Calculate how many grams of oxygen form when 2.72 g of KCIOg reacts completely given the
following equation:
2 KCI03 (s)
- 2 KCI (s) + 302 (g)

337.92 moles of Ozone will be produced

1 Oxygen atom is 8 g

1 mole of ozone, O3 = 8 * 3 = 24 g

7.92 * 1024 = 8110.08 g

1 mole = 24 g

? moles = 8110.08 g

? = 337.92 moles

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Hope it helps

Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.

Molecular formula is defined as an expression that defines a number of atoms of each element in one molecule of a compound.

It can also be defined as a chemical formula that gives the total number of atoms of each elements in each molecules of a substance.

Ozone is defined as a highly reactive gas composed of three oxygen atoms and form a layer above the earth surface called as ozone layer.

1 oxygen atom = 8 g

1 mole of ozone = 8 x 3 = 24 g

7.92 x 10²⁴ = 8110.08 g

24 g = 1 mole

So, 8110.08 g = 337.92 moles

Thus, Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.

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#SPJ2

Answer:

2AgNO³(l) → 2Ag(s) + O²(g) + 2NO²(g)

Explanation:

I used powers ³,²,²

So change them to be down

Answer:

Your answer would be:
0.98atm.

Explanation:

The pressure of a gas can be calculated by using the following expression:

PV = nRT

P = pressure

V = volume
-----------------------------------

n = number of moles

R = gas law constant

T = temperature

P × 5 = 0.2 × 0.0821 × 298

5P = 4.893

P = 4.893 ÷ 5 = 0.98atm

P = 0.98atm

In conclusion, the pressure of a 5.00 L flask at 25 degrees C. that contains 0.200 mol of Cl2 is 0.98atm.

Have a great rest of your day
#TheWizzer

Answer:

Hello, senzawahl SORRY IF I SPELLED YOUR NAME INCORRECT
Prime here ready to solve your question :)


so your correct answer is 0.98atm.

Explanation:

Stay safe


-prime

Answer:

S orbital

Explanation:

no explanation, just a name you memorize

Answer:

d=3.95 g/l

Explanation:

1) Ideal gas equation:

pV = nRT

2) Transform the equation to compute density, d = m / V

n = mass in grams / molar mass = m / MM

pV = (m/MM) RT

=> pV = mRT/MM

=> m/V = pMM / (RT)

d = pMM / (RT)

p = 1.21 atm

MM = 83.80 g/mol (this is the atomic mass of krypton element)

T = 50 + 273.15 K = 323.15K

3) Compute:

d = (1.25 atm * 83.80 g/mol) / (0.0821 atm*liter /K*mol * 323.15K)

Answer:

water vapor is less dense than dry air

Answer:

option B

cementation and compaction

Answer: The gas from an erupting volcano had the following composition: 494 torr CO₂, 0.054 atm HCI, 0.028 atm HF, 0.017 atm 50₂. 0.76 mmHg H₂5, and H₂. If the total pressure is 1.00 atm, what is the partial pressure of H₂?

Explanation:

When an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

During transition from n=2 to n=1 in a hydrogen atom, the electron emits energy in the form of photon. We know that when electron absorb energy, it moves from lower level to higher level and vice versa.

So we can conclude that when an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

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Answer:

The answer is the Sodium Chloride.

Explanation:

A solute is the minor component in a solution, dissolved in the solvent, and the sodium is being dissolved in water ( or the solvent).

A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves, in this scenario sodium chloride is solute.

Those substance which are present in the solution relatively in less amount is known as solute.

In the question given that 36 grams of sodium chloride is added in the 200 grams of water. From this it is clear that sodium chloride is a solute and water is a solvent, which additionally makes a solution.

Hence, sodium chloride is a solute.

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Answer:

A.

Explanation:

For a buffer that was prepared contain 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). the pH is mathematically given as

pH=3.95

Generally, the equation for the Hendersons equation   is mathematically given as

pH=pKa+log(SALT)/(ACID)

Where

moles of  (NaCOOH)=100*0.05/1000

moles of  (NaCOOH)=0.05moles

and  formic acid

moles of formic acid=100*0.05/1000

moles of  formic acid=0.05moles

Therefore

pKa=-logka

pKa=1.4*10*3.77

pH=3.77+log{0.06/0.04}

pH=3.95

In conclusion, the pH is

pH=3.95

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Apply thermodynamics

[tex]\\ \rm\rightarrowtail Q=mc\delta T[/tex]

[tex]\\ \rm\rightarrowtail Q=1500(4.184)(27)[/tex]

[tex]\\ \rm\rightarrowtail Q=169452J[/tex]

When the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

The zinc metal will ionize as shown below;

Zn²₊ + 2e⁻ → Zn

The molar mass of zinc metal is given as 65.38 g/mol

Amount of charge that will deposite the given mass of zinc is calculated as follows;

e⁻ = 96500 C

2e⁻ = 2 x 96500 C = 193,000 C

65.38 g -------> 193,000 C

7.85 g -----------> ?

= (7.85 x 193,000)/(65.38)

= 23,173 C

Thus, when the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

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For a 35.83 g sample of potassium chlorate,  the mass of potassium chloride is mathematically given as

M Kcl=21.62g

Generally, the equation for the Chemical Reaction  is mathematically given as

2KClO_3----->2KCl+2O_2

Therefore

[tex]Mole of KCl=\frac{35.57}{122.55}[/tex]

Mole of KCl=0.29mol

Mass of Kcl=0.29*74.55

Mass of Kcl=21.62g

In conclusion, Mass of Kcl

M Kcl=21.62g

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Answer: True

Explanation:

[tex]\mathrm{The\ balanced \ chemical \ equation\ is\ :}\\$2 \mathrm{Na}{(s)}+\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{NaCl}(s)[/tex]

For Na

[tex]\\$Given mass $=20.4 \mathrm{~g}$ \ \ Molecular mass $=23 \mathrm{~g}\ \ $Number of moles $=\frac{\text { Given mass }}{\text { Molecular mass }}$$$\begin{aligned}&=\frac{20.4}{23} \\&=0.887 \text { moles }\end{aligned}$$Stoichiometric ratio of $\mathrm{Na}$ is same as that of $\mathrm{NaCl}$ i.e., $1: 1$.$\therefore$ Moles of $\mathrm{NaCl}=0.887$ motes[/tex]

For NaCl

[tex]$$\\\begin{aligned}\text { Molecular mass } &=23+35.5 \\&=58.5 \mathrm{~g}\end{aligned}$$[/tex]

[tex]\begin{aligned}\\& $\therefore$ Mass of $\mathrm{NaCl}$ produced will be=\text { No.of moles } \times \text { Molecular mass } \\&=0.887 \times 58.5 \\&=51.9 \\&\simeq 52 \mathrm{~g} \quad\end{aligned}$$[/tex]

Therefore, it is true that when 20.4g of sodium metal are mixed with chlorine gas, 52.0 g of sodium chloride is produced

Explanation:

The answer: True

I explained the answer to your question in the submitted photo

Answer:

Calculate the pOH for a solution with a hydroxide ion, (OH-) of concentration of 6.49 X 10-11 M.

Calculate the pH.

Note: the answers should have three significant figures

The pOH is: Blank 1

The pH is: Blank 2

Explanation:

For 3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0mL water initially,  the density of this unknown meta  is mathematically given as

D= 0.23 g/ml

Generally, the equation for the Volume of water  is mathematically given as

Vw= Volume of water after metal addition - Volume of water initial

Therefore

Vw = 65 ml - 50 ml

Vw= 15 ml

In conclusion,

D= Mass of metal / Volume

D= 3.5 / 15

D= 0.23 g/ml

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An ionic compound does dissociate to a large extent in water. The compound that will completely dissociate in water here is Ba(NO3)2.

A soluble compound is a compound that can dissociate to a large extent in water. Not all compounds are soluble in water. Only ionic compounds are soluble in water.

The compound that  would dissolve in water among the list of compounds here is Ba(NO3)2.

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Answer:

A) Ba(NO3)2

B) CaSO4

C) CO2

D) H2CO3

E) Mg3(PO4)2

Explanation:

Wish I could give a good explanation, but I am still learning myself. Try searching up a video explaining this concept!

The benzene molecule is flat and planar. As a result of this planarity, the substituent is also in the plane of molecule and do not show any directionality.

The benzene molecule is a flat and planar molecule owing to the fact that all the bond lengths and bond angles in the molecules are the same. This results from resonance in the molecule.

Hence, owing to the planarity of the molecule, the substituent is also in the plane of molecule and do not show any directionality.

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The volume of the 1.75 M H₃PO₄ solution required to neutralize 50 ml of 3.5 M Ca(OH)₂ solution is 66.67 mL

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

MaVa / MbVb = nA / nB

(1.75 × Va) / (3.5 × 50) = 2/3

(1.75 × Va) / 175= 2/3

Cross multiply

1.75 × 3 × Va  = 175 × 2

5.25 × Va = 350

Divide both side by 5.25

Va = 350 / 5.25

Va = 66.67 mL

Thus, the volume of the H₃PO₄ solution needed is 66.67 mL

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Answer:

BIKE riding, Watching yt, Hanging with friends, Food,Dogs

Answer:

the enthalpy change of this is 5.02mol

The  metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between hydrogen and fluorine is 1:1.

A compound is madeup of two or more atoms that are chemically combined together. In this case, we have the atoms; hydrogen and fluorine.

The electronic configuration of the atoms  are not shown here but the  metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between hydrogen and fluorine is 1:1.

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Answer:

It is Se.

hope this helps.

Answer:

Explanation:

This is not my photo. I got it from this website.

https://pubchem.ncbi.nlm.nih.gov/compound/Chlorocyclohexane#section=2D-Structure

The molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

The molarity of a solution can be calculated using the following formula:

CaVa/CbVb = na/nb

Where;

The balanced equation of the reaction is as follows:

Pb(NO3)2 (aq) + 2KI (aq) → 2KNO3 (aq) + PbI2 (s)

22 × 2/18 × Cb = 2/1

44/18Cb = 2

Cb = 44 ÷ 36

Cb = 1.2M

Therefore, the molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

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Answer:

B

Explanation:

2.8.1 Na

2.8.2 Mg

and so on and so forth