Can anyone help me with this question?

a) The explicit formula for f ο g is f(g(x)) = 10x + 17. b) The explicit formula for g ο f is g(f(x)) = 10x + 22. c) The explicit formula for f ο h is f(h(x)) = 2[tex]x^{2}[/tex] + 5. d) The explicit formula for h ο f is h(f(x)) = 4[tex]x^{2}[/tex] + 12x + 10.

To find the explicit formulas for each function composition, we substitute the inner function into the outer function and simplify.

(a) f ο g:

f(g(x)) = f(5x + 7)

= 2(5x + 7) + 3

= 10x + 14 + 3

= 10x + 17

Therefore, the explicit formula for f ο g is f(g(x)) = 10x + 17.

(b) g ο f:

g(f(x)) = g(2x + 3)

= 5(2x + 3) + 7

= 10x + 15 + 7

= 10x + 22

Therefore, the explicit formula for g ο f is g(f(x)) = 10x + 22.

(c) f ο h:

f(h(x)) = f([tex]x^{2}[/tex] + 1)

= 2([tex]x^{2}[/tex] + 1) + 3

= 2[tex]x^{2}[/tex] + 2 + 3

= 2[tex]x^{2}[/tex] + 5

Therefore, the explicit formula for f ο h is f(h(x)) = 2[tex]x^{2}[/tex] + 5.

(d) h ο f:

h(f(x)) = h(2x + 3)

= [tex](2x+3)^{2}[/tex] + 1

= 4[tex]x^{2}[/tex] + 12x + 9 + 1

= 4[tex]x^{2}[/tex] + 12x + 10

Therefore, the explicit formula for h ο f is h(f(x)) = 4[tex]x^{2}[/tex] + 12x + 10.

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The explicit formulas for the compositions of functions are:

(a) f ο g: 10x + 17

(b) g ο f: 10x + 22

(c) f ο h: 2x^2 + 5

(d) h ο f: 4x^2 + 12x + 10

For the explicit formulas for the compositions of functions, we substitute the inner function into the outer function. Using the provided functions:

(a) f ο g: We substitute g(x) into f(x).

f(g(x)) = 2(g(x)) + 3 = 2(5x + 7) + 3 = 10x + 17

The explicit formula for f ο g is 10x + 17.

(b) g ο f: We substitute f(x) into g(x).

g(f(x)) = 5(f(x)) + 7 = 5(2x + 3) + 7 = 10x + 22

The explicit formula for g ο f is 10x + 22.

(c) f ο h: We substitute h(x) into f(x).

f(h(x)) = 2(h(x)) + 3 = 2(x^2 + 1) + 3 = 2x^2 + 5

The explicit formula for f ο h is 2x^2 + 5.

(d) h ο f: We substitute f(x) into h(x).

h(f(x)) = (f(x))^2 + 1 = (2x + 3)^2 + 1 = 4x^2 + 12x + 10

The explicit formula for h ο f is 4x^2 + 12x + 10.

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The teacher will have a total of 120 pens if 12 sets of pens are ordered.

To find the total number of pens a teacher will have if 12 sets of pens are ordered, we can start by finding the total number of pens in one set and then multiply it by 12.

In one set, there are 4 blue pens, 3 black pens, 2 red pens, and 1 purple pen. To find the total number of pens in one set, we can simply add the number of pens of each color:

Total pens in one set = 4 + 3 + 2 + 1 = 10

Therefore, the numerical expression to represent how many pens a teacher will have if 12 sets of pens are ordered is:

12 × 10 = 120

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The ramp includes the flat piece as well as the angled piece and is made entirely out of concrete,the total amount of concrete in the ramp is  696 square inches.

To calculate the total amount of concrete in the ramp, we need to find the surface area of each component (rectangular prism and triangular prism) and sum them up.

Rectangular Prism:

The rectangular prism has a length of 6 inches, width of 18 inches, and height of 6 inches. The surface area of a rectangular prism is given by the formula:

Surface Area = 2lw + 2lh + 2wh

Substituting the values, we get:

Surface Area of Rectangular Prism = 2(6 * 18) + 2(6 * 6) + 2(18 * 6) = 216 + 72 + 216 = 504 square inches

Triangular Prism:

The triangular prism has triangular sides with a base of 8 inches and height of 6 inches. The prism has a height of 18 inches. To find the surface area of a triangular prism, we need to calculate the area of the triangular sides and the area of the rectangular side.

Area of Triangular Sides = 2 * (1/2 * base * height) = 2 * (1/2 * 8 * 6) = 48 square inches

Area of Rectangular Side = length * height = 8 * 18 = 144 square inches

Surface Area of Triangular Prism = Area of Triangular Sides + Area of Rectangular Side = 48 + 144 = 192 square inches

Total Surface Area:

To get the total surface area of the ramp, we sum up the surface areas of the rectangular prism and the triangular prism:

Total Surface Area = Surface Area of Rectangular Prism + Surface Area of Triangular Prism

= 504 + 192

= 696 square inches

Therefore, the total amount of concrete in the ramp is 696 square inches.

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If an auditorium has a total of 1280 seats, there are 40 seats in each row.

The total number of seats in the auditorium is modeled by the function f(x) = [tex]2x^{2} -24x[/tex], where x represents the number of seats in each row. We need to find the value of x when f(x) equals 1280.

Setting the equation equal to 1280, we have:

[tex]2x^{2} -24x[/tex] = 1280

Rearranging the equation, we get:

[tex]2x^{2} -24x[/tex] - 1280 = 0

To solve this quadratic equation, we can either factor it or use the quadratic formula. Factoring is not straightforward in this case, so we'll use the quadratic formula

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = 2, b = -24, and c = -1280. Plugging in these values, we have:

x = (-(-24) ± √((-24)^2 - 4(2)(-1280))) / (2(2))

Simplifying further, we get:

x = (24 ± √(576 + 10240)) / 4

x = (24 ± √10816) / 4

x = (24 ± 104) / 4

This gives us two possible solutions: x = (24 + 104) / 4 = 128/4 = 32 or x = (24 - 104) / 4 = -80/4 = -20.

Since the number of seats cannot be negative, the valid solution is x = 32. Therefore, there are 32 seats in each row of the auditorium.

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The equation is solved for x as x = √12 - 2

Real numbers are simply defined as the combination of rational and irrational numbers, in the number system.

Note that algebraic expressions are defined as expressions that are made up of terms, variables, coefficients, factors and constants

From the information given, we have that;

5(x+2)² = 60

Divide both sides by the multiplier, we have;

(x + 2)²= 60/5

Divide the values

(x + 2)²= 12

Now, find the square root of both sides, we get;

x+ 2= √12

Now, collect the like terms, we have;

x = √12 - 2

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The given series is a complex alternating series. By applying the ratio test, we can show that the series converges. However, it does not have a closed form expression, and therefore we cannot obtain an exact value for the sum of the series.

The given series can be written in sigma notation as:

∑n=0 ∞ 7[tex](-1)^n([/tex]2n +1) [tex]3^(2n +1)[/tex] (2n + 1)!

To test for convergence, we can apply the ratio test, which states that if the limit of the absolute value of the ratio of consecutive terms is less than 1, then the series converges absolutely. Applying the ratio test to this series, we get:

lim|(7*[tex](-1)^(n+1)[/tex] * 3[tex]^(2n+3)[/tex] * (2n+3)!)/((2n+3)(2n+2)(3^(2n+1))*(2n+1)!)| = 9/4 < 1

Therefore, the series converges absolutely.

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The value of a is -1/2 when the slope of a line passing through points A(2a,3) and B(-1,3) is 6.

The slope formula can be used to find the value of a in the equation,  which states that the slope of a line passing through two points (x1, y1) and (x2, y2) is given by the formula (y2 - y1) / (x2 - x1).

In this case, the two points are A(2a, 3) and B(-1, 3), and we know that the slope is 6.

By substituting values into the slope formula:

(3 - 3) / (-1 - 2a) = 6

Simplifying the equation:

0 / (-1 - 2a) = 6

-1 - 2a = 0

-1 = 2a

Dividing both sides by 2:

-1/2 = a

So, the value of "a" is -1/2.

Therefore the value of a is -1/2 when the slope of a line passing through points A(2a,3) and B(-1,3) is 6.

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There is no incorrect statement to fix. The incorrect statement has not been specified in the question. Thus, we need to check for the correctness of both statements.

After Christmas, artificial Christmas trees are 60% off. Employees get an additional 10% off the sale price. We know the original prices of both trees, which are $115 and $205 respectively. Let's calculate the new price of Tree A and Tree B.

Tree A original price $115. Tree B original price $205. After Christmas, both trees are 60% off. Let's calculate the new price of Tree A and Tree B. Tree A:  [tex]$115 - (60/100) x $115 = $46 [/tex].

Therefore, the sale price of Tree A is $46.

Employees get an additional 10% off the sale price.

Therefore, the discounted price for the employees is  [tex]$46 - (10/100) x $46 = $41.4 [/tex].

Tree B:  [tex]$205 - (60/100) x $205 = $82 [/tex].

Therefore, the sale price of Tree B is $82. Employees get an additional 10% off the sale price.

Therefore, the discounted price for the employees is [tex]$82 - (10/100) x $82 = $73.8[/tex].

As we calculated above, the statements are correct. Hence, there is no incorrect statement. Thus, no fix is required. Therefore, the answer is "There is no incorrect statement to fix."

There is no incorrect statement to fix. The original prices of Tree A and Tree B are correctly calculated, as well as the discounted prices for employees. The given statements are accurate and do not require any correction.

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The incorrect statement is, “Tree A is $46 after all discounts are applied.”

After Christmas, the artificial Christmas trees are 60% off and employees get an additional 10% off the sale price.

Two trees are Tree A and Tree B.

Tree A original price is $115.

After a 60% discount, the price is:60/100 x $115 = $69

The sale price of Tree A is $69.

After the employees' 10% discount: 10/100 x $69 = $6.9

Discounted price of Tree A is: $69 - $6.9 = $62.1

Tree B original price is $205.

After a 60% discount, the price is: 60/100 x $205 = $123

The sale price of Tree B is $123.

After the employees' 10% discount:10/100 x $123 = $12.3

Discounted price of Tree B is: $123 - $12.3 = $110.7

Therefore, the incorrect statement is “Tree A is $46 after all discounts are applied.”

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Answer: The Total number of Students who like Milk is 12 and the total number of Students who like Tea is 9.

Step-by-step explanation:

Let us start off by subtracting the number of students who like both milk and tea from the total number of students:

33-12 = 21

Rest of the 21 Students like either Milk or Tea. Now with the help of the ratio, we find the total number of students who like Milk alone:

21 x  4/7 = 12

(4 Being the ratio of students who like Milk and 7 being the total ratio of 4+3 )

12 Students like Milk while:

21-12= 9 (or) 21 x 3/7= 9

9 Students like Tea.

The given series is absolutely convergent and conditionally convergent.

To determine whether the series

Š 15 - cos(3n) / [tex]n^{(2/3)}[/tex] - 2

is absolutely convergent, conditionally convergent, or divergent, we need to check both the absolute convergence and conditional convergence.

First, we consider the absolute convergence of the series. We take the absolute value of the series to obtain:

Š |15 - cos(3n)| / [tex]\ln^{(2/3)}[/tex] - 2|

By using the limit comparison test with the series 1/n^(2/3), we can conclude that the series is convergent, and therefore, absolutely convergent.

Next, we consider the conditional convergence of the series. We take the series:

Š 15 - cos(3n) / [tex]n^{(2/3)}[/tex] - 2

and group the terms for even and odd values of n, respectively:

Š (15 - cos(3n)) / [tex]n^{(2/3)}[/tex] - 2 = [15 / [tex]n^{(2/3)}[/tex] - 2] - [cos(3n) / [tex]n^{(2/3)}[/tex] - 2]

The first term in the above equation converges to 0, as n approaches infinity. However, the second term is an alternating series, which does not converge to 0. Thus, by the alternating series test, the series is conditionally convergent.

Therefore, the given series is absolutely convergent and conditionally convergent.

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To determine whether the series Š 15 - cos(3n) / n^(2/3) - 2 n = 1 is absolutely convergent, conditionally convergent, or divergent, we need to first check if the series converges absolutely.

To do this, we need to find the absolute value of each term in the series:

|15 - cos(3n)| / |n^(2/3) - 2|

Since the absolute value of cosine is always less than or equal to 1, we can simplify the expression to:

(15 + 1) / |n^(2/3) - 2|

= 16 / |n^(2/3) - 2|

Next, we need to determine whether the series Σ 16 / |n^(2/3) - 2| converges or diverges.

We can use the limit comparison test with the p-series Σ 1/n^(2/3):

lim(n → ∞) (16 / |n^(2/3) - 2|) / (1/n^(2/3))

= lim(n → ∞) (16n^(2/3)) / |n^(2/3) - 2|

We can simplify this expression by dividing the numerator and denominator by n^(2/3):

= lim(n → ∞) (16 / |1 - 2/n^(2/3)|)

Since the limit of the denominator is 1 and the limit of the numerator is 16, we can apply the limit comparison test and conclude that the series Σ 16 / |n^(2/3) - 2| converges if and only if Σ 1/n^(2/3) converges.

However, the series Σ 1/n^(2/3) is a p-series with p = 2/3, which is less than 1. Therefore, Σ 1/n^(2/3) diverges by the p-series test.

Since Σ 16 / |n^(2/3) - 2| converges if and only if Σ 1/n^(2/3) diverges, we can conclude that Σ 16 / |n^(2/3) - 2| diverges.

Therefore, the original series Š 15 - cos(3n) / n^(2/3) - 2 n = 1 is also divergent.

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To determine if the given vectors form a fundamental set of solutions on the interval (-∞, ∞) for the system ′ = , we need to check if they are linearly independent. If they are linearly independent, they form a fundamental set of solutions, and the general solution can be obtained by taking linear combinations of these vectors.

To determine if the vectors form a fundamental set of solutions, we need to check if they are linearly independent. If they are linearly independent, it means that no vector can be expressed as a linear combination of the others.

Let's denote the given vectors as v1, v2, ..., vn. We can create a matrix A by placing these vectors as its columns. If the determinant of A is non-zero, the vectors are linearly independent, and they form a fundamental set of solutions.

If the vectors are linearly independent, the general solution to the system is given by the linear combination of these vectors, where the coefficients can be any constants. Each solution can be expressed as a linear combination of the vectors, and the general solution represents all possible solutions to the system.

On the other hand, if the vectors are linearly dependent, they do not form a fundamental set of solutions. In this case, additional vectors are needed to form a complete set of solutions.

By determining the linear independence of the given vectors, we can conclude whether they form a fundamental set of solutions and obtain the general solution accordingly.

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The system has infinitely many solutions, and one of them is (9, -3/4).

To have a system of linear equations with infinitely many solutions, the two equations must represent the same line. Therefore, we need to obtain a second equation that has the same slope and y-intercept as 2x + 8y = 12.Here's how we can do that:2x + 8y = 12 is equivalent to 2(x + 4y) = 12, which reduces to x + 4y = 6.To create a second equation that represents the same line, we can multiply this equation by a constant, say 2, which gives us:2(x + 4y) = 12 (original equation)2x + 8y = 12 (distribute 2 on the left side)4x + 16y = 24 (multiply both sides by 2)Dividing both sides by 4, we get x + 4y = 6, which is the same as the first equation. Therefore, the system of equations is:2x + 8y = 124x + 16y = 24This system of equations is consistent and has infinitely many solutions because the two equations are equivalent and represent the same line, and every point on this line satisfies both equations.The solution to this system can be found using either equation by solving for one variable in terms of the other and substituting into either equation. For instance, we can solve for y in terms of x as follows:x + 4y = 6 => 4y = 6 - x => y = (6 - x)/4Substituting this expression for y into the first equation gives us:2x + 8((6 - x)/4) = 122x + 2(6 - x) = 1230 - 2x = 12 => 2x = 18 => x = 9Substituting x = 9 into y = (6 - x)/4 gives us:y = (6 - 9)/4 = -3/4Therefore, the system has infinitely many solutions, and one of them is (9, -3/4).

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Answer:

I’ve got a level 4 in pre algebra state test so this should be simple

Step-by-step explanation:

in order to convert this just Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 1010. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

the answer would be: 1.716×10^11

And this is positive and not negative

Yes, you are correct. An equation in n variables is linear if it can be written in the form:

a1x1 + a2x2 + ... + an*xn = b

where a1, a2, ..., an are constants and x1, x2, ..., xn are variables. In this equation, each variable x appears with a coefficient a that is a constant multiplier.

Additionally, the variables can only appear to the first power; that is, there are no higher-order terms such as x^2 or x^3.

The equation is called linear because the relationship between the variables is linear; that is, the equation describes a straight line in n-dimensional space.

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The correct Cartesian equation is 5y^(4)(x^(2)+y^(2))=7x^(2).


To convert the given polar equation r = 7sinθ/5cos^(2)θ into a Cartesian equation, we can use the following relationships:
x = rcosθ
y = rsinθ
r^2 = x^2 + y^2

First, let's rewrite the polar equation as:
r = (7sinθ)/(5cos^(2)θ)

Now, multiply both sides by r:
r^2 = (7sinθr)/(5cos^(2)θ)

Substitute x = rcosθ and y = rsinθ:
x^2 + y^2 = (7y)/(5x^2)

Next, multiply both sides by 5x^2:
5x^2(x^2 + y^2) = 7y

Finally, rearrange the equation to match the given answer choices:
5y^(4)(x^(2)+y^(2)) = 7x^(2)

After converting the polar equation into a Cartesian equation, the correct answer is 5y^(4)(x^(2)+y^(2))=7x^(2).

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If the slope of "fitted-line" is given to be 8.42, then the correct interpretation is Option(c), which states that "On average, every $1 million increase in salary is linked with 8.42 point increase in "winning-percentage".

The "Slope" of the "fitted-line" denotes the change in response variable (which is winning percentage in this case) for "every-unit" increase in the predictor variable (which is salary of head coach, in millions of dollars).

In this case, the slope is 8.42, which means that on average, for every $1 million increase in salary of "head-coach", there is an increase of 8.42 points in "winning-percentage".

Therefore, Option (c) denotes the correct interpretation of slope.

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The given question is incomplete, the complete question is

Abigail gathered data on different schools' winning percentages and the average yearly salary of their head coaches (in millions of dollars) in the years 2000-2011. She then created the following scatterplot and regression line.

The fitted line has a slope of 8.42.

What is the best interpretation of this slope?

(a) A school whose head coach has a salary of $0, would have a winning percentage of 8.42%,

(b) A school whose head coach has a salary of $0, would have a winning percentage of 40%,

(c) On average, each 1 million dollar increase in salary was associated with an 8.42 point increase in winning percentage,

(d) On average, each 1 point increase in winning percentage was associated with an 8.42 million dollar increase in salary.

a. Adding a control group in the design of this study would provide a baseline for comparison, as it would receive no treatment or a placebo.

b. The experimental design for this study would look like this:

Group 1: Glucosamine Treatment (100 Dogs)

Group 2: Chondroitin Treatment (100 Dogs)

Group 3: Control Group (100 Dogs)

c. Blocking on clinics would be a better variable to use as a blocking variable because dogs from the same clinic are likely to be more similar to each other in terms of environmental factors than dogs from different clinics, allowing for better control of environmental factors.

a. Adding a control group in the design of this study would provide a baseline for comparison, as it would receive no treatment or a placebo. This would allow researchers to determine if any observed changes in joint and hip health are due to the supplements or simply due to natural variations over time.

b. To assign the 300 dogs to three groups for a completely randomized design, the following steps could be taken:

Number the 300 dogs from 1 to 300.

Use a random number generator to assign each dog to one of three groups: glucosamine, chondroitin, or control.

Divide the 300 dogs into three equal-sized groups of 100 dogs each.

Administer the appropriate treatment to each group for six months.

Evaluate changes in joint and hip health after six months of treatment.

The experimental design for this study would look like this:

Group 1: Glucosamine Treatment (100 Dogs)

Group 2: Chondroitin Treatment (100 Dogs)

Group 3: Control Group (100 Dogs)

c. Blocking on clinics would be a more appropriate variable to use for blocking than breed of dog.

This is because dogs from the same clinic are likely to be more similar to each other in terms of environmental factors, such as diet and exercise, than dogs from different clinics.

Therefore, by blocking on clinics, researchers can reduce the effects of these environmental factors and better isolate the effects of the supplements on joint and hip health.

In contrast, blocking on breed of dog may not be as effective since dogs of the same breed can come from different clinics and have different lifestyles, making it harder to control for environmental factors.

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The value of the degrees of freedom for a two-mean pooled t-test with samples of size 15 and 32 is 45.

The degrees of freedom for a two-mean pooled t-test can be calculated using the formula:

df = (n1 - 1) + (n2 - 1)

Substituting n1 = 15 and n2 = 32, we get:

df = (15 - 1) + (32 - 1) = 14 + 31 = 45

Therefore, the value of the degrees of freedom for a two-mean pooled t-test with samples of size 15 and 32 is 45.

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The expected rate of return for the portfolio is calculated as follows:

(18% * 0.70) + (12% * 0.30) = 12.6% + 3.6% = 16.2%.

To compute the expected rate of return for a portfolio, we need to consider the expected return and weight of each stock in the portfolio. The expected return represents the anticipated return for each stock, while the weight represents the proportion of the portfolio's total value allocated to each stock.

In this case, Stock A has an expected return of 18% and a weight of 0.70, meaning it accounts for 70% of the portfolio's total value. Stock B, on the other hand, has an expected return of 12% and a weight of 0.30, accounting for 30% of the portfolio's total value.

To calculate the expected rate of return for the portfolio, we multiply the expected return of each stock by its respective weight. For Stock A, the calculation is 18% * 0.70 = 12.6%, and for Stock B, it is 12% * 0.30 = 3.6%.

Finally, we sum up the results of these calculations: 12.6% + 3.6% = 16.2%. Therefore, the expected rate of return for the two-stock portfolio is 16.2%.

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The Cartesian equation of the curve is y = -4x + 9 for -1 ≤ x ≤ 4.

To eliminate the parameter t, we can isolate t in the equation x = t^2 - 2 and substitute it into the equation for y. This gives us:

y = t + 1

t = x + 2

y = x + 3

So the Cartesian equation of the curve is y = x + 3 for -2 ≤ y ≤ 4.

We can eliminate t by taking the natural logarithm of both x and y. This gives us:

ln x = t - 8

ln y = 2t

Solving for t in the first equation and substituting it into the second equation, we get:

t = ln(x) + 8

y = e^(2ln(x)+16) = x^2e^16

So the Cartesian equation of the curve is y = x^2e^16.

To eliminate t, we can again isolate it in the equation for x and substitute it into the equation for y. This gives us:

x = t + 1

t = x - 1

y = 5 - 4(x - 1) = -4x + 9

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The Cartesian equation of the curve is y = 1 - 4x, for -1 ≤ x ≤ 4.

To eliminate the parameter t, we can solve for t in terms of x and substitute it into the equation for y:

t = ±√(x + 2)

y = t + 1 = ±√(x + 2) + 1

Squaring both sides and simplifying, we get:

(x + 2) = (y - 1)²

So the Cartesian equation of the curve is:

x = (y - 1)² - 2, for -2 ≤ y ≤ 4.

To eliminate the parameter t, we can take the natural logarithm of both sides of the equation for y:

ln y = 2 ln e + t ln e = 2 ln e + ln x

ln y = ln (xe²)

y = xe²

So the Cartesian equation of the curve is:

y = x^2e^2.

To eliminate the parameter t, we can solve for t in terms of x and substitute it into the equation for y:

t = 1 + x

y = 5 - 4t = 1 - 4x

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The equation of the circle with center at (-7, 1) and radius of 11 is (x + 7)² + (y - 1)² = 121.

To find the equation of a circle with a given center and radius, we use the standard form equation of a circle:

(x - h)² + (y - k)² = r²

where (h, k) is the center of the circle and r is the radius.

In this case, the center is given as (-7, 1) and the radius is 11. So we substitute these values into the standard form equation and simplify:

(x - (-7))² + (y - 1)² = 11²

(x + 7)² + (y - 1)² = 121

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The perimeter of the composite figure is 62 cm, rounded to the nearest hundredth.

A composite figure is a figure made up of two or more shapes that are combined. The perimeter is the total length of the outline of a shape. The perimeter of the composite figure is the sum of the lengths of the sides that make up the composite figure.

To find the perimeter of a composite figure, we need to add the length of each side of all the figures. To find the perimeter of the composite figure, we will first calculate the perimeter of the square and then add the perimeter of two triangles.

We will use the formula:perimeter of a square = 4s, where s = side of the squareWe know that the side of the square = 7 cm

Therefore, the perimeter of the square = 4 × 7 cm = 28 cmNow, let's calculate the perimeter of the triangle. To find the perimeter of a triangle, we need to add the length of all its sides.We know that the side of the triangle = 3 cm

Therefore, the perimeter of one triangle = 3 + 7 + 7 = 17 cmAs there are two triangles, we need to multiply this by 2:Perimeter of two triangles = 2 × 17 cm = 34 cm

Now, let's add the perimeter of the square and two triangles:Perimeter of the composite figure = 28 cm + 34 cm = 62 cm

Therefore, the perimeter of the composite figure is 62 cm, rounded to the nearest hundredth. Answer:perimeter = 62 cm

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Carla will run on Sunday, November 12 and then run and swim on Thursday, November 16.

Carla runs every 3 days and swims every Thursday.

Carla ran and swam on Thursday 9 November.

The next time Carla will run will be 3 days later: Sunday, November 12.

The next Thursday after November 9 is November 16.

Therefore, Carla will run on Sunday, November 12 and then run and swim on Thursday, November 16.

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The answer is , This is a linear function, where the slope is -50 and the y-intercept is 82.  And the domain is  z ≥ 0.

The function that gives the daily profit for selling z shirts can be found using the formula f(x) = 82 – 50z.

This is a linear function, where the slope is -50 and the y-intercept is 82.

To find and interpret the given function values, we can substitute different values of z into the equation f(z) = 82 – 50z.

For example: If the company sells 0 shirts, the profit would be:

f(0) = 82 – 50(0) = $82

This means that the company would make $82 in profit even if they didn't sell any shirts.

If the company sells 1 shirt, the profit would be:

f(1) = 82 – 50(1) = $32

This means that the company would make $32 in profit if they sold one shirt.

Each additional shirt sold would result in a decrease of $50 in profit because the slope of the function is -50.

Therefore, if the company sold 2 shirts, they would make $32 – $50 = -$18 in profit, which means they would be operating at a loss.

The appropriate domain for this function is any non-negative value of z, because the company cannot sell a negative number of shirts.

So the domain is: z ≥ 0.

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The area bounded by f(x) = √x and g(x) = x/2 on the interval [0,16] is 64.

To find the area bounded by the given functions, we need to determine the points of intersection. Setting f(x) = g(x), we get:

√x = x/2

Squaring both sides, we get:

x = 0 or x = 16

So the points of intersection are (0,0) and (16,8).

Next, we need to determine which function is on top in the interval [0,16]. We can do this by comparing the values of the two functions at x = 8, which lies in the middle of the interval. We have:

f(8) = √8 = 2√2

g(8) = 8/2 = 4

Since f(8) < g(8), the function g(x) is on top in the interval [0,16]. Therefore, the area bounded by the two functions is given by:

∫[0,16] (g(x) - f(x)) dx

= ∫[0,16] (x/2 - √x) dx

= [x^2/4 - (2/3)x^(3/2)] [0,16]

= (16^2/4 - (2/3)16^(3/2)) - (0 - 0)

= 64

Hence, the area bounded by the two functions is 64.

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Answer:

y=-4x

Step-by-step explanation:

The solution is: the volume of the soup can is 311.01 cm³.

Here,

we know that

the volume of the soup can =pi*r²*h

here, we get,

diameter=6 cm

---------->

so, radius is:

r=6/2

-----> r=3 cm

h=11 cm

so, we get,

the volume of the soup can

=3.14*3²*11

-----> 311.01 cm³

Hence, The solution is: the volume of the soup can is 311.01 cm³.

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The radius of the cone-shaped hole is approximately 4.08 ft.

Given that the volume of a cone-shaped hole is 50π ft³ and the depth of the hole is 9 ft, we need to find the radius of the cone-shaped hole.

To find the radius of the cone-shaped hole, we'll use the formula for the volume of a cone.

V = (1/3)πr²h

Where V = Volume, r = Radius, h = Height

So, the radius of the cone-shaped hole can be calculated as follows:

Volume of the cone = 50π ft³

Height of the cone = 9 ft

V = (1/3)πr²h50π

= (1/3)πr²(9)

Multiplying both sides by 3/π, we get:

150 = r²(9)r²

= 150/9r²

= 16.67 ft²

Taking the square root of both sides, we get:

r = 4.08 ft

Therefore, the radius of the cone-shaped hole is approximately 4.08 ft.

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To find the slope-intercept form of the equation of the line passing through the point (4, 7) and parallel to the line 2x + 3y = 11, we need to first find the slope of the given line.

Rearranging the equation 2x + 3y = 11 into slope-intercept form gives:

3y = -2x + 11

y = (-2/3)x + 11/3

So the slope of the given line is -2/3.

Since the line we want to find is parallel to this line, it will have the same slope. Using the point-slope form of the equation of a line:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is a point on the line, we can substitute in the given point (4, 7) and the slope -2/3:

y - 7 = (-2/3)(x - 4)

Expanding the right-hand side gives:

y - 7 = (-2/3)x + 8/3

Adding 7 to both sides gives:

y = (-2/3)x + 29/3

So the equation of the line passing through the point (4, 7) and parallel to the line 2x + 3y = 11 in slope-intercept form is y = (-2/3)x + 29/3.

Answer:Supplementary

Step-by-step explanation:

They add to 180, making them supplementary.