Does trans-oleic acid have a higher or lower melting point than cis-oleic acid? Explain Which triacylglycerol yields more energy on oxidation: one containing three resides of linolenic acid or three residues of stearic acid?

Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the balanced chemical equation

H₂ + F₂ → 2HF

An ideal gas is a gas that obey gas laws at all temperature and pressure conditions. It have velocity and mass but do not have volume. Ideal gas is also called perfect gas. Ideal gas is a hypothetical gas.

It is expressed as:

PV = nRT

where,

P = Pressure

V = Volume

n = number of moles

R = Ideal gas constant

T = temperature

Here,

P = 1 atm   [At STP]

V = 110 ml = 0.11 L

T = 273 K   [At STP]

R = 0.0821   [Ideal gas constant]

Now put the values in above expression

PV = nRT

1 atm × 0.11 L = n × 0.0821 L.atm/ K. mol × 273 K

[tex]n = \frac{1\ \text{atm} \times 0.11\ L}{0.0821\ \text{L. atm/ K. mol} \times 273\ K}[/tex]

n = 0.0049 mol

To calculate the concentration of resulting solution use the expression

[tex]C = \frac{n}{V}[/tex]

   [tex]= \frac{0.0049}{0.15}[/tex]  

   = 0.032 M

Thus from the above conclusion we can say that Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.

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Answer:

1ppm = 1 mg/kg

60460 = 0.13

0.13

Explanation:

Answer:0.013 ppb

Explanation:

re write the question.

Explanation:

it seems incomplete.

Answer:

6.21 moles O

Explanation:

To find the moles of oxygen, you need to (1) convert grams Mn(ClO₄)₄ to moles Mn(ClO₄)₄ (via molar mass) and then (2) convert moles Mn(ClO₄)₄ to moles O (via mole-to-mole ratio from formula subscripts). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.

Molar Mass (Mn(ClO₄)₄): 452.74 g/mol

1 Mn(ClO₄)₄ = 1 Mn and 4 Cl and 16 O

175.7 g Mn(ClO₄)₄           1 mole                   16 moles O
---------------------------  x  -------------------  x  ---------------------------  =  6.21 moles O
                                       452.74 g            1 mole Mn(ClO₄)₄

Answer:

4.48 dm^3

Explanation:

As given in the problem, the conversion factor for the molar volume of all gases is 22.4 dm^3/mole at STP.  A mole of all ideal gases will occupy 22.4 liters (dm^3).  Calculate the moles of hydrogen contained in 0.4 grams of the gas by dividing the mass by the molar mass of H2.  H2 has a molar mass of 2 grams/mole.

 (0.4 g)/(2 grams/mole) = 0.2 moles H2

(0.2 moles H2 at STP)*(22.4 dm^3/mole at STP) = 4.48 dm^3  (4.48 liters at STP)

Answer:

1.) 2 Mg + H₂ ------> 2 MgH

2.) 2 K + O₂ -----> 2 KO

3.) K + S -----> KS

4.) 2 Ba + Br₂ -----> 2 BaBr

5.) 2 Ca + N₂ ------> 2 CaN

Explanation:

An equation is balanced when there is an equal amount of each element on both sides of a reaction. If there is an unequal amount, they can be altered by adding coefficients which modify the amount of an element/molecule. It is important that the coefficients are as small as possible while staying as whole numbers.

1.) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

Mg + H₂ -----> MgH

Reactants: 1 magnesium, 2 hydrogen

Products: 1 magnesium, 1 hydrogen

The balanced equation:

2 Mg + H₂ ------> 2 MgH

Reactants: 2 magnesium, 2 hydrogen

Products: 2 magnesium, 2 hydrogen

2.) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

K + O₂ -----> KO

Reactants: 1 potassium, 2 oxygen

Products: 1 potassium, 1 oxygen

The balanced equation:

2 K + O₂ -----> 2 KO

Reactants: 2 potassium, 2 oxygen

Products: 2 potassium, 2 oxygen

3.) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

K + S -----> KS

Reactants: 1 potassium, 1 sulfur

Products: 1 potassium, 1 sulfur

This equation is already balanced with all the elements/compounds having coefficients of 1.

4.) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

Ba + Br₂ -----> BaBr

Reactants: 1 barium, 2 bromine

Products: 1 barium, 1 bromine

The balanced equation:

2 Ba + Br₂ -----> 2 BaBr

Reactants: 2 barium, 2 bromine

Products: 2 barium, 2 bromine

5.) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

Ca + N₂ ------> CaN

Reactants: 1 calcium, 2 nitrogen

Products: 1 calcium, 1 nitrogen

The balanced equation:

2 Ca + N₂ ------> 2 CaN

Reactants: 2 calcium, 2 nitrogen

Products: 2 calcium, 2 nitrogen

The type of cleaning agent that should be used to clean a laminar flow hood is 70% Isopropyl Alcohol.

Isopropyl alcohol is mixed with water for use as a rubbing-alcohol antiseptic. It is also utilized in aftershave creams, hand lotions, and other cosmetics. In enterprise, it is used as a less expensive solvent for cosmetics, drugs, shellacs, and gums, in addition to denaturing ethanol (ethyl alcohol).

Isopropyl alcohol is a colorless, flammable chemical compound with a robust alcoholic smell. As an isopropyl institution related to a hydroxyl group, it's far the handiest example of a secondary alcohol, wherein the alcohol carbon atom is connected to 2 other carbon atoms.

Isopropyl alcohol is pure alcohol and is a colorless liquid with a musty, sharp odor. There are no other components in a bottle of isopropyl alcohol. through assessment, rubbing alcohol consists of isopropyl alcohol among different components, including water. maximum rubbing alcohol manufacturers incorporate 70% isopropyl alcohol.

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Answer:

1120 mm Hg

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One way in which God showed precision in his creation was his mighty love on the he has on his creation

The book of John made us to know that: For God do love the world that he gave his only begotten son that whosoever believeth in him shall not perish but have everlasting life.

Creations is the art of producing or making something out of something

So therefore, one way in which God showed precision in his creation was his mighty love on the he has on his creation

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It is correct to state that Amines are suitable for preparing buffers are often synthesized by treating ammonia with epoxides. The relative structures of compound B are attached accordingly.

Amine is a family of basic chemical compounds formed by replacing hydrogen with one or more monovalent hydrocarbon radicals.

Apart from medications and pharmaceuticals, amines are employed in the production of azo-dyes and nylon.

They are commonly employed in the development of crop protection, pharmaceutical, and water purification chemicals. They are also used in personal care products.

Ethanol amines are the most widely utilized form of amine on the global market.

It should be noted that ammonia attacks epoxides at the least substituted carbon to produce (A.)

The generated product is then made to react with another epoxide, resulting in the synthesis of successive products.

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Answer:

terminal

Explanation:

When a hydrogen atom is part of a molecular structure, it is always a terminal atom.

At a particular temperature, the solubility of He in water is 0.060 M when the partial pressure is 0.90 atm. 2.27 atm is the partial pressure of Kr would give a solubility of 0.150 M.

Solution:

The solubility of gas is directly proportional to partial pressure. It is expressed as:

S = [tex]K_ h \times P _g_a_s[/tex]

where, S = Solubility of gas

[tex]K_h[/tex] = Henry's Law constant

[tex]P_g_a_s[/tex] = Partial pressure of gas

Now, put the values in above expression we get

0.060M = [tex]K_h[/tex] × 0.9 atm

   [tex]K_h[/tex] =  = 0.066 M/atm

Now we have to find the partial pressure of He

0.150 M = 0.066 M/atm × [tex]P_g_a_s[/tex]

[tex]P_g_a_s[/tex] = 2.27 atm

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Explanation:

One of the most fascinating chemical experiments is the reaction between silver nitrate and copper wire in water. Characterised by fractal-like precipitates, this experiment is a stunning example of a simple redox reaction.

Copper reacting with silver nitrate is a chemical change. In a chemical change, new substances are formed with different chemical properties.

Copper (Cu) is a metal, and silver nitrate is a compound made of silver (Ag), nitrogen (N), and oxygen (O).When copper is added to silver nitrate, a reaction occurs. The copper atoms react with the silver nitrate molecules, resulting in the formation of new substances.

The reaction produces copper nitrate  and silver (Ag) as products.Copper nitrate is a compound formed by the combination of copper, nitrogen, and oxygen, while silver remains unchanged.

The color of the solution changes, indicating a chemical reaction has taken place. Copper nitrate is usually a blue-green color, while silver is a metallic silver color.The chemical properties of the substances involved in the reaction are altered. Copper, being a metal, is malleable and conducts electricity, whereas copper nitrate is a compound and does not possess these properties.

Thus, the reaction between copper and silver nitrate is a chemical change because new substances with different properties are formed.

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Dry powder extinguishers

They are for Class D or combustible metal fires, only. They are ineffective on all other classes of fires.

Extinguishing Agent means a source of extinguishment in which to quickly and effectively suppress the fire.

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Answer:

0.375 moles Al

Explanation:

To find the moles Al, you need to (1) convert grams AlCl₃ to moles AlCl₃ (via molar mass) and then (2) convert moles AlCl₃ to moles Al (via mole-to-mole ratio from equation coefficients). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (50.0 g).

Molar Mass (AlCl₃): 26.982 g/mol + 3(35.453 g/mol)

Molar Mass (AlCl₃): 133.341 g/mol

2 Al(s) + 3 CuCl₂(aq) -----> 3 Cu(s) + 2 AlCl₃(aq)

50.0 g AlCl₃           1 mole                 2 moles Al
--------------------  x  ------------------  x  -----------------------  =  0.375 moles Al
                               133.341 g           2 moles AlCl₃

Half-life in geology is defined as the time it takes for a radioactive material or element to decay half its original quantity into a daughter radiogenic isotope.

From the radioactive elements listed the Carbon-14 would be most preferable for dating a specimen.

Radiometric dating is defined as the process that is used by scientists to calculate the age of geologic materials.

From the data given in the table above, the radioactive element with the most recent half-life is carbon-14 being 5,730 years.

The uses os Carbon-14 include the following:

The carbon-14 is preferably used for dating specimen because it is the most stable and accurately dates archaeological artifacts.

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Dalton's law

States that the total pressure exerted by a mixture of gases is the sum of the pressures exerted independently by each gas in the mixture.

Dalton's law, which states that a gas mixture's overall pressure is equal to the sum of its component gases' partial pressures. The pressure that each gas would produce if it occupied the same volume of the mixture by itself at the same temperature is known as the partial pressure.

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A solution that contains 7.8% W/V ethanol is equivalent to 0.078g/mL. Details about weights per volume can be found below.

Weights per volume is a unit for measuring density of a substance. It can be converted to g/mL using the following expression:

w/v% = g/100mL

According to this question, a solution contains 7.8% W/V ethanol. The equivalent of this in g/mL is as follows:

7.8% W/V = 7.8g/100mL

= 0.078g/mL

Therefore, a solution that contains 7.8% W/V ethanol is equivalent to 0.078g/mL.

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Answer:

3 Electron shell/orbit

Explanation:

the number of shell an element has is what determines the period of that element.

18.06 ₓ [tex]10^{23}[/tex] molecules in 3 mol of carbon dioxide (CO2).

The proportionality factor that connects the quantity of substance in a sample to the number of constituent particles in that sample is called the Avogadro constant. The reciprocal mole, which is its SI unit, is specified precisely as NA 6.02214076 × [tex]10^{23}[/tex] [tex]mol^{-1}[/tex]. It bears Amedeo Avogadro's name, an Italian scientist.

When dealing with very big quantities, chemistry uses Avogadro's number. It serves as the foundation for the mole, a unit of measurement that makes converting between moles, mass, and the number of molecules simple. The quantity, for instance, can be used to determine how many water molecules make up a single snowflake.

1 Mole is 6.02ₓ [tex]10^{23}[/tex] molecules.

Therefore 3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =3(6.02ₓ [tex]10^{23}[/tex])

3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =18.06 ₓ [tex]10^{23}[/tex]molecules of [tex]CO_{2}[/tex].

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Yes, it will be worthwhile to investigate finding a catalyst to use in this reaction under standard conditions because it is negative.

This is a substance which speeds up the rate of a chemical reaction by lowering the activation energy.

ΔG being negative indicates a a slow reaction which is why a catalyst under standard conditions should be used.

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The name of the molecule above is Ethene

Organic compounds can be defined as compounds containing carbon and hydrogen.

Some classes of organic compounds are:

So therefore, he name of the molecule above is Ethene

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Empirical formula mass

[tex]\\ \tt{:}\dashrightarrow 12+2+16[/tex]

[tex]\\ \tt{:}\dashrightarrow 30g/mol[/tex]

n:-

[tex]\\ \tt{:}\dashrightarrow \dfrac{Molecular\:mass}{Empirical\:mass}[/tex]

[tex]\\ \tt{:}\dashrightarrow \dfrac{90}{30}[/tex]

[tex]\\ \tt{:}\dashrightarrow 3[/tex]

Molecular formula

[tex]\\ \tt{:}\dashrightarrow n\times Empirical\: formula [/tex]

[tex]\\ \tt{:}\dashrightarrow 3(CH_2O)[/tex]

[tex]\\ \tt{:}\dashrightarrow C_3H_6O_3[/tex]

The number of atoms in one unit cell with one atom at each corner, one atom on 8 of the edges, and one atom on 6 of the faces are 4.6atoms.

There is one atom at each corner and there are 8 corners in a unit cell, so there is one atom in each of the eight corners.

Therefore, the number of atom from corners = 1 x 1/8 = 1atom

There are 12 edges, since there are one atom on 8 of the edges the number of atom = 1 x 8/12 = 0.6atom

There is one atom at each face and there are 6 faces in a unit cell, each atom shares two face.

Therefore, the number of atoms on face = 2 x 1/6 = 3

Total number of atoms in one unit cell = 1 + 0.6 + 3 = 4.6atoms

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You picked up a dirty test tube with a sticky substance on the outside. You get some of this substance on your hand. The first thing that I should do is wash my hand and then tell the teacher.

A test tube often referred to as a culture tube or sample tube, is a typical item of lab glassware that is made up of a finger-like length of clear plastic or glass tubing that is open at the top and closed at the bottom. Usually, test tubes are stored on dedicated racks.

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Considering the definition of empirical formula, the empirical formula is C₃H₈.

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

In this case, in first place you know the percent composition:

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 81.71 grams of carbon and 18.29 grams of hydrogen H.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

To express this relationship in the form of simple integers, it is necessary to multiply by a simple number to achieve this:

Therefore the C: H mole ratio is 3: 8

Finally, the empirical formula is C₃H₈.

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Answer:

Yes

Explanation:

Answer:it act as a precursor to proteins

Explanation:

Answer: 2Al(s) + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)

Explanation: The quantities of aluminum and copper sulfate used as reactants will be such that the copper sulfate will be in excess. Thus, the aluminum will be the limiting factor in determining the number of moles (gram-atoms) of products that will be formed.

The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. The masses (in mg) that remains after t years A=150/2^t/30yrs

A substance's half-life is the amount of time it takes for half of it to decompose.

Half-life is the length of time it takes for half of an unstable nucleus to go through its decay process. A radioactive element's half-life decay time varies depending on the element. For instance, carbon-10 has a half-life of only 19 seconds, making it impossible to discover in nature. On the other hand, uranium-233 has a half-life of almost 160000 years.

When n half-lives have passed, the formula for estimating the amount still left is:-

A=A°/2^n

where,

A=initial amount

A°=remaining amount

n=t/t_{1/2}

A=150/2^t/30yrs

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