Assignment 3: Chatbot
What the code for assignment 3: chatbot Edhesive.

Coding is difficult but I don't have a chatbot

Answer:

import random

# Introduction

print("Welcome to the fashion chatbot! I'm here to help you with your fashion preferences.")

# Ask for user's first name

print("What is your first name?")

name = input()

# Ask for user's shoe preference

print("What shoes do you like?")

shoe_preference = input()

# Use if-elif-else statement to respond to user's shoe preference

if shoe_preference == "Converse":

 print("Nice, casual is always in!")

elif shoe_preference == "Boots":

 print("Cool, boots are a versatile choice.")

else:

 print("Great choice!")

# Ask for user's age

print("How old are you?")

age = input()

# Use if-elif-else statement to respond to user's age

if int(age) < 18:

 print("It's a great time to start exploring your style!")

elif int(age) < 25:

 print("You're at a fun age to experiment with your fashion choices.")

else:

 print("It's always a good time to try out new fashion styles!")

# Use a randomly generated number to randomly respond

random_number = random.randint(1, 3)

if random_number == 1:

 print("I think I might know your style.")

elif random_number == 2:

 print("You have a unique sense of style.")

else:

 print("You have great fashion taste.")

# Ask for user's favorite top

print("So, " + name + ", what is your favorite top?")

top_preference = input()

# Use if-elif-else statement to respond to user's top preference

if top_preference == "Graphic Tees":

 print("That's a good choice.")

elif top_preference == "Button-up shirts":

 print("Classy and sophisticated.")

else:

 print("Great choice!")

# Use a randomly generated number to randomly respond

random_number = random.randint(1, 3)

if random_number == 1:

 print("Ay that's lit.")

elif random_number == 2:

 print("wow, so stylish!")

else:

 print("That's in right now.")

# Ask for user's bottom preference

print("I like where this is going.")

print("What about your choice of bottom?")

bottom_preference = input()

# Use if-elif-else statement to respond to user's bottom preference

if bottom_preference == "Jeans":

 print("Jeans are a classic choice.")

elif bottom_preference == "Cargo pants":

 print("You can't go wrong with those.")

else:

 print("Great choice!")

# Ask for user's head accessory preference

print("What about your head accessory?")

head_accessory_preference = input()

# Use if-elif-else statement to respond to user's head accessory preference

if head_accessory_preference == "Beanies":

   print("Beanies are fun!")

elif head_accessory_preference == "Baseball hats":

   print("Baseball hats are a popular choice.")

else:

   print("Unique choice!")

# End conversation

print("Well, " + name + ", it was awesome getting to know your style.")

Why did Madison recommend a server-based network for SEAT?

A) It provides centralized access to resources.
B) It is simpler to expand.
C) It is easier to operate.
D) It is less expensive.
E) It provides more security.

MTBF is a measurement of

A) the speed at which a storage device can read and write data
B) the number of digits used to store a computer file
C) the average length of a time a storage device can reliably hold data without it beginning to degrade
D) the average length of time between failures on a device

What did the police threaten to do?

Code to be written in python:
Correct answer will get brainliest! :)

For any positive integer S, if we sum up the squares of the digits of S, we get another integer S1. If we repeat the process, we get another integer S2. We can repeat this process as many times as we want, but it has been proven that the integers generated in this way always eventually reach one of the 10 numbers 0, 1, 4, 16, 20, 37, 42, 58, 89, or 145. Particularly, a positive integer S is said to be happy if one of the integers generated this way is 1. For example, starting with 7 gives the sequence {7, 49, 97, 130, 10, 1}, so 7 is a happy number.


Your task is to write a function compute_happy_numbers(range1, range2) , where range1 and range2 are each tuples of the form (lower_bound, upper_bound), and returns a tuple containing: (1) the number of happy numbers in range1, (2) the number of happy numbers in range2, (3) the number of the range (1 or 2) containing more happy numbers, or None if both ranges have the same number of happy numbers.

def compute_happy_numbers(range1, range2):
"""Your code here"""

Test Cases:
compute_happy_numbers((1,1), (1,1)) (1, 1, None)
compute_happy_numbers((1, 10), (11, 100)) (3, 17, 2)

use router,switches and Hubs to design a simple network for maendeleo institute of Technology having 240 employees.The institute have five department: computer science has 100 employees ,information technology 60 employees ,Account 40 employees ,Human resource has 20 employees and marketing has 20 employees . Require: .network topology showing five network that corresponding to five department .use class C IP addresses (example 192.168.10.0/24) to show subnet ID and broadcast ID of each department , the IP address must not overlap .consider scalability .Give reason for your choice /decision​

solve the MRS y,x = 12 mean? for constant mariginal utility?

Code to be written in python:
Correct answer will be automatically awarded the brainliest!

Since you now have a good understanding of the new situation, write a new num_of_paths function to get the number of ways out. The function should take in a map of maze that Yee Sian sent to you and return the result as an integer. The map is a tuple of n tuples, each with m values. The values inside the tuple are either 0 or 1. So maze[i][j] will tell you what's in cell (i, j) and 0 stands for a bomb in that cell.
For example, this is the maze we saw in the previous question:

((1, 1, 1, 1, 1, 1, 1, 1, 0, 1),
(1, 0, 0, 1, 1, 1, 0, 0, 1, 1),
(0, 1, 1, 1, 0, 0, 1, 1, 1, 0),
(1, 1, 0, 1, 1, 1, 1, 0, 1, 1),
(0, 1, 0, 1, 0, 0, 1, 0, 1, 0),
(1, 0, 1, 1, 1, 1, 0, 1, 1, 1),
(0, 1, 1, 1, 1, 1, 1, 1, 1, 0),
(1, 0, 1, 0, 0, 1, 1, 0, 1, 1),
(1, 0, 1, 1, 1, 0, 1, 0, 1, 0),
(1, 1, 0, 1, 0, 1, 0, 1, 1, 1))
Note: You should be using dynamic programming to pass time limitation test.

Hint: You might find the following algorithm useful:

Initialize an empty table (dictionary), get the number of rows n and number of columns m.
Fill in the first row. For j in range m:
2.1 If maze[0][j] is safe, set table[(0, j)] to be 1 because there's one way to go there.
2.2 If maze[0][j] has a bomb, set table[(0, k)] where k >= j to be 0. Since one cell is broken along the way, all following cells (in the first row) cannot be reached.
Fill in the first column. For i in range n:
3.1 If maze[i][0] is safe, set table[(i, 0)] to be 1 because there's one way to go there.
3.2 If maze[i][0] has a bomb, set table[(i, 0)] and all cells under it to be 0. The reason is same as for the first row.

Main dynamic programming procedure - fill in the rest of the table.
If maze[i][j] has a bomb, set table[(i, j)] = 0.
Otherwise, table[(i, j)] = table[(i - 1, j)] + table[(i, j - 1)]
Return table[(n - 1, m - 1)]

Incomplete code:

def num_of_paths(maze):
# your code here

# Do NOT modify
maze1 = ((1, 1, 1, 1, 1, 1, 1, 1, 0, 1),
(1, 0, 0, 1, 1, 1, 0, 0, 1, 1),
(0, 1, 1, 1, 0, 0, 1, 1, 1, 0),
(1, 1, 0, 1, 1, 1, 1, 0, 1, 1),
(0, 1, 0, 1, 0, 0, 1, 0, 1, 0),
(1, 0, 1, 1, 1, 1, 0, 1, 1, 1),
(1, 1, 0, 1, 0, 1, 0, 0, 1, 1),
(0, 1, 1, 1, 1, 1, 1, 1, 1, 0),
(1, 0, 1, 0, 0, 1, 1, 0, 1, 1),
(1, 0, 1, 1, 1, 0, 1, 0, 1, 0),
(1, 1, 0, 1, 0, 1, 0, 1, 1, 1))


maze2 = ((1, 1, 1, 1, 1, 1, 1, 1, 1),
(1, 1, 1, 1, 1, 1, 1, 1, 1),
(1, 1, 1, 1, 1, 1, 1, 1, 1),
(1, 1, 1, 1, 1, 1, 1, 1, 1),
(1, 1, 1, 1, 1, 1, 1, 1, 1),
(1, 1, 1, 1, 1, 1, 1, 1, 1),
(1, 1, 1, 1, 1, 1, 1, 1, 1))

maze3 = ((1, 0, 1, 1),
(1, 0, 1, 1),
(1, 0, 1, 1),
(1, 0, 1, 1),
(1, 0, 1, 0),
(1, 0, 0, 1))

Test Cases:
num_of_paths(maze1) 2
num_of_paths(maze2) 3003
num_of_paths(maze3) 0

np.arange(5,8,1) what output will be produced?

Put the networks below in order according to the geographic distance they cover. Put a one next to the network that covers the largest area, a two next to the one that covers the second largest area, etc.

LAN

WAN

MAN

In what ways does a computer network make setting appointments easier?


A) by providing a common calendar
B) by reassigning workloads to enable attendance
C) by sending out invitations
D) by telephoning those involved
E) by sending electronic reminders

How do networks help protect data?

A) by shutting down at 5:00 p.m. each evening
B) by restricting access to department chairs
C) by scheduling regular backups
D) by preventing access by more than one person at a time

Select the correct answer.
Ergonomic principles suggest minimizing pressure points while working on a computer. What will help to minimize pressure points while doing
sedentary work?
O A. use handles on boxes
O B.
take regular breaks
O C.
use cushioning while sitting
arrange your work area
O
D.
Reset
Next

Directions :: Write a Ship class. Ship will have x, y, and speed properties. x, y, and speed are integer numbers. You must provide 3 constructors, an equals, and a toString for class Ship.



One constructor must be a default.

One constructor must be an x and y only constructor.

One constructor must be an x, y, and speed constructor.

Provide all accessor and mutator methods needed to complete the class.

Add a increaseSpeed method to make the Ship speed up according to a parameter passed in.

Provide an equals method to determine if 2 Ships are the same(i.e. in the same location).

You also must provide a toString() method.

The toString() should return the x, y, and speed of the Ship.



In order to test your newly created class, you must create another class called ShipRunner. There you will code in the main method and create at least 2 Ship objects (although you can create more if you like), using the constructors you created in the Ship class. Then you will print them out using the toString method and compare them with the equals method.



I'm trying to make an equals method I just don't know how to​

You are given a design board with four input pins a 4-bit INDATA,
1-bit Load,Enable, and Clock; and one output, a 4-bit OUTDATA.
Build a sequential circuit that contains a register (Don’t forget to
trigger that register by the FALLING edge of the clock, Logisim’s default
is the opposite!).
The register is updated every clock cycle in which Enable is up. If
Load is down, the register is incremented, otherwise it is loaded with the
data asserted on the INDATA pin.
The register data output should be connected with the output pin
OUTDATA.

write flow chart pseudocode and algorithm for a computation that perform balance,interest, withdrawal,in bank for Ethiopia?​

Create a program that asks the user to input three integers. After saving the values, the
program should identify the maximum and minimum from the three numbers. The output
should read
The minimum number entered was….
The maximum number entered was….

• Describe the core components and terminology of Group Policy.

Alvin has designed a storyboard using the following technique. Which storyboard technique did he use?

A.
hierarchical
B.
linear
C.
webbed
D.
wheel

50 Points <3

A(n) ____ is a central computer that enables authorized users to access networked resources.

A) peripheral
B) server
C) application
D) LAN

one example of FLAT artwork is tagged image file format which is a common computer what file

what is primary key? List any two advantage of it.​

Demonstrate the Max() functio with example in ms excel

Create a program for the given problems using one-dimensional array. Program to identify the highest value in the given numbers.​

Code to be written in Python:
Correct answer will get the brainliest!

Uyen decides to write a Python program to count towards the next birthday.
In order to do so, she plans to write a function count_days(start_date, end_date) which takes in the start date and end date in the string format, "dd/mm/yyyy", and returns the number of days between the start date and end date. The start date is included while the end date is not included in the count. Note that leading zeros in start_date and end_date are skipped if there are any (For example, the date 1st January 2017 will be in the format 1/1/2017).

Currently, Uyen has only completed a skeleton of count_days, and a few helper functions, which are provided below.

Your Tasks:

(a) Help Uyen complete the four functions marked with 'TODO'. They are get_day_month_year, less_than_equal, next_date and count_days.

(b) Uyen was quite careless, she didn't check for input data validity. You will also need to help her with this. We only proceed to count days if the dates are valid, and the start date is before or same as the end date.

Assume a valid date is between 1/1/1970 and 31/12/9999. The leap year and valid date check are already provided.
If one of the dates is not valid, throw an exception with a message that has the value: "Not a valid date: " + date, where date is the invalid date.
If the start date is after the end date, throw an exception with a message value: "Start date must be less than or equal end date."

Note: is_leap_year(year) and is_valid(d, m, y) are provided, you can make use of them.

Incomplete code:

def is_leap_year(year):
# DONE: do not need to modify
if year % 4 == 0 and year % 100 != 0:
return True
if year % 400 == 0:
return True
return False

def is_valid(d, m, y):
# DONE: do not need to modify
# d, m, y represents day, month, and year in integer.
if y < 1970 or y > 9999:
return False
if m < 1 or m > 12:
return False
if d < 1 or d > 31:
return False

if m == 4 or m == 6 or m == 9 or m == 11:
if d > 30:
return False

if is_leap_year(y):
if m == 2 and d > 29:
return False
else:
if m == 2 and d > 28:
return False

return True

def get_day_month_year(date):
# TODO: split the date and return a tuple of integer (day, month, year)
d = 1
m = 1
y = 1970
return (d, m, y)

def less_than_equal(start_day, start_mon, start_year, \
end_day, end_mon, end_year):
# TODO: return true if start date is before or same as end date
return False

def next_date(d, m, y):
# TODO: get the next date from the current date (d, m, y)
# return a tuple of integer (day, month, year).
return (d, m, y)

def count_days(start_date, end_date):
# date is represented as a string in format dd/mm/yyyy
start_day, start_mon, start_year = get_day_month_year(start_date)
end_day, end_mon, end_year = get_day_month_year(end_date)

# TODO: check for data validity here #
# if start date is not valid...
# if end date is not valid...
# if start date > end date...

# lazy - let the computer count from start date to end date
count = 0
while less_than_equal(start_day, start_mon, start_year, end_day, end_mon, end_year):
count = count + 1
start_day, start_mon, start_year = next_date(start_day, start_mon, start_year)

# exclude end date
return count - 1

Test Cases:

test_count_days('1/1/1970', '2/1/1970') 1
test_count_days('1/1/1970', '31/12/1969') Not a valid date: 31/12/1969
test_count_days('1/1/1999', '29/2/1999') Not a valid date: 29/2/1999
test_count_days('14/2/1995', '19/3/2014') 6973
test_count_days('19/3/2014', '19/4/2013') Start date must be less than or equal end date.
get_day_month_year('19/3/2014') (19, 3, 2014)
get_day_month_year('1/1/1999') (1, 1, 1999)
get_day_month_year('12/12/2009') (12, 12, 2009)
less_than_equal(19, 3, 2014, 19, 3, 2014) True
less_than_equal(18, 3, 2014, 19, 3, 2014) True
less_than_equal(20, 3, 2014, 19, 3, 2014) False
less_than_equal(19, 3, 2015, 19, 3, 2014) False
less_than_equal(19, 6, 2014, 19, 3, 2014) False
less_than_equal(18, 12, 2014, 19, 11, 2014) False
less_than_equal(18, 12, 2014, 19, 11, 2015) True
less_than_equal(31, 3, 2018, 29, 4, 2018) True
next_date(1, 1, 2013) (2, 1, 2013)
next_date(28, 2, 2014) (1, 3, 2014)
next_date(28, 2, 2012) (29, 2, 2012)
next_date(29, 2, 2012) (1, 3, 2012)
next_date(30, 4, 2014) (1, 5, 2014)
next_date(31, 5, 2014) (1, 6, 2014)
next_date(31, 12, 2014) (1, 1, 2015)
next_date(30, 5, 2014) (31, 5, 2014)

A sequential circuit has one flip-flop Q, two inputs X and Y, and one output S. The circuit consists of a D flip-flop with S as its output and logic implementing the function D = X ⊕ Y ⊕ S with D as the input to the D flip-flop. Derive the state table and state dia- gram of the sequential circuit.

Rory has asked you for advice on (1) what types of insurance she needs and (2) how she should decide on the coverage levels vs monthly premium costs. Give Rory specific recommendations she can follow to minimize her financial risk but also keep a balanced budget.

Can someone write a code that makes circles change colors. Name it update () function.

Which company has the highest number of operating system versions on the market?

Linux

Microsoft

Apple

IBM

How BFS takes more memory than DFS?

Next, you begin to clean your data. When you check out the column headings in your data frame you notice that the first column is named Company...Maker.if.known. (Note: The period after known is part of the variable name.) For the sake of clarity and consistency, you decide to rename this column Company (without a period at the end).

Assume the first part of your code chunk is:

flavors_df %>%

What code chunk do you add to change the column name?