There is a drag force that opposes a person's motion while they are moving through a fluid, whether it be air or liquid. Range of motion is constrained by the drag force. Drag force is overcome by the suits. The drawback is overheating.
A bodysuit's main function is to give you support and a seamless tuck-in so you may dress comfortably and easily. Bodysuits can be skin-tight or loose, and because of the tension they create from the shoulders to the crotch, they can embrace your curves and serve as the ideal foundation for whichever bottom you choose.
They can be warm and tight or very thin - useful for warmth - or even be very light (say, 60g), cooling underwear. They are typically elastic and stretchy. They can serve as both underwear and outerwear, but a pair of trousers, pants, or a skirt must be worn below.
Benefits include being thin, warm or cooling, extremely snug, occasionally shapewear, suitable for layering, and warm without bulk (you can get a big deal from a 60g torso garment). fitting in.
They interfere with using the restroom and can occasionally make it difficult to distinguish their front from back sides. Typically, the longer portion of the crotch, called the tail, is at the back. The bodysuits without arms, however, can also be worn buttoned up.
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What is Accenture doing for sustainability?
By calculating carbon emissions reduction and sustainability index improvement, the Accenture MyNav Green Cloud Advisor incorporates sustainability when moving client data centers to the cloud.
The availability of computer system resources without the user having to manage them directly is referred to as cloud computing. The network of remote servers located on the internet in this instance aids in the management and storage of the data.
Mynav Green Cloud Advisor is essential since it aids businesses in creating cloud solutions that may be utilized to lower carbon emissions.
As cloud solutions are essential to businesses, Accenture MyNav Green Cloud Advisor integrates sustainability.
reduces the expense of transportationcreates a design that is appropriate and aids the customer in becoming more sustainable.by reconfiguring factories so that carbon emissions may be easily measuredestablishes sustainable guidelines for disposing of outdated technology.by implementing creative business techniques to reduce the cost of transportationby creating new regulations for removing outdated technologies.To learn more about Accenture and sustainability from given link
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A Shuttle astronaut is sent to repair a defective relay in a 600. 00- kg satellite that is traveling in space at 17 00. 0 m/s * a * w * a * y Suppose the astronaut and his Manned Maneuvering Unit ( MMU) have a mass of 400. 00 kg and travel at 17 010. 0 m/s toward the satelliteWhat is the combined velocity when the astronaut grabs hold of the satellite?
A Shuttle astronaut is sent to repair a defective relay in a 600. 00- kg satellite that is traveling in space. The combined velocity when the astronaut grabs hold of the satellite is 17,004.4 m/s.
The combined velocity of the astronaut and the satellite when the astronaut grabs hold of the satellite is the relative velocity between the two objects. The relative velocity can be calculated using the principle of conservation of momentum. The principle states that the total momentum of an isolated system remains constant if no external forces act on it.
The initial momentum of the satellite is
= (600.00 kg) * (17,000.0 m/s)
= 10,200,000 kg*m/s
The initial momentum of the astronaut and the MMU is
= (400.00 kg) * (17,010.0 m/s)
= 6,804,400 kg*m/s
The final momentum of the combined system is
= (600.00 kg + 400.00 kg) * v,
where v is the final velocity of the combined system.
The conservation of momentum equation:
=> initial momentum = final momentum
= 10,200,000 kgm/s + 6,804,400 kgm/s
= (1000 kg) * v
= v
= (10,200,000 + 6,804,400) / 1000
= v
= 17,004.4 m/s
So, the combined velocity of the astronaut and the satellite when the astronaut grabs hold of the satellite is 17,004.4 m/s.
It's important to note that the relative velocity is the same in both directions, this is a vector quantity and direction is important.
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4. A 9.35 kg bowling ball would require what force to accelerate it down an alleyway at
a rate of 3.12m/s²?
The force needed is 29.2 N.
To calculate the force needed to accelerate a 9.35 kg bowling ball at a rate of 3.12 m/s²,
you can use the equation F = ma, where F is the force, m is the mass of the object (in this case, the bowling ball), and a is the acceleration. Putting in the values, you get:
F = (9.35 kg) x (3.12 m/s²)
= 29.2 N
This works out to be approximately 29.2 Newtons of force.
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A 5 kg block is on a frictionless surface. A 15 n force is applied To the the block in a direction parallel to the surface. What is the acceleration of the block?
The acceleration is 3 [tex]m/s^2[/tex] when a block with a mass of 5 kg is pulled with a force of 15 n.
The block will experience a net external force of 15 N due to the frictionless surface it is kept in place on.
The block weighs 5 kg.
F = m × a
There is a net external force (F), mass (m), and acceleration acting on the object in this situation (a).
Using the appropriate values in place of F and m:
15 = 5 × a
15/5 = a
3=a
Taking 5 as a factor, we get 3 = a.
As a result, a 5-kilogram item is drawn over a friction less surface with an acceleration of 15 N is 3 m/s².
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calculate the frequency of the red light emitted by a neon sign with a wavelength of 659.9 nm.
The frequency of the red light emitted by a neon sign with a wavelength of 659.9 nm is 4.5×10^14 Hz.
What is the frequency?The frequency is the number of times a recurring occurrence takes place during a predetermined period. For example, if an event occurs twice in one second, then the frequency is 2 Hz (Hertz).
A recurring event's frequency is the number of times it happens in a predetermined period. For example, a frequency of a wave is the number of wave peaks passing a fixed point in one second.
The frequency is the number of times something occurs in a given period. For example, the frequency of a radio station is the number of times it broadcasts a signal per second.
Given:
Wavelength = 659.9nm
Speed of light = 3×10^8 m/s
Frequency = speed of light / wavelength
Frequency = (3.0 x 10^8 m/s) / (659.9 nm)
Frequency = 4.5 x 10^14 Hz
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At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 3.0 m/s, and an 83-kg person feels a 545-N force pressing against his back. What is the radius of a chamber
When the outer wall moves at a speed of 3.0 m/s, and an 83-kg person feels a 545-N force pressing against his back then the radius of a chamber is 8.5 meters.
The radius of the chamber can be calculated using the equation
F = mv²/r, where F is the force felt by the person, m is the mass of the person, v is the velocity of the chamber and r is the radius of the chamber. In this case, F is 545 N, m is 83 kg, and v is 3.0 m/s.
Plugging in these values, we get
r= mv²/F
r= 83×3²/545
r = 8.5 m.
Therefore, the radius of the chamber is 8.5 m.
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What happens to the magnitude of the torque if the angle increases toward 90?
The magnitude of the torque will increase as the angle between the force and the line of action of the torque approaches 90 degrees.
Torque is a measure of the rotational force acting on an object and is defined as the product of the force and the distance from the axis of rotation to the point where the force is applied. The torque is also proportional to the sine of the angle between the force and the line of action of the torque.
When the angle between the force and the line of action of the torque is 0 degrees, the torque is zero, as the force is acting in the same direction as the line of action of the torque. As the angle increases, the torque increases and reaches its maximum value when the angle is 90 degrees, at this point the sine of the angle is 1, so the torque is at its maximum value.
In practical terms, if you imagine a door knob, when you push or pull the door knob closer to 90 degree angle with the door, it will be harder to open or close the door, than when you push or pull the door knob at a small angle.
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the driver of a 2000 kg car moving at 30 m/s presses on the break pedal. If the braking force is 10000 N, how far does the car travel before stopping
If the braking force is 10000 N, 90 meters is far the car travel before stopping.
What is force ?When an object interacts with another object, it experiences a push or pull known as a force. Every time two objects come into contact, a force is applied to each one of them. Actual forces can only be created by interaction.
What is energy ?The definition of energy is "the ability to do work, which is the capability to apply a force causing the displacement of an object." Despite this vague description, energy simply refers to the power that propels motion.
Given that,
Mass of automobile = 2000 kg
speed = 30 m/s
Braking force = 10000 N
For, The acceleration is
Using newton's formula
Where, f = force
m= mass
a = acceleration
Put the value of F and m into the formula
-10000 = 2000*a
The braking force is visible in the negative sing.
It demonstrates that the force's direction is the inverse of the motion.
a = -10000/2000
a = -5m/s2
For the distance,
Using third equation of motion
[tex]v^{2} - u^{2} = 2as[/tex]
[tex]0- 30^{2} = 2 * (-5) *s[/tex]
s = 90m
Consequently, the automobile went 90 meters before coming to a stop.
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How long would it take for a falling object to reach a final velocity of 147 m/s?
Answer:
15 seconds :)
Explanation:
The question states "The amplitude of a body undergoing simple harmonic motion is doubled. Which of the following is also doubled?
a) maximum speed
b) frequency
c) total energy
d) period
When the amplitude of a body undergoing simple harmonic motion is doubled then the maximum speed is doubled.
Equation of shm is
x(t) = Xo + Acos(wt + f)
Differentiate it with t
v(t) = wA * sin(wt + f)
Then max speed Vmax is wA
So by above relation if we double the amplitude then velocity will be doubled.
If the force acting on the oscillating body is always in the direction opposite to the displacement of the body from the equilibrium or the mean position and its magnitude is proportional to the magnitude of displacement, the body is said to be executing SHM.
If the displacement vs. time curve of the oscillating body is sinusoidal in nature, the body is said to be executing SHM. This is another definition of SHM.
If the potential energy of the oscillating body is proportional to the square of its displacement with reference to the mean position, the body is said to be executing SHM. This is yet another definition of SHM.
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Ms. Estes shows her class a video from when she worked at the space center launching rockets. She asks her students which of the following items in the video were examples of Newton's first law of motion? (1 point)
-- The rocket accelerating rapidly off the launch pad
-- The astronaut being pushed back into his seat as the rocket accelerates
-- The astronaut experiencing zero gravity in orbit
-- The booster rocket falling back into the ocean after the launch
The astronaut being pushed back into his seat as the rocket accelerates - this was the example of Newton's first law of motion.
What is Newton's first law of motion?According to Newton's First Law, a body in uniform motion or at rest will remain in that state up to and unless a net external force acts on it.
When the astronaut worked at the space center launching rockets, no force is worked on him. When the rocket accelerates, according to Newton's first law of motion, the astronaut remains in same motion, that's why, he pushed back into his seat .
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A 200-kg crate is pushed horizontally with a force of 720 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate.
1.54 is the acceleration of the crate. The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.
Acceleration is proportional to the net force.That acceleration is proportional to the net force and inversely proportional to the mass of the object. It can be expressed with the formula: Where, Fn = Net force, m = mass. The m=200 kg crate is pushed horizontally with a force Fa=700 N. The friction force opposes the motion and a horizontal net force appears causing the acceleration.
Forces in the vertical direction?The forces in the vertical direction are in balance since the crate does not accelerate in that direction, thus the weight and the normal force are equal: N = W = mg, The friction force can be calculated by using the coefficient of friction μ: μ*n. Calculating the normal force: N = 200 * 9.8 = 1,960 N. The friction force is f=0.2*1960, f=392. The horizontal net force is 308. Finally, the acceleration is computed: m/s^2
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If an object was traveling horizontally off a cliff at 6 m/s for 3 seconds, how long did it take to
hit the ground?
The time taken by the object to hit the ground is 1.8 seconds.
What do you mean by gravitational force?The attraction that draws two objects together is known as gravitational force, sometimes referred to as gravity. Every mass-containing object pulls on nearby things gravitationally in a sizable way.
The time it takes for an object to hit the ground after being dropped off a cliff can be calculated using the formula:
t = √(2*d/g)
where t is the time, d is the distance fallen, and g is the acceleration due to gravity.
In this case, we don't know the distance fell, but we can use the horizontal velocity and time of travel to find it:
d = v * t
where v is the velocity (6 m/s), and t is time (3 seconds)
d = 6 * 3 = 18 m
Now we can use the distance fallen to calculate the time it takes to hit the ground:
t = √(2*d/g)
g is approximately 9.8 m/s^2
t = √(2*18/9.8) = √ (3.6) = 1.8 seconds
So, it takes 1.8 seconds for the object to hit the ground after traveling horizontally off a cliff at 6 m/s for 3 seconds.
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A car is traveling $$ m/s when the gas pedal is released and the brakes are gradually applied, resulting in an acceleration given by the function $$ m/s^2. What is the distance traveled before the car comes to a stop?
The distance traveled before the car comes to a stop is 66.66 m. It's important to note that the negative sign on acceleration indicates that the car is slowing down.
Calculation-To find the distance traveled before the car comes to a stop, we can use the formula for distance traveled under constant acceleration. The formula is:
Distance = initial velocity * time + (1/2) * acceleration * time^2
The car is traveling at an initial velocity of 20 m/s and the acceleration is given by the function -6.0t, where t is the time in seconds.
We can find the time it takes for the car to come to a stop by setting the final velocity to 0 and solving for t.
0 = 20 + (-6.0)t
t = 20/6
t = 3.333 s
Now that we have the time, we can substitute it back into the distance formula along with the initial velocity and acceleration:
Distance = 20 * 3.333 + (1/2) * -6.0 * (3.333)^2
Distance = 66.66 m
How much further will the automobile go before stopping?The reaction distance for a vehicle traveling at 60 mph on the highway is 312 feet, and the reaction distance for a vehicle traveling at 80 mph is 496 feet. Simply put, at current speeds, doubling the car's speed will result in a three-fold increase in stopping distance.
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Why are dynamic flexibility tests not used as often as static flexibility tests a dynamic flexibility tests involve m?
Dynamic flexibility tests are not used as often as static flexibility tests because dynamic flexibility tests involve movement, while static flexibility tests are stationary.
Dynamic flexibility tests are more difficult to perform and require more coordination, and they can be less reliable than static flexibility tests. Additionally, dynamic flexibility tests require more time and equipment to administer, making them less practical for most fitness assessment settings.
Also, dynamic flexibility tests are more specific and measure the ability to perform a specific movement, rather than measuring the general range of motion of a joint. This makes them more suitable for testing athletes and those who need to measure their ability to perform specific movements.
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A plane flying at the speed of 150. M/s is accelerated uniformly at a rate of 5. 00 m/s^2
a. What is the plane's speed at the end of 10. 0 seconds?
b. What distance has it traveled?
The plane's speed at the end of 10.0 seconds is 200 m/s and the distance it has travelled is 1750 meters.
The initial speed of the plane, u = 150 m/s
Acceleration of the plane, a = 5 m/s²
Time, t = 10 sec
We can find the plane's speed at the end of 10. 0 seconds by the formula
a = (v - u)/ t
⇒5 = (v - 150)/ 10
⇒50 = v - 150
⇒v = 150 + 50
⇒v = 200 m/s
Now, to find the distance it has travelled we will use the kinematic equation
v² = u² + 2as
⇒200² = 150 ² + 2 × 5 × s
⇒40000 = 22500 + 10s
⇒17500 = 10 s
⇒s = 1750 m
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A sound wave generated by a musical note has the characteristics presented in the table. What is the missing value?
Air 346 55 6. 3
Glass 5,640 55 102
Brass 4,700 55 ?
A.
112
B.
100
C.
85
D.
98
The missing value is D. 98
The table provides information about the speed (m/s), frequency (Hz), and wavelength (m) of a sound wave generated by a musical note, in different mediums (air, glass, and brass). The frequency of the sound wave is constant across the three mediums, but the speed and wavelength will vary depending on the medium. Since we know the frequency and wavelength, we can use the formula:
Speed = Frequency x Wavelength
to find the missing value of the speed of the sound wave in brass.
4,700 = 55 x Wavelength
Wavelength = 4,700/55 = 85.818...
So the missing value is 98 (approximately) in the table.
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The hammer throw is a track-and-field event in which a 7.1-kg ball (the ''hammer''), starting from rest, is whirled around in a circle several times and released. It then moves upward on the familiar curving path of projectile motion. In one throw, the hammer is given a speed of 26.0 m/s. For comparison, a .22 caliber bullet has a mass of 2.6 g and, starting from rest, exits the barrel of a gun with a speed of 403 m/s. Determine the work done to launch the motion of both the hammer and the bullet.
The work done to launch the motion of both the hammer and the bullet are 3.1×10³ Joule and 2.2×10² Joules respectively.
As we know,
Work = Kinetic Energy
= (0.5)(mv^2)
For Work in Joules, the mass is in units of Kg, and the velocity is in units of m/s.
KE(hammer) = 1/2mv^2 = 1/2 x 7.3 x (29)^2 = 3.1 x 10^3 J
and KE(bullet) = 1/2mv^2 = 1/2 x 2.6 x 10^-3 x (410)^2 = 2.2 x 10^2 J
To solve this problem, we must assume that energy is conserved. (This isn't stated in the problem, and is not true in general in these real-world examples, however we must assume conservation of energy in order to solve the problem with the information given).
When an object moves while a force is being exerted on it, then work is being done on the object by the force. If an object moves through a displacement d while a constant force F is acting on it, the force does an amount of work equal to W = F · d = F d cos φ where φ is the angle between d and F.
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Which statement best describes how the gravitational attraction between objects is related to their distance from each other: A) The objects always attract each other.
B) The objects repel each other only if they have very different masses.
C) The objects always repel each other.
D) The objects attract each other only if they are moving toward each other.
Correct option is A) The objects always attract each other.
There is always a pull from gravity. It won't repel.
A mass attracts a mass; the amount of the gravitational force is directly proportional to the masses of the two items and inversely proportional to the square of the distance between the two objects. Gravitational force is an attractive force that exists between all objects with mass.
A rise in one quantity causes a fall in the value of the other since the two values are inversely proportionate. In other words, as the separation distance increases, the force of gravity decreases, and as the separation distance decreases, the force of gravity increases.
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How is Pythagorean Theorem used in baseball?
Bill James came up with the Pythagorean Theorem of Baseball, which connects the amount of runs a club has scored and given up to its actual winning %.
Its uses are:The Pythagorean Theorem is the idea that a baseball team's record may be roughly estimated by taking the square of team runs scored and dividing it by the square of team runs scored plus the square of team runs allowed. Bill James, a baseball analyst, made this idea famous.
The Pythagorean Winning % approach uses the relationship between a team's victories and losses and the number of points scored and allowed to calculate the predicted winning percentage. To follow Pythagorean winning percentages for the seasons, consult the team statistics.
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Why momentum is denoted by P?
It's unknown where the term "p" for momentum first appeared. Since m had already been used for "mass," it has been proposed that the p may have been derived from the Latin petere or from "progress".
Why is momentum given the letter p?The letter "I" would cause a misunderstanding between inertia and moment of inertia. The French and Germans selected "p" for momentum because of this.
What does the momentum unit p mean?The formula p = mv can be used to compute momentum, where p stands for momentum, m for mass, and v for velocity. The usage of the letter p to represent momentum has various benefits. First off, it would be unclear to use m for momentum because m stand for mass.
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How is torque calculated using the moment arm?
Torque is calculated using the moment arm is Torque =Lever Arm x Fy (or Force sin( )) Torque = Force (Fm) x Moment Arm.
How is torque moment calculated?Calculating Torque: The formula for torque is =|r| |F|sin = | r | | F | sin, where |r| is the size of the lever arm, |F| is the size of the force vector, and is the angle created between the two vectors.
Is torque equivalent to the moment arm?In mechanics, they have slightly different meanings but the same meaning in physics. The moment is a static force, whereas the torque is a moving force, even though they both have the same unit, N-m. Torque is utilized when there is rotation, whereas moment is used when there isn't.
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The speed of light is approximately $3\times10^5$ kilometers per second. How long does it take sunlight to reach Jupiter
it takes about 26 seconds for speed of light with approximate speed of 3\times10^5 kilometers per second to reach Jupiter.
To calculate the time it takes light to reach Jupiter, we need to know the distance between the Sun and Jupiter. The average distance between the Sun and Jupiter is approximately 778 million kilometers. We can use the formula distance = speed x time to calculate the time it takes for sunlight to reach Jupiter. We know that the speed of light is approximately 3x10^5 kilometers per second and the distance between the Sun and Jupiter is 778 million kilometers.time = distance / speed
time = (77810^6 km) / (310^5 km/s)
time = 26 sec (approximately)
Therefore, it takes about 26 seconds for light to reach Jupiter.
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An electron is projected with an initial speed v0 = 1. 10106m/s into the uniform field between the parallel plates in the figure. Assume that the field between the plates is uniform and directed vertically downward, and that the field outside the plates is zero. The electron enters the field at a point midway between the plates.
(a)If the electron just misses the upper plate as it emerges from the field, find the magnitude of the electric field.
(B) suppose that in the figure, the electron is replaced by a proton with the same initial speed. Would the proton hit one of the plates?
(c) what would be the direction of proton's displacement? upward or downward?
(d) compare the paths traveled by the electron and the proton and explain the differences
The electron feels a force upward as it passes between the charged plates and narrowly avoids striking the top plate. It just misses the to plate by a small amount as it moves higher.
The explanation for the above answer:The proton will accelerate less and miss the plates since it is more massive. We once more utilise the kinematic equation to determine the vertical displacement when it occurs for the plates.
y=1/2at²=1/2eE/mp(1.25×10-8s)
² \s=2.73×10-6m
As stated in (b), the proton won't collide with one of the plates because, despite the fact that the electric force felt by the proton and the electrons is identical, the electric force produces a smaller acceleration than g, making it plausible to disregard gravity.
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1. Calculate the size of the gravitational pull of a sphere of mass 10 kg on a mass 2.0 kg. When their
centres are 200 mm apart. What is the force of the 2.0 kg mass on the 10 kg mass?
Please answer with an explanation if you can!!!
Explanation:
Let a be the sphere of mass 10 kg and b be the sphere of mass 20 kg. According to Newton's universal law of gravitation, the gravitational force of a on b is expressed as:
F
a
b
=
G
m
M
d
2
, where:
G
=
6.67
×
10
−
11
N
m
2
/
k
g
2
is the gravitational constant
m = 2 kg is the mass of a
M = 10 kg is the mass of b
d = 0.2 m is the separation between the two spheres
So:
Fab=GmMd26.67
×
10
−
11
×
2
×
10
0.2
2
a telescope searching for newly formed stars would make the most discoveries if it were pointed
Yes, the center of the Milky Way is the most densely populated area of stars, and is therefore the most likely region to find newly formed stars.
What is the populated?
Populated refers to an area that has a large number of people residing in it. It is usually used to describe cities, towns, or other densely populated areas. Populated areas usually contain a variety of services and infrastructure to support their populations, such as schools, hospitals, transport links, and other amenities. Populated areas usually have higher rates of crime, pollution, and other problems associated with increased human activity.Populated refers to an area that has a high density of people living in it. It is usually used to describe cities and towns, but can also describe smaller areas, like neighborhoods.
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How can we determine the change in internal energy of a system?
The greater the mass of an object, the more particles there are in the sample and the more thermal energy it possesses at the same temperature. Assume you have some boiling hot water at 100 degrees Celsius to demonstrate this concept.
The energy contained inside a thermodynamic system is quantified as the quantity of energy required to get the system from its standard internal state to its current internal state of interest, accounting for energy gains and losses owing to changes in its internal state, including magnetization.
It eliminates the kinetic energy of motion and the potential energy of the system's overall location in relation to its surroundings and external force fields.
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What does an increases in concentration do to a material?
Answer:
it will increase the frequency of collisions between the two reactants
Explanation:
mark brainliest?
Suppose you have a set of spheres of various sizes. The formula below shows a possible relationship between the surface area (S) and volume for the spheres (V).
The formula that shows the relationship between the surface area (S) and volume (V) for spheres is S = 4πr² and V = (4/3)πr³ where r is the radius of the sphere.
This formula shows that the surface area of a sphere is directly proportional to the radius squared, and the volume is directly proportional to the radius cubed. This means that as the radius of a sphere increases, the surface area and volume will increase at a much faster rate. For example, a sphere with a radius of 2 will have four times the surface area and eight times the volume of a sphere with a radius of 1.
The question is incomplete, hence the answer is general.
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A tornado lifts a truck 252 m above the ground. As the storm continues, the tornado throws the truck horizontally. It lands 560 m away from where it was picked up. How fast was the truck traveling horizontally through its flight
A tornado lifts a truck 252 m above the ground. As the storm continues, the tornado throws the truck horizontally. It lands 560 m away from where it was picked up. The truck will travel at -78.1 m/s and its time of flight is 17.44 seconds.
Distance of any body or an object is the total path covered by it in a particular time. We can calculate the distance of any object covered by it using the equations of motion in our question. we can also convert equation of motion in our favor to find our answer in a proper format to find our answer by the proper use of equation of motion. By this information we can formerly consider that a tornado lifts a truck 252 m above the ground. As the storm continues, the tornado throws the truck horizontally. It lands 560 m away from where it was picked up. The truck will travel at -78.1 m/s and its time of flight is 17.44 seconds.
Initial velocity = 0 , initial height = 252
[tex]dy = u\times t + \frac{1}{2} at^{2}[/tex]
[tex]dy = u\times t +0.5 gt^{2}[/tex]
[tex]252 =0+ 4.9t^{2}[/tex]
t = 7.17 seconds
horizontal:
v = [tex]\frac{dx}{t} =560\times7.17=[/tex]=78.103 m/s
To the nearest tenth; 78.1 M/s
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