Balance m - 16=35 image attached

Balance M - 16=35 Image Attached

Answers

Answer 1

Answer:

B

Step-by-step explanation:

You're trying to isolate the m so add 16 to both sides to cancel the -16


Related Questions

17.
What is the value of the expression
2a + 5b + 3c for a = 12, b = 6, and
C=3?
A 10
B 21
C49
D 63

Answers

D. 63

2a+5b+3c

2(12)+5(6)+3(3)

24+30+9=63

Hope this helps! :)

Suppose X has an exponential distribution with mean equal to 23. Determine the following:
(a) P(X >10)
(b) P(X >20)
(c) P(X <30)
(d) Find the value of x such that P(X

Answers

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

[tex]f(x) = \mu e^{-\mu x}[/tex]

In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.

The probability that x is lower or equal to a is given by:

[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]

Which has the following solution:

[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]

The probability of finding a value higher than x is:

[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]

Mean equal to 23.

This means that [tex]m = 23, \mu = \frac{1}{23} = 0.0435[/tex]

(a) P(X >10)

[tex]P(X > 10) = e^{-0.0435*10} = 0.6473[/tex]

So

P(X > 10) = 0.6473

(b) P(X >20)

[tex]P(X > 20) = e^{-0.0435*20} = 0.4190[/tex]

So

P(X > 20) = 0.4190

(c) P(X <30)

[tex]P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288[/tex]

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

[tex]P(X > x) = e^{-\mu x}[/tex]

[tex]0.05 = e^{-0.0435x}[/tex]

[tex]\ln{e^{-0.0435x}} = \ln{0.05}[/tex]

[tex]-0.0435x = \ln{0.05}[/tex]

[tex]x = -\frac{\ln{0.05}}{0.0435}[/tex]

[tex]x = 68.87[/tex]

What is the equation, in point-slope form, of the line that
is perpendicular to the given line and passes through the
point (-4,-3)?

Answers

Answer:

The equation of the line is [tex]y + 3 = m(x + 4)[/tex], in which m is found as such [tex]am = -1[/tex], considering a the slope of the given line.

Step-by-step explanation:

Equation of a line:

The equation of a line, in point-slope form, is given by:

[tex]y - y_0 = m(x - x_0)[/tex]

In which m is the slope and the point is [tex](x_0,y_0)[/tex]

Perpendicular lines:

If two lines are perpendicular, the multiplication of their slopes is -1.

Passes through the point (-4,-3)

This means that [tex]x_0 = -4, y_0 = -3[/tex]

So

[tex]y - y_0 = m(x - x_0)[/tex]

[tex]y - (-3) = m(x - (-4))[/tex]

[tex]y + 3 = m(x + 4)[/tex]

The equation of the line is [tex]y + 3 = m(x + 4)[/tex], in which m is found as such [tex]am = -1[/tex], considering a the slope of the given line.

Prove that sinxtanx=1/cosx - cosx
[tex] \sin(x) \tan(x) = \frac{1}{ \cos(x) } - \cos(x) [/tex]

Answers

Answer:

See below

Step-by-step explanation:

We want to prove that

[tex]\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}[/tex]

Taking the RHS, note

[tex]\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}[/tex]

Remember that

[tex]\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)[/tex]

Therefore,

[tex]\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}[/tex]

Once

[tex]\dfrac{\sin(x)}{\cos(x)} = \tan(x)[/tex]

Then,

[tex]\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)[/tex]

Hence, it is proved


Am I correct if not plz fix it ASAP I have 4 minutes left

Answers

Answer:

no not correct it should be horizontally left 2 units and vertically down 5 units

sketch a system of linear equation whose solution is (3,6)​

Answers

Answer: x+y = 9, 2x+3y = 24

Step-by-step explanation:

Find the sum of: 7a² - 9a + 5 and 11a + a² + 8​

Answers

Answer:

Add them:

Squares to squares, a to and number to number:

8a^2+3a+13

The simplified sum of the given expressions 7a² - 9a + 5 and 11a + a² + 8​ is 8a² + 2a + 13.

To find the sum of the expressions 7a² - 9a + 5 and 11a + a² + 8, we simply combine like terms.

The given expressions contain terms with different powers of "a."

Combining the terms with the same powers, we have:

7a² + a² = 8a² (the coefficient for the "a²" term is 7 + 1 = 8)

-9a + 11a = 2a (the coefficient for the "a" term is -9 + 11 = 2)

Finally, we combine the constant terms:

5 + 8 = 13

Putting it all together, the sum of the expressions 7a² - 9a + 5 and 11a + a² + 8 is:

8a² + 2a + 13

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A movie theater sells matinee tickets for $6 each and has a capacity of 100 people. The function M(x) = 6x represents the amount of money the movie theater makes from ticket sales,
where x is the number of customers. What would be the most appropriate domain for the function? (1 point)
Whole numbers less than or equal to 100
Whole numbers that are multiples of 6
All real numbers
All whole numbers

Answers

Answer:

A. Whole numbers less than or equal to 100

Step-by-step explanation:

The domain is the set of x numbers that can be plugged in to a certain equation.

Since the capacity of this movie theater is 100, x can be between 0 and 100, inclusive.

Answer choice A makes sense because whole numbers are definitionally positive integers and this choice caps out at 100.

How many lakhs are there in 4 million?​

Answers

Now,

1 million = 10 lakhs

4 millions = 10 * 4

= 40 lakhs

There are 40 lakhs in 4 millions.

I hope it's help you...

Mark me as brainliest...

Answer: There are 40 lakhs in 4 million.

Step-by-step explanation:

A lakh is 1,00,000. We can divide 4 million by 1,00,000 to get our answer.

[tex]\frac{4,000,000}{1,00,000}[/tex]

The 5 zeros on the 4 million and on 1,00.000 cancel each other out giving us

[tex]\frac{40}{1} \\40[/tex]

The Coast Starlight Amtrak train runs from Seattle to Los Angeles. The mean travel time from one stop to the next on the Coast Starlight is 129 mins, with a standard deviation of 113 minutes. The mean distance traveled from one stop to the next is 108 miles with a standard deviation of 99 miles. The correlation between travel time and distance is 0.636.

Required:
a. Write the equation of the regression line from predicting travel time.
b. Interpret the slope and the intercept in this context.
c. Calculate R2 of the regression line for predicting travel time from distance traveled for the Coast Starlight, and interpret R2 in the context of the application.

Answers

Solution :

a).

Given :

R = 0.636, [tex]$S_x = 99$[/tex], [tex]$S_y=113, M_x=108, M_y=129$[/tex]

Here R = correlation between the two variables

        [tex]$S_x , S_y$[/tex] =  sample standard deviations of the distance and travel time between the two train stops, respectively.

      [tex]$M_x, M_y$[/tex] = means of the distance and travel between two train stops respectively.

The slope of the regression line is given by :

Regression line, [tex]b_1[/tex]  [tex]$=R \times \left(\frac{S_y}{S_x}\right)$[/tex]

                            [tex]$=0.636 \times \left(\frac{113}{99}\right)$[/tex]

                            = 0.726

Therefore, the slope of the regression line [tex]b_1[/tex] is 0.726

The equation of the regression line is given by :

[tex]$\overline {y} = b_0+b_1 \overline x$[/tex]

The regression line also has to pass through the two means. That is, it has to pass through points (108, 129). Substituting these values in the equation of the regression line, we can get the value of the line y-intercept.

The y-intercept of the regression line [tex]$b_0$[/tex] is given by :

[tex]$b_0=M_y-(b_1 \times M_x)$[/tex]

  = 129 - (0.726 x 108)

  = 50.592

Therefore, the equation of the line is :

Travel time = 20.592 + 0.726 x distance

b).[tex]\text{ The slope of the line predicts that it will require 0.726 minutes}[/tex] for each additional mile travelled.

The intercept of the line, [tex]$b_0$[/tex] = 0.529 can be seen as the time when the distance travelled is zero. It does not make much sense in this context because  it seems we have travelled zero  distance in 50.529 minutes, but we could interpret it as that the wait time after which we start travelling and calculating the distance travelled and the additional time required per mile. Or we could view the intercept value as the time it takes to walk to the train station before we board the train. So this is a fixed quantity that will be added to travel time. It all depends on the interpretation.

c). [tex]$R^2=0.404$[/tex]

This means that the model accounts for around 40.4% variation in the travel time.

According to the tables used by insurance companies, a 48-year old man has a 0.169% chance of
passing away during the coming year. An insurance company charges $217 for a life insurance policy
that pays a $100,000 death benefit.
What is the expected value for the person buying the insurance?

Answers

Answer:

The expected value for the person buying the insurance is of -$48.

Step-by-step explanation:

Expected value:

0.169% = 0.00169 probability of earning the death benefit of $100,000, subtracting 217, 100000 - 217 = $99,783.

100 - 0.169 = 99.831% = 0.99831 probability of losing $217.

What is the expected value for the person buying the insurance?

[tex]E = 0.00169*99783 - 0.99831*217 = -48[/tex]

The expected value for the person buying the insurance is of -$48.

What is the area of the irregular polygon shown below?
6
6
4.1
6
6
10
A. 121.5 sq. units
B. 108 sq. units
C. 56 sq. units
O D. 216 sq. units

Answers

The area of the irregular polygon is 121.5 units squared.

How to find the area of an irregular polygon?

The irregular polygon can be divided into a rectangle and a pentagon.

Therefore, the area is the sum of the area of the pentagon and the rectangle.

Therefore,

area of the rectangle = 6 × 10 = 60 units²

area of the pentagon = 1/ 2 × perimeter × apothem

area of the pentagon = 1  /  2 × 30 × 4.1

area of the pentagon = 123 / 2

area of the pentagon = 61.5 units²

Therefore,

area of the irregular polygon = 61.5 + 60  = 121.5 units²

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A right triangle has side lengths 8, 15, and 17 as shown below. Use these lengths to find tanĄ, sind, and cos 4. (GIVING POINTS AND BRAINLEST TO BEST ANSWER)​

Answers

Answer:

Tan A = 8/15

Sin A = 8/17

Cos A = 15/17

I start feeling tired now

Find the perimeter of the figure below, in feet.(Note: diagram is NOT to scale)

Answers

70.2 feet just add it all together

Which relationship is always true for the angles x,y and z of triangle ABC

Answers

Answer:

B. y + z = x

Step-by-step explanation:

x is an exterior angle of the triangle.

y and z are the opposite angles opposite the exterior angle.

The exterior angle theorem of a triangle states that the measure of an exterior angle equals the measure of the sum of the two angles opposite the exterior angle.

Thus:

y + z = x

Choose the correct Set-builder form for the following set written in Roster form: { − 2 , − 1 , 0 , 1 , 2 }

Answers

Step-by-step explanation:

{x:x is an integer where x>-3 and x<3}

A department store, on average, has daily sales of $21,000. The standard deviation of sales is $3600. On Tuesday, the store sold $16,230 worth of goods. Find Tuesday's z score. What is the percentile rank of sales for this day

Answers

Answer:

Tuesday's z-score was of -1.325.

The percentile rank of sales for this day was the 9.25th percentile.

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A department store, on average, has daily sales of $21,000. The standard deviation of sales is $3600.

This means that [tex]\mu = 21000, \sigma = 3600[/tex]

On Tuesday, the store sold $16,230 worth of goods. Find Tuesday's z score.

This is Z when X = 16230. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{16230 - 21000}{3600}[/tex]

[tex]Z = -1.325[/tex]

Tuesday's z-score was of -1.325.

What is the percentile rank of sales for this day

This is the p-value of Z = -1.325.

Looking at the z-table, this is of 0.0925, and thus:

The percentile rank of sales for this day was the 9.25th percentile.

In a regression analysis involving 30 observations, the following estimated regressionequation was obtained.y^ =17.6+3.8x 1 −2.3x 2 +7.6x 3 +2.7x 4​For this estimated regression equation SST = 1805 and SSR = 1760. a. At \alpha =α= .05, test the significance of the relationship among the variables.Suppose variables x 1 and x 4 are dropped from the model and the following estimatedregression equation is obtained.y^ =11.1−3.6x 2​ +8.1x 3For this model SST = 1805 and SSR = 1705.b. Compute SSE(x 1 ,x 2 ,x 3 ,x 4 )c. Compute SSE (x2 ,x3 ) d. Use an F test and a .05 level of significance to determine whether x1 and x4 contribute significantly to the model.

Answers

Answer:

(a) There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]

(b) [tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]

(c) [tex]SSE_{(x_2,x_3)} = 100[/tex]

(d) [tex]x_1[/tex] and [tex]x_4[/tex] are significant

Step-by-step explanation:

Given

[tex]y = 17.6+3.8x_1 - 2.3x_2 +7.6x_3 +2.7x_4[/tex] --- estimated regression equation

[tex]n = 30[/tex]

[tex]p = 4[/tex] --- independent variables i.e. x1 to x4

[tex]SSR = 1760[/tex]

[tex]SST = 1805[/tex]

[tex]\alpha = 0.05[/tex]

Solving (a): Test of significance

We have:

[tex]H_o :[/tex] There is no significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]

[tex]H_a :[/tex] There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]

First, we calculate the t-score using:

[tex]t = \frac{SSR}{p} \div \frac{SST - SSR}{n - p - 1}[/tex]

[tex]t = \frac{1760}{4} \div \frac{1805- 1760}{30 - 4 - 1}[/tex]

[tex]t = 440 \div \frac{45}{25}[/tex]

[tex]t = 440 \div 1.8[/tex]

[tex]t = 244.44[/tex]

Next, we calculate the p value from the t score

Where:

[tex]df = n - p - 1[/tex]

[tex]df = 30 -4 - 1=25[/tex]

The p value when [tex]t = 244.44[/tex] and [tex]df = 25[/tex] is:

[tex]p =0[/tex]

So:

[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]

Solving (b): [tex]SSE(x_1 ,x_2 ,x_3 ,x_4)[/tex]

To calculate SSE, we use:

[tex]SSE = SST - SSR[/tex]

Given that:

[tex]SSR = 1760[/tex] ----------- [tex](x_1 ,x_2 ,x_3 ,x_4)[/tex]

[tex]SST = 1805[/tex]

So:

[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4)} = 1805 - 1760[/tex]

[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]

Solving (c): [tex]SSE(x_2 ,x_3)[/tex]

To calculate SSE, we use:

[tex]SSE = SST - SSR[/tex]

Given that:

[tex]SSR = 1705[/tex] ----------- [tex](x_2 ,x_3)[/tex]

[tex]SST = 1805[/tex]

So:

[tex]SSE_{(x_2,x_3)} = 1805 - 1705[/tex]

[tex]SSE_{(x_2,x_3)} = 100[/tex]

Solving (d): F test of significance

The null and alternate hypothesis are:

We have:

[tex]H_o :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are not significant

[tex]H_a :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are significant

For this model:

[tex]y =11.1 -3.6x_2+8.1x_3[/tex]

[tex]SSE_{(x_2,x_3)} = 100[/tex]

[tex]SST = 1805[/tex]

[tex]SSR_{(x_2 ,x_3)} = 1705[/tex]

[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]

[tex]p_{(x_2,x_3)} = 2[/tex]

[tex]\alpha = 0.05[/tex]

Calculate the t-score

[tex]t = \frac{SSE_{(x_2,x_3)}-SSE_{(x_1,x_2,x_3,x_4)}}{p_{(x_2,x_3)}} \div \frac{SSE_{(x_1,x_2,x_3,x_4)}}{n - p - 1}[/tex]

[tex]t = \frac{100-45}{2} \div \frac{45}{30 - 4 - 1}[/tex]

[tex]t = \frac{55}{2} \div \frac{45}{25}[/tex]

[tex]t = 27.5 \div 1.8[/tex]

[tex]t = 15.28[/tex]

Next, we calculate the p value from the t score

Where:

[tex]df = n - p - 1[/tex]

[tex]df = 30 -4 - 1=25[/tex]

The p value when [tex]t = 15.28[/tex] and [tex]df = 25[/tex] is:

[tex]p =0[/tex]

So:

[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]

Hence, we reject the null hypothesis

a scalene triangle has angles of 53 degree and 69 degree .what is the measure of it third angles?​

Answers

Answer:

x+53+69=180

x+122=180

x=180-122

x=58

In grade 6, there are 40 students. There are 8 girls, find the percentage of the boys?

Answers

40 - 8 = 32
Therefore, there are 32 boys

(32/40)*100 = 80

Therefore, percentage of boys = 80%

Answer:

[tex]40 - 8 = 32 \\ \frac{32}{40} \times 100 \\ = 80\%[/tex]


[tex] {x}^{2} + 2x = 0[/tex]

Answers

Answer:

[tex]\textbf{Hello!}[/tex]

[tex]\Longrightarrow2^2+2z=0[/tex]

[tex]\Longrightarrow x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}[/tex]

[tex]\Longrightarrow \sqrt{2^2-4\cdot \:1\cdot \:0}[/tex]

[tex]\Longrightarrow =\sqrt{2^2-0}[/tex]

[tex]\Longrightarrow =\sqrt{2^2}[/tex]

[tex]\Longrightarrow=2[/tex]

[tex]\Longrightarrow x_{1,\:2}=\frac{-2\pm \:2}{2\cdot \:1}[/tex]

[tex]\Longrightarrow x_1=\frac{-2+2}{2\cdot \:1},\:x_2=\frac{-2-2}{2\cdot \:1}[/tex]

[tex]\Longrightarrow\frac{-2+2}{2\cdot \:1}[/tex]

[tex]\Longrightarrow =\frac{0}{2\cdot \:1}[/tex]

[tex]\Longrightarrow =\frac{0}{2}[/tex]

[tex]=0[/tex]

[tex]\Longrightarrow\frac{-2-2}{2\cdot \:1}[/tex]

[tex]\Longrightarrow =\frac{-4}{2\cdot \:1}[/tex]

[tex]\Longrightarrow =\frac{-4}{2}[/tex]

[tex]\Longrightarrow =-\frac{4}{2}[/tex]

[tex]=-2[/tex]

[tex]x=0,\:x=-2\Longleftarrow[/tex]

[tex]\underline{HOPE ~IT~HELPS}[/tex]

In a geometric sequence, the term an+1 can be smaller than the term ar O A. True O B. False​

Answers

9514 1404 393

Answer:

  True

Step-by-step explanation:

In a geometric sequence, the terms a[n+1] and a[n] are related by the common ratio. If the sequence is otherwise unspecified, two sequential terms may have any a relation you like.* Either could be larger or smaller than the other.

__

* If one is zero, the other must be as well. Multiplying 0 by any finite common ratio will give zero as the next term.

Simplify (5 square root 2 - 1 ) ^2

Answers

Answer:

576

Step-by-step explanation:

5 square root 2 is 25

25 minus 1 is 24

24 square root 2 is 576

Answer:

25

Step-by-step explanation:

[tex](5\sqrt{(2-1)} ^{2}[/tex]

[tex](5\sqrt{1}) ^{2}[/tex]

Lines DE and AB intersect at point C.
What is the value of x?
А.
|(2x + 2)
с
(5x + 3)

Answers

Given:

Lines DE and AB intersect at point C.

To find:

The value of x.

Solution:

In the given figure it is clear that the angles  and  are lie on a straight line AB.

              [Linear pair]

Subtract 5 from both sides.

Divide both sides by 7.

Therefore, the correct option is B.

Help is appreciated

Answers

Answer:

m = 6

n = 2√3

Step-by-step explanation:

Reference angle = 30°

Hypotenuse = 4√3

Opposite = n

Adjacent = m

✔️To find m, apply CAH:

Cos θ = Adj/Hypo

Substitute

Cos 30° = m/4√3

4√3 × Cos 30° = m

4√3 × √3/2 = m (cos 30 = √3/2)

(4*3)/2 = m

6 = m

m = 6

✔️To find n, apply SOH:

Sin θ = Opp/Hypo

Substitute

Sin 30° = n/4√3

4√3 × Sin 30° = n

4√3 × ½ = n (Sin 30 = ½)

2√3 = n

n = 2√3

HELP ASAP WILL GIVE BRAINLIST

Consider the sequence {5,10,15,20,…}. Find n if an = 4875. Show all steps including the formulas used to calculate your answer.

Answers

Answer:

n = 975

Step-by-step explanation:

[tex]a_1 = 5 = 5 \times 1\\a_2 = 10 = 5 \times 2\\\\Therefore, \ a_n = 5 \times n\\[/tex]

[tex]Given \ a_n = 4875\\\\So, a_n = 5 \times n \\\\=> 4875 = 5 \times n\\\\=>\frac{4875}{5} = n\\\\=> 975 = n[/tex]

Given:
p: 2x = 16
q: 3x – 4 = 20
RE
Which is the converse of p - q?
ООО
If 2x + 16, then 3x - 47 20.
If 3x - 420, then 2x + 16.
If 2x = 16, then 3x – 4 = 20.
If 3x - 4 = 20, then 2x = 16

Answers

Given:

The given statements are:

[tex]p:2x=16[/tex]

[tex]q:3x-4=20[/tex]

To find:

The converse of [tex]p\to q[/tex].

Solution:

The statement [tex]p\to q[/tex] means if p, then q and the converse of this statement is [tex]q\to p[/tex].

[tex]q\to p[/tex] means if q , then p.

We have, [tex]p:2x=16[/tex] and [tex]q:3x-4=20[/tex].

So, the converse of given statement is:

[tex]q\to p:[/tex] If [tex]3x-4=20[/tex], then [tex]2x=16[/tex].

Therefore, the correct option is D.

Answer: Therefore, the correct option is D.

Step-by-step explanation:

Given:

p: 2x = 16

q: 3x – 4 = 20

RE

Which is the converse of p - q?

ООО

If 2x + 16, then 3x - 47 20.

If 3x - 420, then 2x + 16.

If 2x = 16, then 3x – 4 = 20.

If 3x - 4 = 20, then 2x = 16

To find:

The converse of .

Solution:

The statement  means if p, then q and the converse of this statement is .

means if q , then p.

We have,  and .

So, the converse of given statement is:

If , then .

Therefore, the correct option is D.

use the rules of exponents to evaluate or simplify.write without negative exponents. 1/4^-2=?

Answers

9514 1404 393

Answer:

  4² = 16

Step-by-step explanation:

The applicable rule of exponents is ...

  1/a^-b = a^b

So, ...

 [tex]\dfrac{1}{4^{-2}}=\boxed{4^2 = 16}[/tex]

_____

Additional comment

If you were to evaluate this using the Order of Operations, you would evaluate the exponent first:

  1/4^-2 = 1/(1/16)

Then, you would do the division.

 1/(1/16) = 16

__

We sometimes find it convenient to manipulate exponential terms to the form with the smallest positive exponents before we begin the evaluation.

Find the length of the missing side. Leave your answer in simplest radical form.
Hyp = 15yd
Leg = 13yd
Leg = X

Answers

Answer:

The other side is 7.48 yards.

Step-by-step explanation:

Given that,

Hypotenuse = 15 yards

One leg = 13 yards

We need to find the length of the other leg. We can use the Pythagoras theorem to find it such that,

[tex]H^2=b^2+h^2[/tex]

Where

h is other leg

Put all the values,

[tex]h=\sqrt{H^2-b^2} \\\\h=\sqrt{(15)^2-(13)^2} \\\\h=7.48\ yd[/tex]

So, the other side is 7.48 yards.

Find the area of the circle. Leave your answer in terms of T.

Answers

Answer:

4.2025 [tex]\pi m^{2}[/tex]

Step-by-step explanation:

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