Answer:
condensation?
Explanation:
Durante su práctica un atleta recorre en línea recta una distancia de 900m en un tiempo de 170 segundos. ¿Cuál fue su rapidez promedio?
Answer:
Velocidad promedio = 5.29 m/s
Explanation:
Dados los siguientes datos;
Distancia = 900 m
Tiempo = 170 segundos
Para encontrar la velocidad media;
La velocidad se puede definir como la distancia recorrida por unidad de tiempo. La velocidad es una cantidad escalar y, como tal, tiene magnitud pero no dirección.
Matemáticamente, la velocidad viene dada por la fórmula;
[tex] Velocidad = \frac{distancia}{tiempo}[/tex]
Sustituyendo en la fórmula anterior;
[tex] Velocidad = \frac{900}{170}[/tex]
Velocidad = 5.29 m/s
Por lo tanto, la velocidad promedio del automóvil es 5.29 metros por segundo.
Express 0.00005 s in µs
Answer:
0.00005 second =
50 microseconds
Time
0.00005
Second
50
Microsecond
An airplane with constant speed 696 mph than another 40 minutes constant speed 804 mph what is distance it go?
Answer:
536 miles
Explanation:
If the airplane is running at a speed of 804 miles per hour, and covers a distance, x in a particular number of mile. The distance in mile can be gotten they the application of direct formula. Multiplying the speed by the time it took, and thus
804 mph * 40
Remember the time is in minutes and not hours, so, you convert it to hours.
804 * 40/60 hours =
536 miles
mechanical energy that has been "lost" to friction has actually been destroyed.
Answer:
Yes
Explanation:
The friction is bigger than the mechanical energy so it kind off takes over the mechanical energy. but if the friction decreases mechanical energy can work on the object again
The pressure difference, , across a partial blockage in an artery (called a stenosis) is approximated by the equation where is the blood velocity, the blood viscosity , the blood density , the artery diameter, the area of the unobstructed artery, and the area of the stenosis. Determine the dimensions of the constants and . Would this equation be valid in any system of units
The question is incomplete. The complete question is :
The pressure difference, Δp, ac[tex]K_u[/tex]ross a partial blockage in an artery (called a stenosis) is approximated by the equation :
[tex]$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$[/tex]
Where V is the blood velocity, μ the blood viscosity {FT/L2}, ρ the blood density {M/L3}, D the artery diameter, [tex]A_0[/tex] the area of the unobstructed artery, and A1 the area of the stenosis. Determine the dimensions of the constants [tex]K_v[/tex] and [tex]K_u[/tex]. Would this equation be valid in any system of units?
Solution :
From the dimension homogeneity, we require :
[tex]$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$[/tex]
Here, x means dimension of x. i.e.
[tex]$[ML^{-1}T^{-2}]=\frac{[K_v][ML^{-1}T^{-1}][LT^{-1}]}{[L]}+[K_u][1][ML^{-3}][L^2T^{-2}]$[/tex]
[tex]$=[K_v][ML^{-1}T^{-2}]+[K_u][ML^{-1}T^{-2}]$[/tex]
So, [tex]$[K_u]=[K_v]=[1 ]=$[/tex] dimensionless
So, [tex]K_u[/tex] and [tex]K_v[/tex] are dimensionless constants.
This equation will be working in any system of units. The constants [tex]K_u[/tex] and [tex]K_v[/tex] will be different for different system of units.
Activity 1 MATCH IT
Directions: Match Column A to Column B. Write your answer on the space provided before the number.
COLUMN A
__1. Hiking
__2. Orienteering
__3. Zumba
__4. Volleyball
__5.badminton
COLUMN B
A. It is an outdoor navigational recreational activity using specially drawn and detailed maps.
B. Created through on-the –spot aerobics class using the non- traditional music.
C.Going on an extended walk for the purpose of pleasure and exercise.
D. Can be traced from the ingenuity of William J. Morgan in 1895 at Holyoke Massachusetts.
E. Games are held inside the gym to avoid the effect of air in the flight of the shuttle.
Answer:
1. A hiking
2. C
3. B
4. D
5. E
How can you increase efficiency of a simple machine??
Answer:
Efficiency can be increase by using rollers in conjunction with the inclined plane. Wedge. The wedge is an adaptation of the inclined plane. It can be used to raise a heavy load over a short distance or to split a log.
Explanation:
Hope it helps
explain how conservation of mechanical energy occurs a kicking a ball
What does the survey reveal about your participation in rereational activity
Answer:
uugizj8iwuu3ueugeeuieieyeueureir
The three scientists credited with using all available data and correctly determing the sturcture of dna from many years of previous work are
Answer:
James Watson, Francis Crick, and Maurice Wilkins
Explanation:
The three scientists that used the available data ( x-ray images of DNA provided by Rosalind Franklin) to correctly determine the structure of DNA are : James Watson, Francis Crick, and Maurice Wilkins.
These scientists discovered the structure of DNA in 1953 and they received, and they receive a Nobel Prize in Physiology or Medicine for their discovery
what is the relationship between the energy of a wave and ruts frequency?
Answer:
Just as wavelength and frequency are related to light, they are also related to energy. The shorter the wavelengths and higher the frequency corresponds with greater energy. So the longer the wavelengths and lower the frequency results in lower energy. The energy equation is E = hν.
Explanation:
what happens if a voltmeter is connected in series with other components of the circuit (i.e , ammeter, cell, battery, resistor and wires). Why is it so?
Answer:the voltmeter measures the potential difference of the circuit,. Voltmeter is a device used to measure potential difference.
Explanation:
ΡΟ. . When preparing for any of the golf variation games (golf foot golf, disc golf), a person should consider the following before they start.
O Distance
O Terrain
O Wind Speed
O All of the above
Answer:
All of the above
Explanation:
To ensure the ball go to where we expected it go
quicklime which is calcium oxide, is made by heathig limestone in a furnace as per the equation :
CaCO3(s)CaO(s)+CO2
7.00Kg of calcium oxide was formed. what mass of calcium carbonate was heated?
Answer:
h2 PRD algo trata gevbjjgcvnkoytewxc.
Answer:
12.5kg
Explanation:
The process is explained in the paper
Which of the following graph is used for determining the instantaneous velocity from the slope?
A. distance-time graph
B. x - t graph
C. both of these
D. none of these
Answer:
B. x - t graph
Explanation:
A position-time (x-t) graph is a graph of the position of an object against (versus) time.
Generally, the slope of the line of a position-time (x-t) graph is typically used to determine or calculate the velocity of an object.
An instantaneous velocity can be defined as the rate of change in position of an object in motion for a short-specified interval of time. Thus, an instantaneous velocity is a quantity that can be found by measuring the slope of a line that is tangent to a point on the graph.
Hence, the x - t graph also referred to as the position-time graph is used for determining the instantaneous velocity from the slope.
For example;
Given that the equation of motion is S(t) = 4t² + 2t + 10. Find the instantaneous velocity at t = 5 seconds.
Solution.
[tex] S(t) = 4t^{2} + 2t + 10[/tex]
Differentiating the equation, we have;
[tex] S(t) = 8t + 2 [/tex]
Substituting the value of "t" into the equation, we have;
[tex] S(5) = 8(5) + 2 [/tex]
[tex] S(5) = 40 + 2 [/tex]
S(5) = 42 m/s.
Answer:
B. x - t graph
Explanation:
Thus, an instantaneous velocity is a quantity that can be found by measuring the slope of a line that is tangent to a point on the graph. Hence, the x - t graph also referred to as the position-time graph is used for determining the instantaneous velocity from the slope.
If the amplitude of a sound wave is increased by a factor of four,how does the energy carry by the sound wave in each time interval change?
Answer:
The energy will be increased by a factor 16
Explanation:
Mathematically, we have it that the energy carried by the sound wave is directly proportional to the square of the amplitude
So we have it that;
E = k * A^2
where E is the wave energy
K is the constant value
A is the amplitude value
So;
If E1 = k * (A1)^2
E2 = k * (A2)^2
But A2 = 4A1
E2 = k * (4A1)^2
E2 = k * 16(A1)^2
Divide E2 by E1
E2/E1 = k/k * 16(A1)^2/(A1)^2
E2/E1 = 16
E2 = 16 * E1
so simply, the energy will be increased by a factor of 16
This circuit has five bulbs (A, B, C, D, and E). Select which bulbs would turn off if bulb C was unscrewed.
Answer:
C, A and E
Explanation:
In theory you always assume that the prostive is going to the negtive and since C, A and E are in series they all will turn off will turn off
Which instrument changes kinetic energy into electrical energy?
electric motor
hair drier
electric bell
dynamo
Answer:
Dynamo
Explanation:
As we all know, there are dynamos in bicycles. When we paddle the cycle, the wheels of the cycle rotates by generating kinetic energy. When the wheels rotate, the dynamo starts to rotate. This makes the motor inside the dynamo rotates and generate electrical energy.
why are circuit breakers used in parts of national grid ?
Answer:
To protect control circuits or small devices with insufficient cutting power
Explanation:
A.All three bulbs will go out
B.Bulbs 2 and 3 will go out, but bulb 1 will remain lit
C. All three bulbs will go out
D. Bulb 3 will go out, but bulbs 1 and 2 remain lit
Answer:
(D)
Explanation:
When switch C is opened then, Current is not flowing across 3 So bulb 3 will go out.
But current is flowing across 1 and 2 bulb because their switch is closed
therefore bulb 1 and 2 will remain it.
Hence, option (D) will be correct.
Find the acceleration a body whose velocity increases from 11m/s to 33m/s in 10 seconds
Answer:
I am not sure if this is the answer
acceleration: 2.2m/s
Explanation:
here
initial velocity(u): 11m/s
Final velocity(v): 33m/s
time taken(t): 10 s
now
a:v-u/t
or
acceleration:final velocity-initial velocity/time taken
or
a: 33-11/10
or
a:22/10, divide it
: a=2.2m/s#
Um comentarista de futebol certa vez comentou:"A bola bateu na trave e voltou duas vezes mais forte". Sabendo que quando a bola atinge a trave ela acerta com uma força chamada de ação e a outra trave acerta com outra força chamada de reação explique porque a frase documentalista soa errada.
Answer:
Por ela ter batido na trave, não tem como voltar 2x mais forte, por que toda ação correspondente a uma reação de igual intensidade, mas que atua no sentido oposto
Explanation:
Una prenda de 320gramos de ropa gira en el interior de una lavadora si dicha lavadora tiene 40 cm y gira con una frecuencia de 4 hz halla el periodo la velocidad angular la fuerza con la que gira la prenda y la velocidad lineal de la lavadora
Answer:
Período del tambor: [tex]T = 0.25\,s[/tex], fuerza sobre la prenda: [tex]F \approx 80.852\,N[/tex], velocidad lineal del tambor: [tex]v \approx 10.053\,\frac{m}{s}[/tex], velocidad angular del tambor: [tex]\omega \approx 25.133\,\frac{rad}{s}[/tex].
Explanation:
La expresión tiene un error por omisión, su forma correcta queda descrita a continuación:
"Una prenda de 320 gramos de ropa gira en el interior de una lavadora si dicha lavadora tiene un radio de 40 centímetros y gira con una frecuencia de 4 hertz. Halle a) el período, b) la velocidad angular, c) la fuerza con la que gira la prenda y d) la velocidad lineal de la lavadora."
El tambor gira a velocidad angular constante ([tex]\omega[/tex]), en radianes por segundo, lo cual significa que la prenda experimenta una aceleración centrífuga ([tex]a[/tex]), en metros por segundo al cuadrado. En primer lugar, calculamos el período de rotación del tambor ([tex]T[/tex]), en segundos:
[tex]T = \frac{1}{f}[/tex] (1)
Donde [tex]f[/tex] es la frecuencia, en hertz.
([tex]f = 4\,hz[/tex])
[tex]T = \frac{1}{4\,hz}[/tex]
[tex]T = 0.25\,s[/tex]
Ahora determinamos la fuerza aplicada sobre la prenda ([tex]F[/tex]), en newtons:
[tex]F = m\cdot a[/tex] (2)
[tex]F = \frac{4\pi^{2}\cdot m \cdot r}{T^{2}}[/tex] (2b)
Donde:
[tex]m[/tex] - Masa de la prenda, en kilogramos.
[tex]r[/tex] - Radio interior del tambor, en metros.
([tex]m = 0.32\,kg[/tex], [tex]r = 0.4\,m[/tex], [tex]T = 0.25\,s[/tex])
[tex]F = \frac{4\pi^{2}\cdot (0.32\,kg)\cdot (0.4\,m)}{(0.25\,s)^{2}}[/tex]
[tex]F \approx 80.852\,N[/tex]
La velocidad lineal de la lavadora es:
[tex]v = \frac{2\pi\cdot r}{T}[/tex] (3)
([tex]r = 0.4\,m[/tex], [tex]T = 0.25\,s[/tex])
[tex]v = \frac{2\pi\cdot (0.4\,m)}{0.25\,s}[/tex]
[tex]v \approx 10.053\,\frac{m}{s}[/tex]
Y la velocidad angular del tambor de la lavadora:
[tex]\omega = \frac{2\pi}{T}[/tex]
([tex]T = 0.25\,s[/tex])
[tex]\omega = \frac{2\pi}{0.25\,s}[/tex]
[tex]\omega \approx 25.133\,\frac{rad}{s}[/tex]
Which of the following is NOT a type of satellite?
a. a baseball thrown from pitcher to catcher
b. a rice bag being thrown towards a cornhole
c. a paper airplane being thrown
d. a jet ski tied to a dock
What is an example of a series circuit
Answer:
Explanation
The most famous and common example is Christmas tree lights. You can't tell easily by looking at them whether they are in series or parallel. But you sure know the difference when one of them burns out. When that happens, the whole string goes dead. No matter what you do (other than find out which bulb burned out) will not fix the problem.
Another example is anything that is temperature controlled. For example a furnace is controlled by a thermostat. When the room temperature reaches a certain point, the thermostat is constructed in a certain way so that it forms an open circuit and no current can flow through it. The furnace motor turns off and the furnace stops pumping hot air into a room.
Write the equation which links gravitational field strength,gravitational potential energy,height and mass
Answer:
PE = mgh
Explanation:
PE is potential energy
m is mass
g is gravitational field strength
h is height
A sled with mass 11.00 kg moves in a straight line on a frictionless horizontal surface. At one point in its path, its speed is 4.00 m/s; after it has traveled a distance 3.00 m beyond this point, its speed is 7.00 m/s. Use the work-energy theorem to find the force acting on the sled, assuming that this force is constant and that it acts in the direction of the sled's motion.
Answer:
The magnitude of the force acting on the sled is 60.5 newtons.
Explanation:
The Work-Energy Theorem states that the work done by the external force applied on the sled ([tex]W[/tex]), in joules, is equal to the change of its translational kinetic energy ([tex]\Delta K[/tex]), in joules:
[tex]W = \Delta K[/tex] (1)
By definitions of work and translational kinetic energy we expand the equation above:
[tex]F\cdot s = \frac{1}{2}\cdot m\cdot (v_{2}^{2}-v_{1}^{2})[/tex] (1b)
Where:
[tex]F[/tex] - External force applied on the sled, in newtons.
[tex]s[/tex] - Travelled distance, in meters.
[tex]v_{1}, v_{2}[/tex] - Initial and final velocities, in meters per second.
If we know that [tex]m = 11\,kg[/tex], [tex]v_{1} = 4\,\frac{m}{s}[/tex], [tex]v_{2} = 7\,\frac{m}{s}[/tex] and [tex]s = 3\,m[/tex], then the external force applied on the sled is:
[tex]F = \frac{m\cdot (v_{2}^{2}-v_{1}^{2})}{2\cdot s}[/tex]
[tex]F = \frac{(11\,kg)\cdot \left[\left(7\,\frac{m}{s} \right)^{2}-\left(4\,\frac{m}{s} \right)^{2}\right]}{2\cdot (3\,m)}[/tex]
[tex]F = 60.5\,N[/tex]
The magnitude of the force acting on the sled is 60.5 newtons.
When playing a game of disc golf, each throw to your target is considered to be a O Point O Stroke O Hit O Toss
Answer:
an o point i think
Explanation:
How does the temperature affect the speed of sound?
Explanation:
The relation between the speed of sound and the temperature is direct. As the temperature increases, the speed of sound also increases. If the substance is heated up, its molecules moves faster. As a result they collide faster and hence the speed increases. There is a relation between the speed of sound and the temperature i.e.
[tex]v=331+0.61T[/tex]
Hence, this is the required solution.
how moment act when applying a force on the pedal of a bicycle
Answer:
Forces that the rider applies to the pedals, saddle and handlebars during speeding, hill climbing and starting are estimated from cine film records using elementary mechanics. The results are compared with force measurements obtained from an instrumented pedal. Pedal forces of up to three times bodyweight were recorded during starting. Handlebar loads were always significantly large.