Construct a probability distribution for the data.
7. The probabilities that a patient will have blood drawn 0,1,2, or 3 times in a visit are 6/15, 5/15, 3/15, and 1/15, respectively.

Volume of the single prism will be : 576 inches

In geometry a Rectangular prism is a polyhedron with two congruent and parallel bases. It has six faces and have twelve edges.

Volume of a Rectangular prism = L * B * H

                                                      = 24 * 6 * 24

                                                    = 3456 inch^3

Since , it consists of six identical Rectangular prisms

Volume of single prism will be  = 3456 / 6

                                                      576 inch^3

Learn more about  Rectangular Prism:

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Answer: 2.3

Step-by-step explanation:

Calculator

Answer:

-0.5

if 1.4-0.9=0.5

1.4+(-0.5)=0.9

Answer:

I th8nk it means diagonal like 1 and 4 or 2 and 3

Answer:

El 40.75% de los alumnos del centro docente estudian matemáticas.

Step-by-step explanation:

Dado que el 35 % de los estudiantes de un centro docente practica el fútbol, y el 70 % de los que practican el fútbol estudia Matemáticas, así como el 25 % de los que no practican el fútbol, para determinar los porcentajes de estudiantes de matemáticas en el centro docente se debe realizar el siguiente calculo, suponiendo que el total de alumnos del centro sea 100:

35 x 70 / 100 = 2,450 / 100 = 24.5%

100 - 35 = 65

65 x 25 / 100 = 1,625 / 100 = 16.25%

24.5 + 16.25 = 40.75

Así, el 40.75% de los alumnos del centro docente estudian matemáticas.

1. x + 6 = 8

8 - 6 = 2

x = 2

2. 12 + y = 21

21 - 12 = 9

x = 9

3. h - 7 = 13

13 - 7 = 6

x = 6

4. 35 = 50 - 15

p = 50

5. 17 = 8 + 9

e = 8

6. 0 + 10 = 10

k = 10

Hope this helps! Have a wonderful day!

Answer:2√5/5

Step-by-step explanation:

Multiply 2√5  by √5√5

Combine and simplify the denominator.

2√5divide5

The result can be shown in multiple forms.

Exact Form:

2√5/5

.

Answer:

r=C2

Step-by-step explanation:

C=2r is the equation to find circumference

She needs to work backwards in this case, so:

r=C2

r=The circumference she knows x 2 x 3.14(or 3.14159265359)

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I hope this helped!

Answer:

Germany - 90

Step-by-step explanation:

Here are the options to this question

Germany 90

Sweden   78

Japan       63

Canada    75

The appropriate answer should be a multiple of 2, 3, 5, 6, and 9. That is when the number is divided by 2, 3, 5, 6, and 9 it should have a remainder of zero.

90 / 2 = 45

90 / 3 = 30

90 / 5 = 18

90 / 6 = 15

90 / 9 = 10

Thus, the appropriate number is 90

When 78 is divided by 5 and 9, the remainder is not zero

When 63 is divided by 2, 5 and 6, the remainder is not zero

When 75 is divided by 2, 3, 6 and 9, the remainder is not zero

Answer:

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

[tex]\cot(x)+\tan(x)[/tex]

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{1}{\cos(x)}][/tex]

[tex]\csc(x)[\sec(x)][/tex]

[tex]\csc(x)[\csc(\frac{\pi}{2}-x)][/tex]

[tex]\csc(x)\csc(\frac{\pi}{2}-x)[/tex]

Step-by-step explanation:

I'm going to use [tex]x[/tex] instead of [tex]\theta[/tex] because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

I'm going to use a cofunction identity for the 2nd term.

This is the identity: [tex]\tan(x)=\cot(\frac{\pi}{2}-x)[/tex] I'm going to use there.

[tex]\cot(x)+\tan(x)[/tex]

I'm going to rewrite this in terms of [tex]\sin(x)[/tex] and [tex]\cos(x)[/tex] because I prefer to work in those terms. My objective here is to some how write this sum as a product.

I'm going to first use these quotient identities: [tex]\frac{\cos(x)}{\sin(x)}=\cot(x)[/tex] and [tex]\frac{\sin(x)}{\cos(x)}=\tan(x)[/tex]

So we have:

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

I'm going to factor out [tex]\frac{1}{\sin(x)}[/tex] because if I do that I will have the [tex]\csc(x)[/tex] factor I see on the right by the reciprocal identity:

[tex]\csc(x)=\frac{1}{\sin(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

Now I need to somehow show right right factor of this is equal to the right factor of the right hand side.

That is, I need to show [tex]\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}[/tex] is equal to [tex]\csc(\frac{\pi}{2}-x)[/tex].

So since I want one term I'm going to write as a single fraction first:

[tex]\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}[/tex]

Find a common denominator which is [tex]\cos(x)[/tex]:

[tex]\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}[/tex]

[tex]\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}[/tex]

[tex]\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}[/tex]

By  the Pythagorean Identity [tex]\cos^2(x)+\sin^2(x)=1[/tex] I can rewrite the top as 1:

[tex]\frac{1}{\cos(x)}[/tex]

By the quotient identity [tex]\sec(x)=\frac{1}{\cos(x)}[/tex], I can rewrite this as:

[tex]\sec(x)[/tex]

By the cofunction identity [tex]\sec(x)=\csc(x)=(\frac{\pi}{2}-x)[/tex], we have the second factor of the right hand side:

[tex]\csc(\frac{\pi}{2}-x)[/tex]

Let's just do it all together without all the words now:

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

[tex]\cot(x)+\tan(x)[/tex]

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{1}{\cos(x)}][/tex]

[tex]\csc(x)[\sec(x)][/tex]

[tex]\csc(x)[\csc(\frac{\pi}{2}-x)][/tex]

[tex]\csc(x)\csc(\frac{\pi}{2}-x)[/tex]

Answer:

https://www.mrelisara.com/uploads/5/8/7/3/58736993/chapter_2_review_ws_answers.pdfStep-by-step explanation:

Answer:

The circle is the radius divided by equal, so it is the same as the other section meaning 16 as well

Step-by-step explanation:

Add the two ends to the result 32

Answer:

Step-by-step explanation:

yea what she said

Answer:

x=2 or x=−8

Step-by-step explanation:

Answer:

d.

Step-by-step explanation:

102 in.² should be the answer

Answer:

Original coordinates of F is (2,1)

Step-by-step explanation:

when DEFG is dilated by a scale factor of 1/2 with a dilation center of (0, 0), coordinates of point F' will be

( 2 x 1/2, 1 x 1/2 ) = ( 1, 1/2 )

Answer:

y=-1/2x-1

Step-by-step explanation:

Answer:

87  ?

Step-by-step explanation:

Answer:

step 1: =4% of £500

=20

=20 × 5 years

= 100

= £500 + £100

=£600 ....therefore Rob will have £600 in his bank account after years.

Answer:

Step-by-step explanation:

The length is (x-1), not (2-1).

area = (x-1)(x+3) = 12 ft²

x²+2x-3 = 12

x²+2x-15 = 0

(x+5)(x-3) = 0

x = -5, 3

-5 is an extraneous solution, so x=3.

Length = x-1 = 2 feet

Width = x+3 = 6 feet

Answer:

9

Step-by-step explanation:

Answer:

not 35

Step-by-step explanation:

it 18

Answer:

4x+2y

Step-by-step explanation:

6x is the answer to this question

Answer:

212.5

Step-by-step explanation:

For triangles, A = (bh)/2

You can do 15+25 to find the base, which is 40. From here do 17*40/2. You get 340. However, you need to remove the right triangle on the left side.

Again do 17*15/2, which you get 127.5.

From here subtract 127.5 from 340 and get 212.5

Answer:

Step-by-step explanation: