The single transformation which takes shape A to shape B as in the task content is a 90° clockwise rotation and a 6 units shift rightward.
What transformation is responsible for taking A to B?By observation, it follows that the orientation of the shape A differs from that of B as it lags by 90° in the clockwise direction.
Additionally, the resulting image from a 90° clockwise rotation about the left vertice of A still reguires that A be shifted 6 units rightwards to yield shape B.
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Find the maximum and minimum values of the curve y=2x³-3x²-12x+10
[tex] \underline{ \orange{\huge \boxed{ \frak{Answer : }}}}[/tex]
Let ,
[tex] \sf \large \color{purple} y = 2 {x}^{3} - 3 {x}^{2} - 12x + 10 \: --( \: 1 \: )[/tex]
[tex] \: \: \: [/tex]
Now , Diff wrt ' x ' , we get :
[tex] \sf \: \frac{dy}{dx} = \frac{d}{dx} (2 {x}^{3} - 3 {x}^{2} - 12x + 10) \\ \sf \: \sf \: \frac{dy}{dx} = \frac{d}{dx} \: 2(3 {x}^{2} ) - \frac{d}{dx} 3 {x}^{2} - \frac{d}{dx} 12x + \frac{d}{dx} 10 \\ \sf \: \frac{dy}{dx} =2(3 {x}^{2} ) - 3(2x) - 12(1) + 0 \\ \sf \: \frac{dy}{dx} =6 {x}^{2} - 6x - 12 + 0 \\ \: \sf \red{\frac{dy}{dx} = 6 {x}^{2} 6x - 12 -- (2)}[/tex]
[tex] \: \: \: [/tex]
For maxima or minima \frac{dy}{dx} = 0
[tex] \: \: \: [/tex]
[tex] \sf \: 6 {x}^{2} - 6x - 12 = 0[/tex]
[tex] \: \: \: [/tex]
Divided by 6 on both side , we get.
[tex] \: \: \: [/tex]
[tex] \sf \: {x}^{2} - x - 2 = 0 \\ \sf \: {x}^{2} - 2x + x - 2 = 0 \\ \sf \: x(x - 2) + 1(x - 2) = 0 \\ \sf \: (x - 2)(x + 1) = 0 \\ \sf \: x - 2 = 0 \: \: \bold or \: \: x + 1 = 0 \\ \sf \fbox{x = 2 \: } \: \bold or \: \fbox{ x = - 1}[/tex]
[tex] \: \: \: [/tex]
Again Diff wrt ‘ x ’ , we get.
[tex] \sf \: \frac{d}{dx} =(\frac{dy}{dx} ) = 6\frac{d}{dx} - 6\frac{d}{dx}x - \frac{d}{dx}12 \\ \sf \: \frac{ {d}^{2}y }{ {dx}^{2} } = 6(2x) - 6(1) - 0 \\ \sf \: \sf \bold{ \frac{ {d}^{2}y }{ {dx}^{2} } =12x - 6}[/tex]
[tex] \: \: \: [/tex]
At x = 2
[tex] \: \: \: [/tex]
[tex]\sf \: \frac{ {d}^{2}y }{ {dx}^{2} } =12(2) - 6 \\ \: \: \: \sf \: = 24 - 6 \\ \: \: \: \: \sf \red{ = 18 > 0}[/tex]
At x = -1
[tex] \: \: \: [/tex]
[tex]\sf \: \frac{ {d}^{2}y }{ {dx}^{2} } =12( - 1) - 6 \\ \: \: \: \sf \: = - 12 - 6 \\ \: \: \: \: \sf \red{ = - 18 < 0 }[/tex]
[tex] \: \: \: [/tex]
x = 2 gives minima value of function.
[tex] \: \: \: [/tex]
x = -1 gives maxima value of function.
[tex] \: \: \: [/tex]
Now, put x = 2 in eqⁿ ( 1 )
[tex] \: \: \: [/tex]
[tex] \sf \: y \: minima \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2( {2})^{3} - 3 ({2})^{2} - 12(2) + 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \: \: \: \: = 2(8) - 3(4) - 24 + 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \: \: \: \: \: = 16 - 12 - 24 + 10 \\\sf \: \: \: \: \: \: \: \: \: \: = - 20 + 10 \\\sf \color{red}{\boxed{ = - 10}}[/tex]
[tex] \: \: \: [/tex]
The Point of minima is ( 2 , -10 ).
[tex] \: \: \: [/tex]
Now , put x = -1 in eqⁿ ( 1 )
[tex]\sf \: y \: maxima \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2( { - 1})^{3} - 3 ({ - 1})^{2} - 12( - 1) + 10 \\\sf \color{red}{\boxed{ = 17}}[/tex]
[tex] \: \: \: [/tex]
The point of maxima value is ( -1 , 17 ).
[tex] \: \: \: [/tex]
[tex] \: \: [/tex]
Hope Helps! :)
Find the center and radius of the circle with the equation: (x-5)^2 + (y+1)^2 = 4 a. center: (-5, 1) radius: 4 c. center: (-5, 1) radius: 2 b. center: (5, -1) radius: 4 d. center: (5, -1) radius: 2
Answer:
d
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
(x - 5 )² + (y + 1)² = 4 ← is in standard form
with centre (5, - 1 ) and r = [tex]\sqrt{4}[/tex] = 2
Match each function with the expression representing its inverse function.
1. x - 4
2. x + 4
3. 0.25x
4. x
5. -2x
6. 2x
A. g ( x ) = -0.5 x
B. h ( x ) = 4 x
C. y = x - 4
D. ƒ( x ) = x/2
E. k ( x ) = x
F. p ( x ) = x + 4
Please help!!
Answer:
A matches with 5.B matches with 3.C matches with 2.D matches with 6.E matches with 4.F matches with 1.Step-by-step explanation:
To find the inverse of a function [tex]f(x)[/tex], we let [tex]f(y)=x[/tex] and then solve again for y.
For example, using [tex]g(x)=-0.5x[/tex], we will let [tex]g(y)=x[/tex], giving [tex]x=-0.5y[/tex]. This means that [tex]y=-2x[/tex], and thus [tex]g^{-1}(x)=-2x[/tex].
Using similar logic, we see that:
A matches with 5.B matches with 3.C matches with 2.D matches with 6.E matches with 4.F matches with 1.can someone please help me with this problem?
Given cos(x)=1/2, what is the value of cos(x+pi)?
Answer:
-1/2
Step-by-step explanation:
cos(x+pi) = -cos(x), so the answer is -1/2.
Can someone help me out on these geometry questions? ASAP!!!
Write formal proofs the LA Theorm.
Question 4
1) [tex]\angle B[/tex] and [tex]\angle E[/tex] are right angles, [tex]\overline{AB} \cong \overline{DE}[/tex], [tex]\angle A \cong \angle D[/tex] (given)
2) [tex]\triangle CBA[/tex] and [tex]\triangle FED[/tex] are right triangles (a triangle with a right angle is a right triangle)
3) [tex]\triangle CBA \cong \triangle FED[/tex] (LA)
Note: I wrote the names of the triangles in an alternate order because of the word filter.Question 5
1) [tex]\overline{XY} \perp\overline{WZ}[/tex], [tex]\overline{UV} \perp \overline{WZ}[/tex], [tex]\overline{VW} \cong \overline{YZ}[/tex], and [tex]\angle Z \cong \angle W[/tex] (given)
2) [tex]\angle XYZ[/tex] and [tex]\angle UVW[/tex] are right angles (perpendicular lines form right angles)
3) [tex]\triangle XYZ[/tex] and [tex]\triangle UVW[/tex] are right triangles (a triangle with a right angle is a right triangle)
4) [tex]\triangle XYZ \cong \triangle UVW[/tex] (LA)
5) [tex]\overline{UW} \cong \overline{XZ}[/tex] (CPCTC)
Question 6
1) [tex]\overline{PQ} \perp \overline{QT}[/tex], [tex]\overline{ST} \perp \overline{QT}[/tex], [tex]\overline{PQ} \perp \overline{ST}[/tex] (given)
2) [tex]\angle PQR[/tex] and [tex]\angle RTS[/tex] are right angles (perpendicular lines form right angles)
3) [tex]\triangle PQR[/tex] and [tex]\triangle STR[/tex] are right triangles (a triangle with a right angle is a right triangle)
4) [tex]\angle PRQ \cong \angle SRT[/tex] (vertical angles are congruent)
5) [tex]\triangle PQR \cong \triangle STR[/tex] (LA)
6) [tex]\overline{QR} \cong \overline{TR}[/tex] (CPCTC)
A shipment of 60 highly sensitive accelerometers is to be accepted or rejected based on the testing of 5 chosen randomly from the lot. The shipment will be rejected if more than 1 of the 5 fail. It is known that 10% of the shipment does not meet the specifications. Let X denote the number of units that fail. What is the standard deviation of the distribution
Using the binomial distribution, it is found that the standard deviation of the distribution is of 0.67.
What is the binomial probability distribution?It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
The parameters are:
n = 5, p = 0.1.
Hence the standard deviation is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{5 \times 0.1 \times 0.9} = 0.67[/tex]
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Identify the range of the function shown in the graph.
. A scale factor of 2 is applied to the dimensions of the prism. What effect will this have on the volume
The volume of the prism would be enlarged by a factor of 8
How to determine the effect?The scale factor is given as:
k = 2
Let the initial volume be v and the final volume be V.
The relationship between both volumes is
V = k^3 * v
This gives
V = 2^3 * v
Evaluate
V = 8v
Hence, the volume of the prism would be enlarged by a factor of 8
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Find RS.
A. 12
B. 5
C. 10
D. 9
Answer:
5
Step-by-step explanation:
(2x - 6) + 1 + (x - 4) = 18
3x - 9 = 18
3x = 27
x = 9
RS = x - 4 = 9 - 4 = 5
Answer:
B. 5
Step-by-step explanation:
Pls mark brainiest if helpful!!
PQ + QR + RS = 18
This statement is equivalent to the following:
(2x - 6) + 1 + (x - 4) = 18.
This is because we substitute the line segments with their values.
Now that we have an equation to work with, we will solve it. We start by removing the parenthesis as they are not necessary here.
2x - 6 + 1 + x - 4 = 18
Next, we will make it, so x is alone on the left. We will do this by adding 6 and 4 to both sides
2x - 6 (+6) + 1 + x - 4 (+4) = 18 (+6) (+4)
After doing this we are left with the following equation:
2x + 1 + x = 28
Now we will subtract 1 from both sides to make x alone of the left side of the equation.
2x + 1 (-1) + x = 28 (-1)
After we solve this, we get the following:
2x + x = 27
We can add 2x and x and get 3x because 2 + 1 = 3.
3x = 27
We now simplify this equation by dividing both sides by 3.
[tex]\frac{3x}{3}[/tex] = [tex]\frac{27}{3}[/tex]
We again simplify the equation to the following:
x = 9
BUT THATS NOT THE ANSWER!
Now that we know what x is, we can solve for the value of RS.
We input 9 for x in the equation x - 4.
When we do this, we get 9 - 4 which is 5.
And this is our final answer!!
I hope I could help! Have an amazing day and good luck on your homework!
"You can't predict the future, but you can create it"
-Juliana Palazzolo, 2022
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F(x)=4x^3+7x^2x-1. G(x)=4x-2 find (f-g)(x)
Answer:
4x^3 + 7x^2 - 3x + 1
Step-by-step explanation:
BTW your question, there is a sign misssing
in a school, the ratio of the number of boys to the number of girls is 2:3 and the ratio of the number of girls to the number of teachers is 7:3. what is the ratio of the number of students to the number of teachers
Answer:
35:9
Step-by-step explanation:
The ratios can be combined by making the common element be represented by the same number.
Adjusted ratiosThe common element in the two ratios is the number of girls. In the first ratio, girls are represented by 3 ratio units. In the second ratio, they are represented by 7 ratio units. Multiplying the first ratio by 7 and the second ratio by 3 will make the number of girls the same in both.
boys : girls = 2 : 3 = 14 : 21
girls : teachers = 7 : 3 = 21 : 9
Then the extended ratio can be written ...
boys : girls : teachers = 14 : 21 : 9
The number of students is the total of the numbers of boys and girls, so we have ...
students : teachers = (14 +21) : 9
students : teachers = 35 : 9
the market price of article is rs 3000. a discount of 30% was agreed. find the sale price of the article and the amount of discount.
Answer: 2400
Step-by-step explanation:
3000 x 20/100 = 600
Discount = 600
Sale price of the article: 3000-600 = 2400
In convex pentagon $ABCDE$, angles $A$, $B$ and $C$ are congruent and angles $D$ and $E$ are congruent. If the measure of angle $A$ is 40 degrees less than the measure of angle $D$, what is the measure of angle $D$
The measure of angle D in the convex pentagon ABCDE is 132°
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Let x represent the measure of angle D, hence:
angle A = x - 40.
∠A + ∠B + ∠C + ∠D + ∠E = 540° (sum of angle in a pentagon)
3(x - 40) + 2x = 540
x = 132°
The measure of angle D in the convex pentagon ABCDE is 132°
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Male bullies are often: Question 5 options: below average in verbal assertiveness. above average in verbal assertiveness. above average in size. smaller than average in size.
True or False: Both equations have 'no solutions'.
15x +4-2x = 3(6x + 5)
(2x-8)=(8x+36)
Answer:
False
Step-by-step explanation:
They both have 1 solution
15x + 4 = 3(6x +5)
15x +4 = 18x + 15 Multiple everything in the parentheses by 3.
4 = 3x + 15 Subtract 15 x from both sides
-11 = 3x Subtract 15 from both sides
-11/3 = x Divide both sides by 3
There is only one solution for this equation.
2x -8 = 8x + 36
-8 = 6x + 36 Subtract 2x from both sides
--44 = 6x Subtract 36 from both sides
-44/6 = x Divide both sides by 6.
There is only one solution for this equation.
Answer:
false
Step-by-step explanation:
They both have solutions
Find the slope of the line passing through the vertex and the y-intercept of the quadratic function
[tex]f(x) = 5x{}^{2} + 20x - 7 [/tex]
Find y intercept
y=5(0)²+20(0)-7y=0-7y=-7Point(0,-7)
Find vertex
x coordinate
-b/2a-20/10-2y coordinate
y=5(4)-40-7y=-27Vertex at (-2,-27)
Slope
m=(-27+7)/-2-0m=-20/-2m=10Answer:
10
Step-by-step explanation:
VertexThe x-coordinate of the vertex of a quadratic equation in the form
[tex]f(x)=ax^2+bx+c\quad \textsf{is} \quad -\dfrac{b}{2a}[/tex]
Given function:
[tex]f(x)=5x^2+20x-7[/tex]
[tex]\implies a=5, \quad b=20, \quad c=-7[/tex]
x-coordinate of the vertex
[tex]\implies -\dfrac{b}{2a}=-\dfrac{20}{2(5)}=-2[/tex]
To find the y-coordinate of the vertex, substitute the found value of x into the function:
[tex]\begin{aligned}\implies f(-2) & =5(-2)^2+20(-2)-7\\& = 5(4)-40-7\\& = 20-47\\& = -27\end{aligned}[/tex]
Therefore, the coordinates of the vertex are (-2, -27).
y-interceptThe y-intercept is when the curve crosses the y-axis, so when x = 0.
To find the y-coordinate of the y-intercept, substitute x = 0 into the function:
[tex]\begin{aligned}\implies f(0) & =5(0)^2+20(0)-7\\& = 0 + 0-7\\& = -7\end{aligned}[/tex]
Therefore, the coordinates of the y-intercept are (0, -7).
SlopeTo find the slope of the line passing through the vertex and the y-intercept, simply substitute the found points into the slope formula:
[tex]\implies \sf slope=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{-27-(-7)}{-2-0}=\dfrac{-20}{-2}=10[/tex]
Therefore, the slope of the line passing through the vertex and the y-intercept of the given quadratic function is 10.
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Evaluate 2x for each value of x. Write your answers in simplest form. Show your work!
1. x = 1/4
2. x = 1/3
3. x = 1/2
4. x = 1/6
5. x = 1/7
6. x = 1/8
7. x = 2/3
8. x = 3/4
1. 1/2
2.2/3
3. 1
4. 1/3
5. 2/7
6. 1/4
7. 4/3
8. 3/2
How to evaluate the valueTo find 2x of the vale of x, we have to multiply the value of 'x' by 2
1. x = 1/4
[tex]2x = 2 * \frac{1}{4}[/tex] ⇒ [tex]\frac{2}{4}[/tex] ⇒[tex]\frac{1}{2}[/tex]
2. x = 1/3
[tex]2x = 2 * \frac{1}{3}[/tex] ⇒[tex]\frac{2}{3}[/tex]
3. x = 1/2
[tex]2x = 2* \frac{1}{2}[/tex] ⇒ [tex]\frac{2}{2}[/tex] ⇒ [tex]1[/tex]
4. x= 1/6
[tex]2x = 2* \frac{1}{6}[/tex] ⇒ [tex]\frac{2}{6}[/tex] ⇒ [tex]\frac{1}{3}[/tex]
5. x = 1/ 7
[tex]2x = 2 * \frac{1}{7}[/tex] ⇒ [tex]\frac{2}{7}[/tex]
6. x = 1/8
[tex]2x = 2 * \frac{1}{8}[/tex] ⇒ [tex]\frac{2}{8}[/tex] ⇒ [tex]\frac{1}{4}[/tex]
7. x = 2/3
[tex]2x = 2 * \frac{2}{3}[/tex] ⇒ [tex]\frac{4}{3}[/tex]
8. x = 3/4
[tex]2x = 2 * \frac{3}{4}[/tex] ⇒ [tex]\frac{6}{4}[/tex] ⇒ [tex]\frac{3}{2}[/tex]
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1. Find the product using Suitable Property a) 55×99
Answer:
5445
Step-by-step explanation:
We can use distributive property. a*(b - c) = (a*b) - (a *c)
99 = 100 - 1
55 * 99 = 55 * (100 - 1)
= 55*100 - 55*1
= 5500 - 55
= 5445
A circle is formed when a plane slices through a cone. Which of the following describes the relationship between the plane and the cone
The plane is parallel to the base of the cone describes the relationship between the plane and the cone
A circle is a spherical form without boundaries or edges or we can say that A circle is a closed, curved object with two dimensions in geometry.
The produced cross-section is a circle when a plane slices a cone such that the plane is parallel to the base of the cone.
Ellipse is the shape that is produced when a plane cuts a cone at an angle such that it misses the base or the vertex. (As shown in figure)
Hence A circle is formed when a plane slices through a cone and the plane is parallel to the base of the cone
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which situation is most likley to show a constant rate of change
Option B. The situation that would be more likely to show a constant rate of change would be B. The distance traveled by a truck driving at a constant speed compared with time.
How to solve for the rate of changeThis is the factor that is used to determine if there is a decrease or an increase in a given factor.
A good way to d this is by the use of time and speed to compare the distance that is being traveled.
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Complete question
Which situation is most likely to show a constant rate of change?
A. The weight of a child compared with its age in months
B. The distance traveled by a truck driving at a constant speed compared with time
C. The cost of a new car compared with the number of tires it has
D. The outside temperature compared with the time of day
If the ratio of the measures of corresponding sides of two similar is 4:9, then the ratio of their perimeter is
Answer:
4 : 9
Step-by-step explanation:
ratio of corresponding sides and ratio of perimeter are equal
then ratio of perimeter = 4 : 9
If a line has a slope of 1/3 and passes through the point (1,-2) which ff points also lies on the line a) -2,-5 b) -2,1 c) 4,-1 d) 4,10
Answer: c
Step-by-step explanation:
The equation of the line is
[tex]y+2=\frac{1}{3}(x-1)\\\\y+2=\frac{1}{3}x-\frac{1}{3}\\\\y=\frac{1}{3}x-\frac{7}{3}[/tex]
To determine which point lies on the line, we can substitute in the x coordinate and see if the equation gives the same y-coordinate.
If x = 2, then the equation of the line gives that y = -5/3.If x = 4, then the equation of the line gives that y = -1.Therefore, the answer is c.
The functions f(x) = x^2 – 3 and g(x) = –x^2 + 2 are shown on the graph.
Explain how to modify the graphs of f(x) and g(x) to graph the solution set to the following system of inequalities. How can the solution set be identified?
y ≤ x^2 – 3
y > –x^2 + 2
The set of inequalities y ≤ x² - 3 and y > -x² + 2 do not have a solution
How to modify the graphsFrom the graph, we have:
f(x) = x² - 3
g(x) = -x² + 2
Next, we change the equations to inequalities as follows:
y ≤ x² - 3
y > -x² + 2
To modify the graph, we then perform the following transformations:
Shift the function g(x) down by 2 unitsReflect across the x-axisShift the function g(x) down by 3 unitsHow to identify the solution setAfter the modifications in (a), we have:
y ≤ x² - 3 and y > -x² + 2
Substitute y > -x² + 2 in y ≤ x² - 3
-x² - 2 ≤ x² - 3
This gives
2x² ≤ - 1
Divide by 2
x² ≤ - 0.5
The square root of numbers less than 0 is a complex number
Hence, the set of inequalities do not have a solution
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Ralph Warren purchased 27 shares of stock at 16 3/8 per share. He paid a $27.50 brokerage fee. He later sold all 27 shares at 17 5/8 and paid a $28.75 brokerage fee. (36) What was his total cost for the stock including his brokerage fee? (37) What did he receive from the sale of the stock after he paid the brokerage fee? (38) Did he have a capital gain or loss? (39) How much was the gain or loss? (40) What was the net change from 16 3/8 to 17 5/8?
Based on the number of shares that Ralph Warren purchased, the total cost of the stock was $469.63. The amount he received from sales was $447.13. The capital loss was $22.50.
What was the gain on the sale of the shares?The cost of the stock was:
= (27 x 16³/₈) + 27.50
= $469.63
The amount received from sales:
= (27 x 17⁵/₈) - 28.75
= $447.13
This capital gain (loss):
= 447.13 - 469.63
= -$22.50
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pls help >>> How many solutions does the quadratic
function represented on this graph have?
Answer:
Zero real number solutions
Step-by-step explanation:
Doesn't intercept the x-axis -> No real solutions
What is the slope of the equation y =5/4x-7/4?
Answer is 5/4The slope is the number next to the “x” in the y intercept formula
y= m (slope) x + b
Answer: m= 5/4
Step-by-step explanation:
La ecuación general de la recta es y=mx+by=mx+b, donde m es la pendiente y b es la intersección en y
y=mx+by=mx+b
Marina correctly simplified the expression StartFraction negative 4 a Superscript negative 2 Baseline b Superscript 4 Baseline Over 8 a Superscript negative 6 Baseline b Superscript negative 3 Baseline EndFraction, assuming that a not-equals 0, b not-equals 0. Her simplified expression is below.
Negative one-half a Superscript 4 Baseline b Superscript empty box
What exponent should Marina use for b?
The exponent Marina should use for b is: D. 7.
How to Divide Exponents with the same Base?When dividing, you subtract the exponents. I.e. [tex]a^m \div a^n = a^{m - n}[/tex].
Using the rule, we would also subtract the exponents of b in the simplified expression. Thus:
[tex]b^4 \div b^{-3}[/tex]
Subtract the exponents
4 -(-3) = 4 + 3 = 7.
Therefore, the Maria should use the exponent b = 7.
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Answer: D
Step-by-step explanation:
For what values of o is tan o undefined?
Answer:
90 is the right answer
Step-by-step explanation:
because it give the value pf o is tan o
Is rectangle EFGH the result of a dilation of rectangle ABCD with a center of dilation at the origin
Yes, because both figures are rectangles and all rectangles are similar. Option B is correct option.
According to the statement
We have given that the two rectangles EFGH and ABCD and we have show that the these rectangles Are dilation at origin or not.
So, According to the given diagram
Yes, the rectangle EFGH is a result of dilation of rectangle ABCD with a center of dilation of rectangle at the origin.
Also The scale factor of the dilation is greater than one as the image is bigger than the pre-image i.e. there is a stretch.
The scale factor could be calculated by the ratio of the sides of the image to the pre-image rectangle.
According to the diagram In Rectangle ABCD:
Its vertices have coordinates A(-3,3), B(3,3), C(3,0) and D(-3,0).
Now consider rectangle EFGH:
Its vertices have coordinates E(-4,4), F(4,4), G(4,0) and H(-4,0).
Hence the scale factor is becomes from these values is:
EF/AB = EH/AD = FG/BC = HG/DC = 4/3.
Hence the scale factor becomes 4/3.
Also
∠A=∠B=∠C=∠D=∠E=∠F=∠G=∠H=90°
( When a shape is dilated the two shapes are similar.And similar shapes have equal interior angles , corresponding sides are proportional ).
So, Yes, because both figures are rectangles and all rectangles are similar. Option B is correct option.
Learn more about center of dilation of rectangle here https://brainly.com/question/17986580
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