The final temperature of the 22.8 g sample of copper metal that absorbs 114 J of heat is approximately 49.2 °C.
To calculate the final temperature of a 22.8 g sample of copper initially at 35.4 °C that absorbs 114 J of heat, we will use the following formula:
q = mcΔT
where q is the heat absorbed (114 J), m is the mass of the copper (22.8 g), c is the specific heat of the copper metal (0.385 J/g·°C), and ΔT is the change in temperature.
First, rearrange the formula to find ΔT:
ΔT = q / (mc)
Next, plug in the values:
ΔT = 114 J / (22.8 g * 0.385 J/g·°C)
ΔT ≈ 13.8 °C
Now, to find the final temperature, add the initial temperature to the change in temperature:
Final Temperature = Initial Temperature + ΔT
Final Temperature = 35.4 °C + 13.8 °C
Final Temperature ≈ 49.2 °C
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A rear window defroster consists of a long, flat wire bonded to the inside surface of the window. When current passes through the wire, it heats up and melts ice and snow on the window. For one window the wire has a total length of 11.0 mm, a width of 1.8 mmmm, and a thickness of 0.11 mmmm. The wire is connected to the car's 12.0 VV battery and draws 7.5 AA.
2.6×10[tex]^-8[/tex] Ωm,A long, flat wire is used as a rear window defroster and is bonded to the window's interior surface.
Resistivity of the wire ?Electrical resistivity is a measurement of a material's degree of resistance to current flow. The SI unit for electrical resistivity is the ohm meter (m). It is frequently represented by the Greek letter rho. Materials that easily transmit current and have a low resistance are called conductors.
Length of the wire, l = 12.2 m
width of the wire, w = 1.8 mm
Thickness of the wire, T = 0.11 mm
Potential difference of the battery, v = 12 V
Current in battery, I = 7.5 A
Ohms law says, V = IR.
So that, R = V/I
R = 12/7.5 = 1.6 Ω
The Greek letter rho is frequently used to represent resistance, which is numerically equivalent to the resistance R of a wire-like specimen, multiplied by its cross-sectional area A, and divided by its length.
Resistivity if a material is:
ρ = RA/l
ρ = [1.6 × 1.8 × 10[tex]^-3[/tex] × 0.11×10[tex]^-3[/tex]] / 12.2
ρ = (3.168×10[tex]^-7[/tex]) / 12.2
ρ = 2.596×10[tex]^-8[/tex]
Therefore, the resistivity of the wire is 2.60×10[tex]^-8[/tex] Ωm
Resistivity of the wire is 2.60*10^-8 Ωm
Given:
Length of the wire, I = 12.2 m
width of the wire, w = 1.8 mm
thickness of the wire, T = 0.11 mm
Potential difference of the battery, v = 12
Current in the battery, I = 7.5 A
To Find:
Resistivity
Solution: A characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents.
Remember, Ohms law says, V = IR
So that, RV/I
R = 12/7.5= 1.6 Q
Resistivity if a material is
p = RA/I
p = [1.6 * 1.8*10^-3* 0.11*10^-3] / 12.2
p = (3.168*10^-7)/12.2
p = 2.596*10^-8
Therefore, the resistivity of the wire is 2.60*10^-8 Ωm
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If the coefficient of friction between road and tires on a rainy day is 0.109, what is the minimum distance in which the car will stop
The car will halt at a minimum distance of 98.57 meters on a rainy day having a friction coefficient of 0.109.
Calculation of the minimum distance-
Provided that :
the speed of the car = 52 km/h= 52 x 0.278 m/s = 14.45 m/s
Friction coefficient, μ = 0.109the regular force exerted on the car,
[tex]F_{N} = mg[/tex]
Along X-direction, the force is
[tex]F_{x} = ma_{x}[/tex]
Friction acts in the opposite way along the x-axis
[tex]-f_{friction} = ma_{x}[/tex]
⇒-μ[tex]F_{N} = ma_{x}[/tex]
⇒-μmg = [tex]ma_{x}[/tex]
⇒[tex]a_{x} =[/tex] μg
Utilizing the motion equation-
v² = u²+ 2 .a. s
The final speed, v=0 m/s
⇒0² = (14.45)² - 2 μg .s
⇒2 * 0.109 *9.8 *s = (14.45)² = 208.8
⇒s = 208.8 / 2.14 = 97.57 m
It is concluded that the car will halt at a minimum distance of 98.57 meters.
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An AP Physics student is attempting an FRQ problem. They arrive at the following expression for the total distance an object has traveled:
d = 2vh/g
All you know about the variables in this problem are their dimensions:
[v] = distance/time, [h] = distance, and [g] = distance/time^2.
Given this information, explain why the student’s answer must be wrong.
The student's answer is wrong because the unit of his answer is meter - seconds which is not unit of distance (meter).
Total distance traveled by an object
The total distance traveled by an object projected upward is calculated from third equation of motion a shown below.
Equation for the motion of the objectv² = u² - 2gh
where;
v is final velocityu is initial velocityg is acceleration due to gravityat maximum height, the final velocity is zero, v = 0
0 = u² - 2gh
2gh = u²
h = u²/2g
The equation for the total distance an object has traveled during upward projection is "h = u²/2g".
Dimension of the student's answer;d = (2vh)/g = (m/s x m) / (m/s²) = (m²/s) / (m/s²) = m.s
Thus, the student's answer is wrong because the unit of his answer is meter - seconds which is not unit of distance (meter).
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As a pendulum moves toward the equilibrium position, velocity and acceleration . As the pendulum moves away from the equilibrium position, velocity and acceleration . Velocity is at a when acceleration is zero.
Answer:
As a pendulum moves toward the equilibrium position, velocity increases and acceleration decreases. As the pendulum moves away from the equilibrium position, velocity decreases and acceleration increases.
Explanation:
Using the law of conservation of energy, we know that Em1=Em2.
Em1 (at the highest point) = Eg + Ek, where Ek is 0
Em2 (at the equilibrium point) = Eg +Ek, where Eg is 0
This makes sense. At the highest point, the pendulum is at its maximum height. At this point, however, it stops moving, so its velocity is 0. At the equilibrium point, the pendulum is at its lowest height (i.e. h=0). At this point, however, its moving at its maximum velocity. This velocity is constant, which means that acceleration is 0.
Answer:
1) Increases
2) Decreases
3) Decreases
4) Increases
5) Maximum
Explanation:
As a pendulum moves toward the equilibrium position, velocity
✔ increases
and acceleration
✔ decreases
. As the pendulum moves away from the equilibrium position, velocity
✔ decreases
and acceleration
✔ increases
. Velocity is at a
✔ maximum
when acceleration is zero.
P waves ________. P waves ________. are faster than S waves and surface waves have higher amplitudes than do S waves propagate only in solids produce the strongest ground shaking
P waves are faster than S waves and surface waves.
Surface wavesA surface wave in physics is a mechanical wave that travels at the interface of two different media. Gravity waves on the surface of liquids, like ocean waves, are an example that is frequently used. When two liquids with different densities come together, gravity waves can also form at that junction. Solid surfaces can experience elastic surface waves like Rayleigh or Love waves. The way that electromagnetic waves can be steered along a gradient in refractive index or at the boundary between two substances with varying dielectric constants is known as "surface wave" propagation. A guided wave that travels relatively close to the Earth's surface constitutes a ground wave in radio transmission.
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Visualizing the body in the position is significant because all observers have a common point of reference when describing and discussing its regions.
Visualizing the body in the anatomical position is significant because all observers have a common point of reference when describing and discussing its region.
What is the anatomical position?Anatomical position, also known as conventional anatomical position, refers to the body's position while it is standing erect and looking forward, with each arm hanging on either side of the body and palms facing forward. The legs are parallel, with the feet level on the floor and forward facing. When explaining particular anatomical words and locations in human anatomy and physiology, the anatomical position is a standard point of reference. Visualizing the body in its anatomical location is important because it provides a single point of reference for all observers when describing and discussing its region.As the description itself says, visualizing the body in its anatomical location is important because it provides a single point of reference for all observers when describing and discussing its region.
Therefore, visualizing the body in the anatomical position is significant because all observers have a common point of reference when describing and discussing its region.
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The question you are looking for is given here:
Visualizing the body in the _____________ is significant because all observers have a common point of reference when describing and discussing its region.
According to present scientific understanding of the Milky Way's formation, which of the following statements are true
Halo stars formed before disk stars and the protogalatic cloud(s) contained essentially no elements besides hydrogen and helium.
Halo starsThe hierarchical growth of huge galaxies like the Milky Way results in the natural by-product of extended star haloes. Our galaxy's star halo should contain traces of past merger events if this process is a significant contributor to the galaxy's expansion. However, it is difficult to reliably identify real halo stars. Aims. We have entered a new phase of galactic astronomy with the launch of the Gaia space telescope. Over two million stars the majority of which are in the solar neighbourhood have their locations, parallaxes, and proper motions listed in the initial Gaia data release. This sample will be expanded to include more than 1.5 billion stars in the second Gaia data release, of which 5 million will be fully phase-space characterized stars.
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What happens in a parallel circuit when you increase the number of bulbs
As more bulbs are added in parallel, the current strength will decrease OR. As more bulbs are added in parallel, the current strength will increase.
The maximum height a typical person can jump is about 60cm (0.6m). By how much does the gravitational potential energy increase for a 72kg person in such a jump? Where does this energy come from? (What do I have to find here?)
The gravitational potential energy will increase by 423.36 J
How to determine the potential energy at ground levelMass (m) = 72 kgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 0 mPotential energy at ground level (PE₁) =?PE = mgh
PE₁ = 72 × 9.8 × 0
PE₁ = 0 J
How to determine the potential energy at 60 cm (0.6 m)Mass (m) = 72 kgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 0.6 mPotential energy at 60 cm (0.6 m) (PE₂) =?PE = mgh
PE₂ = 72 × 9.8 × 0.6
PE₂= 423.36 J
How to determine the change in potential energy Potential energy at ground level (PE₁) = 0 JPotential energy at 60 cm (0.6 m) (PE₂) = 423.36 JChange in potential energy =?Change in potential energy = PE₂ - PE₁
Change in potential energy = 423.36 - 0
Change in potential energy = 423.36 J
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A battery delivering a current of 55.0 A to a circuit has a terminal voltage of 22.4 V. The electric power being dissipated by the internal resistance of the battery is 37 W. Find the emf of the battery.
The emf of the battery is 23.071 V.
What is emf?
The emf (electromotive force) is defined as the original potential applied across a circuit when there is no internal resistance.
The emf is given by the formula,
E=V+I*r
where E is the emf of the battery, V is the potential applied across the circuit, I is the current through the circuit and r is the internal resistance of the battery.
What is power?
The power is the product of the square of the current and the resistance. The formula of the power P for the internal resistance r is,
P=I^(2)*r
Given I=55.0 A and P=37 W, substitute I=55.0 A and P=37 W in the above formula and solve it to calculate r.
37 = (55.0)^2*r
r=37/ (55.0)^2
r=0.0122 ohm
Given V=22.4 V, substitute I=55.0 A, r=0.0122 ohm, and V=22.4 V in the formula of emf to calculate the value of emf.
E=22.4+(55.0)*(0.0122)
E=23.071 V
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A penny has a mass of and the Moon has a mass of . Use this information to answer the questions below. Be sure your answers have the correct number of significant digits.
Mass of 1 mole of pennies is 1.506 × 10²¹ kg. 48.805 moles moles of pennies have a mass equal to the mass of the Moon.
What is the mass of one mole of pennies?Mass of one mole pennies= 6.023 × 10²³ × mass of one penny
= 6.023 × 10²³ ×0.0025 kg
= 1.506 × 10²¹ kg
How many moles of pennies are required to have a mass of the moon?No. of moles of pennies = mass of moon/mass of one mole of pennies 7.35 X 10²²/1.506 × 10²¹= 48.805 moles
Thus, we can conclude that the mass of 1 mole of pennies is 1.506 × 10²¹ kg and 48.805 moles moles of pennies have a mass equal to the mass of the Moon.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: A penny has a mass of 2.50g and the Moon has a mass of 7.35 X 10^22kg. Use this information to answer the questions below.
A) What is the mass of 1 moIe of pennies? Round your answer to 3 significant digits.
B) How many moles of pennies have a mass equal to the mass of the Moon? Round your answer to 3 significant digits.
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Block A has a weight of 60 lb and block B has a weight of 10 lb. Determine the speed of block A after it moves 5 ft down the plane, starting from rest. Neglect friction and the mass of the cord and pulleys.
The speed of Block A is 7.18 ft/s.
From energy conservation we know that the initial kinetic energy is equal to final kinetic energy.
Block A has weight of 60 lb.
Block B has weight of 10 lb.
In the question it is said that block A moves from rest at a distance of 5ft.
Relative motion constraint-
2sA + sB =l
differentiating we get:
So, 2ΔsA + ΔsB = 0
→ ΔsB = -2ΔsA
2 vA + vB =0
→ vB = -2vA
Now applying principle of work and energy
TA0 +TBO + ΣwO-AB = TA+TB
1/2 mA v²A₀ + 1/2 mBv²B₀ + wAΔsA + wBΔsB = 1/2 mAv²A + 1/2 mBv²B
0 + 0 +6(5) - 10(10) = 1/2 (-60/32-2) v²A +1/2 (10/32.2) 2v²A
vA = 7.18 ft/s
So, the speed of block A is 7.18 ft/s.
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About how many kwh does the solana parabolic trough solar array generate in a month?
An array of this size can produce an average of 350-850 kWh of AC energy per month.
Solar technologies convert sunlight into electrical energy either through photovoltaic (PV) panels or through mirrors that concentrate solar radiation. This energy can be used to generate electricity or be stored in batteries or thermal storage.
Solar panel systems are measured in terms of kW. A common size solar panel array is usually around 5kW. An array of this size can produce an average of 350-850 kWh of AC energy per month.
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A small water droplet in a mist of air is approximated as being a sphere of diameter 1.25 mil. Calculate the terminal velocity as it falls through still air to the ground.
The terminal velocity as it falls through still air is 4.65154 in/s.
The diameter of small water droplet is 1.25 mil= 1.25×0.0254×10^-3 m
= 3.175 × 10^-5 m
Now the viscosity of still air is η = 1.83× 10⁻⁵ Pa
So the formula for drag force is:
Fd = 6πηrv
where, v is the velocity.
Now to attain terminal velocity acceleration must be zero.
→ W = Fd
ρVg = 6πrηv
ρ × 4/3 πr³×g = 6πrηv
v = 2/9 × ρgr³/ η
v = 2/9 × 10³×9.81×(3.175×10^-3) / 18.6×10^-6
v = 0.1181 m/s
v = 4.65154 in/s
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Normally, whem I shut my door, it takes quite a bit of effort to shut it, but when my window is open, even if I just pull it slightly then let go, it slams automatically. It isn't an issue, I just want to know the physics behind it. Is it something to do with difference in pressure?
Answer:
gravity
Explanation:
gravity pulls anything with with weight towards the earth.
Answer
The reason why this occurs is because if there is any apparent wind being pushed towards the direction of the door, there will be an attempt of equalizing pressure and thus it will slam, or close very loudly when you even just push it shut with some effort.
Explanation
This has happened to me a variety of times, I would have the garage open, and it would be a little bit windy, and when I tried to close it, it would slam shut.
Airflow is a significant factor in the pressure appliance.
Your question at the end is correct (Differences in air pressure.)
Apologies for the late response, but I was interested in this as well.
How does quantum theory explain the emission spectra of atoms?
The quantum theory opines that electron in atoms occur a discreet energy levels.
What is the quantum theory?The quantum theory was initiated by the idea of Max plank. In this idea, energy was viewed as occurring in discrete amounts. This idea was first applied to the phenomenon of the black body radiation hence the Plank Equation; E = hf.
Now Neils Bohr pushed the idea further by putting forward the opinion that when an electron in atom is found in an orbit, it does not radiate energy. The atom was thus visualized as being composed of several energy levels and radiation can only occur when an electron moves from a higher to lower energy level.
This implies that the energy of each electron in an atom is quantized. Thus implies that it has a value which an integral multiple of a fundamental amount.
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A variable capacitor with a range from 12 to 279 pF is used with a coil to form a variable-frequency LC circuit to tune the input to a radio. (a) What is the ratio of maximum frequency to minimum frequency that can be obtained with such a capacitor
The ratio of maximum frequency and minimum frequency is 4.9.
Calculation:
The relation between frequency, f, and conductance, C and inductance, L is given as:
[tex]f = \frac{1}{2\pi \sqrt{LC} }[/tex]
Given,
Cmax = 279 pF
Cmin = 12 pF
The smaller value of C gives the the larger value of f, therefore,
[tex]fmax = \frac{1}{2\pi\sqrt{LCmin} }[/tex] ....(1)
[tex]fmin = \frac{1}{2\pi\sqrt{LCmax} }[/tex] .....(2)
Dividing both the equations (1) and (2):
[tex]\frac{fmax}{fmin} =\frac{\sqrt{Cmax} }{\sqrt{Cmin} }[/tex]
[tex]\frac{fmax}{fmin} = \frac{\sqrt{279} }{\sqrt{12} }[/tex]
[tex]= 4.9[/tex]
Hence, the ratio of maximum to minimum frequency is 4.9.
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7. A 0.5-kg puck is traveling at 3.0 m/s. It strikes a 1.0-kg puck, which is
stationary. The two pucks stick together. What is their final speed after
collision?
A. 1.0 m/s
OB. 2.0 m/s
OC. 2.5 m/s
OD.3.0 m/s
*
1 point
Answer:
A
Explanation:
m1vi1 + m2vi2 = (m1+m2)vf
(0.5×3) + (1×0) = (1 + 0.5)vf
1.5=1.5vf
therefore final speed/velocity is 1m/s
m = mass
vi = velocity initial
vf = velocity final
In the writing of ionic chemical formulas, what factor is "crossed over" in the crossover rule?
In the writing of ionic chemical formulas the value of each ion's charge is crossed over in the crossover rule.
Rules for naming Ionic compounds
Frist RuleThe oxidation state of each ion is also important, thus in the crossover rule, the value of each ion's charge is crossed over.
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An object starts at rest. Its acceleration over 30 seconds is shown in the graph below:
Answer:6m/s
Explanation:as you can see before twenty seconds there was no change in speed,but between twenty to thirty seconds,the speed changed from 0m/s to 6m/s,so change in speed is 6m/s.
The speed of an object between 20 and 30 seconds shown in the graph is 70 m/s.
Given:
Time, ΔT = 30-20 = 10s
Acceleration, a = 7 m/s²
The speed can be computed from the acceleration and time. The standard unit of velocity is meters per second.
For the given case, the speed can be computed from the acceleration and time given in the graph.
The speed is given as:
a = v/t
v = at
v = 7×10
v = 70 m/s
Hence, the speed of an object between 20 and 30 seconds shown in the graph is 70 m/s.
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Consider the elliptical orbit of a comet around the sun. where in its orbit is the comet moving the fastest?
Considering the elliptical orbit of a comet around the sun , the closer is the comet , the faster it will move .
Comets are thought to orbit the sun in either the Oort cloud or Kuiper belt. When another star passes by the solar system, its gravity pushes the Oort cloud and/or Kuiper belt and causes comets to descend toward the sun in a highly elliptical orbit with the sun at one focus of the ellipse. The closer is the comet , the faster it will move
It is been observed that comets motion is mostly get affected by sun's gravity. As a comet gets closer to the sun it moves faster and faster and as comet gets away from the sun , its speed get decreased. So, the comet should be as closer at it can be to the sun in order to move fastest
Here , it can be observed that comet's speed is inversely proportional to its distance from the sun.
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A ray of light strikes a boundary between two transparent materials, and there is no transmitted ray, as shown in the figure. What can you conclude about the indices of refraction of these two materials
Answer:q
Explanation:
A car is traveling north on a straight road at 20 mys and a drone is flying east at 6 mys at an elevation of 25 m. At one instant the drone passes directly over the car. How fast is the distance between the drone and the car changing 5 seconds later
The distance between the drone and the car will be 20,3 m/s.
What is average velocity?
In physics, velocity is a quantity that identifies the displacement of a body in a given time. Thus, the average velocity measures in an average time interval, the speed of displacement of a body.
With that being said, Suppose that both car and drone starts from 0 and move towards north and east, respectively. So, after T time:
Distance covered by the car, [tex]y = 20.T.m[/tex]
Distance cover by the drone, [tex]x = 6.T.m[/tex]
Considering the elevations of 25m, the actual distance between them at any T instant:
[tex]A = \sqrt{(20T)^{2} } + (6T)^{2} +25^{2}[/tex]
Speed, [tex]V = \frac{ds}{dt} = \frac{[2(20T).20+2(6T).8}{\sqrt{(20.5)^{2}+(6T)^{2}+25^{2} } }[/tex]
[tex]V = 20,3 m/s[/tex]
So, the distance between the drone and the car will be 20,3 m/s.
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Answer:
20.3 m/s
Explanation:
dx / dt = 20 m / s
dy / dt = 6 m / s
dj / dt = ? when t = 5 s
The trick here is that the drone is flying at an elevation of 25 m.
x^2 + y^2 = j^2
Implicit Differentiation: 2x dx / dt + 2y dy / dt = 2j dj / dt
We are not given x and y values. Solve by d = vt. Distance = velocity * time
x = 20(5) = 100 m
y = 6 (5) = 30 m
Now we need to solve for j, but we need to solve the hypotenuse z of the right triangle first.
z = [tex]\sqrt{(100)^2 + (30)^2[/tex] ≈ 104.4 m
A mistake occurs when z is used as the distance between the drone and the car. Visualize the distance between the drone and the car as the right triangle where j is the hypotenuse, z is the x value, and 25 m is the y value.
j = [tex]\sqrt{(104.4)^2+(25)^2[/tex] ≈ 107.35 m
dj / dt = 1 / 2(107.35)((4000 + 360)) ≈ 20.3 m/s
Refer to the image. Calculate the magnitude of change in velocity of the cue ball.
The answer is 2.83 m/s. Please explain the step.
Answer:
If you add the 2 velocity vectors you get the velocity of the third vector which is the (change in) velocity of the cue ball after striking the cushion
V * 2 * cos 45 = 4 * cos 45 = 2.83 m/s
Suppose we have two planets with the same mass, but the radius of the second one is twice the size of the first one. How does the free-fall acceleration on the second planet compare to the first planet
The free-fall acceleration on the second planet is one-fourth the value of the first planet.
Calculation:
Consider the mass of planet A to be, M
the mass of planet B to be, Mₓ = M
the radius of planet A to be, R₁
the radius of planet B to be, R₂
The acceleration due to gravity on planet A's surface is given as:
g = GM/R₁² - (1)
Similarly, the acceleration due to gravity on planet B's surface is given as:
g' = GM/R₂² [where, R₂ = 2R₁]
= GM/4R₁² -(2)
From equation 1 & 2, we get:
g/g' = GM/R₁² ÷ GM/4R₁²
g/g' = 4/1
Thus we get,
g' = 1/4 g
Therefore, the free-fall acceleration on the second planet is one-fourth the value of the first planet.
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Thinking about planck's law, which star would give off the most orange light?
Thinking about Planck's law, the Red star would give off the most orange light.
According to Planck's Law, distinct atoms and molecules can emit or take in power in discrete portions simplest. The smallest amount of strength that can be emitted or absorbed inside the form of electromagnetic radiation is called quantum.
Planck's Law describes the quantity of spectral radiance at a particular wavelength radiated through a black body in equilibrium. The equation is E=hv.
The floor temperature of a celeb determines the color of mild it emits. Blue stars are warmer than yellow stars, which are hotter than red stars. The bright orange celebrity Arcturus is particularly noteworthy for its massive right motion, The color is a characteristic of their floor temperatures.
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Is the star moving toward earth, away from earth, or is there not enough information provided to determine its motion?
If a star is moving towards Earth, shift towards the blue end of the spectrum, this is called blue shift. If the star is moving away from Earth the light from that star will be red and is called red shift .
The faster a star moves towards the earth, the more its light is shifted to higher frequencies. In contrast, if a star is moving away from the earth, its light is shifted to lower frequencies on the color spectrum
if a star is moving towards Earth, it appears to emit light that is shorter in wavelength compared to a source of light that isn't moving. Because shorter wavelengths correspond to a shift towards the blue end of the spectrum, this is called blue shift.
If the star is moving away from Earth, its light will lose energy to reach Earth, therefore the light from that star will be red and is called red shift
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Fire spreading from a wall to a nearby couch due to radiant heat transfer is an example of: Select one:
Fire spreading from a wall to a nearby couch due to radiant heat transfer is an example of heat reflectivity.
What is heat reflectivity?
When sunlight and other light sources strike a material's surface, its reflectance is measured. This number can be used to characterize a surface's characteristics in terms of surface finish. Another name for reflection is reflectivity.
This is a measurement of the amount of energy that material reflects at a specific wavelength. A value between 0 and 1 can also be used to represent reflectivity (or a percentage between 0 and 100).
Sigma and other top businesses have created a range of other forms of heat reflective fabric in the 50 years after the creation of space blankets, including Fabric and aluminum foil laminates, fabric laminates with metalized thin films.
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A bicyclist covers the first leg of a journey that is d1meters in t1seconds at a speed of v1m/s and the second leg of d2meters in t2seconds at a speed of v2m/sIf his average speed is equal to the average of v1 and v2
then which of the following is true?
1. t1=t2
2. t1≠t2
3. d1=d2
4. d1≠d2
According to motion in straight line t1≠t2
A biker travels d1 meters in t1 seconds at v1 m/s for the first leg and d2 meters in t2 seconds at v2 m/s for the second leg. It's possible that t1t2 if his average speed is equal to the average of v1 and v2.
An object is said to be in motion if its position in relation to its surroundings changes over time. It is a shift in an object's position over time. The only type of motion that exists is motion in a straight line.
A reference system is constantly used to describe a particle's motion. An arbitrary origin point is used to create a reference system, and a coordinate system is imagined to be connected to it. The reference system for a specific problem is the coordinate system that has been selected for it. For the majority of the problems, we typically select an earth-based coordinate system as the reference system.
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If you want the ball to land in your hand when it comes back down, should you toss the ball straight upward, in a forward direction, or in a backward direction, relative to your body
Straight upward
the ball moves in the forward direction with your walking speed at all times. If you want the ball to land in your hand when it comes back down, you should toss the ball straight upward.
What is Projectile motion ?Projectile motion is the motion of an object thrown (projected) into the air.
After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectoryA projectile can be a thrown ball, a bullet or a springboard diver ... Except for air resistance, the forward velocity of any projectile is constant and is equal to the initial velocity when it was released.Learn more about Projectile motion here:
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