Answer:
Yes
Explanation:
Thus, as a plate moves over the location of a plume eruption, it carries successively older volcanoes with it. As hotspot volcanoes are transported by plate motion away from the mantle plume, hotspot volcanism ceases. Eventually the hotspot volcanoes become extinct, gradually subside, and are eroded by wave action.
Have the best day! :D
Answer:
yes
Explanation:
Thus, as a plate moves over the location of a plume eruption, it carries successively older volcanoes with it. As hotspot volcanoes are transported by plate motion away from the mantle plume, hotspot volcanism ceases. Eventually the hotspot volcanoes become extinct, gradually subside, and are eroded by wave action.
hope this helps!
Wire coils spinning between two magnets will produce …?
A: cold
B : electricity
C: chemicals
D: Steam
Answer:
B
Explanation:
I don't know but its b
The angular quantities L, omega, and alpha are vectors. The vectors point along the axis of rotation with a direction determined by __________.
The vectors point along the axis of rotation with a direction determined by an arrow.
What is a vector?There are two types of physical quantity one is a scaler and another one is a vector.
The quantity that requires only megnitude to define is known as the scalar quantity. While the vector quantities need both megnitude and the direction to define.
The vector quantity is represented by an arrow. The vectors point along the axis of rotation with a direction determined by an arrow.
The angular quantities L, omega, and alpha are vector quantities.
Hence arrow is the correct answer for the blank.
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The direction of the vectors of angular momentum and L, angular velocity omega and the mass alpha is determined using the right hand rule.
What is right hand rule?Righthand rule in physics states that, when we curl our right hand fingers, the direction of the angular momentum and velocity will be in the direction of thumb and curl of fingers determine the axis of rotation.
Angular momentum is a vector quantity defined as the product of moment of inertia and angular velocity where, the angular velocity ω is the rotational analogue of linear velocity i.e.. product of the linear velocity and radius of rotational path.
Therefore, the angular quantities L, angular velocity ω along the axis of rotation can be determined using the right hand rule. Where direction of thump represents the direction of vector components.
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What is the relationship between momentum and kinetic energy.
Answer:
constant object, momentum increases directly with speed
Explanation:
whereas kinetic energy increases the square of the velocity due to energy momentum
Global warming means that
Answer:
The earth is heating up.
Explanation:
This is due to human activities, primarily fossil fuel burning, which increases heat-trapping greenhouse gas levels in Earth's atmosphere.
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Jose’s doctor recommends that he add more cardio to his exercise routine. Which exercise would be the BEST choice?
A.
ballet
B.
jogging
C.
bowling
D.
volleyball
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
jogging
Explanation:
Jogging is often defined as running at a pace less than 6 miles per hour (mph), and it has some significant benefits for people who want to improve their health without overdoing it.
A mass of 5.00 kg in a gravitational field of 7.00 n/kg. What force acts on the mass?
Answer:
35N
Explanation:
force=mass×gravity
the mass is 5 and the gravity is 7 therefore:
force=7×5
=35N
I hope this helps
Tiny mass of 67kg and tubby mass of 83 kg are now on the opposite ends of a see saw and are both 1.4m from the balance point where should their sister teeny whose mass is 32 kg sit so the see saw balances
Answer:
0.7 m between the balance point and Tiny
Explanation:
It's intuitive to say she sould be on the side the smaller mass is placed. How far from the balance point?
Let's call x that distance. and assume that the contraption is "oriented" so that being on the side with tiny (and teeny) gives you a positive distance from the balance point, and negative on the other side.
At equilibrium, the sum of all momentums (momenta?) will be zero:
[tex]67\times 1.4 +32\times x + 83 \times (-1.4) = 0\\32x -16(1.4) = 0 \rightarrow 2x=1.4 x= 0.7[/tex]
In layman's term, she has to be halfway between the balance point and Tiny.
which type of telescope is best used to detect quasars?
Answer:Gamma-Ray Telescopes
Explanation:
Gamma-Ray Telescopes are used for detecting the gamma-ray part of the Electromagnetic Spectrum. These can detect very high-energy gamma-rays from radio galaxies, gamma-ray bursts from stars, supernovae events, and Quasars.
Radio Waves Telescope
A cyclist sitting still at the top of a hill displays gravitational potential energy. What makes it possible for the cyclist to have this type of energy?
Explanation:
because its speed (v) is 0
given. force of 88N and an acceleration of 4 m/s 2 what is the mass?
Give an example of when a conscientious objector might exercise their right:
Which of toby's answers is a correct description of what happens when a 1-kg cart traveling at 1 m/s collides inelastically with another 1-kg cart at rest?.
Answer:
hi I don't know sorry sorry forgive me
Explanation:
sorry
Suppose the gravitational force between two spheres is 30 N. If the magnitude of both masses doubles, and the distance between them tripled. What is the force between the masses?
If both masses double in size and their separation between them triples. 13..33 N will be the force between the masses.
What is gravitational force?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
Given data:
The gravitational force = 30 N
Mass 1 =m₁
Mass 2=m₂
Distance between charges = R
Condition given:
Mass 1 = 2m₁
Mass 2= 2m₂
Distance between charges = 3R
[tex]\rm F = \frac{Gm_1m_2}{R^2}[/tex]
Case 2;
[tex]\rm F'=\frac{G(2m_1)(2m_2)}{(3R)^2} \\\\ F'=\frac{4}{9} \frac{Gm_1m_2}{R^2} \\\\ F'=\frac{4}{9} F \\\\ F'=\frac{4}{9} \times 30 \\\\ F'=13.33 \ N[/tex]
Hence, the forces between the masses will be 13..33 N.
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Fill out the material order form with the Quantity (number of each item) and total cost for
that item (Cost Quantity). Add the totals to ensure you do not exceed $100.
YOU HAVE $100 TO SPEND. NO BONUS POINTS FOR SAVING S.
Use the materials carefully, as they will not be replaced if you damage
them.
Material
Cost ($) Quantity
Cost x Quantity
Straw
2
Paperclip (large)
2.
String (12")
3
Tooth pick
3
Cup
5
Rubber band
5
7
Tape (0.5 m)
7
Paper (8.5" x 11")
Tissue Paper
10
Duct Tape
(.25m)
).
10
Cotton ball
12
Balloon
15
Paper plate
15
Total Cost =
Answer:
Explanation:
Material: Cost ($): Quantity: Cost x Quantity:
Straw 2$ 2x 2$ x 2
Paperclip 2$ 2x 2$ x 2
String 3$ 1x 3$ x 1
Toothpick 3$ 1x 3$ x 1
Cup 5$ 1x 5$ x 1
Rubber band 5$ 1x 5$ x 1
Tape 7$ 1x 7$ x 1
Paper 7$ 1x 7$ x 1
Tissue Paper 10$ 1x 10$ x 1
Duct Tape 10$ 1x 10$ x 1
Cotton ball 12$ 1x 12$ x 1
Balloon 15$ 1x 15$ x 1
Paper Plate 15$ 1x 15$ x 1
total: 100$
hope this really helped!!
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Can Hotspots can be found at the edges of tectonic plates?
Answer:
No.
Explanation:
Hot spots don't appear at the barriers of tectonic plates, instead, they originate at hot centres known as mantle plumes. Mantle plumes exist below the tectonic plates and may develop a string of volcanoes on the Earths surface.
I couldn't answer this question may someone please help me
Distance (s) =20 m
Initial velocity =0 m/s
g=10 m/s²
By using the formula:
v²= u²+ 2as
v²=0²+ 2×10×15
v²= 300
V= 10root over 3
[tex]10 \sqrt{3} [/tex]
For calculating time,
v= u+ at
10 root over 3 = 0+ 10t
10 root over= 10t
t = 1 root over 3
t = 1.73 s
[tex]1 \sqrt{3} [/tex]
The the stone will hit the ground with a velocity of 10 root over 3 m/s in 1 root over 3 sec.
if you have 3 moles of iron, how many grams of iron do you have?
Answer:
55.84 look at periodic table
so 55.84*3= 167.52gFe
2. If Joe rides his bicycle in a straight line for 15 min with an average velocity of 12.5 km/h south, how far has he ridden?
Answer:
3.125 Kilometers
Explanation:
To answer this you just multiply 12.5 by .25 (since 15 minutes is a quarter of an hour) to get 3.125 kilometers ridden.
Scientists are experimenting with a kind of gun that may eventually be used to fire payloads directly into orbit. In one test, this gun accelerates a 5.6-kg projectile from rest to a speed of 3.5 × 103 m/s. The net force accelerating the projectile is 2.5 × 105 N. How much time is required for the projectile to come up to speed?
Answer:
7.84 s
Explanation:
Ok, one step at a time. We know the mass of the projectile, we know the force. Acceleration is easily obtained from Newton second law:
[tex]\vec F = m\vec a[/tex][tex]2.5\times 10^5 = 5.6a \rightarrow a = (2.5/5.6) \times 10^5 = 4.46 \times 10^4 ms^-^2[/tex].
At this point, we know the acceleration, we know initial and final velocity, we can time the ammount of time it took to get there.
[tex]v= v_0 +at \rightarrow 3.5\times10^3 = 0 + 4.46\times10^4 t\\t= \frac{3.5\times10^3}{4.46\times10^4} = 7.84 s[/tex]
Find the volume of this figure.
4 dm
2 dm
3 dm
Answer:
4×2×3= 24dm^3
.......................
Explain why the 4th state of matter would and would NOT make an acceptable force field.
The 4th state of matter would make an acceptable force field.
The 4th state of matter which is plasma would make an acceptable force field because this fourth state of matter is present in ionized form which has two charges on it i.e. cation which is a positive charge and anion which is a negative charge.
We know that charges attract as well repel other objects if they are strong enough. Positive charge repel positive charge but attract negative charge so we can conclude that 4th state of matter would make an acceptable force field.
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a girl runs once around a circular track with a radius of 100m at speed of 10m/s.
calculate her displacement
Answer:
0 m
Explanation:
Displacement is the shortest distance from one ppont to another. Here, the girl returns to the same spot after running. Hence, displacement is 0 m.
How much force is required to move a tractor 60m, when using 250J of work?
Answer:
Work done,W= 250J
Displacement , s = 60
We know that, Work done = Force x displacement
i.e , W = Fxs
250 J = F x 60m
F = 250/60
=4.16 N
Hence , 4.16 N of Force is applied on the body.
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
In an exothermic reaction, energy is
the surroundings.
In an endothermic reaction, energy is
the surroundings.
Trick to identify:-
Exothermic reaction has +∆H sign on product sideEndothermic reaction has -∆H sign on product side or +∆H sign on reactant sideAnswer:
In an exothermic reaction, energy is
✔ released to
the surroundings.
In an endothermic reaction, energy is
✔ absorbed from
the surroundings.
Explanation:
Describe the steps in solving the problem below.
A red cart of mass 4 kg slides to the right on a frictionless track with a velocity of +4 m/s. It collides with the stationary blue cart of mass 1 kg. After the collision, the blue cart has a velocity of +8 m/s. Calculate the velocity of the red cart after the collision. ;)
The velocity of the red cart after the collision is 2 m/s
From the law of conservation of momentum, initial momentum of system = final momentum of system.
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.
Substituting the values of the variables into the equation, we have,
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄
4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s
16 kgm/s + 0 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s - 8 kgm/s = (4 kg)v₃
(4 kg)v₃ = 8 kgm/s
Divide both sides by 4 kg, we have
v₃ = 8 kgm/s ÷ 4 kg
v₃ = 2 m/s
The velocity of the red cart after the collision is 2 m/s.
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The wavelength is 1. 87 x 10-7 m. What is the frequency?.
Answer:
11.7 im pretty sure. i did the work so it should be correct
What kind of force could cause this ball to not be at rest anymore, or cause it to move?
Answer:
friction
Explanation
Answer:
Friction
Explanation:
What force prevents an object at rest?
Sliding Friction While static friction keeps an object at rest, sliding friction slows down an object that slides. If you push an object across a room, you notice the sliding friction between the bottom of the object and the floor. You have to keep pushing to overcome the force of sliding friction.
a car is moving due south for 4hr and covered a distance of 144km what is the velocity of the car?
Answer:
velocity ,V=?,T=4hr,Distance ,144km,
V=distance divide by time
=144/4=36km/hr
A balance and a graduated cylinder are used to determine the density of a mineral sample. The sample has a mass of 14. 7 g and a volume of 2. 2 cm3. What is the density of the mineral sample?.
At what tension, in newtons, must the D-string must be stretched in order for it to be properly tuned
The fundamental frequency, wavelength of the wave, and mass per unit
length of the string, determines the tension in the string.
The tension to which the D-string must be tuned is approximately 19.718 NewtonsReasons:
From a similar question, we have;
Fundamental frequency, f₁ = 146.8 Hz
Oscillating length on the D-string, λ₁ = 0.61 m
Mass of the string = 1.5 × 10⁻³ kg.
We have;
[tex]\displaystyle f_1 \cdot \lambda _1 =\mathbf{ \sqrt{\frac{T}{m/L} }}[/tex]
Therefore;
[tex]\displaystyle T = \mathbf{\frac{f_1^2 \cdot \lambda _1^2 \cdot m }{L}}[/tex]
Which gives;
[tex]\displaystyle T = \frac{146.8^2 \times 0.61^2 \times 1.5 \times 10^{-3} }{0.61 } \approx \mathbf{19.718}[/tex]
The tension to which the D-string must be tuned, T ≈ 19.718 Newtons
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The parameters given in a similar question obtained online are;
The fundamental frequency of the tone, f₁ = 146.8 Hz
The oscillating length on the D-string, λ₁ = 0.61 m
The mass of the string = 1.5 × 10⁻³ kg.