex]

          [tex]\sf y = \dfrac{17}{Sin \ 117^\circ}*Sin \ 31^\circ\\\\ y = \dfrac{17}{0.89}*0.515\\\\y = 9.84 \ mm[/tex]

Answer: [tex]\frac{2}{25} +\frac{11}{25}i[/tex]

Step-by-step explanation:

To get the following you have multiply the conjugate. [tex]\frac{(2-i)(3-4i)}{(3+4i)(3-4i)}[/tex]

The p value for the difference is 0.005.

According to the statement

we have given that the 74 of 100 urban residents favor the construction while only 70 of 125 suburban residents are in favor.

And we have  to find the difference between them in proportions.

So,

X1 = 74 represent the number of residents in a certain city and its suburbs who favor the construction of a nuclear power plant

X2 = 70 represent the number of people suburban residents are in favor

N1  = 100 sample 1 selected

N2 = 125 sample 2 selected

AND

P1 = 0.74 represent the proportion of residents in a certain city and its suburbs who favor the construction of a nuclear power plant

And P2 = 0.56 represent the proportion of suburban residents are in favor And z would represent the statistic (variable of interest)  

Pv represent the value for the test (variable of interest)

Here we apply the Z test to find the difference then

Z = (0.74 - 0.56) / (0.64(1-0.64)(1/100+1/125) )^1/2

Now after solving

Z = 2.795.

Now The significance level provided is  ,and we can calculate the p value for this test.  

Since is a two tailed test the p value would be:  

P = (z>2,795)

P = 0.005.

So, The p value for the difference is 0.005.

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Answer: [tex]\triangle RQP \sim \triangle VPW[/tex]

Step-by-step explanation:

By the corresponding angles theorem, [tex]\angle RPQ \cong \angle VWP[/tex] and [tex]\angle RQP \cong \angle VPW[/tex].

Therefore, [tex]\triangle RQP \sim \triangle VPW[/tex] by AA.

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

5×(-4)=20

5×3=15

5×0.5=2.5

5×5=25

5×0=0

5×(-2)=-10

A quadratic equation in standard form that can be used to determine the value of x is [tex]x^{2}[/tex] - 8x - 65 = 0.

The Factor of the equation from Part B is (x - 13)(x + 5)  and the possible solutions to the equation is x = 13 or -5.

The value for the second number is 5

The general formula for quadratic equation in a in standard form is

a[tex]x^{2}[/tex] + bx + c = 0

Given that the  difference between two integers is 8

Let the two integers = x and y,

and their product is 65. If the larger of the two numbers is x. Then,

x - y = 8 and xy = 65

Since we are looking for the value of x, make y the subject of formula in the first equation.

y = x - 8

Substitute y in the second equation.

x(x - 8) = 65

[tex]x^{2}[/tex] - 8x - 65 = 0

[tex]x^{2}[/tex] - 13x + 5x - 65 = 0

(x - 13)(x + 5) = 0

x = 13 or -5

We will ignore -5 since x is the larger number.

To get y Substitute x in the second equation.

xy = 65

13y = 65

y = 65/13

y = 5

Therefore, a quadratic equation in standard form that can be used to determine the value of x is [tex]x^{2}[/tex] - 8x - 65 = 0. The Factor of the equation from Part B is (x - 13)(x + 5)  and the possible solutions to the equation is x = 13 or -5. The value for the second number is 5

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Answer:

40%

Step-by-step explanation:

Percent must be equal to 100, so if 60 are girls, then 40% must be boys.

The number to add to the set of data is 26

The set of data is given as:

11,14,23 and 16

Let the new number be x

So that

Mean = 18

Mean is calculated as:

Mean = Sum/Count

So, we have:

(11 + 14 + 23 + 16 + x)/5 = 18

Multiply by 5

11 + 14 + 23 + 16 + x = 90

Evaluate the like terms

x = 26

Hence, the number to add is 26

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Complete question

A set of data already has the values 11, 14, 23, and 16. What value would have to be added to the set for the mean of the five numbers to be 18?

Answer:

[tex]6x^{2} -24x-10[/tex] with remainder -5

Answer:

[tex]6^2-24x-10-\frac{5}{x+4}[/tex]

In other words, [tex]6x^2-24x-10[/tex] is the answer and -5 is the remainder

Step-by-step explanation:

I used long division for this, and I uploaded an image for the steps. The final answer I got was [tex]6x^2-24x-10-\frac{5}{x+4}[/tex]

You have to find the slope of the line. It will give you the conversion rate from inches to centimetres or the other way around.

Looking closely at the graph, or using a ruler as reference, you can estimate that 30 cm ≈ 12 in. In terms of the graph, the line very nearly passes through the point (12, 30). It also passes through the origin, (0, 0), since 0 cm = 0 in exactly.

The slope of the line is then

[tex]\dfrac{30\,\mathrm{cm}-0\,\mathrm{cm}}{12\,\mathrm{in}-0\,\mathrm{in}} = \dfrac{30\,\rm cm}{12\,\rm in} = \dfrac{5\,\rm cm}{2\,\rm in} = 2.5\dfrac{\rm cm}{\rm in}[/tex]

which means that 1 in ≈ 2.5 cm.

So, if Sarah's height is 64 in, we convert this to cm and find her height is (approximately)

[tex]64\,\mathrm{in} \times 2.5\dfrac{\rm cm}{\rm in} = \boxed{160\,\rm cm}[/tex]

The points which represents the vertices of the given equation are; (15, −2) and (−1, −2).

The complete question gives the equation of the ellipse as; (x-7)²/64+(y+2)²/9=1.

Since, It follows from convention that general equation of ellipse with centre as (h, k) takes the form;

(x-h)²/a² +(y-k)²/b² = 1.

Consequently, it follows from observation that the value of a and b in the given equation in the task content is; √64 = 8 and √9 = 3 respectively.

Since, 8 > 3, The vertices of the ellipse are given by; (h±a, k).

The vertices in this scenario are therefore;

(7+8, -2) and (7-8, -2).

= (15, -2) and (-1, -2).

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