Can someone answer this question

Answer:

A. [tex] 8x\sqrt{5} [/tex]

Step-by-step explanation:

Given:

[tex] \sqrt{45x^2} + \sqrt{5x^2} + 4x\sqrt{5} [/tex]

Required:

Simplify

[tex] \sqrt{9*5*x^2} + \sqrt{5*x^2} + 4x\sqrt{5} [/tex]

[tex] 3x\sqrt{5} + x\sqrt{5} + 4x\sqrt{5} [/tex]

Add like terms

[tex] 8x\sqrt{5} [/tex]

Answer:

4xy^2√2x

Step-by-step explanation:

Answer:

4xy²[tex]\sqrt{2x}[/tex]

Step-by-step explanation:

√32x³y^4 can be broken down to:

√4√4√2√x²√y²√y²√x which can be simplified to be:

4xy²√2x

Answer:

(A) true.

(B). False.

Step-by-step explanation:

(A). F(x) = 4xe^-2x.

Let's make the assumption that 2x = b -----------------------(1).

Therefore, taking the differentiation with respect to x, we have;

2x dx = db.

The next thing thing to do is to integrate, taking the upper limit to be infinity and the lower limit to be zero:

∫( b e^-b db).

Changing the Lim. infinity = 2.

= ∫( b e^-b db). ----------------------------(2).

The step (2) above can be solve with Integrations by part;

Lim. 2 ---> infinity [ b e^-b + ∫( 1 e^-b db|

( | = Upper boundary = 2 and the lower boundary = 0).

Lim. 2 ----> infinity [ 2 e^-2 - 0] - lim. 2 --> infinity [ 0 - 1].

Lim 2 ---> infinity [ 2/e^2 + 1].

Let 2/e^2 = j.

The, lim 2 ---> infinity j + 1.

To solve this, there is need to make use of L'hospital rule,

j = Lim 2 ---> infinity [ 1 /e^2] = 0.

Thus, j = 0. And 0 + 1 = 1.

(PROVED TO BE TRUE).

(B). Taking limit from 1 (upper) to 0( lower). Assuming that b = 3 - 4x.

Therefore, -4dx = db.

∫( 8 /(3 - 4x)^3 dx.

Taking the upper boundary = -1 and the lower boundary = 3.

∫ ( - 2db/ b^3.

= 2 ∫ ( - db/ b^3.

= 2 [ b^-3 + 2) / -3 + 1.

= 2 | - 1/ 2 db

= 8/9.

Not true.

:

Knowing the average monthly rainfall for a location is helpful when you're packing for a ... Add together all of the monthly rainfall totals in your sample data. ... in inches because rainfall is generally measured in inches in the United States. ... is to maintain the linear relationship of the formula, since there is no 0 BC or 0 AD

Answer:

(1,1)

Step-by-step explanation:

Answer:

Draw a box and split it into four pieces. Write 4 in each of those pieces. Put a "{" or "}" around 3 of them. Next to it write. 4 x 3 OR 4 + 4 + 4 = 12

Step-by-step explanation:

Draw a box and split it into four pieces. Write 4 in each of those pieces. Put a "{" or "}" around 3 of them. Next to it write. 4 x 3 OR 4 + 4 + 4 = 12

Hope that helps!

Answer:

n = -5/2d   or  d = -5n/2

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

We can have any. two numbers that represent a and b

It CANT BE THIS FOLLOWING

A AND B CANT BE ZERO SO WE CAN USE MULTIPLES OF 10

A CANT BE EQUAL TO B SO WE CANT USE MULTIPLES OF 11( ALL THE WAY UP TO 99 BUT WE CANT USE ANY NUMBER AFTER THAT SINCE NUMBERS THAT COME AFTER 99 ARE THREE DIGIT NUMBER)

Let use 5 and 6.

56

Reverse the digits

65

add 56 to 65

121

Divide this by 6+5=11

The answer is 11 This vary for all answers let use 1,7

17 then reverse

71 then add 71 and 17

88 then divide by 1+7=8

11

The quotient is 11.

Step-by-step explanation:

Given:

A two-digit number,'ab'.

Where a and b are non-zero and are unequal to each other.

To find:

Quotient after dividing the sum of the given digit and its reverse with(a+b).

Solution:

The given digit = [tex]ab = (10a+b)[/tex]

[tex]Where:\\a \neq b, a\neq 0,b\neq 0[/tex]

On reversing the given digit =[tex]ba = (10b +a)[/tex]

Now adding the given digit and its reverse:

[tex]= ab +ba = (10a+b)+(10b+a)\\=(11a+11b)=11(a+b)[/tex]

Diving the sum with (a+b):

[tex]=\frac{11(a+b)}{(a+b)}=11[/tex]

The quotient is 11.

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Using the z-distribution, we have that:

a) The confidence interval is: (24.33%, 30.37%).

b) The correct option is: No, the confidence interval includes 0.25, so the true percentage could easily equal 25%.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.

The other parameters are given as follows:

[tex]n = 427 + 161 = 588, \pi = \frac{161}{588} = 0.2735[/tex]

Then the bounds of the interval are:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2735 - 1.645\sqrt{\frac{0.2735(0.7265)}{588}} = 0.2433[/tex]

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2735 + 1.645\sqrt{\frac{0.2735(0.7265)}{588}} = 0.3037[/tex]

As a percentage, the interval is: (24.33%, 30.37%).

25% is part of the interval, hence the correct statement is:

No, the confidence interval includes 0.25, so the true percentage could easily equal 25%.

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Based on the various meals offered by the catering service, the ways that the order can be done is 6,930 ways..

This can be found as:

= (11! / (9!2!)) x (7! / (5!2!)) x (4! / (2!2!)

= 55 x 21 x 6

= 6,930 ways

In conclusion, the order can be made in 6,930 ways.

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Answer:

∠AFB = Acute

∠DFB = Obtuse

∠CFD = Right

Step-by-step explanation:

∠AFB is acute b/c its less than 90°

∠DFB is obtuse b/c it more than 90°

∠CFD is right b/c it's exactly 90°

Answer:

Fountain= 147.65 square yards

path= 28.28 square yards

Step-by-step explanation:

pi*47 <---square root cancels out the square

=147.65

pi*56=175.93

175.93-147.65=28.28

The true statement about the diagram is (a) IJ ≅ JG

From the question, we understand that:

KH bisects line IG at point J

This means that:

Line segment IG is divided into two equal parts, and point J is the middle

So, we have:

IJ ≅ JG

Hence, the true statement about the diagram is (a) IJ ≅ JG

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The equation that shows a pair of equivalent ratios that can be used to find the unknown is [tex]\frac{22}{1} =\frac{x}{3}[/tex]

From the question, we are to determine which equation shows a pair of equivalent ratios that can be used to find the unknown

In the given table, the unknown is x

Consider the given values in the table,

The equation that shows a pair of equivalent ratios that can be used to find the unknown is

[tex]\frac{22}{1} =\frac{x}{3}[/tex]

Hence, the equation that shows a pair of equivalent ratios that can be used to find the unknown is [tex]\frac{22}{1} =\frac{x}{3}[/tex]

Here is the complete question:

A car travels 22 miles for every gallon of gasoline used. The table below represents this relationship. Gas Mileage Distance Traveled (miles) Gasoline Used (gallons) 22 1 44 2 x 3 88 4. Which equation correctly shows a pair of equivalent ratios that can be used to find the unknown.

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Answer: x = 20/3 = 6.667

Step-by-step explanation:

 Solve  :    3x-20 = 0

Add  20  to both sides of the equation :

                     3x = 20

Divide both sides of the equation by 3:

                    x = 20/3 = 6.667

Answer:

id

Step-by-step explanation:

Answer:

0.052

Step-by-step explanation:

[tex]P=\frac{4}{77}=.052[/tex]

Using the normal distribution, there is a 0.0781 = 7.81% probability that a randomly selected cyclist will take between 2.35 and 2.45 hours to complete the race.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation are given, respectively, by:

[tex]\mu = 2.5, \sigma = 0.5[/tex].

The probability that a randomly selected cyclist will take between 2.35 and 2.45 hours is the p-value of Z when X = 2.45 subtracted by the p-value of Z when X = 2.35, hence:

X = 2.45:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{2.45 - 2.5}{0.5}[/tex]

Z = -0.1

Z = -0.1 has a p-value of 0.4602.

X = 2.35:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{2.35 - 2.5}{0.5}[/tex]

Z = -0.3

Z = -0.3 has a p-value of 0.3821.

0.4602 - 0.3821 = 0.0781.

0.0781 = 7.81% probability that a randomly selected cyclist will take between 2.35 and 2.45 hours to complete the race.

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Answer: pretty sure

There were 108 children and 175 adults.

Answer:

3/2x²+28x+130

Step-by-step explanation:

Area of shaded region = Area of rectangle – Area of triangle

Area of rectangle:

[tex](2x + 15)(x + 10) = \\2x {}^{2} + 35x + 150[/tex]

Area of triangle:

[tex] \frac{1}{2 } \times (x + 4)(x + 10) = \\ \frac{1}{2} x {}^{2} + 7x + 20[/tex]

then subtract

Answer:

You can't simplify 9/2, but 9/2 as a mixed number is 4 1/2

hope this helped

Step-by-step explanation:

Answer:

You can't simplify 9/2, but 9/2 as a mixed number is 4 1/2

Step-by-step explanation:

Answer:

the ans is 9000

Step-by-step explanation:

simple interest= 60000*3*5/100

Answer:

3/10

Step-by-step explanation:

Just multiply all of the numerators (top numbers)  and then multiple all of the denominators (bottom numbers)

2/3x3/4x3/5  would be 18/60 Then take any number that is a factor to both 18 and 60 and divide both numbers by that factor.  I could use 2 or 3 or 6 because both 18 and 60 is divisible by any of these numbers.  I will choose 3.  I will divide the top and bottom of 18/60 by 3 to get 6/20, now I will divide the top and bottom of that number by 2 to get 3/10

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Equation:}[/tex]

[tex]\mathsf{\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{3}{5}}[/tex]

[tex]\huge\textbf{Simplifying:}[/tex]

[tex]\mathsf{\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{3}{5}}[/tex]

[tex]\mathsf{= \dfrac{2\times3\times3}{3\times4\times5}}[/tex]

[tex]\mathsf{= \dfrac{6\times3}{12\times5}}[/tex]

[tex]\mathsf{= \dfrac{18}{60}}[/tex]

[tex]\mathsf{= \dfrac{18\div3}{60\div 3}}[/tex]

[tex]\mathsf{= \dfrac{6}{20}}[/tex]

[tex]\mathsf{= \dfrac{6\div2}{20\div2}}[/tex]

[tex]\mathsf{= \dfrac{3}{10}}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\frak{\dfrac{3}{10}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

The equation for the height exists h = 31 sin((8π)t + π/2) + 35.

The model for the height can be emanated from the general formula of the sine function, then

y = A sin(Bt - C) + D

Maximum point = 70 - 4 = 66 at t = 0

Minimum point = 4

Amplitude, A = (66 - 4) ÷ 2 = 31

D = 4 + 31 = 35

At t = 0, we have;

66 = 31 × sin(B × 0 - C) + 35

31 = 31 × sin(- C)

sin(- C) = 1

C = -π/2

1 minute = 60 seconds

1 second = 1 minute/60

15 seconds = (15/60) minutes

Period = 15 seconds = 15/60 minutes

Period = 2π/B

Therefore, 15/60 = 2π/B

1/4 = 2π/B

B = 2π/(1/4) = 8π

y = Height of the function

Let h denote the height of the wristband.

The equation for the height exists h = 31 sin((8π)t + π/2) + 35.

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Answer: The probability of rolling a 2 on a 6-sided die is 1/6.

Step-by-step explanation:

The probability of getting 2 on the die P(2) is 1/6.

Probability is the chance of occurrence of a certain event out of the total no. of events that can occur in a given context.

Given, We roll a six-sided die,

So, Sample space N(S) = 1, 2, 3, 4, 5, 6 = 6.

N(2) = 1

∴ The probability of getting the number 2 when we throw a die is

P(2) = N(2)/N(S).

P(2) = 1/6.

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Answer:

1

Step-by-step explanation:

This is a U shaped graph, so the shape is a parabola

Eccentricity of any parabola is 1.

Answer:

Step-by-step explanation:

Just for some extra confrontation indeed the correct answer is 1.

Answer:

breadth: 15, area: 525

Step-by-step explanation:

Answer:

Breadth = 15cm

Area = 525cm^2

Step-by-step explanation:

We know that the perimeter of a rectangluar sheet is 100cm, and we know that the length is 35cm. We are then being asked to find the breadth and the area.

Use the information that we know to solve the breadth, get b alone :

Length = 35cm

2(l + b) = 100

Substitute :

2(35 + b) = 100

Divide 2 from both sides :

35 + b = 50

Subtract 35 from both sides :

b = 15cm

Now for the area :

Area = Length * Breadth

Substitute :

A = 35 * 15

A = 525cm^2

I got 70

Combination=n!/((n-r)!r!)

=8!/((8-4)!*4!)

=8*7*6*5*4!/(4!*4!)

=8*7*6*5/(4*3*2)

=70 ways