atomic absorption spectrophotometry is a characterization technique which determines [ select ] , the total dissolved solids (tds) of a sample gives a measure of [ select ] while edta titrations measures [ select ]

The solution in the bag turned dark purple and glucose could be found in the iodine water within the beaker because:

The definition of diffusion is the transfer of individual molecules of a material from a region of higher concentration to a region of lower concentration over a semipermeable barrier.

The iodine experiments show the process of diffusion.

Therefore, the correct options are a, b, d, and e.

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The molar masses of the compounds are;

a)  342 g/mol

b)  149 g/mol

c)  60 g/mol

Molar mass is the mass of one mole of a substance, usually expressed in grams per mole (g/mol). It is calculated by adding up the atomic masses of all the atoms in a molecule, or the formula weight of a compound. The molar mass is an important concept in chemistry, as it allows scientists to calculate the amount of a substance present in a sample based on its mass or vice versa.

We can calculate the molar masses as follows;

a) 2(27) + 3(32 + 4(16))

= 342 g/mol

b) 3(14 + 4(1)) + 31 + 4(16)

= 149 g/mol

c) 2(12) + 4(1) + 2(16)

= 24 + 4 + 32

= 60 g/mol

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Calcium chloride is a common drying agent used to remove water from organic solvents. It works by absorbing water molecules through a process called hydration. The equation that represents how calcium chloride works to remove water from an organic solvent is:

What is hydration?

Hydration refers to the process by which water molecules combine with other molecules or ions to form a hydrated compound. In this process, one or more water molecules bond to a solute through hydrogen bonding or other intermolecular interactions. This often results in the formation of a solid compound that contains a specific number of water molecules per unit of solute.

CaCl2(s) + H2O(l) → CaCl2•2H2O(s)

This equation shows the reaction between solid calcium chloride (CaCl2) and liquid water (H2O) to form hydrated calcium chloride (CaCl2•2H2O), which is a solid compound that can absorb water molecules from the organic solvent. The hydration reaction is exothermic, which means that heat is released during the process.

This reaction is used to remove water from organic solvents by adding anhydrous calcium chloride to the solvent and stirring the mixture until the calcium chloride has absorbed all the water. The resulting mixture can then be filtered to remove the solid calcium chloride, leaving the dry organic solvent.

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The correct answer is A) NH4+. When a strong base is added to a solution containing NH4+, it reacts with water to produce ammonia gas (NH3) and hydroxide ions (OH-), according to the following equation:

NH4+ + OH- → NH3 + H2O

The ammonia gas produced is responsible for turning the moist red litmus blue, indicating the presence of a base. This reaction is commonly referred to as the ammonium ion hydrolysis reaction.

In contrast, adding a strong base to a solution containing CO32- or Cl- ions will not produce a gas that can cause the litmus paper to turn blue. The carbonate ion (CO32-) would react with a strong acid to release carbon dioxide gas, but it will not release gas upon addition of a strong base. Similarly, the chloride ion (Cl-) is a spectator ion and does not participate in the reaction with the base.

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The model of methane represents a molecule (option D).

Molecule in chemistry is the smallest particle of a specific element or compound that retains the chemical properties of that element or compound.

A molecule is two or more atoms held together by chemical bonds.

According to this question, methane is the simplest aliphatic hydrocarbon made up of one atom of carbon and four atoms of hydrogen.

Methane is a molecule because it is made up of two different atoms.

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Magnesium burns in air with a bright blue flame, leaving behind a solid residue.  The balanced chemical equation for this reaction is

2 Mg + O₂ = 2 MgO

When a magnesium ribbon burns with oxygen present. A brilliant white flame and a white solid residue called magnesium oxide were also visible.

The reaction will be 2 Mg + O₂ = 2 MgO

A metal that is quickly oxidized is magnesium. Magnesium burns as a result of the interaction between oxygen and magnesium. A violet-colored, brilliant light may be produced by the reaction. Most magnesium is used in a solid form, whereas oxygen is a gas.

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The number of atom in  5.18 g Pb is 151 x 10²³ atoms and 2.26 g Hg is  68 x 10²³ atoms

a. 5.18 g Pb:

n = m/M = 5.18 g / 207.2 g/mol = 0.025 moles

N = n x N₀ = 0.025 moles x 6.022 x 10²³ atoms/mol = 151 x 10²³ atoms

b. 2.26 g Hg:

n = m/M = 2.26 g / 200.6 g/mol = 0.0113 moles

N = n x N₀ = 0.0113 moles x 6.022 x 10²³ atoms/mol = 68 x 10²³ atoms

c. 1.87 g Bi:

n = m/M = 1.87 g / 208.9 g/mol = 0.009 moles

N = n x N₀ = 0.009 moles x 6.022 x 10²³ atoms/mol = 54 x 10²³ atoms

d. 0.082 g Sr:

n = m/M = 0.082 g / 87.62 g/mol = 0.000939 moles

N = n x N₀ = 0.000939 moles x 6.022 x 10²³ atoms/mol = 56 x 10² atoms

A particle known as an atom is made up of a nucleus of protons and neutrons surrounded by an electron cloud. The chemical elements are distinguished from one another by the number of protons in their atoms, which is the basic particle of the elements.

There are two kinds of elementary particles that make up an atom: quarks and electrons. The space that surrounds an atom's nucleus is occupied by electrons. The electrical charge of an electron is -1. The nucleus of an atom is made up of protons and neutrons, which are made up of quarks.

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7 half-lives is equivalent to 56 days.

What is Half Life?

Half-life is the time required for half of the atoms in a sample of a radioactive substance to undergo radioactive decay. It is a characteristic property of each radioactive isotope, and can be used to determine the age of materials containing the isotope or to estimate the amount of the isotope remaining in a sample. The concept of half-life is based on the probabilistic nature of radioactive decay, which occurs at random times with a constant probability. The half-life is the time it takes for half of the atoms to decay, but the other half will remain, and each subsequent half-life will reduce the amount of radioactive material by half again.

The given conversion from half-lives to days can be solved using the following steps:

The given quantity is 7 half-lives.

We need to convert this to days.

The conversion factor given is 8 days per 1 half-life.

To convert from half-lives to days, we need to multiply the number of half-lives by the conversion factor.

So, using the given information:

7 half lives x 8 days / 1 half life = 56 days

Therefore, 7 half-lives is equivalent to 56 days.

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The solvent used for recrystallization solvent for this lab exercise is toluene.

Recrystallization is defined as a physical method which is used to purify chemicals based on their different solubility's. This process is completed by heating the material to dissolve the compound with impurities with the a mixture of a suitable solvent.

Generally, toluene is classified as a very good solvent because, unlike water, it can dissolve many organic compounds. In manufacture of many commercial products, toluene is used as a solvent that is present in paint thinners, nail polish remover, glues, and correction fluid.

Hence, the solvent used for recrystallization solvent for this lab exercise is toluene.

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The change in the boiling point of a solution always depends on the solute.

The boiling point is the temperature at which the vapor pressure of a liquid is equal to the external pressure experienced by the liquid. A liquid in a vacuum will have a lower boiling point than if it were under atmospheric pressure.

A solution has a higher boiling point than the pure solvent. This is because the solution must reach a temperature where the boiling pure solvent (eg water 100°C) must also exceed the boiling point of thore solute. So the boiling point of a solution depends on the solute.

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The full electron configuration for this element is: [tex]1s^{2}[/tex][tex]2s^{2} 2p^{3s} 3p^{2}[/tex] ,this corresponds to the element aluminum (Al).

An electronic configuration is a description of how electrons are distributed among the energy levels and sublevels of an atom or ion. It indicates the number of electrons in each sublevel of an atom, starting with the lowest energy level (1s) and moving up in energy through each subsequent level and sublevel.

For example, the electronic configuration of hydrogen is 1s^1, indicating that there is one electron in the 1s sublevel of the first energy level. The electronic configuration of oxygen is 1s^2 2s^2 2p^4, indicating that there are two electrons in the 1s sublevel, two electrons in the 2s sublevel, and four electrons in the 2p sublevel of the second energy level.

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To find the amount of gas in moles, we can use the Ideal Gas Law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for n, we get:

n = PV / RT

Plugging in the given values, we get:

n = (2 atm) * (20 L) / (8.31 J/mol*K * 400 K)

Converting atm to Pa:

n = (2 * 101325 Pa) * (20 L) / (8.31 J/mol*K * 400 K)

Converting liters to cubic meters:

n = (2 * 101325 Pa) * (0.02 m^3) / (8.31 J/mol*K * 400 K)

Solving the equation:

n = 0.077 mol

So there are approximately 0.077 moles of gas in the 20-liter container at a pressure of 2 atm and a temperature of 400 K.

In a balanced equation a molecule is made up of two or more atoms that have been chemically composed.

The term balanced equation is defined as the mass of reactant is exactly similar to the mass of product in chemical reaction.

In a balanced equation two or more than two atoms are combined to produced molecule tha is also called as product. The right side of atoms known as reactant whereas the left side atoms or molecule are known as product.

Thus, Two or more than two atoms joined top formed molecule.

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The concept balanced equation is used here to determine the amount of Tin (II) fluoride produced from 30.00g of hydrogen fluoride. The mass of SnF₂ is 117.5 g.

A chemical equation which obeys the law of conservation of mass in which the mass of the reactants is equal to the mass of the products on either side of the reaction is known as the balanced equation.

The balanced equation for the given reaction is:

Sn + 2HF → SnF₂ + H₂

Here 1 mole of SnF₂ is produced from 2 mole of HF. The molar mass of SnF₂ is 156.71 g and that of HF is 20 g.

30 g HF × 1 mol HF / 20 g HF × 1 mol SnF₂ / 2 mol HF × 156.71 g SnF₂ / 1 mol SnF₂ = 117.5 g SnF₂

Thus the mass of Tin (II) fluoride is 117.5 g .

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When an electrolyte solution (such as NaCl) is added to ice, the ions have strong intermolecular interactions with water molecules and thus decrease  the ability of the water molecules to form a solid ice structure.

This refers to the temperature at which water turns to ice( 0∘C).

The addition of a solute, such as salt (NaCl), to water will lower the freezing point of water. This happens because the salt ions disrupt the regular crystal structure of water molecules, making it more difficult for them to form into a solid. As a result, more energy is required to freeze the solution than pure water, and the freezing point is lowered.

The extent to which the freezing point is lowered depends on the concentration of the salt solution. The change in freezing point (ΔTf) can be calculated using the equation:

ΔTf = Kf * m

Where Kf is the freezing point depression constant for water (1.86 °C/m), and m is the molality of the solution, which is the number of moles of solute per kilogram of solvent.

For example, a 0.1 m solution of NaCl would have a ΔTf of:

ΔTf = 1.86 °C/m * 0.1 mol/kg

      = 0.186 °C

When an electrolyte solution (such as NaCl) is added to ice, the ions have strong intermolecular interactions with water molecules and thus decrease the ability of the water molecules to form a solid ice structure. Therefore, option B is the correct answer.

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Answer: Valence, Atoms

The balance chemical equation is 2H₃PO₄ + 3Mg(OH)₂ → Mg₃(PO₄)₂ + 6H₂O

This is an example of an acid and base neutralizing one another to create salt and water. The reaction is exothermic, emits heat, and can be balanced by adding balancing numbers in front, or molecules, to make sure that the sum of the atom counts for each element on the left and right sides of the equation is the equal.

The law of conservation of matter, which stipulates that matter cannot be generated or destroyed, must be taken into account in order to balance a chemical equation.

H₃PO₄ + Mg(OH)₂ → Mg₃(PO₄)₂ + H₂O

This law states that whatever is available on the reactant side must also be available on the product side.

We must count the atoms on each side of the equation to balance it, and we might also use the number of moles.

The equation is balanced when

2H₃PO₄ + 3Mg(OH)₂ → Mg₃(PO₄)₂ + 6H₂O

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If the hydrate compounds are heated, they lose the water molecules by evaporation from their crystal lattice and they become anhydrous compounds. Thus, copper sulphate penta hydrate will form CuSO₄ solid on heating.

Hydrates are compounds with absorbed water molecules within their crystal lattice. The ability of absorption of moisture from the surrounding and form hydrates is called deliquescence.

Copper sulphate forms its various hydrates such as dihydrates, pentahydrates, hexahydrates etc. The hydrate  Copper Sulfate Pentahydrate,  CuSO₄. 5 H₂O contains 5 water molecules per one formula unit.

When this compound is heated, the water molecules will evaporate from the hydrate and become dry form called anhydrous. Thus, it will form anhydrous  CuSO₄.

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False. According to the statement, the rate of recirculation can be adjusted to control the amount of dissolved oxygen present during the solids-contact clarifying process. Recirculation rate can play a significant role in process control, but it is not the only one.

The rate of recirculation refers to the percentage of a fluid's flow that is redirected back into a system for further processing or reuse, rather than being discharged or wasted. The rate of recirculation can vary depending on the specific system and process involved, but it is often used in industrial settings to improve efficiency and reduce waste. A high rate of recirculation can result in significant cost savings and environmental benefits.

Hence, the answer is False. The statement appears to be about controlling the dissolved oxygen volume in the solids-contact clarification process by controlling the rate of recirculation.

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By dragging each description to the appropriate target area to form the correct sequence of events that occurs when an action potential is generated. when all the descriptions have been placed. Here discussion are done on the basis of sodium-potassium pumps

Mammals have two main kinds of sodium channels: the epithelial sodium channel and the voltage-gated sodium channel (VGSC) family (ESC). Different cell types in the body include voltage-gated sodium channels, although epithelial sodium channels are mostly found in the skin and kidney.

The correct order is as follows:

1) The axon is in its resting state. The interior is negative.

2) Sodium channels open

3) Sodium ions flow into the axon, making the interior positive.

4) Potassium channel open

5) Potassium ions flow out of the axon , making the interior negative

6) Sodium Potassium pumps restore the proper ion ratios.

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The complete question is as follows:

the concentration of glucose inside a cell is 0.1 mM and the cell is suspended in a glucose solution of 0.01 mM: =  [tex]5.93* 10^{-6} KJ[/tex]

Part A:  Glucose concentration inside cell = 0.1 mm - concentration of glucose outside cell= 0.01 mm

Temperature = 2.73 + 37 = 310k

Gibb's free energy

ΔG = RT in {(Glucose)in/(Glucose)out }

= 8.314 J/molk * 310K * ln (0.1/0.001) = 5934.54 J/mol

Energy transported = (5934.54J/mol [tex]* 10^{-6}[/tex] mol)

                                  = (5.93 [tex]* 10^{-6}[/tex] ) KJ

Part B: Glucose concentration in cell = 1 mm

Glucose concentration outside cell = 10 mm

Temperature = 273+37 = 310 K

Gibb's free energy

ΔG = RT ln {(glucose)in (glucose)out}

= 8.314 J/molK [tex]* 310 *[/tex] ln (0.1 mm/ 10.00 mm)

= -5934.54 J/mol

energy transported = (-5934.34.54 J/mol [tex]*[/tex] [tex]10^{-6}[/tex] ) moles

                                 = (-5.934 [tex]* 10^{-6}[/tex] ) KJ

Part C:

ΔG of ArP hydrolysis = -32.2 KJ/mol

The mumber of moles of ATP formedis calculated =

moles of ATP = (-5.934[tex]* 10^{-6}[/tex] KJ/-32.2 KJ/mol )

                       = (1.84 [tex]* 10^{-7}[/tex] ) moles

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The empirical formula for the compound is KClO3.

Percentage yield =72.71%

A limiting agent, also identified as a limiting reactant, is a chemical reactant that restricts the amount of product that can be formed during a chemical reaction. In a chemical reaction, reactants combine to form products in specific proportions based on their mole ratios, as determined by the balanced chemical equation for the reaction. The reactant that is present in the smallest amount, relative to its stoichiometric coefficient in the balanced equation, will be completely consumed in the reaction, leaving excess of the other reactants.

To determine the percent yield, we need to calculate the theoretical yield first.

Finding the limiting reactant:

We need to determine which of the two reactants, potassium chloride or oxygen, is limiting the reaction.

The balanced chemical equation for the reaction would be:

2 KCl + 3 O2 → 2 KClO3

From the equation, we can see that 2 moles of KCl react with 3 moles of O2 to produce 2 moles of KClO3. Therefore, the mole ratio of KCl to O2 is 2:3.

Let's figure out how many moles of each reactant there are:Number of moles of KCl = 9.65 g / 74.55 g/mol = 0.1294 mol

Number of moles of O2 = 4.55 L × (1 mol/22.4 L) = 0.2031 mol

Using the mole ratio, we can see that we need 1.5 times more moles of O2 than KCl.Therefore, oxygen is the limiting reactant.

Finding the theoretical yield:

Since oxygen is the limiting reactant, we can use its moles to calculate the theoretical yield of the product:

Number of moles of KClO3 = 0.2031 mol × (2 mol KClO3/3 mol O2) = 0.1354 mol

Mass of KClO3 = 0.1354 mol × 122.55 g/mol = 16.58 g

Calculating the percent yield:

Percent yield = (actual yield divided by theoretical yield) × 100%

Percent yield = (1205 g / 16.58 g) × 100% = 72.71%

Balanced chemical equation:

2 KCl + 3 O2 → 2 KClO3

Skeletal equation:

KCl + O2 → KClO3

Empirical formula for the product:

Assume 100 g of the compound:

Mass of potassium = 31.01 g

Mass of chlorine = 28.33 g

Mass of oxygen = 39.17 g

Number of moles of each element:

Number of moles of potassium = 31.01 g / 39.10 g/mol = 0.793 mol

Number of moles of chlorine = 28.33 g / 35.45 g/mol = 0.799 mol

Number of moles of oxygen = 39.17 g / 16.00 g/mol = 2.448 mol

Potassium:Chlorine:Oxygen = 0.793/0.793 : 0.799/0.793 : 2.448/0.793

Potassium:Chlorine:Oxygen = 1 : 1.007 : 3.086

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A metal(II) ion concentration of 0.01 mol/L with a molar mass of 58.93 g/mol results in a concentration of the metal(II) ion in units of mg/L (ppm) of 589.3 mg/L (ppm).

One mole of a substance occupies a certain amount of space (designated by the symbol Vm) at a specific temperature and pressure. It is determined by dividing the substance's molecular mass (M) by its density () at the specified temperature and pressure. The SI unit for it is the cubic meter per mole (m3/mol). Cubic meters per mole (m3/mol) is the SI unit for molar volume. The moles per liter of a solution—the measurement of concentration molarity—are referred to as "molars" in this context. The phrase is most frequently used in chemistry to refer to a solute's molar concentration in a solution. Molar concentration is measured in mol/L or M.

Thinking about things from the a molecular perspective is a beneficial quality. All perfect gases will have the same molar volume since they all have the same number density. This will be 22.4 L at STP. This is helpful if you want to visualize the separation of molecules in various samples.

A form's volume is essentially equal to the product of its area and height. Volume = Height x Base Area.

We can use the following formula to change the measurement of the metal(II) ion concentration from mol/L to mg/L (ppm):

concentration in mg/L = (concentration in mol/L) x (molar mass in g/mol) x 1000

The following formula can be used to change the concentration of the metal(II) ion from units of mol/L to mg/L (ppm), assuming the metal(II) ion has a molar mass of 58.93 g/mol:

concentration in mg/L = (concentration in mol/L) x (molar mass in g/mol) x 1000

concentration in mg/L = (concentration in mol/L) x (58.93 g/mol) x 1000

For instance, the concentration in mg/L would be as follows if the metal(II) ion concentration was 0.01 mol/L:

concentration in mg/L = (0.01 mol/L) x (58.93 g/mol) x 1000

concentration in mg/L = 589.3 mg/L or 589.3 ppm

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The answer is Structure 1) very broad, centered about 3330 cm-1.; 2) strong, sharp 1717 cm-1 ; 3) broad with spikes at 3367cm-1 and 3392cm-1.; 4) sharp, 2254cm-1; 5) strong, slightly broadened, 1645cm-1.

The structure with their respective characteristics are:

Structure 1: very broad, centered about 3330 cm-1.

Structure 2: strong, sharp 1717 cm-1.

Structure 3: broad with spikes at 3367cm-1 and 3392cm-1.

Structure 4: sharp, 2254cm-1 .

Structure 5: strong, slightly broadened, 1645cm-1.

OH (hydroxide), a chemical compound made up of a single oxygen atom bonded to a single hydrogen atom. It is usually written OH- in aqueous solutions.

O, [tex]NH_{2}[/tex] and CN are chemical symbols. O is oxygen, NH2 is an amine function and CN is a cyanide function. It is functional group consisting of the nitrogen atom bonded to one or two hydrogen atoms. Cyanide is a functional group consisting of a carbon atom bonded to a nitrogen atom. Both functional groups are very reactive and are also found in many organic compounds.

Full Question:

These five structures all have distinguishing absorption in the IR. Match each structure with its characteristic absorption.

(a) sharp, 2254 cm-1

(b) very broad, centered about 3330cm-1

(c) strong, slightly broadened, 1645cm-1

(d) broad with spikes at 3367cm-1 and 3392cm-1

(e) strong, sharp 1717cm-1

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The statement (laundry detergent is not just soap. there are certain chemicals in detergent that allow greater solvency, more cleaning power, fewer suds, and open up the weave of the fabrics to allow greater chemical penetration) this is true because laundry detergents often contain a number of additional chemicals that boost their cleaning ability and make them more effective than soap alone.

Soap alone is not laundry detergent. While soap and detergent are both surfactants that are used to clean clothes, laundry detergents typically contain more of these chemicals than soap.

Enzymes, builders, bleaches, and other additives are examples of the extra chemicals that can be added to the detergent to help with stain removal, water softening, whitening, and overall effectiveness. Laundry detergents are also designed to produce fewer suds than soap, which can assist to protect washing machines and lower the quantity of water required to rinse the garments.

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The following is the correct Newman projection for the following compound as viewed down the indicated bond. The correct wedge and dash conformation for the following Newman projection is:  IV

A Newman projection is a way of visualizing the conformation of a molecule around a single bond. The projection is created by looking directly down the bond axis, with one atom in front and one atom in back. The front atom is typically represented by a dot, and the back atom is usually hidden behind the front atom.

The 3D structure of organic molecules is depicted using the wedge and dash conformation. It is frequently used in organic chemistry to display how substituents are oriented around chiral centers. The atoms in this conformation are dots, and the bonds in the molecule are represented by lines. Dashes and wedges depict bonds entering and exiting the paper's or screen's plane, respectively.

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The mass of water produced when 9.60 g of butane reacts with excess oxygen is 14.85 gram.

The chemical reaction between substances, usually considering oxygen and usually accompanied by the generation of heat and light in the form of flame is called as combustion reaction.

C4H10(g) + 13 /2 O2(g) → 4CO2(g) + 5H2O(l)

Moles of butane = 9.60⋅g / 58.12⋅g⋅mol−1

= 0.165mol.

We assume complete combustion, and know that each mole of butane gives off 5 mol of water upon combustion.

Given that we know the molar quantity of butane, we simply perform the operation,

= 5 × 0.165 × 18.01

= 14.85 gram

Thus, the mass of water produced when 9.60 g of butane reacts with excess oxygen is 14.85 gram.

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The limiting reactant is N₂O₄ and the mass of N₂ formed from the reaction is 45.7 g (Option C)

The limiting reactant can be obtained as illusrated below:

N₂O₄ + 2N₂H₄ -> 3N₂ + 4H₂O

From the balanced equation above,

92.02 g of N₂O₄ reacted with 64.1 g of N₂H₄

Therefore,

50 g of N₂O₄ will react with = (50 × 64.1) / 92.02 = 34.83 g of N₂H₄

From the above calculation, we can see that only 34.83 g of N₂H₄ out of 45.0 g reacted.

Thus, the limiting reactant is N₂O₄

The limiting reactant shall be used in this case in order to obtain a maximum yield of N₂. Details below:

92.02 g of N₂O₄ reacted to produce 84.06 g of N₂

Therefore,

50 g of N₂O₄ will react to produce = (50 × 84.06) / 92.02 = 45.7 g of N₂

Thus, the mass of N₂ formed is 45.7 g

Therefore, the correct answer to the question is (Option C)

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To calculate the R_f values in the student's experiment, you would need to measure the distance traveled by each solute spot and the distance traveled by the solvent front. Then, you would divide the distance traveled by each solute spot by the distance traveled by the solvent front to get the R_f value for each spot.

The R_f values are the ratio of the distance traveled by the solute to the distance traveled by the solvent. It is calculated by dividing the distance traveled by the solute by the distance traveled by the solvent front.

In chromatography, the R_f value is used to identify compounds by comparing the R_f value of a known compound to the R_f value of an unknown compound.


For example, if a solute spot traveled 4 cm and the solvent front traveled 8 cm, the R_f value for that spot would be 4/8 = 0.5. If another solute spot traveled 6 cm and the solvent front traveled 8 cm, the R_f value for that spot would be 6/8 = 0.75.

By calculating the R_f values for each spot, the student can compare the R_f values to known compounds to identify the components of the mixture.

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