Determine if the three lengths can be the measures of the sides of a triangle.
3 in, 9 in and 8 in

Answer:

1 and 7/10 pounds?

Step-by-step explanation:

because if its 4/10 more you add 3/10 and 4/10 im pretty sure

Answer:

PLEASE MARK BRAInliest

Step-by-step explanation:

tweety weighed 17/10 pounds last year.

Answer:

Is it Khan Academy? You do 5.8 - 2.7 = 3.1

Step-by-step explanation:

Hope that helps!

Answer:

1. A=πr2=π·4.62≈66.4761

A≈66.48

2. A=πr2=π·22≈12.56637

A≈12.57

please mark as brainiest

Answer:

1. 66.48

2. 12.57

Step-by-step explanation:

Formula is A = ㅠr^2

The radius is that half line :))

Step-by-step explanation:

b 8 is the answer

simplify to2^4^(3/4) then 2^3 then that simplies to 8

Answer:

y=3x-7

Step-by-step explanation:

i plotted the point, and used the slope to get the equation

Answer: The answer is 9a^2 - 3a + 1/4

Step-by-step explanation:

Hope this helpfull.

But Im so sorry if this not helpfully

Answer:

120 deg

Step-by-step explanation:

There is an angle symbol in the equilateral triangle and another symbol in half of the vertex angle. Those two angles are congruent.

The measure of the vertex angle is 2 * 60 deg = 120 deg

Answer: 120 deg

Answer:

68.5

Step-by-step explanation:

each pack 7.5 kg

price for each pack $3

he bought 3

7.5 x 3=22.5

22.5 x3=66.5

Answer:

1)whole numbers

2)integers

3)rational numbers

Answer:

it's 80% of 125

the value of x = 125

Step-by-step explanation:

Answer:

x = 0.3333333333

Step-by-step explanation:

Simplifying

42x = 14

Solving

42x = 14

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '42'.

x = 0.3333333333

Simplifying

x = 0.3333333333

Answer:

b my

Step-by-step explanation:

valentines

bbg

In the kitchen triangle,  the largest angle will be at counter

A triangle is a three-sided polygon that consists of three edges and three vertices.

Given that kitchens have a working triangle between the sink (S), the counter (C), and the oven (O).

The distance between the sink in the oven is 8 feet.

The distance between the sink and the counter is 6 feet,

The distance between the oven and the counter at 7 feet.

we need to find in the kitchen triangle, where is the largest angle

SO=8

SC=6

OC=7

Hence, in the kitchen triangle,  the largest angle will be at counter

To learn more on Triangles click:

https://brainly.com/question/2773823

#SPJ2

Answer:

V = pi x radius x 2 x height OR pi x diameter x height

Hope that helps!

Answer:

the formula for the volume of a cylinder is V=πr²h

Answer:

1 i know its one hope it help

Step-by-step explanation:

List all prime factors for each number.

Prime Factorization of 2 shows:

2 is prime  =>  21

Prime Factorization of 7 shows:

7 is prime  =>  71

Prime Factorization of 8 is:

2 x 2 x 2  =>  23

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is

2, 2, 2, 7

Multiply these factors together to find the LCM.

LCM = 2 x 2 x 2 x 7 = 56

In exponential form:

LCM = 2^3 x 7^1 = 56

LCM = 56

Therefore,

LCM(2, 7, 8) = 56

Answer:

The number to use are 10, 7, 20 and 3.

Step-by-step explanation:

Given

[tex]17 * 23[/tex]

Required

Which numbers would be used using the area model or partial products

The number to use are 10, 7, 20 and 3.

This is shown below:

[tex]\begin{array}{ccc}{ } & {10} & {7} & {20} & { } & { } \ \\ {3} & { } & { } \ \end{array}[/tex]

When the numbers are multiplied, we get:

[tex]\begin{array}{cccc}{ } & {10} & {7} & {} & {20} & {200} &{140} &{=340}\ \\ {3} & {30 } & {21 } &{=51} \ \end{array}[/tex]

[tex]Total = 340 + 51[/tex]

[tex]Total = 391[/tex]

Answer:0.028

Step-by-step explanation: 0.07 x 0.4= 0.028

Answer:

First option is the correct answer.

[tex] (m + n - 1) \sqrt{p} [/tex]

Step-by-step explanation:

[tex]m\sqrt{p} + n\sqrt{p} - \sqrt{p} \\ \\ = (m + n - 1) \sqrt{p} [/tex]

Answer: 95 divided by 9 is 10.5 BUT WITH THE 5 REPEATING

Step-by-step explanation:

Answer:

[tex]c. \\ x(x+3)[/tex]

Step-by-step explanation:

Answer:

C)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer: The ratio of eggs, eggs, to two cups of flour. Let me write two cups of flour. Cups of flour. In either case is, is four eggs for every three cups of flour 5/2

Step-by-step explanation: Im not sure through

Answer:

-5+5

= 0

Step-by-step explanation:

Answer:

-5+5

= 0

Step-by-step explanation:

Answer:

y = 6

Step-by-step explanation:

I'm going to assume you want to solve for y.

Step 1: Move all constants to 1 side, isolating y and its coefficient:

14 = 3y - 4

14 + 4 = 3y - 4 + 4

18 = 3y

Step 2: Divide both sides by 3 to solve for y:

3y = 18

3y / 3 = 18 / 3

y = 6

Final answer: y = 6

Answer:

its C. 8 :) please give me brainlist

Answer:

false

Step-by-step explanation:

Answer:

$452.56

Step-by-step explanation:

400 * 1.025^(5)

Answer:

[tex]\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}= \frac{(x+3)}{x}[/tex]

[tex]\frac{3x^2 - 5x - 2}{x^3 - 2x^2} = \frac{3x + 1}{x^2}[/tex]

[tex]\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}=-\frac{5}{2x}[/tex]

[tex]\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x} = \frac{-(x-3)^2}{25}[/tex]

[tex]\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}= x +1[/tex]

[tex]\frac{9x^2 + 3x}{6x^2} = \frac{3x + 1}{2x}[/tex]

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x} = 3x[/tex]

Step-by-step explanation:

Required

Simplify

Solving (1):

[tex]\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}[/tex]

Factorize the numerator and the denominator

[tex]\frac{x^2(x + 2) -9(x+2)}{x(x^2-x-6)}[/tex]

Factor out x+2 at the numerator

[tex]\frac{(x^2 -9)(x+2)}{x(x^2-x-6)}[/tex]

Express x^2 - 9 as difference of two squares

[tex]\frac{(x^2 -3^2)(x+2)}{x(x^2-x-6)}[/tex]

[tex]\frac{(x -3)(x+3)(x+2)}{x(x^2-x-6)}[/tex]

Expand the denominator

[tex]\frac{(x -3)(x+3)(x+2)}{x(x^2-3x+2x-6)}[/tex]

Factorize

[tex]\frac{(x -3)(x+3)(x+2)}{x(x(x-3)+2(x-3))}[/tex]

[tex]\frac{(x -3)(x+3)(x+2)}{x(x+2)(x-3)}[/tex]

Cancel out same factors

[tex]\frac{(x+3)}{x}[/tex]

Hence:

[tex]\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}= \frac{(x+3)}{x}[/tex]

Solving (2):

[tex]\frac{3x^2 - 5x - 2}{x^3 - 2x^2}[/tex]

Expand the numerator and factorize the denominator

[tex]\frac{3x^2 - 6x + x - 2}{x^2(x- 2)}[/tex]

Factorize the numerator

[tex]\frac{3x(x - 2) + 1(x - 2)}{x^2(x- 2)}[/tex]

Factor out x - 2

[tex]\frac{(3x + 1)(x - 2)}{x^2(x- 2)}[/tex]

Cancel out x - 2

[tex]\frac{3x + 1}{x^2}[/tex]

Hence:

[tex]\frac{3x^2 - 5x - 2}{x^3 - 2x^2} = \frac{3x + 1}{x^2}[/tex]

Solving (3):

[tex]\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}[/tex]

Express x^2 - 9 as difference of two squares

[tex]\frac{6 - 2x}{x^2 - 3^2} * \frac{15 + 5x}{4x}[/tex]

Factorize all:

[tex]\frac{2(3 - x)}{(x- 3)(x+3)} * \frac{5(3 + x)}{2(2x)}[/tex]

Cancel out x + 3 and 3 + x

[tex]\frac{2(3 - x)}{(x- 3)} * \frac{5}{2(2x)}[/tex]

[tex]\frac{3 - x}{x- 3} * \frac{5}{2x}[/tex]

Express [tex]3 - x[/tex] as [tex]-(x - 3)[/tex]

[tex]\frac{-(x-3)}{x- 3} * \frac{5}{2x}\\[/tex]

[tex]-1 * \frac{5}{2x}[/tex]

[tex]-\frac{5}{2x}[/tex]

Hence:

[tex]\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}=-\frac{5}{2x}[/tex]

Solving (4):

[tex]\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x}[/tex]

Expand x^2 - 6x + 9 and factorize 5x - 15

[tex]\frac{x^2 -3x -3x+ 9}{5(x - 3)} / \frac{5}{3-x}[/tex]

Factorize

[tex]\frac{x(x -3) -3(x-3)}{5(x - 3)} / \frac{5}{3-x}[/tex]

[tex]\frac{(x -3)(x-3)}{5(x - 3)} / \frac{5}{3-x}[/tex]

Cancel out x - 3

[tex]\frac{(x -3)}{5} / \frac{5}{3-x}[/tex]

Change / to *

[tex]\frac{(x -3)}{5} * \frac{3-x}{5}[/tex]

Express [tex]3 - x[/tex] as [tex]-(x - 3)[/tex]

[tex]\frac{(x -3)}{5} * \frac{-(x-3)}{5}[/tex]

[tex]\frac{-(x-3)(x -3)}{5*5}[/tex]

[tex]\frac{-(x-3)^2}{25}[/tex]

Hence:

[tex]\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x} = \frac{-(x-3)^2}{25}[/tex]

Solving (5):

[tex]\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}[/tex]

Factorize the numerator and expand the denominator

[tex]\frac{x^2(x - 1) -1(x - 1)}{x^2 - x-x+1}[/tex]

Factor out x - 1 at the numerator and factorize the denominator

[tex]\frac{(x^2 - 1)(x - 1)}{x(x -1)- 1(x-1)}[/tex]

Express x^2 - 1 as difference of two squares and factor out x - 1 at the denominator

[tex]\frac{(x +1)(x-1)(x - 1)}{(x -1)(x-1)}[/tex]

[tex]x +1[/tex]

Hence:

[tex]\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}= x +1[/tex]

Solving (6):

[tex]\frac{9x^2 + 3x}{6x^2}[/tex]

Factorize:

[tex]\frac{3x(3x + 1)}{3x(2x)}[/tex]

Divide by 3x

[tex]\frac{3x + 1}{2x}[/tex]

Hence:

[tex]\frac{9x^2 + 3x}{6x^2} = \frac{3x + 1}{2x}[/tex]

Solving (7):

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x}[/tex]

Change / to *

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} * \frac{x}{x-1}[/tex]

Expand

[tex]\frac{x^2-2x-x+2}{4x} * \frac{12x^2}{x^2 - 2x} * \frac{x}{x-1}[/tex]

Factorize

[tex]\frac{x(x-2)-1(x-2)}{4x} * \frac{12x^2}{x(x - 2)} * \frac{x}{x-1}[/tex]

[tex]\frac{(x-1)(x-2)}{4x} * \frac{12x^2}{x(x - 2)} * \frac{x}{x-1}[/tex]

Cancel out x - 2 and x - 1

[tex]\frac{1}{4x} * \frac{12x^2}{x} * \frac{x}{1}[/tex]

Cancel out x

[tex]\frac{1}{4x} * \frac{12x^2}{1} * \frac{1}{1}[/tex]

[tex]\frac{12x^2}{4x}[/tex]

[tex]3x[/tex]

Hence:

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x} = 3x[/tex]