Answer:
Data provide convincing evidence of a difference in SAT scores between students with and without a military scholarship is explained below in details.
Step-by-step explanation:
This is a quiz of 2 autonomous groups. The population model differences are not understood. it is a two-tailed examination. Let w be the index for scores of students with army research and o be the index for scores of students without army research.
Therefore, the population means would be μw and μo.
The irregular variable is x w - xo = variation in the sample mean records of students with military accomplishments and students without.
For students with military accomplishments,
n = 8
Mean = (850 + 925 + 980 + 1080 + 1200 + 1220 + 1240 + 1300)/8
Mean = 1099.375
Standard deviation = √(summation(x - mean)/n
Summation(x - mean) = (850 - 1099.375)^2 + (925 - 1099.375)^2 + (980 - 1099.375)^2 + (1080 - 1099.375)^2 + (1200 - 1099.375)^2 + (1220 - 1099.375)^2 + (1240 - 1099.375)^2 + (1300 -1099.375)^2 = 191921.875
Standard deviation = √(191921.875/8 = 154.89
For students without military scholarship,
n = 12
Mean = (820 + 850 + 980 + 1010 + 1020 + 1080 + 1100 + 1120 + 1120 + 1200 + 1220 + 1330)/12
Mean = 1073.83
Summation(x - mean) = (820 - 1073.83)^2 + (850 - 1073.83)^2 + (980 - 1073.83)^2 + (1010 - 1073.83)^2 + (1020 - 1073.83)^2 + (1080 - 1073.83)^2 + (1100 - 1073.83)^2 + (1120 - 1073.83)^2 + (1120 - 1073.83)^2 + (1200 - 1073.83)^2 + (1220 - 1073.83)^2 + (1330 - 1073.83)^2 = 238199.4268
Standard deviation = √(238199.4268/12 = 140.89
We would set up the hypothesis.
The null hypothesis is
H0 : μw = μo H0 : μw - μo = 0
The alternative hypothesis is
Ha : μw ≠ μo Ha : μw - μo ≠ 0
Since sample standard deviation is recognized, we would analyis the examination statistic by using the t examination. The formula is
(xw - xo)/√(sw²/nw + so²/no)
From the information given,
xw = 1099.375
xo = 1073.83
sw = 154.89
so = 140.89
nw = 8
no = 12
t = (1099.375 - 1073.83)/√(154.89²/8 + 140.89²/12)
t = 0.37
The formula for determining the degree of freedom is
df = [sw²/nw + so²/no]²/(1/nw - 1)(sw²/nw)² + (1/no - 1)(so²/no)²
df = [154.89²/8 + 140.89²/12]²/(1/8 - 1)(154.89²/8)² + (1/12 - 1)(140.89²/12)² = 21650688.37/1533492.15
df = 14
We would get the probability count from the t test calculator. It becomes
p value = 0.72
Since the level of importance of 0.05 < the p value of 0.72, we would not neglect the null hypothesis.
Therefore, these data do not present an acceptable indication of a difference in SAT scores between students with and without a military scholarship.
Part B
The formula for getting the confidence interval for the difference of two population means is expressed as
z = (xw - xo) ± z ×√(sw²/nw + so²/no)
For a 95% confidence interval, the z score is 1.96
xw - xo = 1099.375 - 1073.83 = 25.55
z√(sw²/nw + so²/no) = 1.96 × √(154.89²/8 + 140.89²/12) = 1.96 × √2998.86 + 1654.17)
= 133.7
The confidence interval is
25.55 ± 133.7
Four less than the sum of a number and six is ten.
Someone please help
Answer:
8
Step-by-step explanation:
since u first do six + 8 which is 14. Then u do 14 - 4 which is 10
Plz mark as brainliest
Answer:
x=2
Step-by-step explanation:
x = the number
x + 6 = 6x - 4
Solve for x and get
5x = 10
Write the expression in simpleist form PLZ WILL GIIVE BRAINLIEST
4 + 4x + 6x - 3
1. 29x + 3
2. 75x + 3
3. 22x + 1
4. 10x + 1
Find the solution(s) to the equation sin(x/2) + cos x - 1 = 0 on the interval 0 less than or equal to x 2pie
Answers: A,B, and E
Answer:
A: 0
B: pi/3
E: 5pi/3
Step-by-step explanation:
The solution to the trigonometric equation is 0 , π/3 , 5π/3
What are trigonometric relations?Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles
The six trigonometric functions are sin , cos , tan , cosec , sec and cot
Let the angle be θ , such that
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent
tan θ = sin θ / cos θ
cosec θ = 1/sin θ
sec θ = 1/cos θ
cot θ = 1/tan θ
Given data ,
Let the trigonometric equation be represented as A
sin ( x/2 ) + cos ( x ) - 1 = 0
sin ( x/2 ) - ( 1 - cos ( x ) ) = 0
On further simplification , we get
( 1 - cos ( x ) ) = 2sin² ( x/2 )
So , sin ( x/2 ) - 2sin² ( x/2 ) = 0
Taking sin ( x/2 ) as the common factor , we get
sin ( x/2 ) ( 1 - 2sin ( x/2 ) ) = 0
So , the solutions to the equation are
sin ( x/2 ) = 0
x = 0 , 2π
And , ( 1 - 2sin ( x/2 ) ) = 0
sin ( x/2 ) = 1/2
x = π/3 , 5π/3
Hence , the solutions are x = 0 , π/3 , 5π/3
To learn more about trigonometric relations click :
https://brainly.com/question/14746686
#SPJ2
20 points!! please help im struggling bad with this ):
Answer: Andy completed 7 problems.
Step-by-step explanation:
On a number line, what is the distance between -57 and 13?
A)
-70
B)
-44
9
44
D)
70
Helpppppp
Answer:
-70 so A
Step-by-step explanation:
Answer:
D) 70
Step-by-step explanation:
Here is the correct mathematical way of find a distance between two points on the number line.
Take the absolute value of the difference of their coordinates.
If the points on a number line correspond to coordinates a and b, the distance between the points is
|a - b|
Your problem:
|a - b| = |-57 - 13| = |-70| = 70
The distance is 70.
Answer: D) 70
Find the angle measure D FIRST ANSWER GETS BRAINIEST
Answer:
its 44
Step-by-step explanation:
180=46+90+x
180=136+x
44=x
Developmental norms are used as a benchmark to determine where one should be developmentally. Please select the best answer from the choices provided T F
Answer:
True
Step-by-step explanation:
ed 2020. I went back to check the answer so 100% right.
Answer:
tru
Step-by-step explanation:
Solve x^0 someone help me please
Answer:
x = 1
Step-by-step explanation:
Manuel bought a 3/5 of a pound of clay for the students in his pottery class. He then divided the clay into 6 equal pieces for his students to use for making vases and pots. How much did each piece weigh?
Group of answer choices
Answer:
Each piece weighed 1/10 of a pound.
Step-by-step explanation:
We have 3/5 of a pound and we want to divide it by 6 equal pieces for each student. 6 equal pieces is the same as 6/1.
In order to divide 3/5 by 6/1 we need to invert the 6/1 and multiply. So, it becomes 3/5 x 1/6. First, we multiply the numerators: 3x1=3 then we multiply the denominators: 5x6=30. The result is 3/30, which can be reduced by dividing both the numerator and denominator by 3. 3/3=1 and 30/3=10. So, the result is 1/10.
Solve
[tex] log_{ \sqrt{2} }x = 6[/tex]
then value of x =?
Reilly and Samantha work at frosty freeze ice cream shop. Reilly works every other day, and Samantha works every third day. Today they are working together. How many days will it be until the next time they work together?
Answer:
6 days
Step-by-step explanation:
Given that Reilly works every other day (This means that she works every 2 days) while Samantha works every third day. Today both of them are working together.
The next day none of them will be working, on the second day only Reilly would be working, on the third day only Samantha would be working, on the fourth day only Reilly would be working, on the fifth day none will be working and on the sixth day both Reilly and Samantha would be working.
This is the same as finding the least common multiple (LCM) of 2 days and 3 days which is 6 days
The slope of the line is -1 the y intercept is (0,-6)
Answer:
y=-1x-6
Step-by-step explanation:
you can also use y=-x-6 but its your choice
pls help ill give a brainly
Answer:
C. Positive 6
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
because we find the reciprocal and 9 divided by -3 and 8 divided by -4
9 divided by -3 is -3 and 8 divided by -4 is -2
so -3 times -2 is 6
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
!!!!!!!!!!!!!!!!!!!!!!
Step-by-step explanation:
  
Can someone pleaseee help if you’re correct I’ll
Give u brainlist !
Answer:
Step-by-step explanation:
Statements Reasons
1). UW bisects ∠VUX 1). Given
2). UW bisects ∠VWX 2). Given
3). ∠VUW ≅ ∠WUX 3). Definition of angle bisector
4). ∠UWV ≅ ∠UWX 4). Definition of angle bisector
5). UW ≅ UW 5). Reflexive property
6). ΔUVW ≅ ΔUXW 6). ASA postulate of congruence
Solve this help me
It is the question of class 10 Maths
Answer:
[tex]x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }[/tex]
[tex]\dfrac{9 \cdot x + 10}{3} = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3[/tex]
Therefore;
[tex]x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}[/tex]
Step-by-step explanation:
Given that we have;
[tex]x^2 - 2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} }[/tex]
[tex]x^2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} } + 2 = \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )[/tex]
[tex]x^2 = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )[/tex]
[tex]x = 3 ^{-\frac{1}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )^{\frac{1}{2} }[/tex]
[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]
[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]
[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]
[tex]x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }[/tex]
[tex]\dfrac{9 \cdot x + 10}{3} = 3 \cdot x + \dfrac{10}{3} = 3 \times \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } +\dfrac{10}{3} = \dfrac{ 3 ^{\frac{5}{3} } + 3 }{3 ^{\frac{1}{3} } } + \dfrac{10}{3}= \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } }[/tex]
[tex]\dfrac{9 \cdot x + 10}{3} =\dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } } = \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{5}{3} }+ 10 }{3 } } } = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3[/tex]
Therefore;
[tex]x^3 = \dfrac{9 \cdot x + 10}{3}[/tex]
[tex]x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}[/tex]
A relation is plotted as a linear function on a coordinate plane starting at point C at (3, –2) and ending at point D at (–2, 3). What is the rate of change for the linear function and what is its initial value?The rate of change is ______ and the initial value is ______.
Given:
A linear function starting at point C at (3, –2) and ending at point D at (–2, 3).
To find:
The rate of change and the initial value.
Solution:
If a linear function passes through two points [tex](x_1,y_1)\text{ and }(x_2,y_2)[/tex], then the equation of linear function is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
The given linear function passes through (3,-2) and (-2,3). So, the equation is
[tex]y-(-2)=\dfrac{3-(-2)}{-2-3}(x-3)[/tex]
[tex]y+2=\dfrac{3+2}{-5}(x-3)[/tex]
[tex]y+2=\dfrac{5}{-5}(x-3)[/tex]
[tex]y+2=-(x-3)[/tex]
Subtracting 2 on both sides, we get
[tex]y=-x+3-2[/tex]
[tex]y=-x+1[/tex]
On comparing this equation with slope intercept form [tex]y=mx+b[/tex], where, m is slope and b is y-intercept, we get
[tex]m=-1[/tex] and [tex]b=1[/tex]
Therefore, the rate of change is -1 and the initial value is 1.
Brainliest if answered
Answer:
Hope This Helps!!
it's not perfect.. but we get the idea...
Which of the following measurements could be the side lengths of a right triangle?
A. 60 in, 80 in, 100 in
B. 60 in, 80 in, 120 in
C. 60 in, 90 in, 100 in
D. 50 in, 80 in, 100 in
Answer:
Option A
Step-by-step explanation:
for right angle triangle a²+b²= c²
60²+80²= 10000
√10000= 100
hope it helps!
AAAAAAAAAAAAAAAAAAAA
The answer A.
A as in Apple.
Anyone know? Thank you!!
Answer:
reflect over x axis
x+3 y+3
Step-by-step explanation:
Please help me i dont know how to do this!!
Answer:
-1/2 is m and 3 is b
Step-by-step explanation:
-1/2 is the slope and 3 is the y-intercept,
Answer:
Step-by-step explanation:
The slope m is -1/2
The y-int b is 3
Since the slope is negative the graph should start from the top left and should go down all the way down to the bottom right. The line should also pass the point (0,3) since 3 is the y-int
Write -7/10 as a decimal.
which statement best describes the value of square root of 8?
a. the value of 8 is 2
b. the value of 8 is 4
c. the value of 8 is between 2 and 3.
d. the value of 8 is between 7 and 9.
Answer:
I think A but if im wrong tell me sorry if it wrong
Step-by-step explanation:
Answer:
8 is 2 answers. the answer is A
Find the Valur that Would make the graphs parallel... Its alegebra please help quick i need help!
Answer:
k=8
Step-by-step explanation:
For 2 lines to be parallel, they must have the same slope. First, let's isolate y.
5y=2x+2
y=2/5x+2/5
Now, in our second equation, we must make it so that the slope is 2/5.
5(4)=20
2(4)=k
k=8
y=8/20x+10
If you simplify that, then the slope will be 2/5.
What is the slope of a line that is perpendicular to the line y=2x+3?
Answer: -1/2
Step-by-step explanation: whenever a line is perpendicular you take the opposite reciprocal of the current slope.
Hello!
Perpendicular lines have slopes that are opposite reciprocals.
It means we take a number, flop it over and then make it negative.
So if we have 2, we flop it over:
[tex]\frac{1}{2}[/tex]
Then, we make it negative:
[tex]-\frac{1}{2}[/tex]
That is the slope. Hope it helps
If you have any query, please ask me! :)
~A forlorn girlie
[tex]MagicalNature[/tex]
WILL MARK BRAINLIEST PLS:
Give an example of a combination of two functions, f(x) and g(x), that would result in a rational function. Be sure to identify the function type for f(x) and g(x), as well as the operation used to combine them.
Answer:
fx=3x+7 gx=5x-8
Step-by-step explanation:
here i hope this helps im not 100% sure this is what you want but its what I think
Which graph shows a line with a slope of 1/2
and a y-intercept of 2?
Answer:
1.
Step-by-step explanation:
The line goes through positive 2
Answer:
2
Step-by-step explanation:
the slope has to intercept at y=2 and slope is rise over run so you would go up 1 and over 2.
Can someone help me plss! ?
Marcus solved a problem and found out that 190% of 20 is 380. Is he correct
Answer: He is Incorrect, It's 38
Work: For this question, I did the Cross-Product Method. The Cross Product Method is when you solve equation via to fractions. With the CPM, One one side of the fraction, I had x / 20 (Twenty being the whole number) and on the other side, I had 190/100 (190 being the percent) After setting this up, I made the equation. 190 times 20 is 3800, and the other multiplication is 100 times x which is 100x. So, the new equation is 3800 = 100x. I divided both sides by 100, and the answer is 38 = x
I hope this helps, and Happy Holidays! :)
Answer:
No, Marcus is not correct. He converted the percent to a decimal correctly and he multiplied correctly, but he put the decimal in the wrong place in the answer. There should be two decimal places in the answer, so the answer should be 38.
Step-by-step explanation:
I took the assingment in edge 2020
The starting line for a race in Pike is 2.4 miles from the finish line. On a map of the course, the starting and finish lines are 1 inch apart. What scale does the map use?
Explain how I solve it?
Answer:
The scale factor is 152,064:1
Step-by-step explanation:
Scaling
The real distance of a race track in Pike is 2.4 miles.
One mile is equivalent to 63,360 inches, thus 2.4 miles = 152,064 inches.
On a map, that very same distance is represented as 1 inch. Thus the scale factor is 152,064:1
This means every inch on the map is equivalent to 152,064 inches on the race track.