Answer:
Camouflage is a way of hiding. Blending in.
Explanation:
Look it up in a dictionary
Someone help me with this PE question?
Answer:
Your abdominals
Explanation:
At what speed, in m/s, would a moving clock lose 1.3ns in 1.0 day according to experimenters on the ground?
Answer:
v=0.14c
Explanation:
A runner completes the 200-meter dash with a time of 19.80 seconds. What was the runner's average speed in miles per hour?
Answer:
v = 22.54 mph.
Explanation:
Given that,
Distance moved, d = 200 m
Time, t = 19.8 s
We need to find the runner's average speed.
We know that,
1 mile = 1609.34 m
200 m = 0.124 miles
19.8 seconds = 0.0055 h
So,
Speed = distance/time
[tex]v=\dfrac{0.124}{0.0055}\\\\v=22.54\ mph[/tex]
So, the runner's average speed is 22.54 mph.
6. A baseball player hits a 0.155-kilogram fastball traveling at -44.0 m/s into center field at a speed of 50.0
m/s. If the impact lasts for 0.00450 second, with what force does he hit the
baseball?
Answer:
3,237.78N
Explanation:
According to Newton's second law of motion
F = mass * acceleration
Since a = v-u/t
F = m(v-u)/t
Given
Mass m = 0.155kg
v = 50.0m/s
u = -44.0m/s
Time t = 0.00450secs
Substitute
F = 0.155(50-(-44))/0.00450
F = 0.155(50+44)/0.00450
F = 0.155(94)/0.00450
F = 14.57/0.00450
F = 3,237.78N
hence he hit the baseball with a force of 3,237.78N
An object is traveling at a velocity of 100 rn/s to the left for about 5 seconds. How far has the object traveled? (What is the distance?)
Answer:
500 rn
Explanation:
The surface area of a postage
stamp is 0.00600 m^2, and the air
exerts 1.00 atm of pressure on it.
How much force does it exert on
the stamp?
(Hint: The standard unit for
pressure is Pa.)
(Unit = N)
Answer:
Force = 607.95 Newton
Explanation:
Given the following data;
Area = 0.00600 m^2
Pressure = 1 atm to Pascal = 101325 Pa
To find the force;
Pressure = Force/area
Force = pressure * area
Substituting into the equation, we have;
Force = 101325 * 0.00600
Force = 607.95 Newton.
Therefore, the amount of force exerted by the air on the stamp is 607.95 Newton.
Is it possible for the earth to be sucked into a black hole? If so, what would happen?
Answer:
si es posible
Explanation:
ya no existiria la tierra
if possible
the earth would no longer exist.
Answer:
Yes,
Explanation:
We would all die immediatly, its like being stretched and crushed
How does energy keep the world going? How is energy conserved?
Answer:
The most notable way that reducing energy helps the environment is by decreasing power plant emissions.
Answer:
Explanation:
The conservation of energy law states that energy cant be created or destroyed, only transferred. Since energy cant be created or destroyed, the amount of energy in the universe is completely constant.
Energy keeps the world "going" because we use it every single day in our life. Everything in the universe uses some sort of energy. We digest food for energy, we use electrical energy for electronics, we convert electrical energy into heat energy for heaters and such, we use solar panels to power our houses. There are countless examples of how energy keeps the world "going."
Anastasia constructed a simple circuit with a battery and a light bulb. She knows that the resistance of the light bulb is 10
2 and that the voltage given to the light bulb is 12 V. What is the current through the light bulb?
Answer:
Simple Single Loop Circuits. J. E σ. = ∆V = IR ... To find the current, use the total voltage and equivalent resistance: S. V ... A circuit contains a 48-V battery and two 240Ω light bulbs.
A taxi hurries with a constant speed of 60 miles per hour. How long will it take to travel a distance of 130 miles
Answer:
2.17 hrs
Explanation:
time = distance / velocity
We know that distance = 130 miles and velocity = 60 miles/h.
t = d / v
t = 130 miles / 60 miles/h
t = 2.17 hrs
It takes about 2.17 hours to travel a distance of 130 miles. Hope this helps, thank you !!
A particle with a charge of -4.3 μC and a mass of 4.4 x 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 80 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VA, then give the answer as a positive number. If VB is less than VA, then give the answer as a negative number.
Answer:
ΔV = - 3274 V
Explanation:
For this exercise we can use conservation of energy
starting point.
Em₀ = U = q ΔV
final point
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
q ΔV = ½ m v²
ΔV = [tex]\frac{m \ v^2 }{q}[/tex]
let's calculate
ΔV = [tex]\frac{4.4 \ 10^{-6} \ 80^2 }{ 2 \ 4.3 10^{-6} }[/tex]
ΔV = 3274.4 1 V
since the charge q is negative, the potential at point B must be less than the potential at point A, so the answers
ΔV = - 3274 V
What is a watt a unit of?
light
time
distance
power
Answer:
power...............m....
Answer:
The dimension of power is energy divided by time. In the International System of Units (SI), the unit of power is the watt (W), which is equal to one joule per second.
SI unit: watt (W)
In SI base units: kg⋅m2⋅s−3
Explanation:
Cheetahs can accelerate to a speed of 20.0 m/s in 2.50 s and can continue to accelerate to reach a top speed of 30.0 m/s. Assume the acceleration is constant until the top speed is reached and is zero thereafter. Let the +x-direction point in the direction the cheetah runs. Express the cheetah’s top speed (vtop) in miles per hour (mi/h).
Starting from a crouched position, how much time (t-accel) does it take a cheetah to reach its top speed, and what distance (d) does it travel in that time?
Answer:
The cheetah’s initial velocity is 0 m/s. Let’s use the following equation to determine the acceleration.
Explanation:
Acceleration = (v/t) = (20/2.5) = 8m/sec^2.
1) Time to 29m/sec. = (v/a) = (29/8) = 3.625 secs. (3.6)
Distance covered to top speed = (v^2/2a) = 52.5625 metres (52.6).
2) Distance to run at top speed = (120 - 52.5625) = 67.4375 metres.
Time = (d/v) = (67.4375/29) = 2.325 secs.
Total time to warthog = (2.325 + 3.625) = 5.95 secs.
Cheetah's top speed will be "67.12 mi/h". A complete solution is provided below.
Given that:
Speed,
20.0 m/sTime,
2.50 sAcceleration to top speed,
30.0 m/sNow,
→ Acceleration (a) of cheetah will be:
= [tex]\frac{20}{2.5}[/tex]
= [tex]8 \ m/s^2[/tex]
→ Top speed ([tex]V_{top}[/tex]) of cheetah
= [tex]\frac{30}{1609}\times 3600[/tex]
= [tex]67.12 \ mi/h[/tex]
→ The time required (t) to reach the top speed will be:
= [tex]\frac{30}{8}[/tex]
= [tex]3.75 \ sec[/tex]
and,
→ The distance travelled (d) by cheetah will be:
= [tex]\frac{1}{2}\times 8\times (3.75)^2[/tex]
= [tex]\frac{1}{2}\times 8\times 14.0625[/tex]
= [tex]56.25[/tex]
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9. What is the speed of a 25 kg object that has 2500 J of kinetic energy?
Answer:
We conclude that the speed of a 25 kg object that has 2500 J of kinetic energy is 14.14 m/s.
Explanation:
Given
Mass m = 25 kg Kinetic Energy (K.E) = 2500 JTo determine
The speed v = ?
We know that a body can possess energy due to its movement — Kinetic Energy.
The speed with which a body moves can be determined using the formula
[tex]K.E=\frac{1}{2}mv^2[/tex]
[tex]v=\sqrt{\frac{2\times \:K.E}{m}}\:\:\:[/tex]
substituting m = 25 and K.E = 2500 in the formula
[tex]v=\sqrt{\frac{2\times 2500}{25}}[/tex]
[tex]v=\sqrt{\frac{5000}{25}}[/tex]
[tex]v=\sqrt{200}[/tex]
[tex]v=14.14[/tex] m/s
Therefore, we conclude that the speed of a 25 kg object that has 2500 J of kinetic energy is 14.14 m/s.
A car traveling 85 km/h is 250 m behind a truck
traveling 73 km/h.
Time needed = t = 20.83 s
Further explanationGiven
car speed = 85 km/h
truck speed = 73 km/h
Required
the time it takes for the car to reach the truck
Solution
When the car reaches the truck, the distance between them will be the same
x car - 250 m = x truck
General formula for distance (d) :
d = v.t
So the equation becomes :
85t-250 = 73t
12t=250
t = 20.83 s
Calculate the change in momentum of a ball has 35 kg mass and it changed its velocity from 3m/s to 6 m/s
please hellllpppppp
Answer:
105 kg.m/s
Explanation:
Formula for change in momentum is given as;
ΔP = m(v - u)
We are given;
Mass; m = 35 kg
Initial velocity; u = 3 m/s
Final velocity; v = 6 m/s
Thus;
ΔP = 35(6 - 3)
ΔP = 35 × 3
ΔP = 105 kg.m/s
For each scenario below, choose the best graph.
(a) Maria bikes from home to work.
A line graph that plots either speed or distance against time.
Really, the type of graph depends on what quantity you want the graph to show.
A cart was allowed to roll down a ramp from rest. It reached the bottom of the ramp with a speed of 25 cm/s. A student could conclude that the cart
Answer:
A student could conclude that the cart gained momentum as it rolled down.
Explanation:
If the cart was allowed to roll down the ramp from rest, it means that the initial velocity of the cart is zero (0). Also, if the final velocity of the cart became 25 cm/s, it means that the velocity of the cart increased from 0 to 25 cm/s.
Therefore, A student could conclude that the cart gained momentum as it rolled down.
if |v|= 11, |w|= 23, |v-w|= 30, find |v+w|
Answer:
[tex]|v+w|=20[/tex]
Explanation:
We are given that
|v|=11
|w|=23
|v-w|=30
We have to find the value of |v+w|
|a-b|^2=(a+b)\cdot (a+b)=a^2+b^2-2|a||b|cos\theta
Using the formula
[tex](30)^2=(11)^2+(23)^2-2(11)(23)cos\theta[/tex]
[tex]900=121+529-506cos\theta[/tex]
[tex]900-121-529=-506cos\theta[/tex]
[tex]250=-506cos\theta[/tex]
[tex]cos\theta=-\frac{250}{506}[/tex]
[tex]|a+b|^2=|a|^2+|b|^2+2a\cdot bcos\theta[/tex]
Using the formula
[tex]|v+w|^2=(11)^2+(23)^2+2(11)(23)\times (-\frac{250}{506})[/tex]
[tex]|v+w|^2=400[/tex]
[tex]|v+w|^2=(20)^2[/tex]
[tex]|v+w|=20[/tex]
Predictions about the future based on the position of planets is an example of
- physics
- biology
- earth science
- pseudoscience
Answer:
astronomi
Explanation:
sciemce ya ya
Which statement about personal strength is TRUE?
1. It is inborn and cannot be developed with training or practice.
2. It is something you can acquire with hard work and lots of practice.
3. It is strictly a physical quality, like beauty, or physical ability, like the ability to swim fast.
4. It is such a natural part of a person that they may not even recognize it.
what are the four intermittent reinforcement schedules in your own words?
A pendulum is placed on a distant planet. The length is one meter, and the measured period is 1.4 seconds, what is the acceleration of gravity on that planet?
Answer:
[tex]a=20.14\ m/s^2[/tex]
Explanation:
The time period of the simple pendulum is given by :
[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]
l is the length of the pendulum
g is the acceleration due to gravity
We have,
T = 1.4 s, l = 1 m
So,
[tex]T^2=\dfrac{4\pi^2 l}{g}\\\\g= \dfrac{4\pi^2 l}{T^2}\\\\g= \dfrac{4\pi^2 \times 1}{(1.4)^2}\\\\g=20.14\ m/s^2[/tex]
So, the acceleration due to gravity of that planet is [tex]20.14\ m/s^2[/tex].
A stunt man jumps from a burning building and comes to
rest at ground level. Consider his impulse during landing if
he lands on a soft mat, on a concrete surface, or in a safety
net. Which of the following is true?
a. His impulse is greatest if he lands on a soft mat.
b. His impulse is greatest if he lands on a concrete
surface.
c. His impulse is greatest if he lands in a safety net.
d. The impulse is the same in all three cases.
e. There is zero impulse in all three cases because he
comes to rest.
Answer:
I think it's E it just sounds right to me tbh
Explanation:
Look at the equation. What detail is missing? 3 m/s2= (33 m/s - X)/30 S
Answer:
The starting velocity.
Explanation:
We must understand that this equation comes from the following equation of kinematics.
[tex]v_{f}=v_{o}+a*t[/tex]
where:
Vf = final velocity = 33 [m/s]
Vo = starting velocity [m/s]
a = acceleration = 3 [m/s²]
t = time = 30 [s]
So, these values can be assembly in the following way:
[tex]v_{f}=v_{o}+a*t\\a*t=v_{f}-v_{o}\\3=\frac{33-v_{o}}{30}[/tex]
In a game of ice hockey, you use a hockey stick to hit a puck of mass 0.16 kg that slides on essentially frictionless ice. During the hit you exert a constant horizontal force on the puck that gives it an acceleration of 75 m/s2 for a fraction of a second. During the hit, what is the magnitude of the horizontal force that you exert on the puck
Answer:
12N
Explanation:
given- mass, acelation
Fnet=ma= .16kg*75m/s2
Fnet=12 N only force no friction given.
The driver of a car traveling at 21.6 m/s applies the brakes and undergoes a constant deceleration of 1.86 m/s 2 . How many revolutions does each tire make before the car comes to a stop, assuming that the car does not skid and that the tires have radii of 0.35 m
Answer:
each tire made 57.03 revolutions before the car halted
Explanation:
Given that;
Initial Velocity u = 21.6 m/s
final velocity v = 0 m/s
acceleration = - 1.86 m/s²
radii r = 0.35 m
first we calculate distance travelled by the car to stop;
v² - u² = 2as
s = v² - u² / 2a
we substitute
s = (0² - (21.6)² / 2 × (-1.86)
s = (0 - 466.56) / ( - 3.72 )
s = 125.419 m
Now Distance traveled by each tire in 1 revolution = 2πr
i.e 2πr is travelled in 1 revolution
so
n×2πr = 125.419 m
n = 125.419 m / 2πr
n = 125.419 m / 2π(0.35)
n = 125.419 / 0.7π
n = 57.03 revolutions
Therefore, each tire made 57.03 revolutions before the car halted
What recreational drug does an alcopop contain?
An "alcopop" is a term used to describe a flavored alcoholic beverage that typically resembles a soft drink or a fruit juice in appearance and taste. It is also referred to as a "ready-to-drink" (RTD) beverage.
Alcopops are often targeted toward younger consumers and are known for their sweet and fruity flavors, which can mask the taste of alcohol.
The specific recreational drug that an alcopop contains is alcohol itself. Alcohol, or ethanol, is a psychoactive substance that can have intoxicating effects when consumed.
It is considered a recreational drug because of its ability to alter consciousness, impair judgment and coordination, and produce pleasurable or mood-altering effects.
The alcohol content in alcopops can vary, but it is typically lower than in pure spirits or liquors. This is often achieved through dilution with other ingredients, such as carbonated water or fruit juices, to create a milder alcoholic beverage.
Alcopops may also contain additional flavorings, sweeteners, and additives to enhance their taste and appeal.
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Which of the following statements is FALSE regarding the law of conservation of energy?
The total amount of energy remains constant.
Energy can neither be created nor be destroyed.
Energy can be transformed from one form to another.
The total amount of energy changes upon an energy transformation.
Answer:
D
Explanation:
because it doesn't agree with the law of definite proportion
and energy can niether be created nor destroyed but can be transformed from one form to another
The false statement will be, The total amount of energy changes upon an energy transformation.
What is conservation of energy?The conservation of energy according to the first law of thermodynamics is that energy neither be created nor be destroyed, but can be transformed from one form to another form.
Now we can take many examples like if we are running a bicycle our efforts are converted to the rotation of the wheel and the rotation energy is converted to the linear energy of our motion.
But the necessary point is that from the second law of thermodynamics it states that the energy can not be completely converted to the other form but some part of it is losses in the environment.
Thus the false statement will be, The total amount of energy changes upon an energy transformation.
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A ball player catches a ball 3.10 s after throwing it vertically upward. a) with what speed did he throw it? b) what height did it reach?
Answer:
speed=30.41, height=94.27
Explanation:
since the motion is vertical upward means the motion is against gravitational force and the initial velocity of the ball was zero.