As a promotion, you were offered a free play at the following game: Three balls are drawn, without replacement, from balls numbered 1 through 14. Players try to guess the three numbers drawn, but the order does not matter. • If the player matches all three numbers, they win $100. • If the player matches exactly two numbers, they win $10. If the player matches exactly one number, they win $5.

Answer:

Measuring elevations

Explanation:

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A Weave lane is a single lane used by drivers to enter and exit a freeway.

Weave lanes are known to be lanes that acts as an entrance and exits for a lot of cars in highways.

Hence, one can say that A Weave lane is a single lane used by drivers to enter and exit a freeway.

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The Answer is D. The technician should remove jewelry

Explanation: A technician has been given a PC that is not powering up. After brief troubleshooting, the technician comes to the conclusion the power supply needs to be replaced. Which of the following is the NEXT step in the process of performing the repair?

The equivalent cost per mile is mathematically given as

Equivalent kilometer =  0.61

Distance is a measure of the distance between two places. Depending on context, the term "distance" might refer to a precise measurement or an approximation based on other factors. |AB| can be used to represent the distance between two points.

Generally, the equation for Equivalent annual cost  is  mathematically given as

EAC= $ 25,000 ( A/P, 10% , 3 years ) + $ 900 + $ 0.22 * 22,000 - $ 8000 ( A/F , 10% , 3 years)

Therefore

EAC= $ 25,000 * 0.402115 + $ 5740 - $ 8000 * 0.302115

EAC= $ 13,375.955

In conclusion, the Equivalent cost per kilometer

Equivalent kilometer [tex]=\frac{ 13,375.955}{22,000}[/tex]

Equivalent kilometer =  0.61

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An expression for the voltage drop between inverter and PUC

[tex]V D \rightarrow \frac{I(\Omega / k f t) d}{2770}$[/tex]

This is further explained below.

Generally, the equation for Voltage drop is  mathematically given as

[tex]V=\frac{I R}{V}[/tex]

Therefore

[tex]\%$ Voltage drop $=\frac{I R}{V} * 100\\\\$\rightarrow \frac{100 I(\Omega / 15 f t) d}{1000 V_{p}}\\\\$V_{P}=277 \mathrm{~V}$[/tex]

[tex]V D=\frac{I(\Omega / \mathrm{kft}) d}{10 * 2770} \rightarrow \frac{I(\Omega / \mathrm{kft}) d}{2770} \mathrm{~V}\\\\$\% V D \rightarrow \frac{I(\Omega / k f t) d}{2770}$[/tex]

In conclusion, the expression for the voltage drop between inverter and PUC

[tex]V D \rightarrow \frac{I(\Omega / k f t) d}{2770}$[/tex]

CQ

An inverter has a balanced 3-phase, 277/480 V output and is installed a distance, d, ft from the point of utility connection. The DC/AC converter is shown below in the inverter. And the distance d is the physical separation between this DC/AC converter and the PCC.

Derive an expression for the voltage drop between inverter and PUC in terms of d using the basic equation %VD =100IR/V.

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A broken yellow line on the pavement tells that the adjacent lane is traveling in the opposite direction and passing is permitted.

A broken white line on the pavement show that the adjacent lane is traveling in the same direction and passing is permitted.

Pavement markings are known to be tools that are used to pass infor or messages to roadway users.

Note  that they tell the part of the road that one need to use, give information about conditions ahead, and others

Note that A broken yellow line on the pavement tells that the adjacent lane is traveling in the opposite direction and passing is permitted.

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Answer: The red color on the cylinder is indicative of the material's flammability.

Explanation:

In regards to high-wind installations, if an old composition asphalt shingle roof is going to be replaced, the roofing contractor should remove the existing shingles and underlayment.

High Wind is known to be a newly created installation techniques that is often used in the installation of offshore wind turbines and this is often done at  higher wind speeds.

Note that, In regards to high-wind installations, if an old composition asphalt shingle roof is going to be replaced, the roofing contractor should remove the existing shingles and underlayment.

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The option that best describes electronic stability control are:

The electronic stability control is known to be that which helps to hinder loss of control in regards to curves and emergency steering maneuvers and it often stabilizes  the car if it begins to move off an intended path.

Hence, The option that best describes electronic stability control are:

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The thermal energy when the spark-ignition engine operates on an Otto cycle with a compression ratio of 9 and temperature limits of 30°C and 1000oC is 58%.

From the information given, we are told that spark-ignition engine operates on an Otto cycle with a compression ratio of 9 and temperature limits of 30°C and 1000oC.

The thermal energy will be:

= 1 - 1/(1.4 - 1)

= 0.58

= 58%

Also, the mass flux of air will be illustrated below:

T2 = 729.70k

W = 224.60kj

Therefore, the mass flux will be:

= 500/224.60

= 2.226kg/s

In conclusion, the the mass flux will be 2.226kg/s.

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The fence height, additional structures, and architectural design are generally categorized under covenants.

The primary private land-use control is known to be a form of a deed restrictions, that hinders what a person can do on the property as regards to the owner.

Note that in the case above, the fence height, additional structures, and architectural design are generally categorized under covenants.

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The time at which the acceleration is zero is given as 4.66 seconds

First we have to solve for the velocity. To do this, we would have to take the derivative.

[tex]s = e^-0.5t (3 t - 2)[/tex]

Then velocity =

[tex]ds/dt = e^-0.5t (4 - 1.5 t)[/tex]

The acceleration can be gotten by finding the second derivative

[tex]a = dv/dt = e^-0.5t (.75 t - 3.5)[/tex]

To find t at acceleration = 0

We have

[tex]0 = e^-0.5t (.75t - 3.5)[/tex]

This gives t to be

t = 4.66 sec

The displacement of a particle which moves along the s-axis isgiven by

s = (-2+3t)e^(-0.5t), where s is in meters and t is inseconds. Plot the displacement, velocity and acceleration versustime for the first 20 seconds of motion. Determine the time atwhich the acceleration is zero.

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Maximum absolute values of the shear = 28 KN

Maximum absolute values of bending moment = 5.7 KN.m

A) We can see the beam loaded in the first image attached.

For the shear diagram, let us calculate the shear from point load to point load.

From A to C, summing vertical to zero gives; ∑fy = 0: -20 - V = 0

V = -20 KN

From C to D, summing vertical to zero gives; ∑fy = 0: -20 + 48 - V = 0

V = 28 KN

From D to E, summing vertical to zero gives; ∑fy = 0: -20 + 48 - 20 - V = 0

V = 8 KN

From E to B, summing vertical to zero gives; ∑fy = 0: -20 + 48 - 20 - 20 - V = 0

V = -12 KN

For the bending moment diagram, let us calculate the bending moment from point load to point load.

At point A, the bending moment would be zero. Thus, M_A = 0 KN.m

At point C, taking moment about point C and equating to zero gives;

M_C = 0. Thus; 20(0.225) + M = 0

M = -4.5 KN.m

At point D, taking moment about point D and equating to zero gives;

M_D = 0. Thus; 20(0.525) - 48(0.3) + M = 0

M = 3.9 KN.m

At point E, taking moment about point E and equating to zero gives;

M_D = 0. Thus; 20(0.75) - 48(0.525) + 20(0.225) + M = 0

M = 5.7 KN.m

At point B, taking moment about point E and equating to zero gives;

M_E = 0. Thus; 20(1.05) - 48(0.825) + 20(0.525) + (20 * 0.3) + M = 0

M = 2.1 KN.m

2) From the attached diagrams, we can deduce that;

Maximum absolute values of the shear = 28 KN

Maximum absolute values of bending moment = 5.7 KN.m

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The protection that  must be provided when installing a cable in a notched stud or joist are:

If a nonmetallic cables is said to pass through holes or slots in metal framing members, the cable that need to ]be protected is through bushings or grommets and it is used to cover all metal edges and rightly fastened in the opening before one can install the cable.

Hence, The protection that  must be provided when installing a cable in a notched stud or joist are:

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The higher level of acceleration should be used when accelerating on a short highway entry ramp.

Given data:

When accelerating on a short highway entry ramp, you should use a higher level of acceleration to safely merge with the traffic already on the highway. This is particularly important when the entry ramp is short, as you need to reach the speed of the highway traffic and find a suitable gap to merge into the flow.

Using a higher level of acceleration allows you to match the speed of the vehicles on the highway more quickly and efficiently, reducing the risk of causing disruptions or potential hazards. It's essential to accelerate smoothly and decisively to ensure a safe merge onto the highway. Always follow traffic rules and guidelines while merging onto highways to ensure the safety of yourself and others.

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For the specified values, the saturated density is 430 Kg/m3, whereas the bulk density is 2700 Kg/m3.

Given data

Void ratio e = 0.43

Specific gravity Gs = 2.7

density of water ρw = 1000 Kg/m^3

1)Mass of soil solids = Gs ρw

= 2.7*1000

= 2700 Kg/m^3

2)Value of eρw

= 0.43*1000

=430 Kg/m^3

Soil compaction is indicated by bulk density. It is determined by dividing the dry weight of the soil by its volume.

Both the volume of soil particles and the volume of soil particle pores are included in this volume. Typically, bulk density is stated in g/cm3.

The Influence of Inherent - The density of soil mineral (sand, silt, and clay) and organic matter particles, as well as how they are packed, all affect bulk density. As a general rule, the bulk density of most rocks is 2.65 g/cm3, hence the optimal soil is one with a medium texture.

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if two 1.5 ya alt batteries are connected to head to the tail the voltage is 3.0 volt it is the because the battery is insidious reduce a voltage equal to number of battery is multiplied by the voltage of individual

The net radiation heat transfer between the two plates per unit surface area of the plates with shield and without shied are respectively; 2282.76 W/m² and 9766.75 W/m²

We are given;

Temperature 1; T₁

Temperature 2; T₂

Temperature 3; T₃

Emissivity 1; ε₁ = 0.3

Emissivity 2; ε₂ = 0.7

Emissivity 3; ε₃ = 0.2

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with shield is;

Q'₁₂ = σ(T₁⁴ - T₂⁴)]/[((1/ε₁) + (1/ε₂) - 1) + ((1/ε₃,₁) + (1/ε₃,₂) - 1)]

Q'₁₂ = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[((1/0.3) + (1/0.7) - 1) + ((1/0.15) + (1/0.15) - 1)]

Q'₁₂,shield = 2282.76 W/m²

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with no shield is;

Q'₁₂,no shield = σ(T₁⁴ - T₂⁴)]/((1/ε₁) + (1/ε₂) - 1))

Q'₁₂,no shield = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[(1/0.3) + (1/0.7) - 1)]

Q'₁₂,no shield = 9766.75 W/m²

Then the ratio of radiation heat transfer for the two cases becomes;

Q'₁₂,shield/Q'₁₂,no shield = 2282.76/9766.75 = 0.2337 or 4/17

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A high compression ratio may result in compressor failure.

A compressor refers to a mechanical device that is designed and developed to provide power to refrigerators, especially by increasing the pressure on air or other applicable gases.

According to heating, ventilation, and air conditioning (HVAC) information, a high compression ratio of 8: 1 or higher is most likely to result in compressor failure.

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The capacitance is affected is that the capacitance increases because of the insertion of Teflon.

A `is known to be a form of a device that is said to be used to save some amount of charges in any electrical circuit.

Note that the capacitor functions on the principle that the capacitance of a conductor is said to increases if an earthed conductor is  taken close to it.

Hence, The capacitance is affected is that the capacitance increases because of the insertion of Teflon.

See full question below

A dielectric material, such as Teflon®, is placed between the plates of a parallel-plate capacitor without altering the structure of the capacitor. The charge on the capacitor is held fixed. How is the electric field between the plates of the capacitor affected?

The electric field is not altered, because the structure remains unchanged.

The electric field becomes zero after the insertion of the Teflon®.

The electric field decreases because of the insertion of the Teflon®.

The electric field becomes infinite because of the insertion of the Teflon®.

The electric field increases because of the insertion of the Teflon®.

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First generation computers were also referred to as vacuum-tube computer and they can be defined as a type of computer system that were designed and developed to make use of vacuum tubes for their logic circuitry.

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Complete Question?

What are the features of first generation computers?

Answer:

Continued and/or excessive heat and centrifugal force on turbine engine rotor blades is likely to cause creep.

Explanation:

Creep is a technical term for permanent elongation that happens over time. Heat will result in the rotor blades' material becoming less dense which will allow the material to stretch since the force is centrifugal.

Answer:

passage of the English will of right

"1/2" is the right response to this question. Approximately half of the governor gear in vertical crankshaft engines that have a slinger or governor gear and the correct amount of oil in the crankcase is placed above the oiled surface. Draining the oil from the top oil fill tube, as well as the fuel tank and the engine, should be done when the governor gear is about halfway through its rotation.

This is further explained below.

Generally, Engine connecting rods are joined to the crankshaft through the crank mechanism, which is made up of many rotating parts, including the crankshaft, the crankpins, and the crankshaft gears.

In conclusion, "1/2" is the right answer. About half of the governor gear is visible above the oil surface in vertical crankshaft engines with a slinger or governor gear. In order to drain the oil from the top oil fill tube, both the fuel tank and the engine should be at about half of the governor gear after it is completed.

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Basic speed law requires individuals driving at speeds that are reasonable and prudent for conditions.

This is defined as the rate of change of the position of a body with respect to time and the unit is metre per second.

The basic speed law states that speeds which are reasonable and prudent should be adopted by drivers so as to avoid accidents and potential risks to other road users. Appropriate punishment are also meted out to defaulters in this type of scenario.

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The strategies for dealing with the problem of self-occlusion in object data capture are:

Occlusion is known to often takes place if  two or more objects are seen too close and are seen to be merged or combine with one another.

Note that in the case above, The strategies for dealing with the problem of self-occlusion in object data capture are:

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The coordinate direction angles of F in order to produce the maximum moment about the a-a axis is 14.49Nm and this moment is 15Nm.

What is direction?
Direction is a term that can refer to a number of different concepts. Generally speaking, direction is a line of travel or an orientation in physical space. Direction can also refer to a goal or purpose for which one is striving, such as a career path or a life path. Directions can also be given in terms of instructions, as in directions for using an appliance, directions for playing a game, or even directions for a recipe.

The moment of the force F about the a-a axis is given by:

M = F × d × sin(\alpha + \gamma)

M = 30N × 0.5m × sin(60° + 45°)

M = 30N × 0.5m × 0.9659

M = 14.49Nm

The coordinate direction angles of F in order to produce the maximum moment about the a-a axis are (45°, -45°). The maximum moment is given by:

M = F × d × 1

M = 30N × 0.5m × 1

M = 15Nm

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Answer:

The wheel will go through 1146 revolutions in 5 minutes.

Explanation:

We can the formula:

[tex]\boxed{\omega = \frac{2 \pi}{T}}[/tex]

where

ω ⇒ angular speed (24 rad/s),

T ⇒ time period (? s),

and solve for T to find the time it takes for the wheel to complete one revolution.

⇒  [tex]24 = \frac{2 \pi}{T}[/tex]

⇒  [tex]T = \bf \frac{2 \pi}{24}[/tex]  s

This means it takes [tex]\bf \frac{2 \pi}{24}[/tex] seconds for the wheel to complete one revolution.

Now, using the unitary method,

In [tex]\frac{2 \pi}{24}[/tex] seconds          ⇒    1 revolution completed

In 1 second              ⇒    1 ÷ [tex]\frac{2 \pi}{24}[/tex]   =  [tex]\frac{24}{2 \pi}[/tex]  revolutions completed

In (5 × 60 = ) 300s  ⇒     [tex]\frac{24}{2 \pi}[/tex]   ×  300   = 1145.9

                                                            ≅ 1146 revolutions completed

The first step that is needed in order to shift the reverse would be to Push down on the shift lever.

This is the term that is used in driving to explain the scenario that occurs due to the fact that a person has to go through a system of changing gears while they are driving. An example of how this is used is when a person says that there car has a manual transmission instead of automatic transmission.

This would mean that this person would be the one that would be changing the gears while driving on their own. To do this what would be done is to Push down on the shift lever.

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The section(s) of the Code emphasize that all circuiting must be done so as to avoid the damaging effects of induction heating is 300.35, 300.3(B), and 300.20(A).

The term induction heating is known to be a form of heating of material that occurs via an electric current that makes a flow via the material or its container through the means of electromagnetic induction.

Hence, The section(s) of the Code emphasize that all circuiting must be done so as to avoid the damaging effects of induction heating is 300.35, 300.3(B), and 300.20(A).

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