determine the number of electron groups around the central atom for each of the following molecules. part a ch2cl2

Answer:

Just add what they equal to hope this helps :)

Explanation:

Answer:

the correct answer: 2Ca3(PO4)2 + 6SiO2 -> P4O10 + 6CaSiO3

Explanation:

Utilizing wireless communication and camera imagery is the most effective technological solution to this problem.

To find the answer, we need to know more about the wireless communication and camera imagery

Thus, we can conclude that, the wireless connectivity and camera imaging method meet this obstacle.

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The energy can be identified by their features, characteristics and impacts on the surrounding environment.

If the energy release heat then we can say that it is a thermal energy because it warms the environment whereas if the energy produce light then it is called radiant energy.

If the energy is released from splitting atoms or fusion of atoms so we can say that it is a nuclear energy. If the energy is released from breaking of bonds of atoms and molecules, so it is Chemical energy.

So we can conclude that the energy can be identified by their features, characteristics and impacts on the surrounding environment.

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Answer:

B.) SnO and SnO₂

Explanation:

Tin can either exist as Sn²⁺ or Sn⁴⁺ when ionized. Oxygen always exists as O²⁻ when ionized.

When ions combine, sometimes there needs to be different amounts of each ion in order to create an overall charge of 0. In one combination of the ions (Sn²⁺ and O²⁻), there only needs to be one atom of each ion. In another combination (Sn⁴⁺ and O²⁻), you need to have more anions to balance the high positive charge of the cation.

SnO
-----> Sn²⁺ and O²⁻

-----> +2 + (-2) = 0

SnO₂

-----> Sn⁴⁺ and O²⁻

-----> +4 + (-2) + (-2) = 0

Taking into account the definition of molarity, molar mass and dilution:

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{L}[/tex].

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

If the bleach is a 0.70 mol/L solution of sodium hypochlorite and is required to prepare 1.5 L of chlorine bleach, replacing in the definition of molarity you get:

0.70 [tex]\frac{moles}{L}[/tex]=[tex]\frac{number of moles}{1.5 L}[/tex]

Solving:

0.70 [tex]\frac{moles}{L}[/tex]× 1.5 L= number of moles

1.05 moles= number of moles

The molar mass of sodium hypochlorite is 74.44 g/mol. So you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 74.44 grams, 1.05 moles of the compound contains how much mass?

[tex]mass=\frac{1..05 molesx74.44 grams}{1 mole}[/tex]

mass= 78.162 grams

Finally, the mass of sodium hypochlorite (NaClO) required is 78.162 grams.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

12 mol/L× 420mL= Cf× 2000 mL

Solving:

(12 mol/L× 420mL)÷ 2000 mL= Cf

2.52 mol/L= Cf

In summary, the final concentration of a sodium hydroxide solution is 2.52 mol/L.

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Volume of a real gas shows deviation from ideal gas on low temperature and high pressure

Only 2 options are correct then

There are 2 possible answers here : b and d.

The Ideal Gas Equation is : PV = nRT

Here, when pressure is increased and temperature is lowered, the volume of the molecules will substantially decrease, which means it has deviated from ideal behavior.

Answer:

a

d

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Answer:

A C D. All the other answers got it wrong for Edg3

Explanation:

The amount, in pounds of chlorine that will be needed, will be 201.37 pounds

Calcium hypochlorite goes by the chemical formula, [tex]Ca(ClO)_2[/tex].

In order to know the amount of calcium hypochlorite that will be needed for the operation, we first need to know the percent composition of chlorine in calcium hypochlorite.

Molar mass of calcium hypochlorite = 142.98 g/mol

There are 2 molecules of Cl in calcium hypochlorite. The molar mass will be 35.5 x 2 = 71 g/mol

Percent chlorine in calcium hypochlorite = 71/142.98 x 100 = 49.66%

So, what amount of calcium hypochlorite will give us 100 pounds of chlorine knowing that chlorine is 49.66% of calcium hypochlorite?

49.66% of X = 100 pounds

            X = 100 x 100/49.66 = 201.37 pounds

Thus, 201.37 pounds of calcium hypochlorite will give us approximately 100 pounds of chlorine.

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The empirical formula of Lorelai's compound is C₄H₁₀O

Divide by their molar mass

C = 64.8 / 12 = 5.4

H = 13.62 / 1 = 13.62

O = 21.58 / 16 = 1.35

Divide by the smallest

C = 5.4 / 1.35 = 4

H = 13.62 / 1.35 = 10

O = 1.35 / 1.35 = 1

Thus, the empirical formula of the compound is C₄H₁₀O

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In an aqueous solution containing Mn(II) and Mn (IV) salts, Mn (IV) cation is expected to be the more strongly hydrated.

A chemical event called hydration occurs when two substances interact with water. Since Mn (IV) has a stronger cation with a +4 charge than Mn (II), it will draw more oxygen ions from the Mn(II) in aqueous solution. Mn(IV) will consequently be more intensely hydrated.

Another reason for this is that Mn(IV) ions are often smaller than ions. Now, if we take a look at the element that significantly influences hydration, it is ion size. Therefore, the ion will be more hydrated if it is smaller.

So, In an aqueous solution containing Mn(II) and Mn (IV) salts, Mn (IV) cation is expected to be the more strongly hydrated.

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The equilibrium constant expression for this system is Keq=[NH3][H2S]

The ratio of the equilibrium concentrations of the products to the concentrations of the reactants raised to their respective powers to match the coefficients in the equilibrium equation is K for a system in equilibrium, according to the law of mass action. The equilibrium constant expression is known as the ratio.

Therefore, the equilibrium constant expression for this system is Keq=[NH3][H2S]

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The product that is used on the natural nail prior to application to assist in adhesion and serves to chemically bond the enhancement product to the natural nail is known as nail primer.

A nail primer is a chemical agent used in esthetic centers before applying a colored polish to the nails and serves as an adhesive product.

The nail primers are also very useful for improving the cleaning efficiency of the product before its application.

Nail care products include different types of chemical formulations such as, for example, creams that reinvigorate the cuticle.

In conclusion, the chemical formulation employed on the natural nail that is capable of enhancing and also assisting adhesion is called the nail primer.

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The composition of a given pure compound is always the same no matter what the source of the compound.

A compound seems to be a substance that is entirely made of one kind of molecule.

Every component of compounds shares the same traits and features because of their homogenous makeup. However, because mixtures are composed of several sorts of chemicals, they frequently differ in terms of content, qualities, and samples.

Therefore, the composition of a given pure compound is always the same no matter what the source of the compound.

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The new volume occupied by the gas is 1.2 m³.

Here Boyle's law is applied.

At a constant temperature, the volume of a gas is inversely proportional to the pressure exerted on it.

                                    PV = constant

where,

P = Pressure applied

V = Volume of the gas

Given,

P₁ = 5.0 atm

V₁ = 0.60 m³

P₂ = 2.5 atm

To find

V₂ =?

As PV = constant

Therefore,

P₁ V₁ = P₂ V₂

5 × 0.6 = 2.5 × V₂

3 = 2.5 × V₂

V₂ = 3/2.5

V₂ = 1.2 m³

Hence, the new volume occupied by the gas is 1.2 m³.

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The equation that best represents the addition of potassium sulfate to water is [tex]K_2SO_4(s) -- > 2 K^+ (aq) + SO4^{2-} (aq)[/tex]

When potassium sulfate is dissolved in water, it dissociates into its cation and anion according to the following equation:

[tex]K_2SO_4(s) -- > 2 K^+ (aq) + SO4^{2-} (aq)[/tex]

The positive ions are 2 moles of potassium ions while the negative ion is a mole of sulfate ion.

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The 3 elements of a transaction that can be reclassified are:

On an account transaction screen, one can see there are different elements that exist and some of them are:

This refers to the proof that exists that a person has bought a good or service and can also stand as an agreement.

Hence, we can see that On an account transaction screen, one can see there are different elements that exist and some of them are:

However, there are only 3 elements that can be reclassified on the  reclassify transactions screen and they are:

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Answer:

1.28 x 10⁻¹⁵ eV

Explanation:

To find the energy, you can use the photon energy equation:

E = hc / λ

In this equation,

-----> E = energy (eV)

-----> h = Plank's Constant (4.136 x 10⁻¹⁵ eV*s)

-----> c = speed of light (3.00 x 10⁸ m/s)

-----> λ = wavelength (m)

You can find the energy of the photon by plugging the given values into the equation and solving.

E = hc / λ

E = (4.136 x 10⁻¹⁵ eV*s)(3.00 x 10⁸ m/s) / 9.7 x 10⁸ m

E = 1.2408 x 10⁻⁶ / 9.7 x 10⁸ m

E = 1.28 x 10⁻¹⁵ eV

Answer:

The synthesis of zeolite-supported Mo carbide species was studied by testing different reduction/carburization conditions applied to a zeolite-supported Mo oxide catalyst, with the aim to find the optimized treatment conditions necessary to form stable supported Mo carbide catalysts ex situ for application in methane dehydroaromatization reaction. Four types of treatment were performed and studied using temperature-programmed reduction and carburization profiles: (1) heating the catalyst in a reducing gas, H2, up to reaction temperature and switching to CH4; (2) heating the catalyst in a reducing gas, H2, mixed with dilute CH4; (3) heating the catalyst in CH4 up to reaction temperature; and (4) heating the catalyst in an inert gas (commonly He) up to reaction temperature and then switching to CH4 or to H2 followed by CH4 or to H2/CH4 mixture. Each of these processes were stopped at intermediate points to analyze the phases that were present in order to identify the structural evolution of the supported Mo carbides that originate from the supported Mo oxides. Once the supported carbides were formed, they were quenched under the same gas mixture, and then they were each tested in methane dehydroaromatization via previous heating to reaction temperature in He flow. Despite all of them showing only presence of Mo2C species on HZSM-5, the catalytic properties were dramatically different. Catalysts treated in H2 or CH4/H2 showed remarkably higher stability. These catalysts exhibited a higher Mo dispersion and thus exposure on the active surface.

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Answer:

best answer is D

Explanation:

if element has even number then protons and neutrons are same but if element has odd number then we should add 1 number in number of protons to know neutrons. but this rule is not work in 4 element that element are argon, nitrogen, hydrogen and one other

Taking into account the reaction stoichiometry, 3.33 moles of ammonia are produced when 5.0 moles of hydrogen react with excess nitrogen.

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 3 moles of hydrogen form 2 moles of ammonia, 5 moles of hydrogen form how many moles of ammonia?

[tex]moles of ammonia=\frac{5 moles of hydrogenx 2 moles of ammonia}{3 moles of hydrogen}[/tex]

moles of ammonia= 3.33 moles

Finally, 3.33 moles of ammonia are produced when 5.0 moles of hydrogen react with excess nitrogen.

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The molarity of the chloride ion is 2.0 * 10⁻⁵ M.

The molarity of the chloride ion is calculated using the formula below:

The percentage concentration of chloride ion = 727/kg * 10⁻⁶ Kg * 100/1

The percentage concentration of chloride ion = 0.0727%

Molar mass of Chloride ion = 35.5 g/mol

Molarity = (0.0727 * 1.035)/(35.5 * 100)

Molarity of chloride ion = 2.0 * 10⁻⁵ M

In conclusion, the molarity of the chloride ion is obtained from the density and percent concentration of chloride ions in seawater.

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Answer:

5.0 °C

Explanation:

To find the temperature change, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = heat energy (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = temperature change (°C)

You can find the temperature change by plugging the given values into the equation and simplifying.

Q = 209 J                      c = 4.18 J/g°C

m = 10.0 g                     ΔT = ? °C

Q = mcΔT                                                      <----- Equation

209 J = (10.0 g)(4.18 J/g°C)ΔT                     <----- Insert values

209 J = (41.8)ΔT                                           <----- Multiply 10.0 and 4.18

5.0 = ΔT                                                       <----- Divide both sides by 41.8

Answer:

5° C  temp change

Explanation:

Q = m c T  

       Given:  Q =209    m = 10    c = 4.18     looking for T (change in temp)

209 = 10 * 4.18 T

T = 209 / (10*4.18) = 5° C

Green, because it has less volume and less amount of matter.

Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimeter are a typical unit of measurement for density.

Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion. If an object's density is lower than the liquid's, it will often float.

The dimensions of two colored cubes.

Red: 4 12

Green: 3 10

density = mass/volume

so compare

[tex]12/4^{3}[/tex] and [tex]10/3^{3}[/tex]

None of the choices is the real reason. But is the closest. It is green because 10/27 > 12/64

But red would have been denser for a side of 3.9, and green would still have had less volume and less matter.

Green, because it has less volume and less amount of matter.

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It is a thermodynamically spontaneous process that means Protein folding occurs. The value of ΔG must be negative in the case of folding but in the case of unfolding, the value of ΔG must be positive.

When the process is thermodynamically spontaneous process results in Protein folding otherwise the process is unfolding.

The value for ΔG must be negative in the case of the folding process and the value for ΔG must be positive in the case of the unfolding process. The value of a thermodynamic parameter for the reverse reaction has an opposite sign but the same value that's why the value for ΔG must be positive and known as unfolding (denaturation) process.

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Answer:

B₂

Explanation:

The limiting reactant is always a reactant. You can determine which reactant is limiting by identifying which has the smaller mole-to-mole ratio with the product. This ratio can be found via the coefficients of the balanced reaction.

4 A₂ + 3 B₂ ---> 6 AB

4 moles A₂
------------------  = mole-to-mole ratio A₂/AB
6 moles AB

3 moles B₂
------------------  =  mole-to-mole ratio B₂/AB
6 moles AB

Since the mole-to-mole ratio between B₂ and AB is smaller, B₂ must be the limiting reactant.
                           

- 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

The dilution problem uses the equation :

[tex]M_aV_a= M_bV_b[/tex]

The initial molarity (concentration) [tex]M_a =[/tex] 0.13 M

The initial volume [tex]V_a[/tex] = 0.12 L

The desired molarity (concentration) [tex]M_b[/tex] = 0.23 M

The volume of the desired solution [tex]V_b[/tex] = ( 0.12 + x L )

Substituting values in above equation;

(0.13 M ) (0.12 L) = (0.23 M ) (0.12 L + x L)

0.0156 M L = 0.0276 M L + 0.23 x M L

- 0.012 M L = 0.23 x M L

x = - 0.05

Therefore, - 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

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1. The amount of OH¯ present in the solution is 0.1 mol/L

2. The amount of H⁺ present in the solution is 0.0000000000001 mol/L

3. The pH of the solution with H⁺ concentration of 1×10⁻⁴ mol/L is 4

We'll begin by obtaining the pOH of the solution

pH + pOH = 14

13 + pOH = 14

Collect like terms

pOH = 14 - 13

pOH = 1

Finally, we can determine the OH¯

pOH = –Log [OH¯]

1 = –Log [OH¯]

Multiply through by –1

–1 = Log [OH¯]

Take the anti-log of –1

[OH¯] = anti-log of (–1)

[OH¯] = 0.1 mol/L

pH = –Log [H⁺]

13 = –Log [OH¯]

Multiply through by –1

–13 = Log [H⁺]

Take the anti-log of –13

[H⁺] = anti-log of (–13)

[H⁺] = 0.0000000000001 mol/L

pH = –Log [H⁺]

pH = –Log 1×10⁻⁴

pH = 4

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According to Charle's law equation, the volume of a sample of carbon dioxide will be 684.6 mL and the temperature will be 283.60 K.

According to Charles' Law, the volume of a gas container with a certain amount of gas within is precisely proportional to the temperature when the pressure is constant.

[tex]V_{1}[/tex] = 684.6 mL

[tex]V_{2}[/tex] = 933.9 mL

[tex]T_{1}[/tex] = ?

[tex]T_{2}[/tex] = 387 K

Using Charle's law equation

[tex]\frac{684.6}{T_{1} } = \frac{933.9}{387}[/tex]

[tex]T_{1} = \frac{2,64,862.8}{933.9}[/tex]

[tex]T_{1} = 283.60 K[/tex]

According to Charle's law equation, the temperature at 684.6 mL volume was 283.60 K.

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