What is the total amount of heat needed to change 2.25 kg of silver at 0.0°C to 200.0°C? The specific heat of silver is 0.129 J/g·°C (2.25 kg = 2250 g)

Answers

Answer 1

Answer:

Q = 5805 Joules.

Explanation:

Given the following data;

Mass = 2250g

Specific heat capacity of silver = 0.129 J/g·°C

Initial temperature, T1 = 0.0°C

Final temperature, T2 = 200.0°C

To find the quantity of heat needed;

Heat capacity is given by the formula;

[tex] Q = mcdt[/tex]

Where;

Q represents the heat capacity or quantity of heat. m represents the mass of an object. c represents the specific heat capacity of water. dt represents the change in temperature.

dt = T2 - T1

dt = 200 - 0

dt = 200°C

Substituting the values into the equation, we have;

[tex] Q = 225*0.129*200[/tex]

Q = 5805 Joules.

Therefore, the amount of heat needed is 5805 Joules.

Answer 2
The amount of heat needed will be "5805 Joules".

Given values:

Mass, [tex]m = 2250 \ g[/tex]Specific heat capacity, [tex]0.129 \ J/g.^{\circ} C[/tex]Initial temperature, [tex]T_1 = 0.0^{\circ} C[/tex]Final temperature, [tex]T_2 = 200.0^{\circ} C[/tex]then,Change in temperature, [tex]dt = T_2-T_1[/tex]

                                                      [tex]= 200-0[/tex]

                                                      [tex]= 200^{\circ} C[/tex]

As we know the formula,

Heat capacity, [tex]Q = mcdt[/tex]

By substituting the values, we get

                                [tex]= 225\times 0.129\times 200[/tex]

                                [tex]= 5805 \ Joule s[/tex]

Thus the above answer is right.

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