Claims • Evidence • Reasoning Make a claim about along which type of tectonic plate boundary this fault would be common. Provide evidence to support the claim and
explain your reasoning.

Answer:

NO3-

Explanation:

edge2020

no3-Edg 2020

Explanation

Brainliest

Answer:

Yes, this ring is pure gold because when we divide the mass by the volume we get our density for the ring, which comes out to about 19.32.

Explanation:

Answer:

6

Explanation:

slope= [tex]\frac{rise}{run}[/tex]

slope=[tex]\frac{6}{1}[/tex]

slope=6

Answer:

its one half

Explanation:

i learned this last week

Answer:

The increase in kinetic energy that comes with higher temperatures allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions.

Explanation:

Solubility is affected by temperature due to heatness.

The number of moles of Co that would be required to react with 6.14 moles of P4 would be 36.84 moles

From the equation of the reaction:

6Co + P4 → 2Co3P2

For every 1 mole of P4, 6 moles of Co is required for complete reaction.

Thus, the mole of Co that would be needed for 6.14 moles of P4 would be:

                      6 x 6.14 = 36.84 moles

More on stoichiometric calculations can be found here: https://brainly.com/question/8062886

Answer:

Allotrope of carbon.

High melting point.

Explanation:

Answer:

Density lower than that of diamond.

It has soft, slippery feel.

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

mass = 4.05 g

volume = 28 mL

We have

[tex]density = \frac{4.05}{28} \\ = 0.1446428571...[/tex]

We have the final answer as

Hope this helps you

Answer:

539.35 g

Explanation:

molar mass of Mg = moles of Ag * molar mass of Ag

x = 5 * 107.87

x = 539.35 g

Answer:

62.1 gram

Explanation:

Al molar mass = 27 g/mol

mass = molar mass × no of moles

= 27 × 2.3 = 62.1 gram

Answer:

microscope

Explanation:

Answer:

0.02moles

Explanation:

To answer this question, the general gas law equation is used. The General gas law is:

Pv = nRT

Where; P = standard atmospheric pressure (1 atm)

V = volume (L)

n = number of moles

R = Gas law constant

T = Temperature

For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?

Therefore; Pv = nRT

n = PV/RT

n = 1 × 1/ 0.0821 × 600

n = 1/49.26

n = 0.0203moles

Hence, there are 0.02 moles of gas.

The number of mole of the gas present in the cylinder is 0.02 mole

From the question given above, the following data were:

Temperature (T) = 600 K

Volume (V) = 1 L

Pressure (P) = 1 atm

The number of mole of the gas present in the cylinder can be obtained by using the ideal gas equation (PV = nRT) as illustrated below:

Temperature (T) = 600 K

Volume (V) = 1 L

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

1 × 1 = n × 0.0821 × 600

1 = n × 49.26

Divide both side by 49.26

[tex]n = \frac{1}{49.26}\\\\[/tex]

Thus, 0.02 mole of the gas is present in the cylinder.

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Answer:

d) It incorrectly describes the two processes

Hope it helps you

And please mark it as the brainliest answer

Answer:

Pb2+(aq) + l+(aq) ------------pbl2(s) net ionic equation

Explanation:

Pb(NO3)2(aq) + kI(aq)------------PbI2(s) + kNo3(aq)

Pb2+ (aq)No3-(aq) + k+(aq) l-(aq) ______PbI2(s) + k+(aq) + NO32+(aq)

Pb2+(aq) + I-(aq). ------------Pbl2(s)

1. The specific heat capacity of the sample of gold obtained is 0.81 J/gºC

2. The substance is not pure gold

The specific heat capacity of the sample of gold can be obtained as follow:

Heat loss = Heat gain

M₉C₉(M₉ –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)

2.74 × C₉(72.1 – 26.3) = 15.2 × 4.184 (26.3 – 24.7)

C₉ × 125.492 = 101.75488

Divide both side by 125.492

C₉ = 101.75488 / 125.492

C₉ = 0.81 J/gºC

From the above we can conclude that the substance is not pure gold since the calculated and standard value of the specific heat capacity of the gold sample is not the same

Learn more about heat transfer:

https://brainly.com/question/6363778

elements increase in reactivity as they go down in groups and up in periods!!

Answer:

indeed it 1s22s22p63523p645230104p5 is bromine

Answer:is 15.2%

Explanation:

Got it wrong and this the correct answer it told me

The percentage of water in the original sample is 15.2 %.

From the information provided in the question;

Weight of the wet sample = 5.00g

Weight of the dried sample = 4.24g

Loss in mass =  5.00g - 4.24g = 0.76 g

percentage of water in the original sample = Difference in mass between wet and dry sample/ mass of wet sample × 100/1

Hence, when we substitute values;

percentage of water in the original sample =  0.76 g/5.00g × 100/1

percentage of water in the original sample = 15.2 %

So, the percentage of water in the original sample is 15.2 %.

Learn more: https://brainly.com/question/14102587

Explanation:

s=2

p=6

d=10

f=14

I hope this was helpful

Answer:

0.67 g mL-1

Explanation:

Every time a problem asks you to find the density of a substance, your goal will essentially be to determine the mass of one unit of volume of said substance.

Answer:

answer 7.4 atm

Explanation:

i did this and got it correct

Answer: Chemistry is the properties, composition, and structure of elements and compounds, how they can change, and the energy that is released or absorbed when they change.

Explanation:

Answer:

The scientific study of the structure of substances and what happens to them in different conditions or when mixed with each other is known as Chemistry.

Answer: As air is heated its density decreases because its mass remains constant but its volume increases. As air is cooled, its density increases because its mass remains constant but its volume decreases. ... The decrease in density as air is heated causes it to rise above cooler, more dense air. Hope this helped.

Answer:

Explanation:

In this problem, we have 50.0 g of solute and 150.0 g of water. The total mass of the solution will thus be 50.0 g + 150.0 g = 200.0 g. The mass percent will be 50.0g/200.0 g (x100%) = 25.0 %.

Mass percent of a solution can be defined as grams of solute per 100 grams of solution.  In this problem, we have 50.0 g of solute and 150.0 g of water.  The total mass of the solution will thus be 50.0 g + 150.0 g = 200.0 g.  The mass percent will be 50.0g/200.0 g (x100%) = 25.0 %.  You can also look at it another way.  Since you have 50 g solute in 200 g solution, you will have 25 g solute in 100 g solution.  By the definition provided above, this is a 25% by mass solution.

Histidine, an essential amino acid, has as a positively charged imidazole functional group. The imidazole makes it a common participant in enzyme catalyzed reactions. The unprotonated imidazole is nucleophilic and can serve as a general base, while the protonated form can serve as a general acid.

Answer:

2.408 moles of hydrogen are in the sample.

Explanation:

Molecular formula of acetic acid =CH3COOH

Ratio of carbon to hydrogen :2/4:1/2

Measured  number of moles of carbon atoms = 1.204

Let the moles of hydrogen be = x

Number of carbon atoms in 1.204 mol = 1.204mol*Avogadro number

Number of hydrogen atoms in x mol = x*Avogadro number

As we know that ratio of carbon to hydrogen atoms is 1:2.

1/2=1.204mol* avogadro/ x* avogadro

x = 2.408 moles

2.408 moles of hydrogen are in the sample.

Answer:

Explanation:

Hey there!

From question;

The molecular mass of NH₄OH is 35.

Avogadro number = 6.023*10²³ molecules.

Then,

From mole concept,

Molecular mass =  Avogadro number

So, 35 grams contains  6.023*10²³ molecules.

1 gram contains [tex]\frac{ 6.023*10^{23} }{35}[/tex] molecules.

52.1 grams contains [tex]\frac{6.023*10^{23} }{35} *52.1[/tex] molecules.

Therefore, 52.1 grams contains 8.96*10²³ molecules.

Hope it helps!

Answer:

Triphorphorus Pentanitride

Explanation:

since there are three phosphorus use the prefix tri-, since there are five nitrogen use the prefix penta. tri=3, penta=5. then add a suffix -ide to the end of nitrogen. that will give you triphosphorus pentanitride.

Answer:

Explanation:

The protein comprises of two 60-kD polypeptides and two 40-kD polypeptides. Each one of the 40-kD chains has a disulfide-bond which is directly bonded to a 60-kD chain.

The 100-kD units attach noncovalently to produce a protein with a molecular mass of 200 kD. The interaction among the different subunits in the protein is not affected by the Gel filtration chromatography.

Hence, the protein seems to be 200 kD in size. When SDS-PAGE takes place samples are being subjected to heat and therefore undergoing denaturation conditions. The aftermath effect of this causes disorganization in the 100 kD units.

However, the reducing agent (BME) main task is the reduction of disulfide bonds in a protein.

It implies that BME is responsible for the reduction between the R1-S-S-R2 bond between 40 kD and 60 kD to R1-SH and R2-SH, resulting in seperate proteins.

Each element is given its own chemical symbol, like H for hydrogen or O for oxygen. Chemical symbols are usually one or two letters long. Every chemical symbol starts with a capital letter, with the second letter written in lower case. For example, Mg is the correct symbol for magnesium, but mg, mG and MG are wrong...

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