Answer:
Spring cannot return to its original, since a part of its deformation is plastic, not elastic.
Explanation:
Physically speaking, stress is equal to the axial force divided by effective transversal area of spring. In addition, springs have usually a linear relationship between stress and strain in elastic region, since they are made of ductile materials. Axial force is directly proportional to axial stress, which is also directly proportional to axial strain.
Then, if force is greater than force associated with elastic limit of the spring, then spring cannot return to its original, since a part of its deformation is plastic, not elastic.
you will find the question in the pic
Answer:
8cm/sec
Explanation:
Number of cycle per second. Distance covered is 8cm in one cycle.
An object that is speeding up is accelerating.
True
False
Find the current in the 12 ohm resistor.
Answer:
1.5 A
Explanation:
V =I.R
18 = I × 12
I = 18/12
= 3/2 = 1.5 A
Hari drag a load of 60 kg along a distance of 12 metre what amount of work does he do also mention the type of work
Answer:
W = 7056 J
Explanation:
Given that,
Mass of a load, m = 60 kg
Distance moved, d = 12 m
We need to find the amount of work. The work done by an object is given by :
W = Fd
So,
W = mg×d
W = 60 kg × 9.8 m/s²×12 m
W = 7056 J
So, the amount of work done is 7056 J.
difference between light energy and heat energy
Where is most of Earth’s freshwater found?
in the ground
near the poles
in lakes and streams
in the air as water vapor
A satellite moves in a circular orbit at a constant speed v0 around Earth at a distance R from its center. The force exerted on the satellite is F0. An identical satellite orbits Earth at a distance of 3R from the center of the Earth. How does the tangential speed, vT, of the satellite at distance 3R compare to the speed v0 of the satellite at R
Tangential speed vT, for the stallite that orbits the earth from a distance 3R is compared by [tex]\bold {(vT)= \dfrac {(v0)}{3}}[/tex].
Given here,
Vo - Speed
R - Distance of center of the earth
Fo - Force exerted on satellite
vT - Tangential speed
For satelite, Gravitational force (Fg)is equal to the centripetal force(Fc),
Fg = Fc = Fo
[tex]\bold {\dfrac {GMm}{R^2} = \dfrac {m(v0)^2}R}[/tex]
GM = (v0)²R..................... (1)
Since, For satellite R = 3R
Thus,
[tex]\bold {\dfrac {GMm}{3R^2} = \dfrac {m(v0)^2}{3R}}[/tex]
[tex]\bold {\dfrac {GMm}{3R^2} = \dfrac {m(vT)^2}{3R}}\\\\\bold {\dfrac {GM}{27 R} = \dfrac {(vT)^2}{3R}}\\\\\bold {GM = \dfrac {27 R \times (vT)^2}{3R}}\\\\\bold {{GM}= 9 R \times (vT)^2}\\[/tex].........(2)
From equation 1 and 2,
(v0)²R = 9(vT)²R
Divide through R and then 9, we get
[tex]\bold {(vT)^2 = \dfrac {(v0)^2}{9}}[/tex]
Take the square root,
[tex]\bold {(vT)= \dfrac {(v0)}{3}}[/tex]
Therefore, tangential speed, vT, for the stallite that orbits the earth from a distance 3R is compared by [tex]\bold {(vT)= \dfrac {(v0)}{3}}[/tex].
To know more about tangential speed,
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What is the characteristic that allows an object to have kinetic energy?
Waves that do not need a medium to transfer energy are called
A. Transverse Waves
B. Mechanical Waves
C.Electromagnetic Waves
D.Longitudinal Waves
(help for science Test)
A crane lifts an air conditioner to the top of a building. If the building is 12 m high, and the air conditioner has a mass of 200 kg, how much work did the crane do to lift it? (Hint: the force the crane exerts is equal to the weight of the air conditioner)
Work needed = 23,520 J
Further explanationGiven
height = 12 m
mass = 200 kg
Required
work needed by the crane
Solution
Work is the transfer of energy caused by the force acting on a moving object
Work is the product of force with the displacement of objects.
Can be formulated
W = F x d
W = Work, J, Nm
F = Force, N
d = distance, m
F = m x g
Input the value :
W = mgd
W = 200 kg x 9.8 m/s²x12 m
W = 23520 J
6 N M 8N
What is the net force?
Answer:
14 Newtons
Explanation:
6N + 8N = 14N
What is the net force acting on a 5.0 kg object that has a velocity of 15 m/s and is moving in a
circle of radius 1.6m?
The net force acting on the object is 703.125 N
In the case of circular motion, there is a centripetal acceleration acting on the object given by:
[tex]a_{r}=\frac{v^{2} }{r}[/tex]
where, v is the velocity of the object = 15 m/s,
and r is the radius of the path = 1.6 m
The net force F:
[tex]F=ma_{r}=m\frac{v^{2} }{r}[/tex]
[tex]F=5*\frac{15^{2} }{1.6}\\F=703.125 N[/tex] is the net force acting on the object.
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On average how fast does the radiation spread from an atom-bomb?
Answer:
around 30 grays
Explanation:
Hope this helps :)
A sumo wrestler pushes another sumo wrestler back 3.41 meters, with a force of 120 N. How much work did he do? Round your answer to 2 decimal places.
Answer:
work=force* distance
Explanation:
cal it your self
Turning A of the generator spins a magnet and creates an electric current that lights the bulb. Which of the following observations can be used to indicate the strength of the current created by the generator? *
A. The brightness of the bulb
B. The size of the magnet
C. The length of the handle
D. The mass of the generator
Answer:
A. The brightness of the bulb
Explanation:
An electric current through a circuit turns the lights bulb on. the strength of the current created by the generator will be indicated by the brightness of the bulb because in a closed circuit, the bulb is the only object that is representing that, circuit is properly placed and when bulb lights up only when electrical energy is generated.
More electrical energy generated through the generator means the brighter the bulb glow.
Hence, the correct answer is "A. The brightness of the bulb".
which of the following occurrences is not dependent on gravity?
A. the moon's orbiting the sun.
B. the earth's orbiting the sun.
C. Mar's orbiting the sun.
D. all of the above are dependent of gravity.
Answer:
D
Explanation:
it's all of the above because they all use for gravity
Q3. Recall the equation that links gravitational field
strength, mass and weight
Need help ASAP
Thanks + BRAINLIST only for correct answer
1.Cell phones convert sound waves into______waves.
-light waves
-sound waves
-radio waves
2.Electromagnetic waves used in cell phone communications are called?
-microwave
-radio wave
-infrared
-all of the above
3.To send out a radio signal far and wide...it is called?
-broadcast
-casting
-antenna
Answer:
cell pohnes convert sound waves into radio waves
electromagnetic waves used in cellphone communications are called: radio waves
To send out a radio signal far and wide.. it is called: broadcast
Explanation:
Answer:
1.radio wave
2. radio wave
3.broadcasting
2. A car with mass 2,500 kg is travelling at 15 m/s. What is the car's kinetic energy?
a. 37,500 J
b. 563,000 J
c. 280,000 J
d. 350,000 J
Answer:
c, 280,000J
Explanation:
You should use the equation KE (Kinetic Energy) = [tex]\frac{1}{2} mv^2[/tex]
m = 2500
v = 15
KE = [tex]\frac{1}{2} * 2500 * (15)^2\\[/tex]
KE = 281250 Joules.
This is consistent with the answer B, as all of the parameters given to you are rounded to 2 significant figures so naturally, the answer should also be rounded to 2 sig figs.
KE = 280,000 J
A 1000 kg racecar, which is capable of a top speed of 125 m/s, is sitting in a
parking lot. How much KE does it have?
a sound wave has a frequency of 1192 hertz. all sound waves in air travel at 322m/s. find the wave length of the sound wave
Answer:
0.167 m
Explanation:
By the definition of the velocity if a wave ,
The velocity of light, v, is the product of its wavelength, λ , and its frequency, f.
V= fλ
frequency - number of occurrences in a unit time
Wavelength - distance between corresponding points of two consecutive waves
(check the graph for wavelength)
Question 1 of 10
Whích three factors are used to calculate gravitational potential energy?
A. The height of an object
B. The chemical formula for an object
O C. The density of an object
O D. The acceleration of an object due to gravity
O E. The mass of an object
F. The velocity of an object
Answer:
A., D., and E.
Explanation:
Gravitational potential energy is mgh, the values represented by answers E., D., and E., respectively.
Have a wonderful day!
Answer:
Im late. A D and E
Explanation:
The factors that affect an object's gravitational potential energy are its height relative to some reference point, its mass, and the strength of the gravitational field it is in. The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.
A scooter travelling at 10 m/s speed up to 20 m/s in 4 sec. Find the acceleration of scooter.
Explanation:
The acceleration of the scooter is 2.5 m/s
A(n) _______ is a line in which waves move that are moving together all in the same phase
Light wave
Wave front
Incident beam
Dark wave
Answer:
wave front
Explanation:
wave front is an imaginary line of a wave that joins all adjacent points that are in phase,
so that's the definition, and you apply it to the question
it obviously can't be the rest
hope you get it
please mark it brainliest
Answer:
B Wave front
Explanation:
EDG 21
Camera lenses are described in terms of
their focal length. A 50 mm lens has a focal
length of 50 mm. A camera is focused on an
object 13 m away using a 120 mm lens.
Locate the position of the image.
Answer in units of mm.
Answer:
The position of the image from the camera lens is approximately 121.1 mm
Explanation:
The given parameters of the lens are;
The specification of the camera lens = 120 mm
Therefore, the focal length of the camera lens, f = 120 mm = 0.12 m
The distance of the object from the camera, [tex]d_o[/tex] = 13 m
The lens equation for finding the position of the image is given as follows;
[tex]\dfrac{1}{f} = \dfrac{1}{d_o} + \dfrac{1}{d_i}[/tex]
Where;
[tex]d_i[/tex] = The position of the image from the camera lens
Therefore, by plugging in the known values, we have;
[tex]\dfrac{1}{13} = \dfrac{1}{0.12} + \dfrac{1}{d_i}[/tex]
[tex]\dfrac{1}{d_i} = \dfrac{1}{0.12} - \dfrac{1}{13} = \dfrac{13 - 0.12}{0.12 \times 13} = \dfrac{12.88}{1.56} = \dfrac{322}{39}[/tex]
[tex]\therefore d_i = \dfrac{39}{322} \approx 0.1211[/tex]
The position of the image from the camera lens, [tex]d_i[/tex] = 0.1211 m = 121.1 mm
How will dropping a can from a higher or a lower elevation affect the impact it has on a clay ball?
Dropping a can from a higher elevation affects greater impact compare to dropping a can from a lower elevation.
What is potential energy?Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases.
If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.
Potential energy is a system attribute, not a property of a single body or particle.
The potential energy of the can on higher elevation is greater than the potential energy of the can on lower elevation. That is why, dropping a can from a higher elevation affects greater impact compare to dropping a can from a lower elevation.
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A parallel-plate air capacitor is made from two plates 0.200{\rm m} square, spaced 0.800 {\rm cm} apart. It is connected to a 120 {\rm V} battery. If the plates are pulled apart to aseparation of 1.60 {\rm cm}, suppose the battery remains connected while theplates are pulled apart.
What is the capacitance?
C =2.21×10−11{\rm F}
Part B
What is the charge on each plate?
Enter your answer as two numbers,separated with a comma.
Part C
What is the electric field between theplates?
E =7500 {\rm V/m}
Part D
What is the energy stored in thecapacitor?
U =1.59×10−7{\rm J}
Answer:
A) C = 4.425 10⁻¹³ F, B) Q = 6.31 10⁻¹¹ C, C) E = 8.9 10⁴ N / C,
D) u_{E} = 3.19 10⁻⁹ J
Explanation:
Part A. Capacitance is
C = ε₀ A / d
in this case distance is d = 0.800 cm = 0.800 10⁻² m and the area of the plates is x = 0.200 cm= 0.2 10⁻² m, all the quantities must be in the SI system for the result to be in Farads
A = x²
A = (0.2 10⁻²)²
A = 4 10⁻⁶ m
let's calculate
C = 8.85 10⁻¹² 4 10⁻⁶ / 0.8 10⁻²
C = 44.25 10⁻¹⁴ F
C = 4.425 10⁻¹³ F
Part B. The charge on each plate is
Q = C ΔV
Q = 4.425 10⁻¹³ 120
Q = 6.31 10⁻¹¹ C
Part C. the electric field of a plate is
E = σ / 2ε₀
where the charge density is
σ = Q / A
we substitute
E =[tex]\frac{Q}{ 2\epsilon_o A}[/tex]
let's calculate
E = [tex]\frac{6.31^{-11} }{ 2 \ 8.85^{-12} \ 4^{-6} }[/tex]
E = 8.9 10⁴ N / C
Part D. stored energy
[tex]u_{E}[/tex] = ½ C V²
u_{E} = ½ 4.425 10⁻¹³ 120²
u_{E} = 3.19 10⁻⁹ J
PLS ANSWER FAST WILL GIVE BRAINLSET!!!
Calculate the missing variables using the necessary formula and rules using "FORCE"
A tractor carrying hay bales a total mass of 9 100 kg. What force is required to reach acceleration of 4 m/ s2
Answer:Hey I just wanted to tell you that Jesus LOVES YOU SO MUCH He died on the cross for all your sins so you won’t have to suffer the consequences of your sin He paid for ALL OF IT! He loves you SO FREAKING MUCH like unconditionally... all you have to do is confess with your mouth and believe in your heart that Jesus is Lord and God raised Him from the dead 3 days later you will be saved ;)))))))) He wants an intimate relationship with you all you have to do is reach out to Him I love you AND ABOVE ALL JESUS LOVES YOU
Have a blessed day;))
Explanation:
Please help.
Lions used to hunt by themselves. Now, they hunt in packs. What type of adaptation is this?
A.structural adaptation
B.behavioral adaptation
C. functional adaptation
Answer:
I think it is behavioral
If you add a neutron to an atom how does the properties of the atom change, the atoms identity? the atoms charge? the atoms size?
Answer:
Neutrons do not carry an electrical charge so adding or removing them from the nucleus does not change the electrical charge of the nucleus. ... So, adding or removing protons from the nucleus changes what element that atom is! For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium.