Consider continuous bivariate random variables, X and Y, with the following joint PDF (where c is a constant): FXY(x,y)={x−cy1≤x≤2,0≤y≤10otherwise
Compute P(X≤1.25,Y≥0.75)
.

Answers

Answer 1

By integrating the joint PDF over the specified region.

How to calculate the given probability?

To compute the probability P(X ≤ 1.25, Y ≥ 0.75) using the given joint PDF, we need to integrate the joint PDF over the specified region.

The region of interest is defined as 1 ≤ x ≤ 1.25 and 0.75 ≤ y ≤ 10.

The joint PDF, FXY(x, y), is given by FXY(x, y) = (x - cy) for 1 ≤ x ≤ 2 and 0 ≤ y ≤ 10, and 0 otherwise.

To compute the probability, we integrate the joint PDF over the specified region:

P(X ≤ 1.25, Y ≥ 0.75) = ∫∫[FXY(x, y)]dydx

Breaking down the integral into two parts:

∫[∫[FXY(x, y)]dy]dx

First, integrate the inner integral with respect to y:

∫[FXY(x, y)]dy = ∫[(x - cy)]dy = xy - (cy[tex]^2[/tex])/2

Next, integrate the outer integral with respect to x over the given range:

∫[xy - (cy[tex]^2[/tex])/2]dx = ∫[(xy - (cy)[tex]^2[/tex]/2)]dx

Evaluate the integral over the range 1 ≤ x ≤ 1.25:

= [∫[(xy - (cy[tex]^2[/tex])/2)]dx] evaluated from 1 to 1.25

Substitute the limits of integration into the expression:

= [(1.25y - (cy[tex]^2[/tex])/2) - (y - (cy[tex]^2[/tex])/2)]

Simplifying the expression:

= 1.25y - (cy[tex]^2[/tex])/2 - y + (cy[tex]^2[/tex])/2

= 0.25y

Finally, evaluate the integral with respect to y over the range 0.75 ≤ y ≤ 10:

∫[0.25y]dy = (0.25/2)y[tex]^2[/tex] evaluated from 0.75 to 10

Substitute the limits of integration into the expression:

= (0.25/2)(10^2 - (0.75)^2)

= (0.25/2)(100 - 0.5625)

= (0.25/2)(99.4375)

= 12.4296875

Therefore, P(X ≤ 1.25, Y ≥ 0.75) is approximately equal to 12.4296875.

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Answers

Answer:

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x = 115°

Step-by-step explanation:

Refer to attached picture

The small triangle on the top left has one angle 50° and the other two are same:

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Step-by-step explanation:

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I hope this helped~ <3

-Dream

Answer:

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Happy Tuesday

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Answers

Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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mag-aral ka mabuti para maging matalino

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Answer:

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Answer:

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Answer:±

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I hope this help if it´m wrong I´m so sorry but i´m sure its right tho≤≥

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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x
-3
-2
-1
0
1
2
3
3
4.95
8.1675 13.476375
f(x) 0.6678... 1.1019... 1.8181...
g(x) 0.125 0.25
0.5
1
2
4
8
0.25
0.5
0.75
1
1.25
1.5
1.75
h(x)
k(x)
64
16
4
0
0.25
0.0625
0.0156
O A. h(x)
B. f(x)
OC. k(x)
D. g(x)

Answers

k(×)×95=-0.75 sume k+95=***

g(x) is the function from the table which gives values that could come from the exponential function.

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A relation is a function if it has only One y-value for each x-value.

We have to find the function from the table which gives values that could come from the exponential function.

The exponential function is a mathematical function denoted by .

As we observe the g(x) function.

When x =1, g(x)=2

x=2, g(x)=4

x=3, g(x)=8

g(x)=2ˣ is the required function which is in exponential form

Hence, g(x) is the function from the table which gives values that could come from the exponential function.

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IMPORTANT!! in a unit circle, what is the relationship between arc length and central angle?

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Answer:

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Answers

Answer:

35/9 inches

Step-by-step explanation:

you can put this in a mixed fraction, its still correct:

3 8/9

The area of the rectangle is 35/9 square inches.

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A rectangle is a 2-D shape with length and width.

The length and width are different.

If the length and width are not different then it is a square.

The area of a rectangle is given as:

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We have,

To find the area of a rectangle,

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Length = 2 1/3 = 7/3 inches

Width = 1 2/3 = 5/3 inches

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Area = 35/9 square inches

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The area of the rectangle is 35/9 square inches.

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