whats 3squared correct to 5 decimal places​

The population would be set of all Christians of that particular church from where the random samples is collected.

According to the questions,

A study was performed with a random sample 3000 people from one church. In order to find appropriate population for generalizing conclusions

The population would be set of all Christians of that particular church from where the random samples is collected.

Hence, the population would be set of all Christians of that particular church from where the random samples is collected.

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Using a trigonometric identity, the cosine of the angle is given as follows:

[tex]\cos{\theta} = \frac{60}{61}[/tex]

It is given by:

[tex]\sin^2{\theta} + \cos^2{\theta} = 1[/tex]

In this problem, the sine is:

[tex]\sin{\theta} = \frac{11}{61}[/tex]

Then:

[tex]\cos^2{\theta} = 1 - \sin^2{\theta}[/tex]

[tex]\cos^2{\theta} = 1 - \left(\frac{11}{61}\right)^2[/tex]

[tex]\cos^2{\theta} = \frac{3600}{3721}[/tex]

[tex]\cos{\theta} = \pm \sqrt{\frac{3600}{3721}}[/tex]

On quadrant I, the cosine is positive, hence:

[tex]\cos{\theta} = \frac{60}{61}[/tex]

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Answer:

48

Step-by-step explanation:

So I attached an image explaining how I solved the problem, but essentially you use the Pythagorean Theorem to define the two other sides, which I named "a" and "b", and then defined them in terms of x, using the Pythagorean Theorem. I finally defined the hypotenuse of the entire triangle which is 36+64 in terms of these two equations. Once that entire thing was set up it was a matter of solving for x, to get 48

Answer:

784 cats      Yikes !

Step-by-step explanation:

d/c = 3/8  

              3/8 = 294/c

                        c = 294 * 8/3 = 784 cats

The greatest Common factor of monomials  [tex]33c[/tex]  and  [tex]27c^4[/tex] is  [tex]3c[/tex]

How we can find the GCF of monomials ?

Monomials are [tex]33c[/tex] and [tex]27c^4[/tex]

We can write the monomials in fraction form

[tex]33c=11*3*c[/tex]

[tex]27c^4=3*9*c*c*c*c[/tex]

----------------------------------

So we can see the common factor is [tex]3c[/tex]

The Greatest Common Factor of [tex]33c ,27c^4[/tex] is [tex]3c[/tex]

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Answer:

0.4 pages per minute

Step-by-step explanation:

40/100 = .4

Answer:

Federal tax

Step-by-step explanation:

It is used for tax returns, given out by federal govt

Answer:

C. federal Tax.

Step-by-step explanation:

/     \

/      \

Answer:

B. 4^15*5^10

Step-by-step explanation:

First you can take the out-out-outside exponent and "pass it out" to both the numerator and the denominator. When you have a power raised to a power, you MULTIPLY the exponents. See image.

Next you can "fix" a negative exponent by pushing it across the fraction bar. As it passes across the fraction bar, the exponent changes sign. So the -10 exponent on the bottom, becomes a positive 10 exponent on top. See image.

Answer:

C

Step-by-step explanation:

using the addition formula for sine

sin(A + B) = sinAcosB + cosAsinB

note that [tex]\frac{7\pi }{12}[/tex] = [tex]\frac{\pi }{3}[/tex] + [tex]\frac{\pi }{4}[/tex] , then

sin [tex]\frac{7\pi }{12}[/tex]

= sin([tex]\frac{\pi }{3}[/tex] + [tex]\frac{\pi }{4}[/tex] )

= sin[tex]\frac{\pi }{3}[/tex]cos[tex]\frac{\pi }{4}[/tex] + cos[tex]\frac{\pi }{3}[/tex]sin[tex]\frac{\pi }{4}[/tex]

= ( [tex]\frac{\sqrt{3} }{2}[/tex] × [tex]\frac{\sqrt{2} }{2}[/tex] ) + ([tex]\frac{1}{2}[/tex] × [tex]\frac{\sqrt{2} }{2}[/tex] )

= [tex]\frac{\sqrt{6} }{4}[/tex] + [tex]\frac{\sqrt{2} }{4}[/tex]

= [tex]\frac{\sqrt{2}+\sqrt{6} }{4}[/tex]

Let the missing number x

So, ATQ

[tex] \frac{3}{14} \times x = 6[/tex]

[tex] \frac{14}{3} \times \frac{3}{14} x = 6 \times \frac{14}{3} [/tex]

[tex] \frac{1}{3} \times 3x = \frac{14}{3} \times 6[/tex]

[tex]x = \frac{14}{3} \times 6[/tex]

[tex]x = 14 \times 2[/tex]

[tex]x = 28[/tex]

Therefore, 3/14 of 28 is 6...

Answer:

28

Step-by-step explanation:

Let the number we are looking for = [tex]x[/tex]

∴ [tex]\frac{3}{14}[/tex] of [tex]x[/tex] is 6

⇒  [tex]\frac{3}{14}[/tex]   ×  [tex]x = 6[/tex]

• Divide both sides of equation by  [tex]\frac{3}{14}[/tex] :

⇒  [tex]x = 6 \div \frac{3}{14}[/tex]

⇒ [tex]x = 28[/tex]

∴ The missing part is 28.

The steps in Mia's method were smaller than in Jenna's, which was an advantage.

The same result will be obtained by adding the products of multiplying the sum of two or more addends by a number as opposed to multiplying each addend separately by the number.

The direct algorithm process suggested in this paper is known as the direct calculation method (DCM), and it can deal with using confinement loss as an incremental step to simulate the effect of moving tunnel face excavation, calculating the stresses and displacements in each step, and drawing the results.

Jenna's technique:

[tex]\begin{aligned}&5(30+4) \\&=(5)(30)+(5)(4) \\&=150+20 \\&=170\end{aligned}[/tex]

Mia's technique:

[tex]\begin{aligned}&5(30+4) \\&=(5)(34) \\&=170\end{aligned}[/tex]

Both used the right approach, albeit in different ways.

One uses the distributive property, whereas the other uses direct calculation.

Consequently, Jenna and Mia came to the same conclusion.

However, Mia's approach has one advantage over Jenna's: it requires fewer steps.

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Answer:

a(b+c) = a into b + a*c

So, 79(457+35) = 79*457 + 79*35

Step-by-step explanation:

Answer:

x=-2, 2

Step-by-step explanation:

Aighty check this out

[tex]f(x) = \frac{ {x}^{2} + 3x + 6 }{ {x}^{2} - 4 } = = = > \\(x + 2)(x - 2) \\ so \: x = - 2 \: and \: x = 2 \: are \: not \: defined \: \\ and \: are \: the \: candidates [/tex]

if non of the root give out 0/0 both can be the asymptotes:

[tex]f(2) = \frac{{2}^{2} + 3(2) + 6 }{ { - 2}^{2} + 4 } = = = > \\ f(2) = \frac{16}{0} [/tex]

this one is OK

[tex]f( - 2) = \frac{ { - 2}^{2} + 3( - 2) + 6}{ { - 2}^{2} + 4 } = = = > \\ f( - 2) = \frac{4}{0} [/tex]

so is this one

so the asymptotes are x=-2, 2

Answer:

y =2

Step-by-step explanation:

Substitute -10 for x:

2(-10)-9y = -38

-20-9y = -38

-9y = -18

9y = 18

y = 2

The value of sample size n in this statement according to a confidence interval is 350.

According to the statement

we have a given that the value of error and population proportion and we have to find the value of sample size.

So, we know that the

confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Here

p represent the real population proportion of interest

ρ represent the estimated proportion for the sample

n is the sample size required (variable of interest)

z represent the critical value for the margin of error

So, The population proportion have the following distribution  

P≈n ( p, ([p (1-p)]/n)^1/2)

Here In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by  α = 1 - 0.95 = 0.05

and α/2 = 0.025 And the critical value would be given by:  

z = 1.96

And on this case we have that ME = ±0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got the value

n = 0.35(1-0.35) / (0.05/1.96)^2

so, the value becomes

n = 350.

So, The value of sample size n in this statement is 350.

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Disclaimer: This question was incomplete. Please find the full content below.

Question:

In a survey, the planning value for the population proportion is p* = 0.35. How large a sample should be taken to provide a 95% confidence interval with a margin of error of 0.05?

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Pedro can sell enough by combining the sales of 40 plates of garlic shrimp and 80 dishes of spicy shrimp to reach his objective.

Near the shore, Pedro runs a shrimp delivery business.

He offers spicy shrimp for $6 a plate and garlic shrimp for $8 per plate.

Pedro wants to make at least $800 per day but only stocks enough shrimp to sell a maximum of 120 plates.

We need to ascertain,

Which dish combining hot shrimp and garlicky shrimp can Pedro sell to reach his objective?

In response to the query,

Let's sell the x dishes of garlic shrimp.

And plates of hot shrimp were sold.

Pedro has 120 dishes' worth of shrimp in stock each day.

Then,

Shrimp sold daily total is equal to the sum of plates of garlic shrimp and spicy shrimp.

                           X + Y = 120

Furthermore, He offers $6spicy and $8garlic shrimp, per plate.

To make at least $800 is what he wants to do.

Then,

the sum of the price of the spicy shrimp per plate and the price of the garlic shrimp per plate,

                             8X + 6Y = 800

When the two equations are solved,

                              X + Y = 120

                           8X + 6Y = 800

From equation 1,

                             Y = 120 - X

In equation 2, replace x with its value.

8X + 6Y = 800

8(120 - Y) + 6Y = 800

960 - 8Y + 6Y = 800

- 2Y = - 160

Y = 160/2

Y = 80

In equation 1, replace y with its value.

X + Y = 120

X + 80 = 120

X = 120 - 80

X = 40

In order to achieve his objective, Pedro sold a combination of 40 plates of garlic shrimp and 80 dishes of spicy shrimp.

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Answer:

Step-by-step explanation:

Make equations

8x+6y≥800

x+y≤120

Graph the system of equations and see which answer falls in the shaded area

Answer: 90 Garlic, 25 Spicy

The area of the circle is 78.5 unit square.

A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point.

The line of reflection symmetry is formed by all lines that traverse the circle. Additionally, every angle has rotational symmetry around the centre.

The formula for area of circle is;

Area = [tex]\pi[/tex](radius)²

The distance between the two points are calculated by distance formula.

[tex]\begin{aligned}&d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}} \\&d=\text { distance } \\&\left(x_{1}, y_{1}\right)=\text { coordinates of the first point } \\&\left(x_{2}, y_{2}\right)=\text { coordinates of the second point }\end{aligned}[/tex]

Calculation for the area of the circle;

As, the radius of the circle is xy.

The distance between x and y points will be calculated by the distance formula.

x=(0,3)  y=(-3,-1)

[tex]\begin{aligned}&d=\sqrt{\left(-3-0\right)^{2}+\left(-1-3\right)^{2}} \\\end{aligned}[/tex]

[tex]\begin{aligned}&d=\sqrt{\left(-3\right)^{2}+\left(-4\right)^{2}} \\\end{aligned}[/tex]

[tex]\begin{aligned}&d=\sqrt{25} \\\end{aligned}[/tex]

[tex]d=5[/tex]

As, distance between x and y point is 5 units which is the radius of the circle.

Area of circle = [tex]\pi[/tex](radius)²

                      = 3.14×(5)²

                      = 78.5

Therefore, the area of the circle is 78.5 unit square.

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What number would you multiply the second equation by in order to eliminate the x-terms when adding to the first equation?

It's 2 (to get - 4x & 4x + - 4x = 0)

What number would you multiply the second equation by in order to eliminate the y-terms when adding to the first equation?

It's 3 (to get 9y & - 9y + + 9y =0)

Hope this helps!

Due to length restrictions, we cannot summarize the results of the three parts about the quadratic equations of the form x² + b · x + c = 0. We kindly invite to check the explanation for further details.

In this question we have several exercises with quadratic equations of the form x² + b · x + c = 0 and, to be more exactly, quadratic equations with the following characteristics:

x² - (r₁ + r₂) · x + r₁ · r₂ = 0      (1)

Please notice that the first grade coefficient is equal to the inverse of the sum of the two roots and the zero grade coefficient is the product of the two coefficients.

Now we proceed to resolve all the points:

Part I

a) (x + 17) · (x + 1) = x² + 18 · x + 18, r₁ = - 17, r₂ = - 1

b) (x + 5) · (x + 4) = x² + 9 · x + 20, r₁ = - 5, r₂ = - 4

c) (x - 11) · (x - 1) = x² - 12 · x + 11, r₁ = 11, r₂ = 1

d) (x - 18) · (x - 2) = x² - 20 · x + 36, r₁ = 18, r₂ = 2

Part II

a) x² - 12 · x + 27

b) (x + 4) · (x + 8)

c) (x - 5) · (x - 7)

d) (x - 4) · (x - 5)

Part III

a) (x - 18) · (x + 3) = x² - 15 · x - 54

b) (x + 18) · (x + 3) = x² + 21 · x + 54

c) (x + 18) · (x - 3) = x² + 15 · x - 54

d) (x - 18) · (x - 3) = x² - 21 · x + 54

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Answer:

A) Equation of the line of best fit: y = -5x + 62

B) y = -3

Explanation:

Given points: {(5, 38), (6, 34), (7, 27), (8, 21), (9, 17), (10, 14)}

Plot these points on the graph and draw a straight line between them.

A)

The points (7, 27), (9, 17)

Find slope:

[tex]\sf slope: \dfrac{17-27}{9-7} = -5[/tex]

Equation:

[tex]y - y_1 = m(x - x_1)[/tex]

[tex]\sf y - 27= -5(x - 7)[/tex]

[tex]\sf y = -5x + 35 + 27[/tex]

[tex]\sf y = -5x + 62[/tex]

B) If x = 13, then approximate value of y is

insert x = 13 in equation

y = -5x + 62

y = -5(13) + 62

y = -3

The answers are :

A) y = -5x + 64

B) -1

Part (A) :

Finding the slope : Take the points (6, 34) and (10, 14)

m = Δy/Δx

m = 14 - 34 / 10 - 6

m = -20/4

* m = -5 *

Using point slope formula to find equation :

y - y₁ = m (x - x₁)

y - 34 = -5 (x - 6)

y - 34 = -5x + 30

y = -5x + 64

Part (B) :

Substitute x = 13 in the line of best fit equation

y = -5(13) + 64

y = -65 + 64

y = -1

Answer:

[tex]\huge\boxed{\sf 8:32\ AM}[/tex]

Step-by-step explanation:

Woke up = 7:30 AM

Time to:

Altogether:

= 14 + 9 + 39 min

(As we know that, 1 hour = 60 minutes)

So,

Time he reached the school:

7 hr 30 min + 1 hr 2 min

Combine like terms

7 hr + 1 hr + 30 min + 2 min

OR

[tex]\rule[225]{225}{2}[/tex]

Paul woke up for school at 7:30 AM. He took 14 minutes to get ready, 9 minutes to finish his breakfast and 39 minutes to commute to school. At what time did he reach the school?

In this question we are asked to calculate the time paul reach the school.

Altogether time paul took to get ready, to finish his breakfast and to commute to school.

(14 + 9 + 39) minutes

→ (23 + 39) minutes

→ 62 minutes

Now we will convert minutes into hour.

62 ÷ 60

→ 1 hr 2 min

Now we will calculate the time he reached his school.

7 hr + 30 + 1 hr 2 min

[tex]\begin{array}{cc}7 \sf{hrs} \: & \: 30 \sf{min} \\ \underline{1 \: \sf{hr}} & \underline{2 \sf{min} } \\ \pmb{8 \sf{hrs}}& \pmb{32 \sf{min}}\end{array}[/tex]

He will reach the school at 8:32 AM.

Answer:

127°

Step-by-step explanation:

180°-53°=127°

Angle on a straight line is equal to 180°

Answer:

444

Step-by-step explanation:

There are 9 surfaces to this shape.  You find the area of each shape:

Bottom rectangle (16)(5) =80

Front rectangle (16)(4) = 64

Back rectangle (16)(4) = 64

Right side rectangle (5)(4) = 20

Left side rectangle (5)(4) = 20

Top right rectangle (10)(5) = 50

Top left rectangle (10)(5) = 50

Front top triangle (1/2)(16)(6) = 48

Back top triangle (1/2)(16)(6) = 48

Answer: yes by SSS

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Ava bought [tex]7.73[/tex] pounds of fruit for a class party , class ate [tex]3.59[/tex] pounds fruits then [tex]4.14[/tex] pounds fruit left after party.

How can we find how much fruit is left after party ?

Ava bought [tex]=7.73[/tex] pounds fruit

ate by class [tex]=3.59[/tex] pounds fruit

fruit left after party [tex]= total fruit -fruit ate by class[/tex]

                                [tex]= 7.73-3.59\\=4.14[/tex]

So [tex]4.14[/tex] pound fruit is left .

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Part 1: Correct.

Part 2

[tex]\sqrt{(-52)^2 + 48^2} \approx 70.77[/tex]

Answer:

[tex]y=-\frac{3}{2}x + 6[/tex]

Step-by-step explanation:

For perpendicular lines, we use the same y-intercept. Though, to find the slope of perpendicular lines, we use opposite reciprocals. The opposite reciprocal of [tex]\frac{2}{3}[/tex] is [tex]-\frac{3}{2}[/tex].

The p-value(0.0538) is greater than the given significance level of 0.01. So, there is no sufficient evidence to show that the manufacturer needs to recalibrate the machines.

The test statistics formula for finding the z-score is,

z = (X - μ)/(σ/√n)

Where,

X = sample mean

μ = population mean

σ = population standard deviation

n = sample size

With this z-score, the p-value is calculated. If p > α, then the null hypothesis is not rejected, and if p < α, then the null hypothesis is rejected.

It is given that,

The population mean μ = 4.00

The sample size n = 81

The sample mean X = 3.97

The standard deviation σ = 0.14

and the significance level α = 0.01

So, the hypothesis is:

The null hypothesis: H0: μ = 4

The alternative hypothesis: Ha: μ ≠ 4

Thus, the test statistic value is,

z = (X - μ)/(σ/√n)

  = (3.97 - 4)/(0.14/√81)

  = - 0.03/0.015

  = -1.928

So, for z = -1.928, the p-value is 0.053855

Since p > 0.01, there is no sufficient evidence to show that the manufacturer needs to recalibrate the machines.

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The median number of computers owned by the 17 students is 2.

A dataset's median represents the midpoint; half of the data points are smaller and half are greater than the median.

Identifying the median: The data points should be arranged from smallest to largest. The median is the middle data point in the list if the number of data points is odd.

The total number of students are 17.

The data can be arranged in the following table

number of students        number of computers

             6                                         1

             3                                         2

             3                                         3

             2                                         4

             3                                         5

Arrange the given frequencies in the increasing order-

1 1 1 1 1 1 2 2 2 3 3 3 4 4 5 5 5

The middle term of the arrange frequencies is 17/2 = 8.5

Median = (8 term + 9 term)/2

            = (2 + 2)/2

            = 2

Therefore, the median number of computers owned by the 17 students is 2.

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The correct question is -

Of the 17 students in a programming class, 6 own 1 computer, 3 own 2 computers, 3 own 3 computers, 2 own 4

computers, and 3 own 5 computers. What is the median number of computers owned by the 17 students?