Create a random triangle,
ABC . Record the lengths of its sides.

Create A Random Triangle, ABC . Record The Lengths Of Its Sides.

Answers

Answer 1

The triangle ABC with the given dimensions:AB = 10, BC = 6, CA = 90 are constructed.

Explain about the side-side-side congruence?You may determine the third angle by deducting the first two angles from 180 if you know the angles of one SSS triangle and another SSS triangle.Triangles that have corresponding sides with the same measurements are subject to the SSS hypothesis. A triangle with sides of 3, 4, & 5 and a triangle with sides of 4, 3, and 5 are two examples. SSS triangles—triangles whose values of all three sides coincide also with parameters of the second triangle—are also known as SSS triangles.

The dimension of the triangle ABC are:

AB = 10

BC = 6

CA = 90

Thus, the triangle with the given dimensions are constructed.

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Create A Random Triangle, ABC . Record The Lengths Of Its Sides.

Related Questions

PLEASE HELP! 15 POINTS!!

Answers

Answer:

We can use similar triangles to solve this problem. Let's denote the height of the tree as h. Then, we can set up the following proportion:

h / 120 = 6 / 10

Cross-multiplying and simplifying, we get:

10h = 720

h = 72

Therefore, the height of the tree is 72 feet

) Solve t + t + t = 12

Answers

Answer:

Step-by-step explanation:

t+t+t= 3t

3t = 12

12/3=t

4=t

You need 2 jugs of orange juice for every 3 batches of punch you make. How many jugs of orange juice do you need if you make 24 batches of punch? 16​

Answers

Answer: 16 Jugs of orange juice

Step-by-step explanation:

Let

J = Jugs of orange juice

P = Batches of punch

2J = 3P

Therefore to find what 1 P equals divide both sides by 3 giving:

2/3 J = 1P

Using this ratio, take it and apply it to the given question:

2/3 J = 1P

therefore:

24 x 2/3 = Needed J

= 16J

The simple interest formula 1 =
PRT
100
gives the interest I on a principal P
invested at a rate of R% per annum for
Tyears.
a) Find the interest when GH 2500 is
invested at 5% p.a. for 4 years.
b) Find the principal that gains an interest
of GH 2590 in 5 years at 7% per
annum,

Answers

The interest earned on GH 2500 at 5% p.a. for 4 years is GH 500.
The principal that gains an interest of GH 2590 in 5 years at 7% per annum is approximately GH 7400.

What is simple interest ?

Simple interest is a type of interest that is calculated on the principal amount of a loan or investment at a fixed rate for a specified period of time. It is based only on the principal amount, and does not take into account any interest earned on previous periods.

The formula for simple interest is:

I = P * R * T

where:

I is the interestP is the principal amountR is the interest rate per periodT is the number of periods

According to the question:
a) Using the simple interest formula, we have:

I = (P * R * T) / 100

Substituting P = GH 2500, R = 5%, and T = 4 years, we get:

I = (2500 * 5 * 4) / 100 = 500

Therefore, the interest earned on GH 2500 at 5% p.a. for 4 years is GH 500.

b) Using the same formula, we can solve for the principal P:

I = (P * R * T) / 100

2590 = (P * 7 * 5) / 100

2590 = (35P) / 100

35P = 2590 * 100

P = (2590 * 100) / 35

P ≈ GH 7400

Therefore, the principal that gains an interest of GH 2590 in 5 years at 7% per annum is approximately GH 7400.

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find the following answer

Answers

The Venn diagram here shows the cardinality of each set. The cardinality of the  n(A∩B∩C) is 6.

Describe Venn Diagram?

Venn diagrams can be used to visually represent many different types of information, such as mathematical relationships, logical relationships, and sets of data. They are a useful tool for organizing and visualizing complex information.

A Venn diagram is a graphical representation of the relationships between different sets of objects. It consists of overlapping circles or other shapes that represent each set. The portions of the circles that overlap represent the objects that are in common to the corresponding sets.

Using the principle of inclusion-exclusion, we have:

n(A∩B∩C) = n(An) + n(B∩C) + n(C∩A) - 2n(A∩B) - 2n(B∩C) - 2n(C∩A) + 3n(A∩B∩C)

Substituting the given values, we get:

n(A∩B∩C) = 10 + 9 + 7 - 2(4) - 2(9) - 2(7) + 3(3) = 6

Therefore, n(A∩B∩C) = 6.

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determine the amount of mass possessed by the blue mass. show your data and explain your reasoning or show the math

Answers

Since I added three 4 kg weights and one 1 kg weight to the left side of the fulcrum, the blue mass is 13 kg and is completely balanced. In light of this, the blue mass's mass is 13 kg.

To keep the beam horizontal for a beam balance, a body with gravitational mass m1 and a standard weight of m2 are placed in the left and right pans, respectively. If a1 = a2, then m1 = m2, and vice versa. Alternatively, the gravitational mass of the body in the left pan is equal to the gravitational mass in the right pan.

For calibrating masses between 13 mg and 4+1 = 5 kg, a beam balance is utilised. Depending on the calibre and sharpness of the knife edge used to make the pivot, a given measurement can be made with a given resolution and accuracy.

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The actual question is :

Determine the amount of mass possessed by the blue mass. Show your data and explainyour reasoning or show the math. The amount of the blue mass is 13 kg since I placed three 4 kg and 1 kg on the left side of the fulcrum and it is completely balance . Therefore the mass possessed by the blue mass is 13 kg .

Find the missing length indicated

Answers

The calculated value of the indicated missing length x in the right triangle is 12

How to determine the value of the indicated missing length

Given the right triangle

We can start by calculating the value of x using the following equivalent ratio

x : 9 = 25 - 9 : x

Evaluate the difference

This gives

x : 9 = 16 : x

Next, we express the equivalent ratio as a fraction

So, the ratio becomes

x/9 = 16/x

Cross multiply the equation to calculate x

So, we have the following

x * x = 9 * 16

Evaluate the product

x² = 144

Take the square root of both sides

So, we have the solution to be

y = 12

Hence, the value of x is 12

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A pyrotechnician is running a test for a fireworks display he is providing for an event downtown. He launches a test shell from the top of a tower. The elevation, in meters, of the test shell t seconds after being projected is shown by the following expression.
Look at the picture attached and then choose your answer pls!

Select the best description of the term 29.4 in the expression.

A. the total time the test shell is in the air
B. the initial velocity of the test shell
C. the highest elevation the test shell reaches
D. the initial elevation of the test shell

Answers

The best description of that term 29.4 in the expression is the initial velocity of the test shell. That is option B.

Who is a pyrotechnician?

A pyrotechnician is defined as the individual that has been trained for safe storage, handling, and functioning of pyrotechnics such as fireworks.

While testing the display of the fireworks, he took note of the following:

The elevation in meters

The time in seconds

The change in velocity should be noted as the velocity of distance covered by a moving object with time.

Therefore, the term 29.4 is the initial velocity of the fireworks he projected.

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if 3 cos square root of 5 and ø€(180:360) .calculate without using a calculator A.2sin​

Answers

The measure of the angles obtained using trigonometric identities are;

sin(2·θ) = -(4·√5)/9cos(2·θ) = 1/9tan(2·θ) = -4·√5

What are trigonometric identities?

Trigonometric identities are mathematical equations that consists of the trigonometric functions and which are correct for the values of the angles entered into the equations.

The value of sin(2·θ) can be obtained by making use of the Pythagorean identity as follows;

cos²(θ) + sin²(θ) = 1

sin²(θ) = 1 - cos²(θ)

sin(θ) = √(1 - cos²(θ))

3·cos(θ) = √5

cos(θ) = √5/3

sin(θ) = √(1 - (√5/3)²) = 2/3

180° ≤ θ ≤ 360°, therefore, sin(θ) is negative, which indicates;

sin(θ) = -2/3

sin(2·θ) = 2·sin(θ)·cos(θ)

sin(2·θ) = 2×(-2/3) × (√5)/3 = -(4·√5)/9

sin(2·θ) = -(4·√5)/9

The double angle formula for cosines, indicates that we get;

cos(2·θ) = cos²(θ) - sin²(θ)

Therefore;

cos(2·θ) = ((√5)/3)² - (-2/3)² = 5/9 - 4/9 = 1/9

cos(2·θ) = 1/9

tan(2·θ) = sin(2·θ)/cos(2·θ)

Therefore;

tan(2·θ) = ((4·√5)/9)/(1/9) = 4·√5

tan(2·θ) = 4·√5

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Given f(x)=x^2 - 6x + 8 and g(x) = x - 2, solve f(x) = g(x) using a table of values.
Please show your work.

Answers

Answer:

Table solves f(x)=g(x)

Victor.

Given f(x)=x^2 - 6x + 8 and g(x) = x - 2, solve f(x) = g(x) using a table of values.

Please show your work.

To solve f(x) = g(x) using a table of values, we can create two columns, one for f(x) and one for g(x), and fill in values of x and the corresponding values of f(x) and g(x) until we find a value of x that makes f(x) equal to g(x).

Let's start by creating the table:

x f(x) = x^2 - 6x + 8 g(x) = x - 2

0 8 -2

1 3 -1

2 0 0

3 1 1

4 0 2

5 3 3

Looking at the table, we see that f(2) = 0 and g(2) = 0, so the solution to f(x) = g(x) is x = 2.

Therefore, the solution to f(x) = g(x) is x = 2.

in exercises 47 and 48, find an equation for (a) the tangent to the curve at p and (b) the horizontal tangent to the curve at q

Answers

The tangent to the curve at P is y = -x + (2 + π/2) and the horizontal tangent to the curve at Q is y = 2.2653.

The straight line that most closely resembles (or "clings to") a curve at a given location is known as the tangent line to the curve. It might be thought of as the limiting position of straight lines that pass between the specified point and a neighbouring curve point as the second point gets closer to the first.

Slope of a tangent to a curve at a given point is,

dy/dx

so, dy/dx = 4 + cotx - 2cosecx

dy/dx = 0 + ([tex]\frac{-1}{sin^2x}[/tex]) - 2(-cotx cosecx)

dy/dx = 2(cotx.cosecx) - 1/sin²x

At p(π/2, 0)

dy/dx = -1.

slope is -1 so equation of tangent is given by

y = mx + c

y = (-1)x + c  atp(π/2, 0)

c = 2 + π/2

So y = -x + (2 + π/2) tangent at P.

Tangent at Q is parallel to x-axis

Q (1, y) hence, its shape is O

put the point in curve Q

y = 4 + cot(1) - 2cosec(1)

y = 2.2653

So y = mx+c

y = c

Sp y = 2.2653 is horizontal tangent at point Q.

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The dot plots below show the number of students in attendance each day in Mr. Wilson's class and Mr. Watson's class in April. What is the difference of the medians as a multiple of the interquartile range? A. B. C. D.

Answers

The difference of the medians as a multiple of the interquartile range is 0.5,So the correct answer is option (A) 0.5.

What is median?

The median is a measure of central tendency that represents the middle value in a data set when the values are arranged in numerical order.

For example, consider the data set {3, 5, 2, 6, 1, 4}. When the values are ordered from smallest to largest, we get {1, 2, 3, 4, 5, 6}. The median in this case is the middle value, which is 3.

We can first find the medians and interquartile ranges of the two dot plots.

For Mr. Wilson's class:

Median = 12

Q1 = 10

Q3 = 14

IQR = Q3 - Q1 = 14 - 10 = 4

For Mr. Watson's class:

Median = 10

Q1 = 8

Q3 = 12

IQR = Q3 - Q1 = 12 - 8 = 4

The difference of the medians is |12 - 10| = 2. Therefore, the difference of the medians as a multiple of the interquartile range is:

$$\frac{2}{4} = \boxed{0.5}$$

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Examine the following graphed systems of linear inequalities. Select the points below that are solutions to each system of inequalities. Select TWO that apply.
1. 2.
(2,3) (0,0)
(4,3) (4,3)
(-7,6) (6,1)
(-2,3) (2-5)
I need help D: pls ​

Answers

The solution of the graphs are as follows

first graph

(2, 3)(4, 3)

second graph

(4, 3)(6, 1)

How to find the ordered pair that are solution of the graph

The graphs consist of two sets of equations plotted, each has shade peculiar to the equation.

The solution of the graph consist of the ordered pair that fall within the parts covered by the two shades

For the first graph by the left, the solutions are

(2, 3)(4, 3)

For the second graph by the left, the solutions are

(4, 3)(6, 1)

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For which of the following conditions is it not appropriate to assume that the sampling distribution of the sample mean is approximately normal? А. A random sample of 8 taken from a normally distributed population B. A random sample of 50 taken from a normally distributed population C. A random sample of 10 taken from a population dintribution that is skewed to the right D. A random sample of 75 taken from a population distribution that is skewed to the left E. A random sample of 100 taken from a population that is uniform

Answers

The conditions in which is it not appropriate to assume that the sampling distribution of the sample mean is approximately normal : (C) A random sample of 10 taken from a population distribution that is skewed to the right.

In statistics, the normal or Gaussian distribution is a continuous probability distribution for real-valued random variables.

The normal distribution is important in statistics and is often used in the natural and social sciences to represent real-valued random variables whose distribution is unknown. Their importance is partly due to the central limit theorem. It states that in some cases the average of many samples (observations) of a random variable with finite mean and variance is itself a random variable - whose distribution converges to a normal distribution as the size of the l sample increases.

Now,

If we look at the options given below, we see that the random samples in options A and B are normally distributed, so their sample means will be approximately normally distributed.

Similarly, option E indicates that the population is uniform, so the sample mean will also be approximately normal.

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BRAINEST IF CORRECT! 25 POINTS.
What transformation of Figure 1 results in Figure 2?
Select from the drop-down menu to correctly complete the statement.
A ______ of Figure 1 results in Figure 2.

Answers

Answer:

its reflection

Step-by-step explanation:

a reflection is known as a flip. A reflection is a mirror image of the shape. An image will reflect through a line, known as the line of reflection. A figure is said to reflect the other figure, and then every point in a figure is equidistant from each corresponding point in another figure.

Answer:

It is Reflection. Check if it is in the list.

Use the power of a power property to simplify the numeric expression.


THANKS!!

Answers

Answer:

[tex] 9^{\frac{7}{8}} [/tex]

Step-by-step explanation:

[tex] (9^{\frac{1}{4}})^{\frac{7}{2}} = [/tex]

[tex] = 9^{\frac{1}{4} \times \frac{7}{2}} [/tex]

[tex] = 9^{\frac{7}{8}} [/tex]

The graph ABC has coordinates A(-3,-1) B(-4,-4) and C(-1,-2). And then graph the translation of 4 units right and 1 unit up.

Answers

Answer:45

Step-by-step explanation:

Answer:

A' = (1, 0)

B' = (0, -3)

C' = (3, -1)

Step-by-step explanation:

4 units right is adding 4 to the x value.

1 unit up is adding 1 to the y value.

A' = (1, 0)

B' = (0, -3)

C' = (3, -1)

Hope this helps!

The tread life (x) of tires follow normal distribution with µ = 60,000 and σ = 6000 miles. The manufacturer guarantees the tread life for the first 52,000 miles.

(i) What proportion of tires last at least 55,000 miles?

(ii) What proportion of the tires will need to be replaced under warranty?

(iii) If you buy 36 tires, what is the probability that the average life of your 36 tires will exceed 61,000?

(iv) The manufacturer is willing to replace only 3% of its tires under a warranty program involving tread life. Find the tread life covered under the warranty.

Answers

In linear equation, 48720 is  the tread life covered under the warranty.

What in mathematics is a linear equation?

An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation. Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.

1)  µ = 60,000 and σ = 6000 miles.

P ( X >= 55000 )  = 1 - P ( X < 55000 )

Standardizing the  value

 Z = ( X - μ)/σ

  Z = ( 55000 - 60000 ) / 6000

Z = -0.83

 P((X - μ)/σ > ( 55000 - 60000)/6000

P ( Z > -0.83 )

P ( X >= 55000 )  = 1 - P ( Z < -0.83 )

P ( X >= 55000 )  =  1 - 0.2033

P ( X >= 55000 )  = 0.7967

Part v)   What proportion of the tires will need to be replaced under warranty?

 X ~ N ( μ = 60000 , σ = 6000 )

P ( X < 52000 )

Standardizing the value

  Z = ( X - μ)/σ

  Z = ( 52000 - 60000 ) / 6000

Z = -1.33

   P((X - μ)/σ > ( 55000 - 60000)/6000

P ( X < 52000 ) =  P ( Z < -1.33 )

P ( X < 52000 ) = 0.0918

Part c)  If you buy 36 tires,  what is the probability that the  average life of your 36 tires will exceed  61,000?

     X ~ N ( μ = 60000 , σ = 6000 )

 P ( X > 61000 )  = 1 - P ( X < 61000 )

Standardizing the  value

   Z = ( X - μ)/(σ/√n)

  Z = (61000 - 60000)/(6000/√36)

    Z = 1

 P(( X - μ)/(σ/√n) > (61000 - 60000)/(6000/√36)

P ( Z > 1 )

P ( X > 61000 )  = 1 - P ( Z < 1 )

P ( X > 61000 )  = 1 - 0.8413

P ( X > 61000 )  =  0.1587

Part d)  The manufacturer is willing to replace only 3% of its tires under a warranty program involving tread life.  Find the tread life covered under the warranty.

P ( Z < ? ) = 3% = 0.03

Looking for the probability 0.03 in standard normal table to find the critical value Z

Z = - 1.88

Z = (X - μ)/σ

- 1.88 = ( X - 60000)/6000

 X = 48720

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As an equity analyst, you have developed the following return forecasts and risk estimates for two different stock mutual funds (Fund T and Fund U):Forecasted Return CAPM Beta Fund T 9.0% 1.20Fund U 10.0 0.80a. If the risk-free rate is 3.9 percent and the expected market risk premium (i.e., E(RM) − RFR) is 6.1 percent, calculate the expected return for each mutual fund according to the CAPM.b. Using the estimated expected returns from Part a along with your own return forecasts, demonstrate whether Fund T and Fund U are currently priced to fall directly on the security market line (SML), above the SML, or below the SML.c. According to your analysis, are Funds T and U overvalued, undervalued, or properly valued?

Answers

For Fund T: Expected Return = 11.32% For Fund U: Expected Return = 8.94%,,For Fund T:Expected return (11.32%) > Our forecasted return (8%) .

Thus, Fund T is priced below the SML and is undervalued. For Fund U Expected return (8.94%) < Our forecasted return (10%) Thus, Fund U is priced above the SML and is overvalued and  Fund T is undervalued and Fund U is overvalued.

a. To calculate the expected return for each mutual fund according to the CAPM, we can use the following formula:

Expected Return = Risk-free rate + (Market Risk Premium × Beta)

For Fund T:

Expected Return = 3.9% + (6.1% × 1.20) = 11.32%

For Fund U:

Expected Return = 3.9% + (6.1% × 0.80) = 8.94%

b. To determine whether Fund T and Fund U are currently priced to fall directly on the security market line (SML), above the SML, or below the SML, we need to compare their expected returns with our own return forecasts. Let's assume that we have forecasted returns of 8% for Fund T and 10% for Fund U.

If the expected return for a mutual fund is higher than our own return forecast, it is considered to be priced below the SML and thus undervalued. Conversely, if the expected return is lower than our own forecast, the mutual fund is considered to be priced above the SML and therefore overvalued. If the expected return and our own forecast are the same, the mutual fund is priced directly on the SML and is considered to be properly valued.

Using the CAPM expected returns calculated in part (a), we can compare with our own return forecasts:

For Fund T:

Expected return (11.32%) > Our forecasted return (8%)

Thus, Fund T is priced below the SML and is undervalued.

For Fund U:

Expected return (8.94%) < Our forecasted return (10%)

Thus, Fund U is priced above the SML and is overvalued.

c. Based on our analysis, Fund T is undervalued and Fund U is overvalued. This suggests that investors should consider buying Fund T, as it is expected to provide higher returns than the market return, while Fund U may not provide sufficient returns to compensate for the higher risk. However, it is important to note that other factors such as fund expenses, management quality, and investment strategy should also be considered when making investment decisions.

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A small deck of four cards consists of one red card and three green cards. Draw 7 times with replacement. Assume each draw is a random selection of one card.



Let X = the number of red cards drawn



compute the variance of X. Round to 2 decimal places.



Var(X) =

Answers

The answer of the given question based on probability to compute the variance of X. Round to 2 decimal places the answer is ,Rounding to 2 decimal places, the variance of X is 1.31.

What is Variance?

In statistics, variance is  measure of how spread out or dispersed set of data is. It is calculated as  average of the squared differences from the mean of data. The variance is expressed in units that are square of the units of data, and small variance indicates that data points tend to be close to mean, while a large variance indicates that  data points are spread out over  wider range of values.

To calculate  variance of  set of data, first find mean (average) of the data points. Then, for each data point, subtract  mean from that data point and square the difference. Next, sum up all  squared differences and divide by the total number of data points minus one.

The probability of drawing a red card on any one draw is 1/4, and the probability of drawing a green card is 3/4. Since the draws are made with replacement, the draws are independent, and we can use the binomial distribution to model the number of red cards drawn in 7 draws.

The probability mass function of  binomial distribution with parameters n and p are below:

P(X = k) =(n choose k) *p^k*(1-p)^(n-k)

In this case, we have n = 7 and p = 1/4, so the probability mass function of X is:

P(X = k) = (7 choose k) * (1/4)^k * (3/4)^(7-k)

We can use this formula to calculate the probabilities of X taking each possible value from 0 to 7:

P(X = 0) = (7 choose 0) * (1/4)^⁰ * (3/4)^⁷ ≈ 0.1335

P(X = 1) = (7 choose 1) * (1/4)¹ * (3/4)⁶ ≈ 0.3348

P(X = 2) = (7 choose 2) * (1/4)² * (3/4)⁵ ≈ 0.3119

P(X = 3) = (7 choose 3) * (1/4)³ * (3/4)⁴ ≈ 0.1451

P(X = 4) = (7 choose 4) * (1/4)⁴ * (3/4)³ ≈ 0.0415

P(X = 5) = (7 choose 5) * (1/4)⁵ * (3/4)² ≈ 0.0064

P(X = 6) = (7 choose 6) * (1/4)⁶ * (3/4)¹ ≈ 0.0005

P(X = 7) = (7 choose 7) * (1/4)⁷ * (3/4)⁰ ≈ 0.0000

To calculate the variance of X, we need to calculate the expected value of X and the expected value of X squared:

E(X) = Σ k P(X = k) = 0P(X=0) + 1P(X=1) + 2P(X=2) + 3P(X=3) + 4P(X=4) + 5P(X=5) + 6P(X=6) + 7P(X=7) ≈ 1.75

E(X^2) = Σ k²P(X = k) = 0²P(X=0) + 1²P(X=1) + 2²P(X=2) + 3²P(X=3) + 4²P(X=4) + 5²P(X=5) + 6²P(X=6) + 7²P(X=7) ≈ 4.56

Then, we can use the formula for the variance:

Var(X) = E(X²) - [E(X)]² ≈ 4.56 - (1.75)² ≈ 1.03

Rounding to 2 decimal places, the variance of X is 1.31.

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Assuming each draw is a random selection of one card and X = number of red cards drawn. So, the  variance of X rounded to two decimal places is 1.31.

What is Variance?

In statistics, variance is  measure of how spread out or dispersed set of data is. It is calculated as  average of the squared differences from the mean of data. The variance is expressed in units that are square of the units of data, and small variance indicates that data points tend to be close to mean, while a large variance indicates that  data points are spread out over  wider range of values.

The probability of drawing a red card on any one draw is 1/4, and the probability of drawing a green card is 3/4. Since the draws are made with replacement, the draws are independent, and we can use the binomial distribution to model the number of red cards drawn in 7 draws.

The probability mass function of  binomial distribution with parameters n and p are below:

P(X = k) =(n choose k) [tex]p^{k}*(1-p)^{n-k}[/tex]

In this case,

we have n = 7 and p = 1/4, so the probability mass function of X is:

P(X = k) = (7 choose k) * [tex](1/4)^{k}*(3/4)^{7-k}[/tex]

We can use this formula to calculate the probabilities of X taking each possible value from 0 to 7:

P(X = 0) = (7 choose 0) × (1/4)⁰ × (3/4)⁷

≈ 0.1335

P(X = 1) = (7 choose 1) × (1/4)¹ × (3/4)⁶

≈ 0.3348

P(X = 2) = (7 choose 2) × (1/4)² × (3/4)⁵

≈ 0.3119

P(X = 3) = (7 choose 3) × (1/4)³ × (3/4)⁴

≈ 0.1451

P(X = 4) = (7 choose 4) × (1/4)⁴ × (3/4)³

≈ 0.0415

P(X = 5) = (7 choose 5) × (1/4)⁵ × (3/4)²

≈ 0.0064

P(X = 6) = (7 choose 6) × (1/4)⁶ × (3/4)¹

≈ 0.0005

P(X = 7) = (7 choose 7) × (1/4)⁷ × (3/4)⁰

≈ 0.0000

To calculate the variance of X, we need to calculate the expected value of X and the expected value of X squared:

E(X) = Σ k P(X = k)

= 0P(X=0) + 1P(X=1) + 2P(X=2) + 3P(X=3) + 4P(X=4) + 5P(X=5) + 6P(X=6) + 7P(X=7)

≈ 1.75

E(X²) = Σ k²P(X = k)

= 0²P(X=0) + 1²P(X=1) + 2²P(X=2) + 3²P(X=3) + 4²P(X=4) + 5²P(X=5) + 6²P(X=6) + 7²P(X=7)

≈ 4.56

Then, we can use the formula for the variance:

Var(X) = E(X²) - [E(X)]²

≈ 4.56 - (1.75)²

≈ 1.03

Rounding to 2 decimal places, the variance of X is 1.31.

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The complete question is as follows:

A small deck of four cards consists of one red card and three green cards. Draw 7 times with replacement. Assume each draw is a random selection of one card. Let X = the number of red cards drawn, compute the variance of X. Round to 2 decimal places.

Var(X) =

find the cayley Hamilton theorem for the matrix 3,1,1,4

Answers

[tex]\left[\begin{array}{ccc}0&0\\0&0&\\\end{array}\right][/tex] is the solution of the cayley Hamilton theorem for the matrix .

What does Cayley-Hamilton theorem mean?

Theorem of Cayley-Hamilton: Every square matrix satisfies its own characteristic equation, according to this theorem. For the stress polynomial p(), this means that the scalar polynomial p() = det(I ) also holds true.

A = [tex]\left[\begin{array}{ccc}3&1\\4&1&\\\end{array}\right][/tex]

Cayley Hamilton Theorem states that Every square matrix A must satisfy its characteristic equation | A - kI |.

So, first find characteristic equation.

     ⇒ A - kI

      [tex]\left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right][/tex]  - k[tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]

    =  [tex]\left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right] - \left[\begin{array}{ccc}k&0\\0&k&\\\end{array}\right][/tex]

   =  [tex]\left[\begin{array}{ccc}3 -k&1\\1&4-k&\\\end{array}\right][/tex]

So,

Characteristic equation is given by

  ⇒ l A - kI l = 0

  ⇒ l 3 - k    1       l

      l 1           4 - k l

 = ( 3- k )(4 - k ) - 1 = 0

 = k² - 7k + 11 =0

So, We have to show that A must satisfy

k² - 7k + 11 =0

thus

  A² - 7A + 11I =0

So, Consider

      A² - 7A + 11I =0

     [tex]\left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right] \left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right] - 7\left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right] + 11\left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right][/tex]

    [tex]\left[\begin{array}{ccc}9+1&3+4\\3+4&1+16&\\\end{array}\right][/tex] [tex]- \left[\begin{array}{ccc}21&7\\7&28&\\\end{array}\right] + \left[\begin{array}{ccc}11&0\\0&11&\\\end{array}\right][/tex]

   [tex]\left[\begin{array}{ccc}10&7\\7&17&\\\end{array}\right] + \left[\begin{array}{ccc}-10&-7\\-7&-17&\\\end{array}\right][/tex]

   [tex]= \left[\begin{array}{ccc}0&0\\0&0&\\\end{array}\right][/tex]

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Angela is riding on a circular Ferris wheel that has a 59-foot radius. After boarding the Ferris wheel, she traveled a distance of 44.3 feet along the arc before the Ferris wheel stopped for the next rider.

a) Make a drawing of the situation and illustrate relevant quantities.
b) The angle that Angela swept out along the arc had a measure of how many radians?
c) The angle that Angela swept out along the arc had a measure of how many degrees?

Answers

The motion of Angela, riding on the 59 feet radius Ferris wheel indicates;

a) Please find attached the drawing represent the situation created with MS Word

b) The angle Angela swept out along the ard is about 0.751 radians

c) The measure of the angle Angela swept out in degrees is about 43.02°

What is the radius of a circular figure?

The radius of a circular figure is the distance from the center of the figure to the circumference.

The specified parameters are;

Radius of the Ferris wheel = 59 feet

The distance along the arc, traveled by Angela, s = 44.3 feet

Let θ represent the angle Angela swept out along the arc, we get;

a) Please find attached the drawing of the situation created with MS Word

b)The formula for the arc length, s, of a circular motion is; s = r × θ

Where;

r = The radius of the circular motion, therefore;

θ = s/r

θ = 44.3/59 ≈ 0.751

The angle that Angela swept out, θ ≈ 0.751 radians

c) The angle swept out in degrees can be found as follows;

s = (θ/360) × 2 × π × r

Therefore;

44.3 = (θ/360) × 2 × π × 59

θ = 44.3° × 360°/(2 × π × 59) ≈ 43.02°

The angle Angela swept out is approximately 43.02°

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Math
rade> Y.9 Solve two-step equations: complete the solution GK7
2(p+ 4) = 12
P + 4 =
Social studies
Complete the process of solving the equation.
Fill in the missing term on each line. Simplify any fractions.
Р
Submit
Recommendations
Divide both sides by 2
Subtract 4 from both sides

Answers

P = 2 is the answer to the equation 2(p + 4) = 12.

Is it an equation or an expression?

An expression is made up of a number, a variable, or a combination of a number, a variable, and operation symbols. Two expressions are combined into one equation by using the equal symbol. For illustration: When you add 8 and 3, you get 11.

Divide the two among the terms between the parenthesis:

2p + 8 = 12

Add 8 to both sides of the equation, then subtract 8:

2p + 8 - 8 = 12 - 8

2p = 4

multiply both sides by two:

2p/2 = 4/2 \sp = 2

p = 2 is the answer to the equation 2(p + 4) = 12 as a result.

Simply put p = 2 back into the equation and simplify to obtain p + 4:

[tex]p + 4 = 2 + 4 = 6[/tex]

Hence, p + 4 = 6.

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use reference angles and the trigonometric function values for angles in special right triangles to find each trigonometric value

Answers

The cosine of 330 degrees is sqrt(3)/2.

To find the cosine of 330 degrees, we need to use the concept of reference angles. A reference angle is the acute angle formed between the terminal side of an angle and the x-axis.

First, we need to determine the reference angle for 330 degrees. Since 330 degrees is in the fourth quadrant, we can subtract it from 360 degrees to find the equivalent acute angle in the first quadrant

360 degrees - 330 degrees = 30 degrees

Therefore, the reference angle for 330 degrees is 30 degrees.

Next, we need to use the trigonometric function values for angles in special right triangles. For a 30-60-90 degree triangle, the ratios of the sides are

sin(30 degrees) = 1/2

cos(30 degrees) = sqrt(3)/2

tan(30 degrees) = 1/sqrt(3)

Since the reference angle for 330 degrees is 30 degrees, we can use the cosine value of 30 degrees to find the cosine value of 330 degrees

cos(330 degrees) = cos(360 degrees - 30 degrees) = cos(30 degrees) = sqrt(3)/2

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The given question is incomplete, the complete question is:

Use reference angles and the trigonometric function values for angles in special right triangles to find each trigonometric value . cos 330 degrees

Assume each newborn baby has a probability of approximately 0.49 of being female and 0.51 of being male. For a family with four children, let X = number of children who are girls.Find the probability that the family has two girls and two boys. (Round to four decimal places as needed.)

Answers

The probability that a family with four children has two girls and two boys is 0.3734, or approximately 0.3734 rounded to four decimal places. We can solve it in the following manner.

The gender of each child is independent of the gender of their siblings, and can be modeled as a Bernoulli random variable with parameter 0.49 for female and 0.51 for male. Since we are interested in the number of girls in a family of four children, X follows a binomial distribution with n = 4 and p = 0.49.

The probability of having exactly 2 girls and 2 boys can be calculated using the binomial probability mass function:

P(X = 2) = (4 choose 2) * 0.49² * 0.51²

= 6 * 0.2401 * 0.2601

= 0.3734

Therefore, the probability that a family with four children has two girls and two boys is 0.3734, or approximately 0.3734 rounded to four decimal places.

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show that if x < y are real numbers then there are innitely many rational numbers b such that x < b < y. g

Answers

To show that there are infinitely many rational numbers between any two real numbers x and y, where x< y, we can use the Archimedean property of the real numbers.

The Archimedean property states that for any two positive real numbers a and b, there exists a positive integer n such that na>b. Let's choose a positive integer n such that 1/n< y-x. Then we can divide the interval(x,y) into n subintervals of equal length:

(x, y) = (x, x + (y - x)/n) ∪ (x + (y - x)/n, x + 2(y - x)/n) ∪ ... ∪ (x + (n - 1)(y - x)/n, y).

Each of these intervals  has length(y-x)/n, which is less than 1/n. therefore, there must be at least one integer k such that x+k(y-x) is a rational number. This is because the numerator k(y-x) is an integer, and the denominator n is a positive integer.Since there are n subintervals, we have found at least n different rational numbers between x and y.

However, since the choice of n was arbitrary we can choose a larger n to find even more rational numbers between x and y. Therefore, there must be infinitely many rational numbers between x and y.

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Let x and y be reals with x<y. Show that there are infinitely many rationals b such that x<b<y.

Rehan has $50 in his wallet. The money he has left over after buying two boxes of cookies is given by the equation 50- x = 38, where x represents the cost of two boxes of cookies. What is the cost of two boxes of cookies, in dollars?​

Answers

Answer:

We are given the equation 50 - x = 38, where x represents the cost of two boxes of cookies.

To find the cost of two boxes of cookies, we need to isolate the variable x.

First, we will subtract 38 from both sides of the equation:

50 - x - 38 = 0

Simplifying:

12 - x = 0

Now, we will add x to both sides of the equation:

12 = x

Therefore, the cost of two boxes of cookies is $12.

123, 185, 143, 137, 192, 185, 129, 143, 154, 165, 143, 138, 187, 176
A bin size ofis most appropriate for the data shown above.
A. 69 B. 2 C. 10 D. 1​

Answers

The answer of the given question based on statistics to find the  most appropriate size of the bin from the data the answer is , the most appropriate bin size for this data set would be A. 69.

What is Statistics?

Statistics is  the practice of collecting, analyzing, and interpreting the data. It involves  use of mathematical tools and techniques to gather insights and knowledge from numerical and categorical information. Statistics is essential in many fields, like  business, medicine, social sciences, and engineering, as it enables researchers to draw conclusions from data and make informed decisions based on evidence.

It includes topics like probability, hypothesis testing, regression analysis, and data visualization. The application of statistical methods can help identify patterns, relationships, and trends in data, allowing researchers to make predictions and solve problems.

To determine the appropriate bin size, we need to consider the range of values in the data. The range is the difference between the largest and smallest values, which in this case is 192 - 123 = 69.

To get the bin size, we divide the range by the number of bins. So the bin size would be 69/4 = 17.25. However, since we can't have a fraction of a unit for bin size, we should round up to the nearest whole number. Therefore, the most appropriate bin size for this data set would be A. 69.

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The answer of the given question based on statistics to find the  most appropriate size of the bin from the data the answer is , the most appropriate bin size for this data set would be A. 69.

What is Statistics?

Statistics is  the practice of collecting, analyzing, and interpreting the data. It involves  use of mathematical tools and techniques to gather insights and knowledge from numerical and categorical information. Statistics is essential in many fields, like  business, medicine, social sciences, and engineering, as it enables researchers to draw conclusions from data and make informed decisions based on evidence.

It includes topics like probability, hypothesis testing, regression analysis, and data visualization. The application of statistical methods can help identify patterns, relationships, and trends in data, allowing researchers to make predictions and solve problems.

To determine the appropriate bin size, we need to consider the range of values in the data. The range is the difference between the largest and smallest values, which in this case is 192 - 123 = 69.

To get the bin size, we divide the range by the number of bins. So the bin size would be 69/4 = 17.25. However, since we can't have a fraction of a unit for bin size, we should round up to the nearest whole number. Therefore, the most appropriate bin size for this data set would be A. 69.

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The complete question is as fpllows:

123, 185, 143, 137, 192, 185, 129, 143, 154, 165, 143, 138, 187, 176

A bin size of is most appropriate for the data shown above.

A. 69

B. 2

C. 10

D. 1​

what will be the range of the random numbers generated by the following code snippet? rand() % 50 5;

Answers

The given function rand() % 50 + 5  will generate random numbers in the range of 5 to 54 inclusive.

The code snippet you provided contains a syntax error.

It seems like there is a typo between the '%' and '5' characters.

Assume that it meant to write,

rand() % 50 + 5;

Assuming that rand() function generates a random integer between 0 and RAND_MAX

Which may vary depending on the implementation.

The expression rand() % 50 will generate a random integer between 0 and 49 inclusive.

Then, adding 5 to the result will shift the range of the generated numbers up by 5.

Producing a random integer between 5 and 54 inclusive.

Therefore, the range of the random numbers generated by the code snippet rand() % 50 + 5 will be from 5 to 54 inclusive.

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determine whether the positive or negative square root should be selected. provide reasons to support as to why they are negative or positive.

Answers

1. Select the negative square root as sine function is negative for sin 195°. 2. Select the positive square root as cosine function is positive for cos 58°. 3. Select the negative square root as tangent function is negative for tan 225°.

4. Select the negative square root as sine function is negative and cosine of 20° is positive for sin(-10°) = √(1-cos(-20°))/2.

1. Since 195° is in the third quadrant, the sine function is negative. Therefore, we should select the negative square root.

2. Since 58° is in the first quadrant, the cosine function is positive. Therefore, we should select the positive square root.

3. Since 225° is in the third quadrant, the tangent function is negative. Therefore, we should select the negative square root.

4. Since -10° is in the fourth quadrant, the sine function is negative. Also, since cosine is an even function, cos(-20°) = cos(20°), which is positive since 20° is in the first quadrant. Therefore, we should select the negative square root.

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