Step-by-step explanation:
[tex]\frac12(8k+12k^2+6k^3)\\=4k+6k^2+3k^3\\[/tex]
Rearrange into descending order:
[tex]\boxed{3k^3+6k^2+4k}[/tex]
A number line shows 115, −225, and −135. Which statement is NOT true?
CLEAR CHECK
115<−225 because 11 5 is located to the right of −225 on the number line.
115 > −135 because 115 is located to the right of −135 on the number line.
−225 < −135 because −135 is located to the right of −225 on the number line.
115 > −225 because 115 is located to the right of −225 on the number line.
The statement 115 < -225 because 115 is located to the right of -225 on the number line is not true.
What is a number line?The horizontal straight lines in mathematics known as number lines are where integers are arranged in equal intervals. A number line can be used to represent every number in a sequence. This line continues forever at both ends.
On a number line as we go from left to right the numbers increase. For the given numbers, 115 > -135> -225 as 115 is located on the right of the number line.
Hence, statement one 115 < -225 because 115 is located to the right of -225 on the number line is not true.
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Is it possible to draw a triangle the length of whose sides are 2.5 cm 4.2 cm 8 cm?
No, it is not possible to draw a triangle with side lengths of 2.5 cm, 4.2 cm, and 8 cm.
The triangle inequality theorem states that for any triangle, the sum of the lengths of the two shorter sides must be greater than the length of the longest side.
In other words, for a triangle with sides of lengths a, b, and c, where c is the longest side, the following must be true: a + b > c, b + c > a, and a + c > b.
In the case of the triangle with side lengths of 2.5 cm, 4.2 cm, and 8 cm, the sum of the lengths of the two shorter sides (2.5 cm + 4.2 cm) is 6.7 cm, which is less than the length of the longest side (8 cm).
Therefore, it is not possible to form a triangle with these side lengths, as the triangle inequality theorem is not satisfied.
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The curve C has equation x= cos2y/e^y. Find the equation of the tangent to the curve at the point where y=π/8 in the form ax+by+c=0
[tex]x=\cfrac{cos(2y)}{e^y}\hspace{5em}x\left( \frac{\pi }{8} \right)=\cfrac{1}{e^{\frac{\pi }{8}}\sqrt{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{dx}{dy}\implies \stackrel{quotient~rule}{\cfrac{-2sin(2y)e^y-cos(2y)e^y}{(e^y)^2}}\implies \cfrac{-2sin(2y)-cos(2y)}{e^y} \\\\[-0.35em] ~\dotfill\\\\ \left. \cfrac{dx}{dy} \right|_{y=\frac{\pi }{8}}\implies \cfrac{-2sin(\frac{\pi }{4})-cos(\frac{\pi }{4})}{e^y}\implies \cfrac{-3}{e^{\frac{\pi }{8}}\sqrt{2}}\impliedby m[/tex]
now, since we have the value of "x" at π/8 and we know that at that point y = π/8, and we also have the slope at π/8, let's plug all those fellows in the point-slope formula
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\cfrac{\pi }{8}~~ = ~~\cfrac{-3}{e^{\frac{\pi }{8}}\sqrt{2}}\left(x-\cfrac{1}{e^{\frac{\pi }{8}}\sqrt{2}} \right)[/tex]
[tex]y-\cfrac{\pi }{8}~~ = ~~\cfrac{-3}{e^{\frac{\pi }{8}}\sqrt{2}}x+\cfrac{3}{2e^{\frac{\pi }{4}}} \implies \boxed{\cfrac{3}{e^{\frac{\pi }{8}}\sqrt{2}} {\Large \begin{array}{llll} x \end{array}} + {\Large \begin{array}{llll} y \end{array}}-\cfrac{\pi }{8}-\cfrac{3}{2e^{\frac{\pi }{4}}}~~ = ~~0}[/tex]
1. Finish Problem 1 From The 3.2 Worksheet That Is, Find X And Y Values That Are In The Feasible Region And That Give The Best
The optimal values of x and y to maximize the profit are 10 and 10, respectively, and the maximum profit is $200.
Let X and Y represent the number of units of product A and B that we want to produce. We want to maximize the profit, so our objective function is:
Profit = 10x + 15y
The constraints are:
X + Y ≤ 20
2X + Y ≤ 30
X ≥ 0, Y ≥ 0
To find the optimal values of x and y, we must first solve the system of equations. By subtracting the first equation from the second equation, we get:
X = 10
Substituting this value into the first equation, we get:
Y = 10
Now that we have found the values of x and y, we can plug them into the objective function to find the maximum profit:
Profit = 10(10) + 15(10) = 200
Therefore, the optimal values of x and y to maximize the profit are 10 and 10, respectively, and the maximum profit is $200.
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find the value of X.
-1. x ÷ 5/6 = 1 and 4/5
-2. x ÷ 2 and 1/10 = 1 and 2/3
ILL GIVE 40 POINTS JUST HELP PLEASE
the values of x will be:
x = 1.5x = 3.5What is simplification?Simplifying procedures is one way to achieve uniformity in job efforts, expenses, and time. It reduces diversity and variation that is pointless, harmful, or unneeded. Parenthesis, exponents, multiplication, division, addition, and subtraction are all referred to as PEMDAS. The order of the letters in PEMDAS informs you what to calculate first, second, third, and so on, until the computation is finished, given two or more operations in a single statement.
Given, Two functions, " x ÷ 5/6 = 1 and 4/5" and " x ÷ 2 and 1/10 = 1 and 2/3"
For x ÷ 5/6 = 1 and 4/5
Simplifying the value,
x ÷ 5/6 = 1 4/5
x ÷ 5/6 = 9/5
x ÷ 5/6 = 9/5
Cross multiply
x = 9/5 * 5/6
x = 1.5
For x ÷ 2 and 1/10 = 1 and 2/3
Simplifying the value,
x ÷ 2 1/10 = 1 2/3
x ÷21/10 = 5/3
x = 3.5
Therefore, the values of x will be:
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You know the following information about triangle ABC and triangle DEF:
AB = DE
∠A ≅ ∠D.
What additional information is needed to prove that the triangles are congruent by SAS?
Responses
A AB = DEAB = DE
B ∠B ≅ ∠E∠B ≅ ∠E
C AC = DFAC = DF
D BC = EF
The △ABC and △DEF are congruent by SAS if BC = EF. Hence option D is the correct option.
What are congruent triangles?
If all three corresponding sides are equal and all three corresponding angles are identical in measure, two triangles are said to be congruent. These triangles can be moved, rotated, flipped, and turned to look exactly the same. They coincide if they are relocated. ' is the symbol of congruence.
Given that in △ABC and △DE:
AB = DE
∠A ≅ ∠D
SAS rule: Two triangles are congruent if two sides and an included angle of one triangle are equivalent to two sides and an included angle of the second triangle.
The opposite side of ∠A is BC and the opposite side ∠D is EF.
Thus the additional information, that is needed is BC = EF.
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A recipe call for 2 cup of almond for 5 cup of flour. Uing the ame recipe, how many cup of flour will you need for 3 cup of almond
Number of cups of flour required to make the same recipe for 3 cups of almond as per the given relation is equal to 7.5 cups of flour.
As given in the question,
For the given recipe cups of flour and cups of almond given is :
2 cups of almond used for 5 cups of flour
The relation is written in the form of expression :
2 cups of almond = 5 cups of flour
⇒ 1 cups of almond = ( 5 / 2 ) cups of flour
⇒ 3 cups of almond = [ ( 5 / 2 ) × 3 ] cups of flour
⇒ 3 cups of almond = ( 15 / 2 ) cups of flour
⇒ 3 cups of almond = 7.5 cups of flour
Therefore, the cups of flour required for 3 cups of almond is equal to 7.5 cups of flour.
The above question is incomplete , the complete question is :
A recipe call for 2 cup of almond for 5 cup of flour. Using the same recipe, how many cup of flour will you need for 3 cup of almond?
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Camille is sixty-six inches tall. This is twenty inches less than two times Mindy's height. How tall is Mindy ?
Let's call Mindy's height "M". According to the problem, we know that:
Camille's height = 66 inches
Camille's height = 2 * Mindy's height - 20 inches
We can substitute the first equation into the second equation to solve for Mindy's height:
66 inches = 2 * M - 20 inches
We can add 20 inches to both sides of the equation to get:
66 inches + 20 inches = 2 * M
This gives us:
86 inches = 2 * M
To find Mindy's height, we can divide both sides of the equation by 2:
M = 86 inches / 2
So Mindy is 43 inches tall.
Answer:
Mindy is 46 inches
Step-by-step explanation:
Let m = Mindy's height
66 = 2m - 20 Add 20 to both sides
66 + 20 = 2m - 20 + 20
86 = 2m Divide both sides by 2
[tex]\frac{86}{2}[/tex] = [tex]\frac{2m}{2}[/tex]
46 = m
The table of values represents a continuous function.
x
one ninth
one third
1
3
9
27
81
g(x)
–2
–1
0
1
2
3
4
Which type of function describes g(x)?
Rational
Polynomial
Logarithmic
Exponential
The type of function that represents function g(x) is given as follows:
Logarithmic.
How to define the function?To define the function in this problem, we must observe a pattern with the inputs and the outputs.
The input and output pairs are given as follows:
Input of 1/9 mapped to an output of -2.Input of 1/3 mapped to an output of -1.Input of 1 mapped to an output of 0.Input of 3 mapped to an output of 1.Input of 9 mapped to an output of 2.Input of 27 mapped to an output of 3.Input of 81 mapped to an output of 4.From the pattern, we can see that each output is obtained as the power of 3 to which the input is elevated.
This means that the function is a logarithmic function, more specifically the logarithm of base 3 of x.
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Find the measures of
An irregular hexagon V Y W U Z X. Angles Y and X are congruent angles. Angles V, W, U and Z are labeled 100 degrees, 110 degrees, 149 degrees, and 91 degrees respectively.
M
M
The measure of congruent angles X and Y of the hexagon are 135.
What are congruent angles?Two or more angles must be identical to one another to be considered congruent. As a result, these angles are of equal proportion. They can be acute, obtuse, exterior, or interior angles because the congruence of angles is unaffected by the type of angle.Only when the angle measures are the same can two angles be said to be congruent.It doesn't matter how long or which way the two arms are pointing to create these congruent angles.let the measure of the congruent angles of X and Y be a
Then by the angle sum property of a hexagon sum of all the angle will be
U +V +W +X +Y +Z = 720
then 100 + 110+ 149 + 91 + a + a =720
2a = 720 - 450
2a = 270
Then a = 135
Hence the congruent angles X and Y are 135.
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What is 0 with an exponent of 0?
Answer
0^0 =1
or
0^0 can be undefined.
Dana and monique are dog grooms dogs 4 days a week. Monique grooms dogs 5 days a week. they each earn $12.75 per dog they groom.Each day she works, Dana grooms 15 dogs and Monique grooms 10 dogs each day she works. what is the difference in their weekly earnings
Difference in the weekly earnings of Dana and Monique is $127.5.
What is Multiplication?Multiplication of two numbers is defined as the addition of one of the number repeatedly until the times of the other number.
a × b means that a is added to itself b times or b is added to itself a times.
Dana :
Number of days Dana grooms dogs = 4 days a week
Number of dogs Dana grooms in a day = 15 dogs
Number of dogs Dana grooms in a week = 15 × 4 = 60 dogs
Earning of Dana per dog = $12.75
Earnings of Dana in a week = 60 × $12.75 = $765
Monique :
Number of days Monique grooms dogs = 5 days a week
Number of dogs Monique grooms in a day = 10 dogs
Number of dogs Monique grooms in a week = 10 × 5 = 50 dogs
Earning of Monique per dog = $12.75
Earnings of Monique in a week = 50 × $12.75 = $637.5
Difference in their earnings = $765 - $637.5 = $127.5
Hence there is a difference of $127.5 in their earnings.
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4²times 4² is ? Explain how you know and simplify please
Answer:
For me, it always helps to break down equations like this. Divide it up into two separate parts.
4^2*4^2=x
4^2=16
Replace both 4^2 with 16
16*16=256
Which of the following is/are the solution of the equation 2x+y=10?This question has multiple correct optionsAx=9 and y=3 is one of the solution of given equation.Bx=2 and y=6 is one of the solution of given equation.Cx=3 and y=4 is one of the solution of given equation.Dx=7 and y=2 is one of the solution of given equation.
Answer:
Correct options are B) and C)
Step-by-step explanation:
The given equation is 2x+y=10.
Clearly, x=3 and y=4 satisfy this equation.
Therefore , x=3 and y=4 is one of the solution of given equation.
____the transformation is an example of a translation because the figure slides in one direction, but does not flip, turn, or change size.
The transformation is an example of a translation because the figure slides in one direction, but does not flip, turn, or change size.
Now, According to the question:
Type of Transformation:
There are four types of transformation in geometry, namely translation, reflection, rotation, and dilation. In translation, it slides the figure in any direction while in reflection, it flips the figure over a point or a line. Also, in rotation the figure turns, while in dilation the figure is either enlarged or reduced.
The type of transformation can be defined as moving a figure to a new location, without any change in the figure's size or shape being called translation. In translation, the figure merely slides or moves in the same direction and distance.
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let be given by where t is the angle that the y axis makes with the vector the trace of is called the tractrix show that
equation for a tractrix, hence it proves that the trace of the tractrix is given as (t, t tan t).
The trace of the tractrix is given as:
Trace = (x, y) = (t, t tan t)
To show that the trace is that of a tractrix, we will use the equation for a tractrix, which is given as:
x = t – t tanh t
where t is the angle that the y-axis makes with the vector.
Substituting the value of x in the trace equation, we get:
t – t tanh t = t
Simplifying the equation, we get:
t tanh t = 0
This is the equation for a tractrix, hence it proves that the trace of the tractrix is given as (t, t tan t).
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Henry ran three days last week for a total of 4 1/2 miles. He ran 2 1/4 miles on Monday and 17/8 miles on Wednesday. How many miles did he run on Saturday?
Answer: 0.125 Miles
Step-by-step explanation:
X+2.25 +2.125 = 4.5
X+4.375 =4.5
4.5-4.375= X = 0.125
Why is 0 a prime number?
0 is not a prime number. A prime number is defined as a positive integer greater than 1 that has no positive integer divisors other than 1 and itself. If we look at 0 it does not meet this requirement it means it cannot be a prime number.
0 does not meet this definition because it is not greater than 1 and it does have positive integer divisors other than 1 and itself (for example, it is divisible by 2, 4, and so on). Additionally, the concept of prime numbers is defined only for positive integers, 0 is not positive.
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So far, Leo has put together 40% of his 500-piece puzzle. How many puzzle pieces has Leo put together?
200
Step-by-step explanation:Portions of quantities can be represented as percentages and decimals, which can help solve different types of questions.
Multiplying Decimals
To find any percent of a quantity, you can multiply the quantity by the percentage as a decimal. We can convert percentages to decimals easily. By moving the decimal point 2 places to the left, we can change 40% into a decimal. So, 40% is equal to 0.4. Now, multiply this by 500.
500 * 0.4 = 200So, Leo has put together 200 pieces.
Multiples of 10
Since 40% is a multiple of 10, we can solve using another method. It is easy to find 10% of any quantity, just move the decimal point 1 place to the left. So, 10% of 500 is 50.
Then, since 40 is 4 times 10, we can say that 40% of 500 is 4 times 10% of 500.
50 * 4 = 200This proves that Leo has done 200 pieces.
What is 4 1/3 x 6 Need a little help thanks
The result of the given multiplication of the mixed fraction is found as 78/3.
Define the term mixed fractions?A number that combines an integer as well as a legal fraction is referred to as a mixed fraction.
Mixed number is another name for mixed fraction.It is possible to change an improper fraction into the a mixed fraction and the other way around.When converting a mixed fraction to the an improper fraction, both denominator and the overall number are multiplied, the product is added to the numerator, and the sum is written as the numerator and denominator.The given expression:
= 4 1/3 x 6
Solving the mixed fraction.
= (4*3 + 1)/3 x 6
= (12 + 1)/3 x 6
= 13/3 x 6
= 78/3
Thus, the result of the given multiplication of the mixed fraction is found as 78/3.
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What is the 2 point formula method for finding slope?
The equation to calculate slope from two points (x₁, y₁) and (x₂, y₂) on a line is m = (y₂ - y₁) / (x₂ - x₁).
Here,
m = the line's slope
x1 is equal to the initial point's x-coordinate.
y1 is the first point's y-coordinate.
x2 is equal to the second point's x-coordinate.
The second point's x-coordinate is equal to y2.
It only takes applying the slope formula rise/run to find the slope between two places. With various forms of information about the line available, various formulas can be used to determine the slope. Particularly when two points on the line are given, the formula for finding the slope from two points is utilized.
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What is the equation of the line which passes through the points 2 3 and (- 4 1?
The equation of the line which passes through points (2 3) and (-4 1) is 3y - x = 7.
What is the equation of the line?
The formula for a straight line is y=mx+c where c is the height at which the line intersects the y-axis, often known as the y-intercept, and m is the gradient.
Here, we have
Given: points (2 3) and (-4 1)
We have to find the equation of a line.
we need to determine the slope of the line. The slope can be found by using the formula
m = (y₂ - y₁) /(x₂ - x₁)
Now, we put the given points and get the value of m.
m = (1 - 3) /(-4 - 2)
m = 1/3
Now, we can use the point-slope formula to find an equation for the line. The point-slope formula states:
(y - y₁) = m(x - x₁)
(y - 3) = 1/3 (x-2)
3y - 9 = x - 2
3y - x = 7
Hence, the equation of the line which passes through points (2 3) and (-4 1) is 3y - x = 7.
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ian measures the mass of his cat and his kittens. the mass of the kitten is 6 and 1/5 lb. the kitten is 3 and 7/8 lb lighter than the cat. what is the total mass of cat and the kitten?
evaluate the integral (3 to 1) of x^4 (ln x 2)^2 dx
The definite integral is [tex]& \frac{243}{5}(\ln 3)^2-\frac{2}{5}\left[\ln 3\left(\frac{243}{5}\right)-\frac{243}{25}\right]-\frac{2}{125}[/tex].
The integral is [tex]$\int_1^3 x^4(\ln x)^2 d x$[/tex]
First evaluate indefinite integral, [tex]$\int x^4(\ln x)^2 d x$[/tex]
The definite integral of a real-valued function f(x) with respect to a real variable x on an interval [a, b] is expressed as [tex]\int_a^b f(x) d x=F(b)-F(a)[/tex]
Here,
∫ = Integration symbol
a = Lower limit
b = Upper limit
f(x) = Integrand
dx = Integrating agent
Thus, ∫ab f(x) dx is read as the definite integral of f(x) with respect to dx from a to b.
Indefinite integrals are implemented when the boundaries of the integrand are not specified.
Use integration by parts:
[tex]$\int u d v=u v-\int v d u$[/tex]
Let [tex]$u=(\ln x)^2$[/tex] and [tex]$a v=x^4 d x$[/tex]
This implies [tex]$d u=\frac{2(\ln x)}{x} d x$[/tex] and [tex]$v=\int x^4 d x=\frac{x^5}{5}$[/tex]
Equation (1) becomes,
[tex]$$\begin{aligned}& \int x^4(\ln x)^2 d x=(\ln x)^2 \frac{x^5}{5}-\int \frac{x^5}{5} \times \frac{2(\ln x)}{x} d x \\& \int x^4(\ln x)^2 d x=(\ln x)^2 \frac{x^5}{5}-\frac{2}{5} \int x^4 \ln x d x\end{aligned}$$[/tex]
Again, use integration by parts to evaluate [tex]$\int x^4 \ln x d x$[/tex]
Let [tex]$u=\ln x, d v=x^4 d x$[/tex]
This implies [tex]$d u=\frac{1}{x}$[/tex] and [tex]$v=\int x^4 d x=\frac{x^5}{5}$[/tex]
Let [tex]$u=\ln x, d v=x^4 d x$[/tex]
This implies [tex]d u=\frac{1}{x}$[/tex] and [tex]$v=\int x^4 d x=\frac{x^5}{5}$[/tex]
[tex]$$\begin{aligned}\int x^4 \ln x d x & =\ln x\left(\frac{x^5}{5}\right)-\int\left(\frac{x^5}{5}\right) \frac{1}{x} d x \quad \text { since } \int u d v=u v-\int u d u \\& =\ln x\left(\frac{x^5}{5}\right)-\frac{1}{5} \int x^4 d x \\& =\ln x\left(\frac{x^5}{5}\right)-\frac{x^5}{25}\end{aligned}$$[/tex]
From equation (2),
[tex]$$\int x^4(\ln x)^2 d x=(\ln x)^2 \frac{x^5}{5}-\frac{2}{5}\left[\ln x\left(\frac{x^5}{5}\right)-\frac{x^5}{25}\right]$$[/tex]
The required definite integral is,
[tex]$$\begin{aligned}\int_1^3 x^4(\ln x)^2 d x & =\left[(\ln x)^2 \frac{x^5}{5}-\frac{2}{5}\left[\ln x\left(\frac{x^5}{5}\right)-\frac{x^5}{25}\right]\right]^3 \\& =\left[(\ln 3)^2 \frac{3^5}{5}-\frac{2}{5}\left[\ln 3\left(\frac{3^5}{5}\right)-\frac{3^5}{25}\right]\right]-\left[(\ln 1)^2 \frac{1^5}{5}-\frac{2}{5}\left[\ln 1\left(\frac{1^5}{5}\right)-\frac{1^5}{25}\right]\right] \\& =\frac{243}{5}(\ln 3)^2-\frac{2}{5}\left[\ln 3\left(\frac{243}{5}\right)-\frac{243}{25}\right]-\frac{2}{125}\end{aligned}$$[/tex]
Therefore, the required definite integral is [tex]& =\frac{243}{5}(\ln 3)^2-\frac{2}{5}\left[\ln 3\left(\frac{243}{5}\right)-\frac{243}{25}\right]-\frac{2}{125}[/tex].
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Determine the limit by sketching an appropriate graph. lim: x ->-7 from : f(x), where f(x) = S-3x +0 for x <7 and 5x + 1 for x >=7 a. 1 b. -21 c. 36 d. 2
To determine the limit of f(x) as x approaches -7, we need to analyze the behavior of the function as x gets closer and closer to -7.
Since f(x) is defined differently for x < 7 and x >=7, we need to look at both cases separately.
For x < 7, f(x) = -3x + 0
For x >= 7, f(x) = 5x + 1
If we substitute x = -7 into the first equation, we get f(-7) = -3(-7) + 0 = 21
If we substitute x = -7 into the second equation, we get f(-7) = 5(-7) + 1 = -36
We can see that the function is defined differently for x < 7 and x >=7, and it does not have the same value when x = -7.
Therefore, the limit of f(x) as x approaches -7 does not exist (DNE).
A graph of f(x) with two different lines for x<7 and x>=7, one with slope -3 and y-intercept 0, the other with slope 5 and y-intercept 1. The two lines do not intersect at x = -7, this illustrates the DNE limit.
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When a stone is thrown upwards, the height, h, it reaches is proportional to the square of the initial velocity, v. Write down a formula, using k, connecting the height reached and the initial velocity.
h = kv is the formula connecting the height reached and the initial velocity
How to write a formula connecting variables?A variation is a relation between a set of values of one variable and a set of values of other variables.
From the information, the stone is thrown upwards, the height, h, it reaches is proportional to the square of the initial velocity, v.
Since the height, h is proportional to the square of the initial velocity, v.
We can write the formula as follows:
h α v
h = kv (where k is constant of proportionality)
Therefore, the formula connecting the height reached and the initial velocity is h = kv
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solve for x
u = 1/2x - 1
h is inversely proportional to v h=8 v=7
The equation connecting h and v is h = 56/v and the value of h when v = 5 is 11.2
a) work out an equation of h in terms of vFrom the question, we have the following parameters that can be used in our computation:
Variation = inverse variation
h = 8, v = 7
An inverse variation is represented as
k = vh
Where k is the constant of proportion
Substitute the known values in the above equation, so, we have the following representation
k = 7 * 8
Evaluate
k = 56
So, we have the following representation
vh = 56
Make h the subject
h = 56/v
b) work out the value of h when v = 5Substitute the known values in the above equation, so, we have the following representation
h = 56/5
Evaluate
h = 11.2
Hence, the solution is 11.2
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A car is traveling at a rate of 40 mph. What is the speed in feet per minute?
Please help me if you can thanks
[tex]26 sin 58°[/tex] is the expression that represents the length of segment PR.
What is Length?The word "length" is used to describe an object's size or the separation between two points. The length of an object or the separation between two points is measured by its length. It is employed to determine an object's size or the separation between two points.
Since triangle JKL and triangle PQR are similar, we can use the similarity ratios to find the length of PR.
We know that the ratio of PR to JK is the same as the ratio of PQ to JL. We know that [tex]PQ = 26 and JL = 26 + 13 = 39[/tex], so the ratio is [tex]26/39[/tex].
So, [tex]PR = (26/39) * 13 = 26sin( JL/2) = 26sin58°[/tex]
So the answer is [tex]26 sin 58°[/tex]
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