Bodytemperatures ofhealthy koalasarenormally distributed with a mean of 35.6°C and a standard deviation of 1.3°C. a.What is the probability that a health koalahas a body temperature lessthan 35.0°C? (1pt)b.Veterinarians at a nature preserve in Australiathought a population of koalas might be infected with a virus, so they chose a random sample of n=30koalas and measured their body temperatures. If they got a sample mean body temperature less than 35.0°C, do you think that this population of koalas is healthy? Why/why not?Be specific.(4pt)c.List a potential confounding variable for this study and briefly how it might have impactedthe results. (2pt)2.

Answers

Answer 1

Answer:

a

 [tex]P(X  < 35) =  32.3 \%[/tex]

b

[tex]P(\= X  < 35) =  0.6 \%[/tex]

Here the probability of koalas mean temperature being less than 35 °C is very small hence the koalas are not healthy

c

A potential confounding variable for this study is  the population of the koalas because in the first question the population was not taken into account and the probability was  [tex]P(X  < 35) =  32.3 \%[/tex] but when the population was taken into account (i.e  n =  30) the probability became

[tex]P(\= X  < 35) =  0.6 \%[/tex]  

Step-by-step explanation:

From the question we are told that

  The mean is  [tex]\mu =  35.6^oC[/tex]

   The standard deviation is  [tex]s =  1.3^oC[/tex]

   The sample size is  n = 30

Generally the  probability that a health koala has a body temperature less than 35.0°C is mathematically represented as

     [tex]P(X  < 35) =  P(\frac{X  - \mu }{s}  < \frac{35 - 35.6}{1.3} )[/tex]

Here  [tex](\frac{X  - \mu }{s} =  Z (The   \ standardized \  value \  of  \  X )[/tex]

So

    [tex]P(X  < 35) =  P(Z < -0.46)[/tex]

From the z-table  P(Z <  -0.46) =  0.323

So  

    [tex]P(X  < 35) =  0.323 [/tex]

Converting to percentage

      [tex]P(X  < 35) =  0.323  * 100 [/tex]

      [tex]P(X  < 35) =  32.3 \%[/tex]

considering question b

The sample mean is  [tex]\= x =  35[/tex]

Generally the standard error of the mean is mathematically represented as

   [tex]\sigma_{\= x} =  \frac{s}{\sqrt{n} }[/tex]

=>  [tex]\sigma_{\= x} =  \frac{1.3}{\sqrt{30} }[/tex]

=>  [tex]\sigma_{\= x} =  0.2373 [/tex]

Generally the probability of the mean body temperature of koalas being less than 35.0°C is mathematically represented as

 [tex]P(\= X  < 35) =  P(\frac{\= X  -  \mu  }{\sigma_{\= x }} <  \frac{35 -35.6}{0.2373 }  )[/tex]

[tex]P(\= X  < 35) =  P(Z< -2.53  )[/tex]

From the z-table  we have that

   [tex]P(Z< -2.53  ) =  0.006[/tex]

So

 [tex]P(\= X  < 35) = 0.006 /tex]

Converting to percentage

      [tex]P(\= X  < 35) =   0.006  * 100 [/tex]

      [tex]P(\= X  < 35) =  0.6 \%[/tex]

Here the probability of koalas mean temperature being less than 35 °C is very small hence the koalas are not healthy

A potential confounding variable for this study is  the population of the koalas because in the first question the population was not taken into account and the probability was  [tex]P(X  < 35) =  32.3 \%[/tex] but when the population was taken into account (i.e  n =  30) the probability became

 [tex]P(\= X  < 35) =  0.6 \%[/tex]  


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Answer:

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Answer:

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Step-by-step explanation:

5/4 = 1.25

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Answer:

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Step-by-step explanation:

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33         0.02     0.66          21.78

34          0.06     2.04         69.36

35           0.1      3.5        122.5

36           0.2      7.2         259.2

37           0.24     8.88        328.56

38           0.26     9.88        375.44

39            0.1     3.9         152.1

40            0.02     0.8         32

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We are supposed to find mean and standard deviation

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

3,840 cubic feet

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Answer:

5.4%

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I love u.
U matter.
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hang in there ik it may be bad but u deserve the world <3
ur beautiful no matter ur shape, size, color, gender.. anything
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Ive seen lots of these and just saw this one too but this actually really does help so thankyou for passing it on ily too<3

Step-by-step explanation:

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Answer:

20000

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100 / 5      =     20

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Answer:

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Step-by-step explanation:

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Answers

Answer:

This inequality is impossible. Assuming this is realistic, Linda cannot sell part of a box of cookies and therefore cannot make less than $220.

Step-by-step explanation:

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Casey has 48 red peppers and 16 yellow peppers.

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Answers

Answer:

Casey should use 16 baskets and put 4 red peppers 1 yellow pepper into each one of them.

Step-by-step explanation:

Greatest Common Divisor (GCD)

The GCD of x and y is the maximum possible number that evenly divides both of them.

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Casey should use 16 baskets and put 4 red peppers 1 yellow pepper into each one of them.


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Answers

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Step-by-step explanation: 4x6=28

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According to a study done by a university​ student, the probability a randomly selected individual will not cover his or her mouth when sneezing is . Suppose you sit on a bench in a mall and observe​ people's habits as they sneeze. ​(a) What is the probability that among randomly observed individuals exactly do not cover their mouth when​ sneezing? ​(b) What is the probability that among randomly observed individuals fewer than do not cover their mouth when​ sneezing? ​(c) Would you be surprised​ if, after observing ​individuals, fewer than half covered their mouth when​ sneezing? Why? ​(a) The probability that exactly individuals do not cover their mouth is nothing. ​(Round to four decimal places as​ needed.) ​(b) The probability that fewer than individuals do not cover their mouth is nothing. ​(Round to four decimal places as​ needed.) ​(​c) Fewer than half of individuals covering their mouth ▼ would would not be surprising because the probability of observing fewer than half covering their mouth when sneezing is nothing​, which ▼ is is not an unusual event. ​(Round to four decimal places as​ needed.)

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 [tex]P(X = 8) =  0.0037[/tex]

b

 [tex]P(X <  5) =  0.805[/tex]

c

 [tex]P(X > 6) =  0.0206[/tex]

I would be surprised because the value is very small , less the 0.05

Step-by-step explanation:

From the question we are told that

The probability a randomly selected individual will not cover his or her mouth when sneezing is [tex]p = 0.267[/tex]

Generally data collected from this study follows  binomial  distribution because the number of trials is  finite , there are only two outcomes, (covering  , and  not covering mouth when sneezing ) , the trial are independent

Hence for a randomly selected variable  X we have that  

   [tex]X \ \ \~ \ \ { B ( p , n )}[/tex]

The probability distribution function for binomial  distribution is  

    [tex]P(X = x ) =  ^nC_x *  p^x *  (1 -p) ^{n-x}[/tex]

Considering question a

Generally the  the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when​ sneezing is mathematically represented as

     [tex]P(X = 8) =  ^{12} C_8 *  (0.267)^8 *  (1- 0.267)^{12-8}[/tex]

Here C denotes  combination

So

     [tex]P(X = 8) =  495  *  0.000025828 * 0.28867947[/tex]

    [tex]P(X = 8) =  0.0037[/tex]

Considering question b

Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when​ sneezing is mathematically represented as

     [tex]P(X <  5 ) =[P(X = 0 ) + \cdots + P(X = 4)][/tex]

=>   [tex]P(X <  5 ) =[ ^{12} C_0 *  (0.267)^0 *  (1- 0.267)^{12-0} + \cdots +  ^{12} C_4 *  (0.267)^4 *  (1- 0.267)^{12-4} ][/tex]

=> [tex]P(X <  5 )  =  0.02406 +  0.10516 + 0.21067 + 0.25580 + 0.20964[/tex]

=>  [tex]P(X <  5) =  0.805[/tex]

Considering question c

Generally the probability that fewer than half(6) covered their mouth when​ sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

      [tex]P(X > 6) =  1 - p(X \le  6)[/tex]

=>    [tex]P(X > 6) = 1 - [P(X = 0) + \cdots + P(X =6)][/tex]

=>    [tex] P(X > 6)=1 - [^{12} C_0 *  (0.267)^0 *  (1- 0.267)^{12-0}+ \cdots + ^{12} C_4 *  (0.267)^6 *  (1- 0.267)^{12-6} ][/tex]

=>    [tex] P(X > 6)= 1 - [0.02406 + \cdots + 0.0519 ][/tex]  

=>    [tex]P(X > 6) =  0.0206[/tex]

I would be surprised because the value is very small , less the 0.05

(a )randomly observed individuals exactly do not cover their mouth when​ sneezing

[tex]P[x=8]=0.0037[/tex]

(b) randomly observed individuals fewer than do not cover their mouth when​ sneezing

[tex]P[x < 5]=0.805[/tex]

(c)  fewer than half covered their mouth when​ sneezing

[tex]P(x > 6)=0.0206[/tex]

What will be the probability?

It is given in the question that

The probability a randomly selected individual will not cover his or her mouth when sneezing is

[tex]P=0.267[/tex]

Generally, data collected from this study follows  binomial  distribution because the number of trials is  finite, there are only two outcomes, (covering, and  not covering mouth when sneezing ), the trial is independent

The probability distribution function for binomial  distribution is  

[tex]P(x=8)=n C_X\times p^x\times (1-p)^{n-x}[/tex]

Generally, the probability that among 12 randomly observed individuals exactly 8 does not cover their mouth when​ sneezing is mathematically represented as

[tex]P(x=8)=12c_8\times (0.267)^8\times (1-0.267)^{12-8}[/tex]  

[tex]p(x=8)=495\times 0.000025828\times 0.2886794[/tex]

[tex]p(x=8)=0.0037[/tex]

Generally, the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when​ sneezing is mathematically represented as

[tex]p(x < 5)=[p(x=0)+......+p9x=4)][/tex]

[tex]p(x < 5)=[12c_0\times(0.267)^0\times(1-0.267)^{12-0}+........+12c_4\times(0.267)^4\times (1-0.267)^{12-4}[/tex]

[tex]p(x < 5)=0.02406+0.10516+0.21067+0.25580+0.20964[/tex]

[tex]p(x < 5)=0.805[/tex]

Generally the probability that fewer than half(6) covered their mouth when​ sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

[tex]p(x > 6)=1-p(x\leq 6)[/tex]

[tex]p(x > 6)=1-[p(x=6)+......+p(x=6)][/tex]

[tex]p(x > 6)=1-[12c_0(0.267)^0\times(1-0.267)^{12-0}+....+12c_4\times(0.267)^6\times(1-0.267)[/tex]

[tex]p(x > 6)=1-[0.02406+.....+0.0519][/tex]

[tex]p(x > 6)=0.0206[/tex]

Thus

(a )randomly observed individuals exactly do not cover their mouth when​ sneezing

[tex]P[x=8]=0.0037[/tex]

(b) randomly observed individuals fewer than do not cover their mouth when​ sneezing

[tex]P[x < 5]=0.805[/tex]

(c)  fewer than half covered their mouth when​ sneezing

[tex]P(x > 6)=0.0206[/tex]

To know more about probability follow

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Step-by-step explanation:

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Answer

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Step-by-step explanation:

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